Sobolev extensions over Cantor-cuspidal graphs
Abstract.
For a continuous function , define the corresponding graph by setting
In this paper, we study the Sobolev extension property for the upper and lower domains over the graph for , where is the classical ternary Cantor set in the unit interval and .
2010 Mathematics Subject Classification:
46E35, 30L991. Introduction
Let . If is a Lipschitz function on then the upper and lower domains determined by the graph of are extension domains for all the first order Sobolev spaces by the works of Calderón and Stein [11]: if is either one of these domains, then there is a linear bounded extension operator from into In fact, it is not hard to check that one can obtain such an extension operator via a bi-Lipschitz reflection that switches the upper and lower domains: the bi-Lipschitz map maps the two domains onto half-planes and one can use the usual reflection with respect to the first coordinate axes, modulo and its inverse.
If is Hölder-continuous, one cannot necessarily extend from to since the graph of can contain cusps. In this case, under the correct assumptions on and the Hölder-exponent, one can nevertheless extend from to see [2], in the sense that the extension belongs to with
More precisely, if and then any can be obtained. For a single cusp, the sharp exponents for the interior are and and for the exterior and or . This follows from more general work of Gol’dshtein and Sitnikov [3] who showed that for certain cusp-like domains with Hölder boundaries one can obtain an extension via a reflection which in this case is not anymore bi-Lipschitz. For an exposition and more historical references for the theory of Sobolev spaces on non-smooth domains, we refer the reader to [10].
In this paper we consider the above extension problem in a model case in oder to gain better insight to the problem. Towards our model case, let be the standard ternary Cantor set, obtained by removing a sequence of ‘centrally located” open intervals from : at stage we have closed intervals, each of length from the middle of each we remove an open interval of length For , we define by setting
(1.1) |
Then is Hölder continuous with exponent Define the corresponding graph by setting
and let be the domain above the “Cantor-cuspidal” graph
and be the domain below the “Cantor-cuspidal” graph
See Figure below. Notice that
for all Hence the common boundary of both of these domains is ‘cusp-like” in a set of Hausdorff dimension
Towards our results, we call a homeomorphism a reflection over if and for all Let be one of the domains We say that a reflection over induces a bounded linear extension operator from to if for every the function defined by setting on and on has a representative that belongs to such that for every bounded open set , we have
(1.2) |
for a positive constant independent of . In our setting, this conclusion easily implies that one can find an extension with

The following theorem is the main result of the article.
Theorem 1.1.
Let . Then there exists a reflection over which induces a bounded linear extension operator from to and a bounded linear extension operator from to , whenever and .
The following proposition shows the sharpness of Theorem 1.1.
Proposition 1.1.
Let be fixed. Then for arbitrary , there exist functions and which do not have extensions in the class .
Let be fixed. Then for arbitrary , there exist functions and which do not have extensions in the class .
Let be fixed. Then for arbitrary and , there exist functions and which do not have extensions in the class .
We would like to know if Theorem 1.1 exhibits a general principle: could it be the case that for graphs the Sobolev extension problem is equivalent to the existence of a suitable reflection? For partial results in this direction see [3, 9]. The symmetry in Theorem 1.1 cannot hold in general as follows by the results in [3], our reflection has better properties that one would in general expect [6, 7].
We close this introduction with a comment regarding the case A domain is called quasiconvex, if there exists a positive constant such that for every pair of points , there exists a rectifiable curve joining with
For every , one can easily see that neither nor is quasiconvex. Then the corollary in [8] with a bit of work implies that neither nor is a Sobolev -extension domain. Hence, in the proof to Proposition 1.1 below, we will only discuss the case for .
2. Preliminaries
The notation means a point in the Euclidean plane . Typically will be a constant that depends on various parameters and may differ even on the same line of inequalities. The notation means there exists a finite constant with , and means for a constant . The Euclidean distance between points in the Euclidean plane is denoted by . The open disk of radius centered at is denoted by . means the -dimensional Lebesgue measure for a measurable set .
To obtain the classical ternary Cantor set in the unit interval , we remove a class of pairwise disjoint open intervals step by step. At the first step, we remove the middle -interval from the unit interval . At the second step, we remove the middle -intervals and from the two intervals of length obtained from the first step. By induction, at the -th step, we remove the middle -intervals from the intervals of length obtained from the -th step. Finally, we obtain the classical ternary Cantor set
Let us denote the removed open intervals by . Then, the function defined in (1.1) can be rewritten as
(2.1) |
Let us give the definition of Sobolev spaces.
Definition 2.2.
Let be a domain and . A vector function is called a weak derivative of if
holds for every function . We refer to by . For , we define the Sobolev space by
and we define the norm by
If for every bounded open subset with , , then we say .
Although the Cantor-cuspidal graph has a plethora of singularities, the corresponding upper and lower domains and still enjoy some nice geometric properties. For example, they satisfy the following so-called segment condition.
Definition 2.3.
We say that a domain satisfies the segment condition if every has a neighborhood and a nonzero vector such that if , then for .
For domains which satisfy the segment condition, we have the following density result. See [1, Theorem 3.22].
Lemma 2.1.
If the domain satisfies the segment condition, then the set of restrictions to of functions in is dense in for . In short, is dense in for .
Lemma 2.2.
Let . Suppose that is a homeomorphism in the class Then the following assertions are equivalent:
for every locally Lipschitz function defined on , the inequality
holds for a positive constant independent of ;
3. A reflection over
In this section, we always assume . To begin, we define a class of sets by setting
(3.1) |
We also define and to be the corresponding upper and lower parts of with respect to by setting
(3.2) |
and
(3.3) |
Fix for some and Then
(3.4) |
is a vertical line segment in and
(3.5) |
is a vertical line segment in .

Now, we are ready to define our reflection over . Our reflection will map the segment onto the segment affinely for every . To be precise, we define the reflection on by setting
(3.6) |
where . It is easy to check that maps onto , for every and . On , we simply let be the inverse of (3.6). Since , and for every , is a reflection over . For every with and , the reflection maps onto affinely.
By a simple computation, at every point for some and , the differential matrix is
(3.7) |
By another simple computation, there exists a positive constant such that for every , we have
(3.8) |
and
(3.9) |
Next, let us estimate the analog of of Lemma 2.2 for :
whenever and .
By a simple computation, we can rewrite the reflection on as
(3.11) |
where . At every point for and , the differential matrix is
(3.12) |
There exists a positive constant such that
(3.13) |
and
(3.14) |
Hence, we have
whenever and .
Finally, it is easy to see that the reflection is bi-Lipschitz on every open set with .
4. Sobolev extendability for
4.1. Extension from to
Theorem 4.1.
Proof.
Let and be fixed. Since satisfies the segment condition defined in Definition 2.3, by Lemma 2.1, is dense in . Let be arbitrary. We define a function on by setting
(4.1) |
Since , is continuous on . Also since is bi-Lipschitz on every open set with , the function is locally Lipschitz on . Hence, the weak derivative is well-defined on .
Let be an arbitrary bounded open set. We define
We will show that with
Here the constant may depend on the open set but must be independent of the function . Since is an arbitrary bounded open set, it suffices to prove inequalities
(4.2) |
and
(4.3) |
Define
Then . Since , we have
(4.4) |
and
(4.5) |
By the definition of in (4.1), the Hölder inequality implies
(4.6) |
and
(4.7) |
By (3.9), the Hölder inequality and a change of variables, we have
By combining (4.6) and (4.1), we obtain the inequality (4.2). In order to prove the inequality (4.3), it suffices to show
(4.9) |
By Lemma 2.2, it suffices to show that
By a similar computation as in the previous section, we have
whenever and . By combining (4.7) and (4.9), we obtain the inequality (4.3). Hence, the reflection defined in (3.6) induces a bounded linear extension operator from to . For arbitrary , there exists a sequence of function with
and
By combining (4.2) and (4.3), we obtain
(4.10) |
It implies that is a Cauchy sequence in the Sobolev space for arbitrary bounded open set . Hence, there exists a subsequence of which converges to a Sobolev function point-wise almost everywhere. By covering with countably many bounded open sets, there exists a subsequence of which converges to a function point-wise almost everywhere and for every bounded open set . We define on by setting
(4.11) |
By the definition of , we have for almost every . Hence, for almost every . It means that with
(4.12) |
Since is an arbitrary bounded open set, we proved that the reflection induces a bounded linear extension operator from to , whenever and . ∎
4.2. Sharpness of Theorem 4.1 for
Let be fixed. For every and , we define a cuspidal domain by setting
(4.13) |
The reason why we call a cuspidal domain is that the domain has a cuspidal singularity at every end-point of the removed interval . For -th generation of cuspidal domains , let be the left-most one and be the right-most one. For a cuspidal domain with in the -th generation with , there exist two cuspidal domains and from generations before which are close to . One is on the right-hand side of and the other is on the left-hand side of . Let be in the left-hand side of and be in the right-hand side of . For every removed open interval , define to be the middle point of it. Then we define two open sets and by setting
and
For the left-most generation cuspidal domain , we define
and
For the right-most generation cuspidal domain , we define
and
On every with , we define a function by setting
(4.14) |
On the set , we simply set . For every , we define a number by setting
(4.15) |
Then . Next, we define our test-function by setting
(4.16) |
with
(4.17) |
First, a simple computation gives
for and . Furthermore
(4.19) |
Hence,
for and . Hence, . For every and and every
we define to be a horizontal line segment inside the cuspidal domain . See the picture below. Assume that there exists an extension for some . By the -characterization of Sobolev functions and the Hölder inequality, for almost every
we have
(4.21) |
with a uniform constant independent of .
The following three propositions show the sharpness of the result in Theorem 4.1.
Proposition 4.1.
Let and let be the corresponding Cantor-cuspidal graph. Then, for arbitrary , the function cannot be extended to be a function in the class .
Proof.
Since , we can choose in the definition of the function in (4.16). Then . Since both and vanish outside a bounded set, the Hölder inequality implies , for every . Assume that there exists an extension in the class . By (4.21) and the Fubini theorem, we obtain
This contradicts the assumption that and the proof is finished. ∎
Proposition 4.2.
Let and be the corresponding Cantor-cuspidal graph. Then for arbitrary , there exists a function which can not be extended to be a function in the class .
Proof.
Proposition 4.3.
Let and be the corresponding Cantor-cuspidal graph. For arbitrary , there exists a function which can not be extended to be a function in the class , whenever .
5. Sobolev extendability for
5.1. Extension from to
Theorem 5.1.
Proof.
Simply replace by in the proof of Theorem 4.1 and repeat the argument. ∎
5.2. Sharpness of Theorem 5.1
Let us define a function on . For every even and , we define
For odd and every , we define the function on by setting
(5.1) |
Outside the set , we just set . Finally, we define our function on by setting
(5.2) |
where is given in (4.15) and is given in (4.17). Then we have
since . There exists a positive constant such that for odd
(5.4) |
for every with . Moreover elsewhere. Hence, we have
since and . Hence, . Fixing an odd and , there exists two cuspidal domains and nearby from the next generation. One is on the right-hand side of and the other is on the left-hand side of . Without loss of generalization, we assume is on the left-hand side of and is on the right-hand side of . For every
we define
and
Assume that there exists an extension . By the -characterization of Sobolev functions and the Hölder inequality, we have
(5.6) |
and
(5.7) |
for almost every
where the constant is independent of .
The following propositions show the sharpness of the result in Theorem 5.1.
Proposition 5.1.
Let and be the corrersponding Cantor-cuspidal graph. Then for arbitrary , there exists a function which cannot be extended to be a function in the class .
Proof.
Since , we fix in the definition of in (5.2). Then . Since both and vanish outside a bounded set, the Hölder inequality implies , for every . Assume that there exists an function in the class . By (5.6), (5.7) and the Fubini theorem, we have
since and This contradicts the assumption that and the proof is finished. ∎
Proposition 5.2.
Let and be the corresponding Cantor-cuspidal graph. Then, for arbitrary , there exists a function which can not be extended to be a function in the class .
Proof.
Proposition 5.3.
Let and be the corresponding Cantor-cuspidal graph. For arbitrary , there exists a function which can not be extended to be a function in the class , whenever .
Proof.
Fix
The Hölder inequality implies that it suffices to show that can not be extended to be a function in the class . Fix in the definition of in (5.2). Assume that there exists an extension . By (5.6), (5.7) and the Fubini theorem, we have
since and . This contradicts the assumption that and the proof is finished. ∎
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