Overgroups of exterior powers of an elementary group.
Levels
Abstract.
We prove a first part of the standard description of groups lying between an exterior power of an elementary group and a general linear group for a commutative ring and . The description uses the classical notion of a level: for every group we find a unique ideal of the ground ring which describes .
Key words and phrases:
General linear group, elementary group, overgroup, fundamental representation, exterior power, level1991 Mathematics Subject Classification:
20G35Introduction
The present paper is devoted to the solution of the following general problem.
Problem.
Let be an arbitrary commutative associative ring with and let be a reduced irreducible root system. is a Chevalley–Demazure group scheme and is its arbitrary representation. Describe all overgroups of the elementary subgroup in the representation :
The conjectural answer, the standard overgroup description, in a general case can be formulated as follows. For any overgroup of the elementary group there exists a net of ideals of the ring such that
where is a relative elementary subgroup for the net .
In the special case of a trivial net, i. e., consists of one ideal of the initial ring , overgroups of the group can be parametrized by the ideal of the ring :
(1) |
where equals by definition.
Based on the classification of finite simple groups in 1984, Michael Aschbacher proved the Subgroup structure theorem [1]. It states that every maximal subgroup of a finite classical group either falls into one of the eight explicitly described classes –, or is an ‘‘almost’’ simple group in an irreducible representation (class ). In the recent past, many experts studied overgroups of groups from the Aschbacher classes for some special cases of fields. For finite fields and algebraically closed fields maximality of subgroups was obtained by Peter Kleidman and Martin Liebeck, see [2, 3]. Oliver King, Roger Dye, and Shang Zhi Li proved maximality of groups from Aschbacher classes for arbitrary fields or described its overgroups in cases where they are not maximal, see [4, 5, 6, 7, 8, 9, 10, 11, 12]. We recommend the surveys [13, 14, 15], which contain necessary preliminaries, complete history, and known results about the initial problem.
In the present paper, we consider the case of the -th fundamental representation of a simply connected group of type , i. e., the scheme equals a [Zariski] closure of the affine group scheme in the representation with the highest weight . In our case the extended Chevalley group scheme coincides with the -th fundamental representation of the general linear group scheme . This case corresponds to the Aschbacher class consisting of almost simple groups in certain absolutely irreducible representations. Morally, the paper is a continuation of a series of papers by the St. Petersburg school on subgroups in classical groups over a commutative ring, see [16, 17, 13, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28].
We deal only with the case of a trivial net, i. e., a net consists of only one ideal . As shown below (Propositions 1 and 16), it imposes a constraint , we proceed with this restriction. In this case the general answer has the following form. Let and be a subgroup in containing . Then there exists a unique maximal ideal such that
The present paper is the first part in the serial study of the problem. We construct a level and calculate a normalizer of connected (i. e., perfect) intermediate subgroups. Further, it is necessary to construct invariant forms for and calculate a normalizer of . Finally, we will extract an elementary transvection from an intermediate subgroup . These steps are enough to solve the problem completely, see [29].
There are separate results for special cases of the ring such as a finite field or an algebraically closed field. For finite fields Bruce Cooperstein proved maximality of the normalizer in [30]. For algebraically closed fields a description of overgroups of follows from the classical results about maximal subgroups of classical algebraic groups, for instance, see [31].
The present paper is organized as follows. In the next Section we formulate main results of the paper. In Section 2 we set up the notation. Section 3 contains all complete proofs, for instance, in §3.1 we have considered an important special case — a level computation for exterior squares of elementary groups. In §3.2–§3.4 we develop a technique for an arbitrary general exterior power. Finally, a level reduction for exterior powers is proved in §3.5.
Acknowledgment. We would like to express our sincere gratitude to our scientific adviser Nikolai Vavilov for formulating the problem and for a constant support, without which this paper would never have been written. The authors are grateful to Alexei Stepanov for carefully reading our original manuscript and for numerous remarks and corrections. Also, we would like to thank an anonymous referee for bringing our attention to the paper [32].
1. Main results
Fundamental representations of the general linear group , as well as of the special linear group , are the ones with the highest weights for . The representation with the highest weight degenerates for the group . The explicit description of these representations uses exterior powers of the standard representation.
In detail, for a commutative ring by we denote an -th exterior power of the free module . We consider the following natural transformation, an exterior power,
which extends the action of the group from to .
An elementary group is a subgroup of the group of points , so its exterior power is a well defined subgroup of the group of points . A more user–friendly description of the elementary group will be presented in Subsections 3.1 and 3.2.
Let be an arbitrary overgroup of an elementary group :
For any unequal weights , which are indices for matrix entries of elements from , by we denote the following set
It turns out these sets are ideals that coincide for any pair of unequal weights .
Proposition 1.
Sets coincide for .
In the case description of overgroups cannot be done by a parametrization only by a single ideal. Moreover, as it could be seen from further calculations we need up to ideals in some cases for a complete parametrization of overgroups. There are a lot of nontrivial relationships between the ideals. So even the notion of a relative elementary group is far more complicated and depends on a Chevalley group (for instance, see [28]), let alone formulations of the Main Theorems. The authors work in this direction and hope this problem would be solved in the near future. In a general case this [partially ordered] set of ideals forms a net of ideals (due to Zenon Borevich; for a definition see [33], for further progress in the direction of subgroup classification see [34, 35]).
Back to the case , the set is called a level of an overgroup . The description of overgroups goes as follows.
Theorem 2 (Level computation).
Let be a commutative ring and , be natural numbers with the constraint . For an arbitrary overgroup of the group there exists a unique maximal ideal of the ring such that
Namely, if a transvection belongs to the group , then .
The left–hand side subgroup is denoted by . We note that this group is perfect (Lemma 22). Motivated by the expected relations , we present an alternative description of the normalizer .
For this we introduce the canonical projection mapping to . Applying the projection to all entries of a matrix, we get the reduction homomorphism
Eventually, we have the following explicit congruence description.
Theorem 3 (Level reduction).
Let . For any ideal , we have
2. Principal notation
Our notation for the most part is fairly standard in Chevalley group theory. We recall all necessary notion below for the purpose of self-containment.
First, let be a group. By a commutator of two elements we always mean the left-normed commutator , where . Multiple commutators are also left-normed; in particular, . By we denote the left conjugates of by . Similarly, by we denote the right conjugates of by . In the sequel, we will use the Hall–Witt identity:
For a subset , we denote by a subgroup it generates. The notation means that is a subgroup in , while the notation means that is a normal subgroup in . For , we denote by the smallest subgroup in containing and normalized by . For two groups , we denote by their mutual commutator:
Also we need some elementary ring theory notation. Let be an associative ring with . By default, it is assumed to be commutative. By an ideal of a ring we understand the two-sided ideal and this is denoted by . As usual, denotes a multiplicative group of a ring . A multiplicative group of matrices over a ring is called a general linear group and is denoted by . A special linear group is a subgroup of consisting of matrices of determinant . By we denote an entry of a matrix at the position , where . Further, denotes the identity matrix and denotes the standard matrix unit, i. e., the matrix that has at the position and zeros elsewhere. For entries of the inverse matrix we will use the standard notation .
By we denote an elementary transvection, i. e., a matrix of the form , , . Hereinafter, we use (without any references) standard relations [36] among elementary transvections such as
-
(1)
additivity:
-
(2)
the Chevalley commutator formula:
A subgroup generated by all elementary transvections is called an absolute elementary group:
Now define a normal subgroup of , which plays a crucial role in calculating the level of intermediate subgroups. Let be an ideal in . Consider a subgroup generated by all elementary transvections of level , i. e., is a normal closure of in . This group is called an relative elementary group of level :
It is well known (due to Andrei Suslin [37]) that the elementary group is normal in the general linear group for . The normality is crucial for further considerations, so hereafter we suppose that . Furthermore, the relative elementary group is normal in if . This fact, first proved in [37], is cited as Suslin’s theorem. Moreover, if , then the group is generated by transvections of the form , , , . This fact was proved by Leonid Vaserstein and Andrey Suslin [38] and, in the context of Chevalley groups, by Jacques Tits [39].
By we denote the set and by we denote an exterior power of the set . Elements of are ordered subsets of cardinality without repeating entries:
We use the lexicographic order on by default:
Usually, we write an index in the ascending order, . Sign of the index equals the sign of the permutation mapping to the same set in the ascending order. For example, , but .
Finally, let and . By we denote the binomial coefficient . In the sequel, we denote an elementary transvection in by for and . For instance, the transvection equals the matrix with ’s on the diagonal and in the position .
3. Proofs & Computations
We consider a case of an exterior square of a group scheme at first. We have two reasons for this way of presentation. Firstly, proofs of statements in a general case belong to the type of technically overloaded statements. At the same time, simpler proofs in the basic case present all ideas necessary for a general case. In particular, for Nikolai Vavilov and Victor Petrov completed the standard description of overgroups111The restriction of the exterior square map to the group is an isomorphism onto the elementary orthogonal group [18].. Secondly, for exterior squares there are several important results that cannot be obtained for the exterior cube or other powers, see [40, 41, 42]. For example, in [41] the author construct a transvection such that it stabilizes an arbitrary column of a matrix in . And there are no such transvections for other exterior powers.
3.1. Exterior square of elementary groups
Let be a commutative ring with , be a natural number greater than , and be a right free -module with the standard basis . By we denote a universal object in the category of alternating bilinear maps from to -modules. Concretely, take a free module of rank with the basis , . The elements for arbitrary are defined by the relation .
An action of the group on the module is diagonal:
In the basis of the module a matrix consists of second order minors of the matrix with lexicographically ordered columns and rows:
By the Cauchy–Binet theorem the map , is a homomorphism. Thus the map is a representation of the group , called the bivector representation or the second fundamental representation (the representation with the highest weight ). The image of the latter action is called the exterior square of the group . is a subgroup of , therefore the exterior square of the elementary group is well defined. The following lemma is a corollary of Suslin’s theorem.
Lemma 4.
The image of an elementary group is normal in the image of a general linear group under the exterior square homomorphism:
Note that does not equal for arbitrary rings. For detail see the extended description in §3.2.
Let us consider a structure of the group in detail. The following proposition can be extracted from the very definition of .
Proposition 5.
Let be an elementary transvection. For , can be presented as the following product:
(2) |
for any .
Remark.
For a similar equality holds:
Likewise, one can get an explicit form of torus elements of the group .
Proposition 6.
Let be a torus generator, . Then the exterior square of equals a diagonal matrix, with diagonal entries 1 everywhere except in positions:
(3) |
It follows from the propositions that , where a set consists of products of or less elementary transvections, e. g., .
Let be an overgroup of the exterior square of the elementary group :
We consider two indices . By we denote the set
By definition diagonal sets equals whole ring for any index . In the rest of the section, we prove that these sets are ideals, i. .e., form a net of ideals. Moreover, we will get -net in terms of Zenon Borevich [33] by the latter statement.
Let be an elementary transvection. We define a height of (generally, of the pair ) as a cardinality of the intersection :
This combinatorial characteristic of transvections is useful in commutator calculations.
The height splits up all sets into two classes: the one with and the other with . In fact, these classes are equal for . The set is called a level of an overgroup . Note that for the level is unique, that follows from [18].
Lemma 7.
If , then every set is an ideal of the ring . Moreover, for any and the ideals and coincide.
Proof.
A complete proof is presented in Section 3.4, Proposition 16. Here we sketch calculations in the case exclusively. These calculations present the general idea in a transparent way.
-
(1)
Firstly, take any , i. e., . Then
It remains to provide this calculation with and to product two right-hand sides; then we obtain . By the condition , this means that . It follows that
-
(2)
Secondly, take any , then . Consequently,
-
(3)
Thirdly, let , then . Consider two commutators of the latter transvection with and respectively. We obtain that and also . Hence . This means that
-
(4)
Now, take any , then . Thus
-
(5)
Finally, let . As in (1), consider the commutator with . We obtain and . By the same argument we can provide these calculations with the transvection and . We get that and . To finish the proof it remains to commutate latter two products. Then , or
∎
The following lemma is crucial for the rest. It gives an alternative description of the relative elementary group.
Lemma 8.
Let . For any ideal , we have
where by definition
Proof.
The inclusion is trivial. By Vaserstein–Suslin’s lemma [38], the group is generated by elements of the form
Hence to prove the reverse inclusion, it sufficient to check the matrix to belong to for any , . Let us consider two cases:
-
•
Suppose that there exists one pair of the same indices. Without loss of generality, we can assume that . Then this inclusion is obvious:
-
•
Thus, we are left with the inclusion with different indices . Firstly, we express as a commutator of elementary transvections:
Conjugating arguments of the commutator by , we get
Next, we decompose the right-hand side with a help of the formula
and observe the exponent belongs to , so can be ignored. Now a direct calculation, based upon the Chevalley commutator formula, shows that
where all factors on the right-hand side belong to .
∎
Remark.
The attentive reader can remark these calculations to be almost completely coincide with the calculations for the orthogonal and symplectic cases [18, 19, 20]. In the special case calculations are the same due to the isomorphism . Amazingly this argument proves a similar proposition in the case of general exterior power (see Section 3.4, Lemma 20).
Corollary 9.
Let be an arbitrary ideal of . Then
Summarizing above two lemmas, we get the main result of the paper for bivectors.
Theorem 10 (Level Computation).
Let and let be a subgroup in containing . Then there exists a unique maximal ideal such that
Namely, if for some and , then .
Lemma 8 asserts precisely to be generated as a subgroup by transvections , , and by elementary transvections , of level . As usual, we assume that and .
We formulate a perfectness of the lower bound subgroup from the latter Theorem. The proof follows from Lemma 22.
Lemma 11.
Let . The group is perfect for any ideal .
3.2. Exterior powers of elementary groups
In this section, we lift the previous statements from the level of an exterior square to the case of an arbitrary exterior power functor.
Let us define an -th exterior power of an -module as follows. A basis of this module consists of exterior products , where . Products are defined for any set as for any permutation in the permutation group . We denote the -th exterior power of by .
For every the group acts diagonally on the module . Namely, an action of a matrix on decomposable -vectors is set according to the rule
for every . In the basis a matrix consists of -order minors of the matrix with lexicographically ordered columns and rows:
By the Cauchy–Binet theorem the map , is homomorphism. Thus, the map is a representation of the group called the -th vector representation or the -th fundamental representation (the representation with the highest weight ). The image of the latter action is called the -th exterior power of the group . is a subgroup of , therefore the exterior power of the elementary group is well defined.
We cannot but emphasize the difference for arbitrary rings between the groups222The same strict inclusions are still true with changing to .
The first group is a set-theoretic image of the [abstract] group under the Cauchy–Binet homomorphism , while the second one is a group of -points of the categorical image of the group scheme under the natural transformation corresponding to the Cauchy–Binet homomorphism. Since the epimorphism of algebraic groups on points is not surjective in this situation, we see that is strictly larger than . In fact, elements of are still images of matrices, but coefficients are not from the ring itself, but from its extensions. This means that for any commutative ring elements can be represent in the form , , where is an extension of the ring . We refer the reader to [43] for more precise results about the difference between these groups.
As in Section 3.1, is a normal subgroup of by Suslin’s lemma. Moreover, is normal in . This fact follows from [44, Theorem 1].
Theorem 12.
Let be a commutative ring, , then .
For further computations we calculate an exterior power of an elementary transvection in the following proposition. The proof is straightforward by the very definition of the [classical] Binet–Cauchy homomorphism.
Proposition 13.
Let be an elementary transvection in , . Then equals
(4) |
for any .
Similarly, one can get an explicit form of torus elements of the group .
Proposition 14.
Let be a torus generator, . Then the exterior power of equals a diagonal matrix, with diagonal entries 1 everywhere except in positions:
(5) |
As an example, consider and . It follows from the propositions , where by definition every element of the set is a product of or less elementary transvections. In other words, a residue of a transvection equals the binomial coefficient . Recall that a residue of a transformation is called the rank of . Finally, there is a simple connection between the determinant of a matrix and the determinant of , see [45, Proof of Theorem 4]:
3.3. Elementary calculations technique
For an arbitrary exterior power calculations with elementary transvections are huge. In this section, we organize all possible calculations of a commutator of an elementary transvection with an exterior transvection.
Proposition 15.
Up to the action of the permutation group there exist three types of commutators with a fixed transvection :
-
(1)
if both and hold;
-
(2)
if either or . And then or respectively;
-
(3)
If both and hold, then we have the equality:
Note that the latter case is true whenever , otherwise we obtain . This commutator cannot be presented in a simpler form than the very definition.
The rule for commutator calculations from the latter proposition can be translated into the language of weight diagrams:
Weight diagrams tutorial.
-
(1)
Let be a Chevalley–Demazure group scheme, and let be a pair of different weights for the -th exterior power of . Consider any unipotent for a root of the root system , i. e., equals an elementary transvection ;
-
(2)
By denote all paths on the weight diagram333Recall that we consider the representation with the highest weight . of this representation corresponding to the root ;
-
(3)
Then there exist three different scenarios corresponding to the cases of Proposition 15:
-
•
sets of the initial and the terminal vertices of paths from do not contain the vertex ;
-
•
the vertex is initial or terminal for one path from ;
-
•
the vertex is simultaneously initial and terminal for some path444From root systems geometry any vertex can be initial or terminal for at most one -path. from .
-
•
-
(4)
Finally, let us consider a commutator of the transvection and the element . It equals a product of transvections. These transvections correspond to the paths from the previous step. Transvections’ arguments are monomials in and . Namely, in the second case the argument equals ; in the third case it equals .
In Figure 3.3 we present all three cases from step for and :
-
•
, then ;
-
•
, then ;
-
•
, then .
Similarly, for the case the elementary calculations can be seen directly from Figure 3.3.
3.4. Level computation
We generalize the notion of ideals to the case of the -th exterior power. Let be an overgroup of the exterior power of the elementary group :
Let
for any indices . As usual, diagonal sets equal the whole ring for any index . Thus, we will construct -net of ideals of the ring . Recall that the desired parametrization is given by an explicit juxtaposition for any overgroup its level, namely an ideal of the ring . We compute this ideal in the present section.
We assume that due to the isomorphism for an arbitrary free -module . The first step toward the level description is the following observation.
Proposition 16.
If , then sets and coincide. In fact, are ideals of .
But first, we prove a weaker statement.
Lemma 17.
Let be different elements of the set such that . If , then sets and coincide.
Proof of the lemma.
The sets coincide when the set is fixed. This fact can be proved by the third type commutation due to Proposition 15 with and . If we get a transvection . Then the following two products also belong to :
This implies that the product of two factors on the right-hand sides belongs to .
It can be easily proved the set can be changed by the second type commutations. For example, the set can be replaced by the set as follows
∎
Proof of Proposition 16.
Arguing as above, we see that the sets and coincide in the case , where .
In a general case, we can prove the statement by both the second and the third types commutations. Let us give an example of this calculation with replacing the set by the set .
Let . So we have . We commute this transvection with the element . Then the transvection belongs to as well as the product . From the latter inclusion we can see and .
To prove all are ideals in it is sufficient to commute any elementary transvection with exterior transvections with and :
∎
Let be an elementary transvection. Let us define a height of (more abstractly, of the pair ) as the cardinality of the set :
This combinatorial characteristic plays the same role as the distance function for roots and on a weight diagram of a root system. Now Proposition 16 can be rephrased as follows. Sets and coincide for the same heights: . Suppose that the height of is larger than the height of , then using Proposition 15, we get .
Summarizing the above arguments, we have the height grading:
The following result proves a coincidence of the sets .
Proposition 18.
The ideals coincide for . More accurately, the inverse inclusion takes place if .
Proof.
The statement can be proved by the double third type commutation as follows. Let , i. e., a transvection for . By the third type commutation with a transvection , we have . Let us consider an analogous commutator with a specifically chosen transvections and . We get that . The final step is to commute the latter products.
The choice of transvections goes in the way such that the final commutator (initially of the form ) equals an elementary transvection. This choice is possible due to the condition .
Let us give a particular example of such calculations for the case . This calculation could be easily generalized. The first three steps below correspond to the inclusions , , and respectively. We emphasize that the ideas of the proof of all three steps are completely identical. The difference has to do only with a choice of the appropriate indices. We replace the numbers , , with the letters , , respectively.
-
(1)
Let . Consider the mutual commutator
It is equal to the commutator
which is a transvection . As the result, .
-
(2)
For consider similar commutator
Thus,
Again this commutator is equal to , i. e., .
-
(3)
Finally, let . Consider the commutator
It is equal to the commutator
which is an elementary transvection . Thus, .
∎
We proved that all ideals coincide for a large enough . However, the following proposition shows relations between the ideals without this restriction. Recall that a residue of an exterior transvection equals the binomial coefficient .
Proposition 19.
For ideals the following relations hold:
Note that we have not included the relations from the notion of -net , since they hold for any net of ideals by the definition.
Proof.
The first two series of relations have already been proved. Therefore, we must only prove that . Again we will use the third type commutation.
Let ,i. e., for any indices with a transvection . Note that if , then in the commutator
the transvection belongs to the group . Indeed, the height of indices и coincide with the height of . At the same time the height of and equals . Thus for all indices with and all different .
Consider , where . By the definition of exterior transvections (4), we have . The proof is to consistently reduce the number of factors in the product by multiplication on suitable transvections . Finally, we get an elementary transvection , where the height of indices equals and the coefficient equals .
Let us give an example such argument for the exterior cube of the elementary group of dimension 5. Take , .
First, consider the commutator . As we mentioned above, the matrix . Thus,
To get an elementary transvection, consider one more commutator
. Then the matrix . It remains to multiply and . We get the transvection . Therefore, .
∎
As usual, the set is called a level of an overgroup . For level computation we need an alternative description of the relative elementary group.
Lemma 20.
For any ideal , we have
where by definition .
Proof.
Clearly, the left-hand side is contained in the right-hand side. The proof of the inverse inclusion goes by induction on the height of . By Vaserstein–Suslin’s lemma [38] it is sufficient to check the matrix to belong to for any , .
In the base case , the inclusion is obvious:
Now, let us consider the general case , i. e., and . For the following calculations we need two more sets and .
Firstly, we express as a commutator of elementary transvections,
Conjugating the arguments of the commutator by , we get
Next, we decompose the right-hand side with a help of the formula
and observe the exponent to belong to , so can be ignored. Now a direct calculation, based upon the Chevalley commutator formula, shows that
where all factors on the right-hand side belong to . ∎
Remark.
Since we do not use the coincidental elements of and , we also can prove this Lemma by induction on . Then we can assume that is an arbitrarily large number (mentally, ).
Corollary 21.
Suppose be an arbitrary ideal of the ring ; then
3.5. Normalizer of
In this section, we describe a normalizer of the lower bound for a group .
Lemma 22.
Let . The group is perfect for any ideal .
Proof.
It is sufficient to verify all generators of the group to lie in its commutator subgroup, which will be denoted by . The proof goes in two steps.
-
•
For the transvections this follows from the Cauchy–Binet homomorphism:
-
•
For elementary transvections this can be done as follows. Suppose that , where , i. e., and . As in Lemma 20, we define a set . And then
so we get the required.
∎
Let, as above, , and let be the factor-ring of modulo . Denote by the canonical projection sending to . Applying the projection to all entries of a matrix, we get the reduction homomorphism
The kernel of the homomorphism , , is called the principal congruence subgroup in of level . Now, let be the center of the group , consisting of the scalar matrices . The full preimage of the center of , denoted by , is called the full congruence subgroup of level . The group consists of all matrices congruent to a scalar matrix modulo . We further concentrate on a study of the full preimage of the group :
A key point in a reduction modulo an ideal is the following standard commutator formula, proved by Leonid Vaserstein [46], Zenon Borevich, and Nikolai Vavilov [17].
Finally, we are ready to state the level reduction result. See 3
Proof.
In the proof by we mean .
Since and are normal subgroups in , we see
Note that the latter equality is due to the normalizer functoriality:
In particular, using , we get
On the other hand, it is completely clear to be normal in the right-hand side subgroup. Indeed, it is easy to prove the following stronger inclusion:
To check this, we consider a commutator of the form
Then . We need to prove all factors on the right-hand side to belong to . Right away, the second factor lies in the group . For the first commutator, we should consider the following inclusions:
The element , so we ignore it in conjugation. The third commutator lies in due to the following inclusion.
Now if we recall and , we get
To invoke the Hall–-Witt identity, we need a slightly more precise version of the latter inclusion:
Observe that by formula we have already checked the left-hand side to be generated by the commutators of the form
However,
By formula the second commutator belongs to , whereas by the first is an element of .
Now we are ready to finish the proof. By the previous lemma, the group is perfect, and thus, it suffices to show for all . Indeed, the Hall–-Witt identity yields
where the second commutator belongs to by . Removing the conjugation by in the first commutator and carrying the conjugation by inside the commutator, we see that it only remains to prove the relation . Indeed,
where both commutators on the right–hand side belong to by formulas and , and moreover, the conjugating element in the second commutator is an element of the group , and thus by , normalizes . ∎
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