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Topologically and rationally slice knots

Jennifer Hom School of Mathematics, Georgia Institute of Technology [email protected] Sungkyung Kang Center for Geometry and Physics, Institute for Basic Science [email protected]  and  JungHwan Park Department of Mathematical Sciences, Korea Advanced Institute for Science and Technology [email protected]
Abstract.

A knot in S3S^{3} is topologically slice if it bounds a locally flat disk in B4B^{4}. A knot in S3S^{3} is rationally slice if it bounds a smooth disk in a rational homology ball. We prove that the smooth concordance group of topologically and rationally slice knots admits a \mathbb{Z}^{\infty} subgroup. All previously known examples of knots that are both topologically and rationally slice were of order two. As a direct consequence, it follows that there are infinitely many topologically slice knots that are strongly rationally slice but not slice.

Key words and phrases:
Topologically slice, rationally slice, involutive knot Floer homology
2020 Mathematics Subject Classification:
57K10, 57K18

1. Introduction

The smooth concordance group of topologically slice knots contains a (/2)\mathbb{Z}^{\infty}\oplus(\mathbb{Z}/2\mathbb{Z})^{\infty} subgroup; the existence of a \mathbb{Z}^{\infty} subgroup was first proved by Endo in 1995 using gauge theory [End95], while the existence of a (/2)(\mathbb{Z}/2\mathbb{Z})^{\infty} subgroup was not proved until nearly 20 years later, using Heegaard Floer homology [HKL16]. Both of these proofs rely on Freedman’s landmark result [Fre82] that any knot with Alexander polynomial 1 is topologically slice.

Similarly, the smooth concordance group of rationally slice knots also contains a (/2)\mathbb{Z}^{\infty}\oplus(\mathbb{Z}/2\mathbb{Z})^{\infty} subgroup. However, our understanding of rationally slice knots proceeded in the opposite direction: the proof of the (/2)(\mathbb{Z}/2\mathbb{Z})^{\infty} subgroup [Cha07] preceded the proof of the \mathbb{Z}^{\infty} subgroup [HKPS22] by 15 years. For their obstructive side, the former proof relies on J. Levine’s algebraic concordance group [Lev69] while the latter relies on involutive Heegaard Floer homology [HM17]. For their constructive side, they use the fact that the figure-eight knot is rationally slice and generalize its proof. This fact was observed by Cochran using work of Fintushel-Stern [FS84].

What about knots that are both topologically and rationally slice?

  • Rationally slice but not slice: The knots in [Cha07] are not topologically slice, as they are not even algebraically slice. Similarly, the generating set for the \mathbb{Z}^{\infty} subgroup in [HKPS22] are not algebraically slice either.

  • Topologically slice but not slice: The knots representing the (/2)(\mathbb{Z}/2\mathbb{Z})^{\infty} subgroup of [HKL16] can be shown to be rationally slice by a straightforward modification of the proof of [Cha07, Theorem 4.16]. The generating set for Endo’s family [End95] (the pretzel knots P(2k1,4k+1,4k+3)P(-2k-1,4k+1,4k+3) for k1k\geq 1) are not rationally slice. There are more topologically slice knots in the literature and many of them are known to be not rationally slice (see e.g. [Hom15, OSS17, KP18, FPR19, DHST21]) and some of them are not known to be rationally slice or not (see e.g. [HK12, CHH13, CK21, Cha21, KKK22]).

Note that all previously known examples of knots that are both topologically and rationally slice have order two in the smooth concordance group. The goal of this paper is to show that the smooth concordance group of topologically and rationally slice knots does in fact contain a (/2)\mathbb{Z}^{\infty}\oplus(\mathbb{Z}/2\mathbb{Z})^{\infty} subgroup. For any knot KK, let Wh+(K)\mathrm{Wh}^{+}(K) denote the positive Whitehead double of KK, and Kp,1K_{p,-1} denote the (p,1)(p,-1)-cable of KK.

Theorem 1.1.

Denote by the right-handed trefoil and the figure-eight knot by TT and EE, respectively. Then every knot in the family

{Kn:=(Wh+(T)#E)2n+1,1#(Wh+(T))2n+1,1#E2n+1,1n>0}\left\{K_{n}:=(\mathrm{Wh}^{+}(T)\#E)_{2n+1,-1}\#-(\mathrm{Wh}^{+}(T))_{2n+1,-1}\#-E_{2n+1,-1}\mid n>0\right\}

is topologically and rationally slice, and has infinite order in the smooth concordance group. Furthermore, the given family admits a linearly independent infinite subset of the smooth concordance group.

As mentioned in Theorem 1.1, the knots KnK_{n} are topologically and rationally slice. Indeed, up to topological concordance, we may ignore Wh+(T)\mathrm{Wh}^{+}(T), resulting in E2n+1,1#E2n+1,1E_{2n+1,-1}\#-E_{2n+1,-1}, which is clearly slice. Similarly, up to rational concordance, we may ignore EE, which also results in a slice knot. Our family of knots exploits the fact that cabling does not induce a homomorphism on the concordance group; see [HPC21] for further discussion of satellite operators and the concordance group.

We may naturally interpret our main theorem as follows. Let 𝒯\mathcal{T} be the smooth concordance group of topologically slice knots and 𝒯\mathcal{T}_{\mathbb{Q}} be the smooth rational concordance group of topologically slice knots. Since two concordant knots are rationally concordant, we have the following natural surjective homomorphism:

ψ𝒯:𝒯𝒯.\psi_{\mathcal{T}}\colon\mathcal{T}\to\mathcal{T}_{\mathbb{Q}}.

Note that the main theorem of [HKL16] implies that kerψ𝒯\ker\psi_{\mathcal{T}} contains infinitely many order two elements. As a direct corollary of our main theorem, we have the following:

Corollary 1.2.

The group kerψ𝒯\ker\psi_{\mathcal{T}} contains a subgroup isomorphic to \mathbb{Z}^{\infty}.

Furthermore, the knots in 1.1 can be used to prove the existence of a knot which is topologically slice and strongly rationally slice but not slice. Strongly rationally slice knots are knots KK which bound a smoothly embedded disk Δ\Delta in a rational homology ball XX such that the inclusion induces an isomorphism

H1(S3K;)H1(XΔ;)/torsion.H_{1}(S^{3}-K;\mathbb{Z})\xrightarrow{\cong}H_{1}(X-\Delta;\mathbb{Z})/\text{torsion}.

The question of distinguishing strongly rationally slice knots from slice knots is very subtle; the first example of such a knot was found in [KP22]. By directly applying the proof of [KP22, Theorem 1.4] to the knots in 1.1, we immediately get the following corollary.

Corollary 1.3.

Let {Kn}\{K_{n}\} be the knots in 1.1. Then each (Kn)2,1(K_{n})_{2,1} is topologically and strongly rationally slice, and has infinite order in the smooth concordance group.

Recall that there exists a natural surjective homomorphism ψ:𝒞𝒞\psi\colon\mathcal{C}\to\mathcal{C}_{\mathbb{Q}} defined from the smooth concordance group to the smooth rational concordance group. As its counterpart in the topological category, we can also consider the map

ψtop:𝒞top𝒞top\psi^{\text{top}}\colon\mathcal{C}^{\text{top}}\to\mathcal{C}_{\mathbb{Q}}^{\text{top}}

defined from the topological concordance group to the topological rational concordance group. Even though we know that there are subgroups (/2)\mathbb{Z}^{\infty}\oplus(\mathbb{Z}/2\mathbb{Z})^{\infty} in kerψ\ker\psi and (/2)(\mathbb{Z}/2\mathbb{Z})^{\infty} in kerψtop\ker\psi^{\text{top}} [Cha07, HKPS22], the existence of an infinite order element in kerψtop\ker\psi^{\text{top}} is still not known. Hence, we ask:

Question 1.4.

Does there exist an infinite order element in kerψtop\ker\psi^{\text{top}}?

Lastly, we make a remark that the positive Whitehead double of the figure-eight knot is also a good candidate that is likely to have infinite order in kerψ𝒯\ker\psi_{\mathcal{T}}. To the best of the authors’ knowledge it is not even known if this knot is slice or not. Here, we ask:

Question 1.5.

Is the subgroup generated by Wh+(E)\mathrm{Wh}^{+}(E) in kerψ𝒯\ker\psi_{\mathcal{T}} isomorphich to \mathbb{Z}? More specifically, is Wh+(E)\mathrm{Wh}^{+}(E) slice?

1.1. Proof outline

For the reader’s convenience, we now provide a brief overview of the proof strategy. The proof relies on bordered and involutive knot Floer homology, using several tricks and techniques along the way to ease the calculations as much as possible.

  1. (1)

    Up to ιK\iota_{K}-local equivalence, we can replace Wh+(T)\mathrm{Wh}^{+}(T) by T#ET\#E (Lemma 4.3).

  2. (2)

    There is a (non-involutive) inclusion map

    iT:CFD^(S3T)CFD^(S3(T#E)).i_{T}:\widehat{CFD}(S^{3}-T)\rightarrow\widehat{CFD}(S^{3}-(T\#E)).

    Using Zhan’s bordered Floer homology calculator [Zha], we determine that certain type-D morphisms are nullhomotopic (Lemmas 4.1 and 4.2), allowing us to conclude that iTi_{T} induces an almost ιK\iota_{K}-local map from the almost ιK\iota_{K}-complex of the (2n+1,1)(2n+1,-1)-cable of TT to that of T#ET\#E (or equivalently that of Wh+(T)\mathrm{Wh}^{+}(T), as in Equation 4.1).

  3. (3)

    We combine the result from (2) with results from [KP22] to compare our knots KnK_{n} to certain standard complexes CnC_{n}, with respect to the partial order on the horizontal almost ιK\iota_{K}-local equivalence group (described in Section 2). Using properties of how the CnC_{n} interact with the partial order, we arrive at the desired linear independence result.

Acknowledgements

The authors would like to thank Gary Guth for his help on using Zhan’s bordered Floer homology calculator. JH was partially supported by NSF grant DMS-2104144 and a Simons Fellowship. SK was supported by the Institute for Basic Science (IBS-R003-D1). JP was partially supported by Samsung Science and Technology Foundation (SSTF-BA2102-02) and the POSCO TJ Park Science Fellowship.

2. The horizontal almost ιK\iota_{K}-local equivalence group

We assume that the reader is familiar with involutive knot Floer homology [HM17] and the ιK\iota_{K}-local equivalence group [HMZ18]. See [HKPS22, Section 2] for an expository overview of these concepts. In this paper, we focus on the horizontal almost ιK\iota_{K}-local equivalence group, which has the advantage that, modulo the image of the figure eight knot, it is totally ordered. What follows is a short summary of [KP22, Section 2].

A horizontal almost ιK\iota_{K}-complex is a pair (C,ι)(C,\iota) of a bigraded complex CC of finitely generated free modules over 𝔽2[U]\mathbb{F}_{2}[U] and a chain homotopy equivalence ι:C^C^\iota\colon\widehat{C}\rightarrow\widehat{C}, where C^\widehat{C} is the hat-flavored truncation of CC, such that the following conditions are satisfied.

  • The formal variable UU has bigrading (2,0)(-2,0).

  • U1C𝔽2[U,U1]U^{-1}C\simeq\mathbb{F}_{2}[U,U^{-1}]

  • ι\iota is skew-graded, i.e. maps a (a,b)(a,b)-bigraded element to a (b,a)(b,a)-bigraded one.

  • ΦιΦιιΦιΦ\Phi\iota\Phi\iota\sim\iota\Phi\iota\Phi.

  • ι21+ΦιΦι\iota^{2}\sim 1+\Phi\iota\Phi\iota.

  • There exists a chain map f:CCf\colon C\rightarrow C whose hat-flavored truncation is homotopic to ιΦι\iota\Phi\iota.

Here, Φ\Phi denotes the formal derivative of the differential of CC with respect to the formal variable UU, which is a chain map which is well-defined up to homotopy.

A degree-preserving chain map f:CDf\colon C\rightarrow D between horizontal almost ιK\iota_{K}-complexes (C,ιC)(C,\iota_{C}) and (D,ιD)(D,\iota_{D}) is almost ιK\iota_{K}-local map if it satisfies the following conditions.

  • ff is local, i.e. the localized map U1f:U1CU1DU^{-1}f\colon U^{-1}C\rightarrow U^{-1}D is a homotopy equivalence.

  • ιCf^f^ιD\iota_{C}\widehat{f}\sim\widehat{f}\iota_{D}, where f^\widehat{f} is the hat-flavored truncation of ff.

Furthermore, if there exist almost ιK\iota_{K}-local maps f:CDf\colon C\rightarrow D and g:DCg:D\rightarrow C, then we say that (C,ιC)(C,\iota_{C}) and (D,ιD)(D,\iota_{D}) are almost ιK\iota_{K}-locally equivalent.

We denote the almost ιK\iota_{K}-local equivalence classes of horizontal almost ιK\iota_{K}-complexes by KU\mathfrak{I}^{U}_{K}. We endow this set with a tensor product operation \otimes as (C,ιC)(D,ιD)=(CD,ιCD)(C,\iota_{C})\otimes(D,\iota_{D})=(C\otimes D,\iota_{C\otimes D}), where ιCD\iota_{C\otimes D} is defined as ιCD=ιCιD+ΦιCιDΦ\iota_{C\otimes D}=\iota_{C}\otimes\iota_{D}+\Phi\iota_{C}\otimes\iota_{D}\Phi. Although this operation is nonsymmetric, the group KU\mathfrak{I}^{U}_{K} is indeed abelian [KP22, Proposition 2.6].

The involutive knot Floer homology package associates to a knot KK a well-defined element in KU\mathfrak{I}^{U}_{K}, given by the chain complex CFK(S3,K)CFK^{-}(S^{3},K), together with the ιK\iota_{K}-action on CFK^(S3,K)\widehat{CFK}(S^{3},K). For simplicity, we denote this element as [K][K]. It is clear that this defines a group homomorphism

𝒞KU,\mathcal{C}\rightarrow\mathfrak{I}^{U}_{K},

where 𝒞\mathcal{C} is the smooth concordance group. The image of the unknot is denoted by 0KU0\in\mathfrak{I}^{U}_{K}.

Notice that the existence of almost ιK\iota_{K}-local map gives a partial order on KU\mathfrak{I}^{U}_{K}. In particular, we say that CDC\leq D if there exists an almost ιK\iota_{K}-local map CDC\rightarrow D. It turns out that this is actually a total order KU\mathfrak{I}^{U}_{K}, modulo the figure-eight complex [E][E], i.e. the 2-torsion element induced by the involutive knot Floer homology of the figure-eight knot EE. In other words, two elements C,DKUC,D\in\mathfrak{I}^{U}_{K} are incomparable if and only if C=D+[E]C=D+[E] [KP22, Theorem 2.11]. We will exploit this ordering to prove the main theorem.

3. Lemmas from involutive bordered Floer homology

We assume that the reader is familiar with standard materials in bordered Heegaard Floer homology, in particular the materials in [LOT18].

For simplicity, from now on, we will denote the \infty-framed solid torus, as a bordered manifold, as TT_{\infty}. Given a pattern PTP\subset T_{\infty}, we can define the minus-flavored type-A module CFA(T,P)CFA^{-}(T_{\infty},P), which is a type-A structure over the torus algebra 𝒜(T2)\mathcal{A}(T^{2}) with the coefficient ring 𝔽2[U]\mathbb{F}_{2}[U]. We denote its truncation by U=0U=0 as CFA^(T,P)\widehat{CFA}(T_{\infty},P). Furthermore, we can also remove a tubular neighborhood of PP from TT_{\infty} and endow the newly created torus boundary with the 0-framing; this defines a bordered manifold with two torus boundaries, whose type-DA bordered Floer homology is denoted as CFDA^(TP)\widehat{CFDA}(T_{\infty}-P). Note that we have

CFD^(S3P(K))CFDA^(TP)CFD^(S3K)\widehat{CFD}(S^{3}-P(K))\simeq\widehat{CFDA}(T_{\infty}-P)\boxtimes\widehat{CFD}(S^{3}-K)

via standard gluing formulae.

We will denote the longitudinal knot inside TT_{\infty} by ν\nu. In particular, we have a gluing formula [LOT18, Theorem 11.29]:

CFK(S3,K)CFA(T,ν)CFD^(S3K),CFK^{-}(S^{3},K)\simeq CFA^{-}(T_{\infty},\nu)\boxtimes\widehat{CFD}(S^{3}-K),

where CFKCFK^{-} denotes the truncation of CFKUV(S3,K)CFK_{UV}(S^{3},K) by V=0V=0. Note that we can also apply the gluing formula to get an identification

CFA(T,P)CFA(T,ν)CFDA^(TP).CFA^{-}(T_{\infty},P)\simeq CFA^{-}(T_{\infty},\nu)\boxtimes\widehat{CFDA}(T_{\infty}-P).

Given a bordered manifold MM with one torus boundary, its type-D bordered involution takes the form

ιM:CFDA^(𝐀𝐙)CFD^(M)CFD^(M),\iota_{M}:\widehat{CFDA}(\mathbf{AZ})\boxtimes\widehat{CFD}(M)\rightarrow\widehat{CFD}(M),

where 𝐀𝐙\mathbf{AZ} denotes the Auroux-Zarev piece, defined in [LOT11, Section 4]. Although ιM\iota_{M} is not well-defined up to homotopy due to the lack of naturality in bordered Floer homology, it is still a homotopy equivalence, and we will not need its uniquenss anyway. We denote the set of homotopy classes of all possible type-D bordered involutions of MM by 𝐈𝐧𝐯D(M)\mathbf{Inv}_{D}(M).

The following lemma follows from the proof of [KP22, Theorem 4.5]. Its proof is straightforward from the discussions preceding the proof of [Kan22, Theorem 1.2], so we omit it for the sake of simplicity.

Lemma 3.1.

Given two knots K1,K2K_{1},K_{2}, let f:CFD^(S3K1)CFD^(S3K2)f\colon\widehat{CFD}(S^{3}-K_{1})\rightarrow\widehat{CFD}(S^{3}-K_{2}) be a type-D morphism. Given a pattern PTP\subset T_{\infty}, consider the induced type-D morphism P(f):CFD^(S3P(K1))CFD^(S3P(K2))P(f)\colon\widehat{CFD}(S^{3}-P(K_{1}))\rightarrow\widehat{CFD}(S^{3}-P(K_{2})), defined as

CFD^(S3P(K1))CFDA^(TP)CFD^(S3K1)idCFDA^(TP)fCFDA^(TP)CFD^(S3K2)CFD^(S3P(K2)).\begin{split}\widehat{CFD}(S^{3}-P(K_{1}))&\simeq\widehat{CFDA}(T_{\infty}-P)\boxtimes\widehat{CFD}(S^{3}-K_{1})\\ &\xrightarrow{\mathrm{id}_{\widehat{CFDA}(T_{\infty}-P)}\boxtimes f}\widehat{CFDA}(T_{\infty}-P)\boxtimes\widehat{CFD}(S^{3}-K_{2})\simeq\widehat{CFD}(S^{3}-P(K_{2})).\end{split}

Then we have

ιS3P(K2)(idCFDA^(𝐀𝐙)P(f))ιS3P(K1)1P(ιS3K2(idCFDA^(𝐀𝐙)f)ιS3K11)\iota_{S^{3}-P(K_{2})}\circ\left(\mathrm{id}_{\widehat{CFDA}(\mathbf{AZ})}\boxtimes P(f)\right)\circ\iota^{-1}_{S^{3}-P(K_{1})}\sim P\left(\iota_{S^{3}-K_{2}}\circ\left(\mathrm{id}_{\widehat{CFDA}(\mathbf{AZ})}\boxtimes f\right)\circ\iota^{-1}_{S^{3}-K_{1}}\right)

for suitable choices of bordered involutions ιS3P(Ki)𝐈𝐧𝐯D(S3P(Ki))\iota_{S^{3}-P(K_{i})}\in\mathbf{Inv}_{D}(S^{3}-P(K_{i})) and ιS3Ki𝐈𝐧𝐯D(S3Ki)\iota_{S^{3}-K_{i}}\in\mathbf{Inv}_{D}(S^{3}-K_{i}) for each i{1,2}i\in\{1,2\}.

4. Proof of the main theorem

We start with several explicit computations of bordered Floer homology modules. Given any knot KK in S3S^{3}, the type-D module CFD^(S3K)\widehat{CFD}(S^{3}-K) can be easily computed from the knot Floer chain complex CFKUV(S3,K)CFK_{UV}(S^{3},K). For example, for the right-handed trefoil TT, the type-D module CFD^(S3T)\widehat{CFD}(S^{3}-T) for the 0-framed complement of TT can be described as follows:

s1\textstyle{s_{1}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ1\scriptstyle{\rho_{1}}t1\textstyle{t_{1}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2\scriptstyle{\rho_{2}}s2\textstyle{s_{2}\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ3\scriptstyle{\rho_{3}}ρ1\scriptstyle{\rho_{1}}t4\textstyle{t_{4}}t2\textstyle{t_{2}}t3\textstyle{t_{3}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ23\scriptstyle{\rho_{23}}s3\textstyle{s_{3}\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ3\scriptstyle{\rho_{3}}ρ123\scriptstyle{\rho_{123}}

Similarly, we can also describe CFD^(S3E)\widehat{CFD}(S^{3}-E) for the 0-framed complement of the figure-eight knot EE, as shown below. We will call its summand generated by a,b,c,e,y1,y2,y3,y4a,b,c,e,y_{1},y_{2},y_{3},y_{4} as the square-module, and denote it by SS.

b\textstyle{b\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ1\scriptstyle{\rho_{1}}y1\textstyle{y_{1}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2\scriptstyle{\rho_{2}}a\textstyle{a\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ3\scriptstyle{\rho_{3}}ρ1\scriptstyle{\rho_{1}}y2\textstyle{y_{2}}y4\textstyle{y_{4}}\textstyle{\oplus}z\textstyle{z\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ12\scriptstyle{\rho_{12}}e\textstyle{e\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ123\scriptstyle{\rho_{123}}y3\textstyle{y_{3}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2\scriptstyle{\rho_{2}}c\textstyle{c\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ3\scriptstyle{\rho_{3}}ρ123\scriptstyle{\rho_{123}}

We will also need the (hat-flavored) type-A module CFA^(T,P2n+1,1)\widehat{CFA}(T_{\infty},P_{2n+1,-1}) of the (2n+1,1)(2n+1,-1)-cabling pattern in the \infty-framed solid torus TT_{\infty}, which is shown below. Note that CFA(T,P2n+1,1)CFA^{-}(T_{\infty},P_{2n+1,-1}) was computed originally in [OSS17, Lemma 8.3]; we simply truncated their computation by taking U=0U=0.

a2n+1\textstyle{a_{2n+1}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2\scriptstyle{\rho_{2}}a2n\textstyle{a_{2n}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2,ρ1\scriptstyle{\rho_{2},\rho_{1}}\textstyle{\cdots\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2,ρ1\scriptstyle{\rho_{2},\rho_{1}}a2\textstyle{a_{2}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2,ρ1\scriptstyle{\rho_{2},\rho_{1}}a1\textstyle{a_{1}\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ2,ρ1\scriptstyle{\rho_{2},\rho_{1}}w\textstyle{w\ignorespaces\ignorespaces\ignorespaces\ignorespaces}ρ3\scriptstyle{\rho_{3}}b2n+1\textstyle{b_{2n+1}}b2n\textstyle{b_{2n}}\textstyle{\cdots}b2\textstyle{b_{2}}b1\textstyle{b_{1}}

Based on these computations, we will now prove two computational lemmas, which play a crucial role in the proof of 1.1.

Lemma 4.1.

Any type-D morphism from CFD^(S3T)\widehat{CFD}(S^{3}-T) to the square-summand SS becomes nullhomotopic after box-tensored with the identity morphism of CFA^(T,P2n+1,1)\widehat{CFA}(T_{\infty},P_{2n+1,-1}) for any positive integer nn.

Proof.

Zhan’s bordered Floer homology calculator [Zha] tells us that the space HMor(CFD^(S3T),S)H_{\ast}\mathrm{Mor}(\widehat{CFD}(S^{3}-T),S) of homotopy classes of type-D morphisms from CFD^(S3T)\widehat{CFD}(S^{3}-T) to SS is six-dimensional, generated over 𝔽2\mathbb{F}_{2} by f1,f2,f3,g1,g2,g3f_{1},f_{2},f_{3},g_{1},g_{2},g_{3}, which are defined as follows.

f1:s2e,t2ρ23y2,f2:s1e,s2c,t2ρ23y4,t4ρ23y2,f3:s2b,s3e,t2ρ23y2,g1:s3ρ3y1,g2:s3ρ3y3,g3:s1ρ1y4.\begin{split}f_{1}&:s_{2}\mapsto e,\,t_{2}\mapsto\rho_{23}y_{2},\\ f_{2}&:s_{1}\mapsto e,\,s_{2}\mapsto c,\,t_{2}\mapsto\rho_{23}y_{4},\,t_{4}\mapsto\rho_{23}y_{2},\\ f_{3}&:s_{2}\mapsto b,\,s_{3}\mapsto e,\,t_{2}\mapsto\rho_{23}y_{2},\\ g_{1}&:s_{3}\mapsto\rho_{3}y_{1},\\ g_{2}&:s_{3}\mapsto\rho_{3}y_{3},\\ g_{3}&:s_{1}\mapsto\rho_{1}y_{4}.\end{split}

Thus, to prove the lemma, we only have to show that these six morphisms become nullhomotopic after box-tensored with idCFA^(T,P2n+1,1)\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}. For simplicity, we will use the following convention: a chain complex CC over 𝔽2\mathbb{F}_{2} has an acyclic summand (:ab)(\partial\colon a\rightarrow b) if aa and bb generate a direct summand of CC and a=b\partial a=b.

We start with the map f1f_{1}. The only simple tensors (of basis elements) on which idCFA^(T,P2n+1,1)f1\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{1} takes nontrivial values are ws2w\otimes s_{2} and a2n+1t2a_{2n+1}\otimes t_{2}. In particular, we have

(idCFA^(T,P2n+1,1)f1)(ws2)=weand(idCFA^(T,P2n+1,1)f1)(a2n+1t2)=b2n+1y2.\left(\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{1}\right)(w\otimes s_{2})=w\otimes e\quad\text{and}\quad\left(\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{1}\right)(a_{2n+1}\otimes t_{2})=b_{2n+1}\otimes y_{2}.

However, ws2w\otimes s_{2} is contained in the acyclic summand (:ws2b2n+1t1)(\partial\colon w\otimes s_{2}\rightarrow b_{2n+1}\otimes t_{1}) and b2n+1y2b_{2n+1}\otimes y_{2} is contained in the acyclic summand (:a2ny3b2n+1y2)(\partial\colon a_{2n}\otimes y_{3}\rightarrow b_{2n+1}\otimes y_{2}). Thus idCFA^(T,P2n+1,1)f1\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{1} is nullhomotopic.

For f2f_{2}, the map idCFA^(T,P2n+1,1)f2\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{2} takes nontrivial values only on ws1w\otimes s_{1}, a2n+1t1a_{2n+1}\otimes t_{1} (which are both mapped to wew\otimes e), and ws2w\otimes s_{2}. But wew\otimes e and ws2w\otimes s_{2} are contained in the acyclic summands (:a2n+1y3we)(\partial\colon a_{2n+1}\otimes y_{3}\rightarrow w\otimes e) and (:ws2b2n+1t1)(\partial\colon w\otimes s_{2}\rightarrow b_{2n+1}\otimes t_{1}), respectively. Thus idCFA^(T,P2n+1,1)f2\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{2} is nullhomotopic.

Similarly, the map idCFA^(T,P2n+1,1)f3\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{3} takes nontrivial values on ws2w\otimes s_{2} and ws3w\otimes s_{3}, which are contained in the acylic summands (:ws2b2n+1t1)(\partial\colon w\otimes s_{2}\rightarrow b_{2n+1}\otimes t_{1}) and (:ws3b2n+1t3)(\partial\colon w\otimes s_{3}\rightarrow b_{2n+1}\otimes t_{3}). Hence idCFA^(T,P2n+1,1)f3\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes f_{3} is also nullhomotopic.

For the maps g1g_{1} and g2g_{2}, the only simple tensor on which idCFA^(T,P2n+1,1)gi\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes g_{i} takes a nontrivial value for i=1,2i=1,2 is ws3w\otimes s_{3}, on which idCFA^(T,P2n+1,1)gi\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes g_{i} takes the value b2n+1y1b_{2n+1}\otimes y_{1} for i=1i=1 and b2n+1y3b_{2n+1}\otimes y_{3} for i=2i=2. But the former is contained in the acyclic summand (:wab2n+1y1)(\partial\colon w\otimes a\rightarrow b_{2n+1}\otimes y_{1}) and the latter is contained in the acyclic summand (:wcb2n+1y3)(\partial\colon w\otimes c\rightarrow b_{2n+1}\otimes y_{3}). Hence idCFA^(T,P2n+1,1)gi\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes g_{i} is nullhomotopic for i=1,2i=1,2.

It remains to show that idCFA^(T,P2n+1,1)g3\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes g_{3} is nullhomotopic. The complete list of its nontrivial values is given as follows:

a1t1a2y4,,a2nt1a2n+1y4.a_{1}\otimes t_{1}\mapsto a_{2}\otimes y_{4},\cdots,\,a_{2n}\otimes t_{1}\mapsto a_{2n+1}\otimes y_{4}.

But for each i{1,,2n}i\in\{1,\cdots,2n\}, we have that ait1a_{i}\otimes t_{1} is contained in the acyclic summand (:ait1ai+1t4)(\partial\colon a_{i}\otimes t_{1}\rightarrow a_{i+1}\otimes t_{4}), and thus idCFA^(T,P2n+1,1)g3\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes g_{3} is also nullhomotopic. ∎

Recall that bordered Heegaard Floer homology comes with gradings by nonabelian groups; given a bordered 3-manifold YY with boundary 𝒵\mathcal{Z}, the associated type-D module CFD^(Y)\widehat{CFD}(Y) is graded by a transitive G(𝒵)G(\mathcal{Z})-set. Hence the notion of degree-preserving endomorphisms of CFD^(Y)\widehat{CFD}(Y) is well-defined. See [LOT18, Chapter 10] for a detailed description of gradings in bordered Floer homology.

Lemma 4.2.

Let ff be a degree-preserving endomorphism of CFD^(S3T)\widehat{CFD}(S^{3}-T). Then ff is either nullhomotopic or homotopic to the identity morphism.

Proof.

One can use Zhan’s bordered Floer homology calculator to show that the space HEnd(CFD^(S3T))H_{\ast}\mathrm{End}(\widehat{CFD}(S^{3}-T)) is six-dimensional, generated by the identity morphism and the morphisms h1,,h5h_{1},\cdots,h_{5} described below.

h1:s1ρ3t4,s2s3,t1t3,t2ρ23t2,h2:s2s1,s3ρ1t3,t2ρ23t4,h3:s1ρ1t2,h4:s2ρ1t2,h5:s3ρ3t1.\begin{split}h_{1}&:s_{1}\mapsto\rho_{3}t_{4},\,s_{2}\mapsto s_{3},\,t_{1}\mapsto t_{3},\,t_{2}\mapsto\rho_{23}t_{2},\\ h_{2}&:s_{2}\mapsto s_{1},\,s_{3}\mapsto\rho_{1}t_{3},\,t_{2}\mapsto\rho_{23}t_{4},\\ h_{3}&:s_{1}\mapsto\rho_{1}t_{2},\\ h_{4}&:s_{2}\mapsto\rho_{1}t_{2},\\ h_{5}&:s_{3}\mapsto\rho_{3}t_{1}.\end{split}

It is straightforward to see that h1,,h5h_{1},\cdots,h_{5} are not degree-preserving. Therefore the space of degree-preserving type-D endomorphisms of CFD^(S3T)\widehat{CFD}(S^{3}-T) is one-dimensional and generated by the identity morphism. ∎

We need one more lemma regarding the ιK\iota_{K}-local equivalence class of the involutive knot Floer homology of Wh+(T)\mathrm{Wh}^{+}(T), which we will denote as DD for simplicity.

Lemma 4.3.

The ιK\iota_{K}-complex of DD is ιK\iota_{K}-locally equivalent to the knot Floer complex of the twist knot 525_{2}, or equivalently, T#ET\#E.

Proof.

It follows from the proof of [HKL16, Lemma A.1] that we have

CFKUV(S3,D)CFKUV(S3,T)A3,CFK_{UV}(S^{3},D)\simeq CFK_{UV}(S^{3},T)\oplus A^{\oplus 3},

where AA is a unit box summand, as shown below.

β\textstyle{\beta\ignorespaces\ignorespaces\ignorespaces\ignorespaces}V\scriptstyle{V}α\textstyle{\alpha\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces\ignorespaces}U\scriptstyle{U}V\scriptstyle{V}δ\textstyle{\delta}γ\textstyle{\gamma\ignorespaces\ignorespaces\ignorespaces\ignorespaces}U\scriptstyle{U}

We follow the general strategy of the proof of [HM17, Proposition 8.1], noting that in this case, our knot is not thin. In particular, the proof uniquely determines ιKmod(U,V)\iota_{K}\mod(U,V) up to chain homotopy, which we summarize in the following table. Note that we have three copies of AA; we denote their generators as αi,βi,γi,δi\alpha_{i},\beta_{i},\gamma_{i},\delta_{i} for i=0,1,2i=0,1,2.

\partial grU\operatorname{gr}_{U} grV\operatorname{gr}_{V} AA ιKmod(U,V)\iota_{K}\mod(U,V)
ρ\rho 0 0 2-2 11 τ\tau
σ\sigma Uρ+VτU\rho+V\tau 1-1 1-1 0 σ+δ0\sigma+\delta_{0}
τ\tau 0 2-2 0 1-1 ρ\rho
α0\alpha_{0} Uβ0+Vγ0U\beta_{0}+V\gamma_{0} 1-1 1-1 0 α0+σ\alpha_{0}+\sigma
β0\beta_{0} Vδ0V\delta_{0} 0 2-2 11 γ0+τ\gamma_{0}+\tau
γ0\gamma_{0} Uδ0U\delta_{0} 2-2 0 1-1 β0+ρ\beta_{0}+\rho
δ0\delta_{0} 0 1-1 1-1 0 δ0\delta_{0}
α1\alpha_{1} Uβi+Vγ1U\beta_{i}+V\gamma_{1} 2-2 2-2 0 α2\alpha_{2}
β1\beta_{1} Vδ1V\delta_{1} 1-1 3-3 11 γ2\gamma_{2}
γ1\gamma_{1} Uδ1U\delta_{1} 3-3 1-1 1-1 β2\beta_{2}
δ1\delta_{1} 0 2-2 2-2 0 δ2\delta_{2}
α2\alpha_{2} Uβi+Vγ2U\beta_{i}+V\gamma_{2} 2-2 2-2 0 α1+δ1\alpha_{1}+\delta_{1}
β2\beta_{2} Vδ2V\delta_{2} 1-1 3-3 11 γ1\gamma_{1}
γ2\gamma_{2} Uδ2U\delta_{2} 3-3 1-1 1-1 β1\beta_{1}
δ2\delta_{2} 0 2-2 2-2 0 δ1\delta_{1}

We are left with the possibility that ιK\iota_{K} may contain terms that are multiples of UU or VV. Due to the bidegree reasons, such terms can arise only for the values of ιK\iota_{K} at αi,βi,γi,δi\alpha_{i},\beta_{i},\gamma_{i},\delta_{i} for i=1,2i=1,2. Since α1=Uβ1+Vγ1\partial\alpha_{1}=U\beta_{1}+V\gamma_{1}, we may homotope ιK\iota_{K}, which changes the values of ιK\iota_{K} only at α1,β1,γ1\alpha_{1},\beta_{1},\gamma_{1}, to eliminate all terms arising in ιK(α1)\iota_{K}(\alpha_{1}) which have nontrivial UU or VV exponents in their coefficients. Then, since β1=Vδ1\partial\beta_{1}=V\delta_{1}, we can further homotope ιK\iota_{K}, which changes the values of ιK\iota_{K} only at β1,γ1,δ1\beta_{1},\gamma_{1},\delta_{1}, to eliminate all terms arising in ιK(β1)\iota_{K}(\beta_{1}) involving nontrivial UU-exponents. Thus we may assume that

ιK(α1)=α2andιK(β1)=γ2+Vc\iota_{K}(\alpha_{1})=\alpha_{2}\quad\text{and}\quad\iota_{K}(\beta_{1})=\gamma_{2}+Vc

for some element cc. But then cc should lie in bidegree (3,1)(-3,1), and there is no such an element in the given complex, so we should have

ιK(β1)=γ2.\iota_{K}(\beta_{1})=\gamma_{2}.

Then it follows from

Vγ2+UιK(γ1)=ιK(α1)=ιK(α1)=Uβ2+Vγ2V\gamma_{2}+U\iota_{K}(\gamma_{1})=\iota_{K}(\partial\alpha_{1})=\partial\iota_{K}(\alpha_{1})=U\beta_{2}+V\gamma_{2}

that ιK(γ1)=β2\iota_{K}(\gamma_{1})=\beta_{2}, and then we deduce from

UιK(δ1)=ιK(β1)=ιK(β1)=Uδ2U\iota_{K}(\delta_{1})=\iota_{K}(\partial\beta_{1})=\partial\iota_{K}(\beta_{1})=U\delta_{2}

that ιK(δ1)=δ2\iota_{K}(\delta_{1})=\delta_{2}. Thus, to summarize, we have homotoped ιK\iota_{K} in the square summand generated by {α1,β1,γ1,δ1}\{\alpha_{1},\beta_{1},\gamma_{1},\delta_{1}\} so that it acts by

α1α2,β1γ2,γ1β2,δ1δ2.\alpha_{1}\mapsto\alpha_{2},\quad\beta_{1}\mapsto\gamma_{2},\quad\gamma_{1}\mapsto\beta_{2},\quad\delta_{1}\mapsto\delta_{2}.

Similarly, we can also homotope ιK\iota_{K} in the square summand generated by {α2,β2,γ2,δ2}\{\alpha_{2},\beta_{2},\gamma_{2},\delta_{2}\} so that it acts by

α2α1+δ1,β2γ1,γ2β1,δ2δ1.\alpha_{2}\mapsto\alpha_{1}+\delta_{1},\quad\beta_{2}\mapsto\gamma_{1},\quad\gamma_{2}\mapsto\beta_{1},\quad\delta_{2}\mapsto\delta_{1}.

But then the action of ιK\iota_{K} splits as the direct sum of its action on the summand generated by ρ,σ,τ,α0,β0,γ0,δ0\rho,\sigma,\tau,\alpha_{0},\beta_{0},\gamma_{0},\delta_{0} and the summand generated by αi,βi,γi,δi\alpha_{i},\beta_{i},\gamma_{i},\delta_{i}, i=1,2i=1,2. Since the latter summand is acyclic after localizing by (U,V)1(U,V)^{-1}, we see that the given ιK\iota_{K}-complex is ιK\iota_{K}-locally equivalent to its summand generated by ρ,σ,τ,α0,β0,γ0,δ0\rho,\sigma,\tau,\alpha_{0},\beta_{0},\gamma_{0},\delta_{0}. However [HM17, Proposition 8.1] implies that this summand is ιK\iota_{K}-locally equivalent to the involutive knot Floer complex of T#ET\#E. The lemma follows. ∎

We are now ready to prove 1.1; its proof will be divided in two parts. In the first part, we will prove that the knots

{Kn=(D#E)2n+1,1#D2n+1,1#E2n+1,1n>0}\left\{K_{n}=(D\#E)_{2n+1,-1}\#-D_{2n+1,-1}\#-E_{2n+1,-1}\mid n>0\right\}

have infinite order in the smooth concordance group. Then, in the second part, we will prove that infinitely many KnK_{n} form a linearly independent family of the smooth concordance group.

Proof of 1.1, first part.

It follows from 4.3 and [Kan22, Theorem 1.2] that

[(D#E)2n+1,1]=[(T#E#E)2n+1,1]=[T2n+1,1]KU.[(D\#E)_{2n+1,-1}]=[(T\#E\#E)_{2n+1,-1}]=[T_{2n+1,-1}]\in\mathfrak{I}^{U}_{K}.

Since CFKUV(S3,D)CFK_{UV}(S^{3},D) has CFKUV(S3,T)CFK_{UV}(S^{3},T) as a direct summand, the type-D module CFD^(S3D)\widehat{CFD}(S^{3}-D) also has CFD^(S3T)\widehat{CFD}(S^{3}-T) as a direct summand; here, all knot complements are endowed with the 0-framing. Take the inclusion map

iT:CFD^(S3T)CFD^(S3D).i_{T}\colon\widehat{CFD}(S^{3}-T)\rightarrow\widehat{CFD}(S^{3}-D).

By box-tensoring with the identity morphism on the type-DA module CFDA(TP2n+1,1)CFDA(T_{\infty}-P_{2n+1,-1}), we get a type-D morphism

(iT)2n+1,1:CFD^(S3T2n+1,1)CFD^(S3D2n+1,1).(i_{T})_{2n+1,-1}\colon\widehat{CFD}(S^{3}-T_{2n+1,-1})\rightarrow\widehat{CFD}(S^{3}-D_{2n+1,-1}).

Box-tensoring this morphism further with the identity morphism on CFA(T,ν)CFA^{-}(T_{\infty},\nu) gives a (nz,nw)(n_{z},n_{w})-bidegree-preserving chain map

Minus((iT)2n+1,1):CFK(S3,T2n+1,1)CFK(S3,D2n+1,1),\mathrm{Minus}\left((i_{T})_{2n+1,-1}\right)\colon CFK^{-}(S^{3},T_{2n+1,-1})\rightarrow CFK^{-}(S^{3},D_{2n+1,-1}),

whose truncation by U=0U=0 is given by Hat((iT)2n+1,1)\mathrm{Hat}((i_{T})_{2n+1,-1}). Then, by [KP22, Lemma 3.1] and 3.1, it follows that

ιD2n+1,1Hat((iT)2n+1,1)ιT2n+1,11idCFA^(T,P2n+1,1)(ιS3D(idCFDA^(𝐀𝐙)iT)ιS3T1)\iota_{D_{2n+1,-1}}\circ\mathrm{Hat}\left((i_{T})_{2n+1,-1}\right)\circ\iota^{-1}_{T_{2n+1,-1}}\sim\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes\left(\iota_{S^{3}-D}\circ\left(\mathrm{id}_{\widehat{CFDA}(\mathbf{AZ})}\boxtimes i_{T}\right)\circ\iota^{-1}_{S^{3}-T}\right)

for some bordered involutions ιS3D𝐈𝐧𝐯D(S3D)\iota_{S^{3}-D}\in\mathbf{Inv}_{D}(S^{3}-D) and ιS3T𝐈𝐧𝐯D(S3T)\iota_{S^{3}-T}\simeq\mathbf{Inv}_{D}(S^{3}-T), since we have

CFA^(T,P2n+1,1)CFA^(T,ν)CFDA^(TP2n+1,1).\widehat{CFA}(T_{\infty},P_{2n+1,-1})\simeq\widehat{CFA}(T_{\infty},\nu)\boxtimes\widehat{CFDA}(T_{\infty}-P_{2n+1,-1}).

Hence, if we consider the type-D morphism

F=iT+ιS3D(idCFDA^(𝐀𝐙)iT)ιS3T1,F=i_{T}+\iota_{S^{3}-D}\circ\left(\mathrm{id}_{\widehat{CFDA}(\mathbf{AZ})}\boxtimes i_{T}\right)\circ\iota^{-1}_{S^{3}-T},

then we have

Hat((iT)2n+1,1)+ιD2n+1,1Hat((iT)2n+1,1)ιT2n+1,11idCFA^(T,P2n+1,1)F.\mathrm{Hat}((i_{T})_{2n+1,-1})+\iota_{D_{2n+1,-1}}\circ\mathrm{Hat}((i_{T})_{2n+1,-1})\circ\iota^{-1}_{T_{2n+1,-1}}\sim\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes F.

Claim: idCFA^(T,P2n+1,1)F\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes F is nullhomotopic. Assuming the claim, we immediately get

Hat((iT)2n+1,1)ιT2n+1,1ιD2n+1,1Hat((iT)2n+1,1).\mathrm{Hat}((i_{T})_{2n+1,-1})\circ\iota_{T_{2n+1,-1}}\sim\iota_{D_{2n+1,-1}}\circ\mathrm{Hat}((i_{T})_{2n+1,-1}).

To prove the claim, we recall that CFKUV(S3,D)CFKUV(S3,T)A3CFK_{UV}(S^{3},D)\simeq CFK_{UV}(S^{3},T)\oplus A^{\oplus 3}; note that the three AA summands lie in different bigradings, but we do not have to care about this issue here. By [LOT18, Theorem 11.26], this corresponds to the splitting

CFD^(S3D)CFD^(S3T)S3,\widehat{CFD}(S^{3}-D)\simeq\widehat{CFD}(S^{3}-T)\oplus S^{\oplus 3},

where the inclusion map for the CFD^(S3T)\widehat{CFD}(S^{3}-T) summand is the map iTi_{T}. Choose any one of the three SS-summands, and take its projection map

prS:CFD^(S3D)S.\mathrm{pr}_{S}:\widehat{CFD}(S^{3}-D)\rightarrow S.

Then it follows from 4.1 that idCFA^(T,P2n+1,1)(prSF)\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes\left(\mathrm{pr}_{S}\circ F\right) is nullhomotopic.

It remains to show that idCFA^(T,P2n+1,1)(prTF)\mathrm{id}_{\widehat{CFA}(T_{\infty},P_{2n+1,-1})}\boxtimes(\mathrm{pr}_{T}\circ F) is nullhomotopic, were prT\mathrm{pr}_{T} denotes the projection map to the trefoil summand, i.e.

prT:CFD^(S3D)CFD^(S3T).\mathrm{pr}_{T}:\widehat{CFD}(S^{3}-D)\rightarrow\widehat{CFD}(S^{3}-T).

We will actually prove a stronger assertion that prTF\mathrm{pr}_{T}\circ F is nullhomotopic. To see this, we start with the fact that FF is degree-preserving, which implies that prTF\mathrm{pr}_{T}\circ F is a degree-preserving type-D endomorphism of CFD^(S3T)\widehat{CFD}(S^{3}-T). Then it follows from 4.2 that prTF\mathrm{pr}_{T}\circ F is either nullhomotopic or homotopic to the identity morphism. However, if it were homotopic to the identity, then we should have

idCFK^(S3,T)=idCFA^(T,ν)(prTF)prCFK^(S3,T)(idCFA^(T,ν)F)prCFK^(S3,T)(Hat((iT)2n+1,1)+ιD2n+1,1Hat((iT)2n+1,1)ιT2n+1,11),\begin{split}\mathrm{id}_{\widehat{CFK}(S^{3},T)}&=\mathrm{id}_{\widehat{CFA}(T_{\infty},\nu)}\boxtimes\left(\mathrm{pr}_{T}\circ F\right)\\ &\sim\mathrm{pr}_{\widehat{CFK}(S^{3},T)}\circ\left(\mathrm{id}_{\widehat{CFA}(T_{\infty},\nu)}\boxtimes F\right)\\ &\sim\mathrm{pr}_{\widehat{CFK}(S^{3},T)}\circ\left(\mathrm{Hat}((i_{T})_{2n+1,-1})+\iota_{D_{2n+1,-1}}\circ\mathrm{Hat}\left((i_{T})_{2n+1,-1}\right)\circ\iota^{-1}_{T_{2n+1,-1}}\right),\end{split}

where prCFK^(S3,T)\mathrm{pr}_{\widehat{CFK}(S^{3},T)} denotes the projection map from CFK^(S3,D)\widehat{CFK}(S^{3},D) to its direct summand CFK^(S3,T)\widehat{CFK}(S^{3},T). However, the right hand side of the above equation is the truncation (by U=V=0U=V=0) of a chain endomorphism of CFKUV(S3,T)CFK_{UV}(S^{3},T) which becomes nullhomotopic after localizing by (U,V)1(U,V)^{-1}. This is impossible since the identity map of CFK^(S3,T)\widehat{CFK}(S^{3},T) clearly does not satisfy this property. Thus prTF\mathrm{pr}_{T}\circ F should be nullhomotopic and the claim is proved.

Now that we have

Hat((iT)2n+1,1)ιT2n+1,1ιD2n+1,1Hat((iT)2n+1,1),\mathrm{Hat}((i_{T})_{2n+1,-1})\circ\iota_{T_{2n+1,-1}}\sim\iota_{D_{2n+1,-1}}\circ\mathrm{Hat}((i_{T})_{2n+1,-1}),

it follows that Minus((iT)2n+1,1)\mathrm{Minus}((i_{T})_{2n+1,-1}) is an almost ιK\iota_{K}-local map by [KP22, Lemma 3.3], i.e. we have an inequality

(4.1) [T2n+1,1][D2n+1,1].[T_{2n+1,-1}]\leq[D_{2n+1,-1}].

Since [(D#E)2n+1,1]=[T2n+1,1]KU[(D\#E)_{2n+1,-1}]=[T_{2n+1,-1}]\in\mathfrak{I}^{U}_{K} and Kn=(D#E)2n+1,1#D2n+1,1#E2n+1,1K_{n}=(D\#E)_{2n+1,-1}\#-D_{2n+1,-1}\#-E_{2n+1,-1}, we get

[Kn]=[T2n+1,1][D2n+1,1][E2n+1,1][E2n+1,1].[K_{n}]=[T_{2n+1,-1}]-[D_{2n+1,-1}]-[E_{2n+1,-1}]\leq-[E_{2n+1,-1}].

Furthermore, it is shown in the proof of [KP22, Theorem 4.5] that 0<[E2n+1,1]0<[E_{2n+1,-1}] and [E2n+1,1][E_{2n+1,-1}] has infinite order in KU\mathfrak{I}^{U}_{K}. Hence, we deduce that

[Kn][E2n+1,1]<0,[K_{n}]\leq-[E_{2n+1,-1}]<0,

and [Kn][K_{n}] has infinite order in KU\mathfrak{I}^{U}_{K}. Therefore KnK_{n} has infinite order in the smooth concordance group. ∎

To prove the linear independence part of 1.1, we recall more facts about KU\mathfrak{I}^{U}_{K} from [KP22]. Recall from [KP22, Section 4] that, for each n2n\geq 2, the horizontal almost ιK\iota_{K}-complex CnC_{n} is generated by elements an,bn,cn,dn,xna_{n},b_{n},c_{n},d_{n},x_{n}, where ana_{n} and xnx_{n} have bidegree (0,0)(0,0). The differential is given by

an=Unbn,cn=Undn,bn=dn=xn=0\partial a_{n}=U^{n}b_{n},\,\partial c_{n}=U^{n}d_{n},\,\partial b_{n}=\partial d_{n}=\partial x_{n}=0

and the involution on its hat-flavored truncation C^n\widehat{C}_{n} is given by

ιCn(an)=an+xn,ιCn(bn)=cn,ιCn fixes dn,xn.\iota_{C_{n}}(a_{n})=a_{n}+x_{n},\,\iota_{C_{n}}(b_{n})=c_{n},\,\iota_{C_{n}}\text{ fixes }d_{n},x_{n}.

These complexes satisfy the following inequalities in KU\mathfrak{I}^{U}_{K} (for detailed discussion see the proofs of [KP22, Lemma 4.6 and Theorem 4.7]). First of all, for any n2n\geq 2, we have

(4.2) 0<[Cn]andM[Cn]<[Cn+1]for any integer M.0<[C_{n}]\quad\text{and}\quad M\cdot[C_{n}]<[C_{n+1}]\quad\text{for any integer $M$}.

Furthermore, for any n2n\geq 2, we have

(4.3) [Cn][E2n+1,1].[C_{n}]\leq[E_{2n+1,-1}].

Lastly, if a knot JJ satisfies CFKUV(S3,J)𝔽2[U,V]ACFK_{UV}(S^{3},J)\simeq\mathbb{F}_{2}[U,V]\oplus A, for some acyclic summand AA (which is the case for each knot KnK_{n}), then there is a positive integer N2N\geq 2 such that

(4.4) M[J]<[CN]for any integer M.M\cdot[J]<[C_{N}]\quad\text{for any integer $M$}.

Now, we are ready to prove the second part of the main theorem.

Proof of 1.1, second part.

It follows from the first part of the proof of 1.1 and (4.3) that for each n2n\geq 2, we have

[Kn][E2n+1,1][Cn].[K_{n}]\leq-[E_{2n+1,-1}]\leq-[C_{n}].

Furthermore, by (4.4) for each positive integer nn, there is a positive integer N(n)N(n) such that

[CN(n)]<M[Kn]for any intger M.-[C_{N(n)}]<M\cdot[K_{n}]\quad\text{for any intger }M.

Hence, if we choose an increasing sequence of integers {sn}\{s_{n}\} such that s1=2s_{1}=2 and sn+1N(sn)s_{n+1}\geq N(s_{n}) for each n1n\geq 1, then by combining the above two inequalities with (4.2) we have that

[Ksn+1][Csn+1][CN(sn)]<M[Ksn]for any intger M.[K_{s_{n+1}}]\leq-[C_{s_{n+1}}]\leq-[C_{N(s_{n})}]<M\cdot[K_{s_{n}}]\quad\text{for any intger }M.

Suppose that the knots KsnK_{s_{n}} are linearly dependent in the smooth concordance group. Then there exists a finite sequence D1,D2,,DnD_{1},D_{2},\ldots,D_{n} of nonzero integers such that

D1[Ks1]+D2[Ks2]++Dn[Ksn]=0.D_{1}\cdot[K_{s_{1}}]+D_{2}\cdot[K_{s_{2}}]+\cdots+D_{n}\cdot[K_{s_{n}}]=0.

Without loss of generality, we may assume that Dn>0D_{n}>0. Then we have

0=D1[Ks1]+D2[Ks2]++Dn[Ksn]<(D21)[Ks2]+D3[Ks3]++Dn[Ksn]<(D31)[Ks3]+D4[Ks4]++Dn[Ksn]<<(Dn1)[Ksn]0,\begin{split}0&=D_{1}\cdot[K_{s_{1}}]+D_{2}\cdot[K_{s_{2}}]+\cdots+D_{n}\cdot[K_{s_{n}}]\\ &<(D_{2}-1)\cdot[K_{s_{2}}]+D_{3}\cdot[K_{s_{3}}]+\cdots+D_{n}\cdot[K_{s_{n}}]\\ &<(D_{3}-1)\cdot[K_{s_{3}}]+D_{4}\cdot[K_{s_{4}}]+\cdots+D_{n}\cdot[K_{s_{n}}]\\ &<\cdots<(D_{n}-1)\cdot[K_{s_{n}}]\leq 0,\end{split}

a contradiction. Therefore the knots KsnK_{s_{n}} are linearly independent, as desired. ∎

Remark 4.4.

By applying the arguments used in the proof of [HKPS22, Lemma 3.2], it follows that we can take N(n)N(n) to be 2n+22n+2. With a more explicit calculation of ιK\iota_{K} for KnK_{n}, we expect that a much smaller value for N(n)N(n) should be possible.

Remark 4.5.

The argument used in the second part of the proof of 1.1 can be summarized as follows; note that the same argument was also used in [KP22]. Let {Kn}\{K_{n}\} be a sequence of rationally slice knots such that for any i2i\geq 2, there exists a positive integer nin_{i} such that [Kni][Ci][K_{n_{i}}]\geq[C_{i}] in KU\mathfrak{I}^{U}_{K}. Then {Kn}\{K_{n}\} admits a linearly independent infinite subsequence in 𝒞\mathcal{C}.

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