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On the classification of normal Stein spaces and finite ball quotients with Bergman-Einstein metrics

Peter Ebenfelt Department of Mathematics, University of California at San Diego, La Jolla, CA 92093, USA [email protected] Ming Xiao Department of Mathematics, University of California at San Diego, La Jolla, CA 92093, USA [email protected]  and  Hang Xu Department of Mathematics, University of California at San Diego, La Jolla, CA 92093, USA [email protected]
Abstract.

In this paper, we study the Bergman metric of a finite ball quotient 𝔹n/Γ\mathbb{B}^{n}/\Gamma, where ΓAut(𝔹n)\Gamma\subseteq\operatorname{Aut}(\mathbb{B}^{n}) is a finite, fixed point free, abelian group. We prove that this metric is Kähler–Einstein if and only if Γ\Gamma is trivial, i.e., when the ball quotient 𝔹n/Γ\mathbb{B}^{n}/\Gamma is the unit ball 𝔹n\mathbb{B}^{n} itself. As a consequence, we establish a characterization of the unit ball among normal Stein spaces with isolated singularities and abelian fundamental groups in terms of the existence of a Bergman-Einstein metric.

2010 Mathematics Subject Classification:
32F45, 32Q20, 32E10,32C20
The first and second authors were supported in part by the NSF grants DMS-1900955 and DMS-1800549, respectively.

1. Introduction

Since the introduction of the Bergman kernel in [3, 4] and the subsequent groundbreaking work of Kobayashi [21] and Fefferman [12], the study of the Bergman kernel and metric has been a central subject in several complex variables and complex geometry. A general problem of fundamental importance seeks to characterize complex analytic spaces in terms of geometric properties of their Bergman metrics. The Bergman kernel of the unit ball 𝔹nn\mathbb{B}^{n}\subseteq\mathbb{C}^{n}, for example, is explicitly known,

K𝔹n(z,w¯)=n!πn1(1z,w¯)n+1,z,w¯=j=1nzjw¯j,K_{\mathbb{B}^{n}}(z,\bar{w})=\frac{n!}{\pi^{n}}\frac{1}{(1-\left<z,\bar{w}\right>)^{n+1}},\quad\left<z,\bar{w}\right>=\sum_{j=1}^{n}z_{j}\bar{w}_{j},

and it is routine to verify that the Bergman metric,

(g𝔹n)ij¯=2ziz¯jlogK𝔹n(z,z¯),(g_{\mathbb{B}^{n}})_{i\bar{j}}=\frac{\partial^{2}}{\partial{z_{i}}\partial{\bar{z}_{j}}}\log K_{\mathbb{B}^{n}}(z,\bar{z}),

is Kähler-Einstein, i.e., has Ricci curvature equal to a constant multiple of the metric tensor; indeed, the Bergman metric of the unit ball has constant holomorphic sectional curvature, which implies the Kähler-Einstein property. A well-known conjecture posed by S.-Y. Cheng [8] in 1979 asserts that the Bergman metric of a bounded, strongly pseudoconvex domain in n\mathbb{C}^{n} with smooth boundary is Kähler-Einstein if and only if the domain is biholomorphic to the unit ball 𝔹n\mathbb{B}^{n}. There are also variations of this conjecture in terms of other canonical metrics; see, e.g., Li [23, 24, 25] and references therein.

The aforementioned Cheng Conjecture was confirmed by S. Fu–B. Wong [15] and S. Nemirovski–R. Shafikov [27] in the two dimensional case and by X. Huang and the second author [19] in higher dimensions. X. Huang and X. Li [17] recently generalized this result to Stein manifolds with strongly pseudoconvex boundary as follows: The only Stein manifold with smooth and compact strongly pseudoconvex boundary for which the Bergman metric is Kähler-Einstein is the unit ball 𝔹n\mathbb{B}^{n} (up to biholomorphism). These results lead naturally to the question of whether a similar characterization of 𝔹n\mathbb{B}^{n} holds in the setting of normal Stein spaces with possible singularities; see Conjecture 1.4 in [18]. In this paper, we provide strong evidence that this is the case. The following two theorems establish the first results that the authors are aware of characterizing the unit ball among normal Stein spaces with possible singularities in terms of the existence of a Bergman-Einstein metric.

Theorem 1.1.

Let VV be an nn-dimensional Stein space in N\mathbb{C}^{N} with N>n2N>n\geq 2, and G=V𝔹NG=V\cap\mathbb{B}^{N}. Assume that every point in G¯\overline{G} is a smooth point of VV, except for finitely many normal singularities in GG, and that GG has a smooth boundary. Then the Bergman metric of GG is Kähler-Einstein if and only if GG is biholomorphic to 𝔹n\mathbb{B}^{n}.

Theorem 1.2.

Let VV be an nn-dimensional Stein space in N\mathbb{C}^{N} with N>n2N>n\geq 2 and ΩN\Omega\subseteq\mathbb{C}^{N} a bounded strongly pseudoconvex domain with smooth and real-algebraic boundary. Write G=VΩ.G=V\cap\Omega. Assume every point in G¯\overline{G} is a smooth point of VV, except for finitely many normal singularities in GG, and that GG has a smooth boundary. Then the following are equivalent:

  • (i)

    GG is biholomorphic to 𝔹n\mathbb{B}^{n}.

  • (ii)

    The fundamental group of the regular part of GG is abelian and the Bergman metric of GG is Kähler-Einstein.

Remark 1.3.

As we will see in the proof (Section 3), if GG itself is assumed to be bounded in Theorem 1.2, then the boundedness assumption on Ω\Omega can be dropped.

We shall utilize the work of D’Angelo–Lichtblau [10] (see also F. Forstnerič [14]) and X. Huang [16], as well as methods from [19], [17] and [11] to reduce the proofs of Theorems 1.1 and 1.2 to that of the following theorem, which is one of the main results in the paper.

Theorem 1.4.

Let Γ\Gamma be a finite abelian subgroup of Aut(𝔹n)\operatorname{Aut}(\mathbb{B}^{n}), n2n\geq 2, and assume Γ\Gamma is fixed point free. Then the Bergman metric of 𝔹n/Γ\mathbb{B}^{n}/\Gamma is Kähler-Einstein if and only if Γ\Gamma is the trivial group consisting of the identity element.

Here a subgroup Γ\Gamma of Aut(𝔹n)\operatorname{Aut}(\mathbb{B}^{n}) is called fixed point free if the only element γΓ\gamma\in\Gamma with a fixed point on 𝔹n\partial\mathbb{B}^{n} is the identity. The fixed point free condition on Γ\Gamma guarantees that the quotient space 𝔹n/Γ\mathbb{B}^{n}/\Gamma has smooth boundary (see [14]). Moreover, as we shall see in Section 4, an abelian fixed point free finite group Γ\Gamma is in fact cyclic.

To prove Theorem 1.4, it suffices to show that if Γ\Gamma is not the trivial group, i.e., Γ{id}\Gamma\neq\{\mathrm{id}\}, then the Bergman metric is not Kähler-Einstein. For that, we shall use the transformation formula for the Bergman kernel under branched holomorphic coverings of complex analytic spaces; see Theorem 2.3 below. A crucial step in the proof is to reduce the non-Einstein condition to several combinatorial inequalities. The proofs of these combinatorial inequalities are technical and will be given in a separate section; see Section 5.

We remark that the analogue of Theorem 1.4 is not true in the case n=1n=1. If we denote the unit disk in \mathbb{C} by 𝔻\mathbb{D} (=𝔹1=\mathbb{B}^{1}), then one readily verifies that any finite subgroup ΓAut(𝔻)\Gamma\subseteq\mathrm{Aut}(\mathbb{D}) must be fixed point free and cyclic. Nevertheless, in this case, X. Huang and X. Li [17] proved the very interesting result that the Bergman metric of 𝔻/Γ\mathbb{D}/\Gamma always has constant Gaussian curvature, which is equivalent to being Kähler-Einstein in the one-dimensional case.

The paper is organized as follows. Section 2 recalls some preliminaries on the Bergman metric and finite ball quotients. In Section 3, we prove that Theorems 1.1 and 1.2 follow from Theorem 1.4. Theorem 1.4 is then proved in Section 4, except for some combinatorial lemmas used in the proof that are left to Section 5.

2. Preliminaries

2.1. The Bergman kernel

In this subsection, we will briefly review some properties of the Bergman kernel and metric on a complex manifold. More details can be found in [21] and [22].

Let MM be an nn-dimensional complex manifold. Let L(n,0)2(M)L^{2}_{(n,0)}(M) denote the space of L2L^{2}-integrable (n,0)(n,0)-forms on M,M, equipped with the inner product

(2.1) (φ,ψ)L2(M):=in2Mφψ¯,φ,ψL(n,0)2(M).(\varphi,\psi)_{L^{2}(M)}:=i^{n^{2}}\int_{M}\varphi\wedge\overline{\psi},\quad\varphi,\psi\in L^{2}_{(n,0)}(M).

Define the Bergman space of MM to be

(2.2) A(n,0)2(M):={φL(n,0)2(M):φ is a holomorphic (n,0)-form on M}.A^{2}_{(n,0)}(M):=\bigl{\{}\varphi\in L^{2}_{(n,0)}(M):\varphi\mbox{ is a holomorphic $(n,0)$-form on $M$}\}.

Assume A(n,0)2(M){0}A^{2}_{(n,0)}(M)\neq\{0\}. Then A(n,0)2(M)A^{2}_{(n,0)}(M) is a separable Hilbert space. Taking any orthonormal basis {φk}k=1q\{\varphi_{k}\}_{k=1}^{q} of A(n,0)2(M)A^{2}_{(n,0)}(M) with 1q1\leq q\leq\infty, we define the Bergman kernel (form) of MM to be

KM(x,y¯)=in2k=1qφk(x)φk(y)¯.K_{M}(x,\bar{y})=i^{n^{2}}\sum_{k=1}^{q}\varphi_{k}(x)\wedge\overline{\varphi_{k}(y)}.

Then, KM(x,x¯)K_{M}(x,\bar{x}) is a real-valued, real-analytic form of degree (n,n)(n,n) on MM and is independent of the choice of orthonormal basis.

The Bergman kernel form remains unchanged if we remove a proper complex analytic subvariety, as the following theorem from [21] shows:

Theorem 2.1 ([21]).

If MM^{\prime} is a domain in an nn-dimensional complex manifold MM and if MMM-M^{\prime} is a complex analytic subvariety of MM of complex dimension n1\leq n-1, then

KM(x,y¯)=KM(x,y¯) for any x,yM.K_{M}(x,\bar{y})=K_{M^{\prime}}(x,\bar{y})\quad\mbox{ for any }x,y\in M^{\prime}.

This theorem suggests the following generalization of the Bergman kernel form to complex analytic spaces.

Definition 2.2.

Let MM be a reduced complex analytic space, and let VMV\subseteq M denote its set of singular points. The Bergman kernel form of MM is defined as

KM(x,y¯)=KMV(x,y¯) for any x,yMV,K_{M}(x,\bar{y})=K_{M-V}(x,\bar{y})\quad\mbox{ for any }x,y\in M-V,

where KMVK_{M-V} denotes the Bergman kernel form of the complex manifold consisting of regular points of MM.

Let N1,N2N_{1},N_{2} be two complex manifolds of dimension nn. Let γ:N1M\gamma:N_{1}\rightarrow M and τ:N2M\tau:N_{2}\rightarrow M be holomorphic maps. The pullback of the Bergman kernel KM(x,y¯)K_{M}(x,\bar{y}) of MM to N1×N2N_{1}\times N_{2} is defined in the standard way. That is, for any zN1,wN2z\in N_{1},w\in N_{2},

((γ,τ)KM)(z,w¯)=k=1qγφk(z)τφk(w)¯.\bigl{(}(\gamma,\tau)^{*}K_{M}\bigr{)}(z,\bar{w})=\sum_{k=1}^{q}\gamma^{*}\varphi_{k}(z)\wedge\overline{\tau^{*}\varphi_{k}(w)}.

In terms of local coordinates, we may write the Bergman kernel form of MM as

(2.3) KM(x,y¯)=K~M(x,y¯)dx1dxndy1¯dyn¯,K_{M}(x,\bar{y})=\widetilde{K}_{M}(x,\bar{y})dx_{1}\wedge\cdots dx_{n}\wedge d\overline{y_{1}}\wedge\cdots\wedge d\overline{y_{n}},

where the function K~M(x,y¯)\widetilde{K}_{M}(x,\bar{y}) depends on the choice of local coordinates. We then have

(2.4) ((γ,τ)KM)(z,w¯)=K~M(γ(z),τ(w)¯)Jγ(z)Jτ(w)¯dz1dzndw1¯dwn¯,\bigl{(}(\gamma,\tau)^{*}K_{M}\bigr{)}(z,\bar{w})=\widetilde{K}_{M}(\gamma(z),\overline{\tau(w)})\,J_{\gamma}(z)\,\overline{J_{\tau}(w)}\,dz_{1}\wedge\cdots dz_{n}\wedge d\overline{w_{1}}\wedge\cdots\wedge d\overline{w_{n}},

where JγJ_{\gamma} and JτJ_{\tau} are the Jacobian determinants of the maps γ\gamma and τ\tau, respectively. In particular, we observe that the kernel function K~M(x,y¯)\widetilde{K}_{M}(x,\bar{y}) transforms accordining to the usual biholomorphic invariance formula under changes of local coordinates.

Let MM be as in Definition 2.2. Assume KM(x,x¯)K_{M}(x,\bar{x}) is non-vanishing (on the set of regular points of MM, where it is defined). We define a Hermitian (1,1)(1,1)-form on the regular part of MM by

(2.5) ωM:=i¯logK~M(x,x¯).\omega_{M}:=i\,\partial\overline{\partial}\log\widetilde{K}_{M}(x,\bar{x}).

The biholomorphic invariance of the Bergman kernel implies that this form is independent of the choice of local coordinates used to determine the function K~M(x,x¯)\widetilde{K}_{M}(x,\bar{x}). The Bergman metric on MM is the metric induced by ωM\omega_{M} (when it indeed induces a positive definite metric on the regular part of MM).

We recall the Bergman kernel transformation formula in [11] for (possibly branched) covering maps of complex analytic spaces. This formula generalizes a classical theorem of Bell ([1], [2]; see also [7]):

Theorem 2.3.

Let M1M_{1} and M2M_{2} be two complex analytic sets. Let V1M1V_{1}\subseteq M_{1} and V2M2V_{2}\subseteq M_{2} be proper analytic subvarieties such that M1V1,M2V2M_{1}-V_{1},M_{2}-V_{2} are complex manifolds of the same dimension. Assume that f:M1V1M2V2f:M_{1}-V_{1}\rightarrow M_{2}-V_{2} is a finite (mm-sheeted) holomorphic covering map. Let Γ\Gamma be the deck transformation group for the covering map (with |Γ|=m|\Gamma|=m), and denote by KiK_{i} the Bergman kernels of MiM_{i} for i=1,2i=1,2. Then the Bergman kernel forms transform according to

γΓ(id,γ)K1=(f,f)K2on(M1V1)×(M1V1),\sum_{\gamma\in\Gamma}(\mathrm{id},\gamma)^{*}K_{1}=(f,f)^{*}K_{2}\quad\leavevmode\nobreak\ \text{on}\leavevmode\nobreak\ (M_{1}-V_{1})\times(M_{1}-V_{1}),

where id:M1M1\mathrm{id}:M_{1}\rightarrow M_{1} is the identity map.

2.2. Finite ball quotients

In this subsection, we recall the canonical realization of a finite ball quotient due to H. Cartan [6]. Let 𝔹n\mathbb{B}^{n} denote the unit ball in n\mathbb{C}^{n} and Aut(𝔹n)\text{Aut}(\mathbb{B}^{n}) its (biholomorphic) automorphism group. Let Γ\Gamma be a finite subgroup of Aut(𝔹n)\text{Aut}(\mathbb{B}^{n}). Assume Γ\Gamma is fixed point free; that is, assume no γΓ{id}\gamma\in\Gamma-\{\mathrm{id}\} has any fixed points on 𝔹n\partial\mathbb{B}^{n}. As the unitary group U(n)U(n) is a maximal compact subgroup of Aut(𝔹n)\operatorname{Aut}(\mathbb{B}^{n}), by basic Lie group theory, there exists some ψAut(𝔹n)\psi\in\operatorname{Aut}(\mathbb{B}^{n}) such that Γψ1U(n)ψ\Gamma\subseteq\psi^{-1}\cdot U(n)\cdot\psi. Thus without loss of generality, we can assume ΓU(n)\Gamma\subseteq U(n), i.e., Γ\Gamma is a finite unitary subgroup. The origin 0n0\in\mathbb{C}^{n} is then always a fixed point of every element in Γ\Gamma. Moreover, the fixed point free condition on Γ\Gamma is equivalent to the assertion that every γΓ{id}\gamma\in\Gamma-\{\mathrm{id}\} has no other fixed point than 0. We also note that, by the fixed point free condition, the action of Γ\Gamma on 𝔹n\partial\mathbb{B}^{n} is properly discontinuous and 𝔹n/Γ\partial\mathbb{B}^{n}/\Gamma is a smooth manifold.

By a theorem of H. Cartan [6], the quotient n/Γ\mathbb{C}^{n}/\Gamma can be realized as a normal algebraic subvariety VV in some N\mathbb{C}^{N}. To be more precise, we write 𝒜\mathcal{A} for the algebra of Γ\Gamma-invariant holomorphic polynomials, that is,

𝒜:={p[z1,,zn]:pγ=p for all γΓ}.\mathcal{A}:=\big{\{}p\in\mathbb{C}[z_{1},\cdots,z_{n}]:p\circ\gamma=p\,\mbox{ for all }\gamma\in\Gamma\big{\}}.

By Hilbert’s basis theorem, 𝒜\mathcal{A} is finitely generated. Moreover, we can find a minimal set of homogeneous polynomials {p1,,pN}𝒜\{p_{1},\cdots,p_{N}\}\subseteq\mathcal{A} such that every p𝒜p\in\mathcal{A} can be expressed in the form

p(z)=q(p1(z),,pN(z)),p(z)=q(p_{1}(z),\cdots,p_{N}(z)),

where qq is some holomorphic polynomial in N\mathbb{C}^{N}. The map Q:=(p1,,pN):nNQ:=(p_{1},\cdots,p_{N}):\mathbb{C}^{n}\rightarrow\mathbb{C}^{N} is proper and induces a homeomorphism of n/Γ\mathbb{C}^{n}/\Gamma onto V:=Q(n)V:=Q(\mathbb{C}^{n}). As QQ is a proper holomorphic polynomial map, VV is an algebraic variety. The restriction of QQ to the unit ball 𝔹n\mathbb{B}^{n} maps 𝔹n\mathbb{B}^{n} properly onto a relatively compact domain ΩV\Omega\subseteq V. In this way, 𝔹n/Γ\mathbb{B}^{n}/\Gamma is realized as Ω\Omega by QQ. Following [28], we call such QQ the basic map associated to Γ\Gamma. The ball quotient Ω=𝔹n/Γ\Omega=\mathbb{B}^{n}/\Gamma is nonsingular if and only if the group Γ\Gamma is generated by reflections, i.e., elements of finite order in U(n)U(n) that fix a complex subspace of dimension n1n-1 in n\mathbb{C}^{n} (see [28]); thus, if Γ\Gamma is fixed point free and nontrivial, then Ω=𝔹n/Γ\Omega=\mathbb{B}^{n}/\Gamma must have singularities. Moreover, Ω\Omega has smooth boundary if and only if Γ\Gamma is fixed point free (see [14] for more results along this line).

3. Proof of Theorem 1.1 and 1.2

In this section, we prove that Theorem 1.1 and 1.2 follow from Theorem 1.4; see Section 3.2 and 3.1, respectively.

3.1. Proof of Theorem 1.2

The implication (i) \implies (ii) in Theorem 1.2 is trivial. We therefore only need to prove the converse. Let GG be as in Theorem 1.2 and assume the conditions in (ii) hold. To prove (i), assuming that Theorem 1.4 has been proved, we proceed in three steps.

Step 1. It follows from the assumption that the boundary G\partial G is strongly pseudoconvex. We first prove that the boundary G\partial G is indeed spherical. Recall that a CR hypersurface MM of dimension 2n12n-1 is said to be spherical if it is locally CR diffeomorphic, near every point, to an open piece of the unit sphere S2n1nS^{2n-1}\subseteq\mathbb{C}^{n}. To prove that G\partial G is spherical near a given boundary point qGq\in\partial G, one first uses the Kähler-Einstein assumption and the localization of the Bergman kernel (see [12], [5] and also see Proposition 3.1 in [17] for a detailed and nice proof) near qq to study the coefficients in Fefferman’s expansion of the Bergman kernel of a smaller domain in VV, which shares an open piece of its boundary with GG and is biholomorphic to a smoothly bounded strongly pseudoconvex domain in n\mathbb{C}^{n}. In the two-dimensional case (n=2n=2), one applies the argument in [15] (see Section 2 in [15]) to prove that the coefficient of the logarithmic term in Fefferman’s expansion of the Bergman kernel vanishes to infinite order at in an open neighborhood of qq. Using the (local) resolution of the Ramadanov Conjecture in 2\mathbb{C}^{2}, as in [15], one deduces that G\partial G is spherical. In the higher dimensional case (n3n\geq 3), one uses the argument in [19] (see the proof of Theorem 1.1 in [19]) to study the coefficient of the principle term (strong singularity) in Fefferman’s expansion of the Bergman kernel and prove that every boundary point of GG is CR-umbilical, which implies that G\partial G is spherical. The detailed proof for step 1 is contained in [17] (see Theorem 1.1 in [17]). We will omit the proof here.

Step 2. In this step, we prove that GG is biholomorphic to a ball quotient 𝔹n/Γ\mathbb{B}^{n}/\Gamma for some finite fixed point free subgroup ΓU(n)\Gamma\subseteq U(n). Since we know G\partial G is spherical from Step 1 and G\partial G is contained in a real algebraic hypersurface in N\mathbb{C}^{N}, it follows from Corollary 3.3 in [16] that G\partial G is CR equivalent to CR spherical space form S2n1/ΓS^{2n-1}/\Gamma where ΓU(n)\Gamma\subseteq U(n) is as above. More precisely, there is an algebraic CR map F:S2n1GF:S^{2n-1}\rightarrow\partial G, which is a finite covering map. From this one can further prove that GG is biholomorphic to 𝔹n/Γ\mathbb{B}^{n}/\Gamma. The proof of this is identical with Step 3 in Section 5 of [11]. The general setting of [11] is in dimension n=2n=2, but, as pointed out in Remark 5.4 in [11], this argument works for all dimensions. The argument shows that FF extends to a proper, holomorphic branched covering map from 𝔹n\mathbb{B}^{n} onto GG, which realizes GG as the ball quotient 𝔹n/Γ\mathbb{B}^{n}/\Gamma. In particular, GG is biholomorphic to 𝔹n/Γ\mathbb{B}^{n}/\Gamma as claimed. Since ΓU(n)\Gamma\subseteq U(n) is fixed point free, either GG has one unique singular point at F(0)F(0) when Γ{id}\Gamma\neq\{\mathrm{id}\} or GG is smooth when Γ={id}\Gamma=\{\mathrm{id}\}. In the former case, F:𝔹n{0}G{F(0)}F:\mathbb{B}^{n}-\{0\}\rightarrow G-\{F(0)\} is a smooth covering map whose group of deck transformations is Γ\Gamma, and in the latter case, FF extends as a biholomorphism 𝔹nG\mathbb{B}^{n}\to G.

Step 3. By the conclusion in Step 2, the fundamental group of the regular part of GG is isomorphic to Γ\Gamma. By assumption in (ii), Γ\Gamma is abelian. Moreover, the biholomorphism between GG and 𝔹n/Γ\mathbb{B}^{n}/\Gamma gives an isometry between the Bergman metrics of GG and 𝔹n/Γ\mathbb{B}^{n}/\Gamma. By assumption in (ii) again, the Bergman metric of 𝔹n/Γ\mathbb{B}^{n}/\Gamma is Kähler-Einstein. Thus, by Theorem 1.4, Γ\Gamma must then be the trivial group {id}\{\mathrm{id}\}. Hence GG is biholomorphic to 𝔹n\mathbb{B}^{n}. ∎

3.2. Proof of Theorem 1.1

We now prove Theorem 1.1, under the assumption that Theorem 1.4 has been proved. The "if" implication is trivial, and we only need to prove the converse. Thus, we assume that GG is as in Theorem 1.1 and the Bergman metric of GG is Kähler-Einstein, and we shall prove GG is biholomorphic to 𝔹n\mathbb{B}^{n}. By copying the argument in Step 1 and Step 2 in Section 3.1, we conclude that there is an algebraic CR map FF from S2n1S^{2n-1} to G𝔹N=S2N1\partial G\subseteq\partial\mathbb{B}^{N}=S^{2N-1}, which is a finite covering map. In particular, the map FF induces a smooth, nonconstant CR map from the spherical space form S2n1/ΓS^{2n-1}/\Gamma, for some finite fixed point free subgroup ΓAut(𝔹n)\Gamma\subseteq\operatorname{Aut}(\mathbb{B}^{n}), to S2N1S^{2N-1} (see [26], [10] and [9]). Since Γ\Gamma is a finite subgroup of Aut(𝔹n)\operatorname{Aut}(\mathbb{B}^{n}), by basic Lie group theory as above, Γ\Gamma is contained in a conjugate of the unitary group U(n)U(n). By Theorem 8 in [10], Γ\Gamma is conjugate to one in a short list of special cyclic subgroups of U(n)U(n). In particular, the finite subgroup Γ\Gamma, as well as the fundamental group of the regular part of GG then, is abelian. Now, Theorem 1.1 follows from Theorem 1.2. ∎

4. Proof of Theorem 1.4

In this section, we shall prove Theorem 1.4. It suffices to prove the Bergman metric of 𝔹n/Γ\mathbb{B}^{n}/\Gamma cannot be Kähler-Einstein if ΓAut(𝔹n)\Gamma\subseteq\mathrm{Aut}(\mathbb{B}^{n}) is nontrivial, abelian, and fixed point free. We will prove this by contradiction. Thus, we suppose ΓAut(𝔹n)\Gamma\subseteq\mathrm{Aut}(\mathbb{B}^{n}) is abelian and fixed point free, Γ{id},\Gamma\neq\{\mathrm{id}\}, and the Bergman kernel of Ω=𝔹n/Γ\Omega=\mathbb{B}^{n}/\Gamma is Kähler-Einstein. As before, we know Γ\Gamma is contained in a conjugate of U(n).U(n). Thus, without loss of generality, we will assume ΓU(n).\Gamma\subseteq U(n).

We shall split our proof into three subsections. Section 4.1 reduces the Kähler-Einstein condition of the Bergman metric to a functional equation (see equation (4.8)) for general finite, fixed point free groups ΓAut(𝔹n)\Gamma\subset\operatorname{Aut}(\mathbb{B}^{n}). In Section 4.2, we focus on the case where the group Γ\Gamma is additionally assumed to be abelian, and simplify the equation further into a rather explicit one (see equation (4.13)). After that, in Section 4.3, we take the Taylor expansion of both sides of the equation. By carefully comparing the lowest order Taylor terms, we conclude that they can never match up due to some combinatorial inequalities. The proofs of these inequalities are then given in Section 5, which concludes the proof of Theorem 1.4.

4.1. The Kähler-Einstein equation on finite ball quotients

Since any two realizations of 𝔹n/Γ\mathbb{B}^{n}/\Gamma are biholomorphic, we can use H. Cartan’s canonical realization of 𝔹n/Γ\mathbb{B}^{n}/\Gamma, which was discussed Section 2.2. Thus, let Q:nNQ:\mathbb{C}^{n}\rightarrow\mathbb{C}^{N} be the basic map realizing 𝔹/Γ\mathbb{B}/\Gamma as a domain Ω:=Q(𝔹n)\Omega:=Q(\mathbb{B}^{n}) in the nn-dimensional algebraic variety Q(n)Q(\mathbb{C}^{n}), as explained in Section 2.2. Set

Z:={zn:the Jacobian of Q at z is not of full rank}.Z:=\{z\in\mathbb{C}^{n}:\mbox{the Jacobian of $Q$ at $z$ is not of full rank}\}.

Note that in fact Z={0}Z=\{0\} by the fixed point free condition and nontriviality of Γ\Gamma (see [6] and [11]). We denote by KΩK_{\Omega} and K𝔹nK_{\mathbb{B}^{n}} the Bergman kernel forms of Ω\Omega and 𝔹n\mathbb{B}^{n} respectively. By the transformation formula in Theorem 2.3, they are related by

(4.1) γΓ(id,γ)K𝔹n=(Q,Q)KΩon(𝔹nZ)×(𝔹nZ),\sum_{\gamma\in\Gamma}(\mathrm{id},\gamma)^{*}K_{\mathbb{B}^{n}}=(Q,Q)^{*}K_{\Omega}\quad\leavevmode\nobreak\ \text{on}\leavevmode\nobreak\ (\mathbb{B}^{n}-Z)\times(\mathbb{B}^{n}-Z),

where id:𝔹n𝔹n\mathrm{id}:\mathbb{B}^{n}\rightarrow\mathbb{B}^{n} is the identity map. We note that

Q(i¯logK~Ω)=i¯log((Q,Q)K~Ω).Q^{*}(i\partial\overline{\partial}\log\widetilde{K}_{\Omega})=i\partial\overline{\partial}\log((Q,Q)^{*}\widetilde{K}_{\Omega}).

Furthermore, we also note that the Kähler-Einstein condition is a local property and that QQ is a local biholomorphism (on 𝔹nZ\mathbb{B}^{n}-Z). It follows that the Bergman metric of Ω\Omega is Kähler-Einstein if and only if the logarithm of the left hand side of (4.1), restricted to the diagonal w=zw=z, gives the potential function of a Kähler-Einstein metric on 𝔹nZ.\mathbb{B}^{n}-Z.

Recall the notation u,v=i=1nuivi\langle u,v\rangle=\sum_{i=1}^{n}u_{i}v_{i} for two column vectors u=(u1,,un),v=(v1,,vn)u=(u_{1},\cdots,u_{n})^{\intercal},v=(v_{1},\cdots,v_{n})^{\intercal}. Set dγ:=detγd_{\gamma}:=\det\gamma for γU(n)\gamma\in U(n). The left hand side of (4.1), in the standard coordinates z,wz,w of n\mathbb{C}^{n}, equals

γΓ(id,γ)K𝔹n=n!πnγΓdγ¯(1z,γw¯)n+1dz1dzndw¯1dw¯n,\sum_{\gamma\in\Gamma}(\mathrm{id},\gamma)^{*}K_{\mathbb{B}^{n}}=\frac{n!}{\pi^{n}}\sum_{\gamma\in\Gamma}\frac{\overline{d_{\gamma}}}{(1-\langle z,\overline{\gamma w}\rangle)^{n+1}}dz_{1}\wedge\ldots dz_{n}\wedge d\overline{w}_{1}\wedge\ldots\wedge d\overline{w}_{n},

where z,w𝔹nz,w\in\mathbb{B}^{n} are regarded as column vectors and the elements of Γ\Gamma as unitary matrices. We introduce the function

φ(z,w¯):=γΓdγ¯(1z,γw¯)n+1,\varphi(z,\overline{w}):=\sum_{\gamma\in\Gamma}\frac{\overline{d_{\gamma}}}{(1-\langle z,\overline{\gamma w}\rangle)^{n+1}},

and note that φ(z,z¯)\varphi(z,\overline{z}) is real analytic on 𝔹n.\mathbb{B}^{n}. By the preceding discussion, we conclude that the Bergman metric of Ω\Omega is Kähler-Einstein if and only if φ=φ(z,z¯)\varphi=\varphi(z,\bar{z}) is the potential function of a Kähler-Einstein metric, i.e., for z𝔹nZz\in\mathbb{B}^{n}-Z and some constant c1c_{1}\in\mathbb{R},

(4.2) ¯logG(z,z¯)=c1¯logφ(z,z¯),-\partial\overline{\partial}\log G(z,\overline{z})=-c_{1}\,\partial\overline{\partial}\log\varphi(z,\overline{z}),

where G=det(gij¯)G=\det(g_{i\overline{j}}) with gij¯=zizj¯logφg_{i\overline{j}}=\partial_{z_{i}}\partial_{\overline{z_{j}}}\log\varphi. (We remark that one can use the result of Klembeck [20] to find the value of c1c_{1}, but this value will also come out directly from our arguments below.) The equation (4.2) is equivalent to the statement that logGc1logφ\log G-c_{1}\log\varphi is pluriharmonic on 𝔹nZ\mathbb{B}^{n}-Z. Consequently, since Z={0}Z=\{0\} and n2n\geq 2 so that 𝔹nZ\mathbb{B}^{n}-Z is simply connected, there exists some holomorphic function hh on 𝔹nZ\mathbb{B}^{n}-Z such that

logG(z,z¯)c1logφ(z,z¯)=h(z)+h(z)¯.\log G(z,\overline{z})-c_{1}\log\varphi(z,\overline{z})=h(z)+\overline{h(z)}.

By Hartogs’s extension theorem, again since n2n\geq 2, we may assume hh is holomorphic on 𝔹n\mathbb{B}^{n}.

Lemma 4.1.

The function hh is constant. Furthermore, h+h¯=nln(n+1)h+\overline{h}=n\ln(n+1) and c1=1c_{1}=1.

Proof.

This lemma is in fact proved in [17] using ideas from [15]. For the reader’s convenience, we also sketch a proof here. We give a slightly different proof in order to avoid some tedious computations.

Set g=e2hg=e^{2h}. Then gg is holomorphic in 𝔹n\mathbb{B}^{n} and |g|=eh+h¯>0|g|=e^{h+\bar{h}}>0. We first study the boundary behavior of gg.

Claim. lim|z|1|g|=a\lim_{|z|\rightarrow 1}|g|=a for some constant 0a0\leq a\leq\infty.

Proof of the claim.

Note that

(4.3) |g|=eh+h¯=Gφc1.|g|=e^{h+\bar{h}}=\frac{G}{\varphi^{c_{1}}}.

We also note that

(4.4) n!πnφ(z,z¯)=n!πn(1(1|z|2)n+1+γΓ,γiddγ¯(1z,γz¯)n+1):=n!πn1(1|z|2)n+1+T(z,z¯),\displaystyle\begin{split}\frac{n!}{\pi^{n}}\varphi(z,\bar{z})=&\frac{n!}{\pi^{n}}\Bigl{(}\frac{1}{(1-|z|^{2})^{n+1}}+\sum_{\gamma\in\Gamma,\gamma\neq\mathrm{id}}\frac{\overline{d_{\gamma}}}{(1-\langle z,\overline{\gamma z}\rangle)^{n+1}}\Bigr{)}\\ :=&\frac{n!}{\pi^{n}}\frac{1}{(1-|z|^{2})^{n+1}}+T(z,\bar{z}),\end{split}

where T(z,z¯)T(z,\bar{z}) is real analytic in a neighborhood of 𝔹n¯\overline{\mathbb{B}^{n}} since Γ\Gamma is assumed to be fixed point free. In particular, the asymptotic singular part of n!πnφ\frac{n!}{\pi^{n}}\varphi as z𝔹nz\rightarrow\partial\mathbb{B}^{n} is the same as that of the Bergman kernel of 𝔹n\mathbb{B}^{n}. Let JJ be the Monge-Ampère type operator as defined in (4.7). With the preceding observation and the well known formula

G=det(zizj¯log(φ))=J(φ)φn+1,G=\det\Bigl{(}\partial_{z_{i}}\partial_{\overline{z_{j}}}\log\bigl{(}\varphi\bigr{)}\Bigr{)}=\frac{J(\varphi)}{\varphi^{n+1}},

a simple calculation yields that the most singular part of GG (as z𝔹nz\rightarrow\partial\mathbb{B}^{n}) is identical with that of the volume form of the Bergman metric on 𝔹n\mathbb{B}^{n}. More precisely,

(4.5) G=(n+1)n(1|z|2)n+1+G^,G=\frac{(n+1)^{n}}{(1-|z|^{2})^{n+1}}+\widehat{G},

where G^\widehat{G} is real analytic in 𝔹nZ\mathbb{B}^{n}-Z and satisfies (1|z|2)n+1G^0(1-|z|^{2})^{n+1}\widehat{G}\rightarrow 0 as |z|1|z|\rightarrow 1. Then by (4.3), (4.4) and (4.5), we see

(4.6) lim|z|1|g|=(n+1)nlim|z|1(1|z|2)(n+1)c1(1|z|2)n+1.\lim_{|z|\rightarrow 1}|g|=(n+1)^{n}\lim_{|z|\rightarrow 1}\frac{(1-|z|^{2})^{(n+1){c_{1}}}}{(1-|z|^{2})^{n+1}}.

Thus, depending on c1c_{1}, we have lim|z|1|g|=a\lim_{|z|\rightarrow 1}|g|=a for some 0a0\leq a\leq\infty. This proves the claim. ∎

But gg is a nowhere vanishing holomorphic function in 𝔹n\mathbb{B}^{n}. A standard maximum principle argument applied to gg and 1g,\frac{1}{g}, respectively, yields a0a\neq 0 and aa\neq\infty, respectively. Hence 0<a<0<a<\infty. But by (4.6), this happens if and only if c1=1c_{1}=1. And in this case by (4.6), a=(n+1)na=(n+1)^{n}. Applying the maximum principle again, we see |g|a=(n+1)n.|g|\equiv a=(n+1)^{n}. This implies gg and thus hh are constant functions, and h+h¯nln(n+1).h+\overline{h}\equiv n\ln(n+1). The proof of the lemma is finished. ∎

We define the Monge-Ampère type operator JJ as follows (note that it differs by a sign from the standard operator introduced by Fefferman [13]):

(4.7) J(φ):=det(φφzj¯φziφzizj¯),J(\varphi):=\det\begin{pmatrix}\varphi&\varphi_{\overline{z_{j}}}\\ \varphi_{z_{i}}&\varphi_{z_{i}\overline{z_{j}}}\end{pmatrix},

We use Lemma 4.1 and the well-known formula G=J(φ)/φn+1G=J(\varphi)/\varphi^{n+1} to further simplify (4.2) into

(4.8) J(φ)(z,z¯)=(n+1)nφn+2(z,z¯)J(\varphi)(z,\overline{z})=(n+1)^{n}\varphi^{n+2}(z,\overline{z})

for z𝔹nZ.z\in\mathbb{B}^{n}-Z. Since both sides of (4.8) are in fact real-analytic in 𝔹n,\mathbb{B}^{n}, we see (4.8) holds on 𝔹n\mathbb{B}^{n} by continuity. We pause here to observe that if Γ\Gamma is such that φ(0,0)0\varphi(0,0)\neq 0, then it follows that logφ\log\varphi extends as the potential of a Kähler-Einstein metric in the whole unit ball 𝔹n\mathbb{B}^{n}, which by uniqueness of the Cheng-Yau metric can be used to directly conclude that Γ={id}\Gamma=\{\mathrm{id}\}; this was previously observed in [17, Corollary 5.4]. Now, let us compute J(φ)J(\varphi). Clearly, we have

φzi=(n+1)γΓdγ¯(γz)i¯(1z,γz¯)n+2,φzj¯=(n+1)γΓdγ¯(zγ¯)j(1z,γz¯)n+2,\displaystyle\varphi_{z_{i}}=(n+1)\sum_{\gamma\in\Gamma}\frac{\overline{d_{\gamma}}\cdot\overline{(\gamma z)_{i}}}{(1-\langle z,\overline{\gamma z}\rangle)^{n+2}},\qquad\varphi_{\overline{z_{j}}}=(n+1)\sum_{\gamma\in\Gamma}\frac{\overline{d_{\gamma}}\cdot(z^{\intercal}\overline{\gamma})_{j}}{(1-\langle z,\overline{\gamma z}\rangle)^{n+2}},

where (γz)i(\gamma z)_{i} denotes the ii-th entry of the column vector γz\gamma z and similarly (zγ¯)j(z^{\intercal}\overline{\gamma})_{j} denotes the jj-th entry of the row vector zγ¯z^{\intercal}\overline{\gamma}. By differentiating both sides one more time, we obtain

φzizj¯=\displaystyle\varphi_{z_{i}\overline{z_{j}}}= (n+1)γΓdγ¯γij¯(1z,γz¯)+(n+2)(γz)i¯(zγ¯)j(1z,γz¯)n+3,\displaystyle(n+1)\sum_{\gamma\in\Gamma}\overline{d_{\gamma}}\cdot\frac{\overline{\gamma_{ij}}(1-\langle z,\overline{\gamma z}\rangle)+(n+2)\overline{(\gamma z)_{i}}(z^{\intercal}\overline{\gamma})_{j}}{(1-\langle z,\overline{\gamma z}\rangle)^{n+3}},

where γij\gamma_{ij} is the (i,j)(i,j) component of the matrix γ\gamma.

For each γΓ,0jn\gamma\in\Gamma,0\leq j\leq n, we define a column vector-valued function ξj(γ):𝔹nn+1\xi_{j}(\gamma):\mathbb{B}^{n}\rightarrow\mathbb{C}^{n+1} in the variables (z,z¯)(z,\overline{z}) as follows:

ξ0(γ)(z,z¯):=(1z,γz¯(n+1)γz¯)andξj(γ)(z,z¯):=(z(γ)j(γ)j(1z,γz¯)+(n+2)γz¯(z(γ)j)1z,γz¯) for 1jn,\displaystyle\xi_{0}(\gamma)(z,\overline{z}):=\begin{pmatrix}1-\langle z,\gamma\overline{z}\rangle\\ (n+1)\gamma\overline{z}\end{pmatrix}\quad\mbox{and}\quad\xi_{j}(\gamma)(z,\overline{z}):=\begin{pmatrix}z^{\intercal}(\gamma)_{j}\\ \frac{(\gamma)_{j}(1-\langle z,\gamma\overline{z}\rangle)+(n+2)\gamma\overline{z}(z^{\intercal}(\gamma)_{j})}{1-\langle z,\gamma\overline{z}\rangle}\end{pmatrix}\mbox{ for }1\leq j\leq n,

where (γ)j(\gamma)_{j} is the jj-th column vector of the matrix γ\gamma. Given any (n+1)(n+1) (possibly repeated) elements γ0,,γn\gamma_{0},\cdots,\gamma_{n} in Γ\Gamma, we define a matrix-valued function A(γ0,,γn):𝔹n(n+1)2A(\gamma_{0},\cdots,\gamma_{n}):\mathbb{B}^{n}\rightarrow\mathbb{C}^{(n+1)^{2}} as follows:

A(γ0,,γn)=(ξ0(γ0)ξn(γn)).A(\gamma_{0},\cdots,\gamma_{n})=\begin{pmatrix}\xi_{0}(\gamma_{0})&\cdots&\xi_{n}(\gamma_{n})\end{pmatrix}.

We emphasize that the map A(γ0,,γn)A(\gamma_{0},\cdots,\gamma_{n}) sends a point z𝔹nz\in\mathbb{B}^{n} to an (n+1)×(n+1)(n+1)\times(n+1) matrix. We then expand the determinant in (4.7) by multi-linearity with respect to columns. We obtain the following formula:

(4.9) J(φ)=γ0,,γnΓ(n+1)ndγ0¯dγn¯i=0n(1z,γiz¯)n+2det(A(γ0¯,,γn¯)).\displaystyle J(\varphi)=\sum_{\gamma_{0},\cdots,\gamma_{n}\in\Gamma}\frac{(n+1)^{n}\,\overline{d_{\gamma_{0}}}\cdots\overline{d_{\gamma_{n}}}}{\prod_{i=0}^{n}(1-\langle z,\overline{\gamma_{i}z}\rangle)^{n+2}}\,\det\bigl{(}A(\overline{\gamma_{0}},\cdots,\overline{\gamma_{n}})\bigr{)}.

4.2. Abelian group case

From now on, we will assume that Γ\Gamma is a finite, abelian, fixed point free subgroup of U(n)U(n).

Lemma 4.2.

If ΓU(n)\Gamma\subseteq U(n) is finite, abelian, and fixed point free, then it is cyclic.

Proof.

Since ΓU(n)\Gamma\subseteq U(n) is abelian, by basic Lie group theory, Γ\Gamma is contained in a conjugate of the maximal torus U(1)××U(1)U(1)\times\cdots\times U(1). Replacing Γ\Gamma by an appropriate conjugate of Γ\Gamma, we can assume ΓU(1)××U(1)\Gamma\subseteq U(1)\times\cdots\times U(1). Consider the group homomorphism π1:ΓU(1)\pi_{1}:\Gamma\rightarrow U(1) defined by

π1(γ):=γ11 for γ=diag(γ11,,γnn).\pi_{1}(\gamma):=\gamma_{11}\quad\mbox{ for }\gamma=\text{diag}(\gamma_{11},\cdots,\gamma_{nn}).

Since π1(Γ)U(1)\pi_{1}(\Gamma)\subseteq U(1) is finite, it must be cyclic. To verify that Γ\Gamma is also cyclic, it is sufficient to prove that Γ\Gamma is actually isomorphic to π1(Γ)\pi_{1}(\Gamma). We will conclude this by showing that π1\pi_{1} is injective. Thus, take γΓ\gamma\in\Gamma such that

π1(γ)=1.\pi_{1}(\gamma)=1.

It follows that the point (1,0,,0)(1,0,\cdots,0) is a fixed point of γ\gamma. Since Γ\Gamma is fixed point free, γ\gamma is the identity matrix. So π1\pi_{1} is injective and the proof is complete. ∎

By the proof of Lemma 4.2, we can assume ΓU(1)××U(1)\Gamma\subseteq U(1)\times\cdots\times U(1). As Γ\Gamma is actually cyclic, we can write

Γ={γ,γ2,,γm=id}\Gamma=\{\gamma,\gamma^{2},\cdots,\gamma^{m}=\mathrm{id}\}

for some generator

γ=(ε1εn).\gamma=\begin{pmatrix}\varepsilon_{1}&&\\ &\ddots&\\ &&\varepsilon_{n}\end{pmatrix}.

Here m2m\geq 2 by the nontriviality of Γ.\Gamma. Since Γ\Gamma is fixed point free, ε1,,εn\varepsilon_{1},\cdots,\varepsilon_{n} are primitive mm-th roots of unity. By setting ε:=ε1\varepsilon:=\varepsilon_{1}, for 1jn1\leq j\leq n we can write εj\varepsilon_{j} in the form of

εj=εtj,for some 1tjm1 with gcd(tj,m)=1.\varepsilon_{j}=\varepsilon^{t_{j}},\quad\mbox{for some }1\leq t_{j}\leq m-1\mbox{ with }\gcd(t_{j},m)=1.

Without loss of generality, we can assume

1=t1t2tnm1.1=t_{1}\leq t_{2}\leq\cdots\leq t_{n}\leq m-1.

For any γΓU(1)××U(1)\gamma\in\Gamma\subseteq U(1)\times\cdots\times U(1), note that γ1=γ¯=γ¯\gamma^{-1}=\overline{\gamma}^{\intercal}=\overline{\gamma}. Hence, we can replace all γj¯\overline{\gamma_{j}} by γj\gamma_{j} in the sum in J(φ)J(\varphi) and obtain

J(φ)=γ0,,γnΓ(n+1)ndγ0dγni=0n(1z,γiz¯)n+2det(A(γ0,,γn)).\displaystyle J(\varphi)=\sum_{\gamma_{0},\cdots,\gamma_{n}\in\Gamma}\frac{(n+1)^{n}\,d_{\gamma_{0}}\cdots d_{\gamma_{n}}}{\prod_{i=0}^{n}(1-\langle z,\gamma_{i}\overline{z}\rangle)^{n+2}}\,\det\bigl{(}A(\gamma_{0},\cdots,\gamma_{n})\bigr{)}.

Write γj=γkj\gamma_{j}=\gamma^{k_{j}} for some 0kjm10\leq k_{j}\leq m-1. Then dγj=detγj=εkj(i=1nti).d_{\gamma_{j}}=\det\gamma_{j}=\varepsilon^{k_{j}(\sum_{i=1}^{n}t_{i})}. Choose z=z:=(z1,0,,0)z=z^{*}:=(z_{1},0,\cdots,0)^{\intercal} with |z1|<1|z_{1}|<1 and set x=zz¯=z1z1¯<1x=z^{*}\cdot\overline{z^{*}}=z_{1}\overline{z_{1}}<1. Then at z,z^{*}, we have

det(A(γ0,,γn))=\displaystyle\det\bigl{(}A(\gamma_{0},\cdots,\gamma_{n})\bigr{)}= |1εk0xz1εk10(n+1)εk0w1¯εk1(1εk1x)+(n+2)ε2k1x1εk1x000(ε2k2εnkn)|\displaystyle\begin{vmatrix}1-\varepsilon^{k_{0}}x&z_{1}\varepsilon^{k_{1}}&0\\ (n+1)\varepsilon^{k_{0}}\overline{w_{1}}&\frac{\varepsilon^{k_{1}}(1-\varepsilon^{k_{1}}x)+(n+2)\varepsilon^{2k_{1}}x}{1-\varepsilon^{k_{1}}x}&0\\ 0&0&\begin{pmatrix}\varepsilon_{2}^{k_{2}}&&\\ &\ddots&\\ &&\varepsilon_{n}^{k_{n}}\end{pmatrix}\end{vmatrix}
=\displaystyle= εk1+j=2nk2t2(1(n+2)εk0x+(n+2)1εk0x1εk1xεk1x).\displaystyle\varepsilon^{k_{1}+\sum_{j=2}^{n}k_{2}t_{2}}\Bigl{(}1-(n+2)\varepsilon^{k_{0}}x+(n+2)\frac{1-\varepsilon^{k_{0}}x}{1-\varepsilon^{k_{1}}x}\,\varepsilon^{k_{1}}x\Bigr{)}.

In the following, we use the notation

  • T=(t1,,tn)T=(t_{1},\cdots,t_{n}), where t1=1t_{1}=1.

  • K=(k0,k1,,kn)K=(k_{0},k_{1},\cdots,k_{n}) and K=(k1,,kn)K^{\prime}=(k_{1},\cdots,k_{n}).

  • |T|=j=1ntj|T|=\sum_{j=1}^{n}t_{j} and |K|=j=1nkj|K^{\prime}|=\sum_{j=1}^{n}k_{j}.

Using these notations, we have, at z=zz=z^{*},

J(φ)(z,z¯)=(n+1)nk0,,kn=0m1ε|K||T|+KTi=0n(1εkix)n+2(1(n+2)εk0x+(n+2)1εk0x1εk1xεk1x).\displaystyle J(\varphi)(z^{*},\overline{z^{*}})=(n+1)^{n}\sum_{k_{0},\cdots,k_{n}=0}^{m-1}\frac{\varepsilon^{|K|\cdot|T|+K^{\prime}\cdot T}}{\prod_{i=0}^{n}(1-\varepsilon^{k_{i}}x)^{n+2}}\Bigl{(}1-(n+2)\varepsilon^{k_{0}}x+(n+2)\frac{1-\varepsilon^{k_{0}}x}{1-\varepsilon^{k_{1}}x}\,\varepsilon^{k_{1}}x\Bigr{)}.

If we set

I:=\displaystyle\text{I}:= k0,,kn=0m1ε|K||T|+KTi=0n(1εkix)n+2,\displaystyle\sum_{k_{0},\cdots,k_{n}=0}^{m-1}\frac{\varepsilon^{|K|\cdot|T|+K^{\prime}\cdot T}}{\prod_{i=0}^{n}(1-\varepsilon^{k_{i}}x)^{n+2}},
II:=\displaystyle\text{II}:= (n+2)k0,,kn=0m1ε|K||T|+KT+k0xi=0n(1εkix)n+2,\displaystyle-(n+2)\sum_{k_{0},\cdots,k_{n}=0}^{m-1}\frac{\varepsilon^{|K|\cdot|T|+K^{\prime}\cdot T+k_{0}}x}{\prod_{i=0}^{n}(1-\varepsilon^{k_{i}}x)^{n+2}},
III:=\displaystyle\text{III}:= (n+2)k0,,kn=0m1ε|K||T|+KT+k1xi=0n(1εkix)n+21εk0x1εk1x,\displaystyle(n+2)\sum_{k_{0},\cdots,k_{n}=0}^{m-1}\frac{\varepsilon^{|K|\cdot|T|+K^{\prime}\cdot T+k_{1}}x}{\prod_{i=0}^{n}(1-\varepsilon^{k_{i}}x)^{n+2}}\frac{1-\varepsilon^{k_{0}}x}{1-\varepsilon^{k_{1}}x},

then

(4.10) J(φ)(z,z¯)=(n+1)n(I+II+III).J(\varphi)(z^{*},\overline{z^{*}})=(n+1)^{n}\bigl{(}\text{I}+\text{II}+\text{III}\bigr{)}.

We pause to introduce the following definition and lemmas. Let ε\varepsilon be as above. Write 𝔻\mathbb{D} for the open unit disc in .\mathbb{C}.

Definition 4.3.

Let t,p+t\in\mathbb{Z},p\in\mathbb{Z}^{+}. Define ft,p:𝔻f_{t,p}:\mathbb{D}\rightarrow\mathbb{C} as

ft,p(x):=k=0m11εtk(εkx)p.f_{t,p}(x):=\sum_{k=0}^{m-1}\frac{1}{\varepsilon^{tk}(\varepsilon^{k}-x)^{p}}.
Lemma 4.4.

The following holds:

ft,p(x)=pft,p+1(x).f_{t,p}^{\prime}(x)=pf_{t,p+1}(x).

In general, for j2,j\geq 2, ft,p(j)(x)=p(p+1)(p+j1)ft,p+j(x).f_{t,p}^{(j)}(x)=p(p+1)\cdots(p+j-1)f_{t,p+j}(x).

Proof.

Note

ft,p(x)=k=0m1pεtk(εkx)p+1=pft,p+1(x).\displaystyle f_{t,p}^{\prime}(x)=\sum_{k=0}^{m-1}\frac{p}{\varepsilon^{tk}(\varepsilon^{k}-x)^{p+1}}=pf_{t,p+1}(x).

This proves the first statement. The latter assertion follows from the first statement and an inductive argument. ∎

Lemma 4.5.

The following hold:

  1. (1)
    ft,p(0)={0 if m(t+p),m if m(t+p).f_{t,p}(0)=\begin{cases}0&\mbox{ if }m\nmid(t+p),\\ m&\mbox{ if }m\mid(t+p).\end{cases}
  2. (2)

    For j1,j\geq 1,

    ft,p(j)(0)={0 if m(t+p+j),mi=0i=j1(p+i) if m(t+p+j).f_{t,p}^{(j)}(0)=\begin{cases}0&\mbox{ if }m\nmid(t+p+j),\\ m\prod_{i=0}^{i=j-1}(p+i)&\mbox{ if }m\mid(t+p+j).\end{cases}
Proof.

To prove part (1), we note that

ft,p(0)=k=0m1εk(t+p).f_{t,p}(0)=\sum_{k=0}^{m-1}\varepsilon^{-k(t+p)}.

Then the result in part (1) follows directly by the fact that ε\varepsilon is a primitive mm-th root of unity. Part (2) follows from part (1) and Lemma 4.4. ∎

Lemma 4.6.

The following holds:

k=0m1εtk(1εkx)p=ftp,p(x).\sum_{k=0}^{m-1}\frac{\varepsilon^{tk}}{(1-\varepsilon^{k}x)^{p}}=f_{t-p,p}(x).
Proof.
k=0m1εtk(1εkx)p=k=0m11εtk(1εkx)p=k=0m11ε(tp)k(εkx)p=ftp,p(x),\displaystyle\sum_{k=0}^{m-1}\frac{\varepsilon^{tk}}{(1-\varepsilon^{k}x)^{p}}=\sum_{k=0}^{m-1}\frac{1}{\varepsilon^{tk}(1-\varepsilon^{-k}x)^{p}}=\sum_{k=0}^{m-1}\frac{1}{\varepsilon^{(t-p)k}(\varepsilon^{k}-x)^{p}}=f_{t-p,p}(x),

where the first equality follows from the fact that ε\varepsilon is a primitive mm-th root of unity. ∎

Now, using the above notation and Lemma 4.6, we shall express J(φ)(z,z¯)J(\varphi)(z^{*},\overline{z^{*}}) in terms of ft,pf_{t,p}.

I=\displaystyle\quad\text{I}= k0,,kn=0m1ε|K||T|+KTi=0n(1εkix)n+2\displaystyle\sum_{k_{0},\cdots,k_{n}=0}^{m-1}\frac{\varepsilon^{|K|\cdot|T|+K^{\prime}\cdot T}}{\prod_{i=0}^{n}(1-\varepsilon^{k_{i}}x)^{n+2}}
=\displaystyle= k0=0m1εk0|T|(1εk0x)n+2k1=0m1εk1(|T|+t1)(1εk1x)n+2kn=0m1εkn(|T|+tn)(1εknx)n+2\displaystyle\sum_{k_{0}=0}^{m-1}\frac{\varepsilon^{k_{0}|T|}}{(1-\varepsilon^{k_{0}}x)^{n+2}}\,\sum_{k_{1}=0}^{m-1}\frac{\varepsilon^{k_{1}(|T|+t_{1})}}{(1-\varepsilon^{k_{1}}x)^{n+2}}\cdots\sum_{k_{n}=0}^{m-1}\frac{\varepsilon^{k_{n}(|T|+t_{n})}}{(1-\varepsilon^{k_{n}}x)^{n+2}}
=\displaystyle= f|T|(n+2),n+2(x)f|T|+t1(n+2),n+2(x)f|T|+tn(n+2),n+2(x).\displaystyle f_{|T|-(n+2),n+2}(x)\,f_{|T|+t_{1}-(n+2),n+2}(x)\cdots f_{|T|+t_{n}-(n+2),n+2}(x).
II=\displaystyle\quad\text{II}= (n+2)xk0,,kn=0m1ε|K||T|+KT+k0i=0n(1εkix)n+2\displaystyle-(n+2)x\sum_{k_{0},\cdots,k_{n}=0}^{m-1}\frac{\varepsilon^{|K|\cdot|T|+K^{\prime}\cdot T+k_{0}}}{\prod_{i=0}^{n}(1-\varepsilon^{k_{i}}x)^{n+2}}
=\displaystyle= (n+2)xk0=0m1εk0(|T|+1)(1εk0x)n+2k1=0m1εk1(|T|+t1)(1εk1x)n+2kn=0m1εkn(|T|+tn)(1εknx)n+2\displaystyle-(n+2)x\sum_{k_{0}=0}^{m-1}\frac{\varepsilon^{k_{0}(|T|+1)}}{(1-\varepsilon^{k_{0}}x)^{n+2}}\,\sum_{k_{1}=0}^{m-1}\frac{\varepsilon^{k_{1}(|T|+t_{1})}}{(1-\varepsilon^{k_{1}}x)^{n+2}}\cdots\sum_{k_{n}=0}^{m-1}\frac{\varepsilon^{k_{n}(|T|+t_{n})}}{(1-\varepsilon^{k_{n}}x)^{n+2}}
=\displaystyle= (n+2)xf|T|(n+1),n+2(x)f|T|+t1(n+2),n+2(x)f|T|+tn(n+2),n+2(x).\displaystyle-(n+2)x\,f_{|T|-(n+1),n+2}(x)\,f_{|T|+t_{1}-(n+2),n+2}(x)\cdots f_{|T|+t_{n}-(n+2),n+2}(x).
III=\displaystyle\quad\text{III}= (n+2)xk0,,kn=0m1ε|K||T|+KT+k1i=0n(1εkix)n+21εk0x1εk1x\displaystyle(n+2)x\sum_{k_{0},\cdots,k_{n}=0}^{m-1}\frac{\varepsilon^{|K|\cdot|T|+K^{\prime}\cdot T+k_{1}}}{\prod_{i=0}^{n}(1-\varepsilon^{k_{i}}x)^{n+2}}\frac{1-\varepsilon^{k_{0}}x}{1-\varepsilon^{k_{1}}x}
=\displaystyle= (n+2)xk0=0m1εk0|T|(1εk0x)n+1k1=0m1εk1(|T|+t1+1)(1εk1x)n+3k2=0m1εkn(|T|+t2)(1εk2x)n+2kn=0m1εkn(|T|+tn)(1εknx)n+2\displaystyle(n+2)x\sum_{k_{0}=0}^{m-1}\frac{\varepsilon^{k_{0}|T|}}{(1-\varepsilon^{k_{0}}x)^{n+1}}\,\sum_{k_{1}=0}^{m-1}\frac{\varepsilon^{k_{1}(|T|+t_{1}+1)}}{(1-\varepsilon^{k_{1}}x)^{n+3}}\,\sum_{k_{2}=0}^{m-1}\frac{\varepsilon^{k_{n}(|T|+t_{2})}}{(1-\varepsilon^{k_{2}}x)^{n+2}}\cdots\sum_{k_{n}=0}^{m-1}\frac{\varepsilon^{k_{n}(|T|+t_{n})}}{(1-\varepsilon^{k_{n}}x)^{n+2}}
=\displaystyle= (n+2)xf|T|(n+1),n+1(x)f|T|+t1(n+2),n+3(x)f|T|+t2(n+2),n+2(x)f|T|+tn(n+2),n+2(x).\displaystyle(n+2)x\,f_{|T|-(n+1),n+1}(x)\,f_{|T|+t_{1}-(n+2),n+3}(x)\,f_{|T|+t_{2}-(n+2),n+2}(x)\cdots f_{|T|+t_{n}-(n+2),n+2}(x).

Set

(4.11) P:=f|T|(n+2),n+2f|T|(n+1),n+2(n+2)x(f|T|(n+1),n+22f|T|(n+1),n+1f|T|(n+1),n+3),Q:=f|T|+t2(n+2),n+2f|T|+tn(n+2),n+2.\displaystyle\begin{split}P:=&f_{|T|-(n+2),n+2}f_{|T|-(n+1),n+2}-(n+2)x\bigl{(}f_{|T|-(n+1),n+2}^{2}-f_{|T|-(n+1),n+1}f_{|T|-(n+1),n+3}\bigr{)},\\ Q:=&f_{|T|+t_{2}-(n+2),n+2}\cdots f_{|T|+t_{n}-(n+2),n+2}.\end{split}

By (4.10) and the fact t1=1t_{1}=1, we conclude that J(φ)(z,z¯)J(\varphi)(z^{*},\overline{z^{*}}) can be written as

(4.12) J(φ)(z,z¯)=(n+1)nP(x)Q(x).\displaystyle J(\varphi)(z^{*},\overline{z^{*}})=(n+1)^{n}P(x)\,Q(x).

Moreover, at z=z=(z1,0,,0)z=z^{*}=(z_{1},0,\cdots,0)^{\intercal} we can simplify φ\varphi as

φ(z,z¯)=γΓdγ¯(1z,γz¯)n+1=γΓdγ(1z,γz¯)n+1=k=0m1εk|T|(1εkx)n+1=f|T|(n+1),n+1(x).\displaystyle\varphi(z^{*},\overline{z^{*}})=\sum_{\gamma\in\Gamma}\frac{\overline{d_{\gamma}}}{(1-\langle z^{*},\overline{\gamma z^{*}}\rangle)^{n+1}}=\sum_{\gamma\in\Gamma}\frac{d_{\gamma}}{(1-\langle z^{*},\gamma\overline{z^{*}}\rangle)^{n+1}}=\sum_{k=0}^{m-1}\frac{\varepsilon^{k\,|T|}}{(1-\varepsilon^{k}x)^{n+1}}=f_{|T|-(n+1),n+1}(x).

The second equality here is due to the fact that ΓU(1)××U(1)U(n)\Gamma\subseteq U(1)\times\cdots\times U(1)\subseteq U(n), as also explained above. By the above expression for φ\varphi and (4.12), we conclude that at z=z,z=z^{*}, the Kähler-Einstein equation (4.8) is reduced to, for x[0,1),x\in[0,1)\subseteq\mathbb{R},

(4.13) f|T|(n+1),n+1n+2(x)=P(x)Q(x),f_{|T|-(n+1),n+1}^{n+2}(x)=P(x)Q(x),

where P,QP,Q are defined in (4.11). Since both sides of (4.13) are holomorphic in 𝔻,\mathbb{D}, we conclude that (4.13) in fact holds for all x𝔻.x\in\mathbb{D}.

4.3. Reduction to combinatorial inequalities

We shall take the Taylor expansion of both sides in (4.13) at x=0x=0. By comparing the Taylor coefficients, we shall prove that (4.13) cannot hold if m=|Γ|2m=|\Gamma|\geq 2 and n2n\geq 2, which will establish Theorem 1.4. We shall proceed by dividing the proof into several cases.

Case I. m|T|m\mid|T|.

As m|T|m\mid|T|, m|T|+1m\nmid|T|+1. Lemma 4.5 yields that

f|T|(n+1),n+1(0)=m,f|T|(n+1),n+2(0)=0.f_{|T|-(n+1),n+1}(0)=m,\qquad f_{|T|-(n+1),n+2}(0)=0.

Therefore, at x=0x=0

f|T|(n+1),n+1n+2(0)=mn+20=P(0)Q(0),f_{|T|-(n+1),n+1}^{n+2}(0)=m^{n+2}\neq 0=P(0)\cdot Q(0),

which implies that the Kähler-Einstein equation (4.13) does not hold.

Case II. m|T|m\nmid|T| and m|T|+1m\mid|T|+1.

In this case, we have

m|T|+2,,m|T|+m,m|T|+m+1.m\nmid|T|+2,\cdots,m\nmid|T|+m,\,m\mid|T|+m+1.

We take the Taylor expansion of f|T|(n+2),n+2f_{|T|-(n+2),n+2} at x=0x=0.

(4.14) f|T|(n+2),n+2(x)=j=0m+1f|T|(n+2),n+2(j)(0)j!xj+O(m+2)=(n+21)mx+(n+m+2m+1)mxm+1+O(m+2).\displaystyle\begin{split}f_{|T|-(n+2),n+2}(x)=&\sum_{j=0}^{m+1}\frac{f_{|T|-(n+2),n+2}^{(j)}(0)}{j!}x^{j}+O({m+2})\\ =&\binom{n+2}{1}mx+\binom{n+m+2}{m+1}mx^{m+1}+O({m+2}).\end{split}

Here for a holomorphic function hh in a neighborhood UU\subseteq\mathbb{C} of 0, we say hh is O(j),j1,O(j),j\geq 1, if h(i)(0)=0h^{(i)}(0)=0 for all 0i<j.0\leq i<j. The last equality follows from Lemma 4.5.

Similarly, we also have

f|T|(n+1),n+2(x)=\displaystyle f_{|T|-(n+1),n+2}(x)= m+(m+n+1m)mxm+O(m+1),\displaystyle m+\binom{m+n+1}{m}mx^{m}+O({m+1}),
f|T|(n+1),n+1(x)=\displaystyle f_{|T|-(n+1),n+1}(x)= (n+11)mx+(m+n+1m+1)mxm+1+O(m+2),\displaystyle\binom{n+1}{1}mx+\binom{m+n+1}{m+1}mx^{m+1}+O({m+2}),
f|T|(n+1),n+3(x)=\displaystyle f_{|T|-(n+1),n+3}(x)= (m+n+1m1)mxm1+O(m).\displaystyle\binom{m+n+1}{m-1}mx^{m-1}+O({m}).

By (4.11), it follows that

P=\displaystyle P= ((n+21)mx+(n+m+2m+1)mxm+1)(m+(m+n+1m)mxm)\displaystyle\left(\binom{n+2}{1}mx+\binom{n+m+2}{m+1}mx^{m+1}\right)\left(m+\binom{m+n+1}{m}mx^{m}\right)
(n+2)x(m+(m+n+1m)mxm)2\displaystyle-(n+2)x\left(m+\binom{m+n+1}{m}mx^{m}\right)^{2}
+(n+2)x((n+11)mx+(m+n+1m+1)mxm+1)(m+n+1m1)mxm1+O(m+2)\displaystyle+(n+2)x\left(\binom{n+1}{1}mx+\binom{m+n+1}{m+1}mx^{m+1}\right)\binom{m+n+1}{m-1}mx^{m-1}+O({m+2})
=\displaystyle= m2(n+m+1m)xm+1(n2+m+n+2m+1+(n+1)m)+O(m+2)\displaystyle m^{2}\binom{n+m+1}{m}x^{m+1}\left(-n-2+\frac{m+n+2}{m+1}+(n+1)m\right)+O({m+2})
=\displaystyle= m4(n+1)m+1(n+m+1m)xm+1+O(m+2).\displaystyle\frac{m^{4}(n+1)}{m+1}\binom{n+m+1}{m}x^{m+1}+O({m+2}).

Recall that

Q=f|T|+t2(n+2),n+2f|T|+tn(n+2),n+2,Q=f_{|T|+t_{2}-(n+2),n+2}\cdots f_{|T|+t_{n}-(n+2),n+2},

where 1=t1t2tnm11=t_{1}\leq t_{2}\leq\cdots\leq t_{n}\leq m-1. Let 1an1\leq a\leq n be such that

1=t1==ta<ta+1tn.1=t_{1}=\cdots=t_{a}<t_{a+1}\leq\cdots\leq t_{n}.

When a=n,a=n, the above means that all tjt_{j}^{\prime}s equal 11. Now for 1ja1\leq j\leq a, we have

f|T|+tj(n+2),n+2(x)=f|T|(n+1),n+2(x)=m+O(1).f_{|T|+t_{j}-(n+2),n+2}(x)=f_{|T|-(n+1),n+2}(x)=m+O(1).

And for a+1jna+1\leq j\leq n, |T|+1<|T|+tj<|T|+m+1|T|+1<|T|+t_{j}<|T|+m+1. We get, by a similar computation as in (4.14),

f|T|+tj(n+2),n+2(x)=(n+m+2tjm+1tj)mxm+1tj+O(m+2tj).f_{|T|+t_{j}-(n+2),n+2}(x)=\binom{n+m+2-t_{j}}{m+1-t_{j}}mx^{m+1-t_{j}}+O({m+2-t_{j}}).

Thus,

Q=mn1(m+n+2ta+1m+1ta+1)(m+n+2tnm+1tn)x(m+1)(na)(ta+1++tn)+h.o.t,\displaystyle Q=m^{n-1}\binom{m+n+2-t_{a+1}}{m+1-t_{a+1}}\cdots\binom{m+n+2-t_{n}}{m+1-t_{n}}x^{(m+1)(n-a)-(t_{a+1}+\cdots+t_{n})}+\text{h.o.t},

where h.o.t denotes the higher order term. Combining this with the Taylor expansion of PP, the lowest order term in PQPQ at x=0x=0 is

(4.15) mn+3(n+1)m+1(n+m+1m)(m+n+2ta+1m+1ta+1)(m+n+2tnm+1tn)x(m+1)(na+1)j=a+1ntj.\frac{m^{n+3}(n+1)}{m+1}\binom{n+m+1}{m}\binom{m+n+2-t_{a+1}}{m+1-t_{a+1}}\cdots\binom{m+n+2-t_{n}}{m+1-t_{n}}x^{(m+1)(n-a+1)-\sum_{j=a+1}^{n}t_{j}}.

When a=n,j=a+1ntja=n,\sum_{j=a+1}^{n}t_{j} is a null sum and equals zero. Furthermore, we have

(4.16) f|T|(n+1),n+1n+2=(n+1)n+2mn+2xn+2+h.o.t.f^{n+2}_{|T|-(n+1),n+1}=(n+1)^{n+2}m^{n+2}x^{n+2}+\text{h.o.t}\,.

Suppose that the Kähler-Einstein equation (4.13) holds. Then f|T|(n+1),n+1n+2f^{n+2}_{|T|-(n+1),n+1} and PQPQ must share the same Taylor expansion at x=0x=0. In particular, their lowest order terms, where the former is found in (4.16) and the latter in (4.15), must have the same degree, that is, n+2=(m+1)(na)j=a+1ntjn+2=(m+1)(n-a)-\sum_{j=a+1}^{n}t_{j}. In this case, however, the coefficients of the lowest order terms do not match by the following lemma.

Lemma 4.7.

Suppose m,n2m,n\geq 2, 1an1\leq a\leq n and 1=t1==ta<ta+1tnm11=t_{1}=\cdots=t_{a}<t_{a+1}\leq\cdots\leq t_{n}\leq m-1. If n+2=(m+1)(na+1)j=a+1ntjn+2=(m+1)(n-a+1)-\sum_{j=a+1}^{n}t_{j}, then

(n+1)n+1(m+1)>m(n+m+1m)(m+n+2ta+1m+1ta+1)(m+n+2tnm+1tn).(n+1)^{n+1}(m+1)>m\binom{n+m+1}{m}\binom{m+n+2-t_{a+1}}{m+1-t_{a+1}}\cdots\binom{m+n+2-t_{n}}{m+1-t_{n}}.

In the case a=n,a=n, i.e., all tjt_{j}^{\prime}s equal 11, the above is reduced to the following: If m=n+1,m=n+1, then

(n+1)n+1(m+1)>m(n+m+1m).(n+1)^{n+1}(m+1)>m\binom{n+m+1}{m}.

This is a contradiction and we thus conclude the Kähler-Einstein equation (4.13) does not hold. The proof of Lemma 4.7 is left to Section 5.

Case III. m|T|,m|T|+1,,m|T|+k1m\nmid|T|,m\nmid|T|+1,\cdots,m\nmid|T|+k-1 and m|T|+km\mid|T|+k for some 2k<m2\leq k<m.

We follow the same procedure as in Case II. Similarly as in (4.14), by using Lemma 4.5, we have

f|T|(n+2),n+2(x)=\displaystyle f_{|T|-(n+2),n+2}(x)= j=0k+mf|T|(n+2),n+2(j)(0)j!xj+O(xk+m+1)\displaystyle\sum_{j=0}^{k+m}\frac{f_{|T|-(n+2),n+2}^{(j)}(0)}{j!}x^{j}+O(x^{k+m+1})
=\displaystyle= (n+k+1k)mxk+(n+k+m+1k+m)mxk+m+O(k+m+1),\displaystyle\binom{n+k+1}{k}mx^{k}+\binom{n+k+m+1}{k+m}mx^{k+m}+O({k+m+1}),

and

f|T|(n+1),n+2(x)=\displaystyle f_{|T|-(n+1),n+2}(x)= (n+kk1)mxk1+(k+m+nk+m1)mxk+m1+O(k+m),\displaystyle\binom{n+k}{k-1}mx^{k-1}+\binom{k+m+n}{k+m-1}mx^{k+m-1}+O({k+m}),
f|T|(n+1),n+1(x)=\displaystyle f_{|T|-(n+1),n+1}(x)= (n+kk)mxk+(n+k+mk+m)mxk+m+O(k+m+1),\displaystyle\binom{n+k}{k}mx^{k}+\binom{n+k+m}{k+m}mx^{k+m}+O({k+m+1}),
f|T|(n+1),n+3(x)=\displaystyle f_{|T|-(n+1),n+3}(x)= (n+kk2)mxk2+(n+k+mk+m2)mxk+m2+O(k+m1).\displaystyle\binom{n+k}{k-2}mx^{k-2}+\binom{n+k+m}{k+m-2}mx^{k+m-2}+O({k+m-1}).

By (4.11), it follows that

(4.17) P=(n+kk1)(n+k+mn)m4kx2k+m1+h.o.t.\displaystyle P=\binom{n+k}{k-1}\binom{n+k+m}{n}\frac{m^{4}}{k}x^{2k+m-1}+\text{h.o.t}.

Now we turn to the computation of the leading term in QQ. Recall that 1=t1t2tnm11=t_{1}\leq t_{2}\leq\cdots\leq t_{n}\leq m-1. We shall divide the computation into two subcases: k<tnk<t_{n} and ktnk\geq t_{n}.

Subcase III (a). k<tnk<t_{n}.

Since k2k\geq 2, there exists some 1an11\leq a\leq n-1 such that

1=t1tak<ta+1tnm1.1=t_{1}\leq\cdots\leq t_{a}\leq k<t_{a+1}\leq\cdots\leq t_{n}\leq m-1.

For 1ja1\leq j\leq a, as |T|+1|T|+tj|T|+k|T|+1\leq|T|+t_{j}\leq|T|+k, by the Taylor expansion and Lemma 4.5, we have

f|T|+tj(n+2),n+2(x)=(n+1+ktjktj)mxktj+O(ktj+1).f_{|T|+t_{j}-(n+2),n+2}(x)=\binom{n+1+k-t_{j}}{k-t_{j}}mx^{k-t_{j}}+O({k-t_{j}+1}).

For a+1jna+1\leq j\leq n, it follows that |T|+k<|T|+tj<|T|+k+m|T|+k<|T|+t_{j}<|T|+k+m. Thus, by the Taylor expansion and Lemma 4.5,

f|T|+tj(n+2),n+2(x)=(n+1+m+ktjm+ktj)mxm+ktj+O(m+ktj+1).f_{|T|+t_{j}-(n+2),n+2}(x)=\binom{n+1+m+k-t_{j}}{m+k-t_{j}}mx^{m+k-t_{j}}+O({m+k-t_{j}+1}).

By (4.11), we obtain

Q=j=2a(n+1+ktjktj)mxktjj=a+1n(n+1+m+ktjm+ktj)mxm+ktj+h.o.t.Q=\prod_{j=2}^{a}\binom{n+1+k-t_{j}}{k-t_{j}}mx^{k-t_{j}}\cdot\prod_{j=a+1}^{n}\binom{n+1+m+k-t_{j}}{m+k-t_{j}}mx^{m+k-t_{j}}+\text{h.o.t}.

Therefore, (4.17) and the above equality yield the leading term in the Taylor expansion of PQPQ at x=0x=0 as

mn+3k(n+kk1)(n+k+mn)j=2a(n+1+ktjktj)j=a+1n(n+1+m+ktjm+ktj)xs,\displaystyle\frac{m^{n+3}}{k}\binom{n+k}{k-1}\binom{n+k+m}{n}\prod_{j=2}^{a}\binom{n+1+k-t_{j}}{k-t_{j}}\cdot\prod_{j=a+1}^{n}\binom{n+1+m+k-t_{j}}{m+k-t_{j}}\cdot x^{s},

where

(4.18) s=(n+1)k+m1j=2atj+j=a+1n(mtj).s=(n+1)k+m-1-\sum_{j=2}^{a}t_{j}+\sum_{j=a+1}^{n}(m-t_{j}).

On the other hand, the left hand side of (4.13) satisfies

f|T|(n+1),n+1n+2=(n+kk)n+2mn+2xk(n+2)+h.o.t.f_{|T|-(n+1),n+1}^{n+2}=\binom{n+k}{k}^{n+2}m^{n+2}x^{k(n+2)}+\text{h.o.t}.

Suppose that the Kähler-Einstein equation (4.13) holds. Then f|T|(n+1),n+1n+2f^{n+2}_{|T|-(n+1),n+1} and PQPQ must share the same Taylor expansion at x=0x=0. In particular, their lowest order terms have the same degree, that is, s=k(n+2)s=k(n+2), which in view of (4.18) implies that

(4.19) k=mj=1atj+j=a+1n(mtj).k=m-\sum_{j=1}^{a}t_{j}+\sum_{j=a+1}^{n}(m-t_{j}).

In this case, the coefficients of the lowest terms are, however, unequal by the following lemma.

Lemma 4.8.

Suppose 1an11\leq a\leq n-1, 2km12\leq k\leq m-1 and 1=t1tak<ta+1tnm11=t_{1}\leq\cdots\leq t_{a}\leq k<t_{a+1}\leq\cdots\leq t_{n}\leq m-1. If (4.19) holds, then

k(n+kk)n+2>m(n+k+mn)j=1a(n+1+ktjktj)j=a+1n(n+1+m+ktjm+ktj).\displaystyle k\,\binom{n+k}{k}^{n+2}>m\,\binom{n+k+m}{n}\prod_{j=1}^{a}\binom{n+1+k-t_{j}}{k-t_{j}}\cdot\prod_{j=a+1}^{n}\binom{n+1+m+k-t_{j}}{m+k-t_{j}}.

This is a contradiction and we thus conclude that (4.13) does not hold. We will leave the proof of Lemma 4.8 to Section 5.

Subcase III (b). ktnk\geq t_{n}.

In this case, |T|+1|T|+tj|T|+k|T|+1\leq|T|+t_{j}\leq|T|+k for all 1jn1\leq j\leq n. Thus we have, by the Taylor expansion,

Q=j=2n(n+1+ktjktj)mxktj+h.o.t.Q=\prod_{j=2}^{n}\binom{n+1+k-t_{j}}{k-t_{j}}mx^{k-t_{j}}+\text{h.o.t}.

Note that all other terms in (4.13) have the same Taylor expansions as in the case III (b). As before, in order to disprove (4.13), it is sufficient to verify the following lemma, whose proof is also delayed to Section 5.

Lemma 4.9.

Let 2km12\leq k\leq m-1 and n2.n\geq 2. Let 1=t1tnk1=t_{1}\leq\cdots\leq t_{n}\leq k. If

k=mj=1ntj,k=m-\sum_{j=1}^{n}t_{j},

then

k(n+kk)n+2>m(n+k+mn)j=1n(n+1+ktjktj).\displaystyle k\,\binom{n+k}{k}^{n+2}>m\,\binom{n+k+m}{n}\prod_{j=1}^{n}\binom{n+1+k-t_{j}}{k-t_{j}}.

5. Proof of the Combinatorial lemmas

In this section, we shall prove Lemmas 4.7, 4.8, and 4.9.

5.1. Proof of Lemma 4.7

For the reader’s convenience, we restate Lemma 4.7 here.

Lemma 5.1.

Suppose m,n2m,n\geq 2, 1an1\leq a\leq n and 1=t1==ta<ta+1tnm11=t_{1}=\cdots=t_{a}<t_{a+1}\leq\cdots\leq t_{n}\leq m-1. If n+2=(m+1)(na+1)j=a+1ntjn+2=(m+1)(n-a+1)-\sum_{j=a+1}^{n}t_{j}, then

(5.1) (n+1)n+1(m+1)>m(n+m+1m)(m+n+2ta+1m+1ta+1)(m+n+2tnm+1tn).(n+1)^{n+1}(m+1)>m\binom{n+m+1}{m}\binom{m+n+2-t_{a+1}}{m+1-t_{a+1}}\cdots\binom{m+n+2-t_{n}}{m+1-t_{n}}.
Proof.

We divide the proof into two cases.

Case I. n=2n=2.

In this case, by the assumption of Lemma 4.7, we have 4=(m+1)(3a)j=a+1ntj4=(m+1)(3-a)-\sum_{j=a+1}^{n}t_{j} and 1a21\leq a\leq 2.

Suppose a=1a=1. Then 2(m+1)=4+t2m+32(m+1)=4+t_{2}\leq m+3, which yields m1m\leq 1. This contradicts the assumption m2m\geq 2. Thus we have a=2a=2. It follows that t2=1t_{2}=1 and m=3m=3. A straightforward computation shows

LHS of (5.1)=108>60=RHS of (5.1).\displaystyle\text{LHS of \eqref{lemma combinatorial 1 eq}}=108>60=\text{RHS of \eqref{lemma combinatorial 1 eq}}.

So this case is verified.

Case II. n3n\geq 3.

We first prove the following elementary combinatorial inequality, which will be used in the proof.

Lemma 5.2.

For any integers n,k3n,k\geq 3, we have

(5.2) (n+kk1)<(n+1)k1.\binom{n+k}{k-1}<(n+1)^{k-1}.
Proof.
(n+kk1)(n+1)(k1)=t=1k1(n+1+t)t(n+1)=(n+2)(n+3)2(n+1)2t=3k1(n+1+t)t(n+1).\displaystyle\binom{n+k}{k-1}\cdot(n+1)^{-(k-1)}=\prod_{t=1}^{k-1}\frac{(n+1+t)}{t\cdot(n+1)}=\frac{(n+2)(n+3)}{2(n+1)^{2}}\cdot\prod_{t=3}^{k-1}\frac{(n+1+t)}{t\cdot(n+1)}.

Since n3n\geq 3,

2(n+1)2(n+2)(n+3)=n2n42>0,\displaystyle 2(n+1)^{2}-(n+2)(n+3)=n^{2}-n-4\geq 2>0,

which implies that

(n+2)(n+3)2(n+1)2<1\frac{(n+2)(n+3)}{2(n+1)^{2}}<1

When t3t\geq 3,

t(n+1)(n+1+t)=n(t1)12n1>0,\displaystyle t(n+1)-(n+1+t)=n(t-1)-1\geq 2n-1>0,

which implies that

(n+1+t)t(n+1)<1.\frac{(n+1+t)}{t\cdot(n+1)}<1.

The result therefore follows. ∎

Recall that 1tjm11\leq t_{j}\leq m-1 for any 1jn1\leq j\leq n. By applying (5.2) with k=m+2tjk=m+2-t_{j}, we get

(m+n+2tjm+1tj)<(n+1)(m+1tj).\binom{m+n+2-t_{j}}{m+1-t_{j}}<(n+1)^{(m+1-t_{j})}.

Thus,

RHS of (5.1)<m(n+1)m+j=a+1n(m+1tj)=m(n+1)(n+1)<LHS of (5.1).\displaystyle\text{RHS of \eqref{lemma combinatorial 1 eq}}<m(n+1)^{m+\sum_{j=a+1}^{n}(m+1-t_{j})}=m(n+1)^{(n+1)}<\text{LHS of \eqref{lemma combinatorial 1 eq}}.

So the proof is complete also in Case II. ∎

5.2. Proof of Lemma 4.8 and Lemma 4.9

We will prove a slightly more general result.

Lemma 5.3.

Let k,m,nk,m,n be integers such that 1km11\leq k\leq m-1 and n2n\geq 2. Let λ=(λ1,λn)n\lambda=(\lambda_{1},\cdots\lambda_{n})\in\mathbb{Z}^{n} satisfy λjk\lambda_{j}\leq k for each 1jn1\leq j\leq n. If

mk=j=1nλj,m-k=\sum_{j=1}^{n}\lambda_{j},

then

(5.3) k(n+kk)n+2>m(n+k+mn)j=1n(n+1+kλjkλj).\displaystyle k\,\binom{n+k}{k}^{n+2}>m\,\binom{n+k+m}{n}\prod_{j=1}^{n}\binom{n+1+k-\lambda_{j}}{k-\lambda_{j}}.

Clearly, Lemma 4.8 follows from 5.3 by taking (λ1,,λn)=(t1,,ta,ta+1m,,tnm)(\lambda_{1},\cdots,\lambda_{n})=(t_{1},\cdots,t_{a},t_{a+1}-m,\cdots,t_{n}-m). Lemma 4.9 follows from 5.3 by taking (λ1,,λn)=(t1,,tn)(\lambda_{1},\cdots,\lambda_{n})=(t_{1},\cdots,t_{n}).

Proof of Lemma 5.3.

We divide the proof into several steps.

Step 1. We show that it is actually sufficient to prove (5.3) for 0λjk0\leq\lambda_{j}\leq k for all 1jn1\leq j\leq n.

We begin this step with the following elementary combinatorial lemma.

Lemma 5.4.

Let nn\in\mathbb{N} and let s,ts,t be integers such that s+1<tks+1<t\leq k. Then we have

(5.4) (n+1+ksks)(n+1+ktkt)<(n+1+k(s+1)k(s+1))(n+1+k(t1)k(t1)).\binom{n+1+k-s}{k-s}\binom{n+1+k-t}{k-t}<\binom{n+1+k-(s+1)}{k-(s+1)}\binom{n+1+k-(t-1)}{k-(t-1)}.
Proof.

A straightforward computation gives

LHS of (5.4)RHS of (5.4)=n+1+ksksk+1tn+2+kt.\displaystyle\frac{\text{LHS of }\eqref{lemma rearrangement eq}}{\text{RHS of }\eqref{lemma rearrangement eq}}=\frac{n+1+k-s}{k-s}\cdot\frac{k+1-t}{n+2+k-t}.

Note that

(n+1+ks)(k+1t)(ks)(n+2+kt)=(n+1)(s+1t)<0.\displaystyle(n+1+k-s)(k+1-t)-(k-s)(n+2+k-t)=(n+1)(s+1-t)<0.

The result thus follows immediately. ∎

Now we fix m,n,km,n,k and apply Lemma 5.4 to the product j=1n(n+1+kλjkλj)\prod_{j=1}^{n}\binom{n+1+k-\lambda_{j}}{k-\lambda_{j}} in the right hand side of (5.3). Suppose λj1<0\lambda_{j_{1}}<0 for some 1j1n1\leq j_{1}\leq n. Since j=1nλj=mk1\sum_{j=1}^{n}\lambda_{j}=m-k\geq 1, there is some 1j2n1\leq j_{2}\leq n such that λj2>0\lambda_{j_{2}}>0. We change (n+1+kλj1kλj1)(n+1+kλj2kλj2)\binom{n+1+k-\lambda_{j_{1}}}{k-\lambda_{j_{1}}}\binom{n+1+k-\lambda_{j_{2}}}{k-\lambda_{j_{2}}} to (n+1+k(λj1+1)k(λj1+1))(n+1+k(λj21)k(λj21))\binom{n+1+k-(\lambda_{j_{1}}+1)}{k-(\lambda_{j_{1}}+1)}\binom{n+1+k-(\lambda_{j_{2}}-1)}{k-(\lambda_{j_{2}}-1)}, i.e., use λj1+1\lambda_{j_{1}}+1 as the new λj1\lambda_{j_{1}} and use λj21\lambda_{j_{2}}-1 as the new λj2\lambda_{j_{2}}. Then the sum j=1nλj\sum_{j=1}^{n}\lambda_{j} is still equal to mkm-k, and the value of the right hand side of (5.3) becomes larger. We keep doing this if there is some λj<0\lambda_{j}<0 for some 1jn1\leq j\leq n. Then we finally get 0λjk0\leq\lambda_{j}\leq k for all 1jn1\leq j\leq n and mk=j=1nλjm-k=\sum_{j=1}^{n}\lambda_{j} still holds; and the process will not make the value of the right hand side of (5.3) smaller. So we only need to prove (5.3) with the additional condition λj0\lambda_{j}\geq 0 for all 1jn1\leq j\leq n.

From now on, we will assume λj0\lambda_{j}\geq 0 for all 1jn1\leq j\leq n. As j=1nλj=mk1\sum_{j=1}^{n}\lambda_{j}=m-k\geq 1, without loss of generality, we can further assume λ11\lambda_{1}\geq 1.

Step 2. We show that it is actually sufficient to prove (5.3) for λ1=1\lambda_{1}=1 and λ2==λn=0\lambda_{2}=\cdots=\lambda_{n}=0.

For simplicity, we denote the right hand side of (5.3) by FF:

(5.5) F(n,k,λ):=m(n+k+mn)j=1n(n+1+kλjkλj),F(n,k,\lambda):=m\binom{n+k+m}{n}\prod_{j=1}^{n}\binom{n+1+k-\lambda_{j}}{k-\lambda_{j}},

where m=k+j=1nλjm=k+\sum_{j=1}^{n}\lambda_{j} and λ=(λ1,,λn)\lambda=(\lambda_{1},\cdots,\lambda_{n}). The function FF has the following property.

Lemma 5.5.

Suppose n,k1n,k\geq 1 and λ=(λ1,,λn)n\lambda=(\lambda_{1},\cdots,\lambda_{n})\in\mathbb{Z}^{n} with 0λjk0\leq\lambda_{j}\leq k for each 1jn1\leq j\leq n. If λj11\lambda_{j_{1}}\geq 1 for some 1j1n1\leq j_{1}\leq n, then

(5.6) F(n,k,λ)F(n,k,λej1),F(n,k,\lambda)\leq F(n,k,\lambda-e_{j_{1}}),

where ej1=(0,,0,1,0,0)e_{j_{1}}=(0,\cdots,0,1,0\cdots,0) is the unit vector along the j1j_{1}-th direction in n\mathbb{R}^{n}.

Consequently, if λ11\lambda_{1}\geq 1, and all other λj\lambda_{j}^{\prime}s are nonnegative, then

F(n,k,λ)F(n,k,e1).F(n,k,\lambda)\leq F(n,k,e_{1}).
Proof.

We cancel the common combinatorial factors in (5.6), and write it as

m(n+k+mn)(n+1+kλj1kλj1)(m1)(n+k+m1n)(n+2+kλj1kλj1+1),m\binom{n+k+m}{n}\binom{n+1+k-\lambda_{j_{1}}}{k-\lambda_{j_{1}}}\leq(m-1)\binom{n+k+m-1}{n}\binom{n+2+k-\lambda_{j_{1}}}{k-\lambda_{j_{1}}+1},

where m=k+j=1nλjm=k+\sum_{j=1}^{n}\lambda_{j}.

By expanding the remaining combinatorial terms and further canceling common factors, we deduce that (5.6) is equivalent to

mn+k+mk+m(m1)n+2+kλj1kλj1+1.m\cdot\frac{n+k+m}{k+m}\leq(m-1)\cdot\frac{n+2+k-\lambda_{j_{1}}}{k-\lambda_{j_{1}}+1}.

Clearly, the right hand side is increasing with respect to 1λj1k1\leq\lambda_{j_{1}}\leq k. Thus, it is sufficient to prove

(5.7) mn+k+mk+m(m1)n+k+1k,m\cdot\frac{n+k+m}{k+m}\leq(m-1)\cdot\frac{n+k+1}{k},

A straightforward computation shows that

(5.7)\displaystyle\eqref{lemma F eq simplified} mnk+m+1(m1)n+1k\displaystyle\iff m\cdot\frac{n}{k+m}+1\leq(m-1)\cdot\frac{n+1}{k}
mnk+k2+mkmnk+mknkk+(m2m)(n+1)\displaystyle\iff mnk+k^{2}+mk\leq mnk+mk-nk-k+(m^{2}-m)(n+1)
k2+nk+k(m2m)(n+1).\displaystyle\iff k^{2}+nk+k\leq(m^{2}-m)(n+1).

The last inequality follows immediately by the fact m=k+j=1nλjk+1m=k+\sum_{j=1}^{n}\lambda_{j}\geq k+1. So the proof is finished.

Thus, with the help of Lemma 5.5, it suffices to prove (5.3) for λ1=1\lambda_{1}=1, λ2==λn=0\lambda_{2}=\cdots=\lambda_{n}=0 and m=k+1m=k+1. That is, we only need to show that

(5.8) k(n+kk)n+2>(k+1)(n+2k+1n)(n+kk1)(n+k+1k)n1.k\,\binom{n+k}{k}^{n+2}>(k+1)\,\binom{n+2k+1}{n}\binom{n+k}{k-1}\binom{n+k+1}{k}^{n-1}.

Step 3. We complete the proof of Lemma 5.3, by proving (5.8) for any n2n\geq 2, k1k\geq 1.

Let us further simplify (5.8) to the following equivalent inequalities.

(5.8)\displaystyle\eqref{main lemma simplified eq} k(n+k)!2n!2k!2>(k+1)(n+2k+1)!n!(2k+1)!kn+1(n+k+1)n1(n+1)n1\displaystyle\iff k\cdot\frac{(n+k)!^{2}}{n!^{2}k!^{2}}>(k+1)\cdot\frac{(n+2k+1)!}{n!(2k+1)!}\cdot\frac{k}{n+1}\cdot\frac{(n+k+1)^{n-1}}{(n+1)^{n-1}}
(n+1)n(k+1)(n+k+1)n1(n+k)!2(2k+1)!n!k!2(n+2k+1)!>1.\displaystyle\iff\frac{(n+1)^{n}}{(k+1)(n+k+1)^{n-1}}\cdot\frac{(n+k)!^{2}(2k+1)!}{n!k!^{2}(n+2k+1)!}>1.

Denote the left hand side term in the last inequality by L(n,k)L(n,k), i.e.,

L(n,k):=(n+1)n(k+1)(n+k+1)n1(n+k)!2(2k+1)!n!k!2(n+2k+1)!.L(n,k):=\frac{(n+1)^{n}}{(k+1)(n+k+1)^{n-1}}\cdot\frac{(n+k)!^{2}(2k+1)!}{n!k!^{2}(n+2k+1)!}.

It remains to prove L(n,k)>1L(n,k)>1 for n2n\geq 2, k1k\geq 1.

Lemma 5.6.

Given nonnegative integers n,kn,k, we have

(5.9) L(n,k)L(n+1,k).L(n,k)\leq L(n+1,k).
Proof.

Set Q(n,k):=L(n+1,k)/L(n,k)Q(n,k):=L(n+1,k)/L(n,k). Then

Q(n,k)=(n+2)n+1(n+1)n+1(n+k+1)n+1(n+k+2)n(n+2k+2).Q(n,k)=\frac{(n+2)^{n+1}}{(n+1)^{n+1}}\cdot\frac{(n+k+1)^{n+1}}{(n+k+2)^{n}(n+2k+2)}.

Regarding kk as a real variable in [0,)[0,\infty), we take the logarithmic derivative of Q(n,k)Q(n,k) with respect to kk:

logQ(n,k)k=\displaystyle\frac{\partial\log Q(n,k)}{\partial k}= n+1n+k+1nn+k+22n+2k+2\displaystyle\frac{n+1}{n+k+1}-\frac{n}{n+k+2}-\frac{2}{n+2k+2}
=\displaystyle= 2n+k+2(n+k+1)(n+k+2)2n+2k+2\displaystyle\frac{2n+k+2}{(n+k+1)(n+k+2)}-\frac{2}{n+2k+2}
=\displaystyle= nk(n+k+1)(n+k+2)(n+2k+2).\displaystyle\frac{nk}{(n+k+1)(n+k+2)(n+2k+2)}.

It follows that for given n0n\geq 0, Q(n,k)Q(n,k) is increasing with respect to k0k\geq 0. Thus, for n,k0n,k\geq 0, we have

Q(n,k)Q(n,0)=1.Q(n,k)\geq Q(n,0)=1.

That is the desired result. ∎

Now, for n2,k1n\geq 2,k\geq 1, Lemma 5.6 yields that

L(n,k)L(2,k)=\displaystyle L(n,k)\geq L(2,k)= 32(k+1)(k+3)(k+2)!2(2k+1)!2!k!2(2k+3)!\displaystyle\frac{3^{2}}{(k+1)(k+3)}\cdot\frac{(k+2)!^{2}(2k+1)!}{2!k!^{2}(2k+3)!}
=\displaystyle= 9(k+1)2(k+2)22(k+1)(k+3)(2k+2)(2k+3)\displaystyle\frac{9(k+1)^{2}(k+2)^{2}}{2(k+1)(k+3)(2k+2)(2k+3)}
=\displaystyle= 9(k2+4k+4)4(2k2+9k+9)>1.\displaystyle\frac{9(k^{2}+4k+4)}{4(2k^{2}+9k+9)}>1.

The proof of Lemma 5.3 is now complete. ∎

References

  • [1] Steven R. Bell. Proper holomorphic mappings and the Bergman projection. Duke Math. J., 48(1):167–175, 1981.
  • [2] Steven R. Bell. The Bergman kernel function and proper holomorphic mappings. Trans. Amer. Math. Soc., 270(2):685–691, 1982.
  • [3] Stefan Bergmann. Über die Kernfunktion eines Bereiches und ihr Verhalten am Rande. I. J. Reine Angew. Math., 169:1–42, 1933.
  • [4] Stefan Bergmann. Über die Kernfunktion eines Bereiches und ihr Verhalten am Rande. II. J. Reine Angew. Math., 172:89–128, 1935.
  • [5] Louis Boutet de Monvel and Johannes Sjöstrand. Sur la singularité des noyaux de Bergman et de Szegö. In Journées: Équations aux Dérivées Partielles de Rennes (1975), pages 123–164. Astérisque, No. 34–35. 1976.
  • [6] Henri Cartan. Quotient d’un espace analytique par un groupe d’automorphismes. In Algebraic geometry and topology, pages 90–102. Princeton University Press, Princeton, N. J., 1957. A symposium in honor of S. Lefschetz,.
  • [7] Bo-Yong Chen and Siqi Fu. Stability of the Bergman kernel on a tower of coverings. J. Differential Geom., 104(3):371–398, 2016.
  • [8] Shiu-Yuen Cheng. Open Problems, Conference on Nonlinear Problems in Geometry held in Katata, Sep. 3-8, 1979. Tohoku University, Department of Math., Sendai, 1979.
  • [9] John P. D’Angelo. Invariant holomorphic mappings. J. Geom. Anal., 6(2):163–179, 1996.
  • [10] John P. D’Angelo and Daniel A. Lichtblau. Spherical space forms, CR mappings, and proper maps between balls. J. Geom. Anal., 2(5):391–415, 1992.
  • [11] Peter Ebenfelt, Ming Xiao, and Hang Xu. Algebraicity of the Bergman kernel. arXiv:2007.00234, 2020.
  • [12] Charles Fefferman. The Bergman kernel and biholomorphic mappings of pseudoconvex domains. Invent. Math., 26:1–65, 1974.
  • [13] Charles Fefferman. Monge-Ampère equations, the Bergman kernel, and geometry of pseudoconvex domains. Ann. of Math. (2), 103(2):395–416, 1976.
  • [14] Franc Forstnerič. Proper holomorphic maps from balls. Duke Math. J., 53(2):427–441, 1986.
  • [15] Siqi Fu and Bun Wong. On strictly pseudoconvex domains with Kähler-Einstein Bergman metrics. Math. Res. Lett., 4(5):697–703, 1997.
  • [16] Xiaojun Huang. Isolated complex singularities and their CR links. Sci. China Ser. A, 49(11):1441–1450, 2006.
  • [17] Xiaojun Huang and Xiaoshan Li. Bergman-Einstein metric on a Stein space with a strongly pseudoconvex boundary. arXiv:2008.03645v1, 2020.
  • [18] Xiaojun Huang and Ming Xiao. A uniformization theorem for Stein spaces. Complex Anal. Synerg., 6(2):Paper No. 6, 5, 2020.
  • [19] Xiaojun Huang and Ming Xiao. Bergman-Einstein metrics, a generalization of Kerner’s theorem and Stein spaces with spherical boundaries. J. Reine Angew. Math., 2020, https://doi.org/10.1515/crelle-2020-0012.
  • [20] Paul F. Klembeck. Kähler metrics of negative curvature, the Bergmann metric near the boundary, and the Kobayashi metric on smooth bounded strictly pseudoconvex sets. Indiana Univ. Math. J., 27(2):275–282, 1978.
  • [21] Shoshichi Kobayashi. Geometry of bounded domains. Transactions of the American Mathematical Society, 92(2):267–290, 1959.
  • [22] Shoshichi Kobayashi and Katsumi Nomizu. Foundations of differential geometry. Vol. II. Wiley Classics Library. John Wiley & Sons, Inc., New York, 1996. Reprint of the 1969 original, A Wiley-Interscience Publication.
  • [23] Song-Ying Li. Characterization for balls by potential function of Kähler-Einstein metrics for domains in n\mathbb{C}^{n}. Comm. Anal. Geom., 13(2):461–478, 2005.
  • [24] Song-Ying Li. On characterization for a class of pseudo-convex domains with positive constant pseudo-scalar curvature on their boundaries. Comm. Anal. Geom., 17(1):17–35, 2009.
  • [25] Song-Ying Li. Plurisubharmonicity for the solution of the Fefferman equation and applications. Bull. Math. Sci., 6(2):287–309, 2016.
  • [26] Daniel Lichtblau. Invariant proper holomorphic maps between balls. Indiana Univ. Math. J., 41(1):213–231, 1992.
  • [27] S. Y. Nemirovski and R. G. Shafikov. Conjectures of Cheng and Ramadanov. Uspekhi Mat. Nauk, 61(4(370)):193–194, 2006.
  • [28] Walter Rudin. Proper holomorphic maps and finite reflection groups. Indiana Univ. Math. J., 31(5):701–720, 1982.