On the first three minimum Mostar indices of tree-like phenylenes

Chemical indices are a class of numerical invariants that are closely related to the structure of a chemical graph. Chemical indices can be used to predicte the structural and physic-chemical properties of a chemical molecular. They are mainly used for the quantitative characterisation of chemical structures and thus contribute to the study of QSAR, QSTR and QSPR relationships of chemical structures. In recent years, chemical indices have been found a wide range of applications in chemical science, medical science, complex networks, toxicology, etc. The combination of quantum chemistry and chemical graph theory has also become a promising area in the study of QSAR and QSPR.

Our convention in this paper follows [4] for notations that we omit here. Phenylenes are a class of chemical compounds in which the carbon atoms form 6-membered cycles and 4-membered cycles. Each 4-membered cycle(=square) is adjacent to two disjoint 6-membered cycles(=hexagons), and no two hexagons are adjacent [25]. If there is a hexagon of phenylene adjacent to three squares, we call it the tree-type phenylene (the definition of tree-type phenylene is similar to tree-type hexagonal system, see [7]). Related structures include extended sp-carbon nets and heterocyclic analogs. These molecules have great theoretical and potential practical significance in finding new molecules with (super) conductive properties [28].

Nowadays, phenylene is still a hot topic in many experimental and theoretical studies. Some topological properties of phenylenes has been established such as (total $\pi$-electron) energy [11], HOMO LUMO separation [13], cyclic conjugation [15], Kekulé structure count[12], Wiener index [10], PI index [6, 14], Detour index [21] and Kirchhoff index [23, 31].

Let $\mathscr{P}_{h}$ be the set of tree-like phenylenes with $h$ hexagons and $h-1$ squares. And $\mathscr{P}=\bigcup_{h=1}^{\infty}\mathscr{P}_{h}$. Suppose $P\in\mathscr{P}_{h}$, and $R$ is a hexagon of $P$. Then $R$ is called an $i$-hexagon, if it has exactly $i$ $(0\leq i\leq 3)$ adjacent squares in $P$. A $1$-hexagon is called a terminal hexagon of $P$. A $2$-hexagon is called turn-hexagon of $P$ if its two $2$-vertices (the vertices of degree $2$) are adjacent in $P$. A $3$-hexagon is called a full-hexagon of $P$. Let $\mathscr{P}_{h,i}\subseteq\mathscr{P}_{h}$ $(0\leq i\leq\lfloor\frac{h-1}{2}\rfloor)$ be the set of phenylenes with $i$ full-hexagons. Each graph in $\mathscr{P}_{h,0}$ (or denoted by $\mathcal{C}_{h}$ ) is called a phenylene chain. A phenylene chain is called a linear phenylene chain (denoted by $L_{h}$) if it contains no turn-hexagons. Let $\mathcal{C}_{h,i}\subseteq\mathcal{C}_{h}$ be the set of phenylene chains with $i$ turn-hexagons.

A segment of a phenylene chain $G\in\mathcal{C}_{h}$ is a maximal linear sub-chain. Denote by $S$ a non-terminal segment of a phenylene chain $G$. We call $S$ a non-zigzag segment (resp., a zigzag segment) if it’s two neighboring segments lie on the same sides (resp., on different sides) of the line through centers of all hexagons and squares on $S$.

Denote by $C_{L}(t_{1},t_{2},t_{3},\cdots,t_{k},t_{k+1})$ the phenylene chain with $h$ hexagons and exactly $k+1$ segments $S_{1},S_{2},\cdots,$ $S_{k+1}$ of lengths $t_{1}+1,t_{2}+2,t_{3}+2,\cdots,t_{k}+2,t_{k+1}+1$, respectively, where $S_{1}$ and $S_{k+1}$ are the terminal segments, all $S_{i}$ $(2\leq i\leq k)$ are zagzig segments, $1\leq t_{1}\leq t_{k+1}$, and $\sum\limits_{i=1}^{k+1}t_{i}+k=h$. Particularly, $C_{L}(j,n)\in\mathcal{C}_{h,1}$ is the graph including two vertex-disjoint linear phenylene chains $L_{j}$ and $L_{n}$ as subgraphs, where $j\leq n$, and $h=j+n+1$. $C_{L}(j,k,n)\in\mathcal{C}_{h,2}$ is the graph including three vertex-disjoint linear phenylene chains $L_{j}$, $L_{k}$ and $L_{n}$ as subgraphs, where $j\leq n$, the second segment is a zigzag segment and $h=j+k+n+2$.

Denote by $P_{L}(j,k,n)\in\mathscr{P}_{h,1}$ the graph including three vertex-disjoint linear phenylene chains $L_{j}$, $L_{k}$ and $L_{n}$ as subgraphs, where $j\leq k\leq n$, and $h=j+k+n+1$.

Došlić et al.[9] introduced Mostar index [9] of a graph $G$, which is defined as

Došlić et al. determined extremal values of Mostar index among trees and unicyclic graphs, then gave a cut method for computing the Mostar index of benzenoid systems.

Similarly, the edge Mostar index [20] is defined as

where $m_{u}$ (resp.,$m_{v}$) is the number of edges whose distance to vertex $u$ (resp., $v$) is smaller than the distance to vertex $v$ (resp., $u$). We can refer to [1, 2, 3, 7, 8, 9, 16, 17, 18, 19, 20, 22, 26, 27, 29, 30] for more details about (edge) Mostar index.

Mostar indices can be used to measure the peripherality of chemical graphs, so in addition to chemical applications, Mostar indices have a wide range of applications in complex networks. It can be used to describe structural properties of the network. Mostar indices can also be used to extend quantum estimates and expand reactivity based on electronic descriptors. In this study, our aim is to solve the extremal problem of tree-like phenylenes with respect to Mostar indices. Using the methods of [7], we determine the first three minimum values of the Mostar index of tree-like phenylenes with a fixed number of hexagons and characterize all the tree-like phenylenes attaining these values.

An orthogonal cut is a line segment that starts from the middle of a peripheral edge of a phenylene, goes orthogonal to this edge and ends at the first next peripheral edge that it intersects. Let $P\in\mathscr{P}_{h}$. Denote by $\mathcal{O}_{P}^{uv}$ the set of edges that parallel with $uv$ in $P$, and $|\mathcal{O}_{P}^{uv}|=o_{P}^{uv}$. Let $\mathcal{O}_{P}$ be the set of all disjoint parallel classes in $P$. Note that $\mathcal{O}_{P}^{uv}$ is an edge cut, denote by $G_{P}^{u}$ $(resp.,G_{P}^{v})$ the connected components of $P-\mathcal{O}_{P}^{uv}$ contain $u$ $(resp.,v)$. Denote by $r_{P}^{u}$ $(resp.,r_{P}^{v})$ the number of hexagons in $G_{P}^{u}$ $(resp.,G_{P}^{v})$. Note that, for any $P\in\mathscr{P}_{h}$, $|V_{P}|=6h$ and $|E_{P}|=8h-2$.

Bearing in mind that $P_{L}(j,k,n)\in\mathscr{P}_{h,1}$ is the graph including three vertex-disjoint linear phenyene chains $L_{j}$, $L_{k}$ and $L_{n}$ as subgraphs, where $j\leq k\leq n$, and $h=j+k+n+1$. By the definition of $Mo(G)$, we can calculate the value of $Mo(P_{L}(j,k,n))$.

$(1)$ If $n\leq\lfloor\frac{h}{2}\rfloor$, then

$(2)$ If $n\geq\lfloor\frac{h}{2}\rfloor+1$, and $h$ is even, then

If $n\geq\lfloor\frac{h}{2}\rfloor+1$, and $h$ is odd, similarly, we have $Mo(G)=6(4j+3j^{2}+8k+3k^{2}+4n+3n^{2}+14kj+6jn+10kn)$.

This completes the proof. $\blacksquare$

Let $G\in\mathcal{C}_{h}$ and $R_{1}$, $R_{h}$ are two terminal hexagons of $G$. Denote by $x_{i,1},x_{i,2},\cdots,x_{i,6}$ the six clockwise successive vertices in $R_{i}$ for $i=1,h$, where $d_{G}(x_{i,j})=2$ for $j=1,2,3,4$. Let $e_{ij}=x_{i,j}x_{i,j+1}$ for $i=1,h$ and $j=1,2,\cdots,6$ (let $x_{i,7}:=x_{i,1}$).

Suppose that $P_{1},P_{2}\in\mathscr{P}$ and $u_{i},v_{i}$ be two adjacent $2$-vertices (vertices with degree 2) in $P_{i}$ for $i=1,2$. Let $P=P_{1}(u_{1},v_{1})\Box P_{2}(u_{2},v_{2})$ be the phenylene obtained from $P_{1},P_{2}$ by connecting $u_{1}$ with $u_{2}$, and $v_{1}$ with $v_{2}$, respectively.

For $uv\in E(G)$, we denote $n_{G}^{u}$ (or $n_{u}$) the number of vertices in $G$ lying closer to vertex $u$ than to vertex $v$. Some symbols involved in the proof are described in Section 2.

Note that $n\geq k-1$, then

$\phi_{1}(E_{d})=6\{2(n-k+1)+2kn+(o_{P}^{st}+2)|(r_{P}^{t}-r_{P}^{s})-(k-1)|\}$;

$\phi_{2}(E_{d})=6\{4(n-k+1)+(o_{P}^{st}+2k)(r_{P}^{t}-r_{P}^{s})\}$;

$\phi_{3}(E_{d})=6\{2(n-k+1)+2kn+(o_{P}^{st}+2)[(r_{P}^{t}-r_{P}^{s})+(k-1)]\}$.

Bearing in mind that $k\geq 2$ and $n=\frac{1}{2}o_{P}^{st}+r_{P}^{t}+r_{P}^{s}$.

If $r_{P}^{t}-r_{P}^{s}<k-1$, then $\phi_{1}(E_{d})-\phi_{2}(E_{d})=12(o_{P}^{st}+2)(k-1-(r_{P}^{t}-r_{P}^{s}))>0$.

This completes the proof. $\blacksquare$

By Lemma 3.1, we have

Let $P\in\mathscr{P}_{n+1}$, where $n\geq max\{j,k\}$, $j,k\geq 1$. $t_{1},t,s,s_{1}$ are vertices in Figure 2, and $r_{P}^{s}\leq r_{P}^{t}$, $h=j+k+n+1$. Then we have

Since $n\geq\max\{j,k\}$, then

Note that $n=\frac{1}{2}o_{P}^{st}+r_{P}^{t}+r_{P}^{s}-1$, $j,k\geq 1$ and $o_{P}^{st}\geq 2$.

$\phi_{1}(E_{d,1})-\phi_{2}(E_{d,2})=12(o_{P}^{st}k+2(k+j)r_{P}^{s}+4kj)>0$.

If $h$ is even, then $j+k\geq n+1$, and

If $h$ is odd, then $j+k\geq n$, and

Note that $n\geq j\geq k+1\geq 2$ and $o_{P}^{st}\geq 2$.

$\phi_{1}(E_{d,1})-\phi_{2}(E_{d,2})=12\{o_{P}^{st}(r_{P}^{s}+j-r_{P}^{t})+2(k+j)r_{P}^{s}+4kj\}>0$.

If $h$ is even, then $j+k\geq n+1$, and

If $h$ is odd, then $j+k\geq n$, and

Thus, $Mo(P_{2})<Mo(P_{1})$. This completes the proof. $\blacksquare$

By Lemma 3.1, we can directly obtain the smallest Mostar index among $\mathcal{C}_{h}$.

By Corollary 3.2, Lemma 3.3 and Lemma 3.4, we can obtain the smallest Mostar index among $\mathscr{P}_{h}$. The proof of Theorem 3.5 follows from the same arguments as the proof of Theorem 1.3 of [7], thus we omit the proof.

Bearing in mind that $C_{L}(j,n)\in\mathcal{C}_{h,1}$ is the graph including two vertex-disjoint linear phenylene chains $L_{j}$ and $L_{n}$ as subgraphs, where $j\leq n$, and $h=j+n+1$. $C_{L}(j,k,n)\in\mathcal{C}_{h,2}$ is the graph including three vertex-disjoint linear phenylene chains $L_{j}$, $L_{k}$ and $L_{n}$ as subgraphs, where $j\leq n$, the second segment is a zigzag segment and $h=j+k+n+2$. In the following, we give some useful results for our proofs of main theorem.

Using the cut method to $C_{L}(j,h-j-1)$ and $L_{h}$, and comparing the change of Mostar index among $C_{L}(j,h-j-1)$ and $L_{h}$, we also have

By Lemma 3.1, Lemma 4.1 and Lemma 3.4, we can also obtain the second minimum Mostar index among phenylene chains $\mathcal{C}_{h}$.