The non-commuting, non-generating graph
of a nilpotent group
Abstract.
For a nilpotent group , let be the difference between the complement of the generating graph of and the commuting graph of , with vertices corresponding to central elements of removed. That is, has vertex set , with two vertices adjacent if and only if they do not commute and do not generate . Additionally, let be the subgraph of induced by its non-isolated vertices. We show that if has an edge, then is connected with diameter or , with in the diameter case. In the infinite case, our results apply more generally, to any group with every maximal subgroup normal. When is finite, we explore the relationship between the structures of and in more detail.
2010 Mathematics Subject Classification:
20F18, 05C251. Introduction
A number of graphs have been defined on the set of elements of a group, aiming to capture some aspect of the group structure in graph-theoretic terms. Prominent among these is the commuting graph, in which two elements are joined by an edge if and only if they commute. This graph is trivially connected with diameter at most , since the identity is connected to all other vertices. However, if we remove the central elements of the group, then the commuting graph is no longer obviously connected, and indeed it fails to be connected for some groups. Giudici and Parker [8] showed that, even if it is connected, its diameter may be unbounded. On the other hand, Morgan and Parker [13] showed that if a group has trivial centre, then any connected component of its commuting graph has diameter at most .
The commuting graph of a group fits into a hierarchy of graphs as follows. Each graph now has vertex set , and the rules for adjacency of vertices and are as follows:
-
•
the power graph: one of and is a power of the other;
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•
the enhanced power graph: and are powers of some element ;
-
•
the commuting graph: ;
-
•
the non-generating graph: ;
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•
the complete graph: all pairs are adjacent.
Observe that each graph is a spanning subgraph of the next (except for the third and fourth when is -generated and abelian). This allows us to refine questions about connectedness, and ask, for instance, whether the difference between consecutive graphs in the hierarchy is connected (often with specified vertices removed). For example, the difference between the complete and non-generating graphs of is the generating graph , where and are adjacent if and only if . For convenience, we will write to denote the subgraph of induced by its non-isolated vertices.
The most basic question is whether the difference between consecutive graphs has any edges at all, for . Finite groups whose power graph and enhanced power graph are equal, or whose enhanced power graph and commuting graph are equal, were determined by Aalipour et al. [1]. The commuting graph and the non-generating graph of a non-abelian group are equal if and only if the group is minimal non-abelian, i.e., every proper subgroup of the group is abelian. Finally, has no edges if and only if is not -generated.
More complicated questions regarding connectedness have also been asked and resolved in the case of . For example, Breuer, Guralnick and Kantor [5, Theorem 1.2] proved that if is a non-abelian finite simple group, then is extremely “dense”, in the sense that it is connected with diameter . More recently, Burness, Guralnick and Harper [6, Corollary 6] generalised this result: if is a finite group, then either has an isolated vertex or is connected with diameter at most .
The structure of is less predictable, however, when isolated vertices are involved. For example, Crestani and Lucchini [7, Theorem 1.3] showed that although is connected when is a -generated direct power of , with an odd prime, can be chosen so that the diameter of is arbitrarily large. On the other hand, Lucchini [11, Corollary 4] proved that if is finite and nilpotent, then is connected with diameter at most .
This motivates the present paper, which considers the non-commuting, non-generating graph of a group , i.e., the difference between the non-generating graph and the commuting graph of . In this case, we remove all vertices corresponding to central elements of , as otherwise these would always be isolated. Thus is the graph whose vertices are , with vertices and adjacent if and only if and . In addition, we write to denote the subgraph of induced by its non-isolated vertices.
We will focus in this paper on the case where is a (not necessarily finite) nilpotent group, and describe the possible diameters of the connected components of . As the unique nontrivial connected component of the generating graph of a finite -generated nilpotent group is always extremely dense, one may expect that the same is not necessarily true for , which is a proper subgraph of the complement of this generating graph. However, the first of our main theorems shows that this is actually the case for any nilpotent group.
Theorem 1.1.
Let be a nilpotent group. If contains an edge, then is connected with diameter or . Moreover, if , then .
We will in fact prove that the conclusion of this theorem holds whenever is a group with every maximal subgroup normal. This is a weaker condition than nilpotency, as illustrated by the infinite -generated -group constructed by Gupta and Sidki [10]. Indeed, every maximal subgroup of this group is normal [17, Theorem 4.3]; however, the group has no finite presentation [19], and is therefore not nilpotent. For further discussion of groups with every maximal subgroup normal, see, for example [14, 15].
It is clear that, for an arbitrary group , the graph is empty if and only if is abelian. As mentioned above, has vertices but no edges if and only if is minimal non-abelian. Since a non-central element of a group is centralised by at most one maximal subgroup, a minimal non-abelian group is necessarily -generated.
The finite minimal non-abelian groups were classified by Miller and Moreno [12] in 1903 (see also [18]). In particular, any such group is either a -group, for some prime , or a non-nilpotent group whose order is divisible by exactly two primes. A concise description of the finite minimal non-abelian -groups is given in [21, Theorem 2.4]. On the other hand, a classification of infinite minimal non-abelian groups is not complete. Well-known examples are the Tarski monsters, which are simple groups where every proper nontrivial subgroup is cyclic of fixed prime order . Ol’shanskiĭ [16] proved that a Tarski monster exists for each prime .
The relationship between and is less clear when has edges. The remaining two main theorems of this paper provide a detailed overview of this relationship in the case where is a finite nilpotent group. We let denote the Frattini subgroup of .
Theorem 1.2.
Let be a finite -group. Then one of the following occurs.
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(i)
is either abelian or minimal non-abelian. In this case, has no edges.
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(ii)
is non-abelian and not -generated. In this case, is connected with diameter .
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(iii)
is non-abelian, -generated and not minimal non-abelian, and contains at most one abelian maximal subgroup. Furthermore, each maximal subgroup contains .
-
(a)
If has an abelian maximal subgroup , then is connected with diameter , and the isolated vertices of are precisely the elements of .
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(b)
If the centre of each maximal subgroup of is equal to , then is connected with diameter .
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(c)
If all maximal subgroups of are non-abelian, and at least one has a centre properly containing , then is connected with diameter .
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(a)
Using Magma [4], we can show that the groups numbered , and in the Small Groups Library [3] are groups of the smallest order satisfying (iii)(a), (b) and (c), respectively.
Theorem 1.3.
Let be a finite nilpotent group whose order is divisible by at least two primes. Then one of the following occurs.
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(i)
is abelian. In this case, is the empty graph.
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(ii)
is non-abelian and contains at least two non-cyclic Sylow subgroups. In this case, is connected with diameter .
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(iii)
, with a non-abelian Sylow subgroup of and cyclic.
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(a)
If contains no isolated vertices, then is connected, and .
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(b)
If contains isolated vertices, then is connected with diameter , and is an isolated vertex of if and only if is an isolated vertex of and is a generator of .
-
(a)
Note that the group in case (iii)(b) of the above theorem may be minimal non-abelian.
The structure of this paper is as follows. In §2, we prove several preliminary results about the graph . Next, in §3, we derive useful properties of groups that contain a normal maximal subgroup. This section concludes with a proof of Theorem 1.1. We then prove Theorem 1.2 in §4. Finally, in §5, we investigate the structure of when is a direct product of groups, and in particular prove Theorem 1.3.
2. Preliminary results
We now prove several elementary but useful results about the non-commuting, non-generating graph of an arbitrary group . Note that if and are vertices of a graph, then we write to denote the distance in the graph between and .
Proposition 2.1.
No connected component of has diameter .
Proof.
Suppose, for a contradiction, that has a connected component of diameter . Observe that an element of and its inverse have the same set of neighbours in , and are not adjacent. This implies that for each .
Let . Then is an edge of , and it follows easily that is also an edge. Hence . Thus , and all have order , and we conclude that . Therefore, is not an edge of , a contradiction. ∎
In order to deduce additional properties of , we will briefly consider the non-commuting graph of . This graph has vertex set , with two vertices adjacent if and only if they do not commute. Thus the graph is the complement of the commuting graph (with central elements removed). Abdollahi, Akbari and Maimani proved the following result, using similar arguments to those in the proof of Proposition 2.1 above, as well as the fact that the union of two proper subgroups of is a proper subset of .
Proposition 2.2 ([2, Proposition 2.1]).
Suppose that is non-abelian. Then the non-commuting graph of is connected with diameter .
We are now able to derive two useful corollaries involving .
Corollary 2.3.
Let be a proper non-abelian subgroup of . Then the induced subgraph of corresponding to is connected with diameter .
Proof.
Since any two elements of generate a proper subgroup of , the induced subgraph of corresponding to is the non-commuting graph of . Hence Proposition 2.2 yields the result. ∎
Next, notice that if is not -generated, then is equal to the non-commuting graph of . We therefore obtain the following corollary of Proposition 2.2.
Corollary 2.4.
Suppose that is non-abelian and not -generated. Then is connected with diameter .
Hence to prove our main theorems, we need only consider non-abelian -generated groups that are not minimal non-abelian.
Remark 2.5.
Suppose that is finite, non-abelian and nilpotent. The non-commuting, non-generating graph of the direct product of and a finite cyclic group is described in Theorem 1.3. We can also determine the structure of . Observe that contains a non-cyclic Sylow subgroup . Let be the smallest size of a generating set for . Then , and Burnside’s Basis Theorem implies that is isomorphic to the elementary abelian group for some prime . As is a quotient of , which is a quotient of , we conclude that the smallest size of a generating set for is at least . Hence Corollary 2.4 shows that is connected with diameter .
The final result in this section generalises the observation that every vertex of is isolated if and only if is minimal non-abelian.
Proposition 2.6.
Suppose that is non-abelian and -generated, and let . Then is an isolated vertex of if and only if:
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(i)
there exists a unique maximal subgroup of containing ; and
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(ii)
.
Moreover, if is not isolated in , then there exists a maximal subgroup of such that .
Proof.
An element is isolated in if and only if for each with . As is finitely generated, each of its proper subgroups lies in some maximal subgroup. Thus is isolated if and only if each maximal subgroup containing also centralises . Since is centralised by at most one maximal subgroup, either (i) and (ii) both hold (and is isolated) or is non-central in at least one maximal subgroup (and is not isolated). ∎
Note that if is finitely generated but not -generated, then each element of lies in more than one maximal subgroup.
3. Groups with normal maximal subgroups
In this section, we derive some of the most important tools that we will use to prove our main theorems. We will conclude the section with a proof of Theorem 1.1.
Proposition 3.1.
Suppose that contains a normal non-abelian maximal subgroup , with . Then each maximal subgroup of is non-abelian.
Proof.
Assume, for a contradiction, that contains an abelian maximal subgroup . It is clear that contains . Let . Then , and so . Thus there is no element , as otherwise would lie in . Therefore, is equal to . It follows that
This is a contradiction, as is simple, while is not. ∎
Our next result, together with Proposition 2.6, allows us to better characterise isolated vertices of in the case where every maximal subgroup of is normal.
Proposition 3.2.
Suppose that is -generated, and let be an element of that lies in a unique maximal subgroup of . Assume in addition that and . Then is abelian.
Proof.
Let . Then lies in no maximal subgroup of , and hence in no proper subgroup, since is finitely generated. It follows that , and so is cyclic. Thus is also cyclic, and therefore is abelian. ∎
Our next result provides upper bounds (and in some cases exact values) for distances between certain non-isolated vertices of , and in fact between any two non-isolated vertices when every maximal subgroup of is normal.
Lemma 3.3.
Suppose that is -generated. In addition, let be an ordered -tuple such that and are normal, non-abelian maximal subgroups of , with and . Then . Moreover, if and only if either:
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(i)
, , and is the only maximal subgroup of containing but not centralising ; or
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(ii)
, , and is the only maximal subgroup of containing but not centralising .
Proof.
As is finitely generated, each proper subgroup of lies in a maximal subgroup. We split the proof into several cases, corresponding to where lies with respect to and , and where lies with respect to and .
Case (a): or . Here, Corollary 2.3 yields .
Case (b): and . As and are normal and maximal in , their intersection is maximal in and in . Notice that is a proper subgroup of , as otherwise would centralise , contradicting . Similarly, . Since the union of two proper subgroups of is a proper subset of , there exists an element that centralises neither nor . Then is a path in , and hence .
Case (c): and . As is non-abelian, the quotient is not cyclic. Hence no element of lies in a generating set for of size two. Thus is adjacent in to each element of that does not centralise , i.e., each element of . Similarly, is adjacent to each element of , and so .
Case (d): and , or and . As there is complete symmetry in and , we may assume that and . Then , and thus . Additionally, as in the proof of Case (b), . Thus there exists an element that does not lie in or . Then is an edge of , and by Corollary 2.3. Hence . It remains to show that if and only if is the unique maximal subgroup of that contains but does not centralise .
If is indeed the unique maximal subgroup of that contains but does not centralise , then the neighbourhood of in is a subset of . However, since , no element of is a neighbour of . Thus , and so .
Suppose instead that there exists a maximal subgroup of that contains but does not centralise , with . Then and are proper subgroups of , and so there exists an element that does not lie in or . It is clear that is an edge of . In addition, since , we conclude as in the proof of Case (c) that is adjacent in to each element of , and in particular to . Thus is a path in , and hence . ∎
We are now able to prove a more general version of Theorem 1.1.
Theorem 3.4.
Let be a group with every maximal subgroup normal. If contains an edge, then is connected with diameter or . Moreover, if , then .
Proof.
Suppose that contains an edge, so that is non-abelian and not minimal non-abelian. We may also assume that is -generated, as otherwise is connected with diameter by Corollary 2.4.
Let and be non-isolated vertices of . Then Proposition 2.6 shows that contains maximal subgroups and such that and . As these maximal subgroups are normal in , applying Lemma 3.3 to the -tuple gives . The theorem’s first conclusion now follows from Proposition 2.1, which shows that no connected component of has diameter .
Suppose now that has an isolated vertex . To complete the proof, we will show that . We observe from Proposition 2.6 that lies in a unique maximal subgroup of , and that . Moreover, as , Proposition 3.2 shows that is abelian. It therefore follows from Proposition 3.1 that each non-abelian maximal subgroup of satisfies . Thus Lemma 3.3 yields . ∎
Theorem 1.1 now follows immediately.
4. Finite -groups
In this section, we determine the diameters of the connected components of when is a finite -group, with a prime, and in particular prove Theorem 1.2. Corollary 2.4 implies that it suffices to consider the case where is non-abelian and -generated. We therefore begin by deducing information about non-abelian, finite, -generated -groups.
The “equality” statement in part (iii) of the following lemma is well known (for example, see [21, Lemma 2.3]).
Lemma 4.1.
Let be a non-abelian, finite, -generated -group. Then the following statements hold.
-
(i)
is a maximal subgroup of each maximal subgroup of .
-
(ii)
Each element of lies in a unique maximal subgroup of .
-
(iii)
, with equality if and only if is minimal non-abelian.
-
(iv)
If is not minimal non-abelian, then contains at most one abelian maximal subgroup.
Proof.
(i) As is non-abelian and -generated, Burnside’s Basis Theorem implies that has index in . Hence is maximal in each maximal subgroup of .
(ii) By (i), is the intersection of each pair of distinct maximal subgroups of .
(iii)–(iv) Let be a maximal subgroup of , and let . Then by (ii), is the unique maximal subgroup of containing . As the abelian group is a proper subgroup of , it follows that contains . As this holds for every maximal subgroup of , we conclude that .
Now, if , then is abelian, and is equal to by (i). This again holds for every maximal subgroup of , and so is minimal non-abelian.
If instead there exists , then at most one maximal subgroup of centralises . As lies in each maximal subgroup of , it follows that at most one of these maximal subgroups is abelian, and in particular is not minimal non-abelian. ∎
We are now able to prove our second main theorem.
Proof of Theorem 1.2.
Lemma 4.1 shows that if is non-abelian, -generated and not minimal non-abelian, then contains at most one abelian maximal subgroup, and . Hence, in this case, each maximal subgroup of contains . Therefore, exactly one of (i), (ii) and (iii) holds.
(i) This is clear.
(ii) This is an immediate consequence of Corollary 2.4.
(iii)(a) By Lemma 4.1(ii), the abelian maximal subgroup of is the unique maximal subgroup containing each element of . It follows from Proposition 2.6 that a vertex of is isolated if and only if . In particular, has isolated vertices, and hence is connected with diameter by Theorem 1.1.
(iii)(b) Let , and let and be maximal subgroups of that contain and , respectively. As , applying Lemma 3.3 to the -tuple gives . It follows from Proposition 2.1 that is connected with diameter .
(iii)(c) Let be a (non-abelian) maximal subgroup of that satisfies . In addition, let , and let . Proposition 3.2 implies that each element of lies in a maximal subgroup of distinct from . Lemma 4.1(ii) shows that is the unique maximal subgroup of containing , and thus . Additionally, the element of lies in a maximal subgroup of that is not equal to . Since , it follows that . Hence applying Lemma 3.3 to the -tuple yields . Theorem 1.1 therefore implies that is connected with diameter . ∎
5. Direct products of groups
In this section, we explore the structure of the non-commuting, non-generating graph of a direct product of groups. In particular, we conclude with a proof of Theorem 1.3.
Let and be arbitrary groups, with and . Observe that if or , then the elements and of do not commute and are therefore non-central. In particular, these elements are vertices of . Additionally, if or , then . Therefore, relatively weak conditions are required for two vertices of to be adjacent. We utilise this fact to prove the following two results.
Lemma 5.1.
Suppose that is non-abelian and is non-cyclic. Then is connected with diameter .
Proof.
Let . Observe that if , then , and vice versa. We split the proof into three (not all mutually exclusive) cases. By Proposition 2.1, it suffices in each case to find a path of length in between and .
Case (a): . Proposition 2.2 shows that there exists an element that does not commute with or . Additionally, as is not cyclic, and . It follows that is a path in .
Case (b): . This case only occurs if is non-abelian, and we conclude as in Case (a) that .
Case (c): Exactly one of and is central in , and exactly one of and is central in . We will assume without loss of generality that , so that . Then, since , we deduce that and . Let and . The non-abelian group properly contains the abelian group , and similarly, . Thus is a path in . ∎
The above result shows that the non-commuting, non-generating graph behaves very differently to the generating graph in the context of -generated direct powers of non-abelian groups. Indeed, as mentioned in §1, Crestani and Lucchini proved that there is no upper bound for the diameter of , for such a direct power.
In the following proposition and its proof, we use the symbol to denote distances in both and . In each case, it will be clear which graph contains the relevant vertices. Additionally, if and are vertices of a graph that lie in distinct connected components, then we write .
Proposition 5.2.
Suppose that is non-abelian and is cyclic. Additionally, let and be distinct elements of , and let . Then the following statements hold.
-
(i)
.
-
(ii)
If is not isolated in , then .
Hence if is connected with diameter , then is connected with diameter at most .
Proof.
Suppose that is a path in . As no two adjacent vertices in this path commute or generate , it follows that is a path in .
(i) This is clear if . Otherwise, we obtain the result by setting to be a path in of minimal length with and .
(ii) This is clear if . Otherwise, note that and commute, and hence are not adjacent in . The result now follows by setting to be the path , with some neighbour of in .
Suppose finally that is connected with diameter , and recall from Proposition 2.1 that . Since is the set of vertices of , it follows from (i) and (ii) that is connected with diameter at most . ∎
It is easy to show, using Burnside’s Basis Theorem, that the direct product of a finite -generated -group and a finite -generated -group is -generated. Thus no non-abelian -generated finite -group can be expressed as a nontrivial direct product. It will follow from Theorem 1.3 that if is a finite cyclic group and is a finite nilpotent group such that is connected, then if and only if and and have a common prime divisor. However, this is not always the case if is not nilpotent. For example, the non-commuting, non-generating graph of the symmetric group is connected with diameter , as is the graph . On the other hand, (note that is -generated).
We now wish to determine which vertices of are isolated. Proposition 2.6 suggests that a classification of the maximal subgroups of will aid us in this task. The next result, which is a consequence of Goursat’s Lemma [9, §11–12], gives such a classification.
Lemma 5.3 ([20, p. 354]).
Let and be groups, and let be a subgroup of . Then is a maximal subgroup of if and only if one of the following occurs:
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(i)
, for some maximal subgroup of ;
-
(ii)
, for some maximal subgroup of ; or
-
(iii)
, where and are maximal normal subgroups of and , respectively, and is an isomorphism from to .
In what follows, we assume the convention that if is an infinite group, then each positive integer divides .
Theorem 5.4.
Let and be finitely generated groups, with non-cyclic, and let and . Additionally, let be the set of maximal subgroups of such that and divides . Then lies in a unique maximal subgroup of if and only if all of the following hold:
-
(i)
;
-
(ii)
lies in a unique maximal subgroup of ; and
-
(iii)
.
Proof.
Since is finitely generated and , there exists a maximal subgroup of containing . Similarly, there exists a maximal subgroup of containing if and only if . Notice that lies in the maximal subgroups and of for every such and . Hence if lies in a unique maximal subgroup of , then (i) and (ii) hold. For the remainder of the proof, we will assume that these conditions hold.
Lemma 5.3 shows that lies in a maximal subgroup of other than if and only if there exist maximal normal subgroups of and of , and an isomorphism with . If this is the case, then since , we conclude that , and hence .
Now, the quotients of by its maximal normal subgroups are exactly the cyclic groups of order a prime dividing . Hence such a normal subgroup of exists if and only if and , i.e., if and only if contains a subgroup not equal to . Therefore, is the unique maximal subgroup of containing if and only if (iii) holds, as required. ∎
We are now able to describe the isolated vertices of .
Corollary 5.5.
Let and be groups, with non-abelian, and let and . Additionally, let be the set of maximal subgroups of such that and divides . Then is an isolated vertex of if and only if all of the following hold:
-
(i)
;
-
(ii)
is an isolated vertex of ; and
-
(iii)
, and if , then .
Proof.
Recall from Corollary 2.4 that the non-commuting, non-generating graph of a group that is not -generated has no isolated vertices. Hence if is not -generated, then (ii) does not hold, and if is not -generated, then (i) does not hold. In either of these cases, is not -generated, and hence has no isolated vertices. We may therefore assume that and are -generated.
Suppose first that is an isolated vertex of . Then Proposition 2.6 implies that has a unique maximal subgroup containing , and . Hence by Theorem 5.4, (i) and (iii) hold, and lies in a unique maximal subgroup of . Since lies in the maximal subgroup of , we conclude that . In addition, since , we deduce that . Proposition 2.6 therefore yields (ii).
Proof of Theorem 1.3.
Observe that exactly one of (i), (ii) and (iii) holds. We may therefore consider each case separately.
(i) This is clear.
(ii) This is an immediate consequence of Lemma 5.1.
(iii)(a) As is not the empty graph, Theorem 1.1 implies that is connected with diameter or . Hence Propositions 2.1 and 5.2 show that is connected, with . It therefore suffices to find a pair of vertices of of distance in the case . Here, Theorem 1.2 shows that is -generated, and that there exists a non-abelian maximal subgroup of with . As and are coprime, is also -generated.
Let , and , with . By Lemma 4.1(ii), is the unique maximal subgroup of containing . As is coprime to , the set in Theorem 5.4 is empty, and so is the unique maximal subgroup of containing . Additionally, lies in , while does not. Since contains no isolated vertices, we conclude from Proposition 2.6 that there exists a maximal subgroup of with , and hence . Applying Lemma 3.3 to the -tuple therefore yields .
Acknowledgements
The authors would like to thank the Isaac Newton Institute for Mathematical Sciences for support and hospitality during the programme “Groups, representations and applications: new perspectives”, when work on this paper was undertaken. This work was supported by EPSRC grant number EP/R014604/1. In addition, this work was partially supported by a grant from the Simons Foundation. Finally, the second author was supported by a St Leonard’s International Doctoral Fees Scholarship and a School of Mathematics & Statistics PhD Funding Scholarship at the University of St Andrews.
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