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Representing the stress and strain energy of elastic solids with initial stress and transverse texture anisotropy

Soumya Mukherjee
Department of Mechanical Engineering
National Institute of Technology Jamshedpur
Jamshedpur, Jharkhand 831014, India.
[email protected] &Michel Destrade
School of Mathematical and Statistical Sciences
University of Galway
Galway, Ireland
Department of Engineering Mechanics
Zhejiang University
Hangzhou 310027, PR China &Artur L. Gower
Department of Mechanical Engineering
The University of Sheffield
Sheffield, United Kingdom
[email protected]
Abstract

Real-world solids, such as rocks, soft tissues, and engineering materials, are often under some form of stress. Most real materials are also, to some degree, anisotropic due to their microstructure, a characteristic often called the ‘texture anisotropy’. This anisotropy can stem from preferential grain alignment in polycrystalline materials, aligned micro-cracks, or structural reinforcement, such as collagen bundles in biological tissues, steel rods in prestressed concrete and reinforcing fibres in composites. Here we establish a framework for initially stressed solids with transverse texture anisotropy. We consider that the strain energy per unit mass of the reference is an explicit function of the elastic deformation gradient, the initial stress tensor, and the texture anisotropy. We determine the corresponding constitutive relations and develop examples of nonlinear strain energies which depend explicitly on the initial stress and direction of texture anisotropy. As an application, we then employ these models to analyse the stress distribution of an inflated initially stressed cylinder with texture anisotropy, and the tension of a welded metal plate. We also deduce the elastic moduli needed to describe linear elasticity from stress reference with transverse texture anisotropy. As an example we show how to measure the stress with small-amplitude shear waves.

Keywords residual stress, initial stress, texture anisotropy, constitutive modelling, ultrasonic modelling

1 Introduction

There are many materials with texture anisotropy that are under stress in their natural state, such as metals, rocks and other polycrystalline materials, or biological soft and hard tissues [53, 49], see examples in Figure 1. It is crucial to account for both initial stress and texture when designing testing methods for these materials, especially non-destructive inspection methods based on the propagation of ultrasonic elastic waves [51, 29, 33, 51, 30]. To understand the elastic response of these materials and link it directly to the initial stress, we must derive constitutive equations from a strain energy function which explicitly depends on both initial stress and texture anisotropy [14].

Refer to caption
Figure 1: Residual stresses and texture anisotropy are present in many natural and man-made structures. A piece of leek (a) or a ring of squid (b) both spontaneously open up when cut radially, revealing that they were subject to circumferential residual stresses (the leek clearly has a microstructure aligned with its axis which creates texture anisotropy in that direction). Concrete slabs (c) are pre-stressed by metallic rods to ensure they are under compression everywhere (shutterstock.com), with the rods creating texture anisotropy. Finite Element simulations (d), made with Ansys® Academic Research Mechanical, show that high temperature metal welding creates very high compressive thermal stresses that can cause compressive plastic deformation localised at the weld zone. This plastic deformation introduces high tensile and compressive residual stresses at the weld-zone and away from it. This build-up is characteristic of many manufacturing processes such as metal cutting, rolling, machining, welding, etc.

In this paper, we deduce strain energy functions WW and necessary restrictions on the Cauchy stress 𝝈\boldsymbol{\sigma}, when they are explicit functions of the initial stress and texture anisotropy. We define initial stress as the stress in some reference configuration, which can have any origin. When this stress is present without any traction applied at the boundary, it is known as residual stress.

Hoger and collaborators [21, 22, 23, 24, 27, 28] developed the first models for initially stressed hyperelastic materials. Johnson and Hoger [27] presented the idea of a virtual stress-free configuration, obtained by cutting an initially stressed body into infinitely many small pieces and releasing all the initial stress stored. They showed numerically that the virtual stress-free configuration can be used to appropriately model the material in an initially stressed configuration, as well.

Strain energy functions can be written explicitly in terms of the initial stress by considering the combined invariants of the initial stress with the elastic deformation gradient, see the work of Ogden and collaborators [45, 42, 36]. Gower and collaborators [14, 15] then introduced a necessary restriction for the strain energy and stress, when these depend on the reference only through the initial stress (and mass density), and elastic deformation gradient; they called the restriction ISRI (Initial Stress Reference Independence). They showed that without this restriction, absurd results could arise, even for a uniaxial deformation, see the example given in the beginning of [15]. These models have since led to practical new methods to measure stress [30]. In this paper, we also use ISRI, applying it now to initially stressed materials that also have texture anisotropy.

Gower et al. [15] developed two models for initially stressed compressible isotropic materials satisfying ISRI of the neo-Hookean type; Agosti et al. [1] proposed incompressible Mooney-Rivlin models; Mukherjee [37, 38] determined a model for incompressible stressed Gent materials [37], and obtained a failure model in the presence of residual stress [38]. These models helped to examine how growth and initial stress are coupled [10, 11, 12, 31], to study wave propagation [4] and wrinkles/creases [5] in residually stressed tubes, and to investigate the static and dynamic characteristics of composite spheres [40]. In this paper, we develop two strain energy functions for initially stressed materials that are compressible and have texture anisotropy, and demonstrate their practical use by solving a boundary value problem involving the inflation of a thick-walled cylinder.

Among other relevant works, we mention those by Merodio et al. [35] and Shariff et al.[47] for initially stressed isotropic materials, and by Ogden and Singh [42] and Shariff [46] for initially stressed structurally anisotropic materials, some of which do not satisfy ISRI [14, 15].

Finally we note that linearised theories for initially stressed isotropic materials provide a powerful tool for many small-strain problems. This type of theory would prove most useful for designing various experiments, like elastic wave propagation, to measure initial stress. Indeed, cutting an initially stressed solid into an infinite number of pieces to arrive at a stress-free configuration is not practical in the real world, so that ultrasonic non-destructive evaluation might be the only avenue available to testing. Grine [17] employed linear constitutive relations for stressed isotropic materials to numerically determine the mechanical fields in a cracked body. So far, there seems to be no appropriate linearised theory for initially stressed transversely isotropic materials available.

This paper is organised as follows. In Section 2, we formulate initial stress reference independence for initially stressed transversely isotropic materials. We employ the reference independence and other properties of initial stress to determine the invariants here. These invariants are then used to derive constitutive relations. In Section 3, we develop some reference-independent strain energy functions for initially stressed compressible transversely isotropic materials by using initial stress symmetry (ISS) [14]. With one of the models, we solve two boundary value problems: inflation of initially stressed tubes and stretching of a welded joint. Finally in Section 4 we determine the linearised constitutive relation for small strain and small initial strain, and employ ISRI to put restrictions on the material parameters. We show how the resulting equations can be used to design a method to measure the initial stress with shear waves.

2 Initial stress reference independence for textural transverse isotropy

In this section, we develop the principle of reference independence for initially stressed transversely isotropic materials and establish other properties of initial stress to determine the required constitutive relations, including the invariants required for hyperelastic modelling.

The constitutive relation for elastic solids can be determined from the strain energy density WW per unit volume of reference. For a material with initial stress tensor 𝝉\boldsymbol{\tau}, and with a preferred direction of textural symmetry along a vector 𝑴{\boldsymbol{M}}, the strain energy density has the functional dependence W=W(𝑭,𝝉,𝑴)W=W\left({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}}\right), where 𝑭{\boldsymbol{F}} is the elastic deformation gradient from the reference configuration \mathcal{R} to the current configuration 𝒞\mathcal{C}.

Refer to caption
Figure 2: The three configurations for initially stressed solids: (a) the reference configuration \mathcal{R} with initial stress 𝝉\boldsymbol{\tau} and texture direction 𝑴{\boldsymbol{M}} (b) the reference configuration ^\hat{\mathcal{R}} with initial stress 𝝉^\hat{\boldsymbol{\tau}} and texture direction 𝑴^\hat{{\boldsymbol{M}}} (c) the current configuration 𝒞\mathcal{C}.

Figure 2 depicts three configurations (\mathcal{R}, ^\hat{\mathcal{R}} and 𝒞\mathcal{C}) for initially stressed solids with textural symmetry. We consider that the deformation (with gradient 𝑭{\boldsymbol{F}}) taking place between \mathcal{R} and 𝒞\mathcal{C} may equivalently by decomposed into a deformation (with gradient 𝑭^\hat{{\boldsymbol{F}}}) from \mathcal{R} to ^\hat{\mathcal{R}}, an intermediate configuration, followed by another deformation (with gradient 𝑭~\tilde{{\boldsymbol{F}}}) from ^\hat{\mathcal{R}} to 𝒞\mathcal{C}. As a result, 𝑭=𝑭~𝑭^{\boldsymbol{F}}=\tilde{{\boldsymbol{F}}}\hat{{\boldsymbol{F}}} and J=J~J^J=\tilde{J}\hat{J}, where J=det𝑭J=\det{\boldsymbol{F}}, J~=det𝑭~\tilde{J}=\det\tilde{\boldsymbol{F}}, J^=det𝑭^\hat{J}=\det\hat{\boldsymbol{F}}. The preferred directions of texture anisotropy are given by 𝑴{\boldsymbol{M}} and 𝑴^\hat{{\boldsymbol{M}}} in the configurations \mathcal{R} and ^\hat{\mathcal{R}}, respectively, and related by

𝑴^=𝑭^𝑴,\hat{{\boldsymbol{M}}}=\hat{{\boldsymbol{F}}}{\boldsymbol{M}}, (1)

noticing that 𝑴^\hat{{\boldsymbol{M}}} is not necessarily a unit vector. We call 𝝉\boldsymbol{\tau} and 𝝉^\hat{\boldsymbol{\tau}} the initial stress fields in configurations \mathcal{R} and ^\hat{\mathcal{R}}, respectively.

We now enforce the principle of Initial Stress Reference Independence (ISRI) [15], stating that the energy density of the configuration 𝒞\mathcal{C} should be the same whether it is arrived at by the direct deformation from {\mathcal{R}} or the composed deformation via ^\hat{\mathcal{R}}. This translates as

W(𝑭,𝝉,𝑴)=J^W(𝑭~,𝝈(𝑭^,𝝉,𝐌),𝐌^),W({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}})=\hat{J}W\left(\tilde{{\boldsymbol{F}}},\boldsymbol{\sigma}(\hat{\boldsymbol{F}},\boldsymbol{\tau},\bf M),\hat{\boldsymbol{M}}\right), (2)

where 𝝈(𝑭^,𝝉,𝐌)\boldsymbol{\sigma}(\hat{\boldsymbol{F}},\boldsymbol{\tau},\bf M) is the Cauchy stress in ^\hat{\mathcal{R}}. We call it 𝝉^\hat{\boldsymbol{\tau}}, and rewrite this identity as

J1W(𝑭,𝝉,𝑴)=J~1W(𝑭~,𝝉^,𝑴^),J^{-1}W\left({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}}\right)=\tilde{J}^{-1}W\left(\tilde{{\boldsymbol{F}}},\hat{\boldsymbol{\tau}},\hat{{\boldsymbol{M}}}\right), (3)

holding for all 𝝉\boldsymbol{\tau}, 𝑴{\boldsymbol{M}}, 𝑭~\tilde{{\boldsymbol{F}}}, and 𝑭^\hat{{\boldsymbol{F}}}. Differentiating both sides of (3) with respect to 𝑭~\tilde{{\boldsymbol{F}}}, we obtain, after some algebra,

J1𝑭W𝑭(𝑭,𝝉,𝑴)=J~1𝑭~W𝑭~(𝑭~,𝝉^,𝑴^),J^{-1}{\boldsymbol{F}}\frac{\partial W}{\partial{\boldsymbol{F}}}\left({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}}\right)=\tilde{J}^{-1}\tilde{{\boldsymbol{F}}}\frac{\partial W}{\partial\tilde{{\boldsymbol{F}}}}\left(\tilde{{\boldsymbol{F}}},\hat{\boldsymbol{\tau}},\hat{{\boldsymbol{M}}}\right), (4)

which provides ISRI in terms of Cauchy stress in the current configuration 𝒞\mathcal{C} as follows:

𝝈(𝑭,𝝉,𝑴)=𝝈(𝑭~,𝝉^,𝑴^).\boldsymbol{\sigma}\left({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}}\right)=\boldsymbol{\sigma}\left(\tilde{{\boldsymbol{F}}},\hat{\boldsymbol{\tau}},\hat{{\boldsymbol{M}}}\right). (5)

Now we investigate the dependence of stress and energy density over their arguments.

Because any rigid body rotation (represented by the proper orthogonal tensor 𝑸{\boldsymbol{Q}}, say) should not result in a change of energy density, we write that W(𝑭,𝝉,𝑴)=W(𝑸𝑭,𝝉,𝑴)W\left({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}}\right)=W\left({\boldsymbol{Q}}{\boldsymbol{F}},\boldsymbol{\tau},{{\boldsymbol{M}}}\right), which ensures that WW depends on 𝑭{\boldsymbol{F}} through the right Cauchy-Green deformation tensor 𝑪=𝑭T𝑭{\boldsymbol{C}}={\boldsymbol{F}}^{T}{\boldsymbol{F}}. Moreover, we assume that the energy density is the same when reversing the direction of 𝑴{\boldsymbol{M}} to 𝑴-{\boldsymbol{M}}. Consequently, the energy density should depend directly on the texture tensor 𝑮=𝑴𝑴{\boldsymbol{G}}={\boldsymbol{M}}\otimes{\boldsymbol{M}}. As a result, W=W(𝑭,𝝉,𝑴)W=W\left({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}}\right) can also be seen as a function of 𝑪{\boldsymbol{C}}, 𝝉\boldsymbol{\tau}, and 𝑮{\boldsymbol{G}}, which enables the following representation of stress,

𝝈(𝑭,𝝉,𝑴)=2J1𝑭W𝑪(𝑪,𝝉,𝑮)𝑭T.\boldsymbol{\sigma}({\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{M}})=2J^{-1}{\boldsymbol{F}}\frac{\partial W}{\partial{\boldsymbol{C}}}\left({\boldsymbol{C}},\boldsymbol{\tau},{\boldsymbol{G}}\right){\boldsymbol{F}}^{T}. (6)

In the same way, the statement of ISRI given in (3) can be reframed as

J1W(𝑭T𝑭,𝝉,𝑮)=J~1W(𝑭~T𝑭~,𝝉^,𝑴^𝑴^.),J^{-1}W\left({\boldsymbol{F}}^{T}{\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{G}}\right)=\tilde{J}^{-1}W\left(\tilde{{\boldsymbol{F}}}^{T}\tilde{{\boldsymbol{F}}},\hat{\boldsymbol{\tau}},\hat{{\boldsymbol{M}}}\otimes\hat{{\boldsymbol{M}}}.\right), (7)

or

W(𝑭T𝑭,𝝉,𝑮)=J~W(𝑭~T𝑭~,𝝈(𝑭^,𝝉,𝑴),𝑭^𝑮𝑭^T).W\left({\boldsymbol{F}}^{T}{\boldsymbol{F}},\boldsymbol{\tau},{\boldsymbol{G}}\right)=\tilde{J}W\left(\tilde{{\boldsymbol{F}}}^{T}\tilde{{\boldsymbol{F}}},\boldsymbol{\sigma}(\hat{{\boldsymbol{F}}},\boldsymbol{\tau},{\boldsymbol{M}}),\hat{{\boldsymbol{F}}}{\boldsymbol{G}}\hat{{\boldsymbol{F}}}^{T}\right). (8)

This relation determines an important restriction for initially stressed materials.

To see this, we consider 𝑭^\hat{{\boldsymbol{F}}} as any proper rotation tensor 𝑸{\boldsymbol{Q}} and determine the relationships between 𝝉\boldsymbol{\tau} and 𝝉^\hat{\boldsymbol{\tau}}, and 𝑴{\boldsymbol{M}} and 𝑴^\hat{{\boldsymbol{M}}}. Note that if we additionally consider 𝑭~=𝑰\tilde{{\boldsymbol{F}}}={\boldsymbol{I}}, we obtain the deformation gradient 𝑭=𝑭^=𝑸{\boldsymbol{F}}=\hat{{\boldsymbol{F}}}={\boldsymbol{Q}}, and consequently 𝑪=𝑭T𝑭=𝑰{\boldsymbol{C}}={{\boldsymbol{F}}}^{T}{{\boldsymbol{F}}}={\boldsymbol{I}}. Then, because 𝑭~\tilde{{\boldsymbol{F}}} is chosen to be the identity, the current configuration 𝒞\mathcal{C} is same as the configuration ^\hat{\mathcal{R}} and the Cauchy stress in the configuration 𝒞\mathcal{C} is identical to the initial stress 𝝉^\hat{\boldsymbol{\tau}} in configuration ^\hat{\mathcal{R}}. We obtain this initial stress 𝝉^\hat{\boldsymbol{\tau}} from (6) as

𝝉^=𝝈(𝑭^,𝝉,𝑴)|𝑭^=𝑸=2𝑸[W𝑪(𝑪,𝝉,𝑮)]𝑪=𝑰𝑸T.\hat{\boldsymbol{\tau}}=\boldsymbol{\sigma}(\hat{{\boldsymbol{F}}},\boldsymbol{\tau},{\boldsymbol{M}})\big{|}_{{\hat{{\boldsymbol{F}}}}={\boldsymbol{Q}}}=2{\boldsymbol{Q}}\left[\frac{\partial W}{\partial{\boldsymbol{C}}}\left({\boldsymbol{C}},\boldsymbol{\tau},{\boldsymbol{G}}\right)\right]_{{\boldsymbol{C}}={\boldsymbol{I}}}{\boldsymbol{Q}}^{T}. (9)

However, using initial condition 𝑭=𝑰{\boldsymbol{F}}={\boldsymbol{I}} in (6), we obtain the initial stress 𝝉\boldsymbol{\tau} in configuration \mathcal{R} as

𝝉=2[W𝑪(𝑪,𝝉,𝑮)]𝑪=𝑰.\boldsymbol{\tau}=2\left[\frac{\partial W}{\partial{\boldsymbol{C}}}\left({\boldsymbol{C}},\boldsymbol{\tau},{\boldsymbol{G}}\right)\right]_{{\boldsymbol{C}}={\boldsymbol{I}}}. (10)

Substituting (10) in (9), we obtain 𝝉^=𝑸𝝉𝑸T\hat{\boldsymbol{\tau}}={\boldsymbol{Q}}\boldsymbol{\tau}{\boldsymbol{Q}}^{T}. Moreover, substituting 𝑭^=𝑸\hat{{\boldsymbol{F}}}={\boldsymbol{Q}} in (1) we obtain 𝑴^=𝑸𝑴\hat{{\boldsymbol{M}}}={\boldsymbol{Q}}{\boldsymbol{M}}. Employing the above expressions of 𝝉^\hat{\boldsymbol{\tau}} and 𝑴^\hat{{\boldsymbol{M}}} in (7) we find the following important restriction on the strain energy density,

W(𝑪,𝝉,𝑮)=W(𝑸𝑪𝑸T,𝑸𝝉𝑸T,𝑸𝑮𝑸T).W\left({\boldsymbol{C}},\boldsymbol{\tau},{\boldsymbol{G}}\right)=W\left({\boldsymbol{Q}}{\boldsymbol{C}}{\boldsymbol{Q}}^{T},{\boldsymbol{Q}}{\boldsymbol{\tau}}{\boldsymbol{Q}}^{T},{\boldsymbol{Q}}{{\boldsymbol{G}}}{\boldsymbol{Q}}^{T}\right). (11)

The 19 invariants which satisfy (11) can be chosen as follows,

I1=tr𝑪,\displaystyle I_{1}=\mathop{\rm tr}\nolimits{\boldsymbol{C}}, I2=12[tr(𝑪)2tr(𝑪2)],\displaystyle I_{2}=\tfrac{1}{2}[\mathop{\rm tr}\nolimits({\boldsymbol{C}})^{2}-\mathop{\rm tr}\nolimits({\boldsymbol{C}}^{2})], I3=det𝑪,\displaystyle I_{3}=\text{det}\;{\boldsymbol{C}}, I𝑴=𝑴.𝑴,\displaystyle I_{{\boldsymbol{M}}}={\boldsymbol{M}}.{\boldsymbol{M}},
I4=𝑴.𝑪𝑴,\displaystyle I_{4}={\boldsymbol{M}}.{\boldsymbol{C}}{\boldsymbol{M}}, I5=𝑴.𝑪2𝑴,\displaystyle I_{5}={\boldsymbol{M}}.\boldsymbol{C}^{2}{\boldsymbol{M}}, I𝝉1=tr𝝉,\displaystyle I_{\boldsymbol{\tau}_{1}}=\mathop{\rm tr}\nolimits\boldsymbol{\tau},
I𝝉2=12[tr(𝝉)2tr(𝝉2)],\displaystyle I_{\boldsymbol{\tau}_{2}}=\tfrac{1}{2}[\mathop{\rm tr}\nolimits(\boldsymbol{\tau})^{2}-\mathop{\rm tr}\nolimits(\boldsymbol{\tau}^{2})], I𝝉3=det(𝝉),\displaystyle I_{\boldsymbol{\tau}_{3}}=\text{det}\left(\boldsymbol{\tau}\right), I𝝉4=𝑴.𝝉𝑴,\displaystyle I_{\boldsymbol{\tau}_{4}}={\boldsymbol{M}}.\boldsymbol{\tau}{\boldsymbol{M}}, I𝝉5=𝑴.𝝉2𝑴,\displaystyle I_{\boldsymbol{\tau}_{5}}={\boldsymbol{M}}.\boldsymbol{\tau}^{2}{\boldsymbol{M}},
I9=tr(𝝉𝑪),\displaystyle I_{9}=\mathop{\rm tr}\nolimits(\boldsymbol{\tau}\boldsymbol{C}), I10=tr(𝝉𝑪2),\displaystyle I_{10}=\mathop{\rm tr}\nolimits(\boldsymbol{\tau}\boldsymbol{C}^{2}), I11=tr(𝝉2𝑪),\displaystyle I_{11}=\mathop{\rm tr}\nolimits(\boldsymbol{\tau}^{2}\boldsymbol{C}), I12=tr(𝝉2𝑪2),\displaystyle I_{12}=\mathop{\rm tr}\nolimits(\boldsymbol{\tau}^{2}\boldsymbol{C}^{2}),
I13=𝑴.𝝉𝑪𝑴,\displaystyle I_{13}=\boldsymbol{M}.\boldsymbol{\tau}\boldsymbol{C}\boldsymbol{M}, I14=𝑴.𝝉𝑪2𝑴,\displaystyle I_{14}=\boldsymbol{M}.\boldsymbol{\tau}\boldsymbol{C}^{2}{\boldsymbol{M}}, I15=𝑴.𝝉2𝑪𝑴,\displaystyle I_{15}=\boldsymbol{M}.\boldsymbol{\tau}^{2}\boldsymbol{C}{\boldsymbol{M}}, I16=𝑴.𝝉2𝑪2𝑴.\displaystyle I_{16}=\boldsymbol{M}.\boldsymbol{\tau}^{2}\boldsymbol{C}^{2}{\boldsymbol{M}}. (12)

Note that we allow 𝑴𝑴1{\boldsymbol{M}}\cdot{\boldsymbol{M}}\not=1 (hence the presence of I𝑴I_{\boldsymbol{M}} in the list), as it simplifies how we use equation (7) to restrict WW (Alternatively, we could have imposed 𝑴𝑴=1{\boldsymbol{M}}\cdot{\boldsymbol{M}}=1, which would complicate calculations later, but would still lead to the same results.)

For background on the invariant approach to constitutive equations, see Spencer [48] and Zheng [54]. Mukherjee and Mandal [39] used similar invariants for a generalisation using fractional powers of 𝑪{\boldsymbol{C}}, and Ogden and Singh [42] used some of these invariants to study wave propagation in initially stressed solids. Shariff et al. [47] show, using a spectral decomposition, that each standard invariant used for isotropic materials with initial stress is not independent of the others, making it is likely that some of the invariants in (12) can be expressed in terms of the others.

Using (6), we next derive the Cauchy stress from the above-derived invariants as

𝝈\displaystyle\boldsymbol{\sigma} (𝑭,𝑴,𝝉)=2J1[WI1𝑩+WI2(I1𝑩𝑩2)+I3WI3𝑰+WI4𝑭𝑮𝑭T+WI11(𝑭𝝉2𝑭T)]\displaystyle\left({\boldsymbol{F}},{\boldsymbol{M}},\boldsymbol{\tau}\right)=2J^{-1}\left[W_{I_{1}}{\boldsymbol{B}}+W_{I_{2}}\left(I_{1}{\boldsymbol{B}}-{\boldsymbol{B}}^{2}\right)+I_{3}W_{I_{3}}{\boldsymbol{I}}+W_{I_{4}}{\boldsymbol{F}}{\boldsymbol{G}}{\boldsymbol{F}}^{T}+W_{I_{11}}\left({\boldsymbol{F}}\boldsymbol{\tau}^{2}{\boldsymbol{F}}^{T}\right)\right]
+2J1[WI5(𝑭𝑮𝑭T𝑩+𝑩𝑭𝑮𝑭T)+WI9(𝑭𝝉𝑭T)+WI10(𝑭𝝉𝑭T𝑩+𝑩𝑭𝝉𝑭T)]\displaystyle+2J^{-1}\left[W_{I_{5}}\left({\boldsymbol{F}}{\boldsymbol{G}}{\boldsymbol{F}}^{T}{\boldsymbol{B}}+{\boldsymbol{B}}{\boldsymbol{F}}{\boldsymbol{G}}{\boldsymbol{F}}^{T}\right)+W_{I_{9}}\left({\boldsymbol{F}}\boldsymbol{\tau}{\boldsymbol{F}}^{T}\right)+W_{I_{10}}\left({\boldsymbol{F}}\boldsymbol{\tau}{\boldsymbol{F}}^{T}{\boldsymbol{B}}+{\boldsymbol{B}}{\boldsymbol{F}}\boldsymbol{\tau}{\boldsymbol{F}}^{T}\right)\right]
+2J1[WI12(𝑭𝝉2𝑭T𝑩+𝑩𝑭𝝉2𝑭T)+WI13(𝑭𝝉𝑮𝑭T+𝑭𝑮𝝉𝑭T)+WI15(𝑭𝑮𝝉2𝑭T)]\displaystyle+2J^{-1}\left[W_{I_{12}}\left({\boldsymbol{F}}\boldsymbol{\tau}^{2}{\boldsymbol{F}}^{T}{\boldsymbol{B}}+{\boldsymbol{B}}{\boldsymbol{F}}\boldsymbol{\tau}^{2}{\boldsymbol{F}}^{T}\right)+W_{I_{13}}\left({\boldsymbol{F}}\boldsymbol{\tau}{\boldsymbol{G}}{\boldsymbol{F}}^{T}+{\boldsymbol{F}}{\boldsymbol{G}}\boldsymbol{\tau}{\boldsymbol{F}}^{T}\right)+W_{I_{15}}\left({\boldsymbol{F}}{\boldsymbol{G}}\boldsymbol{\tau}^{2}{\boldsymbol{F}}^{T}\right)\right]
+J1[WI14(𝑭𝑮𝝉𝑭T𝑩+𝑩𝑭𝝉𝑮𝑭T+𝑩𝑭𝑮𝝉𝑭T+𝑭𝝉𝑮𝑭T𝑩)+WI15(𝑭𝝉2𝑮𝑭T)]\displaystyle+J^{-1}\left[W_{I_{14}}\left({\boldsymbol{F}}{\boldsymbol{G}}\boldsymbol{\tau}{\boldsymbol{F}}^{T}{\boldsymbol{B}}+{\boldsymbol{B}}{\boldsymbol{F}}\boldsymbol{\tau}{\boldsymbol{G}}{\boldsymbol{F}}^{T}+{\boldsymbol{B}}{\boldsymbol{F}}{\boldsymbol{G}}\boldsymbol{\tau}{\boldsymbol{F}}^{T}+{\boldsymbol{F}}\boldsymbol{\tau}{\boldsymbol{G}}{\boldsymbol{F}}^{T}{\boldsymbol{B}}\right)+W_{I_{15}}\left({\boldsymbol{F}}\boldsymbol{\tau}^{2}{\boldsymbol{G}}{\boldsymbol{F}}^{T}\right)\right]
+J1[WI16(𝑭𝑮𝝉2𝑭T𝑩+𝑩𝑭𝝉2𝑮𝑭T+𝑩𝑭𝑮𝝉2𝑭T+𝑭𝝉2𝑮𝑭T𝑩)],\displaystyle+J^{-1}\left[W_{I_{16}}\left({\boldsymbol{F}}{\boldsymbol{G}}\boldsymbol{\tau}^{2}{\boldsymbol{F}}^{T}{\boldsymbol{B}}+{\boldsymbol{B}}{\boldsymbol{F}}\boldsymbol{\tau}^{2}{\boldsymbol{G}}{\boldsymbol{F}}^{T}+{\boldsymbol{B}}{\boldsymbol{F}}{\boldsymbol{G}}\boldsymbol{\tau}^{2}{\boldsymbol{F}}^{T}+{\boldsymbol{F}}\boldsymbol{\tau}^{2}{\boldsymbol{G}}{\boldsymbol{F}}^{T}{\boldsymbol{B}}\right)\right],\ (13)

where WIi:=W/IiW_{I_{i}}:=\partial W/\partial I_{i}. This Cauchy stress should satisfy the initial condition 𝝉=𝝈(𝑰,𝝉,𝑴)\boldsymbol{\tau}=\boldsymbol{\sigma}({\boldsymbol{I}},\boldsymbol{\tau},{\boldsymbol{M}}) for 𝑭=𝑰{\boldsymbol{F}}={\boldsymbol{I}}, which provides the condition for initial stress compatibility on the material parameters.

Note that the initial condition is 𝝉=𝝈(𝑰,𝝉,𝑴)\boldsymbol{\tau}=\boldsymbol{\sigma}({\boldsymbol{I}},\boldsymbol{\tau},{\boldsymbol{M}}). Hence by evaluating (13) for 𝑭=𝑰{\boldsymbol{F}}={\boldsymbol{I}}, we write the initial stress compatibility condition as

𝝉\displaystyle\boldsymbol{\tau} =(2W0I1+4W0I2+2W0I3)𝑰+(2W0I4+4W0I5)𝑮+(2W0I9+4W0I10)𝝉\displaystyle=\left(2{W}_{0I_{1}}+4{W}_{0I_{2}}+2{W}_{0I_{3}}\right){\boldsymbol{I}}+\left(2{W}_{0I_{4}}+4{W}_{0I_{5}}\right){\boldsymbol{G}}+\left(2{W}_{0I_{9}}+4{W}_{0I_{10}}\right)\boldsymbol{\tau}
+(2W0I11+4W0I12)𝝉2+(2W0I13+4W0I14)(𝑮𝝉+𝝉𝑮)\displaystyle+\left(2{W}_{0I_{11}}+4{W}_{0I_{12}}\right)\boldsymbol{\tau}^{2}+\left(2{W}_{0I_{13}}+4{W}_{0I_{14}}\right)\left({\boldsymbol{G}}\boldsymbol{\tau}+\boldsymbol{\tau}{\boldsymbol{G}}\right)
+(2W0I15+4W0I16)(𝝉2𝑮+𝑮𝝉2),\displaystyle+\left(2{W}_{0I_{15}}+4{W}_{0I_{16}}\right)\left(\boldsymbol{\tau}^{2}{\boldsymbol{G}}+{\boldsymbol{G}}\boldsymbol{\tau}^{2}\right), (14)

Equating coefficients of 𝑰{\boldsymbol{I}}, 𝝉\boldsymbol{\tau}, etc., on both sides of (14) we have

(2W0I1+4W0I2+2W0I3)=0,\displaystyle\left(2{W}_{0I_{1}}+4{W}_{0I_{2}}+2{W}_{0I_{3}}\right)=0, (2W0I4+4W0I5)=0,\displaystyle\left(2{W}_{0I_{4}}+4{W}_{0I_{5}}\right)=0, (2W0I9+4W0I10)=1,\displaystyle\left(2{W}_{0I_{9}}+4{W}_{0I_{10}}\right)=1,
(2W0I13+4W0I14)=0,\displaystyle\left(2{W}_{0I_{13}}+4{W}_{0I_{14}}\right)=0, (2W0I13+4W0I14)=0,\displaystyle\left(2{W}_{0I_{13}}+4{W}_{0I_{14}}\right)=0, (2W0I15+4W0I16)=0\displaystyle\left(2{W}_{0I_{15}}+4{W}_{0I_{16}}\right)=0 (15)

where W0Ii{W}_{0I_{i}} is the value of WIiW_{I_{i}} calculated in the reference configuration for 𝑭=𝑰{\boldsymbol{F}}={\boldsymbol{I}}.

3 Strain energy functions satisfying ISRI and application

In the previous section, we derived Initial Stress Reference Independence (ISRI) for materials with texture-induced and stress-induced anisotropy. From now on, we assume that strain energy functions satisfy ISRI, to avoid some non-physical behaviours [14, 15, 1].

In this section we propose two strain energy densities for initially strained (Section 3.1) and initially stressed (Section 3.2) compressible structurally anisotropic materials, one which is linear in I9I_{9} and another with nonlinear combinations of the invariants. Our approach to deriving these strain energy densities can be applied to many other invariant-based energy functions. Then, as two important applications, we solve the boundary value problems of an inflated tube (Section 3.3) and of the tension of a welded steel plate (Section 3.4).

3.1 Constitutive models for initial strain and texture-induced anisotropy

One way to deduce strain energies that depend on the stress explicitly and satisfy ISRI, is to start with a conventional strain energy that depends only on the strain. To this end, we introduce an initial deformation gradient 𝑭0{\boldsymbol{F}}_{0} from a stress-free configuration 0\mathcal{R}_{0} to the initially strained configuration \mathcal{R}, so that the total deformation gradient from 0\mathcal{R}_{0} to the deformed configuration 𝒞\mathcal{C} is 𝑭¯=𝑭𝑭0\bar{{\boldsymbol{F}}}={\boldsymbol{F}}{\boldsymbol{F}}_{0}. We call 𝑴0{\boldsymbol{M}}_{0} the unit vector along the direction of transverse anisotropy in 0\mathcal{R}_{0}.

A strain energy density defined as W:=J01W0(𝑪¯,𝑴0𝑴0)W:=J_{0}^{-1}W_{0}\left({\bar{{\boldsymbol{C}}}},{{\boldsymbol{M}}}_{0}\otimes{{\boldsymbol{M}}}_{0}\right) can be expressed as W=J1W1(𝑪,𝑩0,𝑴𝑴)W=J^{-1}W_{1}\left({\boldsymbol{C}},{{\boldsymbol{B}}}_{0},{{\boldsymbol{M}}\otimes{\boldsymbol{M}}}\right) using transformation of reference configuration 0\mathcal{R}_{0}\rightarrow\mathcal{R} where 𝑪¯=𝑭¯T𝑭¯\bar{{\boldsymbol{C}}}={\bar{{\boldsymbol{F}}}}^{T}{\bar{{\boldsymbol{F}}}}, 𝑩0=𝑭0𝑭0T{{\boldsymbol{B}}}_{0}={{\boldsymbol{F}}}_{0}{{\boldsymbol{F}}}_{0}^{T}, and 𝑴0{{\boldsymbol{M}}}_{0} is along the preferred direction of structural anisotropy in configurations 0\mathcal{R}_{0}.

The strain energy density with reference 0\mathcal{R}_{0} should be a function W=W(I¯1,I¯2,I¯3,I¯4,I¯5,)W=W\left(\bar{I}_{1},\bar{I}_{2},\bar{I}_{3},\bar{I}_{4},\bar{I}_{5},\ldots\right), where I¯1=tr𝑪¯\bar{I}_{1}=\mathop{\rm tr}\nolimits{\bar{{\boldsymbol{C}}}}, I¯2=[tr(𝑪¯)2tr(𝑪¯2)]/2\bar{I}_{2}=[\mathop{\rm tr}\nolimits\left(\bar{{\boldsymbol{C}}}\right)^{2}-\mathop{\rm tr}\nolimits\left(\bar{{\boldsymbol{C}}}^{2}\right)]/2, I¯3=det𝑪¯\bar{I}_{3}=\mathrm{det}\;{\bar{{\boldsymbol{C}}}}, I¯4=𝑴0.𝑪¯𝑴0\bar{I}_{4}={\boldsymbol{M}}_{0}.{\bar{{\boldsymbol{C}}}}{\boldsymbol{M}}_{0}, I¯5=𝑴0.𝑪¯2𝑴0\bar{I}_{5}={\boldsymbol{M}}_{0}.{\bar{{\boldsymbol{C}}}}^{2}{\boldsymbol{M}}_{0}, etc., are various invariants of 𝑪¯{\bar{{\boldsymbol{C}}}}. When \mathcal{R} is considered as the reference, we use 𝑭¯=𝑭𝑭0{\bar{{\boldsymbol{F}}}}={\boldsymbol{F}}{\boldsymbol{F}}_{0} to rewrite the first five invariants of 𝑪¯{\bar{{\boldsymbol{C}}}} as

I¯1\displaystyle\bar{I}_{1} =tr(𝑩0𝑪),\displaystyle=\mathop{\rm tr}\nolimits\left({\boldsymbol{B}}_{0}{\boldsymbol{C}}\right), (16)
I¯2\displaystyle\bar{I}_{2} =12{[tr(𝑩0𝑪)]2tr[(𝑩0𝑪)2]},\displaystyle=\tfrac{1}{2}\left\{\left[\mathop{\rm tr}\nolimits\left({\boldsymbol{B}}_{0}{{\boldsymbol{C}}}\right)\right]^{2}-\mathop{\rm tr}\nolimits\left[\left({\boldsymbol{B}}_{0}{{\boldsymbol{C}}}\right)^{2}\right]\right\}, (17)
I¯3\displaystyle\bar{I}_{3} =J02J2,\displaystyle=J_{0}^{2}J^{2}, (18)
I¯4\displaystyle\bar{I}_{4} =𝑴.𝑪𝑴,\displaystyle={\boldsymbol{M}}.{\boldsymbol{C}}{\boldsymbol{M}}, (19)
I¯5\displaystyle\bar{I}_{5} =𝑴.𝑪𝑩0𝑪𝑴,\displaystyle={\boldsymbol{M}}.{\boldsymbol{C}}{\boldsymbol{B}}_{0}{\boldsymbol{C}}{\boldsymbol{M}}, (20)

where Jo=det𝑭0J_{o}=\text{det}\;{\boldsymbol{F}}_{0} and 𝑴=𝑭0𝑴0{\boldsymbol{M}}={\boldsymbol{F}}_{0}{\boldsymbol{M}}_{0}. Notice that the additional structural tensors introduced in the above invariants are 𝑩0{\boldsymbol{B}}_{0} and 𝑭0𝑴0𝑴0𝑭0T{\boldsymbol{F}}_{0}{\boldsymbol{M}}_{0}\otimes{\boldsymbol{M}}_{0}{\boldsymbol{F}}_{0}^{T}. Using the invariants (16)-(20), we propose the following two strain energy densities for initially strained compressible transversely isotropic materials

W\displaystyle W =μ12J0(I¯13)+μ22J0(I¯41)μ1J0β[1(I¯3)β],\displaystyle=\frac{\mu_{1}}{2J_{0}}\left(\bar{I}_{1}-3\right)+\frac{\mu_{2}}{2J_{0}}\left(\bar{I}_{4}-1\right)-\frac{\mu_{1}}{J_{0}\beta}\left[1-\left(\sqrt{\bar{I}_{3}}\right)^{-\beta}\right], (21)
W\displaystyle W =μ12J0(I¯13)+μ22J0(I¯51)μ1J0β[1(I¯3)β],\displaystyle=\frac{\mu_{1}}{2J_{0}}\left(\bar{I}_{1}-3\right)+\frac{\mu_{2}}{2J_{0}}\left(\bar{I}_{5}-1\right)-\frac{\mu_{1}}{J_{0}\beta}\left[1-\left(\sqrt{\bar{I}_{3}}\right)^{-\beta}\right], (22)

for the stress-free reference configuration, where μ1\mu_{1}, μ2\mu_{2} and β\beta are material parameters. The volumetric function in (21) and (22) is chosen by following Haughton and Orr [18], but other choices are available in the literature. This function requires β>1/3\beta>-{1}/{3} to ensure a positive initial bulk modulus.

The Cauchy stress 𝝈=2J𝑭W𝑪𝑭T\boldsymbol{\sigma}=\frac{2}{J}{\boldsymbol{F}}\frac{\partial W}{\partial{\boldsymbol{C}}}{\boldsymbol{F}}^{T} is then determined for the strain energy functions (21) and (22) as

𝝈\displaystyle\boldsymbol{\sigma} =μ1JJ0𝑭𝑩0𝑭T+μ2JJ0𝑭𝑴𝑭𝑴μ1(JJ0)β+1𝑰,\displaystyle=\frac{\mu_{1}}{JJ_{0}}{\boldsymbol{F}}{\boldsymbol{B}}_{0}{\boldsymbol{F}}^{T}+\frac{\mu_{2}}{JJ_{0}}{\boldsymbol{F}}{\boldsymbol{M}}\otimes{\boldsymbol{F}}{\boldsymbol{M}}-\frac{\mu_{1}}{\left(JJ_{0}\right)^{\beta+1}}{\boldsymbol{I}}, (23)
𝝈\displaystyle\boldsymbol{\sigma} =μ1JJ0𝑭𝑩0𝑭T+μ2JJ0(𝑭𝑩0𝑪𝑴𝑭𝑴+𝑭𝑴𝑴𝑪𝑩0𝑭T)μ1(JJ0)β+1𝑰,\displaystyle=\frac{\mu_{1}}{JJ_{0}}{\boldsymbol{F}}{\boldsymbol{B}}_{0}{\boldsymbol{F}}^{T}+\frac{\mu_{2}}{JJ_{0}}\left({\boldsymbol{F}}{\boldsymbol{B}}_{0}{\boldsymbol{C}}{\boldsymbol{M}}\otimes{\boldsymbol{F}}{\boldsymbol{M}}+{\boldsymbol{F}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}{\boldsymbol{C}}{\boldsymbol{B}}_{0}{\boldsymbol{F}}^{T}\right)-\frac{\mu_{1}}{\left(JJ_{0}\right)^{\beta+1}}{\boldsymbol{I}}, (24)

respectively.

Gower et al. [15] show that initially strained models naturally satisfy ISRI, so that it is the case for the proposed strain energy functions (21), (22). These strain energy functions are useful when the initial strain is known (in terms of 𝑩0{\boldsymbol{B}}_{0}, 𝑴𝑴{\boldsymbol{M}}\otimes{\boldsymbol{M}}, etc.) instead of the initial stress 𝝉\boldsymbol{\tau}. In the next section, we determine strain energy functions for initially stressed transversely isotropic materials when the initial strain is not known.

3.2 Constitutive models for initial stress and texture-induced anisotropy

Here, we rewrite the strain energy densities (21)-(22) using the invariants of initial stress symmetry derived in Section 2. We eliminate 𝑭0{\boldsymbol{F}}_{0} and related quantities in favour of the initial stress 𝝉\boldsymbol{\tau}. The end result is that the final expressions of WW do not depend on knowing the stress-free configuration 0\mathcal{R}_{0}, which indeed might remain hypothetical and unattainable.

Starting with (21), we first obtain the expression of the initial stress 𝝉\boldsymbol{\tau} by substituting 𝑭=𝑰{\boldsymbol{F}}={\boldsymbol{I}} in (23), which gives

μ1J0𝑩0+μ2J0𝑴𝑴=𝝉+μ1J0β+1𝑰.\frac{\mu_{1}}{J_{0}}{\boldsymbol{B}}_{0}+\frac{\mu_{2}}{J_{0}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}=\boldsymbol{\tau}+\frac{\mu_{1}}{J_{0}^{\beta+1}}{\boldsymbol{I}}. (25)

Next we multiply this equation by 𝑪{\boldsymbol{C}} and take the trace, to find the following expression,

W=12(I93μ1μ2)+μ12J0β+1I1μ1J0β[1(JJ0)β].W=\frac{1}{2}\left(I_{9}-3\mu_{1}-\mu_{2}\right)+\frac{\mu_{1}}{2J_{0}^{\beta+1}}I_{1}-\frac{\mu_{1}}{J_{0}\beta}\left[1-\left(JJ_{0}\right)^{-\beta}\right]. (26)

It remains to eliminate J0J_{0} to obtain a strain-energy function in terms of initial stress only (and not initial strain). To express J0J_{0} in terms of initial stress we take the determinant of both sides of (25), as

det(μ1𝑩0+μ2𝑴𝑴)=J03det(𝝉+μ1J0β+1𝑰),\text{det}\left({\mu_{1}}{\boldsymbol{B}}_{0}+{\mu_{2}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}\right)=J_{0}^{3}\text{det}\left(\boldsymbol{\tau}+\frac{\mu_{1}}{J_{0}^{\beta+1}}{\boldsymbol{I}}\right), (27)

the left hand side of which is calculated as

det(μ1𝑩0+μ2𝑭𝑴0𝑴0𝑭T)=(det𝑭0)det(μ1𝑰+μ2𝑴0𝑴0)(det𝑭0)=J02μ12(μ1+μ2).\text{det}\left({\mu_{1}}{\boldsymbol{B}}_{0}+{\mu_{2}}{\boldsymbol{F}}{\boldsymbol{M}}_{0}\otimes{\boldsymbol{M}}_{0}{\boldsymbol{F}}^{T}\right)=\left(\text{det}\;{\boldsymbol{F}}_{0}\right)\text{det}\left({\mu_{1}}{\boldsymbol{I}}+{\mu_{2}}{\boldsymbol{M}}_{0}\otimes{\boldsymbol{M}}_{0}\right)\left(\text{det}{\boldsymbol{F}}_{0}\right)=J_{0}^{2}\mu_{1}^{2}\left(\mu_{1}+\mu_{2}\right). (28)

Substituting (28) in (27) and expanding the determinant on the right hand side, we obtain an equation for J0J_{0},

(μ1J0β+1)3+(μ1J0β+1)2I𝝉1+(μ1J0β+1)I𝝉2+I𝝉3μ12J0(μ1+μ2)=0.\left(\frac{\mu_{1}}{{J_{0}}^{\beta+1}}\right)^{3}+\left(\frac{\mu_{1}}{{J_{0}}^{\beta+1}}\right)^{2}I_{\boldsymbol{\tau}_{1}}+\left(\frac{\mu_{1}}{{J_{0}}^{\beta+1}}\right)I_{\boldsymbol{\tau}_{2}}+I_{\boldsymbol{\tau}_{3}}-\frac{\mu_{1}^{2}}{J_{0}}\left(\mu_{1}+\mu_{2}\right)=0. (29)

For a given initially stressed solid with transverse texture, μ1\mu_{1}, μ2\mu_{2}, 𝝉\boldsymbol{\tau} and β\beta are prescribed, and J0J_{0} is a quantity to found by solving this equation numerically. Then the strain energy density (26) is explicit, and gives the Cauchy stress by differentiation. For example, by choosing μ1=3.0\mu_{1}=3.0, μ2=1.5\mu_{2}=1.5, β=1.0\beta=1.0, 𝝉=diag(1.12,1,1.5)\boldsymbol{\tau}=\text{diag}\left(1.12,1,1.5\right), we find J0=1.9157J_{0}=1.9157 as the only real positive root of (29).

In this way, the model is useful for modelling residually-stressed materials, without having to specify the origin of the residual stress. The resulting constitutive relation is

𝝈=1J[𝑭𝝉𝑭T+μ1J0β+1(𝑩1Jβ+1𝑰)].\boldsymbol{\sigma}=\frac{1}{J}\left[{\boldsymbol{F}}\boldsymbol{\tau}{\boldsymbol{F}}^{T}+\frac{\mu_{1}}{J_{0}^{\beta+1}}\left({\boldsymbol{B}}-\frac{1}{J^{\beta+1}}{\boldsymbol{I}}\right)\right]. (30)

Although it is not obvious at first glance, texture anisotropy is indeed embedded into the model (26),(30). It is measured by the magnitude of the material parameter μ2\mu_{2}, which plays a role in determining J0J_{0} from Equation (29), and also be seen in the form that the initial stress 𝝉\boldsymbol{\tau} must take according to (25).

Turning now to (22), we find that a similar, but more involved, process (detailed in Appendix A), leads to the following expression for WW,

W=\displaystyle W= 12(I9+μ1J0β+1I13μ1)+μ12[2a2(I13+μ1J0β+1I4)+a3(I𝝉4I4+μ1J0β+1I4I𝑴)]\displaystyle\frac{1}{2}\left(I_{9}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}I_{1}-3\mu_{1}\right)+\frac{\mu_{1}}{2}\left[2a_{2}\left(I_{13}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}I_{4}\right)+a_{3}\left(I_{\boldsymbol{\tau}_{4}}I_{4}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}I_{4}I_{{\boldsymbol{M}}}\right)\right]
+μ22[a1𝑴.𝑪𝝉𝑪𝑴+2a2I4I13+a3I42I𝝉4+μ1J0β+1(a1I5+2a2I42+a3I42I𝑴)1]\displaystyle+\frac{\mu_{2}}{2}\left[a_{1}{\boldsymbol{M}}.{\boldsymbol{C}}\boldsymbol{\tau}{\boldsymbol{C}}{\boldsymbol{M}}+2a_{2}I_{4}I_{13}+a_{3}I_{4}^{2}I_{\boldsymbol{\tau}_{4}}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}\left(a_{1}I_{5}+2a_{2}I_{4}^{2}+a_{3}I_{4}^{2}I_{{\boldsymbol{M}}}\right)-1\right]
μ1(1(JJ0)β)βJ0,\displaystyle-{\mu_{1}}\frac{(1-\left(JJ_{0}\right)^{-\beta})}{\beta J_{0}}, (31)

where the material parameters a1a_{1}, a2a_{2}, and a3a_{3} are calculated as

a1=1μ1,a2=μ2μ1(μ1+μ2I𝑴),a3=2μ22μ1(μ12+3μ1μ2I𝑴+2μ22I𝑴2)a_{1}=\frac{1}{\mu_{1}},\qquad a_{2}=-\frac{\mu_{2}}{\mu_{1}(\mu_{1}+\mu_{2}I_{{\boldsymbol{M}}})},\qquad a_{3}=\frac{2\mu_{2}^{2}}{\mu_{1}\left(\mu_{1}^{2}+3\mu_{1}\mu_{2}I_{{\boldsymbol{M}}}+2\mu_{2}^{2}I_{{\boldsymbol{M}}}^{2}\right)} (32)

by inverting a fourth order tensor [26] and the non-linear constitutive relation for transversely isotropic materials. The expression of initial strain obtained in terms of stress and texture is given by

𝑩0=a1𝝉^+a2𝝉^𝑴𝑴+a2𝑴𝑴𝝉^+a3𝑴𝑴𝝉^𝑴𝑴,{\boldsymbol{B}}_{0}=a_{1}\hat{\boldsymbol{\tau}}+a_{2}\hat{\boldsymbol{\tau}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}+a_{2}{\boldsymbol{M}}\otimes{\boldsymbol{M}}\hat{\boldsymbol{\tau}}+a_{3}{\boldsymbol{M}}\otimes{\boldsymbol{M}}\hat{\boldsymbol{\tau}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}, (33)

with 𝝉^=J0(𝝉+μ1J0β+1𝑰)\hat{\boldsymbol{\tau}}=J_{0}\left(\boldsymbol{\tau}+\tfrac{\mu_{1}}{{J_{0}}^{\beta+1}}{\boldsymbol{I}}\right), which is substituted in (24) to obtain Cauchy stress from a stressed reference.

The expression (31) of WW contains most of the invariants developed in (12): I1I_{1}, I3I_{3}, I𝑴I_{{\boldsymbol{M}}} I4I_{4}, I5I_{5}, I𝝉4I_{\boldsymbol{\tau}_{4}}, I9I_{9}, I13I_{13}, and also 𝑴.𝑪𝝉𝑪𝑴{\boldsymbol{M}}.{\boldsymbol{C}}\boldsymbol{\tau}{\boldsymbol{C}}{\boldsymbol{M}}, which can be expressed as a function of other standard invariants using the Cayley-Hamilton theorem.

Using this constitutive relation requires a few more calculations, such as computing the initial strain invariants like J0J_{0} and 𝑴0.𝑪02𝑴0{\boldsymbol{M}}_{0}.{\boldsymbol{C}}_{0}^{2}{\boldsymbol{M}}_{0} in terms of initial stress invariants. We show these details in Appendix A.

3.3 Inflation of a stressed transversely isotropic compressible tube

Here we solve the boundary value problem of the inflation of a thick-walled cylindrical tube with initial stress and preferred direction of texture anisotropy aligned with (a) the axis of the cylinder and (b) the radial direction. This modelling aims at capturing the residual stress fields observed in tubular biological structures such as arteries, veins, ducts, etc., and also leeks or squid rings as shown in Figure (1).

The deformation gradient for inflating the tube is taken as

𝑭=diag(drdR,rR,zZ),{\boldsymbol{F}}=\text{diag}\left(\frac{\mathrm{d}r}{\mathrm{d}R},\frac{r}{R},\frac{z}{Z}\right), (34)

where rr and RR are the radii in the current and the reference configurations respectively, zz and ZZ are the axial positions of a material point in the wall. We assume that the tube is constrained so that no axial extension or contraction occurs: z=Zz=Z, for example by being placed between two fixed rigid platens [12].

We call RAR_{A} and RBR_{B} the inner and outer radii of the tube in the reference configuration. For the radial component of the initial stress we choose τRR=Λ(RRA)(RRB)\tau_{RR}=\Lambda\left(R-R_{A}\right)\left(R-R_{B}\right) where Λ\Lambda is a measure of the initial stress magnitude, which may be positive (radially tensile) or negative (compressive). This choice leaves the curved faces free of normal stress (cylinder in a vacuum). The circumferential component is found by solving the equation of equilibrium dτRR/dR+(τRRτθθ)/R=0\mathrm{d}\tau_{RR}/\mathrm{d}R+(\tau_{RR}-\tau_{\theta\theta})/R=0, to give τΘΘ=Λ[(RRA)(RRB)R(RA+RB2R)]\tau_{\Theta\Theta}=\Lambda\left[\left(R-R_{A}\right)\left(R-R_{B}\right)-R\left(R_{A}+R_{B}-2R\right)\right]. Finally τZZ\tau_{ZZ} is found from the boundary conditions at the platens.

Refer to caption
Figure 3: Radial distribution of the residual stress field in the initially stressed tube. The radial component vanishes on the curved faces of the tube to satisfy the traction-free surface conditions. The hoop stress is compressive on the inner circumference and tensile on the outside. This field captures the characteristics of the residual stress observed in real-world structures such as arteries, squid rings, leeks, etc., which open up when cut radially (see Figure 1). The parameter Λ\Lambda determines the magnitude of the residual stress.

Figure 3 shows the spatial distribution of the residual stress field. It agrees with the residual stress fields reported in Figure 4 of [43] for arteries, and can also be used for other tubular structures which open up when cut radially. Other distributions can be used to model this opening (logarithmic, exponential, etc.), but as shown by Ciarletta et al. [5], we can expect the qualitative results to be similar.

The stress components in this inflated cylinder corresponding to the strain energy density (26) are

σrr=(τRR+μ1J0β+1)rRrμ1(JJ0)β+1,σθθ=(τΘΘ+μ1J0β+1)rrRμ1(JJ0)β+1,\sigma_{rr}=\left(\tau_{RR}+\frac{\mu_{1}}{J_{0}^{\beta+1}}\right)\frac{r^{\prime}R}{r}-\frac{\mu_{1}}{(JJ_{0})^{\beta+1}},\qquad\sigma_{\theta\theta}=\left(\tau_{\Theta\Theta}+\frac{\mu_{1}}{J_{0}^{\beta+1}}\right)\frac{rr^{\prime}}{R}-\frac{\mu_{1}}{(JJ_{0})^{\beta+1}}, (35)

where r=dr/dRr^{\prime}={\mathrm{d}r}/{\mathrm{d}R} and J=rr/RJ=r^{\prime}r/R. To find the function r=r(R)r=r(R), we write the equilibrium equation dσrr/dr+(σrrσθθ)/r=0\mathrm{d}\sigma_{rr}/\mathrm{d}r+(\sigma_{rr}-\sigma_{\theta\theta})/r=0 as

dσrrdR+r(σrrσθθ)r=0.\frac{\mathrm{d}\sigma_{rr}}{\mathrm{d}R}+\frac{r^{\prime}\left(\sigma_{rr}-\sigma_{\theta\theta}\right)}{r}=0. (36)

For our example, we assume that a hydrostatic pressure P-P (to be determined) is applied at the inner face r(RA)r(R_{A}), such that the inner diameter increases by 50%. Hence the boundary conditions are

r(RA)=1.50RA,σrr(RB)=0.r(R_{A})=1.50R_{A},\qquad\sigma_{rr}\left(R_{B}\right)=0. (37)
Refer to caption
Figure 4: Stress distribution for various amounts of residual stress as measured by Λ=1.5,1.0,0.0,1.0,1.5\Lambda=-1.5,-1.0,0.0,1.0,1.5, for a compressible tube with texture anisotropy modelled by the strain-energy density (26). Here the importance of anisotropy to initial stress is measured by the ratio μ2/μ1=1.5\mu_{2}/\mu_{1}=1.5. We consider that under the pressure P=σrr(RA)-P=\sigma_{rr}(R_{A}), the inner radius has increased to r(RA)=1.5RAr(R_{A})=1.5R_{A}, while the outer face at RB=2.0R_{B}=2.0 remains free of traction. Circumferential and radial stress components when the texture direction is aligned with (a) the cylinder axis and (b) the radial direction.

To solve numerically (36), subject to (37), we use the MATLAB ‘bvp5c’ command. Figure 4 shows the variations of the Cauchy stress components σRR\sigma_{RR} and σθθ\sigma_{\theta\theta} through the thickness for different amounts of the initial stress parameter Λ\Lambda. The internal pressure required to inflate the cylinder is found as P=σRR(RA)P=-\sigma_{RR}\left(R_{A}\right).

We observe that all the hoop stress σθθ\sigma_{\theta\theta} curves cross at a point through the thickness, independently of the magnitude of the residual stress. A similar scenario was also observed in the investigation of unbending of an incompressible stressed isotropic cylinder [39]. Using a closed-form solution, Mukherjee and Mandal [39] showed that the hoop and radial components of residual stress have opposing effects and nullify each other’s contribution at this particular point. Such a closed-form solution is not attainable for the present problem of cylinder inflation where the material is compressible and includes texture symmetry as well.

For positive or negative Λ\Lambda, σrr\sigma_{rr} is distributed almost symmetrically around the Λ=0\Lambda=0 curve (no residual stress). It would be exactly symmetric if we considered that the total stress is the sum of the residual stress and of the stress developed without residual stress (see residual stress distribution in Figure 3). However, due to the intrinsic nonlinearity of the system, exact symmetry is not observed.

In conclusion, we observe that the residual stress and the texture anisotropy significantly affect both stress distribution characteristics for this boundary value problem.

3.4 Tension of a welded steel plate

Residual stress develops during manufacturing due to accumulation of incompatible plastic strain. In this section, we investigate the stress developed during the stretching of a welded steel plate by using our strain energy functions (22) and (21).

Figure 1 (d) shows the residual stress in a welded alloy steel structure, which we obtained through finite element analysis. There, the weld plate has finite dimensions, and because of end effects, the residual stress field is complicated, as seen in the figure.

For an infinitely long weld joint, Masubuchi and Martin [34, 3] determined analytically the residual stress field as

τyy(x)=τ0[1(yb)2]e(y22b2),\tau_{yy}\left(x\right)=\tau_{0}\left[1-\left(\frac{y}{b}\right)^{2}\right]e^{\left(-\frac{y^{2}}{2b^{2}}\right)}, (38)

where yy is the direction of welding, xx is the transverse direction, zz is the direction through thickness, τ0\tau_{0} is the maximum residual stress, which can be as high as the yield stress of the material, and bb is half the thickness of the weld-zone. We consider some typical values, say τ0=100\tau_{0}=100 MPa and b=5b=5 cm, and report in Figure 5 the corresponding residual stress distribution.

Using the residual stress (38), we can now predict the stress in the weld when under tension. Note that the considered strain energy densities (21) and (22) are consistent with the Hooke law of linearised elasticity in the stress-free reference for small strain. For example, when we take μ1=E/(1+ν)=156.28\mu_{1}=E/(1+\nu)=156.28 GPa, β=ν/(12ν)=0.6363\beta=\nu/\left(1-2\nu\right)=0.6363, μ2=0\mu_{2}=0, the models match exactly the isotropic properties of steel at small strain where the Young modulus is E=200E=200 GPa and the Poisson ratio is ν=0.28\nu=0.28. To demonstrate the flexibility of our model, we further consider texture anisotropy by taking μ2=0.1μ1\mu_{2}=0.1\mu_{1}, say, and have the texture aligned with the xx direction.

We consider that a stress σxx=90\sigma_{xx}=90 MPa is applied in the transverse direction while σzz=0\sigma_{zz}=0. We solve these equations numerically at every point to obtain λx\lambda_{x} and λz\lambda_{z}, considering that the plane strain condition λy=1\lambda_{y}=1 holds, which is reasonable as the plate is infinitely long in the yy direction. The resulting stretch components λx\lambda_{x} and λy\lambda_{y} are substituted in the current stress (23) to find

σyy=1λxλz[τyy+μ1J0β+1(11λxβ+2λzβ+2)],\sigma_{yy}=\frac{1}{\lambda_{x}\lambda_{z}}\left[\tau_{yy}+\frac{\mu_{1}}{J_{0}^{\beta+1}}\left(1-\frac{1}{\lambda_{x}^{\beta+2}\lambda_{z}^{\beta+2}}\right)\right], (39)

see the resulting the distribution of σyy\sigma_{yy} in Figure 5.

Refer to caption
Figure 5: Bottom curve: distribution of the residual stress τyy\tau_{yy} across the width of a welded plate. Top curve: distribution of the Cauchy stress σyy\sigma_{yy} when a stress σxx=90\sigma_{xx}=90 MPa is applied in the transverse direction.

These results highlight the influence of residual stress on the stress distribution in a welded structure under tension. They show how the high stress intensity in the weld-zone is due to the residual stress, and that the welded structures are expected to fail in the weld zone when stretched from the two sides. Hence, the models and framework developed in this paper can be used to solve complex engineering problems by providing benchmark solutions.

4 Linearised constitutive relations

Many residually stressed solids with texture anisotropy, such as the typical metals used in mechanical and civil engineering, can only sustain small elastic deformations. A linearised model of initial stress is then often required in their modelling. Here we turn our attention to linearised theories for small strain and small rotation (Section 4.1), and then for small initial stress (Section 4.2). The resulting equations allow us to study the propagation of small-amplitude elastic shear waves, with a view to perform the non-destructive evaluation of the level of initial stress (Section 4.3). In Section 4.4, we develop a linearised set of equations for ISRI, and further find restrictions that should apply to the material parameters for small initial stress in Section 4.5. For the calculations, we rely on and make use of results on linearisation from References [23, 15, 7, 8].

4.1 Linearisation for small strain and small rotation

For small deforations, we write the deformation gradient in the form 𝑭=𝑰+𝒖{\boldsymbol{F}}={\boldsymbol{I}}+\nabla{\boldsymbol{u}}, where 𝒖{\boldsymbol{u}} is the infinitesimal displacement vector. For small-amplitude motions, the equation of motion is [9]:

ρu¨k=𝒜klmnum,nl,\rho\ddot{u}_{k}=\mathcal{A}_{klmn}u_{m,nl}, (40)

where ρ\rho is the mass density and the elastic moduli 𝒜klmn\mathcal{A}_{klmn} can be calculated from the equation

𝓐:𝒖=𝝈𝑭|𝑭=𝑰:𝒖𝝉𝒖T+𝝉tr𝒖,\boldsymbol{\mathcal{A}}:\nabla{\boldsymbol{u}}=\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\nabla{\boldsymbol{u}}-\boldsymbol{\tau}\nabla{\boldsymbol{u}}^{T}+\boldsymbol{\tau}\mathop{\rm tr}\nolimits\nabla{\boldsymbol{u}}, (41)

where we defined the notations

(𝑨𝑫)ijkl=AijDkl, and (𝓒:𝑨)ij=𝒞ijklAlk,\left(\frac{\partial{\boldsymbol{A}}}{\partial{\boldsymbol{D}}}\right)_{ijkl}=\frac{\partial A_{ij}}{\partial D_{kl}},\qquad\text{ and }\qquad\left(\boldsymbol{\mathcal{C}}:{\boldsymbol{A}}\right)_{ij}={\mathcal{C}}_{ijkl}A_{lk}, (42)

for any second-order tensors 𝑨{\boldsymbol{A}}, 𝑫{\boldsymbol{D}} and fourth-order tensor 𝓒\boldsymbol{\mathcal{C}}.

Note that simply calculating the divergence div(𝓐:𝒖)\mathrm{div}\,(\boldsymbol{\mathcal{A}}:\nabla{\boldsymbol{u}}), when 𝓐\boldsymbol{\mathcal{A}} is constant in the positions x1x_{1}, x2x_{2}, and x3x_{3}, leads to the right-hand side of (40).

As the term 𝝈𝑭:𝒖\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}:\nabla{\boldsymbol{u}} is essential to solve the equation of motion (40), it is helpful to have simple representations for it. First we split the displacement gradient into

𝒖=𝝎+ϵ,\nabla{\boldsymbol{u}}=\boldsymbol{\omega}+\boldsymbol{\epsilon}, (43)

where 𝝎=(𝒖/𝒖T)/2\boldsymbol{\omega}=(\nabla{\boldsymbol{u}}/-\nabla{\boldsymbol{u}}^{T})/2 (antisymmetric) and ϵ=(𝒖+𝒖T)/2\boldsymbol{\epsilon}=(\nabla{\boldsymbol{u}}+\nabla{\boldsymbol{u}}^{T})/2 (symmetric) are the infinitesimal rotation and strain, respectively.

From [15, Equation (4.5)] we have

𝝈𝑭|𝑭=𝑰:𝝎=𝝎𝝉𝝉𝝎.\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\omega}=\boldsymbol{\omega}\boldsymbol{\tau}-\boldsymbol{\tau}\boldsymbol{\omega}. (44)

The difficult part is to determine 𝝈𝑭|𝑭=𝑰:ϵ\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}|_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}, which we do below. Once this is known we calculate the moduli 𝓐:𝒖\boldsymbol{\mathcal{A}}:\nabla{\boldsymbol{u}} using the above to get

𝓐:𝒖=𝝈𝑭|𝑭=𝑰:ϵ+𝒖𝝉+𝝉trϵϵ𝝉𝝉ϵ.\boldsymbol{\mathcal{A}}:\nabla{\boldsymbol{u}}=\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}+\nabla{\boldsymbol{u}}\boldsymbol{\tau}+\boldsymbol{\tau}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}-\boldsymbol{\epsilon}\boldsymbol{\tau}-\boldsymbol{\tau}\boldsymbol{\epsilon}. (45)

To determine 𝝈𝑭|𝑭=𝑰:ϵ\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}|_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon} we could simply differentiate (13) with respect to 𝑭{\boldsymbol{F}} (with the help of Mathematica [25] or another Computer Algebra Package). Instead we use a representation theorem for second-order tensors [44, 54] for each of the coefficients of the invariants trϵ\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}, trϵ𝝉\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\boldsymbol{\tau}, etc., to write 𝝈𝑭|𝑭=𝑰:ϵ\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}|_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon} in the form:

𝝈𝑭|𝑭=𝑰:ϵ\displaystyle\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon} =α1ϵ+α2𝑮ϵs+α3𝝉ϵs+α4𝝉𝑮ϵs+α5𝑮𝝉ϵs\displaystyle=\alpha_{1}\boldsymbol{\epsilon}+\alpha_{2}\left<{\boldsymbol{G}}\boldsymbol{\epsilon}\right>_{s}+\alpha_{3}\left<\boldsymbol{\tau}\boldsymbol{\epsilon}\right>_{s}+\alpha_{4}\left<\boldsymbol{\tau}{\boldsymbol{G}}\boldsymbol{\epsilon}\right>_{s}+\alpha_{5}\left<{\boldsymbol{G}}\boldsymbol{\tau}\boldsymbol{\epsilon}\right>_{s}
+α6𝝉2ϵs+α7𝝉2𝑮ϵs+α8𝑮𝝉2ϵs\displaystyle+\alpha_{6}\left<\boldsymbol{\tau}^{2}\boldsymbol{\epsilon}\right>_{s}+\alpha_{7}\left<\boldsymbol{\tau}^{2}{\boldsymbol{G}}\boldsymbol{\epsilon}\right>_{s}+\alpha_{8}\left<{\boldsymbol{G}}\boldsymbol{\tau}^{2}\boldsymbol{\epsilon}\right>_{s}
+(α9𝑰+α10𝝉+α11𝝉2+α12𝑮+α13𝝉𝑮s+α14𝝉2𝑮s)trϵ\displaystyle+\left(\alpha_{9}{\boldsymbol{I}}+\alpha_{10}\boldsymbol{\tau}+\alpha_{11}\boldsymbol{\tau}^{2}+\alpha_{12}{\boldsymbol{G}}+\alpha_{13}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>_{s}+\alpha_{14}\left<\boldsymbol{\tau}^{2}{\boldsymbol{G}}\right>_{s}\right)\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}
+(α15𝑰+α16𝝉+α17𝝉2+α18𝑮+α19𝝉𝑮s+α20𝝉2𝑮s)tr(ϵ𝝉)\displaystyle+\left(\alpha_{15}{\boldsymbol{I}}+\alpha_{16}\boldsymbol{\tau}+\alpha_{17}\boldsymbol{\tau}^{2}+\alpha_{18}{\boldsymbol{G}}+\alpha_{19}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>_{s}+\alpha_{20}\left<\boldsymbol{\tau}^{2}{\boldsymbol{G}}\right>_{s}\right)\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}\boldsymbol{\tau})
+(α21𝑰+α22𝝉+α23𝝉2+α24𝑮+α25𝝉𝑮s+α26𝝉2𝑮s)tr(𝑮ϵ)\displaystyle+\left(\alpha_{21}{\boldsymbol{I}}+\alpha_{22}\boldsymbol{\tau}+\alpha_{23}\boldsymbol{\tau}^{2}+\alpha_{24}{\boldsymbol{G}}+\alpha_{25}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>_{s}+\alpha_{26}\left<\boldsymbol{\tau}^{2}{\boldsymbol{G}}\right>_{s}\right)\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\epsilon})
+(α27𝑰+α28𝝉+α29𝝉2+α30𝑮+α31𝝉𝑮s+α32𝝉2𝑮s)tr(𝑮ϵ𝝉)\displaystyle+\left(\alpha_{27}{\boldsymbol{I}}+\alpha_{28}\boldsymbol{\tau}+\alpha_{29}\boldsymbol{\tau}^{2}+\alpha_{30}{\boldsymbol{G}}+\alpha_{31}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>_{s}+\alpha_{32}\left<\boldsymbol{\tau}^{2}{\boldsymbol{G}}\right>_{s}\right)\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\epsilon}\boldsymbol{\tau})
+(α33𝑰+α34𝝉+α35𝝉2+α36𝑮+α37𝝉𝑮s+α38𝝉2𝑮s)tr(ϵ𝝉2)\displaystyle+\left(\alpha_{33}{\boldsymbol{I}}+\alpha_{34}\boldsymbol{\tau}+\alpha_{35}\boldsymbol{\tau}^{2}+\alpha_{36}{\boldsymbol{G}}+\alpha_{37}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>_{s}+\alpha_{38}\left<\boldsymbol{\tau}^{2}{\boldsymbol{G}}\right>_{s}\right)\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}\boldsymbol{\tau}^{2})
+(α39𝑰+α40𝝉+α41𝝉2+α42𝑮+α43𝝉𝑮s+α44𝝉2𝑮s)tr(𝑮ϵ𝝉2),\displaystyle+\left(\alpha_{39}{\boldsymbol{I}}+\alpha_{40}\boldsymbol{\tau}+\alpha_{41}\boldsymbol{\tau}^{2}+\alpha_{42}{\boldsymbol{G}}+\alpha_{43}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>_{s}+\alpha_{44}\left<\boldsymbol{\tau}^{2}{\boldsymbol{G}}\right>_{s}\right)\mathop{\rm tr}\nolimits({{\boldsymbol{G}}\boldsymbol{\epsilon}\boldsymbol{\tau}^{2}}), (46)

where the αi\alpha_{i} are scalar functions of the invariants of 𝝉\boldsymbol{\tau} and 𝑮=𝑴𝑴{\boldsymbol{G}}={\boldsymbol{M}}\otimes{\boldsymbol{M}}, and the brackets notation denotes the symmetric part of a tensor: 𝑫s=(𝑫+𝑫T)/2\langle{\boldsymbol{D}}\rangle_{s}=({\boldsymbol{D}}+{\boldsymbol{D}}^{T})/2 for any tensor 𝑫{\boldsymbol{D}}. Note that terms such as 𝑮ϵ𝝉s\left<{\boldsymbol{G}}\boldsymbol{\epsilon}\boldsymbol{\tau}\right>_{s}, and other higher-order terms in 𝝉\boldsymbol{\tau}, do not appear as they can be expressed using the terms already present in (46).

Some of the coefficients αi\alpha_{i} depend on each other due to the symmetry of the elasticity moduli. Using equations (4.9 – 4.12) from [15], we obtain

𝑨:𝝈𝑭|𝑭=𝑰:𝑫+(𝑨:𝝉)tr𝑫=𝑫:𝝈𝑭|𝑭=𝑰:𝑨+(𝑫:𝝉)tr𝑨,{\boldsymbol{A}}:\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:{\boldsymbol{D}}+\left({\boldsymbol{A}}:\boldsymbol{\tau}\right)\mathop{\rm tr}\nolimits{\boldsymbol{D}}={\boldsymbol{D}}:\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:{\boldsymbol{A}}+\left({\boldsymbol{D}}:\boldsymbol{\tau}\right)\mathop{\rm tr}\nolimits{\boldsymbol{A}}, (47)

for any symmetric 𝑨{\boldsymbol{A}} and 𝑫{\boldsymbol{D}}. By separately substituting 𝑨{\boldsymbol{A}} and 𝑫{\boldsymbol{D}} for ϵ\boldsymbol{\epsilon} we find that

α4=α5,α7=α8\displaystyle\alpha_{4}=\alpha_{5},\quad\alpha_{7}=\alpha_{8}
α10=α151,α11=α33,α12=α21,α13=α27,α14=α39α17=α34\displaystyle\alpha_{10}=\alpha_{15}-1,\quad\alpha_{11}=\alpha_{33},\quad\alpha_{12}=\alpha_{21},\quad\alpha_{13}=\alpha_{27},\quad\alpha_{14}=\alpha_{39}\quad\alpha_{17}=\alpha_{34}
α18=α22,α19=α28,α20=α40,α36=α23,α37=α29,α38=α41\displaystyle\alpha_{18}=\alpha_{22},\quad\alpha_{19}=\alpha_{28},\quad\alpha_{20}=\alpha_{40},\quad\alpha_{36}=\alpha_{23},\quad\alpha_{37}=\alpha_{29},\quad\alpha_{38}=\alpha_{41}
α25=α30,α26=α42α32=α43.\displaystyle\alpha_{25}=\alpha_{30},\quad\alpha_{26}=\alpha_{42}\quad\alpha_{32}=\alpha_{43}.\ (48)

Using the above, we can determine the total number of material constants needed to describe several special cases.

The simplest possible case is that of a uniaxial initial stress aligned with the preferred direction of transverse texture anisotropy. Then, 𝝉=τ𝑮\boldsymbol{\tau}=\tau{\boldsymbol{G}}, which substituted in (46), together with (48), leads to

𝝈𝑭(𝑰,𝑮,𝝉):ϵ=b1ϵ+b2ϵ𝑮s+b3𝑰trϵ+b4(𝑮trϵ+𝑰tr(𝑮ϵ))+b5𝑮tr(𝑮ϵ),\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}({\boldsymbol{I}},{\boldsymbol{G}},\boldsymbol{\tau}):\boldsymbol{\epsilon}=b_{1}\boldsymbol{\epsilon}+b_{2}\left<\boldsymbol{\epsilon}{\boldsymbol{G}}\right>_{s}+b_{3}{\boldsymbol{I}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}+b_{4}\left({\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}+{\boldsymbol{I}}\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\epsilon})\right)+b_{5}{\boldsymbol{G}}\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\epsilon}), (49)

where the bkb_{k} are a combination of the αj\alpha_{j} and τ\tau, with all the bkb_{k} being independent when we assume that the αij\alpha_{ij} and τ\tau can be chosen independently. Hence this case requires five different elastic constants to describe the response for any ϵ\boldsymbol{\epsilon}, which is the same number of elastic constants required for the description of transversely isotropic solids in linear elasticity.

Often in both natural and man-made materials the principal directions of initial stress are co-axial with the direction of texture anisotropy. For this case, we have 𝝉=Diag(τ1,τ2,τ3)\boldsymbol{\tau}=\text{Diag}(\tau_{1},\tau_{2},\tau_{3}), 𝑮=Diag(M12,M22,0){\boldsymbol{G}}=\text{Diag}(M_{1}^{2},M_{2}^{2},0). We may then write 𝝉\boldsymbol{\tau} as 𝝉=a𝑰2×2+b𝑮+τ3𝒆3𝒆3\boldsymbol{\tau}=a{\boldsymbol{I}}_{2\times 2}+b{\boldsymbol{G}}+\tau_{3}{\boldsymbol{e}}_{3}\otimes{\boldsymbol{e}}_{3} where a=(M12τ2M12τ1)/(M12M22)a=(M_{1}^{2}\tau_{2}-M_{1}^{2}\tau_{1})/(M_{1}^{2}-M_{2}^{2}), b=(τ1τ2)/(M12M22)b=\ (\tau_{1}-\tau_{2})/(M_{1}^{2}-M_{2}^{2}) and substitute that decomposition in (46), together with (48), to obtain

𝝈𝑭(𝑰,𝑮,𝝉):ϵ=b1ϵ+b3ϵ𝑮s+b4𝒆2(𝒆3ϵ)s+b5𝑰trϵ+b6[𝒆3𝒆3trϵ+𝑰(𝒆3.ϵ𝒆3)]+b7[𝑮trϵ+𝑰tr(𝑮ϵ)]+b8[𝑮(𝒆3.ϵ𝒆3)+𝒆3𝒆3tr(𝑮ϵ)]+b9𝑮tr(𝑮ϵ),\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}({\boldsymbol{I}},{\boldsymbol{G}},\boldsymbol{\tau}):\boldsymbol{\epsilon}=b_{1}\boldsymbol{\epsilon}+b_{3}\left<\boldsymbol{\epsilon}{\boldsymbol{G}}\right>_{s}+b_{4}\left<{\boldsymbol{e}}_{2}\otimes({\boldsymbol{e}}_{3}\cdot\boldsymbol{\epsilon})\right>_{s}\\ +b_{5}{\boldsymbol{I}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}+b_{6}\left[{\boldsymbol{e}}_{3}\otimes{\boldsymbol{e}}_{3}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}+{\boldsymbol{I}}\left({\boldsymbol{e}}_{3}.\boldsymbol{\epsilon}{\boldsymbol{e}}_{3}\right)\right]+b_{7}\left[{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}+{\boldsymbol{I}}\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\epsilon})\right]\\ +b_{8}\left[{\boldsymbol{G}}\left({\boldsymbol{e}}_{3}.\boldsymbol{\epsilon}{\boldsymbol{e}}_{3}\right)+{\boldsymbol{e}}_{3}\otimes{\boldsymbol{e}}_{3}\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\epsilon})\right]+b_{9}{\boldsymbol{G}}\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\epsilon}), (50)

which requires nine elastic constants (same as for orthotropic materials in linear elasticity, often described in terms of three Young’s moduli, three Poisson’s ratios, and three shear moduli [2]).

When 𝝉\boldsymbol{\tau} is a general triaxial stress field and 𝑴{\boldsymbol{M}} lies on the plane containing two principal directions but does not align with any of them, we find 13 linear elastic constants. By substituting the diagonalised form of initial stress 𝝉=i=13τi𝒆i𝒆i\boldsymbol{\tau}=\sum_{i=1}^{3}{\tau_{i}{\boldsymbol{e}}_{i}\otimes{\boldsymbol{e}}_{i}} and 𝑴=M1𝒆1+M2𝒆2{\boldsymbol{M}}=M_{1}{\boldsymbol{e}}_{1}+M_{2}{\boldsymbol{e}}_{2} into (46) and using (48), the components of the Cauchy stress 𝝈=𝝉+𝝈𝑭|𝑭=𝑰:ϵ\boldsymbol{\sigma}=\boldsymbol{\tau}+\tfrac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\big{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}, without rotation, in the set of coordinates {𝒆1,𝒆2,𝒆3}\left\{{\boldsymbol{e}}_{1},{\boldsymbol{e}}_{2},{\boldsymbol{e}}_{3}\right\}, are given by

{σ11σ22σ33σ23σ31σ12}={τ1τ2τ3000}+[b11b12b1300b16b12b22b2300b26b13b23b3300b36000b44b450000b54b550b16b26b3600b66]{ϵ11ϵ22ϵ332ϵ232ϵ312ϵ12}.\begin{Bmatrix}\sigma_{11}\\ \sigma_{22}\\ \sigma_{33}\\ \sigma_{23}\\ \sigma_{31}\\ \sigma_{12}\end{Bmatrix}=\begin{Bmatrix}\tau_{1}\\ \tau_{2}\\ \tau_{3}\\ 0\\ 0\\ 0\end{Bmatrix}+\begin{bmatrix}b_{11}&b_{12}&b_{13}&0&0&b_{16}\\ b_{12}&b_{22}&b_{23}&0&0&b_{26}\\ b_{13}&b_{23}&b_{33}&0&0&b_{36}\\ 0&0&0&b_{44}&b_{45}&0\\ 0&0&0&b_{54}&b_{55}&0\\ b_{16}&b_{26}&b_{36}&0&0&b_{66}\end{bmatrix}\begin{Bmatrix}\epsilon_{11}\\ \epsilon_{22}\\ \epsilon_{33}\\ 2\epsilon_{23}\\ 2\epsilon_{31}\\ 2\epsilon_{12}\end{Bmatrix}. (51)

Note that linear elastic materials with monoclinic symmetry also require 13 elastic constants and that they have a constitutive relation [41, 6] similar to (51). Hence, we conclude that when the two principal directions of initial stress and the direction of texture remain in the same plane but do not align with each other, the initially stressed material behaves like a monoclinic material.

When the texture direction does not lie in the plane of any two principal stress directions, we find triclinic symmetry with 2121 material constants which fully populates the 6×66\times 6 stiffness matrix in the constitutive relation.

Refer to caption
Figure 6: A visualisation of the symmetries present when combining both residual stress and texture. (a) For hydrostatic initial stress (τ1=τ2=τ3)\left(\tau_{1}=\tau_{2}=\tau_{3}\right) without texture, any arbitrary rotation leads to a material with the same properties. We then say that the symmetry group is composed of all rotations, and therefore the symmetry is isotropy. (b) For three distinct principal stresses (τ1τ2τ3τ1)\left(\tau_{1}\neq\tau_{2}\neq\tau_{3}\neq\tau_{1}\right) without texture, the symmetry group consists of three 180180^{\circ} rotations about the principal directions 𝒆1{\boldsymbol{e}}_{1}, 𝒆2{\boldsymbol{e}}_{2}, and 𝒆3{\boldsymbol{e}}_{3} respectively, which is the case of orthotropy. (c) When the texture direction is not aligned with any principal direction 𝒆1{\boldsymbol{e}}_{1}, 𝒆2{\boldsymbol{e}}_{2}, or e3e_{3}, but lies on the 𝒆1𝒆2{\boldsymbol{e}}_{1}-{\boldsymbol{e}}_{2} plane, only a 180180^{\circ} rotation about 𝒆3{\boldsymbol{e}}_{3} axis leaves the material unchanged. This is the symmetry group of monoclinicity about the 𝒆1𝒆2{\boldsymbol{e}}_{1}-{\boldsymbol{e}}_{2} plane. We obtain 13 linear elastic constants for small deformation theory in this case. (d) Finally, when 𝑴{\boldsymbol{M}} is neither aligned with any principal direction, nor lying on any plane passing through any two principal directions, there is no rotation that preserves the structure. This is the case of triclinicity, which has 21 linear elastic constants.

The above conclusions on material symmetry are in agreement with our investigation of symmetry through physical visualisation in Figure 6. Finally, we note that the αj\alpha_{j}, and therefore bjb_{j}, may not be independent due to the ISRI restriction (8). We explain this in more detail in Section 4.4.

4.2 Third-order elasticity and small initial stress

In the previous section, coefficients such as αj\alpha_{j} and bjb_{j} depend on the combined invariants of 𝝉\boldsymbol{\tau} and 𝑮{\boldsymbol{G}}. In contrast, here we reduce these scalars to material constants which do not depend on the invariants of 𝝉\boldsymbol{\tau} and 𝑮{\boldsymbol{G}}. We achieve this reduction by considering that the elastic moduli (46) vary linearly in 𝝉\boldsymbol{\tau}. This is an important case, as it includes the case of third-order weakly nonlinear materials with transverse texture anisotropy and without initial stresss [7].

The elastic modulus tensor of hyperelastic third-order elastic materials 𝓐\boldsymbol{\mathcal{A}} is correct up to first order in 𝑬{\boldsymbol{E}}, which is asymptotically equivalent to writing 𝓐\boldsymbol{\mathcal{A}} as a linear function of 𝝉\boldsymbol{\tau}. The papers [33, 30] show moduli written in terms of the initial stress which are equivalent to the moduli of classical third-order elastic materials.

By dropping all terms which are explicitly of order 𝒪(𝝉2)\mathcal{O}(\boldsymbol{\tau}^{2}) in (46), and using (48), we obtain

𝝈𝑭|𝑭=𝑰:ϵ=\displaystyle\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}= ϵ[a3(tr𝝉tr(𝑮𝝉))+a1]+ϵ𝑮[a2a3tr𝝉]+a3𝝉ϵ𝑮+a4ϵ𝝉\displaystyle\boldsymbol{\epsilon}\left[a_{3}(\mathop{\rm tr}\nolimits\boldsymbol{\tau}-\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\tau}))+a_{1}\right]+\left<\boldsymbol{\epsilon}{\boldsymbol{G}}\right>\left[a_{2}-a_{3}\mathop{\rm tr}\nolimits\boldsymbol{\tau}\right]+a_{3}\left<\boldsymbol{\tau}\boldsymbol{\epsilon}{\boldsymbol{G}}\right>+a_{4}\left<\boldsymbol{\epsilon}\boldsymbol{\tau}\right>
+trϵ[𝑰(a5a3(tr𝝉tr(𝑮𝝉)))+a3𝑮tr𝝉+a7𝝉+a8𝝉𝑮+a6𝑮]\displaystyle+\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\left[{\boldsymbol{I}}\left(a_{5}-a_{3}(\mathop{\rm tr}\nolimits\boldsymbol{\tau}-\mathop{\rm tr}\nolimits({\boldsymbol{G}}\boldsymbol{\tau}))\right)+a_{3}{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\tau}+a_{7}\boldsymbol{\tau}+a_{8}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>+a_{6}{\boldsymbol{G}}\right]
+tr(ϵ𝑮)[𝑰(a3tr𝝉+a6)+a10𝝉+a11𝝉𝑮+a9𝑮]\displaystyle+\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})\left[{\boldsymbol{I}}\left(a_{3}\mathop{\rm tr}\nolimits\boldsymbol{\tau}+a_{6}\right)+a_{10}\boldsymbol{\tau}+a_{11}\left<\boldsymbol{\tau}{\boldsymbol{G}}\right>+a_{9}{\boldsymbol{G}}\right]
+tr(ϵ𝝉)[(a7+1)𝑰+a10𝑮]+2tr(ϵ𝑮𝝉)[a8𝑰+a11𝑮],\displaystyle+\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}\boldsymbol{\tau})\left[\left(a_{7}+1\right){\boldsymbol{I}}+a_{10}{\boldsymbol{G}}\right]+2\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}\boldsymbol{\tau})\left[a_{8}{\boldsymbol{I}}+a_{11}{\boldsymbol{G}}\right], (52)

where, for simplicity, we introduced a new set of coefficients aja_{j} which can be related to the αj\alpha_{j} in (46). Note that there are 11 scalars in total a1,a2,,a11a_{1},a_{2},\ldots,a_{11}. Five of these scalars a1,a2,a5,a6a_{1},a_{2},a_{5},a_{6}, and a9a_{9} depend on the invariants of 𝝉\boldsymbol{\tau} and 𝑮{\boldsymbol{G}} so they can be expanded in the form

aj=aj,0+aj,1tr𝝉+aj,2tr(𝝉𝑮),a_{j}=a_{j,0}+a_{j,1}\mathop{\rm tr}\nolimits\boldsymbol{\tau}+a_{j,2}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}}), (53)

which when substituted into 𝝈𝑭:ϵ\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}:\boldsymbol{\epsilon} above, clearly shows how many material constants (independent of 𝝉\boldsymbol{\tau}) are needed to fully characterise the material behaviour:

a1,0,a1,1,a1,2,a2,0,a2,1,a2,2,a3,a4,a5,0,a5,1,a5,2,\displaystyle a_{1,0},a_{1,1},a_{1,2},a_{2,0},a_{2,1},a_{2,2},a_{3},a_{4},a_{5,0},a_{5,1},a_{5,2},
a6,0,a6,1,a6,2,a7,a8,a9,0,a9,1,a9,2,a10,a11.\displaystyle a_{6,0},a_{6,1},a_{6,2},a_{7},a_{8},a_{9,0},a_{9,1},a_{9,2},a_{10},a_{11}. (54)

Hence, there are 21 material constants, whereas there are only 14 constants needed for the moduli of hyperelastic third-order elastic material with transverse texture anisotropy [7]. How can there be 7 more degrees of freedom between two models which describe the same type of material and to the same asymptotic order? The answer is given in Section 4.4 which shows that the ISRI condition (8) leads to exactly 7 equations which connect the constants above.

In polycrystalline materials, such as steel, there are many engineering scenarios where the direction of the texture anisotropy aligns with the direction of stress, and there is a stress-free direction. Examples include steel plates and beams. To represent this scenario we use the identities 𝑮𝝉=𝝉𝑮{\boldsymbol{G}}\boldsymbol{\tau}=\boldsymbol{\tau}{\boldsymbol{G}}, tr𝑮=1\mathop{\rm tr}\nolimits{\boldsymbol{G}}=1, and the Cayley-Hamilton theorem111Alternatively, we could choose a coordinate system that diagonalizes 𝝉\boldsymbol{\tau} and thus, diagonalises 𝑮{\boldsymbol{G}}, and then count the number of independent coefficients βj\beta_{j}. This is best done with a computer algebra system [25]to obtain

𝝈𝑭|𝑭=𝑰:ϵ=ϵ𝝉+𝝉ϵ𝝉trϵ+β1ϵ+β2ϵtr(𝝉𝑮)+2β3ϵ𝑮+β4𝑰trϵtr(𝝉𝑮)+β5𝑮tr(ϵ𝑮)+β6[𝑰tr(𝝉𝑮)tr(ϵ𝑮)+𝝉𝑮trϵ]+2β7tr(𝝉𝑮)ϵ𝑮+β8𝑰trϵ+β9[𝑰tr(ϵ𝑮)+𝑮trϵ]+β10𝝉𝑮tr(ϵ𝑮)+𝑯,\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\bigg{|}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}=\boldsymbol{\epsilon}\boldsymbol{\tau}+\boldsymbol{\tau}\boldsymbol{\epsilon}-\boldsymbol{\tau}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}+\beta_{1}\boldsymbol{\epsilon}+\beta_{2}\boldsymbol{\epsilon}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})+2\beta_{3}\left<\boldsymbol{\epsilon}{\boldsymbol{G}}\right>+\beta_{4}{\boldsymbol{I}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})+\beta_{5}{\boldsymbol{G}}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})\\ +\beta_{6}\left[{\boldsymbol{I}}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})+\boldsymbol{\tau}{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\right]+2\beta_{7}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\left<\boldsymbol{\epsilon}{\boldsymbol{G}}\right>+\beta_{8}{\boldsymbol{I}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\\ +\beta_{9}\left[{\boldsymbol{I}}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})+{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\right]+\beta_{10}\boldsymbol{\tau}{\boldsymbol{G}}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})+{\boldsymbol{H}}, (55)

where

𝑯=β11𝑰trϵ[tr𝝉tr(𝝉𝑮)]+β12tr(ϵ𝑮)𝑰[tr𝝉tr(𝝉𝑮)]+β12[𝑮tr𝝉trϵ𝝉𝑮trϵ]+β13𝑰[tr(ϵ𝝉)tr(𝝉𝑮)tr(ϵ𝑮)]+β13trϵ[𝝉𝝉𝑮]+2β14[ϵ𝝉ϵ𝑮tr(𝝉𝑮)]+β15ϵ[tr𝝉tr(𝝉𝑮)]+β16tr(ϵ𝑮)[𝑮tr𝝉𝝉𝑮]+β17[(𝝉2𝝉𝑮)tr(ϵ𝑮)+𝑮tr(ϵ𝝉)]+2β18ϵ𝑮[tr𝝉tr(𝝉𝑮)].{\boldsymbol{H}}=\beta_{11}{\boldsymbol{I}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\left[\mathop{\rm tr}\nolimits\boldsymbol{\tau}-\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\right]+\beta_{12}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}){\boldsymbol{I}}\left[\mathop{\rm tr}\nolimits\boldsymbol{\tau}-\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\right]+\\ \beta_{12}\left[{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\tau}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}-\boldsymbol{\tau}{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\right]+\beta_{13}{\boldsymbol{I}}\left[\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}\boldsymbol{\tau})-\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})\right]+\beta_{13}\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\left[\boldsymbol{\tau}-\boldsymbol{\tau}{\boldsymbol{G}}\right]+\\ 2\beta_{14}\left[\left<\boldsymbol{\epsilon}\boldsymbol{\tau}\right>-\left<\boldsymbol{\epsilon}{\boldsymbol{G}}\right>\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\right]+\beta_{15}\boldsymbol{\epsilon}\left[\mathop{\rm tr}\nolimits\boldsymbol{\tau}-\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\right]+\beta_{16}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})\left[{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\tau}-\boldsymbol{\tau}{\boldsymbol{G}}\right]+\\ \beta_{17}\left[(\boldsymbol{\tau}-2\boldsymbol{\tau}{\boldsymbol{G}})\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}})+{\boldsymbol{G}}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}\boldsymbol{\tau})\right]+2\beta_{18}\left<\boldsymbol{\epsilon}{\boldsymbol{G}}\right>\left[\mathop{\rm tr}\nolimits\boldsymbol{\tau}-\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\right]. (56)

For a uniaxial stress aligned with the texture we would have 𝝉𝑮=𝝉\boldsymbol{\tau}{\boldsymbol{G}}=\boldsymbol{\tau}, 𝑮tr𝝉=𝝉{\boldsymbol{G}}\mathop{\rm tr}\nolimits\boldsymbol{\tau}=\boldsymbol{\tau}, which substituted above leads to 𝑯=𝟎{\boldsymbol{H}}=\boldsymbol{0}. Also, similar to the ai,ja_{i,j} coefficients, the coefficients βj\beta_{j} are not all independent, as we demonstrate in Section 4.6 below.

Finally, another common simplification is to assume that the coupling between 𝑮{\boldsymbol{G}} and 𝝉\boldsymbol{\tau} is weak, which is a typical assumption for steel and hard solids [33]. To achieve this, we can choose different values for the βj\beta_{j}. For example, we can choose the βj\beta_{j} such that no explicit coupling of the form 𝝉𝑮\boldsymbol{\tau}{\boldsymbol{G}} and tr(𝝉𝑮)\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}}) appears in (55). The minimal set of equations needed to achieve this are

β15=β2,β11=β4,β12=β6β13,β18=β7β14,β10=β16+2β17.\beta_{15}=\beta_{2},\quad\beta_{11}=\beta_{4},\quad\beta_{12}=\beta_{6}-\beta_{13},\quad\beta_{18}=\beta_{7}-\beta_{14},\quad\beta_{10}=\beta_{16}+2\beta_{17}.

4.3 Application: measuring initial stress with shear waves

For hard solids, like metals, ceramics, composites and concrete, third-order elasticity is sufficient to describe the elastic response for most scenarios encountered in industry [32, 30]. The topic has also long interested the geophysics community [52] as stress in the Earth alters the propagation of seismic waves.

Among the applications of ultrasonic waves in industry, many have tried to use ultrasonic waves to assess the initial stress within a solid [19]. In principle, ultrasonic waves could give a quick and non-invasive way to measure the stress, as wave speeds are easily related to the stress. One significant hurdle is to separate the influence of the stress-induced anisotropy from the texture-induced anisotropy [33, 19]. This challenge motivates us to develop the framework shown in this section, as it is simpler to find an answer when the elastic moduli 𝓐\boldsymbol{\mathcal{A}} are written explicitly in terms of the initial stress and texture.

We study bulk shear waves of the form

𝒖=𝑼eik(n1x1+n2x2vt),\boldsymbol{u}=\boldsymbol{U}e^{ik(n_{1}x_{1}+n_{2}x_{2}-vt)}, (57)

where 𝑼=(U1,U2,U3)\boldsymbol{U}=(U_{1},U_{2},U_{3}) is the constant amplitude vector, 𝒏=(n1,n2,0)\boldsymbol{n}=(n_{1},n_{2},0) is the unit vector in the direction of propagation, kk is the wavenumber and vv is the speed. The most common scenario found in hard solids is to have the texture aligned with the initial stress and so, we choose a coordinate system (x1,x2,x3)(x_{1},x_{2},x_{3}) aligned with the principal directions of the initial stress 𝝉=diag(τ1,τ2,τ3)\boldsymbol{\tau}=\mathrm{diag}(\tau_{1},\tau_{2},\tau_{3}) and the direction of anisotropy 𝑴=(1,0,0){\boldsymbol{M}}=(1,0,0). We then find from (45) and (55) that

𝒜ipjq0=0unless{p=i&q=j,orp=q&i=j,orp=j&q=i.\mathcal{A}^{0}_{ipjq}=0\quad\text{unless}\quad\begin{cases}p=i\;\&\;q=j,\;\;\;\text{or}\\ p=q\;\&\;i=j,\;\;\;\text{or}\\ p=j\;\&\;q=i.\end{cases} (58)

See Figure 6 for an illustration, noting that the texture vector 𝑴{\boldsymbol{M}} is also aligned with the principal stress direction τ1\tau_{1}. Note that due to the symmetry of the Cauchy stress, we have the following connections [45],

𝒜1212=τ2+𝒜1221,𝒜1212=τ2+𝒜1221,\displaystyle\mathcal{A}_{1212}=\tau_{2}+\mathcal{A}_{1221},\quad\mathcal{A}_{1212}=\tau_{2}+\mathcal{A}_{1221}, (59)
𝒜3131=τ1+𝒜1331,𝒜3232=τ2+𝒜2332.\displaystyle\mathcal{A}_{3131}=\tau_{1}+\mathcal{A}_{1331},\quad\mathcal{A}_{3232}=\tau_{2}+\mathcal{A}_{2332}. (60)

Substituting (57) and (58) into the equation of motion (40) leads to the following eigenvalue problem [30]:

[𝐐(𝒏)ρv2𝐈]𝑼=𝟎,where𝐐(𝒏)=[𝒜1111n12+𝒜1212n22(𝒜1122+𝒜1221)n1n20(𝒜1122+𝒜1221)n1n2𝒜2121n12+𝒜2222n22000𝒜3131n12+𝒜3232n22][\mathbf{Q}(\boldsymbol{n})-\rho v^{2}\mathbf{I}]\boldsymbol{U}=\boldsymbol{0},\quad\text{where}\quad\\ \mathbf{Q}(\boldsymbol{n})=\begin{bmatrix}\mathcal{A}_{1111}n_{1}^{2}+\mathcal{A}_{1212}n_{2}^{2}&(\mathcal{A}_{1122}+\mathcal{A}_{1221})n_{1}n_{2}&0\\ (\mathcal{A}_{1122}+\mathcal{A}_{1221})n_{1}n_{2}&\mathcal{A}_{2121}n_{1}^{2}+\mathcal{A}_{2222}n_{2}^{2}&0\\ 0&0&\mathcal{A}_{3131}n_{1}^{2}+\mathcal{A}_{3232}n_{2}^{2}\end{bmatrix} (61)

is the acoustic tensor. Substituting the moduli given by combining (55) and (45), we then find

𝒜1111=β1+2β3+β5+β8+2β9+τ1[1+β2+β4+2(β6+β7)+β10]\displaystyle\mathcal{A}_{1111}=\beta_{1}+2\beta_{3}+\beta_{5}+\beta_{8}+2\beta_{9}+\tau_{1}[1+\beta_{2}+\beta_{4}+2(\beta_{6}+\beta_{7})+\beta_{10}]
+(τ2+τ3)(β11+2β12+β15+β16+2β18),\displaystyle\qquad\qquad+(\tau_{2}+\tau_{3})(\beta_{11}+2\beta_{12}+\beta_{15}+\beta_{16}+2\beta_{18}),
𝒜1221=[β1+β3+τ1(β2+β7)+τ2(β14+β15+β18)+τ3(β15+β18)]/2,\displaystyle\mathcal{A}_{1221}=[\beta_{1}+\beta_{3}+\tau_{1}(\beta_{2}+\beta_{7})+\tau_{2}(\beta_{14}+\beta_{15}+\beta_{18})+\tau_{3}(\beta_{15}+\beta_{18})]/2,
𝒜1122=β8+β9+τ1(β4+β6)+τ2(β11+β12+β13+β17)+τ3(β11+β12),\displaystyle\mathcal{A}_{1122}=\beta_{8}+\beta_{9}+\tau_{1}(\beta_{4}+\beta_{6})+\tau_{2}(\beta_{11}+\beta_{12}+\beta_{13}+\beta_{17})+\tau_{3}(\beta_{11}+\beta_{12}),
𝒜2222=β1+β8+τ1(β2+β4)+τ2(1+β11+2β13+2β14+β15)+τ3(β11+β15),\displaystyle\mathcal{A}_{2222}=\beta_{1}+\beta_{8}+\tau_{1}(\beta_{2}+\beta_{4})+\tau_{2}(1+\beta_{11}+2\beta_{13}+2\beta_{14}+\beta_{15})+\tau_{3}(\beta_{11}+\beta_{15}),
𝒜1331=[β1+β3+τ1(β2+β7)+τ2(β15+β18)+τ3(β14+β15+β18)]/2,\displaystyle\mathcal{A}_{1331}=[\beta_{1}+\beta_{3}+\tau_{1}(\beta_{2}+\beta_{7})+\tau_{2}(\beta_{15}+\beta_{18})+\tau_{3}(\beta_{14}+\beta_{15}+\beta_{18})]/2,
𝒜2332=[β1+τ1β2+(τ2+τ3)(β14+β15)]/2.\displaystyle\mathcal{A}_{2332}=[\beta_{1}+\tau_{1}\beta_{2}+(\tau_{2}+\tau_{3})(\beta_{14}+\beta_{15})]/2. (62)

With Equations (4.3) and (61) it is now straightforward to calculate shear waves speeds and to design methods to measure the stress.

Refer to caption
Figure 7: Two different methods to measure the stress with shear waves. The Elastic Birefringence method uses waves sent directly across the sample under stress (left). The Angled Shear Wave method uses waves sent at different angles with respect to the principal directions of stress (right).

The most popular technique for non-destructive evaluation of stress is the Elastic Birefringence method [50]. There, two shear waves are sent directly across the stress (n1=0n_{1}=0, n2=1n_{2}=1), as shown in Figure 7. The first wave, with speed v21v_{21}, is polarised along the first principal direction of stress (𝑼=(U1,0,0)\boldsymbol{U}=(U_{1},0,0)), and the second, with speed v23v_{23}, is polarised along the third principal direction of stress (𝑼=(0,0,U3)\boldsymbol{U}=(0,0,U_{3})). It is then a simple exercise to show that

ρ(v212v232)=[β3+τ1β7+τ2β18+τ3(β18β14)]/2.\rho(v_{21}^{2}-v_{23}^{2})=[\beta_{3}+\tau_{1}\beta_{7}+\tau_{2}\beta_{18}+\tau_{3}(\beta_{18}-\beta_{14})]/2. (63)

Often, one or two directions are stress-free in many practical scenarios as, for example, is the case for railways [20]. Taking τ2=τ3=0\tau_{2}=\tau_{3}=0, and assuming we know the values of β3\beta_{3} and β7\beta_{7}, then the above formula would give us access to the stress. However, the constant β3\beta_{3} is due to texture anisotropy, as can be seen from (55). As noted in the literature [20], texture anisotropy can vary greatly from one sample to another, and the term β3\beta_{3} is often of a comparable magnitude to, say, τ1β7\tau_{1}\beta_{7}. This uncertainty is one of the shortcomings of the birefringence method.

Almost all existing techniques to measure stress with ultrasonic waves suffer from the same problem as the Elastic Birefringence method: an a priori knowledge of the constants is required, but their value can vary greatly from one sample to another, making them difficult to measure reliably [30]. A recently proposed method does away with this problem as it is parameter-free: the Angled Shear Wave method [30], see Figure 7 for an illustration of its working principle. Below we show that this method can be extended to include texture anisotropy, provided the effect of the texture is of the same order as the effect of the stress on the wave speed.

To calculate the speed of a shear wave travelling at an angle with respect to the principal directions of initial stress, we take U3=0U_{3}=0 in (61) and solve for ρv2\rho v^{2}, which leads to two solutions. We identify which one corresponds to a shear wave by using (4.3) and taking the limit of no stress anisotropy (τ1=τ2=τ3=0\tau_{1}=\tau_{2}=\tau_{3}=0) and no texture anisotropy (β3=β5=β9=0\beta_{3}=\beta_{5}=\beta_{9}=0). The shear wave speed in this limit is equal to μ/ρ\sqrt{\mu/\rho}, noting that β1=2μ\beta_{1}=2\mu and β8=λ\beta_{8}=\lambda, where μ\mu and λ\lambda are the Lamé parameters.

Let vθv_{\theta} denote the speed of the identified shear wave. As explained by Li et al. [30], the formulas for these wave speeds are only accurate up to first order in the stress τjϵ\tau_{j}\sim\epsilon. In hard polycrystalline materials like steel and concrete, the influence of texture and stress on ultrasonic wave speeds are typically both weak [33]. This implies that the texture anisotropy parameters β3,β5,β9\beta_{3},\beta_{5},\beta_{9} are also small, as confirmed by several experiments [13, 20]. Assuming that β3β5β9ϵ\beta_{3}\sim\beta_{5}\sim\beta_{9}\sim\epsilon, then we can simplify the expression for vθv_{\theta} by taking a series expansion in ϵ\epsilon and keeping only the first-order terms, to give

ρvθ2=μ+β32+β5n12n22+τ12(β2+β7+2n12+2β10n12n22)+τ22[β14+β15+β18+2n22+2n12n22(β162β17)]+τ32(β15+β18+2β16n12n22).\rho v_{\theta}^{2}=\mu+\frac{\beta_{3}}{2}+\beta_{5}n_{1}^{2}n_{2}^{2}+\frac{\tau_{1}}{2}(\beta_{2}+\beta_{7}+2n_{1}^{2}+2\beta_{10}n_{1}^{2}n_{2}^{2})\\ +\frac{\tau_{2}}{2}[\beta_{14}+\beta_{15}+\beta_{18}+2n_{2}^{2}+2n_{1}^{2}n_{2}^{2}(\beta_{16}-2\beta_{17})]+\frac{\tau_{3}}{2}(\beta_{15}+\beta_{18}+2\beta_{16}n_{1}^{2}n_{2}^{2}). (64)

Now we take n1=cosθn_{1}=\cos\theta and n2=sinθn_{2}=\sin\theta and compute the difference ρ(vθ12vθ22)\rho(v_{\theta_{1}}^{2}-v_{\theta_{2}}^{2}), where θ2=±θ1±π/2\theta_{2}=\pm\theta_{1}\pm\pi/2, to obtain

ρ(vθ12vθ2)2cos(2θ1)=τ1τ2.\frac{\rho(v_{\theta_{1}}^{2}-v_{\theta_{2}})^{2}}{\cos(2\theta_{1})}=\tau_{1}-\tau_{2}. (65)

This extension of the angled shear wave method is valid provided that both waves travel through a region with the same texture, that the texture is aligned with the stress, and that the initial stress and the texture both have a small effect on the wave speed. It is independent of the material parameters and allows for a direct measurement of the initial stress in many real-world situations, such as that present in railways or prestressed concrete (see Figure 1(c)).

4.4 Linearised equation of ISRI

In linear elasticity, the term [𝝈𝑭]𝑭=𝑰\left[\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}} is required to solve equilibrium and dynamic problems [45]. Here we focus on using ISRI to derive restrictions on the contraction [𝝈𝑭]𝑭=𝑰:ϵ\left[\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}.

We follow the procedure developed in [15]. We differentiate (8) with respect to 𝑭^\hat{{\boldsymbol{F}}}, while holding 𝑭~\tilde{\boldsymbol{F}}, 𝝉\boldsymbol{\tau}, and 𝑮{\boldsymbol{G}} fixed, to reach and contract both sides on the right with ϵ\boldsymbol{\epsilon}, and obtain

𝝉:ϵ=trϵW^+[W𝝉]𝑭=𝑰:[𝝈𝑭]𝑭=𝑰:ϵ+2[W𝑮]𝑭=𝑰:(𝑮ϵ),\boldsymbol{\tau}:\boldsymbol{\epsilon}=\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\hat{W}+\left[\frac{\partial W}{\partial\boldsymbol{\tau}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}:\left[\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}+2\left[\frac{\partial W}{\partial{\boldsymbol{G}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}:({\boldsymbol{G}}\boldsymbol{\epsilon}), (66)

where we used the identity 𝝉=[W𝑭]𝑭=𝑰\boldsymbol{\tau}=\left[\frac{\partial W}{\partial{\boldsymbol{F}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}. The second and third terms in (66) are expanded in terms of powers of the initial stress as follows:

[W𝝉]𝑭=𝑰=β1𝑰+β2𝝉+β3𝝉2+β4𝑮+β5𝑮𝝉s,\displaystyle\left[\frac{\partial W}{\partial\boldsymbol{\tau}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}=\beta_{1}{\boldsymbol{I}}+\beta_{2}\boldsymbol{\tau}+\beta_{3}\boldsymbol{\tau}^{2}+\beta_{4}{\boldsymbol{G}}+\beta_{5}\left<{\boldsymbol{G}}\boldsymbol{\tau}\right>_{s}, (67)
[W𝑮]𝑭=𝑰=β6𝑰+β4𝝉+12β5𝝉2.\displaystyle\left[\frac{\partial W}{\partial{\boldsymbol{G}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}=\beta_{6}{\boldsymbol{I}}+\beta_{4}\boldsymbol{\tau}+\tfrac{1}{2}\beta_{5}\boldsymbol{\tau}^{2}. (68)

Here the coefficients β1\beta_{1}, β2\beta_{2}, and β3\beta_{3} are obtained by differentiating WW with respect to tr𝝉\mathop{\rm tr}\nolimits\boldsymbol{\tau}, tr𝝉2\mathop{\rm tr}\nolimits\boldsymbol{\tau}^{2}, and tr𝝉3\mathop{\rm tr}\nolimits\boldsymbol{\tau}^{3}, respectively, and evaluating at 𝑭=𝑰{\boldsymbol{F}}={\boldsymbol{I}} [15]. The additional coefficients β4\beta_{4}, β5\beta_{5}, and β6\beta_{6} are expressed as

β4=\displaystyle\beta_{4}= [W𝑴.𝝉𝑴]𝑭=𝑰=[WI13]𝑭=𝑰+[WI14]𝑭=𝑰,\displaystyle\left[\frac{\partial W}{\partial{\boldsymbol{M}}.\boldsymbol{\tau}{\boldsymbol{M}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}=\left[\frac{\partial W}{\partial I_{13}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}+\left[\frac{\partial W}{\partial I_{14}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}},
β5=\displaystyle\beta_{5}= 2[W𝑴.𝝉2𝑴]𝑭=𝑰=2[WI15]𝑭=𝑰+2[WI16]𝑭=𝑰,\displaystyle 2\left[\frac{\partial W}{\partial{\boldsymbol{M}}.\boldsymbol{\tau}^{2}{\boldsymbol{M}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}=2\left[\frac{\partial W}{\partial I_{15}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}+2\left[\frac{\partial W}{\partial I_{16}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}},
β6=\displaystyle\beta_{6}= [W𝑴.𝑪𝑴]𝑭=𝑰+[W𝑴.𝑪2𝑴]𝑭=𝑰=[WI4]𝑭=𝑰+[WI5]𝑭=𝑰.\displaystyle\left[\frac{\partial W}{\partial{\boldsymbol{M}}.{\boldsymbol{C}}{\boldsymbol{M}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}+\left[\frac{\partial W}{\partial{\boldsymbol{M}}.{\boldsymbol{C}}^{2}{\boldsymbol{M}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}=\left[\frac{\partial W}{\partial I_{4}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}+\left[\frac{\partial W}{\partial I_{5}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}}. (69)

Following [15], we use (67), (68), and (44) to rewrite (66) as

tr(ϵ𝝉)=(W^+γ0)trϵ+γ1𝑴.ϵ𝑴+γ2𝑴.ϵ𝝉𝑴+γ3tr(ϵ𝝉)+γ4tr(ϵ𝝉2)+γ5𝑴.ϵ𝝉2𝑴,\mathop{\rm tr}\nolimits\left(\boldsymbol{\epsilon}\boldsymbol{\tau}\right)=\left(\hat{W}+\gamma_{0}\right)\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}+\gamma_{1}{\boldsymbol{M}}.\boldsymbol{\epsilon}{\boldsymbol{M}}+\gamma_{2}{\boldsymbol{M}}.\boldsymbol{\epsilon}\boldsymbol{\tau}{\boldsymbol{M}}\\ +\gamma_{3}\mathop{\rm tr}\nolimits\left(\boldsymbol{\epsilon}\boldsymbol{\tau}\right)+\gamma_{4}\mathop{\rm tr}\nolimits\left(\boldsymbol{\epsilon}\boldsymbol{\tau}^{2}\right)+\gamma_{5}{\boldsymbol{M}}.\boldsymbol{\epsilon}\boldsymbol{\tau}^{2}{\boldsymbol{M}}, (70)

where the γi\gamma_{i} coefficient are expressed in terms of αi\alpha_{i}, βi\beta_{i}, and the invariants (12). As (70) has to hold for every ϵ\boldsymbol{\epsilon}, 𝝉\boldsymbol{\tau}, and unit direction 𝑴{\boldsymbol{M}}, we then deduce the relations

W^+γ0=0,γ1=1,γ2=0,γ3=0,γ4=0,γ5=0.\hat{W}+\gamma_{0}=0,\quad\gamma_{1}=1,\quad\gamma_{2}=0,\quad\gamma_{3}=0,\quad\gamma_{4}=0,\quad\gamma_{5}=0. (71)

In general, solving the above equations analytically seems to be very difficult.

4.5 Small stress 𝝉\boldsymbol{\tau}

Now we linearise [𝝈𝑭]𝑭=𝑰\left[\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\right]_{{\boldsymbol{F}}={\boldsymbol{I}}} for small 𝝉\boldsymbol{\tau}, which simplifies Equations (71) and generalises results of third-order elasticity [7, 30] to include residual stresses. Note that because 𝝉\boldsymbol{\tau} is a dimensional quantity, ‘small stress’ means that 𝝉\|\boldsymbol{\tau}\| is small in comparison to 𝝈𝑭𝑭=𝑰,𝝉=𝟎\|\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}\|_{{\boldsymbol{F}}={\boldsymbol{I}},\boldsymbol{\tau}=\boldsymbol{0}}.

Previous work [15] shows that to expand 𝝈𝑭\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}} to first order in 𝝉\boldsymbol{\tau}, we need to expand the linear ISRI (66) up to second order in 𝝉\boldsymbol{\tau}, as follows

𝝉:ϵ=trϵW^1,𝝉,𝝉2+[W𝝉1,𝝉,𝝉2]𝑭=𝑰:[𝝈𝑭1,𝝉]𝑭=𝑰:ϵ+2[W𝑮1,𝝉,𝝉2]𝑭=𝑰:𝑮ϵ.\boldsymbol{\tau}:\boldsymbol{\epsilon}=\mathop{\rm tr}\nolimits\boldsymbol{\epsilon}\underbrace{\hat{W}}_{1,\boldsymbol{\tau},\boldsymbol{\tau}^{2}}+\Big{[}\underbrace{\frac{\partial W}{\partial\boldsymbol{\tau}}}_{1,\boldsymbol{\tau},\boldsymbol{\tau}^{2}}\Big{]}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\Big{[}\underbrace{\frac{\partial\boldsymbol{\sigma}}{\partial{\boldsymbol{F}}}}_{1,\boldsymbol{\tau}}\Big{]}_{{\boldsymbol{F}}={\boldsymbol{I}}}:\boldsymbol{\epsilon}+2\Big{[}\underbrace{\frac{\partial W}{\partial{\boldsymbol{G}}}}_{1,\boldsymbol{\tau},\boldsymbol{\tau}^{2}}\Big{]}_{{\boldsymbol{F}}={\boldsymbol{I}}}:{\boldsymbol{G}}\boldsymbol{\epsilon}. (72)

Here the terms under the braces are the different orders of 𝝉\boldsymbol{\tau} we need to consider. For example, “1,𝝉,𝝉21,\boldsymbol{\tau},\boldsymbol{\tau}^{2}” means we need to expand the term above up to second order in 𝝉\boldsymbol{\tau}.

Returning to (70), to use these equations and deduce restrictions for the aj,ia_{j,i} we perform a series expansion up to order 𝒪(𝝉2)\mathcal{O}(\boldsymbol{\tau}^{2}) of (70), which together with equations (71), leads to

W^+γ0=0,\displaystyle\hat{W}+\gamma_{0}=0, γ1=0,\displaystyle\gamma_{1}=0, up to 𝒪(𝝉2),\displaystyle\text{up to }\mathcal{O}(\boldsymbol{\tau}^{2}), (73)
γ2=0,\displaystyle\gamma_{2}=0, γ3=0,\displaystyle\gamma_{3}=0, up to 𝒪(𝝉),\displaystyle\text{up to }\mathcal{O}(\boldsymbol{\tau}), (74)
γ4=0,\displaystyle\gamma_{4}=0, γ5=0,\displaystyle\gamma_{5}=0, for 𝝉=𝟎.\displaystyle\text{for }\boldsymbol{\tau}=\boldsymbol{0}. (75)

To expand W^\hat{W}, W/𝝉\partial W/\partial\boldsymbol{\tau}, and W/𝑮\partial W/\partial{\boldsymbol{G}}, we simply expand WW up to third order in 𝝉\boldsymbol{\tau}, see [7] for details, and then directly calculate W/𝝉\partial W/\partial\boldsymbol{\tau} and W/𝑮\partial W/\partial{\boldsymbol{G}}. A third-order expansion of W(𝑰,𝝉,𝑮)W({\boldsymbol{I}},\boldsymbol{\tau},{\boldsymbol{G}}) in 𝝉\boldsymbol{\tau} leads to

W(𝑰,𝝉,𝑮)=ψ1tr𝝉+ψ4tr(𝝉𝑮)+ψ2(tr𝝉)2+ψ5(tr𝝉)tr(𝝉𝑮)+ψ7[tr(𝝉𝑮)]2+ψ10tr(𝝉2)+ψ13tr(𝝉2𝑮)+ψ3(tr𝝉)3+ψ6(tr𝝉)2tr(𝝉𝑮)+ψ8(tr𝝉)tr[(𝝉𝑮)2]+ψ9tr[(𝝉𝑮)3]+ψ11(tr𝝉2)(tr𝝉)+ψ12(tr𝝉2)tr(𝝉𝑮)+ψ14(tr𝝉)tr(𝝉2𝑮)+ψ15tr(𝝉𝑮)tr(𝝉2𝑮)+ψ16tr𝝉3,W({\boldsymbol{I}},\boldsymbol{\tau},{\boldsymbol{G}})=\psi_{1}\mathop{\rm tr}\nolimits\boldsymbol{\tau}+\psi_{4}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})+\psi_{2}(\mathop{\rm tr}\nolimits\boldsymbol{\tau})^{2}+\psi_{5}(\mathop{\rm tr}\nolimits\boldsymbol{\tau})\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\\ +\psi_{7}[\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})]^{2}+\psi_{10}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}^{2})+\psi_{13}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}^{2}{\boldsymbol{G}})+\psi_{3}(\mathop{\rm tr}\nolimits\boldsymbol{\tau})^{3}\\ +\psi_{6}(\mathop{\rm tr}\nolimits\boldsymbol{\tau})^{2}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})+\psi_{8}(\mathop{\rm tr}\nolimits\boldsymbol{\tau})\mathop{\rm tr}\nolimits[(\boldsymbol{\tau}{\boldsymbol{G}})^{2}]+\psi_{9}\mathop{\rm tr}\nolimits[(\boldsymbol{\tau}{\boldsymbol{G}})^{3}]\\ +\psi_{11}(\mathop{\rm tr}\nolimits\boldsymbol{\tau}^{2})(\mathop{\rm tr}\nolimits\boldsymbol{\tau})+\psi_{12}(\mathop{\rm tr}\nolimits\boldsymbol{\tau}^{2})\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\\ +\psi_{14}(\mathop{\rm tr}\nolimits\boldsymbol{\tau})\mathop{\rm tr}\nolimits(\boldsymbol{\tau}^{2}{\boldsymbol{G}})+\psi_{15}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\mathop{\rm tr}\nolimits(\boldsymbol{\tau}^{2}{\boldsymbol{G}})+\psi_{16}\mathop{\rm tr}\nolimits\boldsymbol{\tau}^{3}, (76)

where the constants ψj\psi_{j} do not depend on 𝝉\boldsymbol{\tau} or 𝑮{\boldsymbol{G}}. The first line has first- and second-order terms in 𝝉\boldsymbol{\tau}, while the second and third line are all third-order terms. In the above we assumed that W(𝑰,𝝉,𝑮)0W({\boldsymbol{I}},\boldsymbol{\tau},{\boldsymbol{G}})\to 0 when 𝝉𝟎\boldsymbol{\tau}\to\boldsymbol{0}. By differentiating the above expression with respect to either 𝝉\boldsymbol{\tau} or 𝑮{\boldsymbol{G}}, we can calculate W𝝉\frac{\partial W}{\partial\boldsymbol{\tau}} and W𝑮\frac{\partial W}{\partial{\boldsymbol{G}}}. For example,

[W𝑮]𝑭=𝑰:𝑮ϵ=ψ4tr(ϵ𝑮𝝉)+ψ5(tr𝝉)tr(ϵ𝑮𝝉)+ψ13tr(ϵ𝑮𝝉2)+2ψ7tr(𝝉𝑮)tr(ϵ𝑮𝝉),\Big{[}\frac{\partial W}{\partial{\boldsymbol{G}}}\Big{]}_{{\boldsymbol{F}}={\boldsymbol{I}}}\!\!\!:{\boldsymbol{G}}\boldsymbol{\epsilon}=\psi_{4}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}\boldsymbol{\tau})+\psi_{5}(\mathop{\rm tr}\nolimits\boldsymbol{\tau})\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}\boldsymbol{\tau})+\psi_{13}\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}\boldsymbol{\tau}^{2})+2\psi_{7}\mathop{\rm tr}\nolimits(\boldsymbol{\tau}{\boldsymbol{G}})\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}\boldsymbol{\tau}), (77)

where we discarded terms that were of third order in 𝝉\boldsymbol{\tau} as these are not needed to expand (72) up to second order in 𝝉\boldsymbol{\tau}.

Next we substitute (53), and (76), into the equations (7375). Then we can set the coefficient multiplying the terms

trϵ,tr(ϵ𝑮),tr(ϵ𝑮𝝉),tr(ϵ𝝉),tr(ϵ𝝉2),tr(ϵ𝑮𝝉2)\mathop{\rm tr}\nolimits\boldsymbol{\epsilon},\;\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}),\;\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}\boldsymbol{\tau}),\;\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}\boldsymbol{\tau}),\;\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}\boldsymbol{\tau}^{2}),\;\mathop{\rm tr}\nolimits(\boldsymbol{\epsilon}{\boldsymbol{G}}\boldsymbol{\tau}^{2})

to zero, because the equations (7375) must hold for every 𝝉\boldsymbol{\tau}, ϵ\boldsymbol{\epsilon}, and 𝑮{\boldsymbol{G}}. We provide these equations, and their solution, as supplementary material in the form of a Mathematica [25] notebook, which is also available as a Github Gist [16]. They are too long to reproduce here. These 24 equations can be written in terms of the ai,ja_{i,j} and ψn\psi_{n} coefficients only. As our goal is only to restrict the ai,ja_{i,j} coefficients, we can eliminate the ψn\psi_{n} coefficients and reduce the 24 equations to 7 independent equations, which can be written only in terms of the 21 ai,ja_{i,j} coefficients. In this process we deduce that ψ1=ψ4=0\psi_{1}=\psi_{4}=0, which confirms that WW in Equation (76) has no first-order terms in 𝝉\boldsymbol{\tau}. In conclusion, we know that there must be only 14 independent coefficients of the form ai,ja_{i,j}, which is exactly the same number of independent coefficients for a third-order elastic material with transverse texture anisotropy [7].

When applying the restriction (72) to the incremental stress (52) we expect a response which is asymptotically equivalent to that of a third-order elastic material with transverse texture anisotropy [7], which has undergone a deformation corresponding to the stress field 𝝉\boldsymbol{\tau}. This is because the ISRI restriction is automatically satisfied by classical hyperelastic materials [15, 14].

Of the seven independent equations we were able to deduce for the ai,ja_{i,j}, the three simplest equations are

a3,0=\displaystyle a_{3,0}= a2,0a1,0(a4,0+1),\displaystyle\frac{a_{2,0}}{a_{1,0}}\left(a_{4,0}+1\right), (78)
a4,0=\displaystyle a_{4,0}= (a7,0a1,1)a1,02(a2,0+a1,2(a5,0+a6,0)+a1,1(3a5,0+a6,0))a1,02a2,0a5,02a2,0a5,0+a1,0(a2,0+2a5,0),\displaystyle\frac{\left(a_{7,0}-a_{1,1}\right)a_{1,0}^{2}-\left(a_{2,0}+a_{1,2}\left(a_{5,0}+a_{6,0}\right)+a_{1,1}\left(3a_{5,0}+a_{6,0}\right)\right)a_{1,0}-2a_{2,0}a_{5,0}}{2a_{2,0}a_{5,0}+a_{1,0}\left(a_{2,0}+2a_{5,0}\right)}, (79)
a9,0=\displaystyle a_{9,0}= (a10,0a1,2)a1,02+a2,0a1,0(2a1,12a1,2+a4,0+1)a1,0(a1,1+a1,2)\displaystyle\frac{\left(a_{10,0}-a_{1,2}\right)a_{1,0}^{2}+a_{2,0}a_{1,0}\left(-2a_{1,1}-2a_{1,2}+a_{4,0}+1\right)}{a_{1,0}\left(a_{1,1}+a_{1,2}\right)}
(3a1,1+a1,2+2a4,0)a1,0a6,0+2a2,0(a4,0+1)a6,0a1,0(a1,1+a1,2).\displaystyle-\frac{\left(3a_{1,1}+a_{1,2}+2a_{4,0}\right)a_{1,0}a_{6,0}+2a_{2,0}\left(a_{4,0}+1\right)a_{6,0}}{a_{1,0}\left(a_{1,1}+a_{1,2}\right)}. (80)

We provide all seven restrictions as supplementary material, in the form of a Mathematica notebook, available as a Github Gist [16] (the other four equations are too long to reproduce here.) The notebook also demonstrates that these restrictions do indeed solve Equations (73) to (75).

Specifically we note that Equation (79) reduces to the linearised ISRI condition for materials with no texture anisotropy given by Equation (4.36) in [15] when taking a2,0=a3,0=a6,0=0a_{2,0}=a_{3,0}=a_{6,0}=0. To verify equations (78 - 80) we checked these results directly against the instantaneous moduli of a hyperelastic material with fibre reinforcement [7] and obtained the same equations.

4.6 Example: texture aligned with the initial stress

Substituting the coefficients shown in (55) into the ISRI condition (72) leads us to conclude that β13,β14,β16,β17\beta_{13},\beta_{14},\beta_{16},\beta_{17} are dependent on the other βj\beta_{j} coefficients. In particular, using (78,79,80), we can write β13\beta_{13} and β17\beta_{17} as

β13β1=β2β9+β1(β15+1)+β8(β2+2(β14+β15+1)),\displaystyle\beta_{13}\beta_{1}=\beta_{2}\beta_{9}+\beta_{1}\left(\beta_{15}+1\right)+\beta_{8}\left(\beta_{2}+2\left(\beta_{14}+\beta_{15}+1\right)\right), (81)
β17β1=2(β3+β9)+β2(2β3+β5+β9)+(β3+2β9)β14+β1(β2β15)+2β9β15.\displaystyle\beta_{17}\beta_{1}=2\left(\beta_{3}+\beta_{9}\right)+\beta_{2}\left(2\beta_{3}+\beta_{5}+\beta_{9}\right)+\left(\beta_{3}+2\beta_{9}\right)\beta_{14}+\beta_{1}\left(\beta_{2}-\beta_{15}\right)+2\beta_{9}\beta_{15}. (82)

The equations for β14\beta_{14} and β17\beta_{17} are more complicated and are given in a supplementary Mathematica notebook, available as a Github Gist [16].

Counting, we see that there are 14 independent coefficients for the moduli (55), exactly the same number of independent coefficients needed for hyperelastic third-order elastic material [7] when the strain tensor is co-axial with the texture direction.

5 Conclusion

There are many elastic solids where the combined influence of initial stress and texture is unavoidable. Both induce anisotropy in the material response. In this paper, we developed an elastic theory for strain energy functions that represent compressible materials with texture anisotropy under initial stress. In biological tissues these strain energies can be used to model collagen-reinforced materials under residual stress; in man-made solids, they can represent materials under stress with a preferred grain direction or reinforced/prestressed by fibres and cables.

To deduce the strain energy and the associated stress tensors, we used a restriction called initial stress reference independence (ISRI). In simple terms, this restriction implies that the strain energy density, per unit mass of the reference, depends only on the deformation gradient, initial stress tensor, and texture directions. Strain energy functions that do not satisfy ISRI can lead to non-physical material responses [15]. Here we investigated both the nonlinear and linearized forms of the strain and strain energy.

The present study provides a detailed extension of ISRI as developed by Gower and collaborators [15, 14] to a more general case including transverse texture anisotropy. We developed two examples of strain energy densities for compressible initially stressed transversely isotropic materials that satisfy ISRI. We also investigated the inflation of residually-stressed compressible transversely isotropic tubes, using a residual stress field which captures what is observed in many biological tubular structures. We then studied the tension of a welded steel plate using the developed model, and found a physically acceptable behaviour. For both problems, we observed a considerable influence of the initial stress on the Cauchy stress distribution.

Finally, the linearised theory developed in this paper can be used to investigate small-amplitude wave propagation or vibration analysis in initially-stressed solids with transverse texture. We used this linearisation to propose a non-destructive method to measure initial stress directly with shear waves, a process which is needed, and suited to, hard solids such as metals [29, 33, 30].

Acknowledgments

SM thanks Dr Raja Chakaraborti, Tripura Institute of Technology, Agartala, India, for an enlightening discussion on Masubuchi and Martin’s solution [34] for a welded plate. The research of MD was supported by a 111 Project for International Collaboration (Chinese Government, PR China) No. B21034 and by a grant from the Seagull Program (Zhejiang Province, PR China). AG gratefully acknowledges partial funding provided by IN2TRACK3 - European Commission - Horison Europe and Network Rail LTD and FRA - Federal Rail Association of America (FR21RPD31000000039).

Appendix A Determining the second strain energy as a function of initial stress and preferred direction

Here we express the strain energy potential (22):

W=μ12J0(tr(𝑩0𝑪)3)+μ22J0(𝑴.𝑪𝑩0𝑪𝑴1)μ1J0(1(JJ0)β)β,W=\frac{\mu_{1}}{2J_{0}}\left(\mathop{\rm tr}\nolimits({\boldsymbol{B}}_{0}{\boldsymbol{C}})-3\right)+\frac{\mu_{2}}{2J_{0}}\left({\boldsymbol{M}}.{\boldsymbol{C}}{\boldsymbol{B}}_{0}{\boldsymbol{C}}{\boldsymbol{M}}-1\right)-\frac{\mu_{1}}{J}_{0}\frac{(1-\left(JJ_{0}\right)^{-\beta})}{\beta}, (83)

as a function of initial stress and texture. Presently, this strain energy is expressed as a function of the initial strain 𝑩0{\boldsymbol{B}}_{0}. But the evaluation of 𝑩0{\boldsymbol{B}}_{0} requires the knowledge of the stress-free configuration 0\mathcal{R}_{0} which is usually unattainable. Hence, we aim to replace 𝑩0{\boldsymbol{B}}_{0} with a known function of the initial stress 𝝉\boldsymbol{\tau} and of the preferred direction 𝑴{\boldsymbol{M}}. This step necessitates the inversion of a non-linear anisotropic constitutive relation.

The initial stress is obtained by substituting 𝑭=𝑰{\boldsymbol{F}}={\boldsymbol{I}} in the constitutive relation (24), as

𝝉=μ1J0𝑩0+μ2J0(𝑩0𝑴𝑴+𝑴𝑴𝑩0)μ1J0β+1𝑰.\boldsymbol{\tau}=\frac{\mu_{1}}{J}_{0}{\boldsymbol{B}}_{0}+\frac{\mu_{2}}{J}_{0}\left({\boldsymbol{B}}_{0}{\boldsymbol{M}}\otimes{\boldsymbol{M}}+{\boldsymbol{M}}\otimes{\boldsymbol{M}}{\boldsymbol{B}}_{0}\right)-\frac{\mu_{1}}{J_{0}^{\beta+1}}{\boldsymbol{I}}. (84)

Note that 𝑴{\boldsymbol{M}} and 𝑴0{\boldsymbol{M}}_{0} are the preferred directions in the stressed and the stress-free reference configurations, respectively, where 𝑴=𝑭0𝑴0{\boldsymbol{M}}={\boldsymbol{F}}_{0}{\boldsymbol{M}}_{0}.

To find 𝑩0{\boldsymbol{B}}_{0} in terms of 𝝉\boldsymbol{\tau} and 𝑴{\boldsymbol{M}}, we need to invert the relation (84). To this end, (84) is expressed in the form

J0(𝝉+μ1J0β+1𝑰)=(μ1𝕀+μ2𝑰𝑴𝑴+μ2𝑴𝑴𝑰)𝑩0,J_{0}\left(\boldsymbol{\tau}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}{\boldsymbol{I}}\right)=\left(\mu_{1}\mathbb{I}+\mu_{2}{\boldsymbol{I}}\boxtimes{\boldsymbol{M}}\otimes{\boldsymbol{M}}+\mu_{2}{\boldsymbol{M}}\otimes{\boldsymbol{M}}\boxtimes{\boldsymbol{I}}\right){\boldsymbol{B}}_{0}, (85)

where we define the fourth-order identity tensor as 𝕀=𝑰𝑰\mathbb{I}={\boldsymbol{I}}\boxtimes{\boldsymbol{I}} and the square tensor product by (𝑨𝑩)𝑪=𝑨𝑪𝑩T\left({\boldsymbol{A}}\boxtimes{\boldsymbol{B}}\right){\boldsymbol{C}}={\boldsymbol{A}}{\boldsymbol{C}}{\boldsymbol{B}}^{T} for any second-order tensors 𝑨{\boldsymbol{A}}, 𝑩{\boldsymbol{B}}, 𝑪{\boldsymbol{C}}. We invert [26] the fourth-order tensor [μ1𝕀+μ2𝑰𝑴𝑴+μ2𝑴𝑴𝑰]\left[\mu_{1}\mathbb{I}+\mu_{2}{\boldsymbol{I}}\boxtimes{\boldsymbol{M}}\otimes{\boldsymbol{M}}+\mu_{2}{\boldsymbol{M}}\otimes{\boldsymbol{M}}\boxtimes{\boldsymbol{I}}\right] and multiply the inverse on both the sides of (85) to express 𝑩0{\boldsymbol{B}}_{0} as a function of 𝝉\boldsymbol{\tau} and 𝑴{\boldsymbol{M}}:

𝑩0=a1𝝉^+a2𝝉^𝑴𝑴+a2𝑴𝑴𝝉^+a3𝑴𝑴𝝉^𝑴𝑴,{\boldsymbol{B}}_{0}=a_{1}\hat{\boldsymbol{\tau}}+a_{2}\hat{\boldsymbol{\tau}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}+a_{2}{\boldsymbol{M}}\otimes{\boldsymbol{M}}\hat{\boldsymbol{\tau}}+a_{3}{\boldsymbol{M}}\otimes{\boldsymbol{M}}\hat{\boldsymbol{\tau}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}, (86)

where 𝝉^=J0(𝝉+μ1J0β+1𝑰)\hat{\boldsymbol{\tau}}=J_{0}\left(\boldsymbol{\tau}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}{\boldsymbol{I}}\right) and the scalar parameters a1a_{1}, a2a_{2}, a3a_{3} are calculated as

a1=1μ1,a2=μ2μ1(μ1+μ2I𝑴),a3=2μ22μ1(μ12+3μ1μ2I𝑴+2μ22I𝑴2),a_{1}=\frac{1}{\mu_{1}},\qquad a_{2}=-\frac{\mu_{2}}{\mu_{1}(\mu_{1}+\mu_{2}I_{{\boldsymbol{M}}})},\qquad a_{3}=\frac{2\mu_{2}^{2}}{\mu_{1}\left(\mu_{1}^{2}+3\mu_{1}\mu_{2}I_{{\boldsymbol{M}}}+2\mu_{2}^{2}I_{{\boldsymbol{M}}}^{2}\right)}, (87)

by substituting (86) in (84) and thereafter equating the coefficients of 𝝉^\hat{\boldsymbol{\tau}}, (𝝉^𝑴𝑴+𝑴𝑴𝝉^)\left(\hat{\boldsymbol{\tau}}{\boldsymbol{M}}\otimes{\boldsymbol{M}}+{\boldsymbol{M}}\otimes{\boldsymbol{M}}\hat{\boldsymbol{\tau}}\right), and 𝑴𝑴𝝉^𝑴𝑴{\boldsymbol{M}}\otimes{\boldsymbol{M}}\hat{\boldsymbol{\tau}}{\boldsymbol{M}}\otimes{\boldsymbol{M}} on both sides of the resulting equation.

Finally, we use the derived expression of 𝑩0{\boldsymbol{B}}_{0} (86) to express the strain energy density (83) as a function of initial stress, as

W=\displaystyle W= 12(I9+μ1J0β+1I13μ1)+μ12[2a2(I13+μ1J0β+1I4)+a3(I𝝉4I4+μ1J0β+1I4I𝑴)]\displaystyle\frac{1}{2}\left(I_{9}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}I_{1}-3\mu_{1}\right)+\frac{\mu_{1}}{2}\left[2a_{2}\left(I_{13}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}I_{4}\right)+a_{3}\left(I_{\boldsymbol{\tau}_{4}}I_{4}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}I_{4}I_{{\boldsymbol{M}}}\right)\right]
+μ22[a1𝑴𝑪𝝉𝑪𝑴+2a2I4I13+a3I42I𝝉4+μ1J0β+1(a1I5+2a2I42+a3I42I𝑴)1]\displaystyle+\frac{\mu_{2}}{2}\left[a_{1}{\boldsymbol{M}}\cdot{\boldsymbol{C}}\boldsymbol{\tau}{\boldsymbol{C}}{\boldsymbol{M}}+2a_{2}I_{4}I_{13}+a_{3}I_{4}^{2}I_{\boldsymbol{\tau}_{4}}+\frac{\mu_{1}}{{J_{0}}^{\beta+1}}\left(a_{1}I_{5}+2a_{2}I_{4}^{2}+a_{3}I_{4}^{2}I_{{\boldsymbol{M}}}\right)-1\right]
μ1(1(JJ0)β)βJ0,\displaystyle-{\mu_{1}}\frac{(1-\left(JJ_{0}\right)^{-\beta})}{\beta J_{0}}, (88)

which includes most invariants developed in (12), e.g., I1I_{1}, I3I_{3}, I𝑴I_{{\boldsymbol{M}}} I4I_{4}, I5I_{5}, I𝝉4I_{\boldsymbol{\tau}_{4}}, I9I_{9}, I13I_{13}, and 𝑴𝑪𝝉𝑪𝑴{\boldsymbol{M}}\cdot{\boldsymbol{C}}\boldsymbol{\tau}{\boldsymbol{C}}{\boldsymbol{M}}. However, it also involves J0J_{0}, which is an invariant of the (unknown) initial strain. To express J0J_{0} in terms of the known initial stress invariants, we evaluate the determinant on both sides of the equation

J0(𝝉g(J0)𝑰)=μ1𝑩0+μ2(𝑩0𝑴𝑴+𝑴𝑴𝑩0).J_{0}\left(\boldsymbol{\tau}-g(J_{0}){\boldsymbol{I}}\right)={\mu_{1}}{\boldsymbol{B}}_{0}+{\mu_{2}}\left({\boldsymbol{B}}_{0}{\boldsymbol{M}}\otimes{\boldsymbol{M}}+{\boldsymbol{M}}\otimes{\boldsymbol{M}}{\boldsymbol{B}}_{0}\right). (89)

The determinant of the right-hand side of (89) can be calculated as

det[μ1𝑩0+μ2(𝑩0𝑴𝑴+𝑴𝑴𝑩0)]\displaystyle\text{det}\left[{\mu_{1}}{\boldsymbol{B}}_{0}+{\mu_{2}}\left({\boldsymbol{B}}_{0}{\boldsymbol{M}}\otimes{\boldsymbol{M}}+{\boldsymbol{M}}\otimes{\boldsymbol{M}}{\boldsymbol{B}}_{0}\right)\right] =J02det[μ1𝑰+μ2(𝑪0𝑴0𝑴0+𝑴0𝑴0𝑪0)]\displaystyle=J_{0}^{2}\text{det}\left[{\mu_{1}}{\boldsymbol{I}}+{\mu_{2}}\left({\boldsymbol{C}}_{0}{\boldsymbol{M}}_{0}\otimes{\boldsymbol{M}}_{0}+{\boldsymbol{M}}_{0}\otimes{\boldsymbol{M}}_{0}{\boldsymbol{C}}_{0}\right)\right]
=J02(μ13+μ12I𝑷1+μ1I𝑷2+I𝑷3),\displaystyle=J_{0}^{2}\left(\mu_{1}^{3}+\mu_{1}^{2}I_{{\boldsymbol{P}}_{1}}+\mu_{1}I_{{\boldsymbol{P}}_{2}}+I_{{\boldsymbol{P}}_{3}}\right), (90)

where I𝑷1=𝑴𝑴I_{{\boldsymbol{P}}_{1}}={\boldsymbol{M}}\cdot{\boldsymbol{M}}, I𝑷2=12(𝑴𝑴)2+𝑴0𝑪02𝑴0I_{{\boldsymbol{P}}_{2}}=\frac{1}{2}({\boldsymbol{M}}\cdot{\boldsymbol{M}})^{2}+{\boldsymbol{M}}_{0}\cdot{\boldsymbol{C}}_{0}^{2}{\boldsymbol{M}}_{0}, and I𝑷3=0I_{{\boldsymbol{P}}_{3}}=0. Following similar steps, we also expand the determinant of left-hand side of (89) to finally obtain

g(J0)3g(J0)2I𝝉1+g(J0)I𝝉2I𝝉3+1J0[μ13+μ12μ2(𝑴𝑴)+μ1μ22(𝑴0𝑪02𝑴0)+12μ1μ22(𝑴𝑴)2]=0.g(J_{0})^{3}-g(J_{0})^{2}I_{\boldsymbol{\tau}_{1}}+g(J_{0})I_{\boldsymbol{\tau}_{2}}-I_{\boldsymbol{\tau}_{3}}\\ +\frac{1}{J_{0}}\left[\mu_{1}^{3}+\mu_{1}^{2}\mu_{2}({\boldsymbol{M}}\cdot{\boldsymbol{M}})+\mu_{1}\mu_{2}^{2}({\boldsymbol{M}}_{0}\cdot{\boldsymbol{C}}_{0}^{2}{\boldsymbol{M}}_{0})+\frac{1}{2}\mu_{1}\mu_{2}^{2}({\boldsymbol{M}}\cdot{\boldsymbol{M}})^{2}\right]=0. (91)

This equation for J0J_{0} still contains another invariant, 𝑴0𝑪02𝑴0{\boldsymbol{M}}_{0}\cdot{\boldsymbol{C}}_{0}^{2}{\boldsymbol{M}}_{0}, of the initial strain, because 𝑴0\boldsymbol{M}_{0} and 𝑪0{\boldsymbol{C}}_{0} are both associated with the unknown stress-free configuration. Hence, an additional equation correlating the invariants of initial stress and strain is required. This is accomplished by multiplying 𝑴𝑴{\boldsymbol{M}}\otimes{\boldsymbol{M}} on both sides of (89) and calculating the trace. With some simplifications, we obtain this additional equation as

J0[𝑴𝝉𝑴g(J0)(𝑴𝑴)]=μ1𝑴0.𝑪02𝑴0+2μ2(𝑴0.𝑪02𝑴0)(𝑴𝑴),J_{0}\left[{\boldsymbol{M}}\cdot\boldsymbol{\tau}{\boldsymbol{M}}-g\left(J_{0}\right)({\boldsymbol{M}}\cdot{\boldsymbol{M}})\right]=\mu_{1}{\boldsymbol{M}}_{0}.{\boldsymbol{C}}_{0}^{2}{\boldsymbol{M}}_{0}+2\mu_{2}\left({\boldsymbol{M}}_{0}.{\boldsymbol{C}}_{0}^{2}{\boldsymbol{M}}_{0}\right)({\boldsymbol{M}}\cdot{\boldsymbol{M}}), (92)

which implies that

𝑴0𝑪02𝑴0=J0[I𝝉4g(J0)(𝑴𝑴)]μ1+2μ2(𝑴𝑴).{\boldsymbol{M}}_{0}\cdot{\boldsymbol{C}}_{0}^{2}{\boldsymbol{M}}_{0}=\frac{J_{0}\left[I_{\boldsymbol{\tau}_{4}}-g\left(J_{0}\right)({\boldsymbol{M}}\cdot{\boldsymbol{M}})\right]}{\mu_{1}+2\mu_{2}({\boldsymbol{M}}\cdot{\boldsymbol{M}})}. (93)

We can substitute (93) into (91) and solve to express J0J_{0} completely in terms of the invariants of initial stress 𝝉\boldsymbol{\tau}. Hence, we finally obtain a strain energy function where all terms and parameters are completely expressed with the quantities associated with the stressed reference. We can similarly describe Cauchy stress completely from the stressed reference by substituting 𝑩0{\boldsymbol{B}}_{0} (86) and J0J_{0} in (24).

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