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Planar two-region multi-partite maximally entangled states

Yanwen Liang College of Physics, Hebei Key Laboratory of Photophysics Research and Application, Hebei Normal University, Shijiazhuang 050024, China    Fengli Yan [email protected] College of Physics, Hebei Key Laboratory of Photophysics Research and Application, Hebei Normal University, Shijiazhuang 050024, China    Ting Gao [email protected] School of Mathematical Sciences, Hebei Normal University, Shijiazhuang 050024, China
Abstract

In entanglement theory, there are different methods to consider one state being more entangled than another. The ”maximally” entangled states in a multipartite system can be defined from an axiomatic perspective. According to different criteria for selection, there are many specific types of quantum maximally entangled states, such as absolutely maximally entangled state, planar maximally entangled state and so on. In this paper we propose a new type of maximally entangled states, the planar two-region multipartite maximally entangled state. The requirement condition of this maximally entangled state is weak than that of the absolutely maximally entangled state and different from that of the planar maximally entangled state. We show that there are the two-region four-partite maximally entangled states in 4-qubit and 7-qubit planar systems, although there is no absolutely maximally entangled state in these systems. It is proved that there are the planar two-region four-partite maximally entangled states in both even particle quantum systems and odd particle quantum systems. Additionally, based on some planar two-region four-partite maximally entangled states, the new planar two-region four-partite maximally entangled states are generated. We also provide some important examples of the planar two-region multi-partite maximally entangled states.

pacs:
03.67.Mn, 03.65.Ud, 03.67.-a

I Introduction

Multipartite quantum entanglement Einstein ; Werner ; Horodecki is a distinctive feature of quantum mechanics and responsible for numerous practical tasks Nielsen . So quantum entanglement is an essential constituent part of quantum information and at the same time the subject of philosophical debates Horodecki . By far bipartite entangled states have been studied sufficiently, however the knowledge about multipartite states is far from perfect. From both a theoretical and practical perspective, multipartite entangled states are a very important resource in quantum information science.

It is well-known that the maximally entangled states (MES) play a very important role in practical quantum information processing. However, in fact there are different ways to consider one state to be more entangled than another. A method for defining ”maximally” entangled states in multipartite systems is based on an axiomatic approach. By using this method Gisin and Bechmann-Pasquinucci identify nn-qubit Greenberger-Horne-Zeilinger (GHZ) states as maximally entangled in nn-qubit systems Gisin . The reason for regarding these states as maximally entangled may be that GHZ states of nn qubits maximally violate the Bell-Klyshko inequalities Klyshko . Moreover, Chen proved that GHZ states in nn-qubit systems and the states obtained from them by local unitary transformations are the unique family of states which show such a maximal violation Chen . Recently, the absolutely maximally entangled (AME) states have been defined and discussed Helwig ; Raissi ; limaosheng . The characterization of AME states of an nn-particle quantum system is that any collection of n2\lfloor\frac{n}{2}\rfloor particles are in a maximally mixed state, where, \lfloor\cdot\rfloor is the floor function. Well-known examples are the Bell and GHZ states on two and three parties respectively. Obviously, the 4-qubit GHZ state is not a absolutely maximally entangled state.

According to different criteria 1 ; 2 ; 3 ; 4 ; 5 ; 6 , the maximally entangled states can be divided into multiple types 7 ; 8 ; 9 ; 10 ; 11 , such as the AME state and planar maximally entangled (PME) state. PME states have the property that any collection of n2\lfloor\frac{n}{2}\rfloor adjacent particles in a planar nn-particle quantum system are in a completely mixed state 26 . Various maximally entangled states can be applied to quantum parallel teleportation Helwig ; 12 ; 13 ; 14 ; 15 , quantum secret sharing 16 ; 17 ; 18 and so on.

AME states do not exist in all possible Hilbert spaces . It has been demonstrated that for any nn-particle system, when the dimension dd of the Hilbert space of the subsystem is chosen large enough, one can find the AME states; however, for low local dimensions there are severe constraints. The existence of AME states composed of two-level systems was recently solved. For qubit systems (dd=2), AME states do only exist for n=2,3,5n=2,3,5, and 6 parties, whereas it has been shown that no AME states exist for 4, 7, 8, and more than 8 qubits Helwig ; 20 ; 21 ; 22 ; Higuchi ; Scott ; FHuber .

Compared with AME state, the PME state is one with a lower number of constraints. Hence there are many more PME states than AME states, and the PME states are a wider class of entangled states than the AME states. The AME states are a subclass of PME states, that is, any AME state is a PME state, but the converse is not true 26 . Is there other class of maximally entangled states except the AME states and PME states? In this paper we solve this problem by proposing a new class of maximally entangled states, called the planar two-region multipartite maximally entangled states. In Sec. II, we investigate a special case, the planar two-region four-partite maximally entangled states. Then in Sec. III, we study the exactly definition of this kind of maximally entangled states and prove that there exists this kind of maximally entangled state. A summary with some remarks is provided in Sec. IV.

II Planar two-region four-partite maximally entangled state

It was shown that there exist various PME states for any even number of qudits, and there are two distinct multiparameter classes of four-qudit PMEs 26 . One may ask if it is possible to search for a wider class of entangled states except AME states and PME states.

In this section we will answer the above problem by defining the planar two-region four-partite maximally entangled state first. Then we will show that there is this kind of maximally entangled state.

Assume that the structure of the planar quantum system consisting of nn particles can be divided into two regions AA, BB, and each region has two disconnected parts. In the region AA, one part has kk adjacent particles, and the other part has n/2k\lfloor n/2\rfloor-k adjacent particles. At the same time we also require that one part of region BB has kk adjacent particles and the other part of the region BB has nn/2kn-\lfloor n/2\rfloor-k adjacent particles. As the two parts of region AA are not connected, so the only neighboring parts of each part of region AA are that of region BB. Evidently, for a given planar quantum system there can exist many structures. If a quantum state of the system satisfies that every subset of region AA in each possible quantum structure, is in a completely mixed state, then this state is called a planar two-region four-partite maximally entangled state, simply written as PKME(n,k,4,d)(n,k,4,d) state. Here dd is the dimension of the Hilbert space of single particle. Apparently, the requirement condition of this kind of maximally entangled state is weak than that of AME state and different from that of the planar maximally entangled state.

Next we will prove that there are PKME(n,k,4,d)(n,k,4,d) states for even nn and odd nn, respectively.

Suppose that a partition of nn particles of a quantum system is parted into parts AA and BB with |A||B||A|\leq|B|, then a pure state |Ψ|\Psi\rangle of the quantum system can be written as 26

|Ψ=𝐤|𝐤A|ϕ𝐤B.|\Psi\rangle=\sum_{\mathbf{k}}|\mathbf{k}\rangle_{A}|\phi_{\mathbf{k}}\rangle_{B}. (1)

So the density matrix of part AA is

ρA=𝐤,𝐤|𝐤A𝐤|ϕ𝐤|ϕ𝐤B.\rho_{A}=\sum_{\mathbf{k,k^{\prime}}}|\mathbf{k}\rangle_{A}\langle\mathbf{k^{\prime}}|\langle\phi_{\mathbf{k}}|\phi_{\mathbf{k^{\prime}}}\rangle_{B}. (2)

For ρA\rho_{A} to be the completely mixed state IAI_{A}, it is necessary to demand that the states {|ϕ𝐤}\{|\phi_{\mathbf{k}}\rangle\} are orthogonal and with equal norm, and the states {|𝐤}\{|\mathbf{k}\rangle\} form a basis for the Hilbert space of the part AA 26 .

II.1 PKME(n,k,4,d)(n,k,4,d) states in a quantum system consisting of even number of particles

II.1.1 PKME(4k,k,4,d)(4k,k,4,d) state in a 4kk-qudit planar system

We start from a special case, in which there are 4k4k qudits in a planar system, where kk is a positive integer. This planar 4k4k-qudit system is depicted in figure 1.

Refer to caption
Figure 1: The structure of the planar 4k4k-qudit quantum system.

It is easy to see that there are 2k2k quantum structures satisfying the requirements of the PKME(4k,k,4,d)(4k,k,4,d) state. That is, there exist 2k2k particle distributions satisfying that region AA consists of two nonadjacent parts A1A_{1} and A2A_{2}, region BB consists of two nonadjacent parts B1B_{1} and B2B_{2}, and each of A1A_{1}, A2A_{2}, B1B_{1} and B2B_{2}, has kk adjacent particles.

One can deduce that a state in a Hilbert space (Cd)4k(C^{d})^{\bigotimes 4k} of 4k4k qudits,

|Ψ=1dki1,i2,,i2k=0d|i1,i2,,ik,i1,i2,,ik,ik+1,,i2k,ik+1,,i2k\displaystyle|\Psi\rangle=\frac{1}{d^{k}}\sum_{i_{1},i_{2},\cdots,i_{2k}=0}^{d}|i_{1},i_{2},\cdots,i_{k},i_{1},i_{2},\cdots,i_{k},i_{k+1},\cdots,i_{2k},i_{k+1},\cdots,i_{2k}\rangle (3)

is a PKME(4k,k,4,d)(4k,k,4,d) state, where CdC^{d} denotes a dd-dimensional complex space. Figure 2 shows the corresponding state structure.

Refer to caption
Figure 2: A PKME(4k,k,4,d4k,k,4,d) state of the planar 4k4k-qudit system, where both the 1st particle and the (k+1)(k+1)th particle are red, \cdots, both the kkth particle and the 2k2kth particle are green, \cdots, both the (2k+1)(2k+1)th particle and the (3k+1)(3k+1)th particle are blue, \cdots, and the 3k3kth and 4k4kth particles are both yellow. Here the same color represents the same state.

Therefore, there exists the PKME(4k,k,4,d)(4k,k,4,d) state of a planar 4k4k-qudit system.

II.1.2 The family of PKME(4,1,4,2)(4,1,4,2) states of a 4-qubit planar system

Let us consider a 4-qubit quantum system. The qubits are numbered as {1,2,3,4}\{1,2,3,4\} respectively. Clearly, there are two quantum structures in this system, which are

{A={A1=1,A2=3},B={B1=2,B2=4}},\{A=\{A_{1}=1,A_{2}=3\},B=\{B_{1}=2,B_{2}=4\}\},
{A={A1=2,A2=4},B={B1=1,B2=3}},\{A=\{A_{1}=2,A_{2}=4\},B=\{B_{1}=1,B_{2}=3\}\},

and kk can only be 1. Next we will give the family of the PKME(4,1,4,2)(4,1,4,2) states.

The state of the 4-qubit planar system can be expressed as

|Ψ=12i,j,k,l=01αi,j,k,l|i,j,k,l.\displaystyle|\Psi\rangle=\frac{1}{2}\sum_{i,j,k,l=0}^{1}\alpha_{i,j,k,l}|i,j,k,l\rangle. (4)

Then it can be written as

|Ψ13,24=12(|00|Y00+|01|Y01+|10|Y10+|11|Y11)13,24,\displaystyle|\Psi\rangle_{13,24}=\frac{1}{2}(|00\rangle|Y_{00}\rangle+|01\rangle|Y_{01}\rangle+|10\rangle|Y_{10}\rangle+|11\rangle|Y_{11}\rangle)_{13,24}, (5)

where

|00|Y00=α0000|0000+α0001|0001+α0010|0010+α0011|0011,\displaystyle|00\rangle|Y_{00}\rangle=\alpha_{0000}|0000\rangle+\alpha_{0001}|0001\rangle+\alpha_{0010}|0010\rangle+\alpha_{0011}|0011\rangle\text{,} (6)
|01|Y01=α0100|0100+α0101|0101+α0110|0110+α0111|0111,\displaystyle|01\rangle|Y_{01}\rangle=\alpha_{0100}|0100\rangle+\alpha_{0101}|0101\rangle+\alpha_{0110}|0110\rangle+\alpha_{0111}|0111\rangle\text{,}
|10|Y10=α1000|1000+α1001|1001+α1010|1010+α1011|1011,\displaystyle|10\rangle|Y_{10}\rangle=\alpha_{1000}|1000\rangle+\alpha_{1001}|1001\rangle+\alpha_{1010}|1010\rangle+\alpha_{1011}|1011\rangle\text{,}
|11|Y11=α1100|1100+α1101|1101+α1110|1110+α1111|1111.\displaystyle|11\rangle|Y_{11}\rangle=\alpha_{1100}|1100\rangle+\alpha_{1101}|1101\rangle+\alpha_{1110}|1110\rangle+\alpha_{1111}|1111\rangle\text{.}

According to the generalized Schmidt decomposition of multipartite quantum states Carteret , one can always take

α0001=α0010=α0100=α1000=0\alpha_{0001}=\alpha_{0010}=\alpha_{0100}=\alpha_{1000}=0 (7)

by choosing a suitable basis. Thus we have

|Y00=α0000|00+α0011|11,\displaystyle|Y_{00}\rangle=\alpha_{0000}|00\rangle+\alpha_{0011}|11\rangle\text{,} (8)
|Y01=α0101|01+α0110|10+α0111|11,\displaystyle|Y_{01}\rangle=\alpha_{0101}|01\rangle+\alpha_{0110}|10\rangle+\alpha_{0111}|11\rangle\text{,}
|Y10=α1001|01+α1010|10+α1011|11,\displaystyle|Y_{10}\rangle=\alpha_{1001}|01\rangle+\alpha_{1010}|10\rangle+\alpha_{1011}|11\rangle\text{,}
|Y11=α1100|00+α1101|01+α1110|10+α1111|11.\displaystyle|Y_{11}\rangle=\alpha_{1100}|00\rangle+\alpha_{1101}|01\rangle+\alpha_{1110}|10\rangle+\alpha_{1111}|11\rangle\text{.}

Obviously, if and only if Yik|Yjl=δijδkl\langle Y_{ik}|Y_{jl}\rangle=\delta_{ij}\delta_{kl}, quantum state |Ψ13,24|\Psi\rangle_{13,24} can satisfy ρ13=I\rho_{13}=I. As a matter of fact Yik|Yjl=δijδkl\langle Y_{ik}|Y_{jl}\rangle=\delta_{ij}\delta_{kl} implies that the matrix

V=(α000000α11000α0101α1001α11010α0110α1010α1110α0011α0111α1011α1111)(a00b0cef0ghpqrwy)V=\begin{pmatrix}\alpha_{0000}&0&0&\alpha_{1100}\\ 0&\alpha_{0101}&\alpha_{1001}&\alpha_{1101}\\ 0&\alpha_{0110}&\alpha_{1010}&\alpha_{1110}\\ \alpha_{0011}&\alpha_{0111}&\alpha_{1011}&\alpha_{1111}\\ \end{pmatrix}\equiv\begin{pmatrix}a&0&0&b\\ 0&c&e&f\\ 0&g&h&p\\ q&r&w&y\\ \end{pmatrix} (9)

is a unitary matrix.

It is well-known that a unitary matrix has the properties: (a) Two different rows (columns) are orthogonal; (b) If there is an element whose magnitude is unit module, then all the other elements in the row and column are all 0 except for this element; (c) There is phase freedom globally.

Using the orthogonality of the first, second and third rows, one can obtain

bf=bp=0.bf=bp=0. (10)

The solutions of above equation can be divided the following two cases.

(i) b=0b=0. In this case, one must have |a|=1|a|=1 and q=0q=0. Without loss of generality, we can choose a=1a=1, which means α0000=1\alpha_{0000}=1. Then the matrix VV becomes

(10000cef0ghp0rwy),\begin{pmatrix}1&0&0&0\\ 0&c&e&f\\ 0&g&h&p\\ 0&r&w&y\\ \end{pmatrix}, (11)

where the matrix (cefghprwy)\begin{pmatrix}c&e&f\\ g&h&p\\ r&w&y\\ \end{pmatrix} is a 3×33\times 3 unitary matrix.

Therefore the quantum state can be expressed as

|Ψ13,24=\displaystyle|\Psi^{\prime}\rangle_{13,24}= 12(|0000+c|0101+g|0110+r|0111+e|1001+h|1010\displaystyle\frac{1}{2}(|0000\rangle+c|0101\rangle+g|0110\rangle+r|0111\rangle+e|1001\rangle+h|1010\rangle (12)
+w|1011+f|1101+p|1110+y|1111).\displaystyle+w|1011\rangle+f|1101\rangle+p|1110\rangle+y|1111\rangle).

It is easy to deduce that ρ24=I\rho_{24}=I. Hence, the quantum state |Ψ13,24|\Psi^{\prime}\rangle_{13,24} is a family of PKME(4, 1, 4, 2) states of 4-qubit planar system.

(ii) b0b\neq 0. In this case we can obtain f=p=0f=p=0 by Eq.(10). Similarly, we get r=w=0r=w=0 by using the orthogonality of the first, second and third columns. Thus the matrix VV reads

(a00b0ce00gh0q00y).\begin{pmatrix}a&0&0&b\\ 0&c&e&0\\ 0&g&h&0\\ q&0&0&y\\ \end{pmatrix}. (13)

Evidently, if and only if the inner matrix (cegh)\begin{pmatrix}c&e\\ g&h\ \end{pmatrix} and outer matrix (abqy)\begin{pmatrix}a&b\\ q&y\\ \end{pmatrix} are 2×22\times 2 unitary matrices, then the matrix VV is a unitary matrix.

Hence in this case we have

|Ψ"13,24=\displaystyle|\Psi"\rangle_{13,24}= 12{a|0000+q|0011+b|1100+y|1111\displaystyle\frac{1}{2}\{a|0000\rangle+q|0011\rangle+b|1100\rangle+y|1111\rangle (14)
+c|0101+g|0110+e|1001+h|1010}.\displaystyle+c|0101\rangle+g|0110\rangle+e|1001\rangle+h|1010\rangle\}.

One can also derive that ρ24=I\rho_{24}=I. Therefore |Ψ"13,24|\Psi"\rangle_{13,24} is a PKME(4,1,4,2) state of a 4-qubit planar system, if (cegh)\begin{pmatrix}c&e\\ g&h\\ \end{pmatrix} and outer matrix (abqy)\begin{pmatrix}a&b\\ q&y\\ \end{pmatrix} are 2×22\times 2 unitary matrices.

We use {|Ψ0}\{|\Psi_{0}\rangle\} to denote the intersection set of {|Ψ13,24}\{|\Psi^{\prime}\rangle_{13,24}\} and {|Ψ"13,24}\{|\Psi"\rangle_{13,24}\}. Obviously, one has

|Ψ013,24\displaystyle|\Psi_{0}\rangle_{13,24} =12(|0000+c|0101+g|0110+e|1001+h|1010+|1111),\displaystyle=\frac{1}{2}(|0000\rangle+c|0101\rangle+g|0110\rangle+e|1001\rangle+h|1010\rangle+|1111\rangle), (15)

where (cegh)\begin{pmatrix}c&e\\ g&h\\ \end{pmatrix} is a 2×22\times 2 unitary matrix. Of course, the union {|Ψ13,24}{|Ψ"13,24}\{|\Psi^{\prime}\rangle_{13,24}\}\bigcup\{|\Psi"\rangle_{13,24}\} consists of all PKME(4, 1, 4,2) states of a 4-qubit planar system. So there are PKME(4,1,4,2) states of the 4-qubit planar system, although there is no AME state of 4-qubit system.

Additionally, here we provide an example of PKME state of a 6-qubit planar system. The qubits are denoted as 1,2,3,4,5,6 in a planar circle. Clearly, there are 12 quantum structures

{A1={1},A2={3,4};B1={2},B2={5,6}},\{A_{1}=\{1\},A_{2}=\{3,4\};B_{1}=\{2\},B_{2}=\{5,6\}\},
{A1={1},A2={4,5};B1={6},B2={2,3}},\{A_{1}=\{1\},A_{2}=\{4,5\};B_{1}=\{6\},B_{2}=\{2,3\}\},
{A1={2},A2={4,5};B1={3},B2={1,6}},\{A_{1}=\{2\},A_{2}=\{4,5\};B_{1}=\{3\},B_{2}=\{1,6\}\},
{A1={2},A2={5,6};B1={1},B2={3,4}},\{A_{1}=\{2\},A_{2}=\{5,6\};B_{1}=\{1\},B_{2}=\{3,4\}\},
{A1={3},A2={5,6};B1={4},B2={1,2}},\{A_{1}=\{3\},A_{2}=\{5,6\};B_{1}=\{4\},B_{2}=\{1,2\}\},
{A1={3},A2={1,6};B1={2},B2={4,5}},\{A_{1}=\{3\},A_{2}=\{1,6\};B_{1}=\{2\},B_{2}=\{4,5\}\},
{A1={4},A2={1,6};B1={5},B2={2,3}},\{A_{1}=\{4\},A_{2}=\{1,6\};B_{1}=\{5\},B_{2}=\{2,3\}\},
{A1={4},A2={1,2};B1={3},B2={5,6}},\{A_{1}=\{4\},A_{2}=\{1,2\};B_{1}=\{3\},B_{2}=\{5,6\}\},
{A1={5},A2={1,2};B1={6},B2={3,4}},\{A_{1}=\{5\},A_{2}=\{1,2\};B_{1}=\{6\},B_{2}=\{3,4\}\},
{A1={5},A2={2,3};B1={4},B2={1,6}},\{A_{1}=\{5\},A_{2}=\{2,3\};B_{1}=\{4\},B_{2}=\{1,6\}\},
{A1={6},A2={2,3};B1={1},B2={4,5}},\{A_{1}=\{6\},A_{2}=\{2,3\};B_{1}=\{1\},B_{2}=\{4,5\}\},
{A1={6},A2={3,4};B1={5},B2={1,2}}.\{A_{1}=\{6\},A_{2}=\{3,4\};B_{1}=\{5\},B_{2}=\{1,2\}\}.

One can easily check that a quantum state in a Hilbert space (C2)6(C^{2})^{\bigotimes 6}

|Ψ=122i,j,l=01|i,ij,j,l,jl,ijl123456\displaystyle|\Psi\rangle=\frac{1}{2\sqrt{2}}\sum_{i,j,l=0}^{1}|i,i\oplus j,j,l,j\oplus l,i\oplus j\oplus l\rangle_{123456} (16)

is a PKME(6,1,4,2) state, where k=1k=1.

II.1.3 The constructed PKME states of the quantum systems with even number of particles

Suppose that |Φ+|\Phi^{+}\rangle is a PKME(4k,k,4,d)(4k,k,4,d) state of a 4k4k-qudit quantum system. We can construct a more complicated PKME(4k,k,4,d)(4k,k,4,d) state by using the controlled operators {Λs,t(U)}\{\Lambda_{s,t}(U)\}. Here ss and tt represent the control site and target site respectively, UU is a unitary matrix acting on the tt-th qudit 30 . That is

Λs,t(U)|is|jt|is|U(i,j)t.\displaystyle\Lambda_{s,t}(U)|i\rangle_{s}|j\rangle_{t}\equiv|i\rangle_{s}|U(i,j)\rangle_{t}. (17)

Evidently,

|Ψ=Λk+1,k+2(U1)Λ2k,3k+1(Uk)Λ4k1,4k(U2k1)|Φ+\displaystyle|\Psi\rangle=\Lambda_{k+1,k+2}(U_{1})\cdots\Lambda_{2k,3k+1}(U_{k})\cdots\Lambda_{4k-1,4k}(U_{2k-1})|\Phi^{+}\rangle (18)

is also a PKME(4k,k,4,d)(4k,k,4,d) state of a 4k4k-qudit planar quantum system.

For example, from an 8-qudit PKME(8,2,4,d)(8,2,4,d) state

|Φ+=1d2i,j,l,m=0d1|i,j,i,j,l,m,l,m1,2,3,4,5,6,7,8,\displaystyle|\Phi^{+}\rangle=\frac{1}{d^{2}}\sum_{i,j,l,m=0}^{d-1}|i,j,i,j,l,m,l,m\rangle_{1,2,3,4,5,6,7,8}, (19)

one can make another PKME(8,2,4,d)(8,2,4,d) state

|Ψ\displaystyle|\Psi\rangle =Λ3,4(U1)Λ4,7(U2)Λ7,8(U3)|Φ+\displaystyle=\Lambda_{3,4}(U_{1})\Lambda_{4,7}(U_{2})\Lambda_{7,8}(U_{3})|\Phi^{+}\rangle (20)
=1d2i,j,l,m=0d1|i,j,i,U1(i,j),l,m,U2(j,l),U3(l,m)1,2,3,4,5,6,7,8,\displaystyle=\frac{1}{d^{2}}\sum_{i,j,l,m=0}^{d-1}|i,j,i,U_{1}(i,j),l,m,U_{2}(j,l),U_{3}(l,m)\rangle_{1,2,3,4,5,6,7,8},

where states |U(i,j)|U(i,j)\rangle must satisfy U(i,j)|U(i,j)=δjj\langle U(i,j)|U(i,j^{\prime})\rangle=\delta_{jj^{\prime}}. Figure 3 shows that when the input state is |Φ+|\Phi^{+}\rangle state, namely an 8-qudit PKME(8,2,4,d)(8,2,4,d) state, then the output state is also a PKME(8,2,4,d)(8,2,4,d).

Refer to caption
Figure 3: The constructed PKME(8,2,4,dd) state in an 8-qudit quantum system. The input state in the left is the quantum state in Eq.(19), and the output state in the right is the quantum state in Eq.(20).

By changing the order of action of the controlled operator Λs,t(U)\Lambda_{s,t}(U) in Eq.(18), we can construct another PKME(8,2,4,d)(8,2,4,d) state

|Ψ=Λ4k1,4k(U2k1)Λ2k,3k+1(Uk)Λk+1,k+2(U1)|Φ+.\displaystyle|\Psi\rangle=\Lambda_{4k-1,4k}(U_{2k-1})\cdots\Lambda_{2k,3k+1}(U_{k})\cdots\Lambda_{k+1,k+2}(U_{1})|\Phi^{+}\rangle. (21)

The difference between Eq. (18) and Eq. (21) is the order of action of the controlled operators Λs,t(U)\Lambda_{s,t}(U). By using state in Eq. (19), a new PKME(8,2,4,d)(8,2,4,d) state of an 8-qudit planar quantum system is

|Ψ\displaystyle|\Psi\rangle =Λ7,8(U3)Λ4,7(U2)Λ3,4(U1)|Φ+\displaystyle=\Lambda_{7,8}(U_{3})\Lambda_{4,7}(U_{2})\Lambda_{3,4}(U_{1})|\Phi^{+}\rangle (22)
=1d2i,j,l,m=0d1|i,j,i,U1(i,j),l,m,U2(U1(i,j),l),U3(U2(U1(i,j),l),m)1,2,3,4,5,6,7,8,\displaystyle=\frac{1}{d^{2}}\sum_{i,j,l,m=0}^{d-1}|i,j,i,U_{1}(i,j),l,m,U_{2}(U_{1}(i,j),l),U_{3}(U_{2}(U_{1}(i,j),l),m)\rangle_{1,2,3,4,5,6,7,8},

which is illustrated in figure 4.

Refer to caption
Figure 4: A new PKME(8,2,4,d)(8,2,4,d) state of an 8-qudit quantum system.

II.1.4 PKME(4k+1,k,4,2)(4k+1,k,4,2) state of the 4k+14k+1 particle system

Let us first consider a special case k=1k=1, i.e., a 5-qubit quantum system. Five qubits in a planar circle system are numbered as 1,2,3,4,5, respectively. It is not difficult to check that the quantum state

|Ψ=12i,j=01|i,i,j,j,ij1,2,3,4,5\displaystyle|\Psi\rangle=\frac{1}{2}\sum_{i,j=0}^{1}|i,i,j,j,i\oplus j\rangle_{1,2,3,4,5} (23)

is a PKME(5,1,4,2)(5,1,4,2) state. Here there are 5 quantum structures

{A1={1},A2={3};B1={2},B2={4,5}},\{A_{1}=\{1\},A_{2}=\{3\};B_{1}=\{2\},B_{2}=\{4,5\}\},
{A1={1},A2={4};B1={5},B2={2,3}},\{A_{1}=\{1\},A_{2}=\{4\};B_{1}=\{5\},B_{2}=\{2,3\}\},
{A1={2},A2={4};B1={3},B2={1,5}},\{A_{1}=\{2\},A_{2}=\{4\};B_{1}=\{3\},B_{2}=\{1,5\}\},
{A1={2},A2={5};B1={1},B2={3,4}},\{A_{1}=\{2\},A_{2}=\{5\};B_{1}=\{1\},B_{2}=\{3,4\}\},
{A1={3},A2={5};B1={4},B2={1,2}}.\{A_{1}=\{3\},A_{2}=\{5\};B_{1}=\{4\},B_{2}=\{1,2\}\}.

Therefore, there exist PKME(n,k,4,d)(n,k,4,d) states of the planar quantum system with odd-particles.

Now we consider the generalized case, a (4k+1)(4k+1)-qubit planar system in a circle, where k1k\geq 1 is an arbitrary positive integer. Each quantum structure consists of four parts {A1,A2,B1,B2}\{A_{1},A_{2},B_{1},B_{2}\}. Here A1A_{1}, A2A_{2}, B1B_{1}, and B2B_{2} contain kk, kk, kk, and k+1k+1 neighboring particles, respectively; region AA is composed of parts A1A_{1} and A2A_{2}, region BB is composed of parts B1B_{1} and B2B_{2}, as shown in figure 5. Clearly, there are 4k+14k+1 quantum structures in this planar system.

Refer to caption
Figure 5: Planar 4k+14k+1-qubit quantum system.

A quantum state in a Hilbert space (C2)4k+1(C^{2})^{\bigotimes 4k+1} of the 4k+14k+1 qubits

|Ψ=\displaystyle|\Psi\rangle= 12ki1,i2,,i2k=01|i11|i22|ikk|i1k+1|i2k+2|ik2k\displaystyle\frac{1}{2^{k}}\sum_{i_{1},i_{2},\cdots,i_{2k}=0}^{1}|i_{1}\rangle_{1}|i_{2}\rangle_{2}\cdots|i_{k}\rangle_{k}|i_{1}\rangle_{k+1}|i_{2}\rangle_{k+2}\cdots|i_{k}\rangle_{2k} (24)
|ik+12k+1|ik+22k+2|i2k3k|ik+13k+1|ik+23k+2|i2k4k|i1i2i2k4k+1\displaystyle|i_{k+1}\rangle_{2k+1}|i_{k+2}\rangle_{2k+2}\cdots|i_{2k}\rangle_{3k}|i_{k+1}\rangle_{3k+1}|i_{k+2}\rangle_{3k+2}\cdots|i_{2k}\rangle_{4k}|i_{1}\oplus i_{2}\oplus\cdots\oplus i_{2k}\rangle_{4k+1}

is a PKME(4k+1,k,4,2)(4k+1,k,4,2) state, which is plotted in figure 6.

Refer to caption
Figure 6: The quantum state of the planar (4k+1)(4k+1)-qubit quantum system in Eq.(24). The 1st particle and the k+1k+1th particle are red, the kkth particle and the 2k2kth particle are yellow, the 2k+12k+1th particle and the 3k+13k+1th particle are green, the 3k3kth particle and the 4k4kth particle are blue, and the (4k+1)(4k+1)th particle is purple. Here different colors represent different states.

II.1.5 Constructed PKME(4k+1,k,4,d)(4k+1,k,4,d) state of a quantum system with odd number of particles

Suppose that |Φ+|\Phi^{+}\rangle state is a PKME(4k+1,k,4,d)(4k+1,k,4,d) state of a (4k+1)(4k+1)-qudit quantum system. One can generate a new PKME(4k+1,k,4,d)(4k+1,k,4,d) state

|Ψ=Λk+1,k+2(U1)Λ2k,3k+1(Uk)Λ4k,4k+1(U2k)|Φ+.\displaystyle|\Psi\rangle=\Lambda_{k+1,k+2}(U_{1})\cdots\Lambda_{2k,3k+1}(U_{k})\cdots\Lambda_{4k,4k+1}(U_{2k})|\Phi^{+}\rangle. (25)

For example, one can use a 5-qubit PKME(5,1,4,d)(5,1,4,d) state

|Φ+=1di,j=0d1|i,i,j,j,ij1,2,3,4,5\displaystyle|\Phi^{+}\rangle=\frac{1}{d}\sum_{i,j=0}^{d-1}|i,i,j,j,i\oplus j\rangle_{1,2,3,4,5} (26)

to construct another PKME(5,1,4,d)(5,1,4,d) state

|Ψ\displaystyle|\Psi\rangle =Λ2,4(U1)Λ4,5(U2)|Φ+\displaystyle=\Lambda_{2,4}(U_{1})\Lambda_{4,5}(U_{2})|\Phi^{+}\rangle (27)
=1di,j=0d1|i,i,j,U1(i,j),U2(j,ij)1,2,3,4,5,\displaystyle=\frac{1}{d}\sum_{i,j=0}^{d-1}|i,i,j,U_{1}(i,j),U_{2}(j,i\oplus j)\rangle_{1,2,3,4,5},

as depicted in figure 7, where d=2d=2 and the |U(i,j)|U(i,j)\rangle state satisfies U(i,j)|U(i,j)=δiiδjj=δjj\langle U(i,j)|U(i,j^{\prime})\rangle=\delta_{ii}\delta_{jj^{\prime}}=\delta_{jj^{\prime}}.

Refer to caption
Figure 7: The constructed PKME state in a 5-qubit quantum system. The input state in the left is a state (26), and the output state in the right is the state (27). Here d=2d=2.

By changing the order of action of the controlled operators {Λs,t(U)}\{\Lambda_{s,t}(U)\} in Eq.(25) we can construct another PKME(4k+1,k,4,d)(4k+1,k,4,d) state

|Ψ=Λ4k,4k+1(U2k)Λ2k,3k+1(Uk)Λk+1,k+2(U1)|Φ+.\displaystyle|\Psi\rangle=\Lambda_{4k,4k+1}(U_{2k})\cdots\Lambda_{2k,3k+1}(U_{k})\cdots\Lambda_{k+1,k+2}(U_{1})|\Phi^{+}\rangle. (28)

The difference between this state and the state stated by Eq.(25) is only the order of action of the controlled operator {Λs,t(U)}\{\Lambda_{s,t}(U)\}. Taking state in Eq.(26) as an example, the new PKME(5,1,4,d)(5,1,4,d) state of this 5-qubit system reads

|Ψ\displaystyle|\Psi\rangle =Λ4,5(U2)Λ2,4(U1)|Φ+\displaystyle=\Lambda_{4,5}(U_{2})\Lambda_{2,4}(U_{1})|\Phi^{+}\rangle (29)
=1di,j=0d1|i,i,j,U1(i,j),U2(U1(i,j),ij)1,2,3,4,5,\displaystyle=\frac{1}{d}\sum_{i,j=0}^{d-1}|i,i,j,U_{1}(i,j),U_{2}(U_{1}(i,j),i\oplus j)\rangle_{1,2,3,4,5},

which is illustrated in figure 8. Here d=2d=2.

Refer to caption
Figure 8: Another constructed PKME state of a 5-qudit quantum system. Here d=2d=2, and the input state in the left is the quantum state (26), and the output state in the right is the state (29).

II.1.6 PKME(7,2,4,2) state

Let us consider a 7-qubit quantum system. There are 7 quantum structures

{A1={1,2},A2={5};B1={3,4},B2={6,7}},\{A_{1}=\{1,2\},A_{2}=\{5\};B_{1}=\{3,4\},B_{2}=\{6,7\}\},
{A1={2,3},A2={6};B1={4,5},B2={1,7}},\{A_{1}=\{2,3\},A_{2}=\{6\};B_{1}=\{4,5\},B_{2}=\{1,7\}\},
{A1={3,4},A2={7};B1={5,6},B2={1,2}},\{A_{1}=\{3,4\},A_{2}=\{7\};B_{1}=\{5,6\},B_{2}=\{1,2\}\},
{A1={4,5},A2={1};B1={6,7},B2={2,3}},\{A_{1}=\{4,5\},A_{2}=\{1\};B_{1}=\{6,7\},B_{2}=\{2,3\}\},
{A1={5,6},A2={2};B1={1,7},B2={3,4}},\{A_{1}=\{5,6\},A_{2}=\{2\};B_{1}=\{1,7\},B_{2}=\{3,4\}\},
{A1={6,7},A2={3};B1={1,2},B2={4,5}},\{A_{1}=\{6,7\},A_{2}=\{3\};B_{1}=\{1,2\},B_{2}=\{4,5\}\},
{A1={1,7},A2={4};B1={2,3},B2={5,6}}.\{A_{1}=\{1,7\},A_{2}=\{4\};B_{1}=\{2,3\},B_{2}=\{5,6\}\}.

It is easy to prove that a quantum state in a Hilbert space (C2)7(C^{2})^{\bigotimes 7} of 7-qubit system

|Ψ=122i,j,l=01|i,j,l,j,l,i,ijl1,2,3,4,5,6,7\displaystyle|\Psi\rangle=\frac{1}{2\sqrt{2}}\sum_{i,j,l=0}^{1}|i,j,l,j,l,i,i\oplus j\oplus l\rangle_{1,2,3,4,5,6,7} (30)

is a PKME(7,2,4,2) state. However, AME state of seven qubits do not exist.

III Planar two-region multi-partite maximally entangled state

In this section, we will generalize the definition of two-region four-partite maximally entangled state to the more generalized case. That is we will define two-region multi-partite maximally entangled state and prove that this kind of maximally entangled states do exist.

Consider a quantum system composed of nn particles in a planar circle, where the Hilbert space of each particle is a dd-dimensional complex space CdC^{d}. Suppose that one can divide the nn particles into two-region {A,B}\{A,B\}, where AA (BB) consists of parts {A1,A2,,Am}\{A_{1},A_{2},\cdots,A_{m}\} ({B1,B2,,Bm}\{B_{1},B_{2},\cdots,B_{m}\}), and the particles in each part are adjacent, however A1,A2,,AmA_{1},A_{2},\cdots,A_{m} are not neighbors, so do B1,B2,,BmB_{1},B_{2},\cdots,B_{m}. Each {A1,A2,,AmB1,B2,,Bm}\{A_{1},A_{2},\cdots,A_{m}\,B_{1},B_{2},\cdots,B_{m}\} is called a quantum structure. We also demand that region AA contains n/2\lfloor n/2\rfloor particles, region BB consists of nn/2n-\lfloor n/2\rfloor particles. We use kA1,kA2,,kAm,kB1,kB2,,kBmk_{A_{1}},k_{A_{2}},\cdots,k_{A_{m}},k_{B_{1}},k_{B_{2}},\cdots,k_{B_{m}} to denote the corresponding particle numbers of parts A1,A2,,Am,B1,B2,,BmA_{1},A_{2},\cdots,A_{m},B_{1},B_{2},\cdots,B_{m} respectively. Here 2mn,4n2m\leq n,4\leq n, |A||B||A|\leq|B|. Obviously, for an nn particle system and fixed kA1,kA2,,kAm,kB1,kB2,,kBmk_{A_{1}},k_{A_{2}},\cdots,k_{A_{m}},k_{B_{1}},k_{B_{2}},\cdots,k_{B_{m}} there are many quantum structures.

If a quantum state in the Hilbert space (Cd)n(C^{d})^{\bigotimes n} of the nn-particle system satisfies that every subset of region AA in each possible quantum structure, is in a completely mixed state, then this state is called a planar two-region multi-partite maximally entangled state, simply written as PKME(n,{z},2m,d)(n,\{z\},2m,d) state. Here dd is the dimension of the Hilbert space of single particle and {z}={kA1,kA2,,kAm,kB1,kB2,,kBm}\{z\}=\{k_{A_{1}},k_{A_{2}},\cdots,k_{A_{m}},k_{B_{1}},k_{B_{2}},\cdots,k_{B_{m}}\}.

Clearly, the requirement condition of PKME states is weak than that of the absolutely maximally entangled state and different from that of the planar maximally entangled state.

Next we will give two examples of the planar two-region multi-partite maximally entangled states.

Example 1. Consider a 2mk2mk-qubit system. It is easy to demonstrate that the quantum state in Hilbert space (C2)2mk(C^{2})^{\bigotimes 2mk}

|Ψ=\displaystyle|\Psi\rangle= 12mk2i1,i2,,imk=01|i11|ikk|i1k+1|ik2k|ik+12k+1|i2k3k|ik+13k+1|i2k4k\displaystyle\frac{1}{2^{\frac{mk}{2}}}\sum_{i_{1},i_{2},\ldots,i_{mk}=0}^{1}|i_{1}\rangle_{1}\cdots|i_{k}\rangle_{k}|i_{1}\rangle_{k+1}\cdots|i_{k}\rangle_{2k}|i_{k+1}\rangle_{2k+1}\cdots|i_{2k}\rangle_{3k}|i_{k+1}\rangle_{3k+1}\cdots|i_{2k}\rangle_{4k}\cdots (31)
|i(m1)k+1(2m2)k+1|imk(2m1)k|i(m1)k+1(2m1)k+1|imk2mk\displaystyle|i_{(m-1)k+1}\rangle_{(2m-2)k+1}\cdots|i_{mk}\rangle_{(2m-1)k}|i_{(m-1)k+1}\rangle_{(2m-1)k+1}\cdots|i_{mk}\rangle_{2mk}

is a PKME(2mk,{z},m,2)(2mk,\{z\},m,2) state, with {z}={kA1,kA2,,kAm,kB1,kB2,,kBm|kA1=kA2==kAm=kB1=kB2=kBm=k}\{z\}=\{k_{A_{1}},k_{A_{2}},\cdots,k_{A_{m}},k_{B_{1}},k_{B_{2}},\cdots,k_{B_{m}}|k_{A_{1}}=k_{A_{2}}=\cdots=k_{A_{m}}=k_{B_{1}}=k_{B_{2}}=k_{B_{m}}=k\}.

Therefore, there exists the planar two-region multi-partite maximally entangled state of the planar 2mk2mk-qubit system, where both kk and mm are positive integers larger than or equal to 1.

Example 2. Assume mm, kk are positive integers larger than or equal to 1. Let us consider a 2mk+12mk+1 qubit system. One can verify that a quantum state in the Hilbert space (C2)2mk+1(C^{2})^{\bigotimes 2mk+1}

|Ψ=\displaystyle|\Psi\rangle= 12mk2i1,i2,,imk=01|i11|ikk|i1k+1|ik2k|ik+12k+1|i2k3k|ik+13k+1|i2k4k\displaystyle\frac{1}{2^{\frac{mk}{2}}}\sum_{i_{1},i_{2},\ldots,i_{mk}=0}^{1}|i_{1}\rangle_{1}\cdots|i_{k}\rangle_{k}|i_{1}\rangle_{k+1}\cdots|i_{k}\rangle_{2k}|i_{k+1}\rangle_{2k+1}\cdots|i_{2k}\rangle_{3k}|i_{k+1}\rangle_{3k+1}\cdots|i_{2k}\rangle_{4k}\cdots (32)
|i(m1)k+1(2m2)k+1|imk(2m1)k|i(m1)k+1(2m1)k+1|imk2mk|j=1mkij2mk+1\displaystyle|i_{(m-1)k+1}\rangle_{(2m-2)k+1}\cdots|i_{mk}\rangle_{(2m-1)k}|i_{(m-1)k+1}\rangle_{(2m-1)k+1}\cdots|i_{mk}\rangle_{2mk}|\oplus_{j=1}^{mk}i_{j}\rangle_{2mk+1}

is just a PKME(2mk+1,{z},m,2)(2mk+1,\{z\},m,2) state, with {z}={kA1,kA2,,kAm,kB1,kB2,,kBm|kA1=kA2==kAm=kB1=kB2=kBm1=k,kBm=k+1}\{z\}=\{k_{A_{1}},k_{A_{2}},\cdots,k_{A_{m}},k_{B_{1}},k_{B_{2}},\cdots,k_{B_{m}}|k_{A_{1}}=k_{A_{2}}=\cdots=k_{A_{m}}=k_{B_{1}}=k_{B_{2}}=k_{B_{m-1}}=k,k_{B_{m}}=k+1\}.

Thus, there is the planar two-region multi-partite maximally entangled state of the planar 2mk+12mk+1-qubit system, where both kk and mm are positive integers larger than or equal to 1.

IV Summary

In this paper, we discuss a new kind of maximally entangled states, the planar two-region multi-partite maximally entangled states. It is demonstrated that there are the planar two-region four-partite maximally entangled states in 4-qubit and 7-qubit planar systems, although there is no AME state in 4-qubit and 7-qubit systems. Furthermore we show that there are the planar two-region four-partite maximally entangled states whether in the quantum system with even particles or in that with odd particles. Additionally, based on some planar two-region four-partite maximally entangled states, we also construct the new planar two-region four-partite maximally entangled states. Some important examples of the planar two-region four-partite and multi-partite maximally entangled states are provided.

Evidently, the virtue of two-region multi-partite maximally entangled states may induce many applications, especially in quantum parallel teleportation and quantum secret sharing. One can easily design the protocols of quantum parallel teleportation and quantum secret sharing by using the similar method provided by the authors of Ref. 26 . We hope these protocols can be realized in the future experiments.

Acknowledgements.
This work was supported by the National Natural Science Foundation of China under Grant Nos. 62271189, 12071110, and the Hebei Central Guidance on Local Science and Technology Development Foundation of China under Grant No. 236Z7604G.

References