Projective transformations of convex bodies and volume product
Abstract.
In this paper we study certain variational aspects of the volume product functional restricted to the space of small projective deformations of a fixed convex body. In doing so, we provide a short proof of a theorem by Klartag: a strong version of the slicing conjecture implies the Mahler conjecture. We also exhibit an interesting family of critical convex bodies in dimension containing saddle points for this functional.
Key words and phrases:
Convex body, Mahler conjecture, slicing conjecture, volume product.2010 Mathematics Subject Classification:
Primary: 52A20, 52A40. Secondary: 52A381. Introduction
The volume product of a convex body whose interior contains the origin is the quantity . Here denotes the standard Lebesgue measure in , and is the polar body of . While it is well known [Santaló 1949] that the volume product among convex bodies whose barycenter is centered at the origin is maximized only by ellipsoids, the lower bound is still unknown in dimension greater than . More precisely, the Mahler conjecture claims that any convex body containing the origin in its interior should satisfy the following optimal inequality:
The conjectured lower bound is reached by any -simplex whose vertices span and sum up to zero. Mahler actually proved the inequality in dimension [Mahler 1939], but so far the conjecture remains open for higher dimensions.
If we endow the space of convex bodies in with the usual Hausdorff topology, the volume product becomes a continuous function over the space of convex bodies in containing the origin in their interior. A standard compactness argument then shows that the functional attains its minimum. According to [Santaló 1949] any local minimizer of the volume product satisfies that its barycenter and the barycenter of its polar coincide with the origin. Now recall that the covariance matrix of a convex body whose barycenter is centered at the origin is the symmetric matrix with the following entries:
In this paper we propose a short proof of the following result due to Klartag.
Theorem 1.1.
[Klartag 2018] Let be a local minimizer of the volume product. Then
in the sense of symmetric matrices.
It follows from this result that a strong version of the slicing conjecture implies the Mahler conjecture. This strong slicing conjecture states that the homogeneous quantity is maximized among convex bodies with barycenter at the origin by any -simplex whose vertices span and sum up to zero, see [Klartag 2018] for further details.
Klartag’s proof of Theorem 1.1 is based on a variational argument in the space of projective images of that makes substantial use of the Laplace transform. In this paper we will also use a variational argument in the space of projective images of in order to recover Theorem 1.1, but our computation will be considerably simpler. More precisely, in section 2 we consider the functional which is well-defined for any convex body in on an open neighborhood of the origin in . By [Santaló 1949] we will easily observe (Proposition 2.1) that the origin is a critical point of the functional if and only if . Then an elementary computation (Proposition 2.2) will lead us to the following expression for the Hessian matrix at such a critical point:
Finally we will check (Proposition 2.3) that the above Hessian is positive semi-definite if and only if the symmetric matrix inequality holds true. This implies Theorem 1.1.
Our functional is defined using special projective transformations of the convex body, which are obtained as specific combinations of translations of the polar body with translations of the body itself. In section 3 we will prove that this functional captures all the relevant information about variational properties of the volume product on the space of projective images of a given convex body. More precisely, we will first prove in Proposition 3.1 that once a suitable affine coordinate chart is fixed, the projective transformations close to the identity map transform the convex body into a new convex body which still contains the origin in its interior. We will then show in Proposition 3.2 that the volume product of these small projective perturbations of our convex body factors through the map .
Finally in section 4 we will exhibit an interesting family of convex bodies in dimension that are critical points of the volume product on the space of their own projective images. More precisely, we will show the following.
Theorem 1.2.
There exists a -parameter deformation of an equilateral triangle by axially symmetric pentagons satisfying the following properties.
-
i)
Every pentagon is a critical point of the volume product in its own projective orbit; more precisely, the function has a critical point at the origin.
-
ii)
The pentagon is a saddle point; more precisely the Hessian matrix is non-degenerate and non-definite.
-
iii)
For close enough to we have
(1.1)
The main relevant property of this family is that part of these critical points are saddle points. The last property that there exists small deformations of verifying (1.1) is also remarkable for the following reason. Recall that the -dimensional Euclidean unit ball also satisfies , and that Kuperberg in a private communication to Klartag shows that the Euclidean ball of any dimension is a local maximizer of the functional in the class of centrally-symmetric convex bodies with sufficiently smooth boundary, see [Klartag 2018, p.78]. At some point it was not clear if this upperbound was a global one, until it was disproved in [Klartag 2018, Proposition 1.5] for large dimensions. Our family discards any non-symmetric analog of Kuperberg’s local result near the -simplex, even in low dimensions.
Acknowledgements. We would like to thank B. Klartag for valuable exchanges.
2. A simple variational study of the volume product
The purpose of this section is to give a short proof of Theorem 1.1.
Fix a convex body of containing the origin in its interior, and consider the functional
which is well-defined in an open neighbourhood of .
Proposition 2.1.
The Jacobian matrix of at the origin is the following:
Recall the barycenter of a convex body is defined by the formula .
Proof.
Equivalently, we shall prove that for any , the following holds:
First recall that Santaló proved in [Santaló 1949] the following formula:
Then we easily compute that
The equality easily follows from the previous computation using that . ∎
In particular the origin is a critical point of the functional if and only if .
Proposition 2.2.
Suppose that the origin is a critical point of . Then its Hessian matrix is the following:
Proof.
First observe that for any
Now, using the radial function of a convex body , the support function of its polar set, and the fact that we compute
Therefore
as claimed. The computation of the dual term
for any is similar. It remains to compute the mixed term as follows:
This completes the proof. ∎
Proposition 2.3.
Suppose that the origin is a critical point of . Then
Moreover
(2.1) |
As observed in the introduction, the first part of this statement implies Theorem 1.1. The second part will be useful in the last section.
Proof.
Just remark that if and are two symmetric positive definite matrices, and if we set
then being invertible the following holds true:
Since ,
3. Projective transformations and volume product
The purpose of this section is to show that the volume product on the space of projective images of a given convex body factors through the map . Therefore the functional captures all the relevant information about variational properties of the volume product on the space of projective images of a given convex body.
First recall some material about projective transformations (also called homographies). Consider the real projective space . We will make use of the projective coordinates for points in . Recall that a projective transformation is a diffeomorphism of induced by a linear isomorphism of as follows: given the induced projective transformation is
This allows to identify the group of projective transformations with the projective linear group and defines a natural topology on it. Here denotes the identity matrix. We will use the affine coordinate chart
where . Its inverse map is .
Given two nested open balls centered at the origin , we define the open subset of
where and refer to the closure and the interior respectively.
Proposition 3.1.
There exists an open neighbourhood of the identity in such that and we have and .
Proof.
Let us introduce the following local parametrization
Clearly is a diffeomorphism onto its image which is an open neighbourhood of the identity. We easily compute for any and every that
So if and only if , and the condition that amounts to the condition that . Now if the well-defined set is automatically a convex body, that contains the zero in its interior if and only if . Therefore the open set satisfies the conclusion of the proposition. ∎
Now we will reparametrize this open neighbourhood in order to show that the volume product of projective images of factors through the map .
Proposition 3.2.
There exists an open neighbourhood of in and a map such that , is a diffeomorphism onto its image, and the following holds:
for any convex body and for any .
Therefore, in order to study the variational properties of the volume product of projective images of a convex body , it is enough to study the associated functional .
Proof.
Consider the map
The map fixes points of the form for any , and there exists an open neighbourhood of in such that the restriction of to is a diffeomorphism onto its image whose inverse is . Then define the map
Because
while
we have that which implies that the restriction of to is a diffeomorphism onto its image. By construction . Still denote by the restriction of the map to . Now for any convex body and for any the following holds:
But for all
which implies using the invariance of the volume product by the linear group that
Now observe that
Indeed write . First while . By a straightforward computation it implies that .
It follows that as claimed. ∎
4. A family of critical pentagons
Fix two numbers and , and set and .
We consider the pentagon whose vertices are , and . By construction is symmetric with respect to the -axis:
![[Uncaptioned image]](https://cdn.awesomepapers.org/papers/af00085e-f3e6-4c65-9522-ae94ce42b10d/x1.png)
Lemma 4.1.
The dual of is .
Proof.
This is a direct consequence of the following general fact for convex polygons: a point is a vertex of if and only if the line contains a side of . In this way:
-
•
the line through and containing a side of corresponds to the vertex of ,
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•
the line through and containing a side of corresponds to the vertex of ,
-
•
the line through and containing a side of corresponds to the vertex of .
Therefore coincides with . ∎
By the previous lemma, if the barycenter of lies at the origin, the same holds for its dual , and thus is a critical point for the volume product on the space of projective images of .
The next lemma gives the exact condition on the pair which ensures that is such a critical point.
Lemma 4.2.
The barycenter of lies at the origin if and only if
Proof.
Since is symmetric, its barycenter lies on the -axis, and therefore only the abscissa of the barycenter is relevant. This coordinate can be computed by decomposing the pentagon into six pairwise symmetrical triangles, with one vertex at the origin and one common side with . The condition on the barycenter then becomes
Multiplying by and using that and gives the desired condition. ∎
As concrete examples of pairs such that is critical, i.e. solutions of the equation in Lemma 4.2, we can consider the following pairs:
-
•
the two pairs and at which the pentagon degenerates respectively into an equilateral triangle and its dual ,
-
•
the pair at which the pentagon is regular,
-
•
the remarkable pair which corresponds to a critical saddle point as we will show later.
In addition to these few simple concrete examples, the next lemma 4.3 shows that we have indeed a whole continuous family of critical pentagons .
Lemma 4.3.
The set
is the graph of a decreasing smooth function in the variable .
![[Uncaptioned image]](https://cdn.awesomepapers.org/papers/af00085e-f3e6-4c65-9522-ae94ce42b10d/x2.png)
As mentioned above, the extremal pentagons degenerate to equilateral triangles.
Proof.
According to the implicit function theorem, the result follows from elementary computations that both partial derivatives of the function are strictly positive on this domain, except at point where the first partial derivative is zero.
Indeed first observe that is a quadratic polynomial in the variable . One can check that its discriminant is always negative for , and zero at , by studying its first and second derivative.
Next we compute that and check through the study of that which is a polynomial of degree . A straightforward variational study of ensures its positivity on the desired domain. ∎
Now we explain how to compute the Hessian of the functional associated to some pentagon belonging the above family . For this, we must compute the inertia matrix and the area of such a pentagon. Since these quantities are additive with respect to disjoin union, we can perform these computations by decomposing the pentagon into triangles and using the following lemma.
Lemma 4.4.
The inertia matrix of a triangle with vertices , and is
where
and is twice the area of the triangle.
Proof.
Since we will not need the terms in what follows, we will only do the computations for , the case of being identical. An easy change of variables obtained by parametrizing our triangle by the triangle with vertices , and gives us
∎
By symmetry, the inertia matrix of such critical pentagon is diagonal so we only need to compute the terms and . By decomposing as before in six pairewise symmetrical triangles we get first that
(4.1) |
Using the same decomposition and Lemma 4.4 we derive that
(4.2) | ||||||||
(4.3) |
Hence is negative, and thus has a critical saddle point at the origin. This proves item ii) of Theorem 1.2.
To prove item iii) of Theorem 1.2, it will be enough to compute the derivative of at . First, at we have
On the other hand, one has and thus . Therefore, using the previous values,
Since , this shows that near , thus finishing the proof of Theorem 1.2.
![[Uncaptioned image]](https://cdn.awesomepapers.org/papers/af00085e-f3e6-4c65-9522-ae94ce42b10d/x3.png)
To complete the picture, we conclude with a numerical analysis of the whole family of critical pentagons .
The previous three lemmas (4.1, 4.2 and 4.3) tell us that for any we can compute with very high precision (at least using python with scipy) the unique such that is critical. Then all vertices are computed with precision at least , and therefore the polynomial function is calculated with precision at least to obtain the above curve, which is negative if as .
References
- [Klartag 2018] B. Klartag: Isotropic constants and Mahler volumes. Advances in Math. 330 (2018), 74-108.
- [Mahler 1939] K. Mahler: Ein Übertragungsprinzip für konvexe Körper. Casopis Pěst. Mat. Fys. 68 (1939), 93-102.
- [Santaló 1949] L. A. Santaló: Un invariante afín para los cuerpos convexos del espacio de n dimensiones. Portugaliae Math. 8 (1949), 155-161.