The essential spectrum, norm, and spectral radius of
abstract multiplication operators.
Abstract.
Let be a complex Banach lattice and is an operator in the center of . Then the essential norm of equals the essential spectral radius of . We also prove , where is the atomic part of and is the non-atomic part of . Moreover , where is the Fréchet filter on the set of all positive atoms in of norm one and is given by for all .
2000 Mathematics Subject Classification:
Primary: 47G10; Secondary: 47B65, 47B341. Introduction.
Over the past two decades numerous authors have studied boundedness, invertibility and compactness of multiplication operators on a variety of spaces of measurable functions on a measure space (or sequence spaces, when the measure is atomic). We refer to a recent preprint of J. Voigt ([7]) for some references. It seems that these authors are not aware that these multiplication operators are examples of order bounded band preserving operators (or orthomorphisms). Zaanen showed in 1977 in [9] already that the collection of all such orthomorphisms is lattice isometric to , so that a function defining a multiplication operator has to be essentially bounded and the operator norm of the multiplication operator equals the -norm. Around that time it was also established that for an arbitrary Banach lattice the collection of band preserving operators was equal to the center , where and that for . For this and additional basic properties of the center we refer to the books [4] and [10]. In particular, Proposition 3.1.3 of [4] shows that for a Dedekind complete Banach lattice the center as defined here coincides with the collection of regular operators which commute with band projections. It was proved in [5] that is a full sub-algebra of the algebra of norm bounded operators, i.e., is invertible in if and only if there exists such that . Therefore is equal to the essential range of , when is a multiplication operator on a Banach function space. Moreover the spectral radius . The study of the essential spectrum of operators was initiated in [5], where it was proved that for with a non-atomic Banach lattice. Here the essential spectrum denotes the spectrum of in the Calkin algebra . A few years later in [1] other spectra and essential spectra of operators were considered and an alternative proof of for with a non-atomic Banach lattice was given. A description of compact can be derived from the more general description of compact disjointness preserving operators due to De Pagter (unpublished) and Wickstead [8].
More recently the essential norm in the Calkin algebra has been considered for certain concrete Banach sequence spaces and -spaces (see [7] and [2]) for more references. The current paper was prompted by the preprint [7], which didn’t use our results from [5]. By using the term abstract multiplication operator in our title we hope that future duplication of our results by authors working on these questions for concrete function spaces will be avoided by a web search or MathScinet search. The current paper describes completely the essential spectrum and norm of an operator for an arbitrary Banach lattice . The paper is organized as follows. In section 2 we describe for non-atomic Banach lattices the essential spectrum and norm for an operator . To be able to describe the essential spectral radius for the atomic case where we might have uncountably many atoms, we describe in section 3 what we call Fréchet cluster points of a complex valued function and the Fréchet limit superior and inferior of the modulus of such a function. For the countable case this is standard textbook material, but for the uncountable case one can find some of this in General Topology textbooks, but for the convenience of the reader we have included this section. Then in section 4 the atomic case is handled. In the process of proving the results we reprove the description of a compact . In the final section we combine the atomic and non-atomic case to describe the essential spectrum and norm of for an arbitrary Banach lattice . As in [7] we associate in that case with an atomic part and non-atomic part , but in general (i.e., when is not Dedekind complete) we don’t have a decomposition of , as these parts are not defined on all of . We give in this section a concrete example to illustrate this. We conclude the paper by applying our results to prove that if is essentially quasi-nilpotent, then is compact (and thus in the Calkin algebra).
2. The non-atomic case.
Let be a complex Banach lattice. Let . Then the disjoint complement of is defined as . Then is defined as . Recall that is called an atom, if implies that for some scalar , i.e., . Now is called non-atomic if doesn’t contain any atoms. Typical examples of non-atomic Banach lattices are Banach function spaces over a non-atomic -finite measure space. The following theorem was proved by the author in 1980 in [5] (Theorem 1.11).
Theorem 2.1.
Let be a complex non-atomic Banach lattice and . Then and thus .
Using the methods of the above mentioned paper we can now prove the following theorem. The proof of this theorem, as well as the following theorem, depend on Lemma 1.10 of [5]. As one of the referees correctly pointed out, this lemma is incorrect as stated. Fortunately the fix is easy. In Lemma 1.9 of [5] one needs to replace by .Then the proof of Lemma 1.9 of [5] is correct. Note that in the final step the Eberlein-Smulyan theorem is used. With this correction, Lemma 1.10 of [5] is true if we replace by in the statement.
Theorem 2.2.
Let be a complex non-atomic Banach lattice and . Then .
Proof.
Let . Then . Therefore there exists such that . Now . Therefore . By order continuity of this implies that for all . In particular for all . Now by the corrected (as indicated above) Lemma 1.10 of [5] there exist with such that in the weak topology . Let now . Then, by compactness of , we have that as . From this it follows that
As this holds for all , it follows that . Hence and thus . The result follows now from the above theorem. ∎
Remark.
In case is non-atomic, it was already proved in [6] that for the larger class of disjointness preserving operators.
3. Fréchet cluster points and the Fréchet limit superior.
Let be a non-empty set and a function. Denote by the Fréchet filter on , i.e., a subset of is in if is a finite set.
Definition 3.1.
A point is called a Fréchet cluster point of if for all and all there is an element such that .
In this case we will also say that is an -cluster point. Note that one can equivalently say that is a Fréchet cluster point of if and only if is a cluster point of in the topological sense if and only if there exist distinct () such that . One can show (assuming the axiom of choice) the following proposition.
Proposition 3.2.
Let be a non-empty set and a function. Then is a Fréchet cluster point of if and only there exist a free ultrafilter on such that .
It is also known that the set of all -cluster points of is a closed subset of . Therefore we have the following proposition.
Proposition 3.3.
Let be a non-empty set and a bounded function. Then there exists an -cluster point of with largest and smallest modulus.
We now describe the modulus this largest and smallest -cluster point.
Definition 3.4.
Let be a non-empty set and a bounded function. Then the -limit superior of is defined as
and the -limit inferior of is defined as
Note that these notions can be extended to unbounded function by allowing or as values. As in the sequential case one can prove now the following theorem.
Theorem 3.5.
Let be a non-empty set and a bounded function. Then the -limit superior of is the largest -cluster point of and is the smallest -cluster point of .
Corollary 3.6.
Let be a non-empty set and a bounded function with an -cluster point of of largest modulus. Then
Proof.
The inequality implies immediately that if is an -cluster point of , then is an -cluster point of . Conversely, if is an -cluster point of , then there exist distinct in such that . By passing to a subsequence we can assume that there exists such that . Then . This shows that is an -cluster point of if and only there exist a an -cluster point of with . From this we the corollary follows immediately.
∎
We indicate in the next section a case, where naturally occurs as the quotient norm of by .
4. The atomic case.
Let be an infinite dimensional (complex) Banach lattice throughout this section. Recall that is called an atom, if the band generated by is one dimensional, i.e., . Denote by the set of all positive atoms in of norm one. Then is called an atomic Banach lattice if the band generated by equals . If we denote by the band projection from onto , then every can be written as an order convergent series
Note that if is countable, then we have the usual Banach sequence spaces. Now every can be represented as a multiplication operator, where for each there exists such that . Then, if , we have . The following lemma is well-known in the countable case. We include for convenience of the reader the similar proof for the uncountable case.
Lemma 4.1.
Let be an atomic Banach lattice with, as above, the set the set of all positive atoms of norm one. Let as above. Then if and only if
Proof.
Assume first that . Then there exists such that . Then there exist distinct , for , such that for all . As is a compact operator we can assume, by passing to a subsequence, that . As we can, by passing to a further subsequence, assume that , where . Now , which implies that . This contradicts that for all and thus . This implies that and thus . Conversely if . Then for all we have for at most finitely many . This implies that is countable. Let (with the obvious modification if the set on the right is finite). We have then that . Now the estimate
implies that is a norm limit of finite rank operators and thus compact. ∎
We now show that the expression is actually a quotient norm. Let denote the Banach lattice of all bounded functions with the supremum norm and the closed ideal of all with . Then
Theorem 4.2.
Let and be as above. Then we have for all .
Proof.
Note first that
Let . Then implies that there exists such that . Now implies that there is a finite subset of such that for all . This implies that for all . Hence
Similarly for there exists a finite subset of such that for all . Now define by for and otherwise. Then . Hence
which completes the proof. ∎
Corollary 4.3.
Let be an atomic Banach lattice with, as above, the set the set of all positive atoms of norm one. Let . Then
Theorem 4.4.
Let be an atomic Banach lattice with, as above, the set the set of all positive atoms of norm one. Let . Then the essential spectrum is given by
Moreover, the essential spectral radius of is given by
and the essential norm of satisfies .
Proof.
We note that it is sufficient to prove if and only if is a Fréchet cluster point of the function , as if and only . Assume first that and that is not a Fréchet cluster point of the function . Then by Theorem 3.5 we have . Let . Then there exists a finite subset of such that for all . Now is a finite rank operator, so that . Now for all implies that . As and as is a band projection, it follows that also is a band projection. Combined with the lower estimate we obtained above, this implies that is invertible on . This implies that is a Fredholm operator on and thus , which contradicts our assumption. Now assume that is a Fréchet cluster point of the function . Then there exist infinitely many distinct with such that . This implies that and that is not isolated in . It is well-known that this implies that , which completes the proof of the first part of the theorem. The formula for the essential spectral radius follows now immediately from Corollary 3.6. The formula for the essential norm follows from the above and the previous corollary as follows
∎
5. The general case.
Let be a (complex) Banach lattice. Denote by the set of all positive atoms in of norm one. Then the atomic part of is the band generated by and will be denoted by . The disjoint complement of will be called the non-atomic part (or continuous part) of and will be denoted by . Below we shall see by means of an example that these bands in general don’t need to be projection bands (but are so of course when is Dedekind complete). Therefore we have in general that is only a norm closed, order dense ideal in . We denote the restriction of to by (the atomic part of ) and to by (the non-atomic or continuous part of ). As is band preserving we have and , but in general is not the direct sum of these two operators, as is only defined on . To overcome this technical difficulty, we use the following lemma.
Proposition 5.1.
Let be a Banach lattice and a norm closed, order dense ideal in . Let . Then .
Proof.
As is a restriction of we always have . To prove the reverse inequality, observe that
Now implies by order continuity of that also . This implies that and equality of norms follows. ∎
Theorem 5.2.
Let be a (complex) Banach lattice and . Then
and thus
Moreover .
Proof.
It is easy to see that and , so . Therefore assume that . Then is Fredholm on . As by the main result in the non-atomic case, we see that there exists such that . Now is Fredholm on implies that there exist a finite subset of such that the kernel of is . Then is invertible on , so there exists such that . This implies that for that . This implies that is invertible on . As is finite dimensional this implies that , which shows that . The formula for the essential spectral radius follows now from the previous results. To prove the result about the essential norm, observe that is always true, so it remains to show that . Let . Then is a closed order dense ideal in . Therefore, using the preceding proposition, we have
by the above. Hence . ∎
We conclude with an example of a Banach lattice for which the atomic part is not a projection band.
Example 5.3.
Let and for . Then it is easy to verify that for . Now put . Then is compact in the induced Euclidean topology. Let . Let denote the Dirac delta function supported by . Then it is clear that the set of positive atoms of norm one equals . Note that , as is not continuous at . Now the continuous part of equals . Note implies by continuity that . Now the atomic part is equal to . Again by continuity for . Hence , as the function identical one is in . Therefore is not a projection band. It is well-known that for a space each is given by a multiplication by a function , as is lattice isometric to . Denote by the operator .Then we have . Thus we have . Now for all . As is the only cluster point of the sequence , it follows that . The essential spectrum of the non-atomic part of is
Therefore
We also observe that is compact if and only if we have , i.e., if and only if . Moreover we can write with if and only if , i.e., if and only if is compact.
As the above example shows that in general, if , then is not the sum of and , where and .However that is so if only if is compact. We now show that this is always the case for the if part of the statement.
Proposition 5.4.
Let be a (complex) Banach lattice and such that is compact. Then there exist with compact such that where and .
Proof.
Let . Then is compact implies that . This implies that the set is countable and is a norm limit of the series in . As this series also converges in , it follows that extends to a compact operator in such that . Let . Then it clear from that . ∎
In [3] it was observed that if for all bounded self-adjoint operators on a Hilbert space, for a given self-adjoint , then is compact. The following theorem is an order analogue of this.
Theorem 5.5.
Let be a (complex) Banach lattice and such that . Then is compact.
Proof.
From we conclude that . From Theorem 5.2 we see that and . From Theorem 4.4 we see that . This implies that is compact on . By the above proposition there exist with compact such that where and . Now by Theorem 2.1 and thus . This implies that , which by order density of and order continuity of implies that . Hence is compact. ∎
Remark.
We could have phrased the above result alternatively as: If is essentially quasi-nilpotent, then is compact.
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