Topological Pressure of Discontinuous Potentials and Variational Principle for Flows11footnotemark: 1
Abstract
Let be a compact metric space and be a continuous flow on . We introduce two types of topological pressure for family of discontinuous potentials . First, define the topological pressure of family of measurable potentials on a subset for flow and proof its invariant principle. The second topological pressure is defined on a invariant subset having a nested family of subsets, we also proof its invariant principle.
keywords:
dynamical system, topological pressure, flow, discontinuous potential, variational principleMSC:
[2020]37D35, 26A181 Introduction
Topological pressure emerged in the 1970s as an extension of topological entropy, with the purpose of measuring the complexity of motion in dynamical systems. Different potentials have varying effects on the systemβs motion, which topological entropy fails to reflect. Therefore, topological pressure is defined to capture the relationship between the uncertainty in the system and the potentials.
The refined definition of topological pressure was initially formulated by David Ruelle, a prominent theoretical physicist and esteemed member of the French Academy of Sciences. Drawing inspiration from the contributions of Sinai and Bowen, Ruelle introduced the concept of topological pressure in 1973, building upon the notion of βpressureβ within statistical mechanics. His definition pertained specifically to -actions that adhere to expansivity and specification on a compact metric space. He proved the following equation:
which is the variational principle([21]). In 1984, Pesin and Pitskel further extended this condition, defining the topological pressure of continuous mappings on non-compact sets([17]). In the 1960s, the concept of topological pressure for sequences of subadditive potentials already emerged([14]). In 1988, Falconer studied the topological pressure of sequences of subadditive potentials on mixed repellers and provided a variational principle under Lipschitz conditions and bounded variation([10]). Subsequently, there have been numerous related studies on the topological pressure of sequences of subadditive potentials([7, 12, 23, 9]). In 1996, Barreira further relaxed the subadditive condition and defined the topological pressure of sequence of potentials (not necessarily subadditive) on a subsets of compact metric space([5]). Over the years, the concept of topological pressure has evolved beyond just continuous mappings in discrete dynamical systems. The topological pressure and variational principles for families of continuous potentials have also emerged([4]). Similar to the concept of metric entropy, there is also topological entropy in dynamical systems, which originates from topological pressure and is related to measures([13, 24, 8]).
The above conclusions are all about continuous potentials. When the potential does not satisfy continuity, does topological pressure still exist? In 2006, Mummert first defined the topological pressure of a discontinuous map on a subset of a compact metric space ([16]). In Mummertβs study, the set is represented as the union of a nested sequence of sets: . The potential only needs to be continuous on the closure of each subset, not necessarily on the entire set. Thus, the classical topological pressure can be defined on each subset , and then taking the supremum over , we obtain the topological pressure on the subset : . Subsequently, Ma Xianfeng et al. extended Mummertβs conclusion from a single potential to a subadditive potential sequence([15]). In 2012, J. Barral and D. J. Feng studied the topological pressure of upper semi-continuous subadditive potentials([2]). In 2016, Feng and Huang gave the definition of weighted topological pressure for upper semi-continuous entropy maps, along with a variational principle([11]). In 2017, Marc Rauch directly defined the topological pressure of measurable potentials in compact metric spaces using the Caratheodory structure theory and proved the variational principle([19]). In subsequent research, he also introduced the topological pressure and variational principle for subadditive potential sequences([20]). Additionally, topological pressure can be defined for systems with discontinuous semi-flow([1]).
There have been some results for the topological pressure of discontinuous potentials in discrete dynamical systems, but in continuous dynamical systems it remains to be studied. This paper provides two definitions of the topological pressure of discontinuous potentials with respect to the flow and introduces the corresponding variational principles for each.
First, the topological pressure of family of measurable potentials on a subset is introduced. In a continuous dynamical system , given a nonempty subset , take the real numbers , , We define the topological pressure of the family of potential on the set as :
where
the lower bound is taken from all countably open covers that cover and . In the third part we can see that such definition is well-defined, stemming from the Caratheodory dimension theory of Pesin([18]). Then we have the first main conclusion of this article.
Theorem 1.1: Let be a DTS without fixed point and almost . For each subset one has
In particular, one can choose for each a Borel set such that , and .
For the second definition, consider a -invariational subset . consists of a nested subset of , i.e.: and for all . We require that be continuou on the closure of each subset , but not necessarily on . The topological pressure of on with respect to the flow is defined as:
where is the classical topological pressure of on . Since is continuous on the closure of every subset , is well-defined. Then we have the second main conclusion of this article.
Theorem 1.2: Let be a family of functions with tempered variation such that for all . Let be a Borel invariant set and is continuous with respect to the family of subsets . If there exists a continuous function such that
(1.1) |
uniformly on when for some , then
Although the above two topological pressures are defined using different methods, they both reflect the relationship between the potentials and the complexity of the systemβs motion on a subset of a continuous dynamical system.
2 Prelimilaries
Let be a measurable space and be a continuous flow on . This is, a family of heomorphisms such that and for all .
Definition 2.1: A measure on is said to be invariant, if for each and . A set is called invariant, if for any . A measure on is said to be ergodic for the flow if every Borel invariant set satisfies or .
The set of all invariant probability measures on is denoted by , and the set of the ergodic probability measures is denoted by . For each measurable subset , we define and . For , the quantity .
Let be a compact metric space. Given and , we consider the set
We call to be a finite open cover of if and , where every is open.
Given and , define the probability measures
where is the probability measure concentrated on . Denote by the set of all invariant sublimits of in the weak*-topology. We can proof that for every , and the is a compact metrizable space. The set is called the set of generic points of . Note that if is ergodic.
Given , we say that a set covers a subset if . Let be the set of all satisfying . Let be a family of function with tempered variation, that is, such that where
We write for .
Definition 2.2: Fix , , , Let
with the infimum taken over all countable sets covering . And let
Clearly, increases as increases.We have that
Lemma 2.3: Let and . If , then for all and .
Proof.
The case is clear. Choose some such that . Then for all . Hence
as .The statement is proved. β
By Lemma 2.3, the following quantity is well defined:
For , and , , if one has . This shows that . Hence the following limit is also well-defined:
Definition 2.4: The quantity is called topological pressure of on with respected to .
For , we emphasize that for each potential . This follows from for every and . Thus implies .
Next we introduce some properties of topological pressure.
Lemma 2.5: For , and , The following inequalities hold:
In particular,
for all , and then
Proof.
For a cover , if covers , then it can cover . Hence and then , . β
Lemma 2.6: Given a set , suppose , where and for all . then
Proof.
Since , we have for each and so
Take . Then for each . Hence given and , for each there exists covering such that
Then covers and
This gives and then since the arbitrariness of . Therefore, and letting gives
Letting , we have that . Hence
β
3 Variational principle
In this section, we will introduce the variatiional principle of above topological pressure.
Definition 3.1: A mapping is called Lyapunov exponent.
The corresponding set is called the set of all allowed -invariant measures with respected to . This means that for measures the quantity is well-defined. Fix some , a point such that is called allowed point with respected to and if
(3.1) |
for all sub-family which satisfies as . The set of all those points is denoted by . For a subset , denote in addition
and
Note that can be empty in the case of for each .
Proposition 3.2: Let be upper semi-continuous, and . Then one has
That is both sets are independent of .
Proof.
Let and . If is any sub-family such that . Then
as is upper semi-continuous (lemma A.2(d) in [20]). Thus and . If , then there exists a such that . By definition this means , and hence . Let , then for every and , and then . We have . On the other hand, for , one has for every . Then there exists a subsequence such that . Semilarly,
Hence for every and then , so . The statement for holds. β
Let , then for each , the quantities
and
are well-defined and called upper variational pressure and lower variational pressure of over respectively.
Theorem 3.3: Let be a Lyapunov exponent. If , then one has
(3.2) |
(3.3) |
Proof.
In case the we are done, now we assume . This implies and for each . Thus we can divide into two parts:
and
As a result we obtain by lemma 2.6 and
(3.4) |
Now suppose we have already shown for each such that for all . Define a sequence of Lyapunov exponents for and . As the entropies are finite for all , one has for all and . In addition
holds for each . Thus by using lemma 2.5 and we obtain
Note that if , we already have
otherwise letting yields
And by we end at
Hence it remains to show for all subsets satisfying and for all . Now pick such a set and suppose . This implies ; Otherwise a measure exists such that , which is a contradiction. This means . Thus . Therefore, without restriction we may assume
(3.5) |
To proceed we need some technical lemmas.
Lemma 3.4: Let be a finite set, given and . Define the probability measure as
for every , and set the entropy of to
Then for , one has
For a proof of this lemma, see lemma 2.16 in [6]
Lemma 3.5: Let , and such that is allowed with respected to , and . Let and be a finite cover of . For the open cover of , where with , there exists with arbitrary large, and a sequence such that
: .
: There exists a subset of of length satisfying inequality
: .
Proof.
and are the statements of [4]. The statement can be proven like lemma 4.7 in [20], one can constructs an increasing sub-family and corresponding vectors such that conditions and are satisfied, and as . Then by one has
Thus there is an such that for all . Hence for each the number together with satisfies all the three conditions. β
Continuing the proof. The first goal is to cover with countable many suitable subsets. we fix and a finite open cover of such as lemma 3.5. In addition fix for each a measure such that . Choose some such that for every there exists a satisfying . Now denote for by the set of points , which meet the following criteria:
the measure fulfills .
All three properties in lemma 4.5 are satisfied by and .
As is dense in and by one has , lemma 3.5 ensures for every the existence of some corresponding . Hence we obtain
For simplicity we may assume that all are nonempty, else they can be called out of the union.
Now fix and denote for each
(3.6) |
Pick some , then by lemma 4.5 one can finds arbitrary large and corresponding satisfying
This means and especially
(3.7) |
Applying lemma 3.4 to and , there exists a such that
for all . Fix , count all vectors which can appear in the above situation for any , and denote that number by , namely,
Hence, as :
This means, as for some corresponding ,
As a result there exists some such that
(3.8) |
for all .
For each we define the collection containing all which satisfying the properties of lemma 3.5 for some . This is a cover of , denote as . Note that by lemma 3.5 for each one has
(3.9) |
where and is the number of elements in . Hence we can estimate for and :
Here the last step we used the estimate . Now for every , we obtain
and hence
This means for fixed . To finish the proof we take the supreme for over all and apply that together with lemma 3.5:
Finally Letting results
For the second statement, fix . As , one has by lemma 3.4 and
Taking the infimum over all , yields the result. β
Theorem 3.6: Let be a compact metric space without fixed points. Fix and let be a Borel measurable potential on . Suppose there exists a constant and a Borel set satisfying , such that
(3.10) |
for each . Then if is well-defined, one has
Proof.
we need following lemma.
Lemma 3.7[22]: Let be a compact metric space without fixed points. For any and define . Then one has
(3.11) |
for almost .
Let such that holds for each . Note that . Assume first is finite. Let and . Define the Borel sets
then and , hence: . This shows that there is an such that for all .For each there exists a minimal such that:
(3.12) |
(3.13) |
for all . Define for each the Borel sets:
There exists an such that for all . Now define . If is an cover of such that , then is also an cover of , where , and . Fix and . Fix and let . Then for all . Thus for all . Hence, as for all
(3.14) |
In addition,one has by
(3.15) |
Hence,setting , one has using and
for all . Thus, for each cover of that , where and . There is the estimate
This shows , and hence by lemma 2.5 and lemma 2.3
for all . Now letting and shows that , if is finite.
If , replace by and if , replace by and set . Then the proof works in the same way.
β
Next we proof the theorem 1.1.
Proof.
By theorem 3.3, . For each , there is a Borel set such that and for all . Hence , and this shows by theorem 3.6 and lemma 2.6 that
Taking the supremum on the left side yields the result. β
4 Topological pressure based on nested set strings
In this section we will introduce other definition of topology pressure for discontinuous potential . Before that, letβs review the definition of topological pressure for continuous potentials on compact metric space .
Let be a continuous flow on and be a family of continuous function : with tempered variation. Given , for each and , let
(4.1) |
with the infimum taken over all countable sets covering . and let
(4.2) |
and
(4.3) |
with the infimum taken over all countable sets covering . When does from to , the above quantities and jump from to at unique values and so one can define
Theorem 4.1: For any family of continuous functions with tempered variation and any set , the limits
(4.4) |
and
exists.
Proof.
Take and with . Since , one has . Let
Given , we have
for any large . Thus,
and
for any large . Therefore,
and so
Letting we have
Since is tempered variational we have when , which together with the arbitrariness of yields the inequality
This shows that is well-defined. The existence of the other two limits can be established in a similar way. β
The number is called non-additive topological pressure of the family on , while and are called: respectively, the non-additive lower and upper capacity topological pressure of on . Clearly:
If , then:
Next we introduce the topological pressure of discontinuous potentials.
Let be a compact metric space, and a continuous flow. Consider any invariant subset possessing a nested family of subsets . The and the are not required to be compact; the are not required to be -invariant. Consider a family of measurable functions , we say that is continuous with respected to the family of subsets if is continuous on the closure of each for all . The potential function is not necessarily continuous on . we define the topological pressure of on , with respect to as:
where is the topological pressure of on as defined above. We show that the topological pressure does not depend on the choice of the family of sets .
Theorem 4.2: Assume that an invariant subset has two nested families of subsets and which exhaust , let be continuous with respect to both and . Then
Proof.
Set , and . For every , there exists an such that , as the exhaust , we can write . As is continuous on the closure of and each ,we have
Thus for every . Reversing the roles of and gives the result. β
We continue to assume that is a continuous flow on a compact metric space . Let be the set of invariant probability measures on and be the set of ergodic probability measures on . Given a Borel invariant set , For convenience, let . Given and , consider the Borel invariant set
and
For each , let .
Now we proof theorem 1.2.
Proof.
We will divide the proof process into three steps.
Step 1:Some auxiliary content.
Take and , given , there exists an increasing sequence in such that
for all . This implies that
(4.5) |
Moreover, let .
For each with we have
and so, proceeding inductively,
(4.6) |
Hence, it follows from that
Now let , then and since , we have
for any sufficiently large . Hence, by and since for all , taking , we obtain
again for any sufficiently large .
Now let be a finite set. Given and , we define a probability measure on by
for . moreover, let: .
Step 2: proof that .
As , we have that
We show that for every , .
let the in lemma 3.5 be , then we obtain following lemma.
Lemma 4.4: Given , and , let be a finite cover of for the open cover of , where with , there exists with arbitrary large, and a sequence such that
(a): and .
(b): there exists a subset of of length satisfying the inequality
Given and , let be the set of points such that the two properties in lemma 4.4 hold for some with: . Moreover, let be the number of all sequences satisfying the same two properties for some . this means that
Proceeding as lemma 5.3 in [3] one can show that
for any sufficiently large (since ).
For each , the collection of all sequences satisfying the two properties in lemma 4.4 for some and cover the set , therefore,
where and .
thus, we obtain
(4.7) |
For
(4.8) |
we have and so it from that
(4.9) |
Now take points , such that for each there exists with . Then: and so it follows from and together with the lemma 2.6 that
Since the arbitrariness of and and has tempered variation, we find that
Step 3: proof .
Lemma 4.5: For each there exists a invariant function such that
Proof.
it follows from that
Let , then and since , we have
Since for all , it follows from that uniformly on when . On the other hand, since , by Birkhoffβs ergodic theorem for flows there exists a -invariant function such that
almost everywhere and in . This yields the desired statement. β
Lemma 4.6: For each ergodic measure , we have
Proof.
we will show that there exists an so that: . Given , there exists , a measurable partition of and an open cover of for some such that:
(a): and for .
(b): The set has measure .
Now we consider a measure in the ergodic decomposition of with respect to the time-1 map . The later is described by a measure in the space of -invariant probability measure that is concentrated on the ergodic measure (with respect to ). Note that for in a set of positive measure such that when since
For each and , let be the number of integers such that . By Birkhoffβs ergodic theorem, since is ergodic for we have
(4.10) |
for almost every . On the other hand, by lemma 4.5 and Birkhoffβs ergodic theorem we have
(4.11) |
for almost every . By and and Egrovβs theorem, there exists , and a measurable set with such that
(4.12) |
for every and .
Moreover, let where is the partition induced by on . It from the Shannon-Mcmillian-Breiman theorem and Egorovβs theorem that there exists and a measurable set with such that
(4.13) |
for every and . Take , and . Note that . By construction,properties and holds for every and .
Since the are nested and exhaust , we can choose so that . We have that:. Now let be a Lebesgue number of of the cover and such that . Given , take such that for each there exists a set covering with
(4.14) |
Given , let and define . One can proceed as in the proof of lemma 2 in [17] to show that
(4.15) |
for each . Indeed, let be the number of elements of such that . It follows from that
(4.16) |
Note that by eventually making sufficiently small, for each there exists such that , where (this follows readily from the uniform continuity of the map on the compact set ). Given , we have . Hence, it follows from the first inequality in that the number of elements of the partition such that satisfies . Therefore,
(4.17) |
Inequality follows readily from and .
Observe that by the second inequality in we have
for all and . Therefore,
Without loss of generality one can also assume that is sufficiently small such that
then
and so it follows from that . Therefore, , which implies that
Finally, we consider measurable partition and open covers as before with . For each take such that is a Lebesgue number of the cover . Since diam when , it follows that
Moreover, since the family has tempered variation property, we obtain
Integrating with respect to gives
and letting yields the inequality:
This completes the proof of the lemma. β
When is ergodic, is a nonempty invariant subset of with . Hence, it follows from lemma 4.6 that
When is arbitrary, one can decompose into ergodic components and the previous argument shows that
This completes the proof of the theorem. β
It follows from theorem 4.3 that if for each , and so in particular if is compact and invariant, then
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