The number of automorphic representations of with exceptional eigenvalues
Abstract.
We obtain an upper bound for the dimension of the cuspidal automorphic forms for over a number field, whose archimedean local representations are not tempered. More precisely, we prove the following result.
Let be a number field and be the ring of adeles of . Let be the ring of integers of . Let be the set of irreducible cuspidal automorphic representations of with the trivial central character such that for each archimedean place of , the local representation of at is an unramified principal series and is not tempered. For an ideal of , let be the subgroup of corresponding to . Let be the number of real embeddings of and be the number of conjugate pairs of complex embeddings of . Using the Arthur-Selberg trace formula, we have
From this result, we obtain the result on an upper bound for the number of Hecke-Maass cusp forms of weight on which do not satisfy the Selberg eigenvalue conjecture.
2020 Mathematics Subject Classification:
11F72 (Primary) ; 11F12 (Secondary)1. Introduction
Let be a congruence subgroup of and be a Maass cusp form of weight on . Let be the hyperbolic Laplace operator on the upper half plane , and be the eigenvalue of on . In [19], Selberg proved that , and asserted that . It is called the Selberg eigenvalue conjecture. The best known lower bound for is that
which was proved by Kim and Sarnak [15]. This conjecture has been proven for some congruence subgroups (see [2, 3, 11]).
For , the space of Maass cusp forms of weight on with the Laplacian eigenvalue is a finite-dimensional vector space over . If , then we call an exceptional eigenvalue, and its multiplicity is equal to the dimension of over . The number of exceptional eigenvalues with multiplicities also has been studied in various aspects, as shown in [10, 11, 12, 14]. For with a positive integer , Iwaniec and Szmidt [14] and Huxley [11] independently proved that if , then the number of exceptional eigenvalues with multiplicities satisfying is less than for some constant depending on with . Later, Iwaniec [12] proved that it holds for .
Let be a number field and be the ring of adeles of . In this paper, we consider the number of Maass cusp forms of with exceptional eigenvalues. The Selberg eigenvalue conjecture for Maass cusp forms of can be stated via automorphic representations as follows. Let denote the set of irreducible cuspidal automorphic representations of with the trivial central character such that the local representation of at each archimedean place of is an unramified principal series. When and is a congruence subgroup of , there is a correspondence between Maass cusp forms of weight on and the fixed vectors under of automorphic representations . Here, is the subgroup of corresponding to . For a Maass cusp form of weight on , let be the irreducible cuspidal automorphic representation of corresponding to . By the -module theory due to Harish-Chandra, if and only if is tempered. Thus, the Selberg eigenvalue conjecture is equivalent to that is tempered for every Maass cusp form of weight on . Moreover, the number of exceptional eigenvalues with multiplicities is equal to the sum of with respect to , where is a Maass form of weight on such that is not tempered. Here, for and , denotes the space of fixed vectors under of , i.e.,
where is the underlying vector space of . Let be the subset of consisting of such that for every archimedean place of , is not tempered.
Let be the ring of integers of . For each place of , let be the completion of at and be the ring of integers of . Let (resp. ) be the set of non-archimedean (resp. archimedean) places of . For , let be the prime ideal of corresponding to . For a non-negative integer , we define by
For each , let be the maximal connected compact subgroup of defined by
Let be an ideal of , and be the absolute norm of . Since is a Dedekind domain, there is a unique non-negative integer for each such that
Then, we let
and
In the following theorem, we obtain an upper bound for .
Theorem 1.1.
Assume that is a number field. Assume that is the number of real embeddings of and that is the number of conjugate pairs of complex embeddings of . Then, for non-trivial ideals in ,
Let us consider the case when the number of archimedean places of is . In this case, is the field of rational numbers or an imaginary quadratic field, and means the number of exceptional eigenvalues with multiplicities for a congruence subgroup corresponding to .
When is an imaginary quadratic field, an automorphic form on corresponding to a fixed vector of is called a Maass cusp form of weight over (for details, see [4]). Note that the Laplace–Beltrami operator on is defined by
Assume that is a Maass cusp form of weight over an imaginary quadratic field and is an automorphic representation corresponding to . Let be the eigenvalue of on . Then, the Selberg eigenvalue conjecture is equivalent to that .
Let be the Hecke operator for . For an ideal of , a Hecke-Maass cusp form of weight on over is a Maass cusp form of weight on over that is an eigenform for all with . A Hecke-Maass cusp form is called a normalized Hecke-Maass cusp form if the -norm of is . Then, the vector space of Maass cusp forms of weight on over with the Laplacian eigenvalue has a basis consisting of normalized Hecke-Maass cusp forms. The following corollary is immediately implied by Theorem 1.1.
Corollary 1.2.
Assume that the number of archimedean places of is . Let be a non-trivial ideal of and be the number of normalized Hecke-Maass cusp forms of weight on over that do not satisfy the Selberg eigenvalue conjecture. Then, the followings are true.
-
(1)
Assume that and is a positive integer with . For convenience, we write for . Then, we have
-
(2)
Assume that is an imaginary quadratic field. Then, we have
Remark 1.3.
The rest of this paper is organized as follows. In Section 2, we review the Arthur-Selberg trace formula which is mainly used to prove Theorem 1.1 and describe how to obtain an upper bound for by using the Arthur-Selberg trace formula. In Section 3, we compute the geometric side of the Arthur-Selberg trace formula. In Section 4, we prove Theorem 1.1.
Acknowledgments.
The authors appreciate Andrew Knightly for his kind and helpful comments. The second author is supported by a Royal Society University Research Fellowship.
2. Preliminaries
We introduce some notions as follows. Let and , where is defined by the center of . Let be a number field and (resp. ) be the set of non-archimedean (resp. archimedean) places of , and be the set of places of . Let be the ring of adeles of and be the ring of infinite adeles of . For each , let be the completion of at and be the ring of integers of . Let be the maximal compact subgroup of defined by
For each , let be the uniformizer of and . Let be a unique prime ideal of . For with , a Haar measure on is defined by
(2.1) |
where is a Haar measure on satisfying , and denotes the -adic absolute value on . From (2.1), we have . For , a multiplicative Haar measure on is defined by
For , a multiplicative Haar measure on is defined by
and . If with , then by the Iwasawa decomposition, there are , and such that . Then, a Haar measure on is defined by
where is a Haar measure on . For any , we set a Haar measure on such that the volume of is equal to . Then, a Haar measure on is defined by
where . Thus, a Haar measure on is defined by the product of Haar measures on for all .
For a non-archimedean place of and a non-negative integer , let
Assume that is an ideal of . Then, for each , there is a unique non-negative integer such that
For convenience, let for , where denotes the principal ideal generated by in . Let be the absolute norm of . Let and , where
(2.2) |
is the maximal connected compact subgroup of .
For each and , let
Recall that is defined by the set of irreducible cuspidal automorphic representations of with the trivial central character such that the local representation of at each archimedean place of is an unramified principal series, and that is the subset of consisting of such that is not tempered for every . In other words, if , then for each , there is a unique spectral parameter such that is a right regular representation of on . Note that for , the spectral parameter is either a purely imaginary number or a non-zero real number with . Since is tempered if and only if is a purely imaginary number, it follows that is the subset of consisting of such that for all . For , let be the underlying vector space of and
As in Section 1, we define
The goal of this section is to derive the formula for an upper bound for by using the Arthur-Selberg trace formula.
For each , let be a smooth function on satisfying the following conditions :
-
(a)
for every , and ,
-
(b)
is compactly supported modulo ,
-
(c)
If , then the support of is contained in .
Since is a -invariant function, throughout this paper we see that is a function on by abusing the notation. Let and be defined by
(2.3) |
where , and
(2.4) |
Assume that and satisfy the following conditions :
-
(1)
is smooth and compactly supported,
-
(2)
is even,
-
(3)
,
-
(4)
is entire,
-
(5)
is rapidly decreasing on horizontal strips,
-
(6)
on ,
-
(7)
and on .
To show the existence of and , let us take such that is smooth, even, non-negative on and supported on . Let . Then, is supported on and
Let . Since , we have for ,
(2.5) |
and . Note that if , then and . Thus, there is such that and are positive on . Let . Then, and satisfy the conditions (1) (7). Using the Abel inversion formula, we obtain the following lemma.
Lemma 2.1.
Let be a function satisfying the conditions . Assume that a function satisfies the conditions such that
Then, when , we have for ,
(2.6) | ||||
(2.7) |
When , we have for ,
(2.8) |
Conversely, for a function satisfying the conditions , we define a function on satisfying the conditions as follows. If , then
and if , then
Here, , and . By (2.3), we see that is an even function. When , we have for ,
(2.9) | ||||
The last equality holds by Fubini’s theorem. By changing the variable , we have
Thus, (2.9) becomes
When , for , we have
Since is smooth and compactly supported, it follows that is also smooth and compactly supported modulo . Hence, satisfies the conditions and
Let be an irreducible cuspidal automorphic representation of with the trivial central character. Assume that a smooth function on is -invariant and compactly supported modulo . We define an operator on by
Then, the operator is a trace class.
For , let be a function on defined by the characteristic function of . From the definition of , we see that
We define a constant by
(2.10) |
The following lemma provides the expression of in terms of for .
Lemma 2.2.
Let be a number field and . Let be the number of archimedean places of with . Let be an ideal of and for each , is defined as the characteristic function of . Assume that for each , satisfies the conditions . Let be a function on defined by . Then, we have
Proof.
For any and , we have
Since for any and , it follows that . Thus, the trace of is the same as the trace of the restriction of to the space . To complete the proof of Lemma 2.2, we prove that for any ,
(2.11) |
For each place of , let be the local representation of at . Assume . Then, for each , we have
(2.12) | ||||
where is the image of under the canonical projection modulo . Following the proof of [18, Theorems 4.1 and 5.1], if , then we have
(2.13) |
Combining (2.12) and (2.13), we complete the proof of Lemma 2.2. ∎
Note that for and , we have
(2.14) |
Thus, we obtain the following lemma which provides the relation between and .
Lemma 2.3.
Let be an ideal of . Let be a function on defined as in Lemma 2.2. Then, we have
Proof.
3. Geometric side
In this section, we compute the geometric side of the Arthur-Selberg trace formula. For two non-negative functions and of variables , we write if there exists a constant , dependent on such that
Here, and are positive integers with . For simplicity, if there is a constant which is independent on such that
then we write . We follow the notation in Section 2. Throughout this section, we fix an ideal of and for each . Moreover, is a function on defined as in Lemma 2.2.
3.1. One-dimensional representations
Lemma 3.1.
Let be an ideal of . Then, we have
Proof.
Assume that is an idele class character with such that
(3.1) |
Let , where is a character. Then, we have
For each , we assume . Since is the characteristic function of , it follows that for any . Then, we have
Hence, we obtain that for . Since the set of determinants of all elements in contains , it follows that .
For each , if and , then is the trivial character since the image of is connected. If , then the characters satisfying are only the trivial character and the sign character. Since the support of is contained in when , we obtain that
where denotes the number of archimedean places of satisfying , and denotes the image of modulo . Following the proof of Lemma 2.2, we obtain that if , then
and if , then
∎
3.2. Identity contribution
Let be the identity matrix of size . In [6], is defined by
(3.2) |
Note that for each . Then, we have the following lemma.
Lemma 3.2.
For each , let . Then, we have
3.3. Elliptic contribution
For , let (resp. ) be the centralizer of in (resp. ). For an elliptic matrix , the conjugacy class of is defined by
Let (resp. ) be the centralizer of in (resp. ), where is a representative of . Let and . Then, by [16, Lemma 3.4], we see that
In [6, pp. 244], is defined by
Since for and is factorizable, we obtain that
where for each conjugacy class ,
(3.3) |
Here, and is an embedding corresponding to .
Assume that . Then, for , we have
(3.4) |
Since the centralizer of in contains , we see that
Note that the integral is independent of the choice of the representative of since a Haar measure is invariant under the right multiplication. By (3.4), there are and such that . It follows that for each . Since the entries of are in , we have . By multiplying a non-zero element in , we can assume that the determinant of is in . Since , it follows that for every . From this, we obtain that . Thus, for each , and then . Note that is similar to over . Therefore, there is a unique pair such that is in .
Let be the set of representatives of . Dirichlet’s unit theorem implies that is a finite set. Let with . For a ring containing , the centralizer of in is equal to
Here, denotes the set of units in . Let . Since is an elliptic matrix over , it follows that . We define an isomorphism by
(3.5) |
The isomorphism (3.5) deduces that
(3.6) |
Note that a Haar measure on is given by an isomorphism (3.6). From this isomorphism (3.6), we compute the volume of in the following lemma.
For a number field , let (resp. ) be the subset of (resp. ) consisting of (resp. ) such that (resp. ).
Lemma 3.3.
Let and . Let be the class number of . Let be an inclusion map defined by
Assume that . Then, we have
Remark 3.4.
Proof of Lemma 3.3.
To compute the volume of for , we define a Haar measure on as follows. For , a Haar measure on is defined by
(3.7) |
where . Here, is an additive measure on satisfying . If there exists an element such that , then the prime ideal corresponding to splits completely in . Thus, there are exactly two places lying over , and then there is an isomorphism defined by
(3.8) |
where and are roots of in . If there is no satisfying , then there is a unique lying over . Thus, there is an isomorphism defined by
(3.9) |
Hence, a Haar measure on is given by the isomorphism for each . Thus, the volume of is equal to the volume of the preimage of it under , i.e.,
The following lemma provides an upper bound for in terms of when .
Lemma 3.5.
Assume that and that . Let be defined by the number of satisfying . Let . If , then
and if , then
Proof.
Assume that . Since , it follows that
Therefore, we conclude that
∎
Since contains , it follows that is isomorphic to . In the following lemma, we compute the set of representatives of .
Lemma 3.6.
Assume that and that satisfies . If there is such that , then
is a set of representatives of . Here, and are roots of in . If there is no satisfying , then
is a set of representatives of .
Proof.
For with , we have
(3.10) |
Moreover, if , then
Thus, if there is no root of in , then
is a set of representatives of .
Assume that there is satisfying . Let and be roots of in . Note that if , then for . Thus, we assume that with . If , then
(3.11) | ||||
Note that for any and in , we get
and
(3.12) |
Since is an abelian group and is a unimodular group, there is the unique right -invariant measure on the homogeneous space up to constant multiplication. Thus, Haar measures on and naturally induce a right -invariant Haar measure on as follows. By using Lemma 3.6, a measure on is defined by
(3.14) |
where and . We have to check whether Haar measures on , , and are compatible. Let , and let be an element in the set of representatives of as given in Lemma 3.6. Let . Assume that with and . By the definitions of Haar measures on and , we have
In another way, since , it follows that
Similarly, when does not have the form , we can obtain .
In the following lemma, we obtain an upper bound for the integral
Lemma 3.7.
Proof.
Assume that with and satisfies . Then, we get
(3.15) |
Since , it follows that . By (3.15), if , then we obtain that is in
(3.16) |
If and , then any satisfies the condition (3.16). If and , then we have
Thus, if is in the set (3.16) with , then . From this, we obtain that if , then the set (3.16) is equal to
and if , then the set (3.16) is equal to
For a positive integer , let
Then, we have
Hence, the set of satisfying is equal to
(3.17) | ||||
if , and
(3.18) |
if .
For , the volume of
is computed by
(3.19) |
Similarly, we get
To complete the proof of Lemma 3.7, we compute the number of elements in . Assume that and . For each , there is such that the reduction of modulo is equal to . Since and , there is such that
and then . Note that for , we have
Since is a unit in , the reduction of modulo is equal to the reduction of modulo if and only if the reduction of modulo is in . Thus, if and , then .
If , then for . Thus, we have
For any and , if , then
This implies that
Therefore, if , then we conclude that
∎
Now, we assume that . Suppose that there are two roots and of in . Since is similar to over , we take as a representative of the conjugacy class . Then, we have
and
Thus, there is an isomorphism given by
(3.20) |
An isomorphism (3.20) induces a Haar measure on defined by
(3.21) |
where . In this case, is isomorphic to for . Also, a Haar measure on is defined by
(3.22) |
where . Here, is a Haar measure on .
Assume that there is no root of in . This only occurs when and . Then, is similar to over , where
(3.23) |
Thus, we obtain that
and that
By the Iwasawa decomposition, for , we have
Since a Haar measure on is a unique up to constant multiple, there is a constant such that
(3.24) |
Note that there is an isomorphism given by
(3.25) |
An isomorphism (3.25) induces a Haar measure on defined by
(3.26) |
where is given as in (3.24) and . Also a Haar measure on is defined by
(3.27) |
where .
By (3.21), (3.26) and the definition of the regulator of a number field, we have
Here, denotes the number of roots of unity in , denotes the regulator of , and is the number of such that and . It follows that
(3.28) |
Combining Lemmas 3.3, 3.5, 3.7 and (3.28), we obtain
Note that we have
Let and be the number of prime divisors of an integer . Since there are at most prime ideals in lying over a prime , the number of such that is less than or equal to . Thus, we obtain
The last inequality holds since . Similarly, we get
By [17, Theorem 1], we also have
(3.29) |
where denotes the Euler number, denotes the number of conjugate pairs of complex embeddings of , and denotes the discriminant of . Note that the number of roots of unity of a number field is bounded if the extension degree is fixed. Since , it follows that . Note that for a fixed positive integer and for any , we have
Thus, we conclude that
(3.30) | ||||
To complete the calculation of , we compute the integral
(3.31) |
for . Since the Haar measure on is defined differently in the two cases, we compute (3.31) in the following two lemmas.
Lemma 3.8.
Assume that and that there are two roots of in . Let
Then, we have
(3.32) |
Proof.
Since is the ratio of two roots of in , there are and such that
Thus, we have
By the Iwasawa decomposition,
Since is bi--invariant and , we have
(3.33) |
Assume that . Since the support of is contained in , it follows that
unless . If , then by the Cartan decomposition, there exist and such that
(3.34) |
Then, we have the following relation between and :
where denotes the conjugate transpose of . Since is -invariant and bi--invariant, it follows that
Let . Since the trace of is equal to the trace of , we have
(3.35) |
Hence, by changing the variable , we have
(3.36) | ||||
The last equality holds by (2.3).
Assume that . Similarly, for , we have
Then, we have
(3.37) | ||||
Similarly, by changing the variable , we have
(3.38) | ||||
Since is a non-negative even function on , for any , we have
Thus, we complete the proof of Lemma 3.8. ∎
Lemma 3.9.
Assume that and that there is no root of in . Then, we have
Proof.
3.4. Hyperbolic contribution
For each place of , we define a function on by
(3.40) |
where and . Let be a function on defined by
In [6, (6.35)], is defined by
(3.41) |
where for each with ,
(3.42) |
If , then there are and such that is non-zero for each . Since is a characteristic function of , we have
This implies that
Hence, if , then for each , and so .
For , if , then let
and if , then
Let be an embedding corresponding to an archimedean place of . By (3.42), we have
(3.43) |
Lemma 3.10.
Let and . If , then .
Proof.
Assume that and satisfying
Since the determinant of is in , we have
Let . By a computation, we have
Thus, we obtain that
(3.44) |
From the assumption that , the conditions (3.44) are equivalent to
Since , it follows that at least one of and is in . If , then because . Otherwise, if , then we also have by . Thus, we obtain that . This implies that
(3.45) |
Therefore, we have
∎
By (3.43) and Lemma 3.10, we can rewrite as
(3.46) |
The following lemma provides an upper bound for when .
Lemma 3.11.
Assume that and . Let . Then,
Proof.
First, we assume that . Let be the collection of all satisfying the condition . Since is a characteristic function of , it follows that is equal to the volume of . By (3.44), we obtain that if and only if
(3.47) |
By dividing the set according to , we have
(3.48) |
If , then . Then, we have by (3.47). Thus, we get
(3.49) | ||||
Now, we assume that . Since , it follows that , where . Thus, for each integer , we have
(3.50) | ||||
Combining (3.48) (3.50), we obtain that
Similar to deduce , we have
(3.51) |
and
Then, we have
(3.52) | ||||
Thus, we complete the proof of Lemma 3.11 for the case when .
For the case when , it is enough to show that for , is less than or equal to . If , then by the definition of in (3.40) we have
If for some and , then we have
(3.53) |
From (3.53), we obtain
(3.54) |
Assume that . If , then by (3.47) we have . It follows that . If , then . Again, by (3.47), we obtain that . Thus, we conclude that if , then . Combining (3.54), we obtain for ,
∎
Note that
Combining (3.46) and Lemma 3.11, we have
(3.55) | ||||
where is an arbitrary non-archimedean place of . In the following lemma, we compute when is an archimedean place of .
Lemma 3.12.
Assume that . Fix and . When ,
(3.56) |
When and ,
(3.57) |
When and ,
(3.58) |
Proof.
Following the proof of Lemma 3.8, we obtain (3.56). By the Iwasawa decomposition, we have
Then, we get
As in the proof of Lemma 3.8, there are , such that
and that
(3.59) |
3.5. Parabolic contribution
For with , is defined by
(3.60) |
where for each ,
In [6, (6.34)], is defined by
In the following lemma, we compute for .
Lemma 3.13.
For each , let
Then, we have
Proof.
Suppose that . If is non-zero for some and , then . This implies that . Conversely, if and , then we have is . Thus, we have
By Lemma 3.13, we have
where denotes the Dedekind zeta function of . Let
and
Note that the Laurent series of at has the form
By the definition of , we see that is holomorphic at for each . Also, is holomorphic at (see [6, pp. 242]). Thus, we have
Then, we get
(3.66) |
From Lemma 3.13, we have for each ,
and
Then, we get
and
Again by (3.66), we conclude that
(3.67) |
In the following lemma, we compute and for .
Lemma 3.14.
Assume that . Let . Then, we have
and
(3.68) |
where and are constants depending on .
3.6. Eisenstein series and residual contribution
Let be an idele class character of and be a character of . For , let . For a complex number , we define by the space of functions on satisfying
-
(1)
,
-
(2)
.
Similarly, for each place of , we define by the space of functions on satisfying
-
(1)
,
-
(2)
.
For and , and are defined by
and
where . Let and be defined by
and
Then, we have by [6, pp. 243]
where the sum is over all whose restriction to is trivial. Here, is the subset of consisting of such that for all , and for all .
Note that acts by a scalar multiplication. Thus, there is a constant such that for all ,
Then, for , we obtain that
(3.69) |
and
It implies that
(3.70) |
Assume that there is such that and is non-trivial on the unit circle . Then, there is such that . Let be defined by
Then, we have
This implies that and that for all since
By the Iwasawa decomposition, we conclude that if there is such that and is non-trivial on .
Thus, if and the restriction of to is trivial, then we have
(3.71) |
Here, is the trivial character of for each and denotes the sign function. Assume that is an idele class character of such that satisfies (3.71) for each . If is a non-trivial idele class character, then there is such that is a non-trivial character of . By the strong approximation theorem, there is such that and for with and . This contradicts our assumption that is trivial on . Hence, we get
(3.72) |
Here, is the trivial idele class character of . Let denote the subspace of consisting of such that for all . From (3.72), we compute in the following lemma.
Lemma 3.15.
Let be the number of real embeddings of and be the number of conjugate pairs of complex embeddings of . Let be the Dedekind zeta function of and be the discriminant of . Let be the completed zeta function defined by
Let be defined as in (2.10). Then, we have
Proof.
By (3.72), it is enough to show that
Assume that . We take such that the . Then, we have
(3.73) | ||||
When , we have for all . Thus, we have by (3.73)
(3.74) |
For , we have
Since , it follows that
(3.75) |
Combining (3.74) and (3.75), we deduce that
(3.76) |
Now, we consider an archimedean place of . When , since is a bi--invariant function, we have
Note that there is such that
Thus, for with , we have by [7, 3.251(2)]
(3.77) |
When , by taking , we have
Similarly, we have
Then, we get by [7, 3.251(2)]
for . This implies that
(3.78) |
In [6, pp. 244], is given by
By a similar argument to the Eisenstein series contribution, if an idele class character of satisfies and , then . This implies that
Combining (3.76), (3.77), and (3.78), we obtain the following lemma which provides the formula for .
Lemma 3.16.
With the above notation, we have
4. Proof of Theorem 1.1
In this section, we prove Theorem 1.1. We follow the notation in Sections 2 and 3. In the definitions of and , the sums seem to be infinite sums. However, the following lemma guarantees that these sums are finite.
Lemma 4.1.
Let and . Assume that the support of is contained in for some positive real number . If satisfies
then .
Proof.
By the Cartan decomposition, there are and a non-negative real number such that
Then, the trace of is equal to . Since is a bi--invariant function, we have
(4.1) |
By Lemma 2.1, we have if , then
(4.2) |
and if , then
Thus, we obtain that if , then . ∎
For each , assume that and satisfy the conditions in Section 2. For a real positive number , let
Then, and also satisfy the conditions in Section 2. Thus, we may assume that the support of is contained in for all . For each , we fix . Let be a positive real number. Then, the support of is contained in and
(4.3) |
Note that there is a function on satisfying the conditions in Section 2 such that
For , let be a function on . Recalling that for each , is the characteristic function of .
In the following lemmas, we compute upper bounds for , , , , and .
Lemma 4.2.
With the above notation, we have
Proof.
Lemma 4.3.
With the above notation, we have
Now, we introduce the following lemma which is useful to compute upper bounds for and .
Lemma 4.4.
For each , let be a positive real number. Let . Then, we have
Proof.
Assume that satisfies for all . Let be a monic irreducible polynomial of . Note that the coefficients of can be expressed as a symmetric function of a subset of and that the absolute value of each coefficient of is less than or equal to
Since the degree of is less than or equal to and has at most roots, we complete the proof of Lemma 4.4. ∎
For convenience, let and .
Lemma 4.5.
With the above notation, assume that for all . Then, we have
Proof.
Recalling (3.3), is defined by
First, we find the condition of such that . Suppose that . For each , let be the subset of consisting of such that there are two roots of in and . Note that if and only if and . Thus, if , then we have
and
If , then we have by (3.36) and (3.38)
This implies that
(4.4) |
Note that we have
(4.5) |
Combining (4.4) and (4.5), we get
It immediately implies that
(4.6) |
Hence, we conclude that if is non-zero, then satisfies (4.6) for all .
Recalling Section 3, let be a set of representatives of . Then, Dirichlet’s unit theorem implies that is a finite set. In Section 3.3, we see that if is non-zero, then there is a unique pair corresponding to such that . For , let be the subset of consisting of satisfying (4.6) for all . Then, we have
(4.7) |
Lemma 4.6.
With the above notation, assume that for all . Then, we have
Proof.
By (3.43), if , then there is such that
Lemma 3.12 implies that for all , we have
(4.11) |
Let be the subset of consisting of satisfying (4.11) for all . Then, we get
Assume that . Since , it follows that
(4.12) |
Then, for , we have
(4.13) |
Combining (4.12) and (4.13), for any , we get
(4.14) |
Since , it follows that and that
(4.15) |
Note that , and is an even function. By Lemma 3.12, we may assume that without loss of generality. If , then Lemma 3.12 says that
(4.16) |
Assume that . Since is a smooth function with compact support, there is a positive real number such that
for all . By Lemma 3.12, we have
(4.18) | ||||
where
By (4.15), we obtain
(4.19) | ||||
The last inequality holds since . Thus, combining (4.18) and (4.19), we have
(4.20) | ||||
Recalling (3.55), we have
(4.21) | ||||
for any . Combining (4.16), (4.17) and (4.20), we deduce that (4.21) becomes
for some constants and with . Since , the absolute value of the norm of is . By (4.13), we have
Therefore, we complete the proof of Lemma 4.6. ∎
Lemma 4.7.
With the above notation, assume that for all . Then, we have
(4.22) |
Proof.
Assume that . Since is an even function, it follows that
By the asymptotic behavior of , there are non-negative real numbers and such that
for all non-negative real numbers . Thus,
Since , we have
Then, Lemma 3.14 implies that there are positive constants and satisfying
Lemma 4.8.
With the above notation, assume that for all . Then, we have
Proof.
Recalling Lemma 3.15, we have
There are only finitely many such that . By [5, pp. 73], we have
(4.23) |
For each , let , where denotes a prime ideal of corresponding to and denotes a prime satisfying . Then, we have
(4.24) |
Let be the number of divisors of an integer . Let . Since the number of prime ideals of lying over is less than or equal , it follows that
Combining (4.23) and (4.24), we get
Since for , it follows that
By [13, Proposition 5.7], there are positive real numbers and such that for any ,
Thus, we obtain that
Since is a non-negative function, is less than or equal to . Then, we have
Here, the last inequality holds because is a positive real number with . ∎
Lemma 4.9.
With the above notation, we have
Now, we are ready to prove Theorem 1.1.
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