This paper was converted on www.awesomepapers.org from LaTeX by an anonymous user.
Want to know more? Visit the Converter page.

Optimal consumption under a drawdown constraint over a finite horizon

Xiaoshan Chen,  Xun Li,  Fahuai Yi,  Xiang Yu School of Mathematical Science, South China Normal University, Guangzhou 510631, China, Email:[email protected].Department of Applied Mathematics, The Hong Kong Polytechnic University, Hung Hom, Kowloon, Hong Kong. Email:[email protected].School of Mathematical Science, South China Normal University, Guangzhou 510631, China, Email:[email protected].Department of Applied Mathematics, The Hong Kong Polytechnic University, Hung Hom, Kowloon, Hong Kong. Email:[email protected]. Corresponding author.
Abstract

This paper studies a finite horizon utility maximization problem on excessive consumption under a drawdown constraint. Our control problem is an extension of the one considered in Angoshtari et al. (2019) to the model with a finite horizon and an extension of the one considered in Jeon and Oh (2022) to the model with zero interest rate. Contrary to Angoshtari et al. (2019), we encounter a parabolic nonlinear HJB variational inequality with a gradient constraint, in which some time-dependent free boundaries complicate the analysis significantly. Meanwhile, our methodology is built on technical PDE arguments, which differs from the martingale approach in Jeon and Oh (2022). Using the dual transform and considering the auxiliary variational inequality with gradient and function constraints, we establish the existence and uniqueness of the classical solution to the HJB variational inequality after the dimension reduction, and the associated free boundaries can be characterized in analytical form. Consequently, the piecewise optimal feedback controls and the time-dependent thresholds for the ratio of wealth and historical consumption peak can be obtained.


Keyword: Optimal consumption, drawdown constraint, parabolic variational inequality, gradient constraint, free boundary.

1 Introduction

Optimal portfolio and consumption via utility maximization has always been one of the core research topics in quantitative finance. Starting from the seminal works Merton (1969) and Merton (1971), a large amount of studies can be found in the literature by considering various incomplete market models, trading constraints, risk factors, etc. One notable research direction is to refine the measurement of consumption performance by encoding the impact of past consumption behavior. The so-called addictive habit formation preference recommends that the utility shall be generated by the difference between the current consumption rate and the historical weighted average of the past consumption. In addition, the infinite marginal utility mandates the addictive habit formation constraint that the consumption level needs to stay above the habit formation level, representing that the agent’s standard of living can never be compromised. Along this direction, fruitful results can be found in various market models, see among Constantinides (1990), Detemple and Zapatero (1992), Schroder and Skiadas (2002), Munk (2008), Englezos and Karatzas (2009), Yu (2015), Yu (2017), Yang and Yu (2022), Angoshtari et al. (2022), Bo et al. (2022), Angoshtari et al. (2023) and references therein.

Another rapidly growing research stream is to investigate the impact of the past consumption maximum instead of the historical average. The pioneering work Dybvig (1995) examines an extension of Merton’s problem under a ratcheting constraint on consumption rate such that the consumption control needs to be non-decreasing. Arun (2012) later generalizes the model in Dybvig (1995) by considering a drawdown constraint such that the consumption rate can not fall below a proportion of the past consumption maximum. Angoshtari et al. (2019) revisit the problem by considering a drawdown constraint on the excessive dividend rate up to the bankruptcy time, which can be regarded as an extension of the problem in Arun (2012) to the model with zero interest rate. Jeon and Park (2021) further extend the work in Arun (2012) by considering general utility functions using the martingale duality approach where the dual optimal stopping problem is examined therein. Tanana (2021) employs the general duality approach and establishes the existence of optimal consumption under a drawdown constraint in incomplete semimartingale market models. Jeon and Oh (2022) recently generalizes the approach in Jeon and Park (2021) to the model with a finite horizon and addresses the existence of a solution to the dual optimal stopping problem.

On the other hand, inspired by the time non-separable preference rooted in the habit formation preference, some recent studies also incorporate the past consumption maximum into the utility function as an endogenous reference level. Guasoni et al. (2020) first adopt the Cobb-Douglas utility that is defined on the ratio between the consumption rate and the past consumption maximum and obtain the feedback controls in analytical form. Deng et al. (2022) choose the same form of the linear habit formation preference and investigate an optimal consumption problem when the difference between the consumption rate and the past spending peak generates the utility. Later, the preference in Deng et al. (2022) is generalized to an S-shaped utility in Li et al. (2021) to account for the agent’s loss aversion over the relative consumption. Liang et al. (2022) extends the work in Deng et al. (2022) by considering the change of risk aversion parameter concerning the reference level where an additional drawdown constraint is also required. Li et al. (2022) incorporates the dynamic life insurance control and expected bequest with an additional drawdown constraint on the consumption control.

As an important add-on to the existing literature, the present paper revisits the optimal excessive consumption problem under drawdown constraint as in Angoshtari et al. (2019), however, with a finite investment horizon. We summarize the main contributions of the present paper as two-fold:

  • (i)

    From the modelling perspective, it is well documented that heterogenous agents may have diverse choices of investment horizons in practice. In fact, as the agent’s time horizon changes, the risk tolerance should be adjusted accordingly. Typically, agents seek more stable assets for short-term horizon and would call for a more aggressive strategy for the longer-term investment. Our model and research outcomes to incorporate a terminal horizon provide the flexibility to meet versatile needs in applications with different choices of investment horizons.

    Similar to Angoshtari et al. (2019), we adopt the classical power utility U(x)=x1p1pU(x)=\frac{x^{1-p}}{1-p} with the relative risk aversion coefficient 0<p<10<p<1. On one hand, many empirical studies suggest that the risk aversion of the agent should be relatively constant over wealth levels, which is an important merit of the power utility function. On the other hand, the power utility function enjoys the homogeneity, which enables us to reduce the dimension of the HJB equation by changing variables (see (2.6)). As a result, it is sufficient for us to focus on one state variable in studying the HJB equation and its dual PDE, which significantly simplifies the technical proofs to establish the regularity of the solution and the analytcial characterization of the time-dependent free boundary curves.

  • (ii)

    From the methodology perspective, we encounter the associated parabolic HJB variational inequality with gradient constraint. It is well known that the global regularity of the parabolic problem requires a more delicate analysis of the time-dependent free boundaries and the smooth fit conditions. Some previous arguments in Angoshtari et al. (2019) crucially rely on the constant free boundary points as well as some explicit expressions of the value function, which are evidently not applicable in our framework due to time dependence. The present paper contributes to some new and rigorous proofs to establish the existence and the uniqueness of the classical solution to the associated HJB variational inequality (2.30) (see Theorem 4.1). Moreover, to verify that the dual transform is well defined, we can show that the solution UU is indeed increasing and concave in ω\omega (see Lemma 2.3).

    We stress that, in many existing studies using the dual transform, see Chen et al. (2012), Chen and Yi (2012), Dai and Yi (2009), Guan et al. (2019) among others, the dual domain is often the entire +×(0,T]\mathbb{R}^{+}\times(0,T], which facilitates some classical PDE arguments. In our framework, due to the drawdown constraint ctαztc_{t}\geq\alpha z_{t} (see (2.1) and (2.2) for the description of the constraint), there exists a threshold for the ratio of the wealth level and the past consumption peak such that the minimum consumption plan needs to maintain at a subsistence level (see (2.23)) whenever the ratio falls below that threshold. As a result, the left boundary ω=0\omega=0 is mapped to an unknown finite boundary y0(t)<y_{0}(t)<\infty, t>0t>0. Employing the boundary condition at y0(t)y_{0}(t) in (2.41), we extend the variational inequality with a gradient constraint to an auxiliary variation inequality (3.1) with both function and gradient constraints in the unbounded domain +×(0,T]\mathbb{R}^{+}\times(0,T]. We can then apply several further transformations (see Propositions 3.8, 3.10 and 3.11) and modify some technical arguments in Chen et al. (2019) and Chen and Yi (2012) to establish the existence and uniqueness of the solution in C2,1C^{2,1} regularity to the primal parabolic HJB variational inequality (see Theorem 4.1). More importantly, we provide some tailor-made and technical arguments to characterize the associated time-dependent free boundaries in analytical form such that the smooth fit conditions hold (see Theorem 4.2).

With the help of our new PDE results, we can derive the optimal consumption and portfolio in piecewise feedback form and identify all analytical time-dependent thresholds for the ratio between the wealth level and the past consumption maximum, dividing the domain into three regions for different consumption behaviors (see Theorem 2.1). In addition, the analytical threshold functions allow us to theoretically verify their quantitative dependence on the constraint parameter α\alpha.

The rest of the paper is organized as follows. In Section 2, we introduce the market model and the utility maximization problem under a consumption drawdown constraint. By dimension reduction using the homogeneity of power utility, we formulate the associated HJB variational inequality and its dual problem. In Section 3, we first analyze the dual linear parabolic variational inequality by considering some auxiliary problems with gradient and function constraints. By showing the existence and uniqueness of the solution to the auxiliary problems and characterizing their free boundaries, we obtain the unique classical solution to the dual HJB variational inequality. In Section 4, using the results from the dual problem, we establish the unique classical solution to the primal HJB variational inequality and verify the optimal feedback controls and all associated time-dependent thresholds in analytical form. In Section 5, we conclude our theoretical contributions and discuss some future research directions.

2 Market Model and Problem Formulation

2.1 Model setup

Let (Ω,,𝔽,)(\Omega,\mathcal{F},\mathbb{F},\mathbb{P}) be a standard filtered probability space, where 𝔽=(t)t[0,T]\mathbb{F}=(\mathcal{F}_{t})_{t\in[0,T]} satisfies the usual conditions. We consider a financial market consisting of one riskless asset and one risky asset, and the terminal time horizon is denoted by TT. The riskless asset price satisfies dBt=rBtdtdB_{t}=rB_{t}dt where r0r\geq 0 represents the constant interest rate. The risky asset price follows the dynamics

dSt=St(μ+r)dt+StσdWt,t[0,T],dS_{t}=S_{t}(\mu+r)dt+S_{t}\sigma dW_{t},\ \ t\in[0,T],

where WW is an 𝔽\mathbb{F}-adapted Brownian motion and the drift (μ+r)(\mu+r) and volatility σ>0\sigma>0 are given constants. It is assumed that the excessive return μ>0\mu>0, i.e., the risky asset’s return is higher than the interest rate.

Let (πt)t[0,T](\pi_{t})_{t\in[0,T]} represent the dynamic amount that the investor allocates in the risky asset and (Ct)t[0,T](C_{t})_{t\in[0,T]} denote the dynamic consumption rate by the investor. In this paper, we consider a drawdown constraint on the excess consumption rate ct:=CtrXtc_{t}:=C_{t}-rX_{t} in the sense that ctc_{t} cannot go below a fraction α(0,1)\alpha\in(0,1) of its past maximum that

ctαzt,t[0,T].\displaystyle c_{t}\geq\alpha z_{t},\quad t\in[0,T]. (2.1)

Here, the non-decreasing reference process (zt)t[0,T](z_{t})_{t\in[0,T]} is defined as the historical excessive spending maximum

zt=max{z,supstcs},\displaystyle z_{t}=\max\Big{\{}z,\ \sup\limits_{s\leq t}c_{s}\Big{\}}, (2.2)

and z0z\geq 0 is the initial reference level.

In our setting, rXtrX_{t} stands for the subsistence consumption level that may refer to some mandated daily expenses in practice. On top of that, the drawdown constraint (2.1) is imposed to reflect some practical situations that some decision makers may psychologically feel painful when there is a decline in the consumption plan comparing with the past spending peak. In particular, some large expenditures not only spur some long term continuing spending such as maintenance and repair, but also lift up the investor’s standard of living that affects the future consumption decisions. Moreover, by interpreting the consumption control as dividend payment, Angoshtari et al. (2019) also discussed another motivation of the drawdown constraint that some shareholders feel disappointment when there is a decline in dividend policies.

The self-financing wealth process XtX_{t} is then governed by the SDE that

dXt=(r(Xtπt)Ct)dt+πt((μ+r)dt+σdWt),\displaystyle dX_{t}=(r(X_{t}-\pi_{t})-C_{t})dt+\pi_{t}\left((\mu+r)dt+\sigma dW_{t}\right),

which can be equivalently written by

dXt=(μπtct)dt+σπtdWt,t[0,T],\displaystyle dX_{t}=(\mu\pi_{t}-c_{t})dt+\sigma\pi_{t}dW_{t},\ \ t\in[0,T], (2.3)

with the initial wealth X0=x0X_{0}=x\geq 0.

Let 𝒜(x)\mathcal{A}(x) denote the set of admissible controls (πt,ct)(\pi_{t},c_{t}) if (πt)t[0,T](\pi_{t})_{t\in[0,T]} is 𝔽\mathbb{F}-progressively measurable, (ct)t[0,T](c_{t})_{t\in[0,T]} is 𝔽\mathbb{F}-predictable, the integrability condition 𝔼[0T(ct+πt2)𝑑t]<+\mathbb{E}[\int_{0}^{T}(c_{t}+\pi_{t}^{2})dt]<+\infty holds and the drawdown constraint ctαztc_{t}\geq\alpha z_{t} is satisfied a.s. for all t[0,T]t\in[0,T].

The goal of the agent is to maximize the expected utility of the excessive consumption rate up to time TτT\wedge\tau under the drawdown constraint, where τ\tau is the bankruptcy time defined by τ:=inf{t0|Xt0}\tau:=\inf\big{\{}t\geq 0~{}|~{}X_{t}\leq 0\big{\}}.

To embed the control problem into a Markovian framework and facilitate the dynamic programming arguments, we choose the consumption running maximum process ztz_{t} in (2.2) as the second state process. The value function of the stochastic control problem over a finite time horizon is given by

V(x,z,t)=sup(π,c)𝒜(x)𝔼[tTτeδ(st)cs1p1p𝑑s+eδ(Tτt)XTτ1p1p|Xt=x,zt=z],\displaystyle V(x,z,t)=\sup\limits_{(\pi,c)\in\mathcal{A}(x)}\mathbb{E}\left[\int_{t}^{T\wedge\tau}e^{-\delta(s-t)}\frac{c_{s}^{1-p}}{1-p}ds+e^{-\delta(T\wedge\tau-t)}\frac{X_{T\wedge\tau}^{1-p}}{1-p}\Bigg{|}X_{t}=x,z_{t}=z\right], (2.4)

where the constant δ0\delta\geq 0 denotes the subjective time preference parameter, and 0<p<10<p<1 stands for the agent’s relative risk aversion coefficient.

We first note that the problem (2.4) is an extension of the control problem considered in Angoshtari et al. (2019) to the model with a finite horizon. Some new mathematical challenges arise as we encounter a parabolic variational inequality with time-dependent free boundaries. One main contribution of the present paper is that all time-dependent free boundaries stemming from the control constraint αztctzt\alpha z_{t}\leq c_{t}\leq z_{t} can be characterized in analytical form (see (4.13), (4.14) and (4.15) in Thereom 4.2), allowing us to identify time-dependent thresholds for the ratio between the wealth level and the past consumption running maximum to choose among different optimal feedback consumption strategies, see (2.23) in Theorem 2.1.

On the other hand, if we interpret ctc_{t} in problem (2.4) as a control of consumption rate and regard XtX_{t} in (2.3) as the resulting wealth process under the control pair (πt,ct)(\pi_{t},c_{t}), then the control problem (2.4) is actually equivalent to a finite horizon optimal consumption problem under a drawdown constraint in the financial market with zero interest rate (as r=0r=0 in the SDE (2.3) of XtX_{t} under the control (πt,ct)(\pi_{t},c_{t})). The finite horizon optimal consumption problem under a drawdown constraint has been studied by Jeon and Oh (2022), however, under the crucial assumptions that the interest rate r>0r>0 and the initial wealth is sufficiently large that Xt>αzt1er(Tt)rX_{t}>\alpha z_{t-}\frac{1-e^{-r(T-t)}}{r} (see Assumption 3.1 in Jeon and Oh (2022)). Based on the martingale and duality approach, the original control problem in Jeon and Oh (2022) is transformed into an infinite series of optimal stopping problems, which requires the optimal wealth process to be strictly positive that Xt>0X_{t}>0 and hence Xt>αzt1er(Tt)rX_{t}>\alpha z_{t-}\frac{1-e^{-r(T-t)}}{r} has to be mandated as an upper bound on ztz_{t}.

In contrast, we have interest rate r=0r=0 in the equivalent optimal consumption problem, and no constraint on XtX_{t} or ztz_{t} is imposed because we allow the wealth process to hit zero on or before the terminal horizon TT and will terminate the investment and consumption control once the bankruptcy occurs. Therefore, the main results and the approach in Jeon and Oh (2022) can not cover our problem (2.4) with r=0r=0 and x0x\geq 0. Instead, we rely on the technical analysis of the HJB variational inequality. Note that the interest rate rr does not appear in SDE (2.3) and the objective function in (2.4), our main results, especially all associated wealth thresholds, do not depend on rr. Some major challenges are characterizing the free boundaries caused by the control constraint αztctzt\alpha z_{t}\leq c_{t}\leq z_{t} and the global regularity of the solution to the HJB variational inequality.

2.2 The control problem and main result

By heuristic dynamic programming arguments and the martingale optimality condition, we note that the term zV=0\partial_{z}V=0 holds whenever the monotone process ztz_{t} is strictly increasing, and the associated HJB variational inequality can be written as

{max{supπ,αzcz[tV+12σ2π2xxV+(μπc)xVδV+c1p1p],zV}=0,(x,z,t)Q,V(0,z,t)=0,z>0,t[0,T),V(x,z,T)=x1p1p,x0,z>0,\left\{\begin{array}[]{l}\max\Big{\{}\sup\limits_{\begin{subarray}{c}\pi\in\mathbb{R},\\ \alpha z\leq c\leq z\end{subarray}}\left[\partial_{t}V+\frac{1}{2}\sigma^{2}\pi^{2}\partial_{xx}V+(\mu\pi-c)\partial_{x}V-\delta V+\frac{c^{1-p}}{1-p}\right],\partial_{z}V\Big{\}}=0,\ (x,z,t)\in Q,\\ V(0,z,t)=0,\quad\quad z>0,t\in[0,T),\\ V(x,z,T)=\frac{x^{1-p}}{1-p},\quad\quad x\geq 0,\;z>0,\end{array}\right. (2.5)

where Q:=(0,+)×(0,+)×[0,T).Q:=(0,+\infty)\times(0,+\infty)\times[0,T).

It is straightforward to see that the value function V(x,z,t)V(x,z,t) in (2.4) is homogeneous of degree 1p1-p with respect to xx and zz such that V(βx,βz,t)=β1pV(x,z,t)V(\beta x,\beta z,t)=\beta^{1-p}V(x,z,t). As a result, we can consider the change of variable

ω:=xz0,\displaystyle\omega:=\frac{x}{z}\geq 0, (2.6)

and reduce the dimension that

V(x,z,t)=z1pV(xz,1,t)=:z1pU(xz,t)=z1pU(ω,t).V(x,z,t)=z^{1-p}V\Big{(}\frac{x}{z},1,t\Big{)}=:z^{1-p}U\Big{(}\frac{x}{z},t\Big{)}=z^{1-p}U\Big{(}\omega,t\Big{)}. (2.7)

It then follows that

{tV=z1ptU,xV=z1p(1z)ωU=zpωU,xxV=z(1+p)ωωU,zV=(1p)zpU+z1p(xz2)ωU=zp[(1p)UωωU].\displaystyle\left\{\begin{array}[]{ll}\partial_{t}V=z^{1-p}\partial_{t}U,\\ \partial_{x}V=z^{1-p}(\frac{1}{z})\partial_{\omega}U=z^{-p}\partial_{\omega}U,\\ \partial_{xx}V=z^{-(1+p)}\partial_{\omega\omega}U,\\ \partial_{z}V=(1-p)z^{-p}U+z^{1-p}(-\frac{x}{z^{2}})\partial_{\omega}U=z^{-p}[(1-p)U-\omega\partial_{\omega}U].\end{array}\right. (2.12)

Moreover, let us consider the auxiliary controls π^(ω,t)=π(x,z,t)z\hat{\pi}(\omega,t)=\frac{\pi(x,z,t)}{z} and c^t(ω,t)=c(x,z,t)z\hat{c}_{t}(\omega,t)=\frac{c(x,z,t)}{z}. The HJB equation (2.5) can be rewritten as

{max{tU+supπ^{12σ2π^2ωωU+μπ^ωU}+supαc^1{c^1p1pc^ωU}δU,(1p)UωωU}=0,(ω,t)𝒬,U(0,t)=0,t[0,T),U(ω,T)=ω1p1p,ω0,\displaystyle\left\{\begin{array}[]{l}\max\Big{\{}\partial_{t}U+\sup\limits_{\hat{\pi}\in\mathbb{R}}\left\{\frac{1}{2}\sigma^{2}\hat{\pi}^{2}\partial_{\omega\omega}U+\mu\hat{\pi}\partial_{\omega}U\right\}+\sup\limits_{\alpha\leq\hat{c}\leq 1}\left\{\frac{\hat{c}^{1-p}}{1-p}-\hat{c}\partial_{\omega}U\right\}-\delta U,\\ \hfill(1-p)U-\omega\partial_{\omega}U\Big{\}}=0,\quad(\omega,t)\in\mathcal{Q},\\ U(0,t)=0,\quad t\in[0,T),\\ U(\omega,T)=\frac{\omega^{1-p}}{1-p},\quad\omega\geq 0,\end{array}\right. (2.17)

where 𝒬:=+×[0,T)\mathcal{Q}:=\mathbb{R}^{+}\times[0,T).

We first present the main result of the paper, and its proof is deferred to Section 4.

Theorem 2.1 (Verification Theorem).

There exists a unique classical solution U(ω,t)C2,1(𝒬)U(\omega,t)\in C^{2,1}(\mathcal{Q}) to problem (2.17), and V(x,z,t):=z1pU(xz,t))C2,1(Q)C(Q¯)V(x,z,t):=z^{1-p}U(\frac{x}{z},t))\in C^{2,1}(Q)\cap C(\bar{Q}) is the unique classical solution to problem (2.5). Moreover, we have that

xxV(x,z,t)<0,(x,z,t)Q,\displaystyle\partial_{xx}V(x,z,t)<0,\quad(x,z,t)\in Q, (2.18)

The optimal feedback controls of the problem (2.4) are given by

π(x,z,t)=zπ^(xz,t)=z[μσ2ωU(xz,t)ωωU(xz,t)],\displaystyle\pi^{*}(x,z,t)=z\hat{\pi}^{*}\left(\frac{x}{z},t\right)=z\left[-\frac{\mu}{\sigma^{2}}\frac{\partial_{\omega}U(\frac{x}{z},t)}{\partial_{\omega\omega}U(\frac{x}{z},t)}\right], (2.19)
c(x,z,t)=zc^(xz,t)={αz,if 0<xωα(t)z,(ωU)1p(xz,t)z,if ωα(t)z<x<ω1(t)z,z,if ω1(t)zxω(t)z,\displaystyle c^{*}(x,z,t)=z{\hat{c}}^{*}\left(\frac{x}{z},t\right)=\left\{\begin{array}[]{ll}\alpha z,&\mbox{if }0<x\leq\omega_{\alpha}(t)z,\\ (\partial_{\omega}U)^{-\frac{1}{p}}\left(\frac{x}{z},t\right)z,&\mbox{if }\omega_{\alpha}(t)z<x<\omega_{1}(t)z,\\ z,&\mbox{if }\omega_{1}(t)z\leq x\leq\omega^{*}(t)z,\\ \end{array}\right. (2.23)
𝒟={x,z,t)Q|zV(x,z,t)=0}={(x,z,t)Q|xω(t)z},\displaystyle\mathcal{D}=\{x,z,t)\in Q~{}|~{}\partial_{z}V(x,z,t)=0\}=\{(x,z,t)\in Q~{}|~{}x\geq\omega^{*}(t)z\}, (2.24)
𝒞={x,z,t)Q|zV(x,z,t)<0}={(x,z,t)Q|x<ω(t)z},\displaystyle\mathcal{C}=\{x,z,t)\in Q~{}|~{}\partial_{z}V(x,z,t)<0\}=\{(x,z,t)\in Q~{}|~{}x<\omega^{*}(t)z\}, (2.25)

where ωα(t),ω1(t)\omega_{\alpha}(t),\omega_{1}(t) and ω(t)\omega^{*}(t) are free boundaries to problem (2.30), which are characterized analytically in Theorem 4.2.

Remark 2.2.

In what follows, we first elaborate the intuition behind the existence of the free boundary ω(t)\omega^{*}(t) such that c(x,z,t)=zc^{*}(x,z,t)=z for ω1(t)zxω(t)z\omega_{1}(t)z\leq x\leq\omega^{*}(t)z in Theorem 2.1.

In Section 4 of Jeon and Oh (2022), it is shown by duality and martingale approach that there exists an optimal adjustment boundary ω(t)\omega^{*}(t) such that: (i) if α1er(Tt)rXt/zt<ω(t)\alpha\frac{1-e^{-r(T-t)}}{r}X^{*}_{t}/z^{*}_{t}<\omega^{*}(t), the optimal consumption satisfies αztctzt\alpha z_{t}^{*}\leq c^{*}_{t}\leq z_{t}^{*}; (ii) if Xt/ztω(t)X^{*}_{t}/z^{*}_{t}\geq\omega^{*}(t), the resulting running maximum process ztz_{t}^{*} is increasing and if Xt/zt>ω(t)X^{*}_{t}/z^{*}_{t-}>\omega^{*}(t), the optimal consumption can be chosen in the form of ct=Xt/ω(t)>ztc_{t}^{*}=X^{*}_{t}/\omega^{*}(t)>z^{*}_{t-} such that the resulting ztz^{*}_{t} immediately jumps from ztz^{*}_{t-} to a new global maximum level zt=Xt/ω(t)z^{*}_{t}=X^{*}_{t}/\omega^{*}(t). As a result, the free boundary ω(t)\omega^{*}(t) can be used to split the whole domain of (x,z,t)(x,z,t) into two regions connected in tt variable and the controlled two dimensional process (Xt,zt)(X_{t}^{*},z_{t}^{*}) only diffuses within the region {Xtztω(t)}\{X_{t}^{*}\leq z_{t}^{*}\omega^{*}(t)\} for any 0<tT0<t\leq T. The only possibility for Xt>ztω(t)X_{t}^{*}>z_{t-}^{*}\omega^{*}(t) to occur is at the initial time t=0t=0, at which instant the process z0=zz_{0-}^{*}=z jumps immediately to x/ω(0)x/\omega^{*}(0).

Motivated by the result in Jeon and Oh (2022), we conjecture and will verify later in our model that there also exists such a time-dependent free boundary ω(t)\omega^{*}(t), which is the critical threshold of the wealth-to-consumption-peak ratio under the optimal control (π,c)(\pi^{*},c^{*}) such that if Xt>ω(t)ztX^{*}_{t}>\omega^{*}(t)z^{*}_{t-}, the resulting ztz^{*}_{t} immediately jumps from ztz^{*}_{t-} to a new global maximum level zt=Xt/ω(t)z^{*}_{t}=X^{*}_{t}/\omega^{*}(t). If Xtω(t)ztX^{*}_{t}\leq\omega^{*}(t)z^{*}_{t}, the agent chooses the excessive consumption rate staying in [αzt,zt][\alpha z^{*}_{t},z^{*}_{t}].

Given this conjectured free boundary ω(t)\omega^{*}(t), the domain Q=(0,+)×(0,)×[0,T)Q=(0,+\infty)\times(0,\infty)\times[0,T) can be split into two regions 𝒟:={(x,z,t)Q|xω(t)z}\mathcal{D}:=\{(x,z,t)\in Q|x\geq\omega^{*}(t)z\} and 𝒞:={(x,z,t)Q|x<ω(t)z}\mathcal{C}:=\{(x,z,t)\in Q|x<\omega^{*}(t)z\}, which are connected in the time variable tt. We will first study the existence of a classical solution to the HJB variational inequality with the time-dependent free boundary ω(t)\omega^{*}(t) and characterize ω(t)\omega^{*}(t) in the analytical form in Theorem 4.2. Building upon the classical solution to the HJB variational inequality, we then derive the piecewise feedback functions for the optimal control. Finally, the verification theorem on the optimal control guarantees the validity of our conjecture and the existence of such a free boundary ω(t)\omega^{*}(t) for the optimal control (π,c)(\pi^{*},c^{*}). We note that a similar hypothesis on the existence of a constant free boundary ω\omega^{*} (independent of tt) is also made and verified in Angoshtari et al. (2019) for the infinite horizon stochastic control problem using the verification theorem on the optimal control.

Based on the variational inequality (2.5) and the main results in Verification Theorem 2.1, we plot the numerical illustrations of the value function, the optimal feedback functions of portfolio and consumption in terms of the wealth variable xx while fixing z=1z=1 and t=0.5t=0.5 in Figure 1 as below:

Refer to caption
Refer to caption
Refer to caption
Refer to caption
Refer to caption
Figure 1: The numerical illustration of the value function and its derivative with respect to xx (top panel) The numerical illustration of the optimal portfolio and the optimal consumption with respect to xx (bottom panel)

As shown in Figure 1, the value function is strictly increasing and concave in the wealth variable xx. More importantly, both optimal feedback functions of portfolio and consumption rate are increasing in xx. However, comparing with the Merton’s solution, the optimal portfolio is no longer a constant proportion strategy of the wealth level, in fact, it is even not simply concave or convex in the wealth variable depending on the ratio of the wealth and the past consumption peak. The right-bottom panel also illustrates the piecewise consumption behavior in Theorem 2.1: when x/zωα(t)x/z\leq\omega_{\alpha}(t), the optimal consumption c^(xz,t)=α\hat{c}^{*}(\frac{x}{z},t)=\alpha; when ωα(t)<x/z<ω1(t)\omega_{\alpha}(t)<x/z<\omega_{1}(t), the optimal consumption is the first order condition c^(xz,t)=(ωU)1p(xz,t)\hat{c}^{*}(\frac{x}{z},t)=(\partial_{\omega}U)^{-\frac{1}{p}}(\frac{x}{z},t); and when ω1(t)x/zω(t)\omega_{1}(t)\leq x/z\leq\omega^{*}(t), the optimal consumption is equal to the historical consumption peak.

2.3 The dual variational inequality

We plan to employ the dual transform to linearize the HJB variational inequality (2.17) and study the existence of its classical solution. To this end, we first show below that the dual transform is well defined.

Lemma 2.3.

The solution U(ω,t)U(\omega,t) of the problem (2.17) satisfies

ωωU(ω,t)<0,(ω,t)𝒬,\displaystyle\partial_{\omega\omega}U(\omega,t)<0,\quad(\omega,t)\in\mathcal{Q}, (2.26)
ωU(ω,t)>0,(ω,t)𝒬.\displaystyle\partial_{\omega}U(\omega,t)>0,\quad(\omega,t)\in\mathcal{Q}. (2.27)
Proof.

From the transformation (2.7) between V(x,z,t)V(x,z,t) and U(ω,t)U(\omega,t), let us first show the concavity of U(ω,t)U(\omega,t). Suppose that there exists a point (ω0,t0)𝒬(\omega_{0},t_{0})\in\mathcal{Q} such that ωωU(ω0,t0)>0\partial_{\omega\omega}U(\omega_{0},t_{0})>0, then

sup{12σ2π~2ωωU(ω0,t0)+μπ~ωU(ω0,t0)}=+,\sup\limits\left\{\frac{1}{2}\sigma^{2}\tilde{\pi}^{2}\partial_{\omega\omega}U(\omega_{0},t_{0})+\mu\tilde{\pi}\partial_{\omega}U(\omega_{0},t_{0})\right\}=+\infty,

which is a contradiction to (2.17), hence ωωU(ω,t)0\partial_{\omega\omega}U(\omega,t)\leq 0 in 𝒬\mathcal{Q}.

Next, if there exists a point (ω0,t0)𝒬(\omega_{0},t_{0})\in\mathcal{Q} such that ωωU(ω0,t0)=0\partial_{\omega\omega}U(\omega_{0},t_{0})=0 and ωU(ω0,t0)0\partial_{\omega}U(\omega_{0},t_{0})\neq 0, then

supπ~{12σ2π~2ωωU(ω0,t0)+μπ~ωU(ω0,t0)}=supπ~{μπ~ωU(ω0,t0)}=+,\sup\limits_{\tilde{\pi}}\left\{\frac{1}{2}\sigma^{2}\tilde{\pi}^{2}\partial_{\omega\omega}U(\omega_{0},t_{0})+\mu\tilde{\pi}\partial_{\omega}U(\omega_{0},t_{0})\right\}=\sup\limits_{\tilde{\pi}}\{\mu\tilde{\pi}\partial_{\omega}U(\omega_{0},t_{0})\}=+\infty,

which also leads to a contradiction. Therefore, if there exists a point (ω¯,t¯)(\bar{\omega},\bar{t}) such that ωωU(ω¯,t¯)=0\partial_{\omega\omega}U(\bar{\omega},\bar{t})=0, we must have ωU(ω¯,t¯)=0\partial_{\omega}U(\bar{\omega},\bar{t})=0, thus (2.17) becomes

max{tU(ω¯,t¯)+11pδU(ω¯,t¯),(1p)U(ω¯,t¯)}=0,\max\left\{\partial_{t}U(\bar{\omega},\bar{t})+\frac{1}{1-p}-\delta U(\bar{\omega},\bar{t}),(1-p)U(\bar{\omega},\bar{t})\right\}=0, (2.28)

which yields that (1p)U(ω¯,t¯)0(1-p)U(\bar{\omega},\bar{t})\leq 0. Moreover, by the definition (2.4) of V(x,z,t)V(x,z,t) and the transformation (2.7) between V(x,z,t)V(x,z,t) and U(ω,t)U(\omega,t), we know U0U\geq 0 in 𝒬\mathcal{Q}, thus UU attains the minimum at the point (ω¯,t¯)(\bar{\omega},\bar{t}). It then follows that tU(ω¯,t¯)0\partial_{t}U(\bar{\omega},\bar{t})\geq 0, and

tU(ω¯,t¯)+11pδU(ω¯,t¯)11p,\partial_{t}U(\bar{\omega},\bar{t})+\frac{1}{1-p}-\delta U(\bar{\omega},\bar{t})\geq\frac{1}{1-p},

which contradicts (2.28). In summary, we obtain (2.26).

We next show the strict monotonicity of U(ω,t)U(\omega,t). By the definition (2.4) of V(x,z,t)V(x,z,t) and the transformation (2.7), we know that U0U\geq 0 in 𝒬\mathcal{Q}. Combining with the inequality (1p)UωωU0(1-p)U-\omega\partial_{\omega}U\leq 0 in (2.17), we have

ωU(1p)U0,(ω,t)𝒬.\partial_{\omega}U\geq(1-p)U\geq 0,\quad(\omega,t)\in\mathcal{Q}.

Moreover, by the concavity of U(ω,t)U(\omega,t), we know ωU\partial_{\omega}U is strictly decreasing in ω\omega. Hence, if there exists a point (ω0,t0)𝒬(\omega_{0},t_{0})\in\mathcal{Q} such that ωU(ω0,t0)=0\partial_{\omega}U(\omega_{0},t_{0})=0, it holds that

ωU(ω,t0)<0,ω>ω0,\partial_{\omega}U(\omega,t_{0})<0,\quad\omega>\omega_{0},

which yields a contradiction. Therefore, we have that (2.27) holds. ∎

As UU is increasing and concave in ω\omega, we can choose the candidate optimal feedback control π^(ω,t){\hat{\pi}}^{*}(\omega,t) by the first order condition that

π^(ω,t):=μσ2ωUωωU0.\hat{\pi}^{*}(\omega,t):=-\frac{\mu}{\sigma^{2}}\frac{\partial_{\omega}U}{\partial_{\omega\omega}U}\geq 0.

Considering the constraint αc^1\alpha\leq\hat{c}\leq 1, we can choose the candidate optimal feedback control

c^(ω,t):=max{α,min{1,(ωU)1p}}.\hat{c}^{*}(\omega,t):=\max\Big{\{}\alpha,\min\big{\{}1,(\partial_{\omega}U)^{-\frac{1}{p}}\big{\}}\Big{\}}. (2.29)

Then (2.17) becomes

{max{tU12μ2σ2(ωU)2ωωU+(c^(ω,t))1p1pc^(ω,t)ωUδU,(1p)UωωU}=0,(ω,t)𝒬,U(0,t)=0,t[0,T),U(ω,T)=ω1p1p,ω0.\left\{\begin{array}[]{l}\max\left\{\partial_{t}U-\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}\frac{(\partial_{\omega}U)^{2}}{\partial_{\omega\omega}U}+\frac{(\hat{c}^{*}(\omega,t))^{1-p}}{1-p}-{\hat{c}}^{*}(\omega,t)\partial_{\omega}U-\delta U,(1-p)U-\omega\partial_{\omega}U\right\}=0,\\ \hfill(\omega,t)\in\mathcal{Q},\\ U(0,t)=0,\quad\quad t\in[0,T),\\ U(\omega,T)=\frac{\omega^{1-p}}{1-p},\quad\omega\geq 0.\end{array}\right. (2.30)

For the conjectured free boundary ω(t)\omega^{*}(t) in Remark 2.2 under the optimal control (π,c)(\pi^{*},c^{*}), using the relationship between V(x,z,t)V(x,z,t) and U(ω,t)U(\omega,t), 𝒬\mathcal{Q} can also be divided into two regions, namely the continuation region and the jump region denoted by CRCR and JRJR (see the illustration in Fig. 1) that

CR:={(ω,t)|(1p)UωωU<0}={(ω,t)|ω<ω(t)},\displaystyle CR:=\big{\{}(\omega,t)|(1-p)U-\omega\partial_{\omega}U<0\big{\}}=\big{\{}(\omega,t)|\omega<\omega^{*}(t)\big{\}}, (2.31)
JR:={(ω,t)|(1p)UωωU=0}={(ω,t)|ωω(t)}.\displaystyle JR:=\big{\{}(\omega,t)|(1-p)U-\omega\partial_{\omega}U=0\big{\}}=\big{\{}(\omega,t)|\omega\geq\omega^{*}(t)\big{\}}. (2.32)

Later, we will rigorously characterize ω(t)\omega^{*}(t) and two regions CRCR and JRJR in analytical form in Theorem 4.2.

To tackle the nonlinear parabolic variational inequality (2.30), we employ the convex dual transform that

u(y,t)=maxω>0[U(ω,t)ωy].u(y,t)=\max\limits_{\omega>0}[U(\omega,t)-\omega y].

As ωω(U(ω,t)ωy)=ωωU<0\partial_{\omega\omega}(U(\omega,t)-\omega y)=\partial_{\omega\omega}U<0, U(ω,t)ωyU(\omega,t)-\omega y is concave in ω\omega. It implies that the critical value ωy\omega_{y} satisfies

ωU(ωy,t)=y>0.\partial_{\omega}U(\omega_{y},t)=y>0. (2.33)

By ωωU<0\partial_{\omega\omega}U<0, there exists I(y,t)I(y,t), the inverse of ωU\partial_{\omega}U in ω\omega such that

ωy=(ωU)1(y,t)=I(y,t)>0.\omega_{y}=(\partial_{\omega}U)^{-1}(y,t)=I(y,t)>0. (2.34)

Then

u(y,t)=U(I(y,t),t)yI(y,t),u(y,t)=U(I(y,t),t)-yI(y,t), (2.35)

which leads to

yu(y,t)=ωU(I(y,t),t)yI(y,t)I(y,t)yyI(y,t)=I(y,t)<0,\displaystyle\partial_{y}u(y,t)=\partial_{\omega}U(I(y,t),t)\partial_{y}I(y,t)-I(y,t)-y\partial_{y}I(y,t)=-I(y,t)<0, (2.36)
yyu(y,t)=yI(y,t)=1ωωU(I(y,t),t)>0.\displaystyle\partial_{yy}u(y,t)=-\partial_{y}I(y,t)=-\frac{1}{\partial_{\omega\omega}U(I(y,t),t)}>0. (2.37)

Hence, I(y,t)I(y,t) strictly decreases in yy, u(y,t)u(y,t) strictly decreases and is convex in yy. Moreover, it follows from (2.35) that we have

tu(y,t)=ωU(I(y,t),t)tI(y,t)+tU(I(y,t),t)ytI(y,t)=tU(I(y,t),t).\displaystyle\partial_{t}u(y,t)=\partial_{\omega}U(I(y,t),t)\partial_{t}I(y,t)+\partial_{t}U(I(y,t),t)-y\partial_{t}I(y,t)=\partial_{t}U(I(y,t),t). (2.38)

In addition, define y0(t):=ωU(0,t)y_{0}(t):=\partial_{\omega}U(0,t), which implies that

yu(y0(t),t)=I(y0(t),t)=0.\partial_{y}u(y_{0}(t),t)=-I(y_{0}(t),t)=0. (2.39)

Combining (2.35) with the boundary condition (2.39), we obtain

u(y0(t),t)=U(I(y0(t),t),t)y0(t)I(y0(t),t)=U(0,t)=0.u(y_{0}(t),t)=U(I(y_{0}(t),t),t)-y_{0}(t)I(y_{0}(t),t)=U(0,t)=0.

Therefore, we have

U(ω,t)=miny(0,y0(t)][u(y,t)+yω],U(\omega,t)=\min\limits_{y\in(0,y_{0}(t)]}[u(y,t)+y\omega],

Let yωy_{\omega} be the critical value satisfying yu(yω,t)+ω=0\partial_{y}u(y_{\omega},t)+\omega=0, it holds that

U(ω,t)=u(yω,t)+ωyω.U(\omega,t)=u(y_{\omega},t)+\omega y_{\omega}. (2.40)

The linear dual variational inequality of (2.30) can be written as

{max{tu+12μ2σ2y2yyu+δyyuδuf(y),(1p)u+pyyu}=0,(y,t)(0,y0(t))×(0,T],u(y0(t),t)=yu(y0(t),t)=0,u(y,T)=p1py11p,y0,\left\{\begin{array}[]{l}\max\left\{\partial_{t}u+\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}y^{2}\partial_{yy}u+\delta y\partial_{y}u-\delta u-f(y),(1-p)u+py\partial_{y}u\right\}=0,\\ \hfill(y,t)\in(0,y_{0}(t))\times(0,T],\\ u(y_{0}(t),t)=\partial_{y}u(y_{0}(t),t)=0,\\ u(y,T)=\frac{p}{1-p}y^{1-\frac{1}{p}},\quad y\geq 0,\end{array}\right. (2.41)

where

f(y)={αyα1p1p,if yαp,p1py11p,if 1<y<αp,y11p,if y1,\displaystyle f(y)=\left\{\begin{array}[]{ll}\alpha y-\frac{\alpha^{1-p}}{1-p},&\mbox{if }y\geq\alpha^{-p},\\ -\frac{p}{1-p}y^{1-\frac{1}{p}},&\mbox{if }1<y<\alpha^{-p},\\ y-\frac{1}{1-p},&\mbox{if }y\leq 1,\end{array}\right.

which is continuously differentiable in yy. Moreover, we define y(t)=ωU(ω(t),t)y^{*}(t)=\partial_{\omega}U(\omega^{*}(t),t).

3 The Solution to the Dual Variational Inequality (2.41)

3.1 Auxiliary dual variational inequality

Taking advantage of the boundary condition of u(y,t)u(y,t) on y0(t)y_{0}(t), we can expand the solution u(y,t)u(y,t) to the problem (2.41) from (0,y0(t))×(0,T](0,y_{0}(t))\times(0,T] to the enlarged domain 𝒬=+×[0,T)\mathcal{Q}=\mathbb{R}^{+}\times[0,T). Let us consider u^(y,t)\hat{u}(y,t) that satisfies the auxiliary variational inequality on 𝒬\mathcal{Q} that

{max{tu^+12μ2σ2y2yyu^+δyyu^δu^f(y),(1p)u^+pyyu^,u^}=0,(y,t)𝒬,u^(y,T)=p1py11p,y0.\left\{\begin{array}[]{l}\max\left\{\partial_{t}\hat{u}+\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}y^{2}\partial_{yy}\hat{u}+\delta y\partial_{y}\hat{u}-\delta\hat{u}-f(y),\ (1-p)\hat{u}+py\partial_{y}\hat{u},\ -\hat{u}\right\}=0,\quad(y,t)\in\mathcal{Q},\\ \hat{u}(y,T)=\frac{p}{1-p}y^{1-\frac{1}{p}},\quad y\geq 0.\end{array}\right. (3.1)

It follows that

u(y,t)=u^(y,t),(y,t)(0,y0(t))×(0,T].u(y,t)=\hat{u}(y,t),\quad(y,t)\in(0,y_{0}(t))\times(0,T].

For the variational inequality above, we consider the following regimes and associated free boundaries:

:={(y,t)𝒬|u^(y,t)=0} (Function constraint region),\displaystyle\mathcal{F}:=\big{\{}(y,t)\in\mathcal{Q}~{}|~{}\hat{u}(y,t)=0\big{\}}{\mbox{ (Function\ constraint region)}},
𝒢:={(y,t)𝒬|(1p)u^(y,t)+pyyu^(y,t)=0} (Gradient constraint region),\displaystyle\mathcal{G}:=\big{\{}(y,t)\in\mathcal{Q}~{}|~{}(1-p)\hat{u}(y,t)+py\partial_{y}\hat{u}(y,t)=0\big{\}}{\mbox{ (Gradient\ constraint region)}},
:={(y,t)𝒬|(1p)u^(y,t)+pyyu^(y,t)<0,u^(y,t)>0} (Equation region).\displaystyle\mathcal{E}:=\big{\{}(y,t)\in\mathcal{Q}~{}|~{}(1-p)\hat{u}(y,t)+py\partial_{y}\hat{u}(y,t)<0,\hat{u}(y,t)>0\big{\}}{\mbox{ (Equation region)}}.

We plot in Figure 2 the numerical illustration of the above free boundaries as below:

Refer to caption
Figure 2: The numerical illustration of free boundaries in the variational inequality (3.1)(3.1)

To simplify some analysis, let us further set y=esy=e^{s},τ=Tt\tau=T-t and u~(s,τ)=u^(y,t)\tilde{u}(s,\tau)=\hat{u}(y,t). It follows that u~(s,τ)\tilde{u}(s,\tau) satisfies

{min{τu~12μ2σ2ssu~(δ12μ2σ2)su~+δu~+f~(s),(p1)u~psu~,u~}=0,(s,τ)Ω,u~(s,0)=p1pep1ps,s,\left\{\begin{array}[]{l}\min\left\{\partial_{\tau}\tilde{u}-\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}\partial_{ss}\tilde{u}-(\delta-\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}})\partial_{s}\tilde{u}+\delta\tilde{u}+\tilde{f}(s),\ (p-1)\tilde{u}-p\partial_{s}\tilde{u},\ \tilde{u}\right\}=0,\quad(s,\tau)\in\Omega,\\ \tilde{u}(s,0)=\frac{p}{1-p}e^{\frac{p-1}{p}s},\quad s\in\mathbb{R},\end{array}\right. (3.2)

where Ω=(,+)×(0,T]\Omega=(-\infty,+\infty)\times(0,T] and

f~(s)={αesα1p1p,if splnα,p1pep1ps,if 0<s<plnα,es11p,if s0.\displaystyle\tilde{f}(s)=\left\{\begin{array}[]{ll}\alpha e^{s}-\frac{\alpha^{1-p}}{1-p},&\mbox{if }s\geq-p\ln\alpha,\\ -\frac{p}{1-p}e^{\frac{p-1}{p}s},&\mbox{if }0<s<-p\ln\alpha,\\ e^{s}-\frac{1}{1-p},&\mbox{if }s\leq 0.\end{array}\right.

The transformed regimes and the associated free boundaries of the variational inequality (3.2) are plotted in Figure 3 as below.

Refer to caption
Figure 3: The numerical illustration of free boundaries in the variational inequality (3.2)(3.2)

Considering

v(s,τ):=e1ppsu~(s,τ),v(s,\tau):=e^{\frac{1-p}{p}s}\tilde{u}(s,\tau), (3.4)

we can work with another auxiliary dual variational inequality of v(s,τ)v(s,\tau) that

{min{τvsv+e1ppsf~(s),sv(s,τ),v(s,τ)}=0,(s,τ)Ω,v(s,0)=p1p,s,\displaystyle\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}v-\mathcal{L}_{s}v+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}v(s,\tau),v(s,\tau)\right\}=0,\quad(s,\tau)\in\Omega,\\ v(s,0)=\frac{p}{1-p},\quad s\in\mathbb{R},\end{array}\right. (3.7)

where

sv=12μ2σ2ssv(2p2pμ2σ2δ)sv(1pδμ2(1p)2p2σ2)v.\mathcal{L}_{s}v=\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}\partial_{ss}v-\left(\frac{2-p}{2p}\frac{\mu^{2}}{\sigma^{2}}-\delta\right)\partial_{s}v-\left(\frac{1}{p}\delta-\frac{\mu^{2}(1-p)}{2p^{2}\sigma^{2}}\right)v.

In what follows, we will first study the existence and uniqueness of the solution to the auxiliary problem (3.7) and investigate its associated free boundary curve. Then, based on the transform (3.4), we can examine the auxiliary variational inequalities (3.2) and (3.1). Finally, we can conclude the existence and uniqueness of the solution to the dual variational inequality (2.41).

3.2 Characterization of the free boundary in (3.7)

Let us first analyze the auxiliary variational inequality (3.7), which is a parabolic variational inequality with both gradient constraint and function constraint. We can obtain the existence and uniqueness of the solution in Wq,loc2,1(Ω)C(Ω¯)W^{2,1}_{q,loc}(\Omega)\cap C(\overline{\Omega}) to problem (3.7) in the next result, where the Sobolev space Wq,loc2,1W^{2,1}_{q,loc} is defined by

Wq,loc2,1(Ω)={v(s,τ)|v,sv,ssv,τvq(Ω),ΩΩ},1<q<.W^{2,1}_{q,loc}(\Omega)=\big{\{}v(s,\tau)|v,\partial_{s}v,\partial_{ss}v,\partial_{\tau}v\in\mathcal{L}^{q}(\Omega^{\prime}),\;\Omega^{\prime}\subset\subset\Omega\big{\}},\quad 1<q<\infty.

In order to obtain the existence and properties of the solution to problem (3.7), we first consider the following problem, for any N>0N>0, vNv_{N} satisfies

{min{τvNsvN+e1ppsf~(s),svN(s,τ),vN(s,τ)}=0,(s,τ)ΩN,vN(s,0)=p1p,s>N,vN(N,τ)=p1p,τ[0,T],\displaystyle\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}v_{N}-\mathcal{L}_{s}v_{N}+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}v_{N}(s,\tau),v_{N}(s,\tau)\right\}=0,\quad(s,\tau)\in\Omega_{N},\\ v_{N}(s,0)=\frac{p}{1-p},\quad s>-N,\\ v_{N}(-N,\tau)=\frac{p}{1-p},\quad\tau\in[0,T],\end{array}\right. (3.11)

where ΩN=(N,+)×(0,T]\Omega_{N}=(-N,+\infty)\times(0,T].

Lemma 3.1.

There exists a solution vN(s,τ)Wq,loc2,1(ΩN)C(ΩN¯)v_{N}(s,\tau)\in W^{2,1}_{q,loc}(\Omega_{N})\cap C(\overline{\Omega_{N}}) to problem (3.11). Moreover, we have

0vN(s,τ)p1p,(s,τ)ΩN,\displaystyle 0\leq v_{N}(s,\tau)\leq\frac{p}{1-p},\quad(s,\tau)\in\Omega_{N}, (3.12)
τvN(s,τ)0,(s,τ)ΩN,\displaystyle\partial_{\tau}v_{N}(s,\tau)\leq 0,\quad(s,\tau)\in\Omega_{N}, (3.13)
lims+vN(s,τ)=0.,\displaystyle\lim\limits_{s\rightarrow+\infty}v_{N}(s,\tau)=0., (3.14)

and the solution satisfying (3.12) is unique.

Proof.

We can solve the problem (3.11) using the standard penalty approximation method. Consider vNεv_{N}^{\varepsilon} satisfies

{τvNεsvNε+e1ppsf~(s)+βε(vNε)+sβε(svNε)=0,(s,τ)ΩN,vNε(s,0)=p1p,s>N,vNε(N,τ)=p1p,τ[0,T],\displaystyle\left\{\begin{array}[]{ll}\partial_{\tau}v_{N}^{\varepsilon}-\mathcal{L}_{s}v_{N}^{\varepsilon}+e^{\frac{1-p}{p}s}\tilde{f}(s)+\beta_{\varepsilon}(v_{N}^{\varepsilon})+s\beta_{\varepsilon}(-\partial_{s}v_{N}^{\varepsilon})=0,\quad(s,\tau)\in\Omega_{N},\\ v_{N}^{\varepsilon}(s,0)=\frac{p}{1-p},\quad s>-N,\\ v_{N}^{\varepsilon}(-N,\tau)=\frac{p}{1-p},\quad\tau\in[0,T],\end{array}\right. (3.18)

where βε(λ)\beta_{\varepsilon}(\lambda) is the penalty function satisfying

βε()C2(,+),βε()0,βε()0,\displaystyle\beta_{\varepsilon}(\cdot)\in C^{2}(-\infty,+\infty),\quad\beta_{\varepsilon}(\cdot)\leq 0,\quad\beta_{\varepsilon}^{\prime}(\cdot)\geq 0,
limε0βε(λ)={0,λ>0,,λ<0.\displaystyle\lim\limits_{\varepsilon\rightarrow 0}\beta_{\varepsilon}(\lambda)=\left\{\begin{array}[]{ll}0,&\lambda>0,\\ -\infty,&\lambda<0.\end{array}\right.

Using the standard fixed point theorem, we are able to show that there exists a solution vNε(s,τ)Wq,loc2,1(ΩN)C(ΩN¯)v_{N}^{\varepsilon}(s,\tau)\in W^{2,1}_{q,loc}(\Omega_{N})\cap C(\overline{\Omega_{N}}) to the penalty problem (3.18). Letting ε0\varepsilon\rightarrow 0, we obtain a solution vN(s,τ)Wq,loc2,1(ΩN)C(ΩN¯)v_{N}(s,\tau)\in W^{2,1}_{q,loc}(\Omega_{N})\cap C(\overline{\Omega_{N}}) to problem (3.11).

The estimate (3.12) follows from the facts svN0,vN0\partial_{s}v_{N}\leq 0,v_{N}\geq 0 and the boundary condition vN(N,τ)=p1pv_{N}(-N,\tau)=\frac{p}{1-p}. Moreover, based on the boundary condition vN(N,τ)=p1pv_{N}(-N,\tau)=\frac{p}{1-p}, we have the uniqueness of the solution to problem (3.11) and then the comparison principle for problem (3.11) holds true.

Now we will show (3.13). For any 0<δ<T0<\delta<T, set vδ(s,τ)=vN(s,τ+δ)v_{\delta}(s,\tau)=v_{N}(s,\tau+\delta), then vδ(s,τ)v_{\delta}(s,\tau) satisfies

{min{τvδsvδ+e1ppsf~(s),svδ,vδ}=0,(s,τ)(N,+)×(0,Tδ],vδ(s,0)=vN(s,δ)p1p=vN(s,0),s>N,vδ(N,τ)=p1p=vN(N,τ),τ[0,Tδ].\displaystyle\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}v_{\delta}-\mathcal{L}_{s}v_{\delta}+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}v_{\delta},v_{\delta}\right\}=0,\quad(s,\tau)\in(-N,+\infty)\times(0,T-\delta],\\ v_{\delta}(s,0)=v_{N}(s,\delta)\leq\frac{p}{1-p}=v_{N}(s,0),\quad s>-N,\\ v_{\delta}(-N,\tau)=\frac{p}{1-p}=v_{N}(-N,\tau),\quad\tau\in[0,T-\delta].\end{array}\right. (3.23)

Using the comparison principle between (3.11) and (3.23), we have that

vN(s,τ+δ)=vδ(s,τ)vN(s,τ),v_{N}(s,\tau+\delta)=v_{\delta}(s,\tau)\leq v_{N}(s,\tau),

which leads to the desired result (3.13).

For each τ>0\tau>0, define

ZN(τ)=min{s|vN(s,τ)=0}.Z_{N}(\tau)=\min\{s|v_{N}(s,\tau)=0\}.

We next show that ZN(τ)Z_{N}(\tau) is finite for τ(0,T]\tau\in(0,T]. Suppose that there exists a τ0>0\tau_{0}>0 such that ZN(τ0)=+Z_{N}(\tau_{0})=+\infty. Together with (3.13), it holds that

vN(s,τ)>0,(s,τ)(N,+)×(0,τ0),v_{N}(s,\tau)>0,\quad(s,\tau)\in(-N,+\infty)\times(0,\tau_{0}),

which implies

{min{τvNsvN+e1ppsf~(s),svN(s,τ)}=0,(s,τ)(N,+)×(0,τ1),vN(s,0)=p1p,s>N,vN(N,τ)=p1p,τ[0,τ1],\displaystyle\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}v_{N}-\mathcal{L}_{s}v_{N}+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}v_{N}(s,\tau)\right\}=0,\quad(s,\tau)\in(-N,+\infty)\times(0,\tau_{1}),\\ v_{N}(s,0)=\frac{p}{1-p},\quad s>-N,\\ v_{N}(-N,\tau)=\frac{p}{1-p},\quad\tau\in[0,\tau_{1}],\end{array}\right. (3.27)

where 0<τ1τ00<\tau_{1}\leq\tau_{0}.

Note that

e1ppsf~(s)\displaystyle e^{\frac{1-p}{p}s}\tilde{f}(s) =\displaystyle= αe1psα1p1pe1pps\displaystyle\alpha e^{\frac{1}{p}s}-\frac{\alpha^{1-p}}{1-p}e^{\frac{1-p}{p}s}
=\displaystyle= e1ps(αα1p1pes)+,ass+,\displaystyle e^{\frac{1}{p}s}\left(\alpha-\frac{\alpha^{1-p}}{1-p}e^{-s}\right)\rightarrow+\infty,\quad{\rm as}\;s\rightarrow+\infty,

it follows that there exists a constant s0s_{0} such that

e1ppsf~(s)3α4e1ps,ss0.e^{\frac{1-p}{p}s}\tilde{f}(s)\geq\frac{3\alpha}{4}e^{\frac{1}{p}s},\quad s\geq s_{0}.

Let v~(s,τ)=p1pα2(e1pse1ps0)τ\tilde{v}(s,\tau)=\frac{p}{1-p}-\frac{\alpha}{2}(e^{\frac{1}{p}s}-e^{\frac{1}{p}s_{0}})\tau. We next show that v~(s,τ)\tilde{v}(s,\tau) is a super-solution to (3.27) on (s0,+)×(0,τ1)(s_{0},+\infty)\times(0,\tau_{1}).

When τ1\tau_{1} is small enough, we can deduce

τv~sv~+e1ppsf~(s)\displaystyle\partial_{\tau}\tilde{v}-\mathcal{L}_{s}\tilde{v}+e^{\frac{1-p}{p}s}\tilde{f}(s)
=\displaystyle= α2(e1pse1ps0)+(δpμ2(1p)2pσ2)(p1p+α2e1ps0τ)+e1ppsf~(s)0.\displaystyle-\frac{\alpha}{2}\left(e^{\frac{1}{p}s}-e^{\frac{1}{p}s_{0}}\right)+\left(\frac{\delta}{p}-\frac{\mu^{2}(1-p)}{2p\sigma^{2}}\right)\left(\frac{p}{1-p}+\frac{\alpha}{2}e^{\frac{1}{p}s_{0}}\tau\right)+e^{\frac{1-p}{p}s}\tilde{f}(s)\geq 0.

Together with vN(s,τ)p1pv_{N}(s,\tau)\leq\frac{p}{1-p}, we know that v~(s,τ)\tilde{v}(s,\tau) satisfies

{min{τv~sv~+e1ppsf~(s),sv~(s,τ)}=0,(s,τ)(s0,+)×(0,τ1),v~(s,0)=p1p,s>s0,v~(N,τ)=p1pvN(s0,τ),τ[0,τ1].\displaystyle\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}\tilde{v}-\mathcal{L}_{s}\tilde{v}+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}\tilde{v}(s,\tau)\right\}=0,\quad(s,\tau)\in(s_{0},+\infty)\times(0,\tau_{1}),\\ \tilde{v}(s,0)=\frac{p}{1-p},\quad s>s_{0},\\ \tilde{v}(-N,\tau)=\frac{p}{1-p}\geq v_{N}(s_{0},\tau),\quad\tau\in[0,\tau_{1}].\end{array}\right.

The comparison principle implies that

vN(s,τ)v~(s,τ),(s,τ)(s0,+)×(0,τ1].v_{N}(s,\tau)\leq\tilde{v}(s,\tau),\quad(s,\tau)\in(s_{0},+\infty)\times(0,\tau_{1}].

Moreover, we have

v~(s,τ)<0,s>pln(e1ps0+2αp(1p)τ1),\tilde{v}(s,\tau)<0,\quad s>p\ln\left(e^{\frac{1}{p}s_{0}}+\frac{2}{\alpha}\frac{p}{(1-p)\tau_{1}}\right),

which leads to

vN(s,τ)<0,s>pln(e1ps0+2αp(1p)τ1),v_{N}(s,\tau)<0,\quad s>p\ln\left(e^{\frac{1}{p}s_{0}}+\frac{2}{\alpha}\frac{p}{(1-p)\tau_{1}}\right),

which is a contradiction. As a result, Zn(τ)Z_{n}(\tau) is finite for each τ>0\tau>0, and it implies that (3.14) holds. ∎

Proposition 3.2.

There exists a solution v(s,τ)Wq,loc2,1(Ω)C(Ω¯)v(s,\tau)\in W^{2,1}_{q,loc}(\Omega)\cap C(\overline{\Omega}) to problem (3.7). Moreover, we have

0v(s,τ)p1p,(s,τ)Ω,\displaystyle 0\leq v(s,\tau)\leq\frac{p}{1-p},\quad(s,\tau)\in\Omega, (3.29)
τv(s,τ)0,(s,τ)Ω,\displaystyle\partial_{\tau}v(s,\tau)\leq 0,\quad(s,\tau)\in\Omega, (3.30)
lims+v(s,τ)=0.\displaystyle\lim\limits_{s\rightarrow+\infty}v(s,\tau)=0. (3.31)

The solution to problem (3.7) satisfying (3.29) and (3.31) is unique.

Proof.

Denote v(s,τ)=limN+vN(s,τ)v(s,\tau)=\lim\limits_{N\rightarrow+\infty}v_{N}(s,\tau), then v(s,τ)Wq,loc2,1(Ω)C(Ω¯)v(s,\tau)\in W^{2,1}_{q,loc}(\Omega)\cap C(\overline{\Omega}) is the solution of problem (3.7). It is easy to see that (3.29) and (3.30) can be derived from (3.12) and (3.13).

We next show (3.31). Suppose N1>N2N_{1}>N_{2}, then

vN1(N2,τ)p1p=vN2(N2,τ).v_{N_{1}}(-N_{2},\tau)\leq\frac{p}{1-p}=v_{N_{2}}(-N_{2},\tau).

By the comparison principle, we have

vN1(s,τ)vN2(s,τ),(s,τ)(N2,+)×(0,T].v_{N_{1}}(s,\tau)\leq v_{N_{2}}(s,\tau),\quad(s,\tau)\in(-N_{2},+\infty)\times(0,T].

It hence holds that

vN1(s,τ)=0,(s,τ)(ZN2,+)×(0,T],v_{N_{1}}(s,\tau)=0,\quad(s,\tau)\in(Z_{N_{2}},+\infty)\times(0,T],

which implies that ZN(τ)Z_{N}(\tau) is decreasing in NN. This, together with (3.14), implies (3.31).

We are ready to show the uniqueness of the solution to problem (3.7) by contradiction. Suppose v1,v2v_{1},v_{2} are two solutions to the problem (3.7). Denote 𝒩={v1>v2}\mathcal{N}=\{v_{1}>v_{2}\}\neq\emptyset, and let τ0=inf{τ:(s,τ)𝒩},A=p𝒩{(s,τ):τ=τ0}\tau_{0}=\inf\{\tau:(s,\tau)\in\mathcal{N}\},\;A=\partial_{p}\mathcal{N}\cap\{(s,\tau):\tau=\tau_{0}\}. It then holds that

v1=v2,onA.v_{1}=v_{2},\quad{\rm on}\;A.

Denote 𝒩1=𝒩{(s,τ):sv1<sv2}\mathcal{N}_{1}=\mathcal{N}\cap\{(s,\tau):\partial_{s}v_{1}<\partial_{s}v_{2}\} and 𝒩2=𝒩{(s,τ):sv1sv2}\mathcal{N}_{2}=\mathcal{N}\cap\{(s,\tau):\partial_{s}v_{1}\geq\partial_{s}v_{2}\}. Suppose 𝒩1\mathcal{N}_{1}\neq\emptyset, by condition (3.31), it is easy to show that there exists a point (s0,τ0)p𝒩1A(s_{0},\tau_{0})\in\partial_{p}\mathcal{N}_{1}\cap A, which implies v1(s0,τ0)=v2(s0,τ0)v_{1}(s_{0},\tau_{0})=v_{2}(s_{0},\tau_{0}), and we have

{τv1sv1+e1ppsf~(s)=0,(s,τ)𝒩1,τv2sv2+e1ppsf~(s)0,(s,τ)𝒩1,v1=v2orsv1=sv2,(s,τ)p𝒩1.\displaystyle\left\{\begin{array}[]{ll}\partial_{\tau}v_{1}-\mathcal{L}_{s}v_{1}+e^{\frac{1-p}{p}s}\tilde{f}(s)=0,\quad(s,\tau)\in\mathcal{N}_{1},\\ \partial_{\tau}v_{2}-\mathcal{L}_{s}v_{2}+e^{\frac{1-p}{p}s}\tilde{f}(s)\geq 0,\quad(s,\tau)\in\mathcal{N}_{1},\\ v_{1}=v_{2}\ {\rm or}\;\partial_{s}v_{1}=\partial_{s}v_{2},\quad(s,\tau)\in\partial_{p}\mathcal{N}_{1}.\\ \end{array}\right.

By condition (3.29) and the maximum principle, we know

v2(s,τ)v1(s,τ),(s,τ)𝒩1,v_{2}(s,\tau)\geq v_{1}(s,\tau),\quad(s,\tau)\in\mathcal{N}_{1},

which contradicts the definition of 𝒩\mathcal{N} and hence 𝒩𝒩2\mathcal{N}\subset\mathcal{N}_{2}.

We then conclude that

{sv1sv2,(s,τ)𝒩,v1=v2,(s,τ)p𝒩.\displaystyle\left\{\begin{array}[]{ll}\partial_{s}v_{1}\geq\partial_{s}v_{2},\quad(s,\tau)\in\mathcal{N},\\ v_{1}=v_{2},\quad(s,\tau)\in\partial_{p}\mathcal{N}.\\ \end{array}\right.

This, together with the condition (3.31), implies that

v1(s,τ)v2(s,τ),(s,τ)𝒩,v_{1}(s,\tau)\leq v_{2}(s,\tau),\quad(s,\tau)\in\mathcal{N},

which is a contradiction to the definition of 𝒩\mathcal{N}. The proof is then complete. ∎

As a direct result of the uniqueness of solution to problem (3.7), the comparison principle for problem (3.7) holds.

Recall the transformation in (3.4), we have the following regions (see the numerical illustrations in Figure 3) that

={(s,τ)Ω|v(s,τ)=0} (Function constraint region),\displaystyle\mathcal{F}=\big{\{}(s,\tau)\in\Omega~{}|~{}v(s,\tau)=0\big{\}}{\mbox{ (Function\ constraint region)}},
𝒢={(s,τ)Ω|sv(s,τ)=0} (Gradient constraint region),\displaystyle\mathcal{G}=\big{\{}(s,\tau)\in\Omega~{}|~{}\partial_{s}v(s,\tau)=0\big{\}}{\mbox{ (Gradient\ constraint region)}},
={(s,τ)Ω|sv(s,τ)<0,v(s,τ)>0} (Equation region).\displaystyle\mathcal{E}=\big{\{}(s,\tau)\in\Omega~{}|~{}\partial_{s}v(s,\tau)<0,v(s,\tau)>0\big{\}}{\mbox{ (Equation region)}}.

Note that v(s,τ)v(s,\tau) satisfies sv(s,τ)0\partial_{s}v(s,\tau)\leq 0 and v(s,τ)0v(s,\tau)\geq 0. For each τ>0\tau>0, let us define

Z(τ):=inf{s|v(s,τ)=0}.Z(\tau):=\inf\big{\{}s~{}|~{}v(s,\tau)=0\big{\}}. (3.34)
Proposition 3.3.

The curve Z(τ)Z(\tau) defined in (3.34) satisfies plnα<Z(τ)<+-p\ln\alpha<Z(\tau)<+\infty for τ(0,T]\tau\in(0,T] and

={(s,τ)𝒬|sZ(τ)}.\mathcal{F}=\big{\{}(s,\tau)\in\mathcal{Q}~{}|~{}s\geq Z(\tau)\big{\}}. (3.35)

Moreover, Z(τ)Z(\tau) strictly decreases in τ\tau. In particular,

limτ0+Z(τ)=+.\lim\limits_{\tau\rightarrow 0^{+}}Z(\tau)=+\infty. (3.36)
Proof.

The result (3.35) follows from definitions of Z(τ)Z(\tau) and \mathcal{F}. By the variational inequality (3.7), we have

τvsv+e1ppsf~(s)0,ifv=0,\partial_{\tau}v-\mathcal{L}_{s}v+e^{\frac{1-p}{p}s}\tilde{f}(s)\geq 0,\quad\text{if}\ v=0,

which leads to splnαln(1p)s\geq-p\ln\alpha-\ln(1-p). Hence, by the definition of Z(τ)Z(\tau), we know Z(τ)>plnαZ(\tau)>-p\ln\alpha.

Next, we show that Z(τ)Z(\tau) is finite for τ(0,T]\tau\in(0,T]. Suppose that there exists a τ0>0\tau_{0}>0 such that Z(τ0)=+Z(\tau_{0})=+\infty. It then holds that

v(s,τ)>0,(s,τ)×(0,τ0],v(s,\tau)>0,\quad(s,\tau)\in\mathbb{R}\times(0,\tau_{0}],

which implies that v(s,τ)v(s,\tau) satisfies

{min{τvsv+e1ppsf~(s),sv(s,τ)}=0,(s,τ)×(0,τ0],v(s,0)=p1p,s.\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}v-\mathcal{L}_{s}v+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}v(s,\tau)\right\}=0,\quad(s,\tau)\in\mathbb{R}\times(0,\tau_{0}],\\ v(s,0)=\frac{p}{1-p},\quad s\in\mathbb{R}.\end{array}\right. (3.37)

Note that

e1ppsf~(s)=αe1psα1p1pe1pps+ass+.e^{\frac{1-p}{p}s}\tilde{f}(s)=\alpha e^{\frac{1}{p}s}-\frac{\alpha^{1-p}}{1-p}e^{\frac{1-p}{p}s}\rightarrow+\infty\ \text{as}\ s\rightarrow+\infty.

There exists a constant s0s_{0} such that

e1ppsf~(s)α2e1ps,ss0.e^{\frac{1-p}{p}s}\tilde{f}(s)\geq\frac{\alpha}{2}e^{\frac{1}{p}s},\quad s\geq s_{0}.

Let v~(s,τ):=p1pα2(e1pse1ps0)τ\tilde{v}(s,\tau):=\frac{p}{1-p}-\frac{\alpha}{2}(e^{\frac{1}{p}s}-e^{\frac{1}{p}s_{0}})\tau. We next show that v~(s,τ)\tilde{v}(s,\tau) is a super-solution to (3.37) on (s0,+)×(0,τ0)(s_{0},+\infty)\times(0,\tau_{0}). In view that

τv~sv~+e1ppsf~(s)\displaystyle\partial_{\tau}\tilde{v}-\mathcal{L}_{s}\tilde{v}+e^{\frac{1-p}{p}s}\tilde{f}(s)
=\displaystyle= α2(e1pse1ps0)+(δpμ2(1p)2p2σ2)(p1p+α2e1ps0τ)+e1ppsf~(s)0.\displaystyle-\frac{\alpha}{2}(e^{\frac{1}{p}s}-e^{\frac{1}{p}s_{0}})+\left(\frac{\delta}{p}-\frac{\mu^{2}(1-p)}{2p^{2}\sigma^{2}}\right)\left(\frac{p}{1-p}+\frac{\alpha}{2}e^{\frac{1}{p}s_{0}}\tau\right)+e^{\frac{1-p}{p}s}\tilde{f}(s)\geq 0.

Together with p1pv(s,τ)\frac{p}{1-p}\geq v(s,\tau), we know that v~(s,τ)\tilde{v}(s,\tau) satisfies

{min{τv~sv~+e1ppsf~(s),sv~(s,τ)}0,(s,τ)(s0,+)×(0,τ0],v~(s,0)=p1p,s(s0,+),v~(s0,τ)=p1pv(s0,τ),τ(0,τ0].\displaystyle\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}\tilde{v}-\mathcal{L}_{s}\tilde{v}+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}\tilde{v}(s,\tau)\right\}\geq 0,&(s,\tau)\in(s_{0},+\infty)\times(0,\tau_{0}],\\ \tilde{v}(s,0)=\frac{p}{1-p},&s\in(s_{0},+\infty),\\ \tilde{v}(s_{0},\tau)=\frac{p}{1-p}\geq v(s_{0},\tau),&\tau\in(0,\tau_{0}].\end{array}\right.

The comparison principle implies that

v(s,τ)v~(s,τ),(s,τ)(s0,+)×(0,τ0].v(s,\tau)\leq\tilde{v}(s,\tau),\quad(s,\tau)\in(s_{0},+\infty)\times(0,\tau_{0}].

Moreover, it is easy to see that

v~(s,τ)<0,s>pln(e1ps0+2αp(1p)τ0),\tilde{v}(s,\tau)<0,\quad s>p\ln\Big{(}e^{\frac{1}{p}s_{0}}+\frac{2}{\alpha}\frac{p}{(1-p)\tau_{0}}\Big{)},

which implies that

v(s,τ)<0,s>pln(e1ps0+2αp(1p)τ0),v(s,\tau)<0,\quad s>p\ln\Big{(}e^{\frac{1}{p}s_{0}}+\frac{2}{\alpha}\frac{p}{(1-p)\tau_{0}}\Big{)},

leading to a contradiction.

Finally, we show the strict monotonicity of Z(τ)Z(\tau). For any τ0>0\tau_{0}>0, suppose Z(τ0)=s0Z(\tau_{0})=s_{0}, i.e. v(s0,τ0)=0.v(s_{0},\tau_{0})=0. According to τv(s,τ)0\partial_{\tau}v(s,\tau)\leq 0, we have v(s0,τ)=0v(s_{0},\tau)=0, τ(τ0,T]\tau\in(\tau_{0},T]. By the definition (3.34) of Z(τ)Z(\tau), we obtain

Z(τ)s0,τ(τ0,T].Z(\tau)\leq s_{0},\quad\tau\in(\tau_{0},T].

Hence, we obtain the monotonicity of Z(τ)Z(\tau). Suppose that Z(τ)Z(\tau) is not strictly monotone and there exists τ1<τ2\tau_{1}<\tau_{2}, such that

Z(τ)=s0,τ[τ1,τ2].Z(\tau)=s_{0},\quad\tau\in[\tau_{1},\tau_{2}].

Denote Γ:={s0}×(τ1,τ2)\Gamma:=\{s_{0}\}\times(\tau_{1},\tau_{2}). Then we have

{τvsv=e1ppsf~(s),(s,τ)(s0ε,s0)×(τ1,τ2),v|Γ=sv|Γ=0,\displaystyle\left\{\begin{array}[]{ll}\partial_{\tau}v-\mathcal{L}_{s}v=-e^{\frac{1-p}{p}s}\tilde{f}(s),\quad(s,\tau)\in(s_{0}-\varepsilon,s_{0})\times(\tau_{1},\tau_{2}),\\ v|_{\Gamma}=\partial_{s}v|_{\Gamma}=0,\end{array}\right.

where ε\varepsilon is small enough. It then follows that

{τ(τv)s(τv)=0,(s,τ)(s0ε,s0)×(τ1,τ2),τv|Γ=sτv|Γ=0.\displaystyle\left\{\begin{array}[]{ll}\partial_{\tau}(\partial_{\tau}v)-\mathcal{L}_{s}(\partial_{\tau}v)=0,\quad(s,\tau)\in(s_{0}-\varepsilon,s_{0})\times(\tau_{1},\tau_{2}),\\ \partial_{\tau}v|_{\Gamma}=\partial_{s\tau}v|_{\Gamma}=0.\end{array}\right.

Together with the fact that τv0\partial_{\tau}v\leq 0, Hopf’s principle implies that

sτv|Γ>0 or τv0,(s,τ)(s0,s0+ε)×(τ1,τ2),\partial_{s\tau}v|_{\Gamma}>0\quad\mbox{ or }\quad\partial_{\tau}v\equiv 0,\quad(s,\tau)\in(s_{0},s_{0}+\varepsilon)\times(\tau_{1},\tau_{2}),

leading to a contradiction.

Moreover, it follows from the monotonicity of Z(τ)Z(\tau) and v(s,0)=p1p>0v(s,0)=\frac{p}{1-p}>0 that the result (3.36) holds. ∎

Let us next focus on the domain {sZ(τ)}\{s\leq Z(\tau)\}. In view of the definition of Z(τ)Z(\tau), v(s,τ)v(s,\tau) is a unique Wq,loc2,1(Ω)W^{2,1}_{q,loc}(\Omega) solution to problem (3.7). On the domain {sZ(τ)}\{s\leq Z(\tau)\}, v(s,τ)v(s,\tau) satisfies

{min{τvsv+e1ppsf~(s),sv(s,τ)}=0,(s,τ)Ω~,v(s,0)=p1p,s,sv(Z(τ),τ)=0,τ(0,T],\left\{\begin{array}[]{ll}\min\left\{\partial_{\tau}v-\mathcal{L}_{s}v+e^{\frac{1-p}{p}s}\tilde{f}(s),-\partial_{s}v(s,\tau)\right\}=0,&(s,\tau)\in\tilde{\Omega},\\ v(s,0)=\frac{p}{1-p},&s\in\mathbb{R},\\ \partial_{s}v(Z(\tau),\tau)=0,&\tau\in(0,T],\end{array}\right. (3.41)

where Ω~:=(,Z(τ))×(0,T]\tilde{\Omega}:=(-\infty,Z(\tau))\times(0,T]. In order to analyze the free boundary arising from gradient constraint, we follow the similar idea in Chen and Yi (2012) and consider the parabolic obstacle problem

{max{τw(s,τ)sw(s,τ)g(s),w(s,τ)}=0,(s,τ)Ω~,w(s,0)=0,s,w(Z(τ),τ)=0,τ(0,T],\left\{\begin{array}[]{ll}\max\big{\{}\partial_{\tau}w(s,\tau)-\mathcal{L}_{s}w(s,\tau)-g(s),w(s,\tau)\big{\}}=0,&(s,\tau)\in\tilde{\Omega},\\ w(s,0)=0,&s\in\mathbb{R},\\ w(Z(\tau),\tau)=0,&\tau\in(0,T],\end{array}\right. (3.42)

where

g(s)=(e1ppsf~(s))=αpe1pps(αpes)I{esαp}+1pe1pps(1es)I{es1}.g(s)=\Big{(}-e^{\frac{1-p}{p}s}\tilde{f}(s)\Big{)}^{\prime}=\frac{\alpha}{p}e^{\frac{1-p}{p}s}(\alpha^{-p}-e^{s})I_{\{e^{s}\geq\alpha^{-p}\}}+\frac{1}{p}e^{\frac{1-p}{p}s}(1-e^{s})I_{\{e^{s}\leq 1\}}. (3.43)

3.3 Characterization of the free boundary in problem (3.42)

Following the standard penalty approximation method as to show the existence of solution to the problem (3.7), it is easy to conclude the next result, and its proof is hence omitted.

Lemma 3.4.

There exists a unique w(s,τ)Wq,loc2,1(Ω~)C(Ω~¯)w(s,\tau)\in W^{2,1}_{q,loc}(\tilde{\Omega})\cap C(\overline{\tilde{\Omega}}) to problem (3.42) for any 1<q<+1<q<+\infty.

To study some properties of the free boundary in (3.42), let us first define

𝒢0:={(s,τ)Ω~|w(s,τ)=0},\displaystyle\mathcal{G}_{0}:=\big{\{}(s,\tau)\in\tilde{\Omega}~{}|~{}w(s,\tau)=0\big{\}},
0:={(s,τ)Ω~|w(s,τ)<0}.\displaystyle\mathcal{E}_{0}:=\big{\{}(s,\tau)\in\tilde{\Omega}~{}|~{}w(s,\tau)<0\big{\}}.
Proposition 3.5.

There exists a function T(s):(,+)[0,T]T(s):(-\infty,+\infty)\rightarrow[0,T] such that

𝒢0={(s,τ)|s,0τT(s)},\mathcal{G}_{0}=\big{\{}(s,\tau)~{}|~{}s\in\mathbb{R},0\leq\tau\leq T(s)\big{\}}, (3.44)

and T(s)T(s) is decreasing in ss such that

T(s)=0,s>0,\displaystyle T(s)=0,\quad s>0, (3.45)
T(s)>0,s<0.\displaystyle T(s)>0,\quad s<0. (3.46)

Particularly, T(s)T(s) is strictly decreasing on {s|0<T(s)<T}\{s~{}|~{}0<T(s)<T\} and T(s)T(s) is continuous.

Proof.

The conjectured free boundary ω(t)\omega^{*}(t) in Remark 2.2 and all the transformations in Section 2 imply that 𝒢0\mathcal{G}_{0} is connected in τ\tau direction. Note that w(s,0)=0w(s,0)=0, let us define

T(s):=sup{τ|w(s,τ)=0},s.T(s):=\sup\big{\{}\tau~{}|~{}w(s,\tau)=0\big{\}},\quad\forall s\in\mathbb{R}.

By the definitions of 𝒢0\mathcal{G}_{0} and T(s)T(s), we get the desired result (3.44).

We next show the monotonicity of T(s)T(s). By the variational inequality (3.42), we have

g(s)0,ifw(s,τ)=0,g(s)\geq 0,\quad{\rm if}\;w(s,\tau)=0,

which implies splnαs\leq-p\ln\alpha. That is, w(s,τ)<0w(s,\tau)<0 for s>plnαs>-p\ln\alpha, τ(0,T]\tau\in(0,T]. It follows that

{(s,τ)|s>plnα,τ(0,T]}0.\big{\{}(s,\tau)~{}|~{}s>-p\ln\alpha,~{}\tau\in(0,T]\big{\}}\subset\mathcal{E}_{0}.

For any s0plnαs_{0}\leq-p\ln\alpha such that T(s0)>0T(s_{0})>0, we define an auxiliary function

w~(s,τ):={0,if (s,τ)(,s0]×[0,T(s0)],w(s,τ),if (s,τ){(s0,+)×[0,T(s0)]}Ω~.\displaystyle\tilde{w}(s,\tau):=\left\{\begin{array}[]{ll}0,&\mbox{if }(s,\tau)\in(-\infty,s_{0}]\times[0,T(s_{0})],\\ w(s,\tau),&\mbox{if }(s,\tau)\in\{(s_{0},+\infty)\times[0,T(s_{0})]\}\cap\tilde{\Omega}.\end{array}\right.

We show that w~(s,τ)\tilde{w}(s,\tau) is the solution to problem (3.42) in the domain {×[0,T(s0)]}\{\mathbb{R}\times[0,T(s_{0})]\}. By the definition of w~(s,τ)\tilde{w}(s,\tau), we have that w~(s,0)=0\tilde{w}(s,0)=0, w~(s,τ)0\tilde{w}(s,\tau)\leq 0, and

{τw~sw~=0g(s),if (s,τ)(,s0]×[0,T(s0)],τw~sw~=τwswg(s),if (s,τ){(s0,+)×[0,T(s0)]}Ω~.\displaystyle\left\{\begin{array}[]{ll}\partial_{\tau}\tilde{w}-\mathcal{L}_{s}\tilde{w}=0\leq g(s),&\mbox{if }(s,\tau)\in(-\infty,s_{0}]\times[0,T(s_{0})],\\ \partial_{\tau}\tilde{w}-\mathcal{L}_{s}\tilde{w}=\partial_{\tau}w-\mathcal{L}_{s}w\leq g(s),&\mbox{if }(s,\tau)\in\{(s_{0},+\infty)\times[0,T(s_{0})]\}\cap\tilde{\Omega}.\end{array}\right.

Moreover, if w~(s,τ)<0\tilde{w}(s,\tau)<0, then w(s,τ)<0w(s,\tau)<0. Hence, we have

τw~sw~=τwsw=g(s),w~(s,τ)<0.\partial_{\tau}\tilde{w}-\mathcal{L}_{s}\tilde{w}=\partial_{\tau}w-\mathcal{L}_{s}w=g(s),\quad\tilde{w}(s,\tau)<0.

Thus, w~(s,τ)\tilde{w}(s,\tau) is a Wq,loc2,1W^{2,1}_{q,loc}-solution to problem (3.42) in the domain {×[0,T(s0)]}Ω~\{\mathbb{R}\times[0,T(s_{0})]\}\cap\tilde{\Omega}. The uniqueness of the solution to (3.42) yields that

w(s,τ)=w~(s,τ)=0,(s,τ)(,s0]×[0,T(s0)].w(s,\tau)=\tilde{w}(s,\tau)=0,\quad(s,\tau)\in(-\infty,s_{0}]\times[0,T(s_{0})].

By the definition of T(s)T(s), we obtain T(s)T(s0),s<s0T(s)\geq T(s_{0}),\quad\forall s<s_{0}, and T(s)T(s) is decreasing in ss.

Next, we show (3.45). Suppose that there exists s0>0s_{0}>0 such that T(s0)=τ0>0T(s_{0})=\tau_{0}>0, by the monotonicity of T(s)T(s), we have

{τwswg(s)0,(s,τ){[0,+)×[0,τ0]}Ω~,w(0,τ)=0,w(Z(τ),τ)=0,τ(0,τ0],w(s,0)=0,s+.\displaystyle\left\{\begin{array}[]{ll}\partial_{\tau}w-\mathcal{L}_{s}w\leq g(s)\leq 0,&(s,\tau)\in\{[0,+\infty)\times[0,\tau_{0}]\}\cap\tilde{\Omega},\\ w(0,\tau)=0,\quad w(Z(\tau),\tau)=0,&\tau\in(0,\tau_{0}],\\ w(s,0)=0,&s\in\mathbb{R}^{+}.\end{array}\right.

The strong maximum principle implies that

w(s,τ)<0,(s,τ)(0,+)×(0,τ0].w(s,\tau)<0,\quad(s,\tau)\in(0,+\infty)\times(0,\tau_{0}].

It contradicts with w(s0,τ)=0,τ(0,τ0].w(s_{0},\tau)=0,\quad\tau\in(0,\tau_{0}]. Hence, (3.45) holds true.

In view of the definition of T(s)T(s) and the fact w(s,τ)0w(s,\tau)\leq 0, we have

τw(s,0)0,s,\displaystyle\partial_{\tau}w(s,0)\leq 0,\quad\forall s\in\mathbb{R}, (3.50)
τw(s,T(s))0,s.\displaystyle\partial_{\tau}w(s,T(s))\leq 0,\quad\forall s\in\mathbb{R}. (3.51)

Suppose that there exists s1<0s_{1}<0 such that T(s1)=0T(s_{1})=0, then we have

τw(s,0)=sw(s,0)+g(s)>0,s(s1,0),\partial_{\tau}w(s,0)=\mathcal{L}_{s}w(s,0)+g(s)>0,\quad s\in(s_{1},0),

yielding a contraction to (3.50). Hence (3.46) follows.

Thanks to (3.51), we claim the strict monotonicity of T(s)T(s) in {s|0<T(s)<T}\big{\{}s~{}|~{}0<T(s)<T\big{\}}. Indeed, suppose that exists s1<s20s_{1}<s_{2}\leq 0 such that

0<T(s1)=T(s2)<T.0<T(s_{1})=T(s_{2})<T.

Then we have

w(s,T(s2))=0,s(s1,s2).w(s,T(s_{2}))=0,\quad s\in(s_{1},s_{2}).

Applying the equation τwsw=g(s)\partial_{\tau}w-\mathcal{L}_{s}w=g(s) at (s1,s2)×{T(s2)}(s_{1},s_{2})\times\{T(s_{2})\}, we have

τw|τ=T(s2)=(sw+g(s))|τ=T(s2)>0,s(s1,s2),\partial_{\tau}w|_{\tau=T(s_{2})}=(\mathcal{L}_{s}w+g(s))|_{\tau=T(s_{2})}>0,\quad s\in(s_{1},s_{2}),

which contradicts with (3.51). The claim therefore holds.

Following the proof of the strictly monotonicity of Z(τ)Z(\tau) in Theorem 3.5, we can conclude the continuity of T(s)T(s). ∎

As T(s)T(s) strictly decreases and is continuous in ss on 0<T(s)<T0<T(s)<T, there exists an inverse function of T(s)T(s) denoted by S(τ):=T1(τ)S(\tau):=T^{-1}(\tau), τ(0,T)\tau\in(0,T). Let us define

S(τ):={T1(τ),if τ(0,T),sup{s|T(s)=T},if τ=T.\displaystyle S(\tau):=\left\{\begin{array}[]{ll}T^{-1}(\tau),&\mbox{if }\tau\in(0,T),\\ \sup\big{\{}s~{}|~{}T(s)=T\big{\}},&\mbox{if }\tau=T.\end{array}\right. (3.54)
Lemma 3.6.

We have that

𝒢0={(s,τ)|sS(τ),τ(0,T]},\mathcal{G}_{0}=\big{\{}(s,\tau)~{}|~{}s\leq S(\tau),\tau\in(0,T]\big{\}}, (3.55)

where S(τ)S(\tau) is continuous and strictly decreases in τ\tau with

S(0)=limτ0+S(τ)=0.S(0)=\lim_{\tau\rightarrow 0^{+}}S(\tau)=0. (3.56)
Proof.

Note that T(s)T(s) strictly decreases in {s|0<T(s)<T}\{s~{}|~{}0<T(s)<T\}, we know S(τ)S(\tau) decreases in τ\tau. Because the strict monotonicity of T(s)T(s) is equivalent to the continuity of S(τ)S(\tau) and the continuity of T(s)T(s) is equivalent to the strict monotonicity of S(τ)S(\tau), we conclude that S(τ)C[0,T]S(\tau)\in C[0,T] and strictly decreases in τ\tau.

In view of the strict monotonicity of S(τ)S(\tau), let us define S(0):=limτ0+S(τ)S(0):=\lim_{\tau\rightarrow 0^{+}}S(\tau). It follows from (3.45)-(3.46) that S(0)=0S(0)=0, which completes the proof. ∎

We next establish the dependence of S(τ)S(\tau) on the parameter α\alpha in the following result.

Lemma 3.7.

The free boundary S(τ)S(\tau) of problem (3.42) is decreasing in α\alpha.

Proof.

By the definition of g(s)g(s), we have

gα=1pe1pps(αpespαp)I{esαp}<0.\displaystyle\frac{\partial g}{\partial\alpha}=\frac{1}{p}e^{\frac{1-p}{p}s}(\alpha^{-p}-e^{s}-p\alpha^{-p})I_{\{e^{s}\geq\alpha^{-p}\}}<0.

Let us choose 0<α1<α210<\alpha_{1}<\alpha_{2}\leq 1. It holds that

g1(s)\displaystyle g_{1}(s) =\displaystyle\overset{\triangle}{=} α1pe1pps(α1pes)I{esα1p}+1pe1pps(1es)I{es1}\displaystyle\frac{\alpha_{1}}{p}e^{\frac{1-p}{p}s}(\alpha_{1}^{-p}-e^{s})I_{\{e^{s}\geq\alpha_{1}^{-p}\}}+\frac{1}{p}e^{\frac{1-p}{p}s}(1-e^{s})I_{\{e^{s}\leq 1\}}
>\displaystyle> α2pe1pps(α2pes)I{esα2p}+1pe1pps(1es)I{es1}=g2(s).\displaystyle\frac{\alpha_{2}}{p}e^{\frac{1-p}{p}s}(\alpha_{2}^{-p}-e^{s})I_{\{e^{s}\geq\alpha_{2}^{-p}\}}+\frac{1}{p}e^{\frac{1-p}{p}s}(1-e^{s})I_{\{e^{s}\leq 1\}}\overset{\triangle}{=}g_{2}(s).

For i=1,2i=1,2, denote wi(s,τ)w_{i}(s,\tau) as the solution to the following problem

{max{τwi(s,τ)swi(s,τ)gi(s),wi(s,τ)}=0,(s,τ)Ω~,wi(s,0)=0,s,wi(Z(τ),τ)=0,τ(0,T].\left\{\begin{array}[]{ll}\max\big{\{}\partial_{\tau}w_{i}(s,\tau)-\mathcal{L}_{s}w_{i}(s,\tau)-g_{i}(s),w_{i}(s,\tau)\big{\}}=0,&(s,\tau)\in\tilde{\Omega},\\ w_{i}(s,0)=0,&s\in\mathbb{R},\\ w_{i}(Z(\tau),\tau)=0,&\tau\in(0,T].\end{array}\right. (3.57)

The comparison principle implies that w2(s,τ)w1(s,τ)w_{2}(s,\tau)\leq w_{1}(s,\tau), for (s,τ)Ω(s,\tau)\in\Omega. In particular, we have that

w2(s,τ)w1(s,τ)<0,s>S1(τ),τ(0,T],w_{2}(s,\tau)\leq w_{1}(s,\tau)<0,\quad s>S_{1}(\tau),\tau\in(0,T],

where Si(τ)S_{i}(\tau) is the free boundary of problem (3.57), i=1,2i=1,2. According to (3.55), we have that S2(τ)S1(τ)S_{2}(\tau)\leq S_{1}(\tau), i.e., S(τ)S(\tau) decreases in α\alpha. ∎

3.4 The solution to problem (3.2)

In this subsection, we first use the solution to problem (3.42) to construct the solution to problem (3.41), and then obtain the solution to problem (3.7). Using the transform (3.4) between u~(s,τ)\tilde{u}(s,\tau) and v(s,τ)v(s,\tau), we can further obtain the solution to problem (3.2). Following the same proof of Theorem 4.6 in Chen and Yi (2012), we can get the next result.

Proposition 3.8.

Let w(s,τ)w(s,\tau) be the solution to problem (3.42) and let us define

v¯(s,τ):=Z(τ)sw(ξ,τ)𝑑ξ+p1pχ{τ=0},(s,τ)Ω~.\bar{v}(s,\tau):=\int_{Z(\tau)}^{s}w(\xi,\tau)d\xi+\frac{p}{1-p}\chi\{\tau=0\},\quad(s,\tau)\in\tilde{\Omega}. (3.58)

Then v¯(s,τ)\bar{v}(s,\tau) is the unique solution to problem (3.41) satisfying

v¯(s,τ)C2,1(Ω~)C(Ω~¯),\displaystyle\bar{v}(s,\tau)\in C^{2,1}(\tilde{\Omega})\cap C(\overline{\tilde{\Omega}}), (3.59)
sv¯(s,τ)Wq,loc2,1(Ω~)C(Ω~¯).\displaystyle\partial_{s}\bar{v}(s,\tau)\in W^{2,1}_{q,loc}(\tilde{\Omega})\cap C(\overline{\tilde{\Omega}}). (3.60)

Moreover, if we define

v(s,τ)={v¯(s,τ),if sZ(τ),0,if s>Z(τ),v(s,\tau)=\left\{\begin{array}[]{ll}\bar{v}(s,\tau),&\mbox{if }s\leq Z(\tau),\\ 0,&\mbox{if }s>Z(\tau),\end{array}\right. (3.61)

then v(s,τ)Wq,loc2,1(Ω)C(Ω¯)v(s,\tau)\in W^{2,1}_{q,loc}(\Omega)\cap C(\overline{\Omega}) is the solution to problem (3.7). In addition, let S(τ)S(\tau) be given in (3.54) and let Z(τ)Z(\tau) be given in (3.34), S(τ)S(\tau) and Z(τ)Z(\tau) are free boundaries of problem (3.7) such that

={v=0}={(s,τ)|sZ(τ),τ(0,T]},\displaystyle\mathcal{F}=\big{\{}v=0\}=\{(s,\tau)~{}|~{}s\geq Z(\tau),\tau\in(0,T]\big{\}}, (3.62)
𝒢={sv=0,v>0}={(s,τ)|sS(τ),τ(0,T]},\displaystyle\mathcal{G}=\big{\{}-\partial_{s}v=0,v>0\}=\{(s,\tau)~{}|~{}s\leq S(\tau),\tau\in(0,T]\big{\}}, (3.63)
={sv>0,v>0}={(s,τ)|S(τ)<s<Z(τ),τ(0,T]}.\displaystyle\mathcal{E}=\big{\{}-\partial_{s}v>0,v>0\}=\{(s,\tau)~{}|~{}S(\tau)<s<Z(\tau),\tau\in(0,T]\big{\}}. (3.64)

We also have the next result

Lemma 3.9.

The solution v(s,τ)v(s,\tau) to problem (3.7) satisfies

sv(s,τ)1ppv(s,τ)<0,(s,τ)Ω~,\displaystyle\partial_{s}v(s,\tau)-\frac{1-p}{p}v(s,\tau)<0,\quad(s,\tau)\in\tilde{\Omega}, (3.65)
ssv(s,τ)2ppsv(s,τ)+1pp2v(s,τ)>0,(s,τ)Ω~.\displaystyle\partial_{ss}v(s,\tau)-\frac{2-p}{p}\partial_{s}v(s,\tau)+\frac{1-p}{p^{2}}v(s,\tau)>0,\quad(s,\tau)\in\tilde{\Omega}. (3.66)

In view of S(τ)0S(\tau)\leq 0 and the definition of ϕ(τ)\phi(\tau), v(s,τ)v(s,\tau) is continuous across the free boundary Z(τ)Z(\tau). By the strong maximum principle, it is easy to show inequalities (3.65)-(3.66) in Lemma 3.9 using standard arguments, and its proof is omitted.

Based on the relationship (3.4), it is straightforward to see that u~(s,τ)=ep1psv(s,τ)\tilde{u}(s,\tau)=e^{\frac{p-1}{p}s}v(s,\tau) is a Wq,loc2,1(Ω)C(Ω¯)W^{2,1}_{q,loc}(\Omega)\cap C(\overline{\Omega})-solution to problem (3.2). Hence, we have the following theorem.

Proposition 3.10.

For (s,τ)Ω~(s,\tau)\in\tilde{\Omega}, u~(s,τ)=ep1psv(s,τ)\tilde{u}(s,\tau)=e^{\frac{p-1}{p}s}v(s,\tau) is the unique solution to problem (3.2), where v(s,τ)v(s,\tau) is the solution to problem (3.7). In addition, S(τ)S(\tau) defined in (3.54) and Z(τ)Z(\tau) defined in (3.34) are free boundaries of problem (3.2) such that

={u~=0}={(s,τ)|sZ(τ),τ(0,T]},\displaystyle\mathcal{F}=\{\tilde{u}=0\}=\{(s,\tau)~{}|~{}s\geq Z(\tau),\tau\in(0,T]\}, (3.67)
𝒢={(p1)u~psu~=0,u~>0}={(s,τ)|sS(τ)},\displaystyle\mathcal{G}=\{(p-1)\tilde{u}-p\partial_{s}\tilde{u}=0,\tilde{u}>0\}=\{(s,\tau)~{}|~{}s\leq S(\tau)\}, (3.68)
={(p1)u~psu~>0,u~>0}={(s,τ)|S(τ)<s<Z(τ)}.\displaystyle\mathcal{E}=\{(p-1)\tilde{u}-p\partial_{s}\tilde{u}>0,\tilde{u}>0\}=\{(s,\tau)~{}|~{}S(\tau)<s<Z(\tau)\}. (3.69)

Moreover, u~(s,τ)Wq,loc2,1(Ω)C(Ω¯)\tilde{u}(s,\tau)\in W^{2,1}_{q,loc}(\Omega)\cap C(\overline{\Omega}) and u~(s,τ)C2,1(Ω~)C(Ω~¯)\tilde{u}(s,\tau)\in C^{2,1}(\tilde{\Omega})\cap C(\overline{\tilde{\Omega}}) that satisfies

su~(s,τ)<0,(s,τ)Ω~\displaystyle\partial_{s}\tilde{u}(s,\tau)<0,\quad(s,\tau)\in\tilde{\Omega} (3.70)
ssu~(s,τ)su~(s,τ)>0,(s,τ)Ω~.\displaystyle\partial_{ss}\tilde{u}(s,\tau)-\partial_{s}\tilde{u}(s,\tau)>0,\quad(s,\tau)\in\tilde{\Omega}. (3.71)
Proof.

It follows from transform (3.4) that u~(s,τ)\tilde{u}(s,\tau) is the unique solution to (3.2). The regularity of u~(s,τ)\tilde{u}(s,\tau) can be deduced from the regularity of v(s,τ)v(s,\tau). The uniqueness of solution to problem (3.7) leads to the uniqueness of solution to the problem (3.2). Using the transform (3.4), we can deduce (3.67)-(3.69) from (3.62)-(3.64), and (3.70)-(3.71) from (3.65)-(3.66). ∎

3.5 The solution to the dual variational inequality (2.41)

Using the transform y=es,t=Tτ,u^(y,t)=u~(s,τ)y=e^{s},t=T-\tau,\hat{u}(y,t)=\tilde{u}(s,\tau), where u~(s,τ)\tilde{u}(s,\tau) is the solution to problem (3.2), we first show that u^(y,t)\hat{u}(y,t) is the solution to problem (3.1).

Proposition 3.11.

u^(y,t)=u~(s,τ)\hat{u}(y,t)=\tilde{u}(s,\tau) is the unique solution to problem (3.1), In particular, let =(0,y0(t))×(0,T]\mathbb{Q}=(0,y_{0}(t))\times(0,T] with y0(t)=eZ(Tt)y_{0}(t)=e^{Z(T-t)}, and

u(y,t)=u^(y,t),(y,t).u(y,t)=\hat{u}(y,t),\quad(y,t)\in\mathbb{Q}. (3.72)

Then u(y,t)u(y,t) is the unique solution to problem (2.41) and eS(Tt)C[0,T]e^{S(T-t)}\in C[0,T] is the free boundary to problem (2.41) such that

𝒢1\displaystyle\mathcal{G}_{1} =\displaystyle= {(y,t)|(1p)u+pyyu=0}\displaystyle\big{\{}(y,t)|(1-p)u+py\partial_{y}u=0\big{\}} (3.73)
=\displaystyle= {(y,t)|0<yeS(Tt),t[0,T)},\displaystyle\big{\{}(y,t)|0<y\leq e^{S(T-t)},t\in[0,T)\big{\}},
1\displaystyle\mathcal{E}_{1} =\displaystyle= {(y,t)|(1p)u+pyyu<0}\displaystyle\big{\{}(y,t)|(1-p)u+py\partial_{y}u<0\big{\}} (3.74)
=\displaystyle= {(y,t)|eS(Tt)<yeZ(Tt),t[0,T)}.\displaystyle\big{\{}(y,t)|e^{S(T-t)}<y\leq e^{Z(T-t)},t\in[0,T)\big{\}}.

Moreover, u(y,t)C2,1()C(¯)u(y,t)\in C^{2,1}(\mathbb{Q})\cap C(\overline{\mathbb{Q}}) that satisfies

yu(y,t)<0,(y,t),\displaystyle\partial_{y}u(y,t)<0,\quad(y,t)\in\mathbb{Q}, (3.75)
yyu(y,t)>0,(y,t).\displaystyle\partial_{yy}u(y,t)>0,\quad(y,t)\in\mathbb{Q}. (3.76)
Proof.

First, it is obvious that u^(y,t)\hat{u}(y,t) is the solution to problem (3.1). It follows from (3.67)-(3.69) that

max{tu^+12μ2σ2y2yyu^+δyyu^δu^f(y),(1p)u^+pyyu^}=0,(y,t),\displaystyle\max\left\{\partial_{t}\hat{u}+\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}y^{2}\partial_{yy}\hat{u}+\delta y\partial_{y}\hat{u}-\delta\hat{u}-f(y),(1-p)\hat{u}+py\partial_{y}\hat{u}\right\}=0,\quad(y,t)\in\mathbb{Q},
u^(eZ(Tt),t)=yu^(eZ(Tt),t)=0.\displaystyle\hat{u}(e^{Z(T-t)},t)=\partial_{y}\hat{u}(e^{Z(T-t)},t)=0.

Combining with the terminal condition on t=Tt=T, we deduce that u(y,t)u(y,t) given in (3.72) is the unique solution to problem (2.41) in \mathbb{Q} with y0(t)=eZ(Tt)y_{0}(t)=e^{Z(T-t)}.

Note that

(p1)u~psu~=(p1)upyyu,(p-1)\tilde{u}-p\partial_{s}\tilde{u}=(p-1)u-py\partial_{y}u,

we can derive (3.73)-(3.74) from (3.68)-(3.69).

The regularity of u~(s,τ)\tilde{u}(s,\tau) in Theorem 3.10 yields the regularity of u(y,t)u(y,t) directly. According to (3.70)-(3.71), we have

yu=essu~(s,τ)<0,(y,t),\displaystyle\partial_{y}u=e^{-s}\partial_{s}\tilde{u}(s,\tau)<0,\quad(y,t)\in\mathbb{Q},
yyu=e2s(ssu~(s,τ)su~(s,τ))>0,(y,t),\displaystyle\partial_{yy}u=e^{-2s}(\partial_{ss}\tilde{u}(s,\tau)-\partial_{s}\tilde{u}(s,\tau))>0,\quad(y,t)\in\mathbb{Q},

which imply (3.75)-(3.76). ∎

4 Proof of Main Results

4.1 The solution to the HJB variational inequality (2.30)

Theorem 4.1.

There exists a solution U(ω,t)U(\omega,t) to the problem (2.30). Moreover, U(ω,t)C2,1(𝒬)U(\omega,t)\in C^{2,1}(\mathcal{Q}) that satisfies

ωU(ω,t)>0,(ω,t)𝒬,\displaystyle\partial_{\omega}U(\omega,t)>0,\quad(\omega,t)\in\mathcal{Q}, (4.1)
ωωU(ω,t)<0,(ω,t)𝒬.\displaystyle\partial_{\omega\omega}U(\omega,t)<0,\quad(\omega,t)\in\mathcal{Q}. (4.2)
0U(ω,t)ω1p1p,(ω,t)𝒬,\displaystyle 0\leq U(\omega,t)\leq\frac{\omega^{1-p}}{1-p},\quad(\omega,t)\in\mathcal{Q}, (4.3)

Moreover, if U1,U2U_{1},U_{2} are the solutions to problem (2.30) satisfying (4.3) and

limω0+ωp1(U1U2)=0,\lim\limits_{\omega\rightarrow 0^{+}}\omega^{p-1}(U_{1}-U_{2})=0, (4.4)

then U1=U2U_{1}=U_{2} in 𝒬\mathcal{Q}.

Proof.

Using the fact that u(y,t)C2,1()u(y,t)\in C^{2,1}(\mathbb{Q}) and (3.76), we can deduce the existence of a continuous inverse function of I(y,t)=yu(y,t)=ω>0I(y,t)=-\partial_{y}u(y,t)=\omega>0 that I1(ω,t)C(𝒬).I^{-1}(\omega,t)\in C(\mathcal{Q}). It follows from (3.75) and the boundary condition on y0(t)y_{0}(t) that we have y0(t)=I1(0,t)y_{0}(t)=I^{-1}(0,t). Set

U(ω,t):=u(I1(ω,t),t)+ωI1(ω,t).U(\omega,t):=u(I^{-1}(\omega,t),t)+\omega I^{-1}(\omega,t).

Then U(ω,t)U(\omega,t) is continuous. Moreover, we have

ωU(ω,t)=yuω(I1(ω,t))+I1(ω,t)+ωω(I1(ω,t))\displaystyle\partial_{\omega}U(\omega,t)=\partial_{y}u\partial_{\omega}(I^{-1}(\omega,t))+I^{-1}(\omega,t)+\omega\partial_{\omega}(I^{-1}(\omega,t))
=yu1yI+I1+I1yI\displaystyle\hskip 50.58878pt=\partial_{y}u\frac{1}{\partial_{y}I}+I^{-1}+I\frac{1}{\partial_{y}I}
=yuyyu+y+yuyyu=y=I1(ω,t)C(𝒬),\displaystyle\hskip 50.58878pt=\frac{\partial_{y}u}{-\partial_{yy}u}+y+\frac{-\partial_{y}u}{-\partial_{yy}u}=y=I^{-1}(\omega,t)\in C(\mathcal{Q}),
ωωU(ω,t)=1yyu(y,t)C(𝒬),\displaystyle\partial_{\omega\omega}U(\omega,t)=-\frac{1}{\partial_{yy}u(y,t)}\in C(\mathcal{Q}),
tU(ω,t)=tu(y,t)=tu(I1(ω,t),t)C(𝒬),\displaystyle\partial_{t}U(\omega,t)=\partial_{t}u(y,t)=\partial_{t}u(I^{-1}(\omega,t),t)\in C(\mathcal{Q}),
U(0,t)=u(y0(t),t)=0,\displaystyle U(0,t)=u(y_{0}(t),t)=0,
U(ω,T)=11p(I1(ω,T))11p=11pω1p.\displaystyle U(\omega,T)=\frac{1}{1-p}\big{(}I^{-1}(\omega,T)\big{)}^{1-\frac{1}{p}}=\frac{1}{1-p}\omega^{1-p}.

Hence, U(ω,t)C2,1(𝒬)U(\omega,t)\in C^{2,1}(\mathcal{Q}) is a solution to problem (2.30) using the dual transform (2.33)-(2.40) and the fact that u(y,t)u(y,t) is the unique solution of (2.41). As ωU(ω,t)=y>0\partial_{\omega}U(\omega,t)=y>0, we have (4.1). In addition, (3.76) implies the desired result (4.2).

We then show the estimate (4.3). By its definition, we know V(x,z,t)0V(x,z,t)\geq 0 and

U(ω,t)=1z1pV(x,z,t)0.U(\omega,t)=\frac{1}{z^{1-p}}V(x,z,t)\geq 0.

Next we will show the right hand side of (4.3). In view of (3.30) and the fact

u(y,t)=yp1pv(s,τ)=yp1pv(lny,Tt),u(y,t)=y^{\frac{p-1}{p}}v(s,\tau)=y^{\frac{p-1}{p}}v(\ln y,T-t),

then

tu(y,t)=yp1pτv(lny,Tt)0.\partial_{t}u(y,t)=-y^{\frac{p-1}{p}}\partial_{\tau}v(\ln y,T-t)\geq 0.

Hence

tU(ω,t)=tu(I1(ω,t),t)0,\partial_{t}U(\omega,t)=\partial_{t}u(I^{-1}(\omega,t),t)\geq 0,

together with the terminal condition U(ω,T)=ω1p1pU(\omega,T)=\frac{\omega^{1-p}}{1-p}, we obtain

U(ω,t)ω1p1p,0tT.U(\omega,t)\leq\frac{\omega^{1-p}}{1-p},\quad 0\leq t\leq T.

In what follows, we show the uniqueness of the solution to problem (2.30) by the contradiction argument. Suppose U1,U2U_{1},U_{2} are two distinct solutions to problem (2.30) satisfying (4.4) that 𝒩:={U1(ω,t)>U2(ω,t)}\mathcal{N}:=\{U_{1}(\omega,t)>U_{2}(\omega,t)\}\neq\emptyset, where

𝒩1:={(ω,t)𝒩|(1p)U1(ω,t)ωωU1<(1p)U2(ω,t)ωωU2},\displaystyle\mathcal{N}_{1}:=\{(\omega,t)\in\mathcal{N}|(1-p)U_{1}(\omega,t)-\omega\partial_{\omega}U_{1}<(1-p)U_{2}(\omega,t)-\omega\partial_{\omega}U_{2}\},
𝒩2:={(ω,t)𝒩|(1p)U1(ω,t)ωωU1(1p)U2(ω,t)ωωU2}.\displaystyle\mathcal{N}_{2}:=\{(\omega,t)\in\mathcal{N}|(1-p)U_{1}(\omega,t)-\omega\partial_{\omega}U_{1}\geq(1-p)U_{2}(\omega,t)-\omega\partial_{\omega}U_{2}\}.

It follows from the definition of 𝒩1\mathcal{N}_{1} that

tU112μ2σ2(ωU1)2ωωU1+(c^(ω,t))1p1pc^(ω,t)ωU1δU1=0,\displaystyle\partial_{t}U_{1}-\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}\frac{(\partial_{\omega}U_{1})^{2}}{\partial_{\omega\omega}U_{1}}+\frac{(\hat{c}^{*}(\omega,t))^{1-p}}{1-p}-{\hat{c}}^{*}(\omega,t)\partial_{\omega}U_{1}-\delta U_{1}=0,
tU212μ2σ2(ωU2)2ωωU2+(c^(ω,t))1p1pc^(ω,t)ωU2δU20.\displaystyle\partial_{t}U_{2}-\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}\frac{(\partial_{\omega}U_{2})^{2}}{\partial_{\omega\omega}U_{2}}+\frac{(\hat{c}^{*}(\omega,t))^{1-p}}{1-p}-{\hat{c}}^{*}(\omega,t)\partial_{\omega}U_{2}-\delta U_{2}\leq 0.

Denote c(ω,t)=g(ωU)c^{*}(\omega,t)=g(\partial_{\omega}U) and u~=U1U2\tilde{u}=U_{1}-U_{2}. We have that

(ωU1)2ωωU1(ωU2)2ωωU2\displaystyle\frac{(\partial_{\omega}U_{1})^{2}}{\partial_{\omega\omega}U_{1}}-\frac{(\partial_{\omega}U_{2})^{2}}{\partial_{\omega\omega}U_{2}} =\displaystyle= (ωU1)2ωωU1(ωU1)2ωωU2+(ωU1)2ωωU2(ωU2)2ωωU2\displaystyle\frac{(\partial_{\omega}U_{1})^{2}}{\partial_{\omega\omega}U_{1}}-\frac{(\partial_{\omega}U_{1})^{2}}{\partial_{\omega\omega}U_{2}}+\frac{(\partial_{\omega}U_{1})^{2}}{\partial_{\omega\omega}U_{2}}-\frac{(\partial_{\omega}U_{2})^{2}}{\partial_{\omega\omega}U_{2}}
=\displaystyle= (ωU1)2ωωU1ωωU2ωωu~+ωU1+ωU2ωωU2ωu~,\displaystyle-\frac{(\partial_{\omega}U_{1})^{2}}{\partial_{\omega\omega}U_{1}\partial_{\omega\omega}U_{2}}\partial_{\omega\omega}\tilde{u}+\frac{\partial_{\omega}U_{1}+\partial_{\omega}U_{2}}{\partial_{\omega\omega}U_{2}}\partial_{\omega}\tilde{u},

then it holds that

tu~+(ωU1)2ωωU1ωωU2ωωu~+ωU1+ωU2ωωU2ωu~δu~\displaystyle\partial_{t}\tilde{u}+\frac{(\partial_{\omega}U_{1})^{2}}{\partial_{\omega\omega}U_{1}\partial_{\omega\omega}U_{2}}\partial_{\omega\omega}\tilde{u}+\frac{\partial_{\omega}U_{1}+\partial_{\omega}U_{2}}{\partial_{\omega\omega}U_{2}}\partial_{\omega}\tilde{u}-\delta\tilde{u}
g(ωU1)ωU1g(ωU2)ωU2[g(ωU1)]1p1p+[g(ωU2)]1p1p.\displaystyle\geq g(\partial_{\omega}U_{1})\partial_{\omega}U_{1}-g(\partial_{\omega}U_{2})\partial_{\omega}U_{2}-\frac{[g(\partial_{\omega}U_{1})]^{1-p}}{1-p}+\frac{[g(\partial_{\omega}U_{2})]^{1-p}}{1-p}. (4.5)

We next show the right hand side of (4.1) is non-negative. Denote

G(x):=g(x)x[g(x)]1p1p.G(x):=g(x)x-\frac{[g(x)]^{1-p}}{1-p}.

It holds in 𝒩1\mathcal{N}_{1} that

0<(1p)u~<ωωu~,(ω,t)𝒩1.0<(1-p)\tilde{u}<\omega\partial_{\omega}\tilde{u},\quad(\omega,t)\in\mathcal{N}_{1}.

Hence, we obtain ωU1ωU2=ωu~>0\partial_{\omega}U_{1}-\partial_{\omega}U_{2}=\partial_{\omega}\tilde{u}>0. In view that

g(ωU)=c(ω,t)={1,ωU<1,(ωU)1/p,1<ωU<αp,α,ωU>αp,\displaystyle g(\partial_{\omega}U)=c^{*}(\omega,t)=\left\{\begin{array}[]{ll}1,\quad\partial_{\omega}U<1,\\ (\partial_{\omega}U)^{-1/p},\quad 1<\partial_{\omega}U<\alpha^{-p},\\ \alpha,\quad\partial_{\omega}U>\alpha^{-p},\end{array}\right.
[g(x)]p={1,x<1,x,1<x<αp,αp,x>αp,\displaystyle[g(x)]^{-p}=\left\{\begin{array}[]{ll}1,\quad x<1,\\ x,\quad 1<x<\alpha^{-p},\\ \alpha^{-p},\quad x>\alpha^{-p},\end{array}\right.
g(x)={0,1px1p1,0,\displaystyle g^{\prime}(x)=\left\{\begin{array}[]{ll}0,\\ -\frac{1}{p}x^{-\frac{1}{p}-1},\\ 0,\end{array}\right.

and the facts that g(x)0g^{\prime}(x)\leq 0 and

G(x)=g(x)x+g(x)[g(x)]pg(x)=g(x)[x[g(x)]p]+g(x)=g(x)0,G^{\prime}(x)=g^{\prime}(x)x+g(x)-[g(x)]^{-p}g^{\prime}(x)=g^{\prime}(x)[x-[g(x)]^{-p}]+g(x)=g(x)\geq 0,

we deduce that G(x)G(x) is increasing in xx. It then follows that G(ωU1)G(ωU2)G(\partial_{\omega}U_{1})\geq G(\partial_{\omega}U_{2}), and the right hand side of (4.1) is nonnegative. Therefore, u~\tilde{u} satisfies the following linear equation

tu~u~0,(ω,t)𝒩1,\partial_{t}\tilde{u}-\mathcal{L}^{*}\tilde{u}\geq 0,\quad(\omega,t)\in\mathcal{N}_{1},

where the coefficients in the operator \mathcal{L}^{*} are all determined. To apply the maximum principle, we need the boundary conditions on the parabolic boundary p𝒩1\partial_{p}\mathcal{N}_{1}. By the definition of 𝒩1\mathcal{N}_{1}, we have

(1p)u~ωωu~=0,(ω,t)p𝒩1.(1-p)\tilde{u}-\omega\partial_{\omega}\tilde{u}=0,\quad(\omega,t)\in\partial_{p}\mathcal{N}_{1}.
ttω\omegaB{B}A{A}C{C}p𝒩{\partial_{p}\mathcal{N}}p𝒩1{\partial_{p}\mathcal{N}_{1}}𝒩1{\mathcal{N}_{1}}𝒩2{\mathcal{N}_{2}}\bullet\bullet\bullet

Figure 4

Define t0=inf{t:(ω,t)𝒩1}t_{0}=\inf\{t:(\omega,t)\in\mathcal{N}_{1}\}. Denote B(ω0,t0),C(ω1,t0)p𝒩1B(\omega_{0},t_{0}),C(\omega_{1},t_{0})\in\partial_{p}\mathcal{N}_{1}, where ω0=inf{ω:(ω,t0)p𝒩1},ω1ω0\omega_{0}=\inf\{\omega:(\omega,t_{0})\in\partial_{p}\mathcal{N}_{1}\},\;\omega_{1}\geq\omega_{0} and BC¯p𝒩1\overline{BC}\subset\partial_{p}\mathcal{N}_{1}, as illustrated in the above figure. We claim that u~(B)=0\tilde{u}(B)=0. If it is not true, then we consider A(0,t0)A(0,t_{0}). So we have

(1p)u~ωωu~0,(ω,t)AB¯.(1-p)\tilde{u}-\omega\partial_{\omega}\tilde{u}\geq 0,\quad(\omega,t)\in\overline{AB}.

It follows that

ω(ωp1u~)0,(ω,t)AB¯.\partial_{\omega}(\omega^{p-1}\tilde{u})\leq 0,\quad(\omega,t)\in\overline{AB}.

By the condition (4.4), we have ωp1u~(B)0\omega^{p-1}\tilde{u}(B)\leq 0. Together with ωp1u~(B)0\omega^{p-1}\tilde{u}(B)\geq 0, we obtain u~(B)=0\tilde{u}(B)=0, and hence

u~(ω,t)=0,(ω,t)BC¯.\tilde{u}(\omega,t)=0,\quad(\omega,t)\in\overline{BC}.

By the maximum principle, we know

U1U2=u~0,(ω,t)𝒩1,U_{1}-U_{2}=\tilde{u}\leq 0,\quad(\omega,t)\in\mathcal{N}_{1},

which leads to a contradiction with the definition of 𝒩1\mathcal{N}_{1}. Hence, 𝒩1=\mathcal{N}_{1}=\emptyset, and 𝒩=𝒩2\mathcal{N}=\mathcal{N}_{2}.

In view that

{ω(ωp1u~)0,(ω,t)p𝒩,ωp1u~=0,(ω,t)p𝒩,\displaystyle\left\{\begin{array}[]{ll}\partial_{\omega}(\omega^{p-1}\tilde{u})\geq 0,\quad(\omega,t)\in\partial_{p}\mathcal{N},\\ \omega^{p-1}\tilde{u}=0,\quad(\omega,t)\in\partial_{p}\mathcal{N},\end{array}\right.

we have ωp2u~=0\omega^{p-2}\tilde{u}=0, for (ω,t)𝒩(\omega,t)\in\mathcal{N}, which contradicts the definition of 𝒩\mathcal{N}. The uniqueness of the solution to problem (2.30) then follows. ∎

4.2 Proof of Theorem 2.1

First, the next result gives the analytical characterization of free boundaries ω(t),ω1(t)\omega^{*}(t),\omega_{1}(t) and ωα(t)\omega_{\alpha}(t) in Theorem 2.1.

Theorem 4.2.

Let w(s,τ)w(s,\tau) be the solution to problem (3.42), and S(τ)S(\tau) be defined in (3.54). There exist three free boundaries ω(t),ω1(t)\omega^{*}(t),\omega_{1}(t) and ωα(t)\omega_{\alpha}(t) to problem (2.30) such that

ωα(t)<ω1(t)ω(t),t[0,T],\displaystyle\omega_{\alpha}(t)<\omega_{1}(t)\leq\omega^{*}(t),\quad t\in[0,T], (4.10)
JR={(ω,t)𝒬¯|(1p)UωωU=0}\displaystyle JR=\big{\{}(\omega,t)\in\overline{\mathcal{Q}}~{}|~{}(1-p)U-\omega\partial_{\omega}U=0\big{\}}
={(ω,t)𝒬¯|ωω(t),t[0,T)},\displaystyle\hskip 14.45377pt=\big{\{}(\omega,t)\in\overline{\mathcal{Q}}~{}|~{}\omega\geq\omega^{*}(t),t\in[0,T)\big{\}}, (4.11)
CR={(ω,t)𝒬¯|(1p)UωωU<0}\displaystyle CR=\big{\{}(\omega,t)\in\overline{\mathcal{Q}}~{}|~{}(1-p)U-\omega\partial_{\omega}U<0\big{\}}
={(ω,t)𝒬¯|ω<ω(t),t[0,T)}.\displaystyle\hskip 14.45377pt=\big{\{}(\omega,t)\in\overline{\mathcal{Q}}~{}|~{}\omega<\omega^{*}(t),t\in[0,T)\big{\}}. (4.12)

Moreover, for t[0,T)t\in[0,T), we have the analytical form in terms of w(s,τ)w(s,\tau) that

ω(t)=1ppe1pS(Tt)Z(Tt)S(Tt)w(ξ,Tt)𝑑ξ,\displaystyle\omega^{*}(t)=\frac{1-p}{p}e^{-\frac{1}{p}S(T-t)}\int_{Z(T-t)}^{S(T-t)}w(\xi,T-t)d\xi, (4.13)
ω1(t)=1ppZ(Tt)0w(ξ,Tt)𝑑ξw(0,Tt),\displaystyle\omega_{1}(t)=\frac{1-p}{p}\int_{Z(T-t)}^{0}w(\xi,T-t)d\xi-w(0,T-t), (4.14)
ωα(t)=α1ppZ(Tt)plnαw(ξ,Tt)𝑑ξαw(plnα,Tt).\displaystyle\omega_{\alpha}(t)=\alpha\frac{1-p}{p}\int_{Z(T-t)}^{-p\ln\alpha}w(\xi,T-t)d\xi-\alpha w(-p\ln\alpha,T-t). (4.15)

Here, ω(t),ω1(t),ωα(t)\omega^{*}(t),\omega_{1}(t),\omega_{\alpha}(t) are continuous in tt. In particular, our conjectured free boundary ω(t)\omega^{*}(t) in Remark 2.2 is now characterized analytically by (4.13).

In addition, the candidate optimal feedback control c^(ω,t){\hat{c}}^{*}(\omega,t) given in (2.29) satisfies that

c^(ω,t)={α,if 0<ωωα(t),(ωU)1p,if ωα(t)<ω<ω1(t),1,if ω1(t)ωω(t).\displaystyle{\hat{c}}^{*}(\omega,t)=\left\{\begin{array}[]{ll}\alpha,&\mbox{if }0<\omega\leq\omega_{\alpha}(t),\\ (\partial_{\omega}U)^{-\frac{1}{p}},&\mbox{if }\omega_{\alpha}(t)<\omega<\omega_{1}(t),\\ 1,&\mbox{if }\omega_{1}(t)\leq\omega\leq\omega^{*}(t).\\ \end{array}\right. (4.19)
Proof.

First, by (2.35)-(2.36), we have

(1p)u(y,t)+pyyu(y,t)=(1p)U(ω,t)ωωU(ω,t).\displaystyle(1-p)u(y,t)+py\partial_{y}u(y,t)=(1-p)U(\omega,t)-\omega\partial_{\omega}U(\omega,t).

According to (3.76), I(y,t)=yu(y,t)I(y,t)=-\partial_{y}u(y,t) is strictly decreasing in yy, it follows that

𝒢1={(y,t)|I(y,t)I(eS(Tt),t),t[0,T)},\displaystyle\mathcal{G}_{1}=\big{\{}(y,t)\in\mathbb{Q}~{}|~{}I(y,t)\geq I(e^{S(T-t)},t),t\in[0,T)\big{\}},
1={(y,t)|I(y,t)<I(eS(Tt),t),t[0,T)}.\displaystyle\mathcal{E}_{1}=\big{\{}(y,t)\in\mathbb{Q}~{}|~{}I(y,t)<I(e^{S(T-t)},t),t\in[0,T)\big{\}}.

The above results, together with (3.73)-(3.74), imply the existence of a free boundary ω(t)=I(eS(Tt),t)=yu(eS(Tt),t)\omega^{*}(t)=I(e^{S(T-t)},t)=-\partial_{y}u(e^{S(T-t)},t) such that (4.11)-(4.12) hold true.

Using the transform u(y,t)=u~(s,τ)=e1ppsv(s,τ)u(y,t)=\tilde{u}(s,\tau)=e^{-\frac{1-p}{p}s}v(s,\tau), y=esy=e^{s} and τ=Tt\tau=T-t, we have that

ω(t)\displaystyle\omega^{*}(t) =\displaystyle= yu(eS(Tt),t)=eS(Tt)su~(S(Tt),Tt)\displaystyle-\partial_{y}u(e^{S(T-t)},t)=-e^{-S(T-t)}\partial_{s}\tilde{u}(S(T-t),T-t)
=\displaystyle= e1pS(Tt)[1ppv(S(Tt),Tt)sv(S(Tt),Tt)]\displaystyle e^{-\frac{1}{p}S(T-t)}\left[\frac{1-p}{p}v(S(T-t),T-t)-\partial_{s}v(S(T-t),T-t)\right]
=\displaystyle= 1ppe1pS(Tt)Z(Tt)S(Tt)w(ξ,Tt)𝑑ξ,\displaystyle\frac{1-p}{p}e^{-\frac{1}{p}S(T-t)}\int_{Z(T-t)}^{S(T-t)}w(\xi,T-t)d\xi,

where the last equality is due to the expression of v(s,τ)v(s,\tau) in (3.58) and the fact that sv(S(Tt),Tt)=0\partial_{s}v(S(T-t),T-t)=0.

Next, we show (4.19). In the domain CRCR, we have

tU12μ2σ2(ωU)2ωωU+c^1p(ω,t)1pc^(ω,t)ωUδU=0,\partial_{t}U-\frac{1}{2}\frac{\mu^{2}}{\sigma^{2}}\frac{(\partial_{\omega}U)^{2}}{\partial_{\omega\omega}U}+\frac{\hat{c}^{1-p}(\omega,t)}{1-p}-\hat{c}(\omega,t)\partial_{\omega}U-\delta U=0,

where c^(ω,t)\hat{c}(\omega,t) is given by (2.29). Then, let us consider two free boundaries ω1(t)\omega_{1}(t) and ωα(t)\omega_{\alpha}(t) in problem (2.30) satisfying that

{ωU(ω1(t),t)=1,ωU(ωα(t),t)=α.\displaystyle\left\{\begin{array}[]{ll}\partial_{\omega}U(\omega_{1}(t),t)=1,\\ \partial_{\omega}U(\omega_{\alpha}(t),t)=\alpha.\end{array}\right. (4.22)

By the strict concavity (4.2) of U(ω,t)U(\omega,t), we get the desired result (4.10). Moreover, the strict concavity of U(ω,t)U(\omega,t), together with definition (2.29) of c^(ω,t)\hat{c}(\omega,t), implies the expression (4.19).

Next, we continue to show (4.14) and (4.15). In view of (2.34) and (2.36), for any fixed t[0,T)t\in[0,T), the first equation of (4.22) implies that ω1(t)\omega_{1}(t) satisfies

ω1(t)\displaystyle\omega_{1}(t) =\displaystyle= (ωU)1(1,t)=yu(1,t)=su~(0,Tt)\displaystyle(\partial_{\omega}U)^{-1}(1,t)=-\partial_{y}u(1,t)=-\partial_{s}\tilde{u}(0,T-t)
=\displaystyle= 1ppv(0,Tt)sv(0,Tt)\displaystyle\frac{1-p}{p}v(0,T-t)-\partial_{s}v(0,T-t)
=\displaystyle= 1ppZ(Tt)0w(ξ,τ)𝑑ξw(0,Tt).\displaystyle\frac{1-p}{p}\int_{Z(T-t)}^{0}w(\xi,\tau)d\xi-w(0,T-t).

Similarly, it follows from the second equation of (4.22) that ωα(t)\omega_{\alpha}(t) satisfies

ωα(t)\displaystyle\omega_{\alpha}(t) =\displaystyle= (ωU)1(αp,t)=yu(αp,t)=αpsu~(plnα,Tt)\displaystyle(\partial_{\omega}U)^{-1}(\alpha^{-p},t)=-\partial_{y}u(\alpha^{-p},t)=-\alpha^{p}\partial_{s}\tilde{u}(-p\ln\alpha,T-t)
=\displaystyle= α[1ppv(plnα,Tt)sv(plnα,Tt)]\displaystyle\alpha\left[\frac{1-p}{p}v(-p\ln\alpha,T-t)-\partial_{s}v(-p\ln\alpha,T-t)\right]
=\displaystyle= α1ppZ(Tt)plnαw(ξ,Tt)𝑑ξαw(plnα,Tt).\displaystyle\alpha\frac{1-p}{p}\int_{Z(T-t)}^{-p\ln\alpha}w(\xi,T-t)d\xi-\alpha w(-p\ln\alpha,T-t).

The continuity of ω(t),ω1(t),ωα(t)\omega^{*}(t),\omega_{1}(t),\omega_{\alpha}(t) can be deduced from the expressions in (4.13)-(4.15), the continuity of w(s,τ)w(s,\tau) and S(τ)S(\tau) with respect to τ\tau.

Corollary 4.3.

The free boundaries ω(t)\omega^{*}(t) and ωα(t)\omega_{\alpha}(t) given in (4.13) and (4.15), respectively, increase in α\alpha.

Proof.

Since ω(t)=yu(eS(Tt),t)\omega^{*}(t)=-\partial_{y}u(e^{S(T-t)},t), by (3.76) and Lemma 3.7 it then follows that

ω(t)α\displaystyle\frac{\partial\omega^{*}(t)}{\partial\alpha} =\displaystyle= yyu(eS(Tt),t)eS(Tt)S(Tt)α>0.\displaystyle-\partial_{yy}u(e^{S(T-t)},t)e^{S(T-t)}\frac{\partial S(T-t)}{\partial\alpha}>0.

Hence, ω(t)\omega^{*}(t) increases in α\alpha.

As ωα(t)=yu(αp,t)\omega_{\alpha}(t)=-\partial_{y}u(\alpha^{-p},t), we deduce that

ωα(t)α\displaystyle\frac{\partial\omega_{\alpha}(t)}{\partial\alpha} =\displaystyle= yyu(αp,t)(pαp1)=pαp1yyu>0.\displaystyle-\partial_{yy}u(\alpha^{-p},t)(-p\alpha^{-p-1})=p\alpha^{-p-1}\partial_{yy}u>0.

Hence, ωα(t)\omega_{\alpha}(t) increases in α\alpha. ∎

Building upon that U(ω,t)U(\omega,t) is strictly concave and strictly increases in ω\omega in Theorem 4.1, we can see that problem (2.30) is equivalent to problem (2.17). Let V(x,z,t)=z1pU(xz,t)V(x,z,t)=z^{1-p}U(\frac{x}{z},t), we can then show that V(x,z,t)V(x,z,t) is the solution to problem (2.5).

Proof of Theorem 2.1.

By Theorem 4.1 and Theorem 4.2, it is straightforward to check that V(x,z,t)V(x,z,t) is the unique solution in C2,1(Q)C(Q¯)C^{2,1}(Q)\cap C(\bar{Q}) to problem (2.5) and also (2.18) holds. In view of (4.11)-(4.12), if xω(t)zx\geq\omega^{*}(t)z, then

zV(x,z,t)=zp[(1p)U(ω,t)ωωU(ω,t)]=0,\partial_{z}V(x,z,t)=z^{-p}[(1-p)U(\omega,t)-\omega\partial_{\omega}U(\omega,t)]=0,

for ω=xzω(t)\omega=\frac{x}{z}\geq\omega^{*}(t); if x<ω(t)zx<\omega^{*}(t)z, then

zV(x,z,t)=zp[(1p)U(ω,t)ωωU(ω,t)]<0,\partial_{z}V(x,z,t)=z^{-p}[(1-p)U(\omega,t)-\omega\partial_{\omega}U(\omega,t)]<0,

for ω=xz<ω(t)\omega=\frac{x}{z}<\omega^{*}(t). Hence, we obtain results (2.24)-(2.25).

To prove the optimality of feedback control (2.19) and (2.23), it suffices to show that the following two conditions hold for all x,z+x,z\in\mathbb{R}^{+} and tTt\leq T:

  • (i)

    The following SDE admits a unique strong solution (Xs)st(X^{*}_{s})_{s\geq t} that

    {dXs=(μπ(Xs,Msω(s),s)c(Xs,Msω(s),s))ds+σπ(Xs,Msω(s),s)dWs;Ms=max{ω(t)z,suptusXu};Xt=x.\left\{\begin{array}[]{ll}dX^{*}_{s}=&\left(\mu\pi^{*}\left(X^{*}_{s},\frac{M^{*}_{s}}{\omega^{*}(s)},s\right)-c^{*}\left(X^{*}_{s},\frac{M^{*}_{s}}{\omega^{*}(s)},s\right)\right)ds+\sigma\pi^{*}\left(X^{*}_{s},\frac{M^{*}_{s}}{\omega^{*}(s)},s\right)dW_{s};\\ M^{*}_{s}=&\max\left\{\omega^{*}(t)z,\sup_{t\leq u\leq s}X^{*}_{u}\right\};\\ X^{*}_{t}=&x.\end{array}\right. (4.23)

    Furthermore, the feedback controls (πt,ct):=(π(Xt,zt,t),c(Xt,zt,t))(\pi^{*}_{t},c^{*}_{t}):=(\pi^{*}(X^{*}_{t},z^{*}_{t},t),c^{*}(X^{*}_{t},z^{*}_{t},t)) are admissible.

  • (ii)

    It holds that

    V(x,z,t)\displaystyle V(x,z,t) =\displaystyle= 𝔼[tTτeδ(st)(cs)1p1p𝑑s+eδ(Tτt)(XTτ)1p1p|Xt=x,zt=z]\displaystyle\mathbb{E}\left[\int_{t}^{T\wedge\tau}e^{-\delta(s-t)}\frac{(c^{*}_{s})^{1-p}}{1-p}ds+e^{-\delta(T\wedge\tau-t)}\frac{(X^{*}_{T\wedge\tau})^{1-p}}{1-p}\bigg{|}X^{*}_{t}=x,z^{*}_{t}=z\right]
    =\displaystyle= sup(π,c)𝒜(x)𝔼[tTτeδ(st)cs1p1p𝑑s+eδ(Tτt)XTτ1p1p|Xt=x,zt=z].\displaystyle\sup_{(\pi,c)\in\mathcal{A}(x)}\mathbb{E}\left[\int_{t}^{T\wedge\tau}e^{-\delta(s-t)}\frac{c_{s}^{1-p}}{1-p}ds+e^{-\delta(T\wedge\tau-t)}\frac{X_{T\wedge\tau}^{1-p}}{1-p}\bigg{|}X_{t}=x,z_{t}=z\right].

For simplicity, we write 𝔼[|Xt=x,zt=z]\mathbb{E}[\cdot|X_{t}=x,z_{t}=z] as 𝔼[]\mathbb{E}[\cdot] in the following.

We first prove that condition (i) holds. By the form of π\pi^{*}, cc^{*} and Remark 2.2, we know that the consumption running maximum process zsz^{*}_{s} satisfies zs=Msω(s)z^{*}_{s}=\frac{M^{*}_{s}}{\omega^{*}(s)} for all s[t,Tτ]s\in[t,T\wedge\tau] with MsM^{*}_{s} given by (4.23). Hence, if the processes XsX^{*}_{s} and zsz^{*}_{s} satisfying (4.23) exist, then it is easy to check that (πt,ct)=(π(Xt,zt,t),c(Xt,zt,t))(\pi^{*}_{t},c^{*}_{t})=(\pi^{*}(X^{*}_{t},z^{*}_{t},t),c^{*}(X^{*}_{t},z^{*}_{t},t)) are admissible. To show that (4.23)\eqref{sde*} has a unique strong solution, by Theorem 7 in section 3 of Chapter 5 of Protter (2005), one needs to show that the functionals

G(s,X):=π(Xs,1ω(t)max{ω(t)z,suptusXu},s)\displaystyle G(s,X):=\pi^{*}\left(X_{s},\frac{1}{\omega^{*}(t)}\max\left\{\omega^{*}(t)z,\sup_{t\leq u\leq s}X_{u}\right\},s\right)

and

F(s,X):=c(Xs,1ω(t)max{ω(t)z,suptusXu},s)\displaystyle F(s,X):=c^{*}\left(X_{s},\frac{1}{\omega^{*}(t)}\max\left\{\omega^{*}(t)z,\sup_{t\leq u\leq s}X_{u}\right\},s\right)

defined for sts\geq t and for continuous functions X:++X:\mathbb{R}^{+}\rightarrow\mathbb{R}^{+}, are functional Lipschitz in the sense of Protter (2005). Note that one can apply the similar arguments as used in Appendix A of Angoshtari et al. (2019) to prove the Lipschitz property of the feedback functions π\pi^{*} and cc^{*}. Therefore, for any s[t,Tτ]s\in[t,T\wedge\tau] and continuous functions XX and YY, we have

|G(s,X)G(s,Y)|\displaystyle|G(s,X)-G(s,Y)| \displaystyle\leq K[|XsYs|+|max{ω(t)z,suptusXu}max{ω(t)z,suptusYu}|]\displaystyle K\left[|X_{s}-Y_{s}|+\left|\max\left\{\omega^{*}(t)z,\sup_{t\leq u\leq s}X_{u}\right\}-\max\left\{\omega^{*}(t)z,\sup_{t\leq u\leq s}Y_{u}\right\}\right|\right]
\displaystyle\leq 2Ksuptus|XuYu|.\displaystyle 2K\sup_{t\leq u\leq s}|X_{u}-Y_{u}|.

Hence, GG is functional Lipschitz. Similarly, FF is also functional Lipschitz.

To prove condition (ii), let us introduce a sequence of stopping times as

τn:=nTτinf{s>t;tseδ(ut)(πu)2(xV(Xu,zu,u))2𝑑un or zsn},nt,\tau_{n}:=n\wedge T\wedge\tau\wedge\inf\left\{s>t;\int_{t}^{s}e^{-\delta(u-t)}(\pi^{*}_{u})^{2}(\partial_{x}V(X^{*}_{u},z^{*}_{u},u))^{2}du\geq n\text{ or }z^{*}_{s}\geq n\right\},\quad n\geq t,

with τnTτ\tau_{n}\rightarrow T\wedge\tau as nn\rightarrow\infty. By an application of Itô’s formula to eδ(st)V(Xs,zs,s)e^{-\delta(s-t)}V(X^{*}_{s},z^{*}_{s},s) on [t,τn][t,\tau_{n}], we have

eδ(τnt)V(Xτn,zτn,τn)\displaystyle e^{-\delta(\tau_{n}-t)}V(X^{*}_{\tau_{n}},z^{*}_{\tau_{n}},\tau_{n})
=\displaystyle= V(x,z,t)tτneδ(st)(cs)1p1p𝑑s+tτneδ(st)tV(Xs,zs,s)ds\displaystyle V(x,z,t)-\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\frac{(c^{*}_{s})^{1-p}}{1-p}ds+\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\partial_{t}V(X^{*}_{s},z^{*}_{s},s)ds
+tτneδ(st)[12σ2(πs)2xxV(Xs,zs,s)+(μπscs)xV(Xs,zs,s)\displaystyle+\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\left[\frac{1}{2}\sigma^{2}(\pi^{*}_{s})^{2}\partial_{xx}V(X^{*}_{s},z^{*}_{s},s)+(\mu\pi^{*}_{s}-c^{*}_{s})\partial_{x}V(X^{*}_{s},z^{*}_{s},s)\right.
δV(Xs,zs,s)+(cs)1p1p]ds+tτneδ(st)σπsxV(Xs,zs,s)dWs\displaystyle\left.-\delta V(X^{*}_{s},z^{*}_{s},s)+\frac{(c^{*}_{s})^{1-p}}{1-p}\right]ds+\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\sigma\pi^{*}_{s}\partial_{x}V(X^{*}_{s},z^{*}_{s},s)dW_{s}
+tτneδ(st)zV(Xs,zs,s)d(zs)c+tsτneδ(st)(V(Xs,zs,s)V(Xs,zs,s)),\displaystyle+\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\partial_{z}V(X^{*}_{s},z^{*}_{s},s)d(z^{*}_{s})^{c}+\sum_{t\leq s\leq\tau_{n}}e^{-\delta(s-t)}\left(V(X^{*}_{s},z^{*}_{s},s)-V(X^{*}_{s},z^{*}_{s-},s)\right),

where (zs)c(z^{*}_{s})^{c} stands for the continuous part of zsz^{*}_{s}. Taking expectations on both sides, we obtain

V(x,z,t)\displaystyle V(x,z,t)
=𝔼[tτneδ(st)(cs)1p1p𝑑s+eδ(τnt)V(Xτn,zτn,τn)]\displaystyle=\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\frac{(c^{*}_{s})^{1-p}}{1-p}ds+e^{-\delta(\tau_{n}-t)}V(X^{*}_{\tau_{n}},z^{*}_{\tau_{n}},\tau_{n})\right]
𝔼[tτneδ(st)[12σ2(πs)2xxV(Xs,zs,s)\displaystyle-\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\left[\frac{1}{2}\sigma^{2}(\pi^{*}_{s})^{2}\partial_{xx}V(X^{*}_{s},z^{*}_{s},s)\right.\right.
+(μπscs)xV(Xs,zs,s)δV(Xs,zs,s)+(cs)1p1p]ds]\displaystyle\left.\left.+(\mu\pi^{*}_{s}-c^{*}_{s})\partial_{x}V(X^{*}_{s},z^{*}_{s},s)-\delta V(X^{*}_{s},z^{*}_{s},s)+\frac{(c^{*}_{s})^{1-p}}{1-p}\right]ds\right]
𝔼[tτneδ(st)zV(Xs,zs,s)d(zs)c+tsτneδ(st)(V(Xs,zs,s)V(Xs,zs,s))].\displaystyle-\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\partial_{z}V(X^{*}_{s},z^{*}_{s},s)d(z^{*}_{s})^{c}+\sum_{t\leq s\leq\tau_{n}}e^{-\delta(s-t)}\left(V(X^{*}_{s},z^{*}_{s},s)-V(X^{*}_{s},z^{*}_{s-},s)\right)\right]. (4.24)

By plugging back the feedback controls in (2.19) and (2.23) and the fact that VV is the solution to problem (2.5), for (Xs,zs,s)𝒞(X^{*}_{s},z^{*}_{s},s)\in\mathcal{C}, we have

𝔼[tτneδ(st)[12σ2(πs)2xxV(Xs,zs,s)+(μπscs)xV(Xs,zs,s)\displaystyle\mathbb{E}\Bigg{[}\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\Big{[}\frac{1}{2}\sigma^{2}(\pi^{*}_{s})^{2}\partial_{xx}V(X^{*}_{s},z^{*}_{s},s)+(\mu\pi^{*}_{s}-c^{*}_{s})\partial_{x}V(X^{*}_{s},z^{*}_{s},s)
δV(Xs,zs,s)+(cs)1p1p]ds]=0,\displaystyle-\delta V(X^{*}_{s},z^{*}_{s},s)+\frac{(c^{*}_{s})^{1-p}}{1-p}\Big{]}ds\Bigg{]}=0, (4.25)

and hence

𝔼[tτneδ(st)zV(Xs,zs,s)d(zs)c+tsτneδ(st)(V(Xs,zs,s)V(Xs,zs,s))]=0.\displaystyle\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\partial_{z}V(X^{*}_{s},z^{*}_{s},s)d(z^{*}_{s})^{c}+\sum_{t\leq s\leq\tau_{n}}e^{-\delta(s-t)}\left(V(X^{*}_{s},z^{*}_{s},s)-V(X^{*}_{s},z^{*}_{s-},s)\right)\right]=0. (4.26)

For (Xs,zs,s)𝒟(X^{*}_{s},z^{*}_{s},s)\in\mathcal{D} and satisfying Xs=ω(s)zsX^{*}_{s}=\omega^{*}(s)z_{s}, by the continuity of VV, xV\partial_{x}V and xxV\partial_{xx}V as well as the fact that zV(Xs,zs,s)=0\partial_{z}V(X^{*}_{s},z^{*}_{s},s)=0, we have (4.2) and (4.26) hold. Furthermore, for (Xs,zs,s)𝒟(X^{*}_{s},z^{*}_{s},s)\in\mathcal{D} and satisfying Xs>ω(s)zsX^{*}_{s}>\omega^{*}(s)z_{s-}, by employing the feedback controls, it occur only at the initial time s=ts=t and ztz^{*}_{t} immediately jumps from ztz^{*}_{t-} to a new global maximum level zt=Xtω(t)z^{*}_{t}=\frac{X^{*}_{t}}{\omega^{*}(t)}, which together with the fact that zV(Xs,zs,s)=0\partial_{z}V(X^{*}_{s},z^{*}_{s},s)=0 yields (4.2) and (4.26). Then, it follows from (4.2) that

V(x,z,t)=𝔼[tτneδ(st)(cs)1p1p𝑑s+eδ(τnt)V(Xτn,zτn,τn)].V(x,z,t)=\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\frac{(c^{*}_{s})^{1-p}}{1-p}ds+e^{-\delta(\tau_{n}-t)}V(X^{*}_{\tau_{n}},z^{*}_{\tau_{n}},\tau_{n})\right].

Letting nn\rightarrow\infty in above equation and using Monotone Convergence Theorem, we obtain

limn𝔼[tτneδ(st)(cs)1p1p𝑑s]=𝔼[tTτeδ(st)(cs)1p1p𝑑s].\displaystyle\lim_{n\rightarrow\infty}\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\frac{(c^{*}_{s})^{1-p}}{1-p}ds\right]=\mathbb{E}\left[\int_{t}^{T\wedge\tau}e^{-\delta(s-t)}\frac{(c^{*}_{s})^{1-p}}{1-p}ds\right]. (4.27)

Additionally, note that the value function of the utility maximization problem on terminal wealth under a drawdown constraint with power utility function is less than the value function of Merton investment problem with power utility function (α=0\alpha=0 in our context) that

sup(π,c)𝒜(x)𝔼[11pXτn1p]sup(π,c)𝒜0(x)𝔼[11pXτn1p],\sup_{(\pi,c)\in\mathcal{A}(x)}\mathbb{E}\left[\frac{1}{1-p}X_{\tau_{n}}^{1-p}\right]\leq\sup_{(\pi,c)\in\mathcal{A}_{0}(x)}\mathbb{E}\left[\frac{1}{1-p}X_{\tau_{n}}^{1-p}\right],

where 𝒜0(x)\mathcal{A}_{0}(x) is the set of admissible strategies for Merton problem. Similar to Lemma A.3 of Angoshtari et al. (2019), there exists a constant M>0M>0 such that 0V(x,z,t)x1p1pM0\leq V(x,z,t)\leq\frac{x^{1-p}}{1-p}M for all x0x\geq 0, independent of zz and tt. Therefore, it holds that

𝔼[eδ(τnt)V(Xτn,zτn,τn)]M𝔼[eδ(τnt)(Xτn)1p1p]Msup(π,c)𝒜0(x)𝔼[Xτn1p1p].\mathbb{E}\left[e^{-\delta(\tau_{n}-t)}V(X^{*}_{\tau_{n}},z^{*}_{\tau_{n}},\tau_{n})\right]\leq M\mathbb{E}\left[e^{-\delta(\tau_{n}-t)}\frac{(X^{*}_{\tau_{n}})^{1-p}}{1-p}\right]\leq M\sup_{(\pi,c)\in\mathcal{A}_{0}(x)}\mathbb{E}\left[\frac{X_{\tau_{n}}^{1-p}}{1-p}\right].

Using the standard transversality condition in the Merton problem, the fact V(x,z,t)0V(x,z,t)\geq 0, the terminal condition V(x,z,T)=x1p1pV(x,z,T)=\frac{x^{1-p}}{1-p}, the boundary condition V(0,z,t)=0V(0,z,t)=0, and the Dominated Convergence Theorem, we have that

limn𝔼[eδ(τnt)V(Xτn,zτn,τn)]\displaystyle\lim_{n\rightarrow\infty}\mathbb{E}\left[e^{-\delta(\tau_{n}-t)}V(X^{*}_{\tau_{n}},z^{*}_{\tau_{n}},\tau_{n})\right] =\displaystyle= 𝔼[eδ(Tτt)V(XTτ,zTτ,Tτ)]\displaystyle\mathbb{E}\left[e^{-\delta(T\wedge\tau-t)}V(X^{*}_{T\wedge\tau},z^{*}_{T\wedge\tau},T\wedge\tau)\right] (4.28)
=\displaystyle= 𝔼[eδ(Tτt)(XTτ)1p1p].\displaystyle\mathbb{E}\left[e^{-\delta(T\wedge\tau-t)}\frac{(X^{*}_{T\wedge\tau})^{1-p}}{1-p}\right].

Combining (4.27) and (4.28), we deduce that the first equality in condition (ii) holds.

Finally, in view that the feedback controls (πt,ct):=(π(Xt,zt,t),c(Xt,zt,t))(\pi^{*}_{t},c^{*}_{t}):=(\pi^{*}(X^{*}_{t},z^{*}_{t},t),c^{*}(X^{*}_{t},z^{*}_{t},t)) are admissible, we readily obtain

V(x,z,t)sup(π,c)𝒜(x)𝔼[tTτeδ(st)cs1p1p𝑑s+eδ(Tτt)XTτ1p1p].V(x,z,t)\leq\sup_{(\pi,c)\in\mathcal{A}(x)}\mathbb{E}\left[\int_{t}^{T\wedge\tau}e^{-\delta(s-t)}\frac{c_{s}^{1-p}}{1-p}ds+e^{-\delta(T\wedge\tau-t)}\frac{X_{T\wedge\tau}^{1-p}}{1-p}\right].

For the inverse inequality, repeating the arguments in the proof of (4.2) with any admissible strategies (π,c)𝒜(x)(\pi,c)\in\mathcal{A}(x) and corresponding state process (X,z)(X,z), we have

V(x,z,t)\displaystyle V(x,z,t)
=𝔼[tτneδ(st)(cs)1p1p𝑑s+eδ(τnt)V(Xτn,zτn,τn)]\displaystyle=\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\frac{(c_{s})^{1-p}}{1-p}ds+e^{-\delta(\tau_{n}-t)}V(X_{\tau_{n}},z_{\tau_{n}},\tau_{n})\right]
𝔼[tτneδ(st)[12σ2(πs)2xxV(Xs,zs,s)+(μπscs)xV(Xs,zs,s)\displaystyle-\mathbb{E}\Bigg{[}\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\Big{[}\frac{1}{2}\sigma^{2}(\pi_{s})^{2}\partial_{xx}V(X_{s},z_{s},s)+(\mu\pi_{s}-c_{s})\partial_{x}V(X_{s},z_{s},s)
δV(Xs,zs,s)+(cs)1p1p]ds]\displaystyle-\delta V(X_{s},z_{s},s)+\frac{(c_{s})^{1-p}}{1-p}\Big{]}ds\Bigg{]}
𝔼[tτneδ(st)zV(Xs,zs,s)d(zs)c+tsτneδ(st)(V(Xs,zs,s)V(Xs,zs,s))].\displaystyle-\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\partial_{z}V(X_{s},z_{s},s)d(z_{s})^{c}+\sum_{t\leq s\leq\tau_{n}}e^{-\delta(s-t)}\left(V(X_{s},z_{s},s)-V(X_{s},z_{s-},s)\right)\right].

Because V(x,z,t)V(x,z,t) is the unique classical solution to problem (2.5), the second term and the third term on the right side of the above equation are non-negative, we obtain that

V(x,z,t)𝔼[tτneδ(st)(cs)1p1p𝑑s+eδ(τnt)V(Xτn,zτn,τn)].\displaystyle V(x,z,t)\geq\mathbb{E}\left[\int_{t}^{\tau_{n}}e^{-\delta(s-t)}\frac{(c_{s})^{1-p}}{1-p}ds+e^{-\delta(\tau_{n}-t)}V(X_{\tau_{n}},z_{\tau_{n}},\tau_{n})\right].

Letting nn\rightarrow\infty and applying the similar arguments in the proof of condition (i), we conclude that the reverse inequality holds, which completes the proof. ∎

5 Conclusions

We revisit the optimal consumption problem under drawdown constraint formulated in Angoshtari et al. (2019) by featuring the finite investment horizon. For this stochastic control problem under control-type constraint, we contribute to the theoretical study on the existence and uniqueness of the classical solution to the parabolic HJB variational inequality. In particular, the consumption drawdown constraint induces some time-dependent free boundaries that deserve careful investigations. Using the dual transform and considering the auxiliary variational inequality with both function and gradient constraints, we develop some technical arguments to obtain the regularity of the unique solution as well as some analytical characterization of the associated time-dependent free boundaries such that the smooth fit conditions hold. As a result, we are able to derive and verify the optimal portfolio and consumption strategies in the piecewise feedback form.

For future research extensions, it will be interesting to study other finite-time horizon optimal consumption problems when the utility function depends on the endogenous reference with respect to the past consumption maximum such as the formulation in Deng et al. (2022) and Li et al. (2021). Some new techniques are needed due to more wealth regimes and free boundary curves. It is also an appealing problem to study the finite-time horizon optimal consumption problems under habit formation constraint as investigated in Angoshtari et al. (2022) and Angoshtari et al. (2023), where the dual transform can no longer linearize the variational inequality. New technical tools are needed to cope with the nonlinear dual parabolic variational inequality.

Acknowledgements: The authors sincerely thank anonymous referees for their valuable comments and suggestions that improved the paper significantly. X. Chen is supported by NNSF of China no.12271188. X. Li is supported by Hong Kong RGC grants under no. 15216720 and 15221621. F. Yi is supported by NNSF of China no.12271188 and 12171169. X. Yu is supported by the Hong Kong RGC General Research Fund (GRF) under grant no. 15306523 and the Hong Kong Polytechnic University research grant under no. P0039251.

References

  • Angoshtari et al. (2019) B. Angoshtari, E. Bayraktar, and V. R. Young. Optimal dividend distribution under drawdown and ratcheting constraints on dividend rates. SIAM Journal on Financial Mathematics, 10: 547-577, 2019.
  • Angoshtari et al. (2022) B. Angoshtari, E. Bayraktar, and V. R. Young. Optimal investment and consumption under a habit-formation constraint. SIAM Journal on Financial Mathematics. 13: 321-352, 2022.
  • Angoshtari et al. (2023) B. Angoshtari, E. Bayraktar, and V. R. Young. Optimal consumption under a habit-formation constraint: the deterministic case. SIAM Journal on Financial Mathematics, 14:557-597, 2023.
  • Arun (2012) T. Arun. The merton problem with a drawdown constraint on consumption. Preprint, available at arXiv:1210.5205, 2012.
  • Bo et al. (2022) L. Bo, S. Wang, and X. Yu. A mean field game approach to equilibrium consumption under external habit formation. Stochastic Processes and their Applications, 178, 104461, 2024.
  • Chen et al. (2012) X. Chen, Y. Chen, and F. Yi. Parabolic variational inequality with parameter and gradient constraints. Journal of Mathematical Analysis and Applications, 385: 928-946, 2012.
  • Chen et al. (2019) X. Chen, X. Li, and F. Yi. Optimal stopping investment with non-smooth utility over an infinite time horizon. Journal of Industrial and Management Optimization, 15: 81-96, 2019.
  • Chen and Yi (2012) X. Chen, and F. Yi. A problem of singular stochastic control with optimal stopping in finite horizon. SIAM Journal on Control and Optimization, 50: 2151-2172, 2012.
  • Constantinides (1990) G. M. Constantinides. Habit formation: A resolution of the equity premium puzzle. Journal of Political Economy. 98(3): 519-543, 1990.
  • Dai and Yi (2009) M. Dai, and F. Yi. Finite horizon optimal investment with transaction costs: A parabolic double obstacle problem. Journal of Differential Equations, 246: 1445-1469, 2009.
  • Deng et al. (2022) S. Deng, X. Li, H. Pham, and X. Yu. Optimal consumption with reference to past spending maximum. Finance and Stochastics, 26: 217-266, 2022.
  • Detemple and Zapatero (1992) J. Detemple, and F. Zapatero. Optimal consumption-portfolio policies with habit formation. Mathematical Finance, 2: 251-274, 1992.
  • Dybvig (1995) P. H. Dybvig. Dusenberry’s racheting of consumption: optimal dynamic consumption and investment given intolerance for any decline in standard of living. Review of Economic Studies, 62: 287-313, 1995.
  • Englezos and Karatzas (2009) N. Englezos, and I. Karatzas. Utility maximization with habit formation: dynamic programming and stochastic PDEs. SIAM Journal on Control and Optimization, 48: 481-520, 2009.
  • Guasoni et al. (2020) P. Guasoni, G. Huberman, and D. Ren. Shortfall aversion. Mathematical Finance, 30(3): 869-920, 2020.
  • Guan et al. (2019) C. Guan, F. Yi, and X. Chen. A fully nonlinear free boundary problem arising from optimal dividend and risk control model. Mathematical Control and Related Fields, 9: 425-452, 2019.
  • Jeon et al. (2024) J. Jeon, T. Kim and Z. Yang. The finite-horizon retirement problem with borrowing constraint: A zero-sum stopper vs. singular-controller game. Preprint, available at SSRN: http://dx.doi.org/10.2139/ssrn.4364441.
  • Jeon and Oh (2022) J. Jeon, and J. Oh. Finite horizon portfolio selection problem with a drawdown constraint on consumption. Journal of Mathematical Analysis and Applications, 506(1): 125542, 2022.
  • Jeon and Park (2021) J. Jeon, and K. Park. Portfolio selection with drawdown constraint on consumption: a generalization model. Mathematical Methods of Operations Research, 93(2): 243–289, 2021.
  • Li et al. (2021) X. Li, X. Yu, and Q. Zhang. Optimal consumption with loss aversion and reference to past spending maximum. SIAM Journal on Financial Mathematics, 15(1): 121-160, 2024.
  • Li et al. (2022) X. Li, X. Yu, and Q. Zhang. Optimal consumption and life insurance under shortfall aversion and a drawdown constraint. Insurance: Mathematics and Economics, 108:25-45.
  • Liang et al. (2022) Z. Liang, X. Luo, and F. Yuan. Consumption-investment decisions with endogenous reference point and drawdown constraint. Mathematics and Financial Economics, 17:285-334, 2023.
  • Merton (1969) R. C. Merton. Lifetime portfolio selection under uncertainty: The continuous-time case. Review of Economics and Statistics, 51: 247-257, 1969.
  • Merton (1971) R. C. Merton. Optimal consumption and portfolio rules in a continuous-time model. Journal of Economic Theory, 3: 373–413, 1971.
  • Munk (2008) C. Munk. Portfolio and consumption choice with stochastic investment opportunities and habit formation in preferences. Journal of Economic Dynamics and Control, 32: 3560-3589, 2008.
  • Protter (2005) P. E. Protter, Stochastic Integration and Differential Equations, Stoch. Model. Appl. Probab. 21, 2nd ed., Springer-Verlag, Berlin, 2005.
  • Schroder and Skiadas (2002) M. Schroder, and C. Skiadas. An isomorphism between asset pricing models with and without linear habit formation. The Review of Financial Studies. 15(4): 1189-1221, 2002.
  • Tanana (2021) A. Tanana. Utility maximization with ratchet and drawdown constraints on consumption in incomplete semimartingale markets. The Annals of Applied Probability, 33(5): 4127-4162, 2023.
  • Yang and Yu (2022) Y. Yang, and X. Yu. Optimal entry and consumption under habit formation. Advances in Applied Probability, 54(2): 433-459, 2022.
  • Yu (2015) X. Yu. Utility maximization with addictive consumption habit formation in incomplete semimartingale markets. The Annals of Applied Probability, 25(3): 1383-1419, 2015.
  • Yu (2017) X. Yu. Optimal consumption under habit formation in markets with transaction costs and random endowments. The Annals of Applied Probability, 27(2): 960-1002, 2017.
  • (32)