The existence of homologically fibered links and solutions of some equations
Abstract
There is one generalization of fibered links in 3-manifolds, called homologically fibered links. It is known that the existence of a homologically fibered link whose fiber surface has a given homeomorphic type is determined by the first homology group and its torsion linking form of the ambient 3-manifold. In this paper, we interpret the existence of homologically fibered links with that of a solution of some equation, in terms of the first homology group and its torsion linking form or a surgery diagram of the ambient manifold. As an application, we compute the invariant , defined through homologically fibered knots, for 3-manifolds whose torsion linkng forms represent a generator of linkings.
1 Introduction
It is known that every connected orientable closed 3-manifold has a fibered link [1], i.e., a link in such that the complement of a small open neighborhood of admits a structure of a connected orientable compact surface bundle over and that each boundary component of a fiber surface is a longitude of a component of .
Moreover, it is known that every connected orientable closed 3-manifold has a fibered knot [9].
However, finding fibered links in a given 3-manifold is difficult in general. For example , defined as the minimal genus of fiber surfaces of fibered knots which has, is a topological invariant which is difficult to calculate.
There is one generalization of fibered links, called homologically fibered links [4] (defined in Definition 2.2 below).
A homologically fibered link requests some Seifert surface such that the result of cut a 3-manifold along the surface is a homological product of a surface and an interval,
whereas a fibered link requests some Seifert surface such that the result of cutting a 3-manifold along the surface is the product of a surface and an interval.
Clearly, a fibered link is also a homologically fibered link,
and [4], defined as the minimal genus of homological fiber surfaces of homologically fibered knots which has gives a lower bound of .
Homological products of surfaces (of a fixed homeomorphic type) and intervals are not merely the homological constraint for fiber structures, but they form a monoid by stacking, which contains the mapping class group as a submonoid (see [4]).
This attracts attention as a generalization of the mapping class groups.
Homological products of surfaces and intervals are studied using “clasper theory”.
As a consequence of clasper theory, it is known that the existence of a homologically fibered link whose fiber is a given homeomorphic type in depends on the first homology group of with its torsion linking form.
In this paper, we interpret the existence of a homologically fibered link whose fiber is a given homeomorphic type with the existence of a solution for some equation as follows.
As a convention, for an -matrix and an -matrix , is an -matrix whose -entry is the same as the -entry of for , the -entry is the same as the -entry of for , and the other entries are .
Let be an -zero-matrix,
an -identity matrix, and we regard -matrix ( and ) as the identity element for .
Let , , , and be matrices as follows, where and :
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is a diagonal -matrix whose -entry is for or for .
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is a diagonal -matrix whose -entry is for or for .
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, and to be ,
and , , for .
Also let and be matrices as follows, where , , , , for , and for :
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.
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.
As usual notation, denotes a connected orientable compact surface of genus with boundary components.
Theorem 1.1.
Let be a connected closed oriented 3-manifold whose free part of the first homology group with integer coefficient is isomorphic to and whose torsion linking form is equivalent to , where are non-negative integers and notations represent linkings, defined in Subsection 3.1.
Suppose .
Then has a homologically fibered link whose homological fiber is homeomorphic to if and only if there exist -matrix of integer coefficients and - symmetric matrix of integer coefficients satisfying the following equation:
(3) |
where is a -matrix whose -entry is for every and the others are .
Remark 1.1.
In general, it is not easy to compute the torsion linking form of a 3-manifold. Sometimes surgery diagrams of a 3-manifold may be easy to handle. A statement in terms of surgery diagrams is given in Proposition 5.1.
The rest of this paper is organized as follows: In Section 2, we recall the definition of homologically fibered links and the fact of their dependence on torsion linking forms. In Section 3, we recall three types of generators of linking forms and give rational homology 3-spheres whose torsion linking forms are the generators. In Section 4, we give a correspondence between surfaces in 3-manifolds and tuples of annuli and bands for Theorem 1.1. In Section 5, we give a proof of Theorem 1.1. In Section 6, we compute for 3-manifolds whose torsion linking forms are two of three types of generators in Section 3.
Acknowledgements
The author would like to thank Takuya Sakasai and Yuta Nozaki for introducing him this subject and giving him many ingredients about it. He also is grateful to referee for his or her kindness, patience and correcting many mistakes in the proofs and the arguments.
2 Homologically fibered links
In this section, we review the definition of homologically fibered links and the fact that the existence of homologically fibered links depends on the torsion linking forms. In this paper, the homology groups are with integer coefficients.
2.1 Definitions
Definition 2.1.
(homology cobordism, [3, Section 2.4])
A homology cobordism over is a triad (),
where is an oriented connected compact 3-manifold and is a partition of , and are homeomorphic to satisfying:
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.
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.
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The induced maps are isomorphisms, where are the inclusions.
Note that the third condition is equivalent to the condition that induce isomorphisms on . Moreover by using the Poincar-Lefschetz duality, we see that it is sufficient to require only one of and to induce an isomorphism on .
Definition 2.2.
[4] Let be a link in a closed orientable 3-manifold . is called homologically fibered link if there exists a Seifert surface of such that is a homology cobordism over a surface homeomorphic to , where are the cut ends. In this situation, we call a homological fiber of .
Clearly every fibered link is a homologically fibered link since the former requests that the manifold cut opened by some Seifert surface to be the product of an interval and a surface and the latter requests it to be the homological product of an interval and a surface. By the observations above the Definition 2.2, for a Seifert surface in a closed 3-manifold to be a homological fiber, it is enough to check that push-ups (or push-downs) of oriented simple closed curves on which form a basis of also form a free basis of .
Remark 2.1.
By definition, when a connected closed orientable 3-manifold has a homologically fibered link with homological fiber , can be generated by elements, where is the Euler number of . Therefore the minimal order of generating sets for imposes some constraint on homeomorphic types of homological fibers in .
2.2 Dependence on the torsion linking forms
Definition 2.3.
(Torsion linking form)
Let be a connected closed oriented 3-manifold, the torsion part of .
For every , there is a non-zero integer such that vanishes in , and we fix such an integer of minimal absolute value.
This has a representative as oriented curves in such that the -parallel copy of bounds a surface in .
The torsion linking form of , maps to , where represents the algebraic intersection number of and .
It is known that is well-defined and is non-singular, symmetric bilinear pairing, and that , where denotes the manifold homeomorphic to with the opposite orientation.
There is the operation of 3-manifolds preserving the first homology groups and the torsion linking forms, called the “Borromean surgery” introduced in [8].
Definition 2.4.
Let be a standard handlebody of genus three in which contains -framed link as in Figure 1. Consider a compact orientable 3-manifold and an embedding . Let be a manifold obtained as a result of the Dehn surgery on along the framed link in . This is called the manifold obtained from (and ) by a Borromean surgery.

About Borromean surgeries, the following facts are known:
Fact 2.1.
Fact 2.2.
[8] Let and be closed oriented 3-manifolds. Then the following are equivalent:
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There is an isomorphism between and such that and are equivalent under this isomorphism.
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is obtained from by a finite sequence of Borromean surgeries.
By the facts above, we can see the dependence on the first homology groups and the torsion linking forms about the existence of homologically fibered links:
Proposition 2.1.
Suppose that for connected closed oriented 3-manifolds and , there exists an isomorphism between their first homology groups such that their torsion linking forms are equivalent under the isomorphism. Then has a homologically fibered link whose homological fiber is homeomorphic to if and only if has a homologically fibered link whose homological fiber is homeomorphic to .
Proof.
We prove the if part and note that it is enough. By Fact 2.2, there is a finite sequence of Borromean surgeries starting from and ending at . Since it is enough to prove when is obtained from by one Borromean surgery, we assume that. Suppose has a homological fibered link with homological fiber which is homeomorphic to . Take a spine of and assume that lies in a small neighborhood of . Isotope so that it is disjoint from the surgery link of the Borromean surgery. This can be done since and the surgery link are graphs in a 3-manifold. Let be a surface, which is the image of after the Borromean surgery. Since is disjoint from the surgery link, a triad is obtained from by the Borromean surgery. Then by Fact 2.1, is a homology cobordism over . This implies that has a homologically fibered link with homological fiber which is homeomorphic to .
Note that if a connected closed oriented 3-manifold has a homologically fibered link whose homological fiber is homeomorphic to , then also has such a homologically fibered link. By Proposition 2.1, for a connected closed oriented 3-manifold containing a homologically fibered link with homological fiber of a given homeomorphic type we can replace with another one whose first homology group with the torsion linking form is the same as arbitrary one of and .
3 Representatives with respect to the first homology groups and their torsion linking forms
In this section, at first we recall a part of the result of [12], which gives a generator of the semigroup of the linkings on finite abelian groups, and next we fix representatives of 3-manifolds with respect to the first homology groups and their torsion linking forms. In fact, representatives are given in [6]. We give another representatives for our use. Note that they may coincide.
3.1 Linking pair
A linking is a pair such that is a finite abelian group and is a non-singular, symmetric bilinear pairing . Sometimes is called a linking on . We call two linkings and equivalent if there exists a group isomorphism between and through which and are equivalent. By fixing a basis of , is represented as a non-singular, symmetric matrix with coefficients in , whose -entry is the image of the -th element and the -th element of the basis under . For two likings and , define the product as , where maps to for every and . Under this product, linkings form an abelian semigroup . For a connected closed orientable 3-manifold , its torsion linking form, is an example of linkings. Moreover, for two connected closed oriented 3-manifolds and , the torsion linking form of is . In [12], a generator of is given as following:
Fact 3.1.
[12]
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Let be a linking on (with a generator ) which is represented by for coprime integers and , and
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let be a linking on (with a basis ) which is represented by for every integer , and
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let be a linking on (with a basis ) which is represented by for every integer .
Then is generated by , and .
Moreover, the presentation of is revealed by combining the results in [12] and [6].
As a notation we regard , and as , the identity element of .
Thus every linking is represented as , where , , is an integer greater than for , is an integer prime to , and , , for , and , , for . Note that this representation is not unique.
3.2 Representatives
We give 3-manifolds representing the generators in Fact 3.1. On showing that the torsion linking forms of these are the generators, we adopt a method of calculating torsion linking forms of rational homology 3-spheres by using their Heegaard splittings [2]. At first, we review the method.
3.2.1 Calculating torsion linking forms by using Heegaard splittings [2]
Let be a rational homology 3-sphere and a Heegaard splitting i.e. is obtained from two handlebodies of same genus, say , and by pasting their boundaries by some orientation reversing homeomorphism, say . We give and orientations as standard handlebodies in , and we give an orientation coming from . Take a symplectic basis of such that is in for every , where symplectic basis means that the intersection form on satisfies , , and for every . Similarly, take a symplectic basis of such that is in for every . Denote by the matrix representing , the map between the first homology group induced by with respect to these bases, where , , and are -matrices over .
Fact 3.2.
[2] In the situation above, and is isomorphic to . Moreover, the torsion linking form is equivalent to .
Remark 3.1.
We review the procedure for the calculation in terms of Heegaard diagrams rather than gluing maps used in the following. Let be a genus Heegaard splitting of a closed oriented 3-manifold (not necessarily a rational homology three sphere), and the splitting surface. Give the orientation as . Take a family of pairwise disjoint oriented simple closed curves on such that each bounds pairwise disjoint disks in and that these disks cut into a ball. Similarly, take a family of pairwise disjoint oriented simple closed curves on such that each bounds pairwise disjoint disks in and that these disks cut into a ball. Note that the triplet determines the homeomorphic type of . It is well-known that we can compute using the curves: , where is the algebraic intersection form on . By this, we can see whether is a rational homology -sphere or not. Suppose that is a rational homology -sphere in the following. Choose a family of pairwise disjoint oriented simple closed curves on such that for every . Similarly, choose a family of pairwise disjoint oriented simple closed curves on such that for every . Then the homology class of in forms a symplectic basis of such that each vanishes in , and the homology class of in forms a symplectic basis of such that each vanishes in . In this situation, we can compute the matrices , using curves: The -entry of is , and the -entry of is .
3.2.2 Representatives for
Let be a lens space of type for . has a surgery presentation as in Figure 2 and a Heegaard splitting as in Figure 3. In Figure 3, is the inner handlebody and is the outer handlebody, and a box containing represents curves in it, a result of resolving the intersection points of horizontal lines and vertical lines so that they twist in left-hand (or right-hand) side if (or , respectively). We take the -curve as and the -curve as on the splitting torus. Note that the orientation of coming from the standard one of corresponds to that coming from . By computation, we see that is a rational homology 3-sphere. Let be the -curve for such that . Then the matrices in 3.2.1 are and by computing the algebraic intersections and on . Note that . Thus by Fact 3.2, and the torsion linking form is . Let be a generator of corresponding to the -matrix . Note that is also a generator of since and are coprime. Under this new generator, the matrix representation of the torsion linking form is since mod , the same as . Henceforth, denotes .


3.2.3 Representatives for
Let be a connected closed orientable 3-manifold having a surgery description as in Figure 4. It has a Heegaard splitting as in Figure 5, so-called a vertical Heegaard splitting. The convention of boxes containing rational numbers is as in Figure 3. Note that this Heegaard diagram is not minimally intersecting. We regard as the inner handlebody and as the outer handlebody. Note that the orientation coming from the standard one of corresponds to that coming from . By computation, we see that is a rational homology 3-sphere. Let be curves as in Figure 6, where is the same as in Figure 5, which we abbreviate. Then the matrices in 3.2.1 are and . Thus by Fact 3.2, and under the basis . By changing a basis, and under the basis , the same as . Henceforth, denotes this .



3.2.4 Representatives for
Let be a connected closed orientable 3-manifold having a surgery description as in Figure 7. It has a Heegaard splitting as in Figure 8, so-called a vertical Heegaard splitting. The convention of boxes containing rational numbers is as in Figure 3. We regard as the inner handlebody and as the outer handlebody. Note that the orientation coming from the standard one of corresponds to that coming from . By computation, we see that is a rational homology 3-sphere. Let be curves as in Figure 9, where are the same as in Figure 8, which we abbreviate. Then the matrices in 3.2.1 are and . Thus by Fact 3.2, and under the basis . By changing a basis, and under the basis , the same as . Henceforth, denotes this .



From the above, we have representatives for connected closed oriented 3-manifolds with respect to the first homology groups and their torsion linking forms.
Proposition 3.1.
Suppose that a connected closed oriented 3-manifold whose free part of the first homology group is isomorphic to and whose torsion linking form is equivalent to for integers as in the end of Subsection 3.1.
Then a 3-manifold has isomorphic first homology group to that of and has equivalent torsion linking forms to that of , where as a notation we regard , , and as .
We use this in Section 5.
4 Thickened surface and its spine bands
In this section, we explain how surfaces (with their spines) in a given 3-manifold correspond to pairs of annuli and bands in the manifold.
All surfaces and 3-manifolds in this section are oriented, and we can use the terminology “front” and “back” sides of surfaces.
We state the statement as a proposition:
Proposition 4.1.
Let be an oriented 3-manifold. Fix non-negative integers and .
There is a bijection between the set of isotopy classes of oriented surfaces in , each of which is homeomorphic to with the spine as in Figure 10
and the set of oriented annuli with oriented core curves and the oriented bands (regarded as small rectangles) satisfying the following condition (see Figure 11 for example):
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One side of , which consists of four sides, is on the back side of and is a properly embedded essential arc on , and the opposite side of is on the front side of and is a part of the core curve of for .
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For , near the intersection of with , the front side of is on the positive direction with respect to the orientation of the core curve of , and near that of with , the front side of is the “right” side of the core curve of , where we look the intersection (this is on the front side of ) so that the core curve of runs from the bottom to the top.
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For , connects the “left” boundary of and the “right” boundary of so that the front sides are attached, and for , connects the “left” boundary of and the “left” boundary of so that the front sides are attached, where we look the front side of so that the core curve runs from the bottom to the top.
We call the condition for annuli and bands in Proposition 4.1 the condition . We construct oriented annuli and bands from a surface with its spine in Subsection 4.1, and construct a surface with its spine from oriented annuli and bands in Subsection 4.2. We can see that these operations are the inverses of each other. Thus Proposition 4.1 holds.


4.1 Annuli and bands obtained from surfaces
Let be a surface homeomrphic to in . Fix an embedding such that and identify with via . Take a spine of as in Figure 10. We assign an orientation to for each . Denote the point for by . Let be the square centered at and the rectangle around as in Figure 12. Take charts such that is a part of , is a part of , and such that is a part of and is near for , near for .

Denote the annulus whose core curve is by for as in Figure 13. Consider , see Figure 14. We regard that it is in via . Let , and be , and , respectively for and . These annuli can be regarded as framed knots in . Let , and be , and , respectively for and . These are bands in . We get an oriented annuli ’s and bands ’s and ’s (these are rectangles) in as in Figure 11. Observe that these satisfy the condition with appropriate orientations.


4.2 Surfaces from annuli and bands
Let be oriented annuli and be bands satisfying the condition in . These look like some embeddings of the union of annuli and bands as in Figure 11. Thicken these (denoted by ) and consider curves with colors as in Figure 15. In this figure, a part of the core curve of , which is also one edge of the band is replaced with the other three edges of for each . A small neighborhood of these curves in is homeomorphic to with a spine as in Figure 10. Let denote the red curve coming from and the blue curve coming from and for , and the green curve coming from for . For each , fix an essential arc in such that it is disjoint from for and for , and let be an essential disk in obtained by thickening . Then each intersects twice with the opposite orientations and ’s cut into a ball. Therefore, gives the structure of so that is . The colored curves play a role of a spine of . We get a surface corresponding to with a spine obtained by projecting the curves along the product structure. In other word, the surface with its spine is isotopic to with its spine in . We can easily show that the operations in Subsections 4.1 and 4.2 are inverses of each other.
Remark 4.1.
Let be a meridian curve of (i.e. an oriented circle on the boundary of a small neighborhood of which bounds a disk in the neighborhood intersecting the core of once positively) for . We assume is in a small neighborhood of and disjoint from . Note that the curve obtained from by the above procedure represents in , where and denote the elements represented by push-ups of the core curves of and , respectively.

5 A proof of Theorem 1.1
In this section, we give a proof of Theorem 1.1. At first, we consider the condition for a connected closed orientable 3-manifold having a homologically fibered link whose homological fiber is given homeomorphic type using a surgery diagram. In order to define the linking number among knots in the surgery link, we have to give the link an orientation. We fix any one. However, this choice does not matter for the existence of a homologically fibered link whose fiber is the given homeomorphism type, see Remark 5.1.
Proposition 5.1.
Let be a connected closed orientable 3-manifold.
Suppose that is obtained from by the surgery along a link , where each is an oriented knot and its coefficient is .
Then has a homologically fibered link whose homological fiber is homeomorphic to if and only if there exist -matrix of integer coefficients and -symmetric matrix of integer coefficients satisfying the following equation:
(6) |
where is an -matrix whose -entry is and -entry is for , is an -diagonal matrix whose -entry is , and is a -matrix whose -entry is for every and the others are .
Proof.
Suppose has a homologically fibered link whose homological fiber is homeomorphic to . We will construct a solution of (6).
By choosing a spine of , and using the construction in Section 4,
we get oriented annuli and oriented bands , satisfying the condition . We regard these annuli and bands are in the surgery diagram on missing the surgery link.
Let be the canonical longitude (regarded in ) of the core curve of and the meridian of (the core curve of) such that and the framing number of regarded as a framed knot.
Note that , and that the push-up of , which is in spines of as in Figure 10 represents
in .
Let be the meridian of and set to be and to be and to be .
Note that is generated by , and that -slope of represents an element in , denoted by .
Note also that the push-up of , which is in a spine of as in Figure 10 represents
under the basis of , denoted by .
Since is homological fiber, must be and the push-ups of ’s form a free basis of .
This implies that is isomorphic to , which also implies that are linearly independent in , and ’s modulo form a basis of it.
Thus is a basis of freely generated by .
Thus considering the change of basis matrix, we get a solution of (6) by setting equal to a matrix whose -entry is , equal to a symmetric matrix whose -entry is , -entry and -entry for are and other -entry is .
Conversely, suppose we have a solution , for (6). Then we can construct oriented framed knots in the surgery diagram on , which will be the core curves of annuli , such that is the -entry of , the framing of is the -entry of , for is equal to plus -entry of , and for other pair is the -entry of . Take bands satisfying the condition . Note that we can choose bands arbitrarily since these do not affect on the homology. We get a surface which is homeomorphic to by the construction in Section 4. By reversing the argument in the previous paragraph, we see that this surface is a homological fiber.
Remark 5.1.
Suppose there is a solution , for the equation (6) in Proposition 5.1 for some orientation of the surgery link. If we reverse the orientation of the -th component of -component surgery link, then the signs of the -th row and -th column of except for the -entry and the -th entry of in the left hand side of the equation (6) are switched. Then a pair of the matrix obtained from by switching the signs of the -th row and is a solution of the new equation. Therefore the existence of a solution of the equation (6) is preserved.
Remark 5.2.
For a given surgery diagram and a solution of (6), we can concretely construct a homologically fibered link as in the latter part of the proof of Proposition 5.1. However we have many choices in construction: There are many links with linking each others in the given number and linking the surgery link in the given number, and we can arbitrary take bands. These homologically fibered links corresponding to one solution are not always different, i.e. they may be isotopic. Moreover, two homological fibered links corresponding to two different solution may be isotopic.
Proof of Theorem 1.1.
Suppose that is a connected closed oriented 3-manifold whose free part of the first homology group is isomorphic to and whose torsion linking form is equivalent to .
Then has the isomorphic first homology group to and has a torsion linking form equivalent to that of by Proposition 3.1.
By Proposition 2.1, has a homologically fibered link whose homological fiber is homeomorphic to if and only if has such homologically fibered link.
We have a surgery diagram on for which consists of copies of an unknot with surgery slope (for ), copies of an unknot with surgery slope for (for ), copies of -component link as in the right of Figure 4 for (for ), and copies of -component link as in the right of Figure 7 for (for ).
Applying Proposition 5.1 with this surgery diagram with appropriate order, we get the equality (3).
Almost the same statement as the next corollary was given by Nozaki.
Corollary 5.1.
Let be a connected closed orientable 3-manifold. Suppose that has a homologically fibered link whose homological fiber is homeomorphic to for (resp. ). Then has a homologically fibered link whose homological fiber is homeomorphic to (resp. ).
Proof.
At first, for the case where has a homologically fibered link whose homological fiber is homeomorphic to , we can see that is generated by one element by Remark 2.1.
Thus is an integral homology -sphere and has a homologically fibered link whose homological fiber is homeomorphic to .
In the following, for the case where has a homologically fibered link whose homological fiber is homeomorphic to , we assume that .
Fix a surgery diagram of , and let be the number of knots in .
A surgery diagram of is obtained by adding disjoint unknot with surgery slope to .
We give an order among the link in so that is the first component.
Then by Proposition 5.1, we have a solution of (6) for (resp. ) and fix it.
Let denote the matrix in the left hand side of (6) and let denote the -entry of .
Note that for , and that for (resp. ).
Since (6) holds, (resp. ) are coprime.
This implies that the (ordered) set (resp. ) can be changed into -element set (resp. two-element set) such that the first element is or and the other elements are in finitely many steps, at each of which the -times of the -th element is added to the -th element for some integer and (resp. ).
Fix one of such sequence of steps.
Along this sequence, at each step, say the -times of the -th element is added to the -th element, we change as follows:
Add times the -th column to the -th column and then add times the -th row to the -th row.
Note that at any time in the sequence, each matrix obtained from is also a “solution” of (6).
A solution for a homologically fibered link whose homological fiber is homeomorphic to neither nor is not necessarily preserved under this operation.
At the end of the sequence we get a matrix obtained from whose -entry is for and for .
Note that the -entry of is for and for .
Expand the determinant of along the first row (the only one cofacter survives) and expand the determinant of the cofacter along the first column (the only one cofacter survives).
The cofacter finally obtained is a solution for (resp. ) in a 3-manifold which has a surgery diagram , representing .
6 Examples
Though we have Theorem 1.1, it is difficult in general to find a solution of (3) for a given manifold and homeomorphic type of a surface. Nozaki [10] proved that has a homologically fibered link whose homological fiber is homeomorphic to for every pair by solving some equations, which is equivalent to (3), using the density theorem. The author [11] proved that has a homologically fibered link whose homological fiber is homeomorphic to for every pair by solving (3) following the Nozaki’s argument. Thanks to Nozaki [10], we see that for every . Moreover, he also proved in his thesis that , and if or is quadratic residue modulo and otherwise for every non-negative integer . Thus we know for all 3-manifolds whose torsion linking form is . In this section, we determine for 3-manifolds whose torsion linking forms are the other generators for linkings, and for a non-negative integer , we state as a proposition, proved at Subsections 6.1 and 6.2:
Proposition 6.1.
In the following, and for a real number represent the minimal integer greater than or equal to and the maximal integer less than or equal to , respectively.
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For , if or .
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, and for .
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For , .
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For , if .
As a preparation, we review two observations: Firstly, the invariant is subadditive under the connected sum i.e. since we get a homological fiber by the plumbing of two homological fibers, see [11] for example. Secondly, it is known that has a fibered link whose fiber surface is an annulus. By the plumbing it and a Hopf annulus in , and by the plumbing two fibered annuli of , we get genus one fibered knots in and . Since they are not integral homology -spheres, we see that and .
6.1
We divide the argument into three cases, where is zero, where is positive even, and where is odd.
6.1.1
We will compute .
Since is not an integral homology 3-sphere, .
Moreover, it is known that has a fibered link whose fiber surface is homeomorphic to as in Figure 16:
If we ignore the green curve, the right of Figure 16 represents a fiber surface of a fibered link whose fiber surface is homeomorphic to in , which is obtained by the plumbing of fibered annuli in each prime components in appropriate way.
The green curve is on this fiber, and note that the canonical framing of this curve is identical with the surface framing.
Then -surgery (with respect to the canonical framing) along the green curve preserves the fiber structure.
By the plumbings of two Hopf annuli, we get a genus two fibered knot in .
This implies .
Thus it is enough to show whether has a genus one homologically fibered knot or not.

By Theorem 1.1, has a genus one homoloically fibered knot if and only if there exist integers and satisfying
(11) | |||||
(12) |
(i)
In this case, it is known that has a genus one fibered knot as in Figure 17:
If we ignore the green curve, the right of Figure 17 represents a fiber surface of a genus one fibered knot in , which is obtained by the plumbing of fibered annuli in each prime components in appropriate way.
The green curve is on this fiber, and note that the surface framing of this curve is the -slope with the canonical framing.
This implies that the -slope of the green curve with respect to the canonical framing is the -slope with respect to the surface framing.
Then the surgery along the green curve preserves the fiber structure.
Thus has a genus one homologically fibered knot.
In fact, and is one of the solutions.
This solution may correspond to a non-fibered knot.

(ii)
In this case, there exist no solutions.
If there was, must be odd since the other terms in the right hand side of (6.2.4) are even.
If is odd, then the right hand side of (6.2.4) is congruent to modulo by noting that and that the square of every odd integer is congruent to modulo .
This cannot be .
(iii)
In this case, and is one of the solutions of (6.2.4).
6.1.2 for
6.1.3 for
6.2
We divide the argument into four cases, where is zero, where is two, where is not two and is even, and where is not two and is odd.
6.2.1
We will compute for .
Since is not an integral homology 3-sphere, .
Moreover, has a genus two fibered knot as in Figure 18:
If we ignore the red curve and the blue curve, two of the bottom of Figure 18 represent fiber surfaces of genus two fibered knots in for odd and even , which are obtained by the plumbings of fibered annuli in each prime components in appropriate way.
The red curve and blue curve are on this fiber.
Note that the -slope of the red curve with respect to the canonical framing is the -slope with respect to the surface framing, and that the -slope of the blue curve with respect to the canonical framing is the -slope with respect to the surface framing.
Then the surgery along the red curve and the blue curve preserves the fiber structure.
Therefore we have .
Thus it is enough to show whether has a genus one homologically fibered knot or not.

By Theorem 1.1, has a genus one homologically fibered knot if and only if there exist integers and satisfying
(18) |
(i)
In this case, we get a genus one fibered knot as in Figure 19:
If we ignore the green curve, the right of Figure 19 represents a fiber surface of a genus one fibered knot in , which is obtained by the plumbing of fibered annuli in each prime components in appropriate way.
The green curve is on this fiber, and note that the surface framing of this curve is the -slope with the canonical framing.
This implies that the -slope of the green curve with respect to the canonical framing is the -slope with respect to the surface framing.
Then the surgery along the green curve preserves the fiber structure.
Thus has a genus one homologically fibered knot.
In Fact, and is one of the solutions.
This solution may correspond to a non-fibered knot.
Thus we have .

6.2.2 for
6.2.3 for and
Note that
We will show that has no homologically fibered links whose homological fibers are homeomorphic to .
This implies that .
Suppose that had a homologically fibered links whose homological fibers are homeomorphic to .
By applying Theorem 1.1, we have a solution , -integer matrix, and , -symmetric integer matrix, for an equation below.
(25) |
Note that the left hand side is congruent to modulo . This cannot be , and this leads a contradiction.
6.2.4 for and
First, we show that has a homologically fibered link whose homological fiber is homeomorphic to . By Theorem 1.1, the existence of such a link is equivalent to that of a solution of the equation below.
(31) |
By substituting , the left hand side of (31) becomes equal to
.
Note that the existence of such that the determinant becomes is equivalent to that of a genus one homologically fibered knot in by Theorem 1.1, and the existence is guaranteed by Nozaki.
Thus has a homologically fibered link whose homological fiber is homeomorphic to .
Moreover, we get a homologically fibered link whose homological fiber is homeomorphic to in by the plumbing with a fibered annulus in .
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