Vector Bundles on Rational Homogeneous Spaces
Abstract
We consider a uniform -bundle on a complex rational homogeneous space and show that if is poly-uniform with respect to all the special families of lines and the rank is less than or equal to some number that depends only on , then is either a direct sum of line bundles or -unstable for some . So we partially answer a problem posted by Muñoz-Occhetta-Solá Conde(19). In particular, if is a generalized Grassmannian and the rank is less than or equal to some number that depends only on , then splits as a direct sum of line bundles. We improve the main theorem of Muñoz-Occhetta-Solá Conde (18 Theorem 3.1) when is a generalized Grassmannian by considering the Chow ring. Moreover, by calculating the relative tangent bundles between two rational homogeneous spaces, we give explicit bounds for the generalized Grauert-Mülich-Barth theorem on rational homogeneous spaces.
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Key words: vector bundle, generalized Grassmannian, rational homogeneous space
1 Introduction
Algebraic vector bundles on a projective variety over complex number field are fundamental research objects in algebraic geometry. However, up to now, algebraic vector bundles are still mysterious for general projective varieties. According to Serre (GAGA), the classification of algebraic vector bundles over is equivalent to the classification of holomorphic vector bundles. So there are not only algebraic ways but also analytic ways to handle the problems of vector bundles. For simplicity, we just call vector bundles of rank or -bundles in the context.
If is , the structure of a vector bundle on is quite clear because Grothendieck tells us that it splits as a direct sum of line bundles. However, if is a projective space and the dimension of it is bigger than or equal to two then the structures of vector bundles on are not so easy to be determined. Since projective spaces are covered by lines, it is a natural way to consider the restriction of vector bundles to lines. From Grothendieck’s result, they split after being restricted to . By semicontinuity theorem, for “almost all” lines, -bundle has the constant splitting type. This means that the lines to which the vector bundle restricts having different splitting type consist a closed subset of a Grassmannian. If the closed subset is empty, such bundles are called uniform vector bundles. Uniform bundles are widely studied not only on projective spaces (25 27 24 9 10 11 3) but also on special Fano manifolds of Picard number one (2 15 12 6 18). Please see Introduction in 6 for the details.
Instead of considering vector bundles, Occhetta-Solá Conde-Wiśniewski (22) studied flag bundles which are constructed upon the action of the defining group on the flag manifold . Recently, Muñoz-Occhetta-Solá Conde (17) studied uniform principle -bundles with semisimple over Fano manifolds. They present a number of theorems that are flag bundle’s versions of some of the central results in the theory of uniform vector bundles. More precisely, they paid special attention to homogeneous filtrations of relative tangent bundles between flag manifolds and generalized the different standard decomposability notions of vector bundles. They used an interesting concept of "tag" of a -bundle to describe diagonalizability of any uniform flag bundle of low rank. But they mainly focus on with Picard number one. In 19, the authors proposed a problem as follows.
Problem 1.1.
Classify low rank uniform principle -bundles ( semisimple algebraic group) on rational homogeneous spaces.
In this paper, we consider uniform bundles on generalized flag varieties or even rational homogeneous spaces with arbitrary Picard numbers and give partial answers to this problem.
Let
where is a simple Lie group with Dynkin diagram whose set of nodes is and is a parabolic subgroup of corresponding to . We set by marking on the Dynkin diagram of the nodes corresponding to . Let be a node in and be the set of nodes in that are connected to .
If , we call
the -th special family of lines of class , where and is by deleting -th term . Denote by
the -th universal family of class , which has a natural -bundle structure over .
We separate our discussion into two cases:
Case I: , then and we have the natural projection ;
Case II: , then we have the standard diagram
(1.5) |
For the definition of "poly-uniform", "-stable", "-unstable", "" and "", please see Section 3.
Theorem 1.2.
On , if an -bundle is poly-uniform with respect to all the special families of lines and , then is -unstable for some () or splits as a direct sum of line bundles.
In particular, if the Picard number of is one, we improve an interesting theorem of Muñoz-Occhetta-Solá Conde (18 Theorem 3.1) a little bit (see Table 2).
Theorem 1.3.
Suppose that is a uniform -bundle on a generalized Grassmann . If , then splits as a direct sum of line bundles.
By calculating the relative tangent bundles and using Descent Lemma, we can have explicit bounds for the generalized Grauert-Mülich-Barth theorem on rational homogeneous spaces.
Theorem 1.4.
Fix and assume that is not an exposed short root. Let be a holomorphic -bundle over of type with respect to . If for some ,
then there is a normal subsheaf of rank with the following properties: over the open set , where is an open set in , the sheaf is a subbundle of , which on the line given by has the form
Corollary 1.5.
With the same assumption as Theorem 1.4. For a -semistable -bundle over of type with respect to , we have
In particular, if fits Case I, then we have ’s are constant for all .
Theorem 1.6.
Fix and assume that is an exposed short root. Let be a holomorphic -bundle over of type with respect to . If for some ,
then there is a normal subsheaf of rank with the following properties: over the open set , where is an open set in , the sheaf is a subbundle of , which on the line given by has the form
Corollary 1.7.
With the same assumption as Theorem 1.6. For a -semistable -bundle over of type with respect to , we have
In particular, if fits Case I, then we have ’s are constant for all .
If , where is a semi-simple Lie group and is a Borel subgroup of , then we have the following result.
Corollary 1.8.
If an -bundle on X is -semistable for all and , then splits as a direct sum of line bundles.
2 Preliminaries
Throughout this paper, all algebraic varieties and morphisms will be defined over complex number field .
2.1 Semisimple Lie groups and algebras
In mathematics, Lie group–Lie algebra correspondence allows one to study Lie groups, which are geometric objects, in terms of Lie algebras, which are linear objects. Let be a semi-simple Lie group. Assume to be a nonzero finite dimensional complex vector space, fix a maximal torus , and let be a representation of . It is well known that decomposes into a direct sum of simultaneous eigenspaces
where the direct sum run over in the character group of , which is the set of all holomorphic homomorphisms from to , and
Since is a finite dimensional vector space, we have for all but finitely many values of . Those values of for which are called the weights of , and is called the weight space.
In the Lie algebra side, let be the associated semi-simple Lie algebra of . The maximal torus corresponds to which is an abelian subalgebra of maximal dimension, i.e. Cartan subalgebra. A holomorphic representation of a complex Lie group gives rise to a complex linear representation of the Lie algebra of . Similarly, every finite dimensional representation of admits a decomposition
where
Those are still called the weights of , and is called the weight space. If we apply the above decomposition to and the adjoint representation, we have Cartan decomposition of :
where
The elements for which are called roots of , and the set of these elements will be denoted by and be called root system. For every , is called root space which is one dimensional.
Fix a linear functional
whose kernel does not intersect . Let
Then is called positive system of roots and is called negative system of roots. Given such a positive system , we define the fundamental system as follows: if and only if and cannot be expressed as the sum of two elements of . A non-zero representation of is called a highest weight representation if it is generated by a vector such that for all . In this case, is called the highest weight vector, and is the highest weight of .
For each there is a unique element such that
The vectors for span . We denote by the set of all elements of form for .
The Killing form defines a nondegenerated bilinear form on , where and ad is the adjoint representation. It can be shown that is a Euclidean space with respect to . Set and . We identify with the set of fundamental roots with respect to a choice of maximal torus and fixed Borel subgroup . It is known that every fundamental system can form a basis of . Let be a fundamental system. Then we define by
The matrix is called the Cartan matrix of .
The Dynkin diagram of , which we denoted by , is determined by the Cartan matrix. It consists of a graph whose set of nodes is and where the nodes and are joined by edges. When two nodes and are joined by a double or triple edge, we add to it an arrow pointing to if . We call a short root of and a non-short (or long) root of . (Sometimes, for the sake of narrative convenience, we freely interchange the terminology "node" and "root".) One may prove that there is a one to one correspondence between isomorphism classes of semisimple Lie algebras and Dynkin diagrams of reduced root systems. Moreover, every reduced root system is a disjoint union of mutually orthogonal irreducible root subsystems, each of them corresponding to one of the connected finite Dynkin diagrams , , , , , , , , :
The connected components of the Dynkin diagram determine the simple Lie groups that are factors of the semisimple Lie group , each of them corresponding to one of the Dynkin diagrams above.
2.2 Parabolic Subgroup and Subalgebra
A closed subgroup of is called parabolic if the quotient space is complete, hence projective. A maximal connected solvable subgroup of is called a Borel subgroup. We fix a Cartan subalgebra . Let
be a fixed Borel subalgebra. It is easy to determine the parabolic subalgebras containing . They are all of the form
where is a subset of that is closed under the addition of roots. Hence the parabolic subalgebras containing lie in bijection with the subsets of . For some subset of , we write the parabolic subalgebra corresponding to . We define by the parabolic subgroup of such that its Lie algebra is . Therefore the parabolic subgroup corresponds to the subset (so a maximal parabolic subgroup is defined by a single root). Then has a minimal homogeneous embedding in projective space of the highest weigh module of corresponding to the highest weight , where is the -th fundamental weight dual to the roots , by a very ample line bundle .
2.3 Rational homogeneous spaces
It is well known that carries a transitive -action, it is a smooth projective variety. Borel and Remmert’s classical theorem (4) states that a projective complex manifold which admits a transitive action of its automorphism group is a direct product of an abelian variety and a rational homogeneous space , where is a semi-simple algebraic group and is a parabolic subgroup.
Every rational homogeneous space can be decomposed into a product
of rational homogeneous spaces with simple algebraic group . Each rational homogeneous space , called the generalized flag manifold, only depends on the Lie algebra of , which is classically determined by the marked Dynkin diagram (16). In the most common notation, we set by marking on the Dynkin diagram of the nodes corresponding to . For instance, numbering the nodes of , the usual flag manifold corresponds to the marking of (sometimes we omit the braces and just write as ).
The two extremal cases correspond to the generalized complete flag manifolds (all nodes marked), and the generalized Grassmannian (only one node marked).
In 16, the authors explicitly describe the lines through a point of a rational homogeneous space , where is a simple Lie group. Let and be the set of nodes in that are connected to .
Definition 2.1.
We call an exposed short root if the connected component of in contains root longer than , i.e., if an arrow in points towards .
Remark 2.2.
Obviously, long roots of in are not exposed short roots. If is a set of single point, i.e. is the generalized Grassmannian, then the exposed short root is just the usual short root. It’s worth mentioning that if contains all long roots of , then short roots of in are not exposed short roots.
Theorem 2.3.
(16 Theorem 4.3) Let . Suppose to be a simple Lie group. Consider in its minimal homogeneous embedding. Denote by the space of s in . Then
-
1.
, where is the space of lines of class .
-
2.
If is not an exposed short root, then .
-
3.
If is an exposed short root, then is the union of two -orbits, an open orbit and its boundary .
Remark 2.4.
If and is a long root, then is just the variety of lines on .
Example 2.5.
Let’s consider the Dynkin diagram , i.e. is the generalized flag manifold.
1) For , is the usual Grassmannian and is just the variety of lines on .
2) For , is the usual flag manifold and is the disjoint union of and .
There is a similar statement for , the set of tangent directions to lines on passing through a fixed point . It is a disjoint union of spaces of lines of class through .
Theorem 2.6.
(16 Theorem 4.8) Let and . Suppose to be a simple Lie group. Consider in its minimal homogeneous embedding. Let be the semisimple part of and be the components of containing an element of , where means plus any nodes of attached to a node of . Denote by the space of lines of class through . Then
-
1.
If is not an exposed short root, then .
-
2.
If is an exposed short root, then is a union of an open -orbit and its boundary .
Remark 2.7.
If , then the set of nodes of the Dynkin diagram is . is a parabolic subgroup of by marking in the nodes in that are connected to and . Moreover, if is a long root then is just the variety of lines through fixed points, i.e. so-called VMRTs. We refer to 14 for a complete account on VMRTs.
Example 2.8.
Let’s consider the Dynkin diagram , i.e. is the generalized flag manifold.
1) For , is the usual Grassmannian and is just the variety of lines through .
2) For , is the usual flag manifold and is the disjoint union of and .
Not only but also all linear spaces can be read from the marked Dynkin diagrams.
Theorem 2.9.
(16 Theorem 4.9, 4.14) Let be a simple group and is a rational homogeneous space. Let denote the variety parameterizing the -class ’s on .
-
•
If is not an exposed short root, then for all , is the disjoint union of homogeneous spaces , where is a set of positive roots such that the component of containing is isomorphic to , intersects only in , and is an extremal node of this component.
-
•
If is an exposed short root, then for all , consists of a finite number of -orbits.
3 Uniform vector bundles
Given a smooth projective variety and a vector bundle on , we denote to be an unsplit family of rational curves on . is called unsplit if is a proper -scheme. We say that is uniform with respect to if the restriction of to the normalization of every curve in splits as a direct sum of line bundles with the same splitting type. If is a generalized Grassmannian , then we just call uniform without mention the unspilt family .
3.1 Uniform vector bundles on generalized Grassmannians
Along this section we will work on uniform vector bundles on rational homogeneous spaces of Picard number one, i.e. generalized Grassmannians. Let be a simple Lie group and be the set of nodes of the Dynkin diagram of . Denote by the parabolic subgroup of corresponds to the node . Consider the generalized Grassmannian or, for brevity, . Denote by the generalized flag manifold defined by the marked Dynkin diagram and by the universal family, which has a natural -bundle structure over , i.e. we have the natural diagram
(3.5) |
Remarkably, defined above is indeed an unsplit family of rational curves on . Given , , which we call the special family of lines of class through , coincides with by Remark 2.7, where the set of nodes of the Dynkin diagram is .
When is an extremal node, that is, the subdiagram is connected. Remarkably, in the case , i.e. , since , we only need to think about the extremal node . Similarly, since , we just consider the the extremal node in . According to Theorem 2.6, has the following possibilities:
-
•
Projective spaces or smooth quadrics,
-
•
Grassmannians,
-
•
Spinor varities,
-
•
, , .
The possibilities are list in Table 1 below.
We observe that for , the morphism from to Grassmannian plays a critical role in determining whether a uniform vector bundle can split as a direct sum of line bundles. Let be a positive integer smaller than or equal to . As long as we show that the morphism can only be constant for any integer and every , then every uniform -bundle on splits for . We suggest that interested readers refer to Theorem 3.1 in paper 18 for details. Now, let’s analyze the morphism one by one according to the probabilities of .
Case I. When is a projective space or a smooth quadric , then their Chow rings have the form
where is a hyperplane section. In particular, for every . By the proof of Lemma 3.4 in paper 18, the only morphisms are constant for any integer .
When is a smooth quadric , since
where is a hyperplane section and is a subvariety of codimension , then we get that can only be constant map similarly.
Case II. is Grassmannian . We claim that the only morphisms are constant for any integer .
Lemma 3.1.
There are no nonconstant maps from to for any integer .
Proof.
Assume that we have a nonconstant morphism . Then there exists a maximal linear subspace such that restricts to it is also nonconstant. Denote by to be the restriction map. Let’s consider and (the pull back of universal bundle and universal quotient bundle under ). Denote by and the Chern classes of and , respectively, and by and the Chern classes of and , respectively.
On , we have an exact sequence
which is the pull back of the universal exact sequence
on . Then
i.e.
Since , obviously we have .
On the other hand, on , we also have an exact sequence
Then
i.e.
Combining the above equation and the nonconstant assumption, i.e.
we get and .
In order to show that this contradicts that , we need to use some Schubert classes in (see 8 Chapter 4). Let’s review some basic facts and fix some notation first. Choose a complete flag in , that is, a nested sequence of subspaces
with dim . For a sequence with , we define the Schubert cycle to be the closed subset
The class ia called Schubert class. By Theorem 4.1 in 8, is of codimension . To simplify notation, we generally suppress trailing zeros in the indices and write in place of . With this notation, can be represented as and we may write
where the s and s are non negative integers by the nefness of (the dual of ) and .
Pieri’s formula (see Proposition 4.9 in 8) tells us that for any integers with ,
Using Giambelli’s formula (see Proposition 4.16 in 8) for ’s, expanding the determinants and then intersecting with , we can immediately get the following identities:
Hence . But
where the summation is linear combination of Schubert cycles with non-negative coefficients by the Littlewood-Richardson formula. Therefore
a contradiction. ∎
When , . By the above Lemma, we obtain the only morphisms are constant for any integer .
When , . By the above Lemma, we obtain the only morphisms are constant for any integer . Remarkably, in these cases, the value of can be appropriately enlarged. Since is dimensional, we can easily know
and
Since the Picard number of is one, the only morphisms
and
are all constant for any integer .
Case III. is spinor variety . The Chow ring of is presented as a quotient of module the relations
for , where are the Schubert classes of codimension , and for or (see Section 3.2 in 26). In particular, for every . Hence, the only morphisms are constant for any integer . Remarkably, for , the value of can be appropriately enlarged. Due to the dimension of is , one can check that
and
Since the Picard number of is one, the only morphisms
and
are all constant for any integer .
Case IV. . The Chow ring of have the following form (see 7 Theorem 5). Let be the Schubert classes on . Then
where
Lemma 3.2.
There are no nonconstant maps from to for any integer .
Proof.
(i). . Since , by the proof of Lemma 3.4 in paper 18, the only morphisms are constant.
(ii). . Let be a morphism from to . On , we have an exact sequence
Then . According to the Chow ring of , we can expand the equation into the following form:
Since is freely generated by the classes , the above equation implies that the coefficient of is , i.e. . On the other hand, is freely generated by the classes , the above equation implies that the coefficient of is also zero, i.e. . Hence . Therefore, this case can boil down to case (i).
(iii). . By iterating the previous process, we get , i.e.
In a similar way, we can prove . Next, let’s consider the vanishing of . Since is freely generated by the classes , the above equation implies that the coefficient of is , i.e. . On the other hand, is freely generated by the classes , the above equation implies that the coefficient of is also zero, i.e. . Combining these equations with , we obtain that . Therefore, this case can boil down to case (i). ∎
Case V. . The Chow ring of have the following form (see 7 Theorem 6). Let be the Schubert classes on . Then
where
Lemma 3.3.
There are no nonconstant maps from to for any integer .
Proof.
(i). . Since , by the proof of Lemma 3.4 in paper 18, the only morphisms are constant.
(ii). . Let be a morphism from to . On , we have an exact sequence
Then . According to the Chow ring of , we can expand the equation into the following form:
Since is freely generated by the classes , the above equation implies that the coefficient of is , i.e. . On the other hand, is freely generated by the classes , the above equation implies that the coefficient of is also zero, i.e. . Hence . Therefore, this case can boil down to case (i).
(iii). . By iterating the previous process, we get , i.e.
In a similar way, we can prove . Next, let’s consider the vanishing of . Since is freely generated by the classes , the above equation implies that the coefficient of is , i.e. . On the other hand, is freely generated by the classes , the above equation implies that the coefficient of is also zero, i.e. . Hence, . Therefore, this case can boil down to case (i). ∎
Case VI. . The Chow ring of is
where are the Schubert classes on (see Section 3.1 in 26). Since for , the only morphisms are constant for any integer .
Summing up, we have obtained the following Table 2.
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Theorem 3.4.
Let be a uniform -bundle on a generalized Grassmannian with extremal node marked. If , then splits as a direct sum of line bundles.
Remark 3.5.
One can find the value of is equal to or bigger than the value of that we analyzed such that the morphism can only be constant. is equal to except and . The reason is that uniform bundles split on and uniform bundles split on by the previous arguments. In all cases, however, the morphism can only be constant.
Corollary 3.6.
If is a generalized Grassmannian with marked point , is not extremal, then is a product of rational homogeneous spaces. If
and
where is the special family of lines of class through on the generalized Grassmannian with extremal node marked. Then uniform -bundle on splits as a direct sum of line bundles.
Proof.
In order to prove splits, we just need to prove that the only morphisms are constant. Let be a morphism from to . Because every can be regarded as the subspace of corresponding to the special family of lines of class through on , we can consider the restriction of to . By assumption , all the restriction maps are constant. Hence, is also constant. ∎
Remark 3.7.
-
•
For the case where or , we can say nothing about the splitting result according to our theorem.
-
•
In some cases, the value of cannot be expanded anymore, which means that there exist uniform but nonsplitting -bundles. For instance, Grassmannian has uniform but nonsplitting -bundle (the universal bundle of ); Spinor variety has uniform but nonsplitting -bundle (the universal quotient bundle of ).
- •
Corollary 3.8.
Let be a generalized Grassmannian covered by linear projective subspaces of dimension and be an -bundle on . If splits as a direct sum of line bundles when it restricts to every , then splits as a direct sum of line bundles on .
Proof.
If is a projective space, then the result holds (23 Theorem 2.3.2). Suppose which is not a projective space and is the unique black node, where is a simple Lie group and is a maximal parabolic subgroup of . The condition implies that is uniform. The reason for this is the fact every line is contained in two different by Theorem 2.9.
We prove the corollary by induction on . If we have the exact sequence of vector bundles
(3.6) |
on , where the rank of and are smaller than , such that
for every , then by the induction hypothesis, and split. Since , the above exact sequence splits and hence also .
Similar to the proof of Theorem 3.3 in 6, on , we can obtain an exact sequence
If we prove that the morphism is constant for every , then there exist two bundles , over with . By projecting the bundle sequence
onto , we can get the desired exact sequence (3.6). Thus, to prove the existence of the above exact sequence, it suffices to show that the map
is constant for every . Given a projective subspace of dimension and a line , we take any point and denote by the subspace of corresponding to the tangent directions to at . By the hypothesis, is a direct sum of line bundles, so
is constant. Since covered by linear projective subspaces of dimension and is chain-connected by , is constant for every . ∎
3.2 Uniform vector bundles on rational homogeneous spaces
Let
where is a simple Lie group with Dynkin diagram whose set of nodes is and is a parabolic subgroup of corresponding to . We set by marking on the Dynkin diagram of the nodes corresponding to . Let be a node in and be the set of nodes in that are connected to .
If , we call
the -th special family of lines of class by Theorem 2.3, where and is by deleting -th term . For and , we will use the notation to denote the special family of lines of class .
For , we call
the -th special part of variety of minimal rational tangents at (sometimes we just write if there is no confusion).
Fix . is just the special family of lines of class through on the generalized Grassmannian whose Dynkin diagram is the maximal sub-diagram of with the only marked point . Denote . Let
Definition 3.9.
A vector bundle on is called poly-uniform with respect to for every and every if the restriction of to every line in has the same splitting type. We also call that poly-uniform with respect to all the special families of lines.
Let be a torsion free coherent sheaf of rank over . Fix integer and . Since the singularity set of has codimension at least , there are lines which do not meet . If
Let
which is independent of the choice of . We set
Definition 3.10.
A torsion free coherent sheaf over is -semistable (-stable) if for every coherent subsheaf with , we have
If is not -semistable, then we call is -unstable.
Proposition 3.11.
Fix integer and . Let be a uniform -bundle on of type with respect to . If and these ’s are not all same, then can be expressed as an extension of uniform bundles with respect to . In particular, is -unstable.
Proof.
After twisting with an appropriate line bundle, we can assume that has the splitting type
with respect to .
Let’s consider the standard diagram
(3.11) |
For , the -fiber
is mapped under to the line identically in and we have
For , the -fiber is mapped isomorphically under to the subvariety
Because
for all . Thus the direct image is a vector bundle of rank over . The canonical homomorphism of sheaves
makes to be a subbundle of . Because over each -fiber , the evaluation map
identifies with Over we thus obtain an exact sequence
of vector bundles, whose restriction to -fibers looks as follows:
Because is a subbundle of of rank , for every point , it provides a morphism
Since , morphism is constant by Remark 3.5 and the definition of . It follows that and are trivial on all -fibers. So the canonical morphisms and are isomorphisms. Hence there are uniform bundles , with respect to over with
By projection formula and the rationality of the fiber SPVMRTx, we project the bundle sequence
onto to get the exact sequence
(3.12) |
So and thus is -unstable ∎
Proposition 3.12.
On , if an -bundle is poly-uniform with respect to all the special families of lines on such that the splitting type with respect to is for each and , then splits as a direct sum of line bundles.
Proof.
After twisting with an appropriate line bundle, we can assume that is trivial on all the special families of lines on . We are going to show that is trivial.
Let’s first consider the case that is a generalized flag manifold, which corresponds to a connected marked Dynkin diagram with black nodes. We prove the lemma by induction on . For , is just a generalized Grassmannian. Then the result holds by 1 Proposition 1.2. Suppose the assertion is true for all generalized flag manifolds with connected marked Dynkin diagram and black nodes (). Let’s consider the natural projection
where is corresponding to the marked Dynkin diagram by changing the first black node to white. It’s not hard to see that every -fiber is isomorphic to the generalized Grassmannian with the only marked point . Since the restriction of to every line in is trivial, so is to every line in . Thus is trivial on all -fibers by 1 Proposition 1.2. It follows that is an algebraic vector bundle of rank over and .
Claim. is trivial on all the special families of lines on .
In fact, let be a black node in that is different from and be a line in . Then is a line in the family of lines of . When runs through all black nodes except and runs through all lines in in , also runs through all lines in all the special families of lines of . The projection induces an isomorphism
We identify with . Since is trivial for every line in by assumption, is trivial for every line in all the special families of lines of . By the induction hypothesis, is trivial. Thus is trivial.
Now let’s think about the general case, where the marked Dynkin diagram of is not connected. Assume can be decomposed into a product
where and is a simple Lie group with connected Dynkin diagram. We prove is trivial by induction on . For , the result holds from the previous analysis. Consider the natural projection
it’s easy to see that every -fiber is isomorphic to . By assumption, is trivial on all the special families of lines on . Thus is trivial on all -fibers by the previous analysis. It follows that is an algebraic vector bundle of rank over and . Similarly, we can prove that is trivial and thus is trivial. ∎
Theorem 3.13.
On , if -bundle is poly-uniform with respect to all the special families of lines and , then is -unstable for some () or splits as a direct sum of line bundles.
4 Semistable vector bundles on rational homogeneous spaces
Let be a simple Lie group and be the set of nodes of the Dynkin diagram of . Denote by the parabolic subgroup of corresponding to the node . Consider in its minimal homogeneous embedding. Denote by the generalized flag manifold defined by the marked Dynkin diagram and by the universal family, which has a natural -bundle structure over , i.e. we have the natural diagram:
(4.5) |
Given , coincides with by Remark 2.7 where the set of nodes of the Dynkin diagram is .
In the above setting, we will show that the splitting type of take the form , or . Building upon this assert, we will generalize the Grauert-Mlich-Barth theorem to any rational homogeneous spaces.
4.1 The classical simple Lie algebras
We say is of classical type when its Dynkin diagram is of type , , or . Because has clear geometric explanations, we can even write down the specific form of the relative tangent bundle . In the case of type , the relative tangent bundle is known (see 6 Lemma 5.6) and the splitting type of is . So let’s just consider the remaining three types.
4.1.1 The marked Dynkin diagram
In this section, we consider the Dynkin diagram , which corresponds to the classical Lie group . Denote by the generalized flag manifold with . Let be a vector space equipped with a nondegenerate symmetric bilinear form . Then is actually the odd Orthogonal flag manifold , which parametrizes flags
where each is an -dimensional isotropic subspace in .
There is a universal flag of subbundles
on , where is the -orthogonal complement of , rank and rank .
(1) For , the odd Orthogonal Grassmannian is just the quadric . In this case, and . We have the natural diagram
(4.10) |
and is , i.e. the quadric .
Lemma 4.1.
Let for . For the relative tangent bundle , we have
Proof.
For , the -fiber is isomorphic to . Over , we have the universal bundle sequence
(4.11) |
where is the rank 1 tautological bundle over , which is the pull back of under the embedding and denotes its -orthogonal complement. Notice that the tangent bundle of can be represented as
Let’s consider the exact sequence
of vector bundles on . By restricting it to the the -fiber , we obtain the universal bundle sequence (4.11) on . Therefore, and
∎
(2) For , the odd Orthogonal Grassmannian parametrizes the -dimensional isotropic subspaces in . In this case, and . We have the natural diagram:
(4.16) |
and is .
Lemma 4.2.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following two exact sequences of vector bundles:
We will consider the following diagram
(4.23) |
All the morphisms in the above diagram are projections. For any , the -fiber is isomorphic to and the -fiber is isomorphic to . Note that for , the projection induces an isomorphism
Hence . So we get
We mimic the proof of Lemma 5.6 in 6 to conclude that
Therefore, and
∎
(3) For (corresponding to the short root ), the odd Orthogonal Grassmannian parametrizes the -dimensional isotropic subspaces in . In this case, and . We have the natural diagram
(4.28) |
and is .
Lemma 4.3.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following exact sequence of vector bundles:
Restricting it to the -fiber is just the Euler sequence on . In fact, the projection identifies in a canonical fashion with the projective bundle of . Hence and
∎
4.1.2 The marked Dynkin diagram
In this section, we consider the Dynkin diagram , which corresponds to the classical Lie group . Denote by the generalized flag manifold with . Let be a vector space equipped with a nondegenerate skew-symmetric bilinear form . Then is actually the Lagrangian flag manifold , which parametrizing flags
where each is an -dimensional isotropic subspace in .
There is universal flag of subbundles
on , where is the -orthogonal complement of , rank and rank .
(1) For (corresponding to the short root ), the Lagrangian Grassmannian is just the projective space . In this case, and . We have the natural diagram
(4.33) |
and is , i.e. the the projective space .
Lemma 4.4.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following exact sequence of vector bundles:
Restricting it to the -fiber is just the Euler sequence on . In fact, the projection identifies in a canonical fashion with the projective bundle of . Hence and
∎
(2) For (corresponding to the short root ), the Lagrangian Grassmannian parametrizes the -dimensional isotropic subspaces in . In this case and . We have the natural diagram
(4.38) |
and is .
Lemma 4.5.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following two exact sequences of vector bundles:
We will consider the following diagram
(4.45) |
All the morphisms in the above diagram are projections. For any , the -fiber is isomorphic to and the -fiber is isomorphic to . Note that for , the projection induces an isomorphism
Hence . So we get
We mimic the proof of Lemma 5.6 in 6 to conclude that
Therefore, and
∎
(3) For (corresponding to the long root ), the Lagrangian Grassmannian parametrizes the -dimensional isotropic subspaces in . In this case and . We have the natural diagram
(4.50) |
and is .
Lemma 4.6.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following exact sequence of vector bundles:
Restricting it to the -fiber is just the Euler sequence on . In fact, the projection identifies in a canonical fashion with the projective bundle of . Hence and
∎
4.1.3 The marked Dynkin diagram
In this section, we consider the Dynkin diagram , it corresponds to the classical Lie group . Denote by the generalized flag manifold with . Let be a vector space equipped with a nondegenerate symmetric bilinear form . Then
Case 1. . is the even Orthogonal flag manifold which parametrizes two families of flags
where each is an -dimensional isotropic subspace in , and are the -dimensional isotropic subspaces in .
There are universal flags of subbundles
on , where rank and .
Case 2. or . is one of the two irreducible components of the even Orthogonal flag manifold , which parametrizes flag
where each is an -dimensional isotropic subspace in .
There is a universal flag of subbundles
on , where rank .
Case 3. . is actually the even Orthogonal flag manifold , which parametrizes flag
where each is an -dimensional isotropic subspace in .
There is a universal flag of subbundles
on , where is the -orthogonal complement of , rank and rank .
(1) For , the even Orthogonal Grassmannian parametrizes the -dimensional isotropic subspaces in . In this case, and , i.e. we have the natural diagram:
(4.55) |
and is .
Lemma 4.7.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following two exact sequences of vector bundles:
We will consider the following diagram
(4.62) |
All the morphisms in the above diagram are projections. For any , the -fiber is isomorphic to and the -fiber is isomorphic to . Note that for , the projection induces an isomorphism
Hence . So we get
We mimic the proof of Lemma 5.6 in 6 to conclude that
Therefore, and
∎
(2) For , the even Orthogonal Grassmannian parametrizes the -dimensional isotropic subspaces in . In this case and . We have the natural diagram
(4.67) |
and is .
Lemma 4.8.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following three exact sequences of vector bundles:
We will consider the following diagram
(4.74) |
All the morphisms in the above diagram are projections. For any , the -fiber is isomorphic to and the -fiber is isomorphic to . Note that for , the projection induces an isomorphism
Hence . So we get
We mimic the proof of Lemma 5.6 in 6 to conclude that
and
Therefore,
and ∎
(3) For or , is one of the two irreducible components of the even Orthogonal Grassmannian . In this case and . We have the natural diagram
(4.79) |
and is Grassmannian .
Lemma 4.9.
Let for . For the relative tangent bundle , we have
Proof.
It’s not hard to check that over , we have the following exact sequence of vector bundles
Restricting it to the -fiber is just the Euler sequence on . In fact, the projection identifies in a canonical fashion with the Grassmannian bundle of . Hence and
∎
4.2 The exceptional simple Lie algebra
We say is of exceptional type if its Dynkin diagram is of type , or . Due to the complexity of the geometry of , it is difficult to write down the specific form of the relative tangent bundle , so here we use the method in 17 to calculate the splitting type of .
When is simple, the fundamental root system will be written as in the standard reference 5. In the case of type, the mark of the nodes of the Dynkin diagam in the reference is different from our paper, so is the expression of the fundamental root system. So we write down the fundamental root system corresponding to the diagram of -type in our paper as follow:
Let be a real vector space with dim with orthogonal basis . Then the vectors
form a fundamental root system of type . Since can be identified canonically with subsystem of , so form a fundamental root system of type .
It’s well known that homogeneous vector bundles especially the tangent bundle on a rational homogeneous space are determined by representations of the Lie algebra . Restricting the relative tangent bundle to a line , we will get a flag bundle and with tag, where the tag is the set of intersection numbers of a minimal section of the associated -flag bundle with the relative canonical divisors (see 22 Proposition 3.17). We refer to 22, 20 for a complete account on the tag of a flag bundle. Assume () where is simple Lie group. Calculating weights that give the tangent bundle of , which are all the positive roots of the Lie algebra of that contain the root adjacent to . Putting together the above tag and weights, we will get the splitting type of . We refer to (20, page 5-7) for a complete account. By calculation, we have the tables (Table 3, 4, 5, 6) in Appendix.
Professor L. E. Solá Conde told us the following example for calculating the relative tangent bundle restricting to an isotropic line by personal correspondance.
Example 4.10.
Let and . Then . Let . The isotropic lines in are the image of the fibers of the -bundle
into via the natural map
Let be the relative anticanonical bundles of and be a fiber of . When mapped to the varieties of Picard number one ’s, ’s are the isotropic lines, where . The can be regarded as a minimal section of the fibration morphism when it restricts to . By 21 Proposition 2.13, the matrix is the Cartan matrix of . The tag is exactly
which is the -th column of the Cartan matrix without the last term and with the signs changed. The weights are coefficients of all the positive roots of the Lie algebra of in term of the linear combinations of the fundamental roots that contain the -th root as a summand; that is the roots of the form with , where ’s are the fundamental roots () (See Table 4 in Appendix for the values of ). So
Proposition 4.11.
Suppose to be of exceptional type and . Let for . When , has the following form respectively:
Otherwise
Summing up, we have obtained the following
Proposition 4.12.
Let be a simple Lie group with the Dynkin diagram and is a long root of . Denote by the generalized Grassmannian by marking on the node . Then for the relative tangent bundle (Notations as Section 4), we have
4.3 The generalization of the Grauert-Mlich-Barth theorem
The construction of subsheaves in holomorphic vector bundles plays an important role in the proof of the generalized Grauert-Mlich-Barth theorem. A generalization of the Grauert-Mlich-Barth theorem to normal projective varieties in characteristic zero is proved (see 13 Theorem 3.1.2). Since the theorem in the book is for any normal projective variety, the bound is pretty coarse. In this section, we will find the explicit bound for rational homogeneous spaces.
The following Descent Lemma provides a way for us to prove the existence of subsheaves.
Lemma 4.13.
(Descent Lemma 23) Let , be nonsingular varieties over , be a surjective submersion with connected fibers and be an algebraic -bundle over . Let be a subbundle of rank in and be its quotient. If
then is the form for some algebraic subbundle of rank .
Follow the previous notations. Let be a simple Lie group with the Dynkin diagram and is a root of . Let’s consider the standard diagram associated to
(4.84) |
Theorem 4.14.
Let be a generalized Grassmannian by marking on the node and be a long root of . Let be a holomorphic -bundle over of type . If for some ,
then there is a normal subsheaf of rank with the following properties: over the open set , where is an open set in , the sheaf is a subbundle of , which on the line given by has the form
Proof.
This theorem has far reaching consequences. We give first a series of immediate deductions.
Corollary 4.15.
Let be a generalized Grassmannian with long root . For a semistable -bundle over of type . we have
Proof.
If for some , we had , then we could find a normal subsheaf which is of the form
over the general line . Then we would have contrary to hypothesis. ∎
In particular, we get the generalization theorem of Grauert-Mlich-Barth :
Corollary 4.16.
Let be a generalized Grassmannian with long root . The splitting type of a semistable normalized 2-bundle over generalized Grassmannian is
Corollary 4.17.
Let be a generalized Grassmannian with long root . For a uniform -bundle over of type (see Section 3 for the notation )
which does not split, we have
Proof.
If for some , we had , then we could find a uniform subbundle of type which is of (because ). Then quotient bundle would be uniform of type . According to Theorem 3.4 the bundle and must be direct sums of line bundles. The exact sequence
would therefore split and hence would be a direct sum of line bundles contrary to hypothesis. ∎
When is a short root of , is not the variety of lines on , but only a closed -orbit. Therefore we’re just going to think about the splitting type and semistability of vector bundles with respect to .
Theorem 4.18.
Let be a generalized Grassmannian by marking on the node and be a short root of . Let be a holomorphic -bundle over of type with respect to . If for some ,
then there is a normal subsheaf of rank with the following properties: over the open set , where is an open set in , the sheaf is a subbundle of , which on the line given by has the form
Proof.
Similarly, we have the following corollary.
Corollary 4.19.
Let be a generalized Grassmannian with short root . For a semistable -bundle over of type with respect to . we have
In particular, if ,
From now, Let
where is a simple Lie group with Dynkin diagram whose set of nodes is and is a parabolic subgroup of corresponding to . We set by marking on the Dynkin diagram of the nodes corresponding to . Let be a node in and be the set of nodes in that are connected to .
If , we call
the -th special family of lines of class , where and is by deleting -th term . Denote by
the -th universal family of class , which has a natural -bundle structure over .
We separate our discussion into two cases:
Case I: , then and we have the natural projection ;
Case II: , then we have the standard diagram:
(4.89) |
Notice that for , coincides with where is the components of containing an element of by Theorem 2.6.
Let be a generalized Grassmannian whose Dynkin diagram is the maximal sub-diagram of with the only marked point . Let’s consider the standard diagram associated to
(4.94) |
It’s not hard to see that is isomorphic to for every and we have the following Lemma.
Lemma 4.20.
Let for . For the relative tangent bundle , we have
If is an exposed short root of , then is a short root of and vice versa. Combining this fact and the above Lemma, we get the following Proposition:
Proposition 4.21.
Let for . If is not an exposed short root, then for the relative tangent bundle , we have
Proof.
It’s obviously from Proposition 4.12. ∎
Similarly, by combining with Lemma 4.3, 4.4, 4.5, 4.20 and Proposition 4.11, we can immediately draw the following proposition.
Proposition 4.22.
Let for . If is an exposed short root, then for the relative tangent bundle , the splitting type of takes several forms: , , , or .
According to Theorem 2.3, 2.6, if is not an exposed short root, then is the space of of lines of class and is the space of lines of class through .
Using the above propositions, we have the similar results for rational homogeneous spaces.
Theorem 4.23.
Fix and assume that is not an exposed short root. Let be a holomorphic -bundle over of type with respect to . If for some ,
then there is a normal subsheaf of rank with the following properties: over the open set , where is an open set in , the sheaf is a subbundle of , which on the line given by has the form
Proof.
Corollary 4.24.
With the same assumption as Theorem 4.23. For a -semistable -bundle over of type with respect to , we have
In particular, if fits Case I, then we have ’s are constant for all .
When is an exposed short root of , is not the space of of lines of class , but only a closed -orbit.
Theorem 4.25.
Fix and assume that is an exposed short root. Let be a holomorphic -bundle over of type with respect to . If for some ,
then there is a normal subsheaf of rank with the following properties: over the open set , where is an open set in , the sheaf is a subbundle of , which on the line given by has the form
Proof.
Corollary 4.26.
For a -semistable -bundle over of type with respect to , we have
In particular, if fits Case I, then we have ’s are constant for all .
Corollary 4.27.
Let , where is a semi-simple Lie group and is a Borel subgroup of . If an -bundle is -semistable for all and over , then splits as a direct sum of line bundles.
Acknowledgements
We would like to show our great appreciation to professor B. Fu, L. Manivel, R. Muñoz, G. Occhetta, L. E. Solá Conde and K. Watanabe for useful discussions. In particular, we would like to thank professor L. E. Solá Conde for recommending us their interesting papers and explaining the details in their papers with patience, especially for the method of calculating the relative tangent bundles between two generalized flag manifolds.
5 Appendix
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