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On the universal constraints for relaxation rates for quantum dynamical semigroup

Dariusz Chruściński1, Gen Kimura2, Andrzej Kossakowski1, Yasuhito Shishido2 1Institute of Physics, Faculty of Physics, Astronomy and Informatics Nicolaus Copernicus University, Grudzia̧dzka 5/7, 87–100 Toruń, Poland
2 College of Systems Engineering and Science, Shibaura Institute of Technology, Saitama 330-8570, Japan
Abstract

A conjecture for the universal constraints for relaxation rates of a quantum dynamical semigroup is proposed. It is shown that it holds for several interesting classes of semigroups, e.g. unital semigroups and semigroups derived in the weak coupling limit from the proper microscopic model. Moreover, proposed conjecture is supported by numerical analysis. This conjecture has several important implications: it allows to provide universal constraints for spectra of quantum channels and provides necessary condition to decide whether a given channel is consistent with Markovian evolution.

pacs:
03.65.Yz, 03.65.Ta, 42.50.Lc

Introduction — Spectral analysis belongs to the heart of quantum theory [1]. Actually, this is spectroscopy which gave birth to quantum theory. Very often one infers information about the quantum system measuring a spectrum of some operator representing physical objects (quantum observables, quantum maps, etc.). In this Letter we analyze the spectral properties of the celebrated Gorini-Kossakowski-Lindblad-Sudarshan (GKLS) generator of quantum Markovian semigroup [2, 3]

ρ˙=(ρ),\dot{\rho}=\mathcal{L}(\rho), (1)

where \mathcal{L} has the following well known form

(ρ)=i[H,ρ]+kγk(LkρLk12{LkLk,ρ}),\mathcal{L}(\rho)=-i[H,\rho]+\sum_{k}\gamma_{k}\left(L_{k}\rho L_{k}^{\dagger}-\frac{1}{2}\{L_{k}^{\dagger}L_{k},\rho\}\right), (2)

with arbitrary noise operators LkL_{k} and positive rates γk\gamma_{k}. This is the most general structure of the generator which guaranties that the dynamical map Λt=et\Lambda_{t}=e^{t\mathcal{L}} is completely positive and trace-preserving (CPTP) [2, 3, 4, 5]. Solutions of (1) define very good approximation of real system’s evolution provided the system-environment interaction is sufficiently weak and there is separation of time scales for the system and environment [5]. Typical examples where Markovian approximation is physically justified are quantum optical systems [6, 7, 8]. It is well known that eigenvalues of \mathcal{L} provide information about the rate of relaxation, dissipation and decoherence processes and hence define key physical property of the physical process. Actually, these are not γk\gamma_{k} which are directly measured in the laboratory but the corresponding eigenvalues of the generator.

Let α\ell_{\alpha} be the corresponding (complex) eigenvalues of \mathcal{L}, that is, (Xα)=αXα\mathcal{L}(X_{\alpha})=\ell_{\alpha}X_{\alpha} for α=0,,d21\alpha=0,\ldots,d^{2}-1, where d=dimd={\rm dim}\,\mathcal{H}. Since \mathcal{L} does preserve Hermiticity one has (Xα)=αXα\mathcal{L}(X^{\dagger}_{\alpha})=\ell^{*}_{\alpha}X_{\alpha}^{\dagger}, that is, if α\ell_{\alpha} is complex, then α\ell^{*}_{\alpha} is also an eigenvalue. It is well known [4] that λ0=0\lambda_{0}=0 and the corresponding eigenvector (zero-mode of \mathcal{L}) X0X_{0} gives rise to the invariant state of the evolution ω=X0/TrX0\omega=X_{0}/{\rm Tr}\,X_{0}, that is, Λt(ω)=ω\Lambda_{t}(\omega)=\omega. The corresponding eigenvalues λα(t)\lambda_{\alpha}(t) of the dynamical map Λt=et\Lambda_{t}=e^{t\mathcal{L}} read λα(t)=etα\lambda_{\alpha}(t)=e^{t\ell_{\alpha}} and hence necessarily the relaxation rates Γα\Gamma_{\alpha} defined by

Γα=Reα,\Gamma_{\alpha}=-{\rm Re}\,\ell_{\alpha}, (3)

are non-negative Γα0\Gamma_{\alpha}\geq 0 for all α=1,,d21\alpha=1,\ldots,d^{2}-1 (otherwise etαe^{t\ell_{\alpha}} blows up as tt\to\infty). Eigenvalues λα(t)\lambda_{\alpha}(t) of the corresponding dynamical map Λt=et\Lambda_{t}=e^{t\mathcal{L}} belong to the unit disc on the complex plane, that is, |λα(t)|1|\lambda_{\alpha}(t)|\leq 1. This is a quantum analog of the celebrated Frobenius-Perron theorem for stochastic matrices. Surprisingly, apart form the fact that all Γα0\Gamma_{\alpha}\geq 0 not much more is known about the structure of the spectrum of a GKSL generator. Actually, one can show that ete^{t\mathcal{L}} is CPTP for t0t\geq 0 if and only if \mathcal{L} satisfy the following property (known as conditional complete positivity) [9, 10]

P[(I)(P)]P0,P^{\perp}[(I\otimes\mathcal{L})(P)]P^{\perp}\geq 0, (4)

where P=|ψ+ψ+|P=|\psi_{+}\rangle\langle\psi_{+}| denotes the projector onto maximally mixed state |ψ+|\psi_{+}\rangle\in\mathcal{H}\otimes\mathcal{H}, and P=1lPP^{\perp}={\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}-P is orthogonal to PP. Unfortunately, condition (4) does not provide any transparent information about the spectrum of \mathcal{L}. The same problem arises for quantum channels. A linear map Φ:()()\Phi:\mathcal{B}(\mathcal{H})\to\mathcal{B}(\mathcal{H}) is completely positive if and only if the corresponding Choi matrix (IΦ)(P)0(I\otimes\Phi)(P)\geq 0 [11]. Again, positivity of the Choi matrix cannot be easily translated into the property of the spectrum of the map Φ\Phi. This should be clear since the map and hence also its Choi matrix depend in a nontrivial way both on the spectrum (eigenvalues) and eigenvectors. On the other hand eigenvalues and in particular relaxation rates have a clear physical interpretation and can be directly measured. Hence, eigenvalues of the Choi matrix decide about complete positivity and eigenvalues of the generator (or the quantum channel) are measurable quantities. It is, therefore, clear that one can expect some additional property relating relaxation rates which is responsible for complete positivity of the quantum evolution. Relaxation properties of GKLS generators were further studied in [4, 19] and more recently e.g. in [20, 21]. Some constraints for relaxation rates for 3- and 4-level systems were presented in [22, 23, 24]. Interestingly, authors of a seminal paper [2] already observed that for a qubit evolution governed by the following well known generator

(ρ)=iΔ2[σz,ρ]+D(ρ),\mathcal{L}(\rho)=-i\frac{\Delta}{2}[\sigma_{z},\rho]+\mathcal{L}_{D}(\rho), (5)

with the dissipative part D=γ+++γ+γzz\mathcal{L}_{D}=\gamma_{+}\mathcal{L}_{+}+\gamma_{-}\mathcal{L}_{-}+\gamma_{z}\mathcal{L}_{z} consisting of: pumping +(ρ)=σ+ρσ12{σσ+,ρ}\mathcal{L}_{+}(\rho)=\sigma_{+}\rho\sigma_{-}-\frac{1}{2}\{\sigma_{-}\sigma_{+},\rho\}, damping (ρ)=σρσ+12{σ+σ,ρ}\mathcal{L}_{-}(\rho)=\sigma_{-}\rho\sigma_{+}-\frac{1}{2}\{\sigma_{+}\sigma_{-},\rho\}, and dephasing z(ρ)=σzρσzρ\mathcal{L}_{z}(\rho)=\sigma_{z}\rho\sigma_{z}-\rho, complete positivity implies the following well known condition for the relaxation times Tα=1/ΓαT_{\alpha}=1/\Gamma_{\alpha}:

TL2TT,T_{\rm L}\geq 2\,T_{\rm T}, (6)

where the longitudinal rate ΓL=Γ3=γ++γ\Gamma_{\rm L}=\Gamma_{3}=\gamma_{+}+\gamma_{-}, and transversal rate ΓT=Γ1=Γ2=12(γ++γ)+γz\Gamma_{\rm T}=\Gamma_{1}=\Gamma_{2}=\frac{1}{2}(\gamma_{+}+\gamma_{-})+\gamma_{z}. Condition (6) was experimentally demonstrated to be true [4, 12]. Clearly, the very condition (6) provides only partial information about the corresponding qubit generator. However, violation of (6) shows that the generator does not provide legitimate CPTP evolution. Condition (6) has even more appealing form when rephrased in terms of relaxation rates. Indeed, one finds

k=13Γk2Γi;i=1,2,3,\sum_{k=1}^{3}\Gamma_{k}\geq 2\Gamma_{i}\ ;\ \ \ i=1,2,3, (7)

that is, each single relaxation rate cannot be too large. In terms of relative relaxation rates Ri=Γi/(Γ1+Γ2+Γ3)R_{i}=\Gamma_{i}/(\Gamma_{1}+\Gamma_{2}+\Gamma_{3}), it says that,

Ri12;i=1,2,3,R_{i}\leq\frac{1}{2}\ ;\ \ \ i=1,2,3, (8)

The generator (5) is very special and in particular implies that the rates Γ1\Gamma_{1} and Γ2\Gamma_{2} are the same. Interestingly, Kimura [13] showed that condition (7) is universal for any qubit generator. For a purely dissipative generator Wolf and Cirac derived the following result (Theorem 6 in [14])

2dΓ,\|\mathcal{L}\|\leq\frac{2}{d}\Gamma, (9)

with Γ:=β=1d21Γβ\Gamma:=\sum_{\beta=1}^{d^{2}-1}\Gamma_{\beta}, where \|\mathcal{L}\| denotes the operator norm. Note, that due to |α|Γα\|\mathcal{L}\|\geq|\ell_{\alpha}|\geq\Gamma_{\alpha}, the above condition implies

Rα2d;α=1,,d21,R_{\alpha}\leq\frac{2}{d}\ ;\ \ \ \alpha=1,\ldots,d^{2}-1, (10)

where Rα=Γα/ΓR_{\alpha}=\Gamma_{\alpha}/\Gamma. Recently, Kimura et al. [15] obtained the following universally valid constraints for any GKLS generator:

Rα2d;α=1,,d21.R_{\alpha}\leq\frac{\sqrt{2}}{d}\ ;\ \ \ \alpha=1,\ldots,d^{2}-1. (11)

In this Letter we conjecture that the bound (11) can be still improved and propose the following

Conjecture 1

Any GKLS generator (2) for dd-level quantum systems implies the following constraints for the relaxation rates

ΓdΓα;α=1,,d21.\Gamma\geq d\Gamma_{\alpha}\ ;\ \ \ \alpha=1,\ldots,d^{2}-1. (12)

Equivalently, in terms of the relative relaxation rates Rα=Γα/ΓR_{\alpha}=\Gamma_{\alpha}/\Gamma, we conjecture that

Rα1d;α=1,,d21.R_{\alpha}\leq\frac{1}{d}\ ;\ \ \ \alpha=1,\ldots,d^{2}-1. (13)

Moreover, the bound (12) is tight, i.e. cannot be improved.

Unfortunately, we still do not have a complete proof of (12). However, we show in this Letter that this conjecture holds for several important classes of GKLS generators. In particular any generator giving rise to the unital evolution, that is (1l)=0\mathcal{L}({\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}})=0, satisfies (12). Unital (often called doubly stochastic) maps characterize decoherence processes that does not decrease entropy [25, 26] and provide direct generalization of unitary maps. A second important class are GKLS generator which display additional symmetry, that is, they are covariant w.r.t. maximal abelian subgroup of the unitary group U(d)U(d). Actually, qubit generator (5) belongs to this class. The classical Pauli master equation is another example.

The formula (2) provides the most general mathematical structure of the generator compatible with the requirement of complete positivity and trace-preservation. Note, however, that not every generator constructed according to (2) has a clear physical interpretation. There exists a natural class of generators of Markovian semigroups derived in the weak coupling limit [17, 4, 5] and these do enjoy the covariance property. Hence, we may summarise that physically motivated generators do satisfy Conjecture (1). This conjecture is also strongly supported by numerical analysis (cf. Figure 1).

Refer to caption
Figure 1: Distributions of eigenvalues of random Lindbladians. For each d=2,3,4,5d=2,3,4,5, we randomly generated 100,000100,000 GKLS generators and plotted the normalized eigenvalues :=α/Γ\ell^{\prime}:=\ell_{\alpha}/\Gamma. Red vertical lines denote the bound ‘1/d-1/d’, corresponding to our conjecture, while blue ones denote the previously obtained bound 2/d-\sqrt{2}/d [15].

Interestingly, it is perfectly consistent with the spectrum of random GKLS generator in the large dd-limit [16]. Finally, we also construct a GKLS model which saturates (13) (for some α\alpha). This implies that (13) are the tightest constraints which characterize the universally valid spectral property of GKLS generators.

Clearly, the conjecture providing universal constraints for relaxation rates is interesting by itself since they are composed of experimentally accessible quantities and hence provide a direct method to check the validity of GKLS generators, or the completely positive condition. It has, however, further very interesting implications. It allows to establish universal constraints for eigenvalues of quantum channels (Conjecture 2). Moreover, it provides necessary condition for a quantum channel Φ\Phi to be represented via Φ=e\Phi=e^{\mathcal{L}} for some GKLS generator [9]. It is found that in this case all eigenvalues are constrained to a ring r|zα|1r\leq|z_{\alpha}|\leq 1, where the inner radius rr is fully characterized by the original channel Φ\Phi (Conjecture 3).

Classical Pauli master equation. — Let us start our analysis with a classical counterpart of master equation. Consider a Pauli rate equation for a classical system with dd states

dpidt=j=1dKijpj,\frac{dp_{i}}{dt}=\sum_{j=1}^{d}K_{ij}p_{j}, (14)

where KK is the classical generator satisfying the following Kolmogorov conditions [27]

Kij0,(ij);i=1dKij=0.K_{ij}\geq 0\ ,\ (i\neq j)\ \ ;\ \ \sum_{i=1}^{d}K_{ij}=0. (15)

Hence KijK_{ij} can be represented as Kij=tijδijm=1dtmjK_{ij}=t_{ij}-\delta_{ij}\sum_{m=1}^{d}t_{mj}, with tij0t_{ij}\geq 0. Note that here only tijt_{ij} with iji\neq j are relevant, so in the following, we put tii=0t_{ii}=0. Equivalently, (14) can be formulated as follows

p˙i=j=1d(tijpjtjipi).\dot{p}_{i}=\sum_{j=1}^{d}(t_{ij}p_{j}-t_{ji}p_{i}). (16)

Do we have a classical analog of (12)? Spectral properties of d×dd\times d matrix KijK_{ij} are similar to that of \mathcal{L}: there are dd complex eigenvalues 0cl,,d1cl\ell^{\rm cl}_{0},\ldots,\ell^{\rm cl}_{d-1} with 0cl=0\ell^{\rm cl}_{0}=0. Moreover, Γkcl=Rekcl0\Gamma^{\rm cl}_{k}=-{\rm Re}\,\ell^{\rm cl}_{k}\geq 0, and the spectrum is symmetric w.r.t. real axis. Interestingly, in the classical case there is no bound on the relative classical rates RkclR^{\rm cl}_{k}, that is, given a set of classical rates Γkcl0\Gamma^{\rm cl}_{k}\geq 0 one can construct a classical generator KijK_{ij} which does display exactly these rates. In particular any single relative rate RkclR^{\rm cl}_{k} can be arbitrary close to ‘11’. (See Appendix A for details.)

Consider now a quantum evolution tρ(t)t\to\rho(t) such that the diagonal elements pk=ρkkp_{k}=\rho_{kk} evolve according to the classical Pauli equation (14). Introducing the family of noise operators Eij=|ij|E_{ij}=|i\rangle\langle j| one constructs the following GKLS generator

(ρ)=i,j=1dtijEijρEij12{B,ρ}\mathop{\mathcal{L}}\nolimits(\rho)=\sum_{i,j=1}^{d}t_{ij}E_{ij}\rho E_{ij}^{\dagger}-\frac{1}{2}\{B,\rho\}\, (17)

where B=kbk|kk|B=\sum_{k}b_{k}|k\rangle\langle k|, with bk=j=1dtjkb_{k}=\sum_{j=1}^{d}t_{jk}. The spectrum of \mathop{\mathcal{L}}\nolimits consists of dd classical eigenvalues of the classical generator represented by the matrix Kij=tijδijbjK_{ij}=t_{ij}-\delta_{ij}b_{j}: λ0=0,1cl,,d1cl\lambda_{0}=0,\ell^{\rm cl}_{1},\ldots,\ell^{\rm cl}_{d-1}, and the remaining eigenvalues correspond to eigenvectors EklE_{kl}:

(Lkl)=12(bk+bl)Ekl,(kl).\mathop{\mathcal{L}}\nolimits(L_{kl})=-\frac{1}{2}(b_{k}+b_{l})E_{kl}\ ,\ \ \ (k\neq l). (18)

Hence, one has classical rates Γ1cl,,Γd1cl\Gamma^{\rm cl}_{1},\ldots,\Gamma^{\rm cl}_{d-1}, and the remaining quantum rates

Γkl=12(bk+bl),(kl).\Gamma_{kl}=\frac{1}{2}(b_{k}+b_{l}),\ \ \ (k\neq l). (19)
Proposition 1

The generator (17) satisfies (12).

For the proof see Appendix B. This simple analysis shows that the role of quantum rates Γkl\Gamma_{kl} is to restore the bound (12) which is violated if one considers only classical rates Γkcl\Gamma^{\rm cl}_{k}. In terms of relative rates for the original classical problem RkclR^{\rm cl}_{k} can be arbitrarily close to ‘11’. However, after incorporating the remaining rates Γkl\Gamma_{kl} one finds

Rkcl1d,Rkl1d.R^{\rm cl}_{k}\leq\frac{1}{d}\ ,\ \ \ R_{kl}\leq\frac{1}{d}.

Clearly, this is the requirement of complete positivity which enforces the rates to satisfy (12).

The bound is tight. — For any dimension dd one can construct \mathcal{L} such that bound (13) is attained for some RαR_{\alpha}. Indeed, consider well known generator constructed via a double commutator

(ρ)=[Σ,[Σ,ρ]]=2ΣρΣ{Σ2,ρ},\mathcal{L}(\rho)=-[\Sigma,[\Sigma,\rho]]=2\Sigma\rho\Sigma-\{\Sigma^{2},\rho\}, (20)

for some Hermitian operator Σ\Sigma. A well known example is a qubit dephasing corresponding to Σ=σz\Sigma=\sigma_{z}. Let Σ=ksk|kk|\Sigma=\sum_{k}s_{k}|k\rangle\langle k| and assume that s1sds_{1}\leq\ldots\leq s_{d}. Then one finds for the relaxation rates Γij=(sisj)2\Gamma_{ij}=(s_{i}-s_{j})^{2} with the maximal rate Γmax=Γ1d\Gamma_{\rm max}=\Gamma_{1d}. One shows (cf. Appendix C) that

i,j=1dΓijdΓmax,\sum_{i,j=1}^{d}\Gamma_{ij}\geq d\Gamma_{\rm max}, (21)

which supports the conjecture (12). Moreover, taking s2==sd1=s1+sd2s_{2}=\ldots=s_{d-1}=\frac{s_{1}+s_{d}}{2}, one finds i,j=1dΓij=dΓmax\sum_{i,j=1}^{d}\Gamma_{ij}=d\Gamma_{\rm max}, or equivalently Rmax=1dR_{\rm max}=\frac{1}{d}.

Dissipativity condition. — It is more convenient to proceed in the Heisenberg picture defined by the dual generator \mathcal{L}^{\ddagger} which is related to Schrödinger picture generator \mathcal{L} via Tr(X(Y))=Tr((X)Y){\rm Tr}(X\mathcal{L}(Y))={\rm Tr}(\mathcal{L}^{\ddagger}(X)Y) for any pair of operators X,Y()X,Y\in\mathcal{B}(\mathcal{H}). Clearly, both \mathcal{L} and \mathcal{L}^{\ddagger} have the same spectrum α\ell_{\alpha} but in general different eigenvectors. As was shown by Lindblad [3] any GKLS generator satisfy the following dissipativity condition

(XX)(X)XX(X)0,\mathcal{L}^{\ddagger}(X^{\dagger}X)-\mathcal{L}^{\ddagger}(X^{\dagger})X-X^{\dagger}\mathcal{L}^{\ddagger}(X)\geq 0, (22)

for all X()X\in\mathcal{B}(\mathcal{H}). Inserting the formula (2) for the generator one finds (cf. Appendix D)

(XX)(X)XX(X)=kγk[Lk,X][Lk,X].\mathcal{L}^{\ddagger}(X^{\dagger}X)-\mathcal{L}^{\ddagger}(X^{\dagger})X-X^{\dagger}\mathcal{L}^{\ddagger}(X)=\sum_{k}\gamma_{k}[L_{k},X]^{\dagger}[L_{k},X]. (23)

Now, inserting X=YαX=Y_{\alpha}, where (Yα)=αYα\mathcal{L}^{\ddagger}(Y_{\alpha})=\ell_{\alpha}Y_{\alpha} one obtains

(YαYα)+2ΓαYαYα=kγk[Lk,Yα][Lk,Yα],\mathcal{L}^{\ddagger}(Y_{\alpha}^{\dagger}Y_{\alpha})+{2}\Gamma_{\alpha}Y_{\alpha}^{\dagger}Y_{\alpha}=\sum_{k}\gamma_{k}[L_{k},Y_{\alpha}]^{\dagger}[L_{k},Y_{\alpha}],

which finally implies

Tr(ω(YαYα))+2ΓαTr(ωYαYα)\displaystyle{\rm Tr}(\omega\mathcal{L}^{\ddagger}(Y_{\alpha}^{\dagger}Y_{\alpha}))+2\Gamma_{\alpha}{\rm Tr}(\omega Y_{\alpha}^{\dagger}Y_{\alpha})
=kγkTr(ω[Lk,Yα][Lk,Yα]),\displaystyle\quad=\sum_{k}\gamma_{k}{\rm Tr}(\omega[L_{k},Y_{\alpha}]^{\dagger}[L_{k},Y_{\alpha}]),

where ω\omega is an invariant state satisfying (ω)=0\mathcal{L}(\omega)=0. One has therefore

Tr(ω(YαYα))=Tr((ω)YαYα)=0,{\rm Tr}(\omega\mathcal{L}^{\ddagger}(Y_{\alpha}^{\dagger}Y_{\alpha}))={\rm Tr}(\mathcal{L}(\omega)Y_{\alpha}^{\dagger}Y_{\alpha})=0,

and hence one finds the following formula for Γα\Gamma_{\alpha}

2ΓαTr(ωYαYα)=kγkTr(ω[Lk,Yα][Lk,Yα]).2\Gamma_{\alpha}{\rm Tr}(\omega Y_{\alpha}^{\dagger}Y_{\alpha})=\sum_{k}\gamma_{k}{\rm Tr}(\omega[L_{k},Y_{\alpha}]^{\dagger}[L_{k},Y_{\alpha}]). (24)

Introducing the following inner product (A,B)ω=Tr(ωAB)(A,B)_{\omega}={\rm Tr}(\omega A^{\dagger}B) and the corresponding ω\omega-norm Aω2=(A,A)ω\|A\|_{\omega}^{2}=(A,A)_{\omega} the formula (24) may be rewritten in the following compact form

Γα=12Yαω2kγk[Lk,Yα]ω2.\Gamma_{\alpha}=\frac{1}{2\|Y_{\alpha}\|^{2}_{\omega}}\sum_{k}\gamma_{k}\|[L_{k},Y_{\alpha}]\|^{2}_{\omega}. (25)

This formula is universal, that is, it holds for any GKLS generator. Clearly, to compute Γα\Gamma_{\alpha} one has to know the corresponding eigenvector YαY_{\alpha} and the invariant state ω\omega. In particular, since Y0=1lY_{0}={\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}, one recovers Γ0=0\Gamma_{0}=0.

Unital semigroups. — In this section starting from the universal formula (25) we prove (12) for generators of unital semigroup, i.e. semigroups satisfying et(1l)=1le^{t\mathcal{L}}({\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}})={\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}. Unital semigroups enjoy several important properties. One proves [25, 26] that ete^{t\mathcal{L}} is unital if and only if for any initial state ρ\rho one has

ddtS(et(ρ))0,\frac{d}{dt}S(e^{t\mathcal{L}}(\rho))\geq 0, (26)

where S(ρ)S(\rho) stands for the von-Neumann entropy (actually it holds also for Rényi and Tsallis entropy as well). The corresponding generator satisfy (1l)=0\mathop{\mathcal{L}}\nolimits({\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}})=0. This condition is equivalent to

kγkLkLk=kγkLkLk.\sum_{k}\gamma_{k}L_{k}^{\dagger}L_{k}=\sum_{k}\gamma_{k}L_{k}L_{k}^{\dagger}. (27)

In particular it happens when all Lindblad operators LkL_{k} are normal (LkLk=LkLkL_{k}L_{k}^{\dagger}=L_{k}^{\dagger}L_{k}).

Inserting ω=1l/d\omega={\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}/d into formula (25) one obtains

Γα=12Yα2kγk[Lk,Yα]2,\Gamma_{\alpha}=\frac{1}{2\|Y_{\alpha}\|^{2}}\sum_{k}\gamma_{k}\|[L_{k},Y_{\alpha}]\|^{2}, (28)

where now A2=Tr(AA)\|A\|^{2}={\rm Tr}(A^{\dagger}A). To prove (12) we use the following intricate inequality [28]

[A,B]22A2B2.\|[A,B]\|^{2}\leq 2\|A\|^{2}\|B\|^{2}. (29)

Actually, this inequality was conjectured by Böttcher and Wenzel [29] in 2005 (see [28] for more details). A simpler proof can be found in [30]. It should be stressed that the bound (11) was shown by the direct use of this inequality as well.

Now, (29) immediately implies

ΓαkγkLk2.\Gamma_{\alpha}\leq\sum_{k}\gamma_{k}\|L_{k}\|^{2}. (30)

Assuming the following normalization Lk2=1\|L_{k}\|^{2}=1 as well as the condition TrLk=0\mathrm{Tr}L_{k}=0 without loss of generality, one shows (cf. Appendix E) that

kγk=1dαΓα,\sum_{k}\gamma_{k}=\frac{1}{d}\sum_{\alpha}\Gamma_{\alpha}, (31)

and hence (30) reproduces (12). Thus, we have shown

Theorem 1

The generator with unital semigroup satisfies (12).

A class of covariant generators. — Symmetry plays a key role in modern physics. In many cases it enables one to simplify the problem and often leads to much deeper understanding and the more elegant mathematical formulation. Let us consider a class of generators covariant w.r.t. the maximal commutative subgroup of the unitary group U(d)U(d)

U𝐱(X)U𝐱=(U𝐱XU𝐱),U_{\mathbf{x}}\mathop{\mathcal{L}}\nolimits(X)U^{\dagger}_{\mathbf{x}}=\mathop{\mathcal{L}}\nolimits(U_{\mathbf{x}}XU^{\dagger}_{\mathbf{x}}), (32)

where U𝐱=k=1deixk|kk|U_{\mathbf{x}}=\sum_{k=1}^{d}e^{-ix_{k}}|k\rangle\langle k|, and 𝐱=(x1,,xd)d\mathbf{x}=(x_{1},\ldots,x_{d})\in\mathbb{R}^{d}. Any generator satisfying (32) has the following form

=0+1+2,\mathop{\mathcal{L}}\nolimits=\mathop{\mathcal{L}}\nolimits_{0}+\mathop{\mathcal{L}}\nolimits_{1}+\mathop{\mathcal{L}}\nolimits_{2}, (33)

where 0(ρ)=i[H,ρ]\mathop{\mathcal{L}}\nolimits_{0}(\rho)=-i[H,\rho], together with

1(ρ)\displaystyle\mathop{\mathcal{L}}\nolimits_{1}(\rho) =\displaystyle= i,j=1dtijEijρEij12{B,ρ}\displaystyle\sum_{{i,j=1}}^{d}t_{ij}E_{ij}\rho E_{ij}^{\dagger}-\frac{1}{2}\{B,\rho\}\, (34)
2(ρ)\displaystyle\mathop{\mathcal{L}}\nolimits_{2}(\rho) =\displaystyle= i,j=1ddij|ii|ρ|jj|12{D,ρ},\displaystyle\sum_{i,j=1}^{d}d_{ij}|i\rangle\langle i|\rho|j\rangle\langle j|-\frac{1}{2}\{D,\rho\},

where the Hamiltonian H=ihi|ii|H=\sum_{i}h_{i}|i\rangle\langle i|, B=jbj|jj|B=\sum_{j}b_{j}|j\rangle\langle j|, with bj=itijb_{j}=\sum_{i}t_{ij}, and D=i=1ddii|ii|D=\sum_{i=1}^{d}d_{ii}|i\rangle\langle i| (See Appendix F). This is GKLS generator iff tij0t_{ij}\geq 0 and the Hermitian matrix [dij]i,j=1d[d_{ij}]_{i,j=1}^{d} is positive definite. Clearly, 1\mathop{\mathcal{L}}\nolimits_{1} is a classical generator considered before and 2\mathop{\mathcal{L}}\nolimits_{2} adds pure decoherence with respect to the orthonormal basis |1,,|d|1\rangle,\ldots,|d\rangle. Interestingly, the very condition (32) implies that αβ=βα\mathop{\mathcal{L}}\nolimits_{\alpha}\,\mathop{\mathcal{L}}\nolimits_{\beta}=\mathop{\mathcal{L}}\nolimits_{\beta}\,\mathop{\mathcal{L}}\nolimits_{\alpha} for α=0,1,2\alpha=0,1,2. Hence 0,1,2\mathop{\mathcal{L}}\nolimits_{0},\mathop{\mathcal{L}}\nolimits_{1},\mathop{\mathcal{L}}\nolimits_{2} share the same eigenvectors. It is, therefore, clear that eigenvalues of \mathcal{L} are simply sum of eigenvalues of α\mathop{\mathcal{L}}\nolimits_{\alpha}. Due to this property the analysis of \mathcal{L} leads to the following

Proposition 2

The generator (33) satisfies (12).

For the proof see Appendix G.

Markovian semigroup in the weak coupling limit. — Any legitimate generator of CPTP semigroup has a GKSL form (2). However, not every such generator has a clear physical interpretation. If the (open) quantum system is weakly coupled to the environment it was shown by Davies [17, 18] that performing so called weak coupling limit one eventually derives Markovian generator which has exactly GKLS form but now has a clear physical meaning being derived from the proper microscopic model (cf. [5, 4, 31, 32]). Actually, if the invariant state ω\omega has a non-degenerate spectrum (generic situation), then the corresponding generator derived in the weak coupling limit satisfies (32), and moreover [ω,U𝐱]=0[\omega,U_{\mathbf{x}}]=0, that is, ω=kωk|kk|\omega=\sum_{k}\omega_{k}|k\rangle\langle k|. Additional property of such generator is a quantum detailed balance condition [4] which in this case reduces to tikωk=tkiωit_{ik}\omega_{k}=t_{ki}\omega_{i}, which is, however, not essential for (12). Hence we may conclude that a class of physically legitimate GKLS generators defined via weak coupling limit does satisfy (12).

Implications. — Provided our conjecture is true what is it good for? Note, that it enables to characterize spectra of quantum channels. Indeed, if Φ\Phi is a quantum channel (CPTP map), then (ρ)=Φ(ρ)ρ\mathop{\mathcal{L}}\nolimits(\rho)=\Phi(\rho)-\rho defines a legitimate GKLS generator [2]. An example of such generator is just qubit dephasing ‘σzρσzρ\sigma_{z}\rho\sigma_{z}-\rho’. Now, let zα=xα+iyαz_{\alpha}=x_{\alpha}+iy_{\alpha} denote eigenvalues of Φ\Phi. Clearly, they belong to the unit disc |zα|1|z_{\alpha}|\leq 1 and z0=1z_{0}=1. It is therefore clear that Conjecture 1 implies the following

Conjecture 2

The spectrum zα=xα+iyαz_{\alpha}=x_{\alpha}+iy_{\alpha} of any quantum channel satisfy

β=1d21xβd(d1)1+dxα,\sum_{\beta=1}^{d^{2}-1}x_{\beta}\leq d(d-1)-1+dx_{\alpha}, (35)

for α=1,,d21\alpha=1,\ldots,d^{2}-1.

Since the Conjecture 1 holds in the qubit case one has

Proposition 3

The spectrum zα=xα+iyαz_{\alpha}=x_{\alpha}+iy_{\alpha} of any qubit channel satisfies

|x1±x2|1±x3.|x_{1}\pm x_{2}|\leq 1\pm x_{3}. (36)

Indeed, (36) follows immediately from (35) for d=2d=2. In particular for the Pauli channel Φ(ρ)=α=03pασαρσα\Phi(\rho)=\sum_{\alpha=0}^{3}p_{\alpha}\sigma_{\alpha}\rho\sigma_{\alpha} one has zk=xkz_{k}=x_{k}, and (36) are equivalent to the celebrated Fujiwara-Algoet conditions [41]. Moreover, since the Conjecture 1 holds for generators satisfying (1l)=0\mathcal{L}({\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}})=0, one immediately proves

Proposition 4

The spectrum of any unital quantum channel satisfies (35).

A second immediate implication of Conjecture 1 is the problem of deciding whether a given quantum channel Φ\Phi can be represented as Φ=e\Phi=e^{\mathcal{L}} for some GKLS generator \mathcal{L} [9, 14]. Our original Conjecture 1 implies

Conjecture 3

If Φ=e\Phi=e^{\mathcal{L}}, then the spectrum zαz_{\alpha} of Φ\Phi satisfies

detΦ=z1zd21|zα|d,{\rm det}\,\Phi=z_{1}\ldots z_{d^{2}-1}\leq|z_{\alpha}|^{d}, (37)

for α=1,,d21\alpha=1,\ldots,d^{2}-1.

Interestingly, it shows that all zαz_{\alpha} are not only constrained to the unit Frobenius disc but belong to the ring

detΦd|zα|1.\sqrt[d]{{\rm det}\,\Phi}\leq|z_{\alpha}|\leq 1. (38)

Clearly, Conjecture 3 is satisfied for all qubit channels and all unital channels. In particular for a qubit Pauli channel all eigenvalues zαz_{\alpha} are real and hence (37) reduces to the following simple condition zizjzkz_{i}z_{j}\leq z_{k}, where i,j,k{1,2,3}i,j,k\in\{1,2,3\} are all different. This condition was recently derived in [33, 34].

Conclusions. — In this Letter we propose a conjecture for the universal constraints for relaxation rates Γα\Gamma_{\alpha} of a quantum dynamical semigroup. Since relaxation rates are measurable quantities proposed constraints provides necessary physical condition for the Markovian generator to be physically legitimate. It is shown that the conjecture is supported by several well known examples of quantum semigroups including unital (doubly stochastic) evolution and semigroups derived in the weal coupling limit. It is strongly supported by numerical analysis (cf. Figure 1). Interestingly, the conjecture has several important implications: it allows to provide universal constraints for spectra of quantum channels and provides necessary condition to decide whether a given channel Φ\Phi is consistent with Markovian evolution Φ=e\Phi=e^{\mathcal{L}}. Note, that presented analysis may be immediately generalized for the time dependent case. Now, the evolution is generated by time-dependent generator t\mathcal{L}_{t}. A question which attracted a lot attention recently – is this evolution Markovian (cf. recent reviews [35, 36, 37, 38]). Now, having an access to local relaxation rates Γα(t)\Gamma_{\alpha}(t) the constraint (12) provides necessary condition for Markovianity (defined via so called CP-divisibility [39]). Hence, whenever local relaxation rates violate (12) the evolution is non-Markovian. In [40] a hierarchy of kk-divisibility (k=1,,dk=1,\ldots,d) was proposed — it states that the propagator Vt,sV_{t,s} defined via Λt=Vt,sΛs\Lambda_{t}=V_{t,s}\Lambda_{s} is kk-positive. Our original conjecture (12) strongly suggests that kk-positivity is controlled by the following constraint ΓkΓα\Gamma\geq k\Gamma_{\alpha}, which reproduces (12) if k=dk=d. If this is true then purely mathematical property of the map (kk-divisibility) can be decided in terms of purely physical quantities (local relaxation rates). This however needs further analysis.

Acknowledgements

We would like to thank Y. Shikano and S. Ajisaka for their comments and discussion. We also thank K. Życzkowski and S. Denisov for valuable discussions on random Lindblad generators. D. C. was supported by the Polish National Science Centre projects No. 2018/30/A/ST2/00837, respectively. G. K. is supported in part by JSPS KAKENHI Grants No. 17K18107.

Appendix A No constraints for Classical Rates

Different from quantum cases, we observe no (non-trivial) constraints on the classical rates Γkcl\Gamma^{\rm cl}_{k}. In particular, any single relative rate Rkcl:=Γkcl/(lΓlcl)R^{\rm cl}_{k}:=\Gamma^{\rm cl}_{k}/(\sum_{l}\Gamma^{\rm cl}_{l}) can be arbitrary close to ‘11’. This can be shown by constructing a classical generator KK which possesses arbitrary positive classical rates rk0(k=1,,d1)r_{k}\geq 0\ (k=1,\ldots,d-1):

K=(r1r2r3rd100r200000r300000rd10r10000).K=\left(\begin{array}[]{cccccc}-r_{1}&r_{2}&r_{3}&\cdots&r_{d-1}&0\\ 0&-r_{2}&0&\cdots&0&0\\ 0&0&-r_{3}&\cdots&0&0\\ \vdots&\cdots&\vdots&\ddots&\vdots&\vdots\\ 0&0&0&\cdots&-r_{d-1}&0\\ r_{1}&0&\cdots&0&0&0\end{array}\right).

Clearly Kolmogorov conditions are satisfied and one can easily check that the eigenvalues of this matrix are rj(j=1,,d1)-r_{j}\ (j=1,\ldots,d-1) and 0.

Appendix B Proof of Proposition 1

For the classical generator (17), a straightforward calculation shows that (Eii)=j(tijδijbi)Ejj=jKijEjj\mathop{\mathcal{L}}\nolimits^{\ddagger}(E_{ii})=\sum_{j}(t_{ij}-\delta_{ij}b_{i})E_{jj}=\sum_{j}K_{ij}E_{jj}, hence the diagonal elements satisfy ddtpi=TrEii(ρ)=Tr(Eii)ρ=jKijpj\frac{d}{dt}p_{i}=\mathrm{Tr}E_{ii}\mathop{\mathcal{L}}\nolimits(\rho)=\mathrm{Tr}\mathop{\mathcal{L}}\nolimits^{\ddagger}(E_{ii})\rho=\sum_{j}K_{ij}p_{j}. Similarly, one has (Eii)=jKjiEjj\mathop{\mathcal{L}}\nolimits(E_{ii})=\sum_{j}K_{ji}E_{jj}. Using this, one can check that the spectrum of \mathop{\mathcal{L}}\nolimits consists of dd classical eigenvalues of the classical generator KK: λ0=0,1cl,,d1cl\lambda_{0}=0,\ell^{\rm cl}_{1},\ldots,\ell^{\rm cl}_{d-1}, and the remaining eigenvalues correspond to eigenvectors EklE_{kl}:

(Ekl)=12(bk+bl)Ekl,(kl).\mathop{\mathcal{L}}\nolimits(E_{kl})=-\frac{1}{2}(b_{k}+b_{l})E_{kl}\ ,\ \ \ (k\neq l). (39)

Hence, one has classical rates Γ1cl,,Γd1cl\Gamma^{\rm cl}_{1},\ldots,\Gamma^{\rm cl}_{d-1}, and the remaining quantum rates

Γkl=12(bk+bl),(kl).\Gamma_{kl}=\frac{1}{2}(b_{k}+b_{l}),\ \ \ (k\neq l). (40)

To prove Proposition 1, we show

Γicl1dβ=1d21Γβ,i=1,,d1,\Gamma^{\rm cl}_{i}\leq\frac{1}{d}\sum_{\beta=1}^{d^{2}-1}\Gamma_{\beta},\ \ \ i=1,\ldots,d-1, (41)

and

Γkl1dβ=1d21Γβ,kl=1,,d.\Gamma_{kl}\leq\frac{1}{d}\sum_{\beta=1}^{d^{2}-1}\Gamma_{\beta},\ \ \ k\neq l=1,\ldots,d. (42)

Reminding our convention that tii=0t_{ii}=0,

Γcl:=i=1d1Γicl=TrK=l(tllk=1dtkl)=k,ltkl.\Gamma^{\rm cl}:=\sum_{i=1}^{d-1}\Gamma^{\rm cl}_{i}=-\mathrm{Tr}K=-\sum_{l}(t_{ll}-\sum_{k=1}^{d}t_{kl})=\sum_{k,l}t_{kl}.

Using (40), one has klΓkl=(d1)k,ltkl\sum_{k\neq l}\Gamma_{kl}=(d-1)\sum_{k,l}t_{kl}, and hence

Γ:=β=1d21Γβ=Γcl+klΓkl=dk,ltkl=dΓcl.\Gamma:=\sum_{\beta=1}^{d^{2}-1}\Gamma_{\beta}=\Gamma^{\rm cl}+\sum_{k\neq l}\Gamma_{kl}=d\sum_{k,l}t_{kl}=d\Gamma^{\rm cl}.

Therefore, one finds

1dΓ=ΓclΓicl,i=1,,d1,\frac{1}{d}\Gamma=\Gamma^{\rm cl}\geq\Gamma^{\rm cl}_{i},\ \ \ i=1,\ldots,d-1, (43)

which shows that (41) is trivially satisfied. Now, to prove (42) one needs to show

1dΓ\displaystyle\frac{1}{d}\Gamma =\displaystyle= Γcl=i,jtij12(bk+bl)\displaystyle\Gamma^{\rm cl}=\sum_{i,j}t_{ij}\geq\frac{1}{2}(b_{k}+b_{l})
=\displaystyle= 12(itik+jtjl),kl=1,,d,\displaystyle\frac{1}{2}\Big{(}\sum_{i}t_{ik}+\sum_{j}t_{jl}\Big{)},\ \ \ k\neq l=1,\ldots,d,

which again is trivially satisfied by the positivity of tijt_{ij}.

Appendix C The bound is tight

To see that the conjectured bound (12) is tight, i.e., the constant dd is the best constant, one can simply construct a simple GKLS generator with which the equality in (12) is attained. The simplest one we have found is given by the generator (20). Here, we show that it satisfies (12) (the fact of which is covered by the general statement in Proposition 1) and in particular that the equality is attained by an appropriate Σ\Sigma.

By ordering the eigenvalues in ascending order: s1s2sds_{1}\leq s_{2}\leq\ldots\leq s_{d}, it is enough to prove

k,l=1dΓkldΓ1d,\sum_{k,l=1}^{d}\Gamma_{kl}\leq d\Gamma_{1d}, (44)

that is,

2k<l(sksl)2d(sds1)2.2\sum_{k<l}(s_{k}-s_{l})^{2}\geq d(s_{d}-s_{1})^{2}. (45)
Lemma 1

For any x1,x2,,xn[a,b]x_{1},x_{2},\ldots,x_{n}\in[a,b] with real numbers a<ba<b and n=1,2,n=1,2,\ldots, one has

2i=1n((xia)2+(xib)2)+i,j=1n(xixj)2n(ab)2,2\sum_{i=1}^{n}((x_{i}-a)^{2}+(x_{i}-b)^{2})+\sum_{i,j=1}^{n}(x_{i}-x_{j})^{2}\geq n(a-b)^{2},

and the equality holds iff x1==xn=a+b2x_{1}=\cdots=x_{n}=\frac{a+b}{2}.

[Proof of Lemma 1] Define f(x1,,xn)=2i=1n((xia)2+(xib)2)+i,j=1n(xixj)2f(x_{1},\ldots,x_{n})=2\sum_{i=1}^{n}((x_{i}-a)^{2}+(x_{i}-b)^{2})+\sum_{i,j=1}^{n}(x_{i}-x_{j})^{2}. Since ff is continuous and differentiable on the compact region [a,b]n[a,b]^{n}, it has a minimum value and is attained by one of the extremum of ff. However, one has

xif\displaystyle\frac{\partial}{\partial x_{i}}f =\displaystyle= 4(xia)+4(xib)+2k,l(xkxl)(δikδil)\displaystyle 4(x_{i}-a)+4(x_{i}-b)+2\sum_{k,l}(x_{k}-x_{l})(\delta_{ik}-\delta_{il})
=\displaystyle= 4((2+n)xi(a+b)kxk).\displaystyle 4((2+n)x_{i}-(a+b)-\sum_{k}x_{k}).

Therefore, the only extremum is at x1=x2==xnx_{1}=x_{2}=\cdots=x_{n}, which turns out to be a+b2\frac{a+b}{2} (from the condition xif=0\frac{\partial}{\partial x_{i}}f=0). Therefore, ff takes its minimum at this point and the substitution of x1=x2==xn=a+b2x_{1}=x_{2}=\cdots=x_{n}=\frac{a+b}{2} to ff gives n(ab)2n(a-b)^{2}. \square

Applying this Lemma for n=d2n=d-2, a=s1,b=sda=s_{1},b=s_{d}, and x1=s2,x2=s3,,xn=sd1x_{1}=s_{2},x_{2}=s_{3},\cdots,x_{n}=s_{d-1} implies (45). Finally, notice that if we take Σ\Sigma with s2==sd1=s1+sd2s_{2}=\ldots=s_{d-1}=\frac{s_{1}+s_{d}}{2} then i,j=1dΓij=dΓ1d\sum_{i,j=1}^{d}\Gamma_{ij}=d\Gamma_{1d}. This shows that the equality in (12) is attained.

Appendix D Derivation of Eq. (23)

Using the dual generator \mathcal{L}^{\ddagger} for GKLS generator (2), which reads

(X)=i[H,X]+kγk(LkXLk12{LkLk,X}),\mathop{\mathcal{L}}\nolimits^{\ddagger}(X)=i[H,X]+\sum_{k}\gamma_{k}\left(L_{k}^{\dagger}XL_{k}-\frac{1}{2}\{L_{k}^{\dagger}L_{k},X\}\right), (46)

one observes a useful identity (23). Indeed, applying XXX^{\dagger}X, XX^{\dagger} to XX in (46), the left hand side of (23) is computed as

kγk(LkXXLkLkXLkXXLkXLk+XLkLkX),\displaystyle\sum_{k}\gamma_{k}(L_{k}^{\dagger}X^{\dagger}XL_{k}-L^{\dagger}_{k}X^{\dagger}L_{k}X-X^{\dagger}L^{\dagger}_{k}XL_{k}+X^{\dagger}L_{k}^{\dagger}L_{k}X),

which coincides with the right hand side of (23).

Appendix E Derivation of Eq. (31)

In this section, we derive Eq. (31) by introducing the following general formula for the trace of GKLS generator (2):

Tr=kγk(|TrLk|2dLk2),\mathrm{Tr}\mathop{\mathcal{L}}\nolimits=\sum_{k}\gamma_{k}(|\mathrm{Tr}L_{k}|^{2}-d\|L_{k}\|^{2}), (47)

where A2=Tr(AA)\|A\|^{2}={\rm Tr}(A^{\dagger}A). If one uses the normalized and traceless generator LkL_{k} (indeed, without loss of generality, the trace part of LkL_{k} can be renormalized to the Hamiltonian part), this can be simplified to

Tr=dkγk.\mathrm{Tr}\mathop{\mathcal{L}}\nolimits=-d\sum_{k}\gamma_{k}. (48)

This relation was previously shown by direct computations based on unitary operator basis in [14] and matrix units in [15], respectively. Here, we give its simple derivation using the well-known super-operator representation of a \mathcal{L} [42]

^\displaystyle\hat{\mathop{\mathcal{L}}\nolimits} =\displaystyle= i(H1l1lHT)+kγkLkLk¯\displaystyle-i(H\otimes{\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}-{\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}\otimes H^{T})+\sum_{k}\gamma_{k}L_{k}\otimes\overline{L_{k}}
\displaystyle- 12LkLk1l121lLkTL¯k.\displaystyle\frac{1}{2}L^{\dagger}_{k}L_{k}\otimes{\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}-\frac{1}{2}{\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}\otimes L^{T}_{k}\overline{L}_{k}.

where TT is the transposition operation. Now the relation (47) is easily obtained by taking the trace operation and using the cyclic property of the trace. Finally, the facts that \mathop{\mathcal{L}}\nolimits has 0=0\ell_{0}=0 eigenvalues and the complex eigenvalues of \mathop{\mathcal{L}}\nolimits always appear as conjugate pairs shows

Tr=β=0d21β=β=1d21Γβ.\mathrm{Tr}\mathop{\mathcal{L}}\nolimits=\sum_{\beta=0}^{d^{2}-1}\ell_{\beta}=-\sum_{\beta=1}^{d^{2}-1}\Gamma_{\beta}.

Comparing this and (48), one gets Eq. (31).

Appendix F General form of generator (32)

In this section, we show that the covariant generators satisfying (32) has the form (33) with (34).

Lemma 2

A linear map Φ\Phi satisfies

U𝐱Φ(X)U𝐱=Φ(U𝐱XU𝐱),U_{\mathbf{x}}\Phi(X)U^{\dagger}_{\mathbf{x}}=\Phi(U_{\mathbf{x}}XU^{\dagger}_{\mathbf{x}}), (49)

for any 𝐱=(x1,,xd)d\mathbf{x}=(x_{1},\ldots,x_{d})\in\mathbb{R}^{d} if and only if it has a form

Φ(X)=i,j=1daijEijXEij+i,j=1dbijEiiXEjj.\Phi(X)=\sum_{i,j=1}^{d}a_{ij}E_{ij}XE_{ij}^{\dagger}+\sum_{i,j=1}^{d}b_{ij}E_{ii}XE_{jj}. (50)

[Proof] If Φ\Phi has the form (50), then one simply verifies (49). Assume that (49) is satisfied for any 𝐱\mathbf{x}. Then, one has

U𝐱Φ(Eij)U𝐱=Φ(U𝐱EijU𝐱)=ei(xixj)Φ(Eij)(i,j=1,,d).U_{\mathbf{x}}\Phi(E_{ij})U_{\mathbf{x}}^{\dagger}=\Phi(U_{\mathbf{x}}E_{ij}U_{\mathbf{x}}^{\dagger})=e^{i(x_{i}-x_{j})}\Phi(E_{ij})\ (i,j=1,\ldots,d). (51)

Letting Φ(Eij)=k,l=1daij;klEkl\Phi(E_{ij})=\sum_{k,l=1}^{d}a_{ij;kl}E_{kl}, this implies

aij;kl=ei(xixk)ei(xjxl)aij;kl(i,j,k,l=1,,d).a_{ij;kl}=e^{-i(x_{i}-x_{k})}e^{i(x_{j}-x_{l})}a_{ij;kl}\ (i,j,k,l=1,\ldots,d).

This can be true for any 𝐱\mathbf{x} if and only if aii;kla_{ii;kl} has the form:

aii;kl=cikδkla_{ii;kl}=c_{ik}\delta_{kl}

and

aij;kl=bijδikδjl(ij).a_{ij;kl}=b_{ij}\delta_{ik}\delta_{jl}\ (i\neq j).

In other words,

Φ(Eii)=k=1dcikEkk\Phi(E_{ii})=\sum_{k=1}^{d}c_{ik}E_{kk}

and

Φ(Eij)=bijEij(ij).\Phi(E_{ij})=b_{ij}E_{ij}\ (i\neq j).

Therefore, the general form of Φ\Phi reads

Φ(X)=Φ(i,j=1diXjEij)\displaystyle\Phi(X)=\Phi(\sum_{i,j=1}^{d}\langle i\rangle{Xj}E_{ij})
=\displaystyle= i,k=1diXicikEkk+ij=1diXjbijEij\displaystyle\sum_{i,k=1}^{d}\langle i\rangle{Xi}c_{ik}E_{kk}+\sum_{i\neq j=1}^{d}\langle i\rangle{Xj}b_{ij}E_{ij}
=\displaystyle= i,j=1dcijEjiXEji+i,j=1dbijEiiXEjj.\displaystyle\sum_{i,j=1}^{d}c_{ij}E_{ji}XE_{ji}^{\dagger}+\sum_{i,j=1}^{d}b_{ij}E_{ii}XE_{jj}.

By adding an arbitrary biib_{ii} and letting aij=cijbiiδija_{ij}=c_{ij}-b_{ii}\delta_{ij}, one gets the form (50). \square

Now, using the fact that any GKLS generator can be represented as

(ρ)=i[H,ρ]+Φ(ρ)12{Φ(1l),ρ},\mathcal{L}(\rho)=-i[H,\rho]+\Phi(\rho)-\frac{1}{2}\{\Phi^{\ddagger}({\mathchoice{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.0mul}{\rm 1\mskip-4.5mul}{\rm 1\mskip-5.0mul}}),\rho\}, (52)

one finds that condition (32) implies that HH is diagonal H=khk|kk|H=\sum_{k}h_{k}|k\rangle\langle k| and hence one arrives at (33).

Appendix G Proof of Proposition 2

Following the analysis of (17) one easily finds the same set of classical rates Γαcl\Gamma^{\rm cl}_{\alpha} and the rates Γkl\Gamma_{kl} are simple modification of (40):

Γkl=12(bk+bl+dkk+dlldkldlk),(kl),\Gamma_{kl}=\frac{1}{2}\Big{(}b_{k}+b_{l}+d_{kk}+d_{ll}-d_{kl}-d_{lk}\Big{)},\ \ \ (k\neq l), (53)

and one has

Γ:=β=1d21Γβ=dΓcl+(d1)idiiijRedij.\Gamma:=\sum_{\beta=1}^{d^{2}-1}\Gamma_{\beta}=d\Gamma^{\rm cl}+(d-1)\sum_{i}d_{ii}-\sum_{i\neq j}{\rm Re}\,d_{ij}. (54)

Since the positivity of the matrix D=[dij]D=[d_{ij}] implies the positivity of every principal sub-matrix, Redij|dij|diidjjdii+djj2{\rm Re}\ d_{ij}\leq|d_{ij}|\leq\sqrt{d_{ii}d_{jj}}\leq\frac{d_{ii}+d_{jj}}{2}. Summing this over all iji\neq j gives

(d1)idiiijRedij.(d-1)\sum_{i}d_{ii}\geq\sum_{i\neq j}{\rm Re}\,d_{ij}. (55)

It is therefore clear that

ΓdΓαcl.\Gamma\geq d\Gamma^{\rm cl}_{\alpha}. (56)

Now, we prove ΓdΓkl\Gamma\geq d\Gamma_{kl}. Without loosing generality we consider k=1k=1 and l=2l=2. Note that ΓdΓ12\Gamma\geq d\Gamma_{12} is equivalent to the following inequality

x+y0,x+y\geq 0, (57)

where

x:=dijtijd2(m1tm1+n2tn2),x:=d\sum_{i\neq j}t_{ij}-\frac{d}{2}\left(\sum_{m\neq 1}t_{m1}+\sum_{n\neq 2}t_{n2}\right), (58)

and

y:=(d1)idii12ij(dij+dji)d2(d11+d22)+d2(d12+d21).y:=(d-1)\sum_{i}d_{ii}-\frac{1}{2}\sum_{i\neq j}(d_{ij}+d_{ji})-\frac{d}{2}(d_{11}+d_{22})+\frac{d}{2}(d_{12}+d_{21}). (59)

Now, since all tij0t_{ij}\geq 0 one has x0x\geq 0 and hence to prove (57) it is enough to show that y0y\geq 0. Let us observe that

y=Tr(𝕁[AD]),y=\mathrm{Tr}(\mathbb{J}[A\circ D]), (60)

where ADA\circ D denotes Hadamard product, 𝕁ij=1\mathbb{J}_{ij}=1, and

A=(d21d2111d21d211111d1111d11111d1).A=\left(\begin{array}[]{ccccc}\frac{d}{2}-1&\frac{d}{2}-1&-1&\ldots&-1\\ \frac{d}{2}-1&\frac{d}{2}-1&-1&\ldots&-1\\ -1&-1&d-1&\ldots&-1\\ \vdots&\vdots&\ddots&\vdots&\vdots\\ -1&-1&\ldots&d-1&-1\\ -1&-1&\ldots&-1&d-1\end{array}\right). (61)

The matrix 𝕁ij\mathbb{J}_{ij} is positive definite. One finds that the eignevalues of the matrix AA read: {0,0,d,,d}\{0,0,d,\ldots,d\} which proves that AA is positive definite as well. Since D0D\geq 0 one has AD0A\circ D\geq 0. Finally y0y\geq 0 since the trace of 𝕁[AD]\mathbb{J}[A\circ D] has to be positive. This completes the proof of Proposition 2.

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