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On regular subgroups of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R})

Sami Douba  and  Konstantinos Tsouvalas
Abstract.

Motivated by a question of M. Kapovich, we show that the 2\mathbb{Z}^{2} subgroups of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) that are regular in the language of Kapovich–Leeb–Porti, or divergent in the sense of Guichard–Wienhard, are precisely the lattices in minimal horospherical subgroups. This rules out any relative Anosov subgroups of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) that are not in fact Gromov-hyperbolic. By work of Oh, it also follows that a Zariski-dense discrete subgroup Γ\Gamma of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) contains a regular 2\mathbb{Z}^{2} if and only if Γ\Gamma is commensurable to a conjugate of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{Z}). In particular, a Zariski-dense regular subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) contains no 2\mathbb{Z}^{2} subgroups.

1. Introduction

Our discussion is motivated by the following question of M. Kapovich, also considered by D. Long and A. Reid.

Question 1.1.

([8, Prob. 3.3]) Is there a subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{Z}) isomorphic to 2\mathbb{Z}^{2}*\mathbb{Z}?

We remark that 𝖲𝖮3,1()\mathsf{SO}_{3,1}(\mathbb{Z}) contains copies of 2\mathbb{Z}^{2}*\mathbb{Z}, and hence so does 𝖲𝖫n()\mathsf{SL}_{n}(\mathbb{Z}) for each n4n\geqslant 4. While we do not resolve Question 1.1, we establish the following.

Theorem 1.2.

There is no regular subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) isomorphic to 2\mathbb{Z}^{2}*\mathbb{Z}.

Regularity (defined with respect to a parabolic subgroup) is a form of discreteness for subgroups of, or representations into, noncompact semisimple Lie groups that coincides with discreteness in the rank-one setting, but is strictly stronger in higher rank. These subgroups already appear in work of Benoist [1], and are the divergent subgroups of Guichard and Wienhard [7]; see Section 2 for the precise definition. For instance, the aforementioned copies of 2\mathbb{Z}^{2}*\mathbb{Z} in 𝖲𝖫n()\mathsf{SL}_{n}(\mathbb{Z}) for n4n\geqslant 4 are regular, as are Anosov representations of Gromov-hyperbolic groups [12, 7] and, more generally, relative Anosov representations of relatively hyperbolic groups [9, 17]. On the other hand, a lattice in a Cartan subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is not regular. Indeed, we show that regular 2\mathbb{Z}^{2} subgroups of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) are of a very particular form. Recall that a (resp., minimal, maximal) horospherical subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is by definition the unipotent radical of a (resp., maximal, minimal) proper parabolic subgroup of the latter.

Theorem 1.3.

A representation ρ:2𝖲𝖫3()\rho:\mathbb{Z}^{2}\rightarrow\mathsf{SL}_{3}(\mathbb{R}) is regular if and only if ρ(2)\rho(\mathbb{Z}^{2}) is a lattice in a minimal horospherical subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}).

It follows from Theorem 1.3 and results111In greater detail, suppose that Γ<𝖲𝖫3()\Gamma<\mathsf{SL}_{3}(\mathbb{R}) is discrete and Zariski-dense, and that some minimal horospherical subgroup UU of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is Γ\Gamma-compact, where, following Oh [14], we say that a closed subgroup HH of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is Γ\Gamma-compact if H/(HΓ)H/(H\cap\Gamma) is compact. Then Oh exhibits in [14, Prop. 4.1] a (Γ\Gamma-compact) maximal horospherical subgroup VV of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) containing UU such that the other minimal horospherical subgroup UU^{\prime} of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) contained in VV is also Γ\Gamma-compact. By Zariski-density of Γ\Gamma, there is some γΓ\gamma\in\Gamma such that the Γ\Gamma-compact minimal horospherical subgroups UU and γUγ1\gamma U^{\prime}\gamma^{-1} are opposite to one another [14, Prop. 3.6]. One now applies the main theorem of [13] to conclude that Γ\Gamma is commensurable to a conjugate of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{Z}). See also Benoist’s survey [2, Prop. 4.1]. of Oh [13, 14] that any Zariski-dense discrete subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) containing a regular 2\mathbb{Z}^{2} is in fact commensurable to an 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R})-conjugate of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{Z}). Theorem 1.2 now follows since any discrete 2\mathbb{Z}^{2}\ast\mathbb{Z} in 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is necessarily Zariski-dense, while 2\mathbb{Z}^{2}\ast\mathbb{Z} cannot be realized as a lattice in 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}), for instance, because groups of the latter form enjoy Kazhdan’s property (T) [11] (see also Furstenberg [6]). Moreover, as regularity is inherited by subgroups, and since 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{Z}) contains a lattice in a Cartan subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}), we deduce the following.

Corollary 1.4.

A Zariski-dense regular subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) contains no 2\mathbb{Z}^{2} subgroups.

We remark that if FF is a lattice in a minimal horospherical subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}), then the limit set of FF in the Furstenberg boundary of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is the set of all projective flags of the form (z,)(z,\ell), where either the point z(3)z\in\mathbb{P}(\mathbb{R}^{3}) is fixed and (3)\ell\subset\mathbb{P}(\mathbb{R}^{3}) varies among all projective lines in (3)\mathbb{P}(\mathbb{R}^{3}) containing zz, or the projective line \ell is fixed and zz varies among all points of \ell; for the precise notion of limit set used here, see Section 2. Thus, another consequence of Theorem 1.3 is that a relative Anosov subgroup Γ\Gamma of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) contains no 2\mathbb{Z}^{2} subgroups, since the limit set of such Γ\Gamma in the Furstenberg boundary of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is antipodal in the language of Kapovich–Leeb–Porti; see [9, 17].

It is known that a group admitting a relative Anosov representation is relatively hyperbolic with respect to a family of virtually nilpotent subgroups; see [9, 17]. Since polycyclic groups that lack 2\mathbb{Z}^{2} subgroups are virtually cyclic, and since groups that are hyperbolic relative to virtually cyclic (more generally, hyperbolic) subgroups are themselves hyperbolic, we conclude the following from the previous paragraph.

Corollary 1.5.

Relative Anosov subgroups of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) are Gromov-hyperbolic.

In fact, in forthcoming work [16] of the second-named author with F. Zhu, Corollary 1.5 is used to prove the stronger statement that a relative Anosov subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) is virtually a free group or a surface group.

The relevance of Theorem 1.3 to Question 1.1 is further explained by the following proposition.

Proposition 1.6.

Let Γ\Gamma be a lattice in a real linear algebraic semisimple Lie group GG of noncompact type and PP be a proper parabolic subgroup of GG. Assume that PP is conjugate to its opposite. If Δ<Γ\Delta<\Gamma is PP-regular in GG and there is a point in G/PG/P that is opposite to each point in the limit set of Δ\Delta in G/PG/P, then for some γΓ\gamma\in\Gamma, the subgroup Δ,γ<Γ\langle\Delta,\gamma\rangle<\Gamma decomposes as Δγ\Delta*\langle\gamma\rangle.

Thus, if there had been a regular 2\mathbb{Z}^{2} in 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{Z}) with “small” limit set in (3)\mathbb{P}(\mathbb{R}^{3})—a scenario that is ruled out by Theorem 1.3—then Proposition 1.6 would have furnished a 2\mathbb{Z}^{2}*\mathbb{Z} subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{Z}), and even a regular such subgroup by work of Dey and Kapovich [4, Thm. 3.2].

In light of Corollary 1.4, a result [3, Thm. 1.1] of the second-named author with R. Canary asserting that Anosov subgroups of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) are virtually isomorphic to Fuchsian groups, and aforementioned forthcoming work of the second-named author with Zhu, the following question seems natural.

Question 1.7.

Is every regular Zariski-dense subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) virtually isomorphic to a Fuchsian group?

Acknowledgements. We thank Nic Brody, Alan Reid, Gabriele Viaggi, and Feng Zhu for interesting discussions. The first-named author was supported by the Huawei Young Talents Program. The second-named author was supported by the European Research Council (ERC) under the European’s Union Horizon 2020 research and innovation programme (ERC starting grant DiGGeS, grant agreement No 715982).

2. Preliminaries

For two sequences (ak)k(a_{k})_{k\in\mathbb{N}} and (bk)k(b_{k})_{k\in\mathbb{N}} of positive real numbers, we write akbka_{k}\asymp b_{k} (resp., ak=O(bk)a_{k}=O(b_{k})) if there is a constant C>1C>1 such that C1akbkCakC^{-1}a_{k}\leqslant b_{k}\leqslant Ca_{k} (resp., akCbka_{k}\leqslant Cb_{k}) for every kk.

Throughout this section, let GG be a finite-center real semisimple Lie group with finitely many connected components and maximal compact subgroup K<GK<G, and let X=G/KX=G/K be the associated symmetric space. Let PP be a proper parabolic subgroup of GG, so that PP is the stabilizer in GG of a point zXz\in\partial_{\infty}X, where X\partial_{\infty}X denotes the visual boundary of XX. Pick a point oXo\in X, and let ξ\xi be the geodesic ray in XX emanating from oo in the class of zz. Fix also a Weyl chamber 𝔞¯+X\overline{\mathfrak{a}}^{+}\subset X for GG in XX with origin oo containing the ray ξ\xi. A sequence (gn)n(g_{n})_{n\in\mathbb{N}} in GG is PP-regular if the vector-valued distances d𝔞¯+(o,gno)d_{\overline{\mathfrak{a}}^{+}}(o,g_{n}o) diverge from each wall of 𝔞¯+\overline{\mathfrak{a}}^{+} not containing ξ\xi. This notion is independent of all the choices made after specifying the parabolic subgroup PP. If Γ\Gamma is a discrete group, a representation ρ:ΓG\rho:\Gamma\rightarrow G is called PP-regular if for every sequence (γn)n(\gamma_{n})_{n\in\mathbb{N}} in Γ\Gamma with γn\gamma_{n}\rightarrow\infty, the sequence (ρ(γn))n(\rho(\gamma_{n}))_{n\in\mathbb{N}} is PP-regular. We remark that such a representation has finite kernel and discrete image, and is moreover PoppP^{\mathrm{opp}}-regular, where PoppP^{\mathrm{opp}} denotes a parabolic subgroup opposite to PP. A subgroup Δ\Delta of GG is called P-regular if the inclusion ΔG\Delta\xhookrightarrow{}G is PP-regular. Notice that if a subgroup Γ\Gamma of GG is PP-regular then so are all subgroups of Γ\Gamma. For more background, see Kapovich–Leeb–Porti [10], as well as earlier work of Guichard–Wienhard [7] where the notion of PP-regularity appears instead as PP-divergence.

Example 2.1.

(The case G=𝖲𝖫3(𝕂)G=\mathsf{SL}_{3}(\mathbb{K})). Let 𝕂=\mathbb{K}=\mathbb{R} or \mathbb{C} and set K=𝖲𝖮(3)K_{\mathbb{R}}=\mathsf{SO}(3) and K=𝖲𝖴(3)K_{\mathbb{C}}=\mathsf{SU}(3). Any element g𝖲𝖫3(𝕂)g\in\mathsf{SL}_{3}(\mathbb{K}) can be written in the form

g=kgdiag(σ1(g),σ2(g),σ3(g))kgkg,kgK𝕂,g=k_{g}\textup{diag}\big{(}\sigma_{1}(g),\sigma_{2}(g),\sigma_{3}(g)\big{)}k_{g}^{\prime}\ \ k_{g},k_{g}^{\prime}\in K_{\mathbb{K}},

where σ1(g)σ2(g)σ3(g)\sigma_{1}(g)\geqslant\sigma_{2}(g)\geqslant\sigma_{3}(g) are uniquely determined and are called the singular values of gg. The Cartan projection222This is the vector-valued distance d𝔞¯+(o,go)d_{\overline{\mathfrak{a}}^{+}}(o,go) with respect to a particular choice of point oX:=𝖲𝖫3(𝕂)/K𝕂o\in X:=\mathsf{SL}_{3}(\mathbb{K})/K_{\mathbb{K}} and Weyl chamber for 𝖲𝖫3(𝕂)\mathsf{SL}_{3}(\mathbb{K}) in XX with origin oo. of gg is μ(g)=(logσ1(g),logσ2(g),logσ3(g))𝔞¯+\mu(g)=(\log\sigma_{1}(g),\log\sigma_{2}(g),\log\sigma_{3}(g))\in\overline{\mathfrak{a}}^{+}.

We will simply say a sequence in (resp., a representation into, subgroup of) 𝖲𝖫3(𝕂)\mathsf{SL}_{3}(\mathbb{K}) is regular if it is PP-regular with respect to the stabilizer P<𝖲𝖫3(𝕂)P<\mathsf{SL}_{3}(\mathbb{K}) of a line in 𝕂3\mathbb{K}^{3}. This language is unambiguous for representations into (hence subgroups of) 𝖲𝖫3(𝕂)\mathsf{SL}_{3}(\mathbb{K}); indeed, if PP and QQ are any two proper parabolic subgroups of 𝖲𝖫3(𝕂)\mathsf{SL}_{3}(\mathbb{K}), then a representation ρ:Γ𝖲𝖫3(𝕂)\rho:\Gamma\rightarrow\mathsf{SL}_{3}(\mathbb{K}) is PP-regular if and only ρ\rho is QQ-regular. A sequence (gn)n(g_{n})_{n\in\mathbb{N}} in 𝖲𝖫3(𝕂)\mathsf{SL}_{3}(\mathbb{K}) is regular if and only if

limnσ1(ρ(gn))σ2(ρ(gn))=.\lim_{n\rightarrow\infty}\frac{\sigma_{1}(\rho(g_{n}))}{\sigma_{2}(\rho(g_{n}))}=\infty.

Note that, in this case, the sequence (1σ1(ρ(gn))ρ(gn))n\left(\frac{1}{\sigma_{1}(\rho(g_{n}))}\rho(g_{n})\right)_{n\in\mathbb{N}} subconverges to a rank-11 matrix.

We will also use the following characterization of PP-regularity in terms of the dynamics on the flag manifold G/PG/P. A sequence (gn)n(g_{n})_{n\in\mathbb{N}} is called PP-contracting if there are points z+G/Pz^{+}\in G/P and zG/Poppz^{-}\in G/P^{\mathrm{opp}} such that gng_{n} converges uniformly on compact subsets of C(z)C(z^{-}) to the constant function z+z^{+}, where C(z)C(z^{-}) denotes the set of all points in G/PG/P opposite to zz^{-}. In this case, we write (gn)n+:=z+(g_{n})_{n}^{+}:=z^{+}.

Fact 2.2.

([10, Prop. 4.15]). A sequence in GG that is PP-contracting is also PP-regular. A sequence in GG that is PP-regular possesses a subsequence that is PP-contracting.

In particular, a sequence (gn)n(g_{n})_{n\in\mathbb{N}} in GG is PP-regular if and only if every subsequence of (gn)n(g_{n})_{n\in\mathbb{N}} possesses a PP-contracting subsequence.

The limit set of a subgroup Γ<G\Gamma<G in the flag manifold G/PG/P, denoted by ΛΓP\Lambda_{\Gamma}^{P}, is by definition the set of (γn)n+G/P(\gamma_{n})_{n}^{+}\in G/P for all PP-contracting sequences (γn)n(\gamma_{n})_{n\in\mathbb{N}} in Γ\Gamma. If PP is conjugate to PoppP^{\mathrm{opp}}, two subsets Λ1,Λ2G/P\Lambda_{1},\Lambda_{2}\subset G/P are antipodal if each element of Λ1\Lambda_{1} is opposite to each element of Λ2\Lambda_{2}.

The proof of the following lemma uses the fact that, for a matrix g=(gij)i,j=13g=(g_{ij})_{i,j=1}^{3} in 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{C}), one has 13g2σ1(g)g2\frac{1}{\sqrt{3}}||g||_{2}\leqslant\sigma_{1}(g)\leqslant||g||_{2}, where g2:=(i,j=13|gij|2)1/2||g||_{2}:=(\sum_{i,j=1}^{3}|g_{ij}|^{2})^{1/2} is the 2\ell^{2}-matrix norm of gg.

Lemma 2.3.

Let (gn)n(g_{n})_{n\in\mathbb{N}} be an infinite unbounded sequence of matrices in 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{C}) with

gn=(1xnyn01zn001).g_{n}=\begin{pmatrix}1&x_{n}&y_{n}\\ 0&1&z_{n}\\ 0&0&1\end{pmatrix}.

Then (gn)n(g_{n})_{n\in\mathbb{N}} is regular if and only if

limnxn2+yn2+zn2|xn|+|zn|+|xnznyn|=.\lim_{n\rightarrow\infty}\frac{x_{n}^{2}+y_{n}^{2}+z_{n}^{2}}{|x_{n}|+|z_{n}|+|x_{n}z_{n}-y_{n}|}=\infty.
Proof.

A straightforward calculation shows that for every nn\in\mathbb{N} we have that

gn1=(1xnxnznyn01zn001).g_{n}^{-1}=\begin{pmatrix}1&-x_{n}&x_{n}z_{n}-y_{n}\\ 0&1&-z_{n}\\ 0&0&1\end{pmatrix}.

Since gn𝖲𝖫3()g_{n}\in\mathsf{SL}_{3}(\mathbb{C}), we have σ1(gn)σ2(gn)σ3(gn)=1\sigma_{1}(g_{n})\sigma_{2}(g_{n})\sigma_{3}(g_{n})=1 and σ1(gn1)=σ3(gn)1\sigma_{1}(g_{n}^{-1})=\sigma_{3}(g_{n})^{-1} for every nn, and hence we obtain

σ1(gn)σ2(gn)=σ1(gn)2σ3(gn)σ1(gn)σ2(gn)σ3(gn)=σ1(gn)2σ1(gn1).\frac{\sigma_{1}(g_{n})}{\sigma_{2}(g_{n})}=\frac{\sigma_{1}(g_{n})^{2}\sigma_{3}(g_{n})}{\sigma_{1}(g_{n})\sigma_{2}(g_{n})\sigma_{3}(g_{n})}=\frac{\sigma_{1}(g_{n})^{2}}{\sigma_{1}(g_{n}^{-1})}.

Now since

σ1(gn)|xn|+|yn|+|zn|,σ1(gn1)|xn|+|xnznyn|+|zn|,\displaystyle\sigma_{1}(g_{n})\asymp|x_{n}|+|y_{n}|+|z_{n}|,\>\ \sigma_{1}(g_{n}^{-1})\asymp|x_{n}|+|x_{n}z_{n}-y_{n}|+|z_{n}|,

the conclusion follows.∎

3. Proof of Theorem 1.3

Proof of Theorem 1.3.

Suppose that ρ:2𝖲𝖫3()\rho:\mathbb{Z}^{2}\rightarrow\mathsf{SL}_{3}(\mathbb{R}) is a regular representation. We first prove that the image of ρ\rho is unipotent. Fix a \mathbb{Z}-basis x,y2x,y\in\mathbb{Z}^{2} for 2\mathbb{Z}^{2}.

Claim 1. The image ρ(2)\rho(\mathbb{Z}^{2}) is a unipotent subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}).

Proof of Claim 1.

Suppose otherwise. Assume first that all the eigenvalues of ρ(x)\rho(x) are distinct. Then, up to conjugation within 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{C}), the image of ρ\rho is a diagonal subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{C}). Since ρ\rho is discrete, we have that μ(ρ(2))\mu(\rho(\mathbb{Z}^{2})) contains the intersection of 𝔞¯+\overline{\mathfrak{a}}^{+} with a lattice in 𝔞\mathfrak{a}. It follows that ρ\rho is not regular in this case.

In the remaining case, up to conjugating ρ\rho within 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}), we have

ρ(x)=(λx100λx000λx2),ρ(y)=(λyαy00λy000λy2),\rho(x)=\begin{pmatrix}\lambda_{x}&1&0\\ 0&\lambda_{x}&0\\ 0&0&\lambda_{x}^{-2}\end{pmatrix},\ \ \rho(y)=\begin{pmatrix}\lambda_{y}&\alpha_{y}&0\\ 0&\lambda_{y}&0\\ 0&0&\lambda_{y}^{-2}\end{pmatrix},

for some λx,λy,αy\lambda_{x},\lambda_{y},\alpha_{y}\in\mathbb{R}. Then we have

ρ(xnym)=λxnλym(1λx1n+αyλy1m001000λx3nλy3m)\rho(x^{n}y^{m})=\lambda_{x}^{n}\lambda_{y}^{m}\begin{pmatrix}1&\lambda_{x}^{-1}n+\alpha_{y}\lambda_{y}^{-1}m&0\\ 0&1&0\\ 0&0&\lambda_{x}^{-3n}\lambda_{y}^{-3m}\end{pmatrix}

for n,mn,m\in\mathbb{Z}. Now there is an infinite sequence of distinct pairs of integers (nk,mk)k(n_{k},m_{k})_{k\in\mathbb{N}} such that limk(λx1nk+αyλy1mk)=0\lim_{k}(\lambda_{x}^{-1}n_{k}+\alpha_{y}\lambda_{y}^{-1}m_{k})=0 and limk(λxnkλymk)=\lim_{k}(\lambda_{x}^{n_{k}}\lambda_{y}^{m_{k}})=\infty; note we can indeed ensure the latter, since otherwise discreteness of ρ\rho would be violated. Observe that σ1(ρ(xnkymk))λxnkλymk\sigma_{1}(\rho(x^{n_{k}}y^{m_{k}}))\asymp\lambda_{x}^{n_{k}}\lambda_{y}^{m_{k}} as kk\rightarrow\infty and that the sequence of matrices (1λxnkλymkρ(xnkymk))k\big{(}\frac{1}{\lambda_{x}^{n_{k}}\lambda_{y}^{m_{k}}}\rho(x^{n_{k}}y^{m_{k}})\big{)}_{k\in\mathbb{N}} converges to a matrix of rank 22. In particular, the sequence (ρ(xnkymk))k(\rho(x^{n_{k}}y^{m_{k}}))_{k\in\mathbb{N}} cannot be regular, so that ρ\rho is not regular. ∎

Therefore, the image of the representation ρ:2𝖲𝖫3()\rho:\mathbb{Z}^{2}\rightarrow\mathsf{SL}_{3}(\mathbb{R}) has to be unipotent. We show that ρ(2)\rho(\mathbb{Z}^{2}) lies in a minimal horospherical subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}). Up to conjugation, we may assume that

ρ(x)=(1axbx01cx001),ρ(y)=(1ayby01cy001),\rho(x)=\begin{pmatrix}1&a_{x}&b_{x}\\ 0&1&c_{x}\\ 0&0&1\end{pmatrix},\ \rho(y)=\begin{pmatrix}1&a_{y}&b_{y}\\ 0&1&c_{y}\\ 0&0&1\end{pmatrix}, (1)

where ax,bx,ay,bya_{x},b_{x},a_{y},b_{y}\in\mathbb{R}. Since ρ(x)\rho(x) commutes with ρ(y)\rho(y), we have that axcy=aycxa_{x}c_{y}=a_{y}c_{x}.

Claim 2. The identity aycx=axcy=0a_{y}c_{x}=a_{x}c_{y}=0 holds.

Proof of Claim 2.

We prove the claim by contradiction. Assuming aycx0a_{y}c_{x}\neq 0, we will exhibit infinite sequences (wm)m(w_{m})_{m\in\mathbb{Z}} in 2\mathbb{Z}^{2} such that (σ1σ2(ρ(wm)))m\big{(}\frac{\sigma_{1}}{\sigma_{2}}(\rho(w_{m}))\big{)}_{m\in\mathbb{Z}} has an infinite bounded subsequence.

Set λ:=cxax=cyay0\lambda:=\frac{c_{x}}{a_{x}}=\frac{c_{y}}{a_{y}}\neq 0. By conjugating the image of ρ\rho with the diagonal matrix diag(1,1,λ)𝖦𝖫3()\textup{diag}(1,1,\lambda)\in\mathsf{GL}_{3}(\mathbb{R}), we may assume that ax=cxa_{x}=c_{x} and ay=cya_{y}=c_{y}, and hence

ρ(x)=(1axbx01ax001),ρ(y)=(1ayby01ay001).\rho(x)=\begin{pmatrix}1&a_{x}&b_{x}\\ 0&1&a_{x}\\ 0&0&1\end{pmatrix},\ \rho(y)=\begin{pmatrix}1&a_{y}&b_{y}\\ 0&1&a_{y}\\ 0&0&1\end{pmatrix}.

A straightforward calculation shows that, for m,nm,n\in\mathbb{Z},

ρ(xn)=(1naxn(bxax22)+n2ax2201nax001),ρ(ym)=(1mayn(byay22)+m2ay2201may001),\rho(x^{n})=\begin{pmatrix}1&na_{x}&n\big{(}b_{x}-\frac{a_{x}^{2}}{2}\big{)}+\frac{n^{2}a_{x}^{2}}{2}\\ 0&1&na_{x}\\ 0&0&1\end{pmatrix},\ \rho(y^{m})=\begin{pmatrix}1&ma_{y}&n\big{(}b_{y}-\frac{a_{y}^{2}}{2}\big{)}+\frac{m^{2}a_{y}^{2}}{2}\\ 0&1&ma_{y}\\ 0&0&1\end{pmatrix},
ρ(xnym)=(1a(m,n)b(m,n)01a(m,n)001),\rho(x^{n}y^{m})=\begin{pmatrix}1&a(m,n)&b(m,n)\\ 0&1&a(m,n)\\ 0&0&1\end{pmatrix},

where

a(m,n)\displaystyle a(m,n) :=nax+may,\displaystyle:=na_{x}+ma_{y},
b(m,n)\displaystyle b(m,n) :=mnaxay+n2ax22+m2ay22+n(bxax22)+m(byay22)\displaystyle:=mna_{x}a_{y}+\frac{n^{2}a_{x}^{2}}{2}+\frac{m^{2}a_{y}^{2}}{2}+n\Big{(}b_{x}-\frac{a_{x}^{2}}{2}\Big{)}+m\Big{(}b_{y}-\frac{a_{y}^{2}}{2}\Big{)}
=12(nax+may)2+n(bxax22)+m(byay22)\displaystyle=\frac{1}{2}\big{(}na_{x}+ma_{y}\big{)}^{2}+n\Big{(}b_{x}-\frac{a_{x}^{2}}{2}\Big{)}+m\Big{(}b_{y}-\frac{a_{y}^{2}}{2}\Big{)}
=12a(m,n)2+Bxaxa(m,n)+m(ByayaxBx)\displaystyle=\frac{1}{2}a(m,n)^{2}+\frac{B_{x}}{a_{x}}a(m,n)+m\Big{(}B_{y}-\frac{a_{y}}{a_{x}}B_{x}\Big{)}
=12((a(m,n)+Bxax)22Bx2ax2+mZx,y),\displaystyle=\frac{1}{2}\Big{(}\Big{(}a(m,n)+\frac{B_{x}}{a_{x}}\Big{)}^{2}-\frac{2B_{x}^{2}}{a_{x}^{2}}+mZ_{x,y}\Big{)},

where the constants Bx,By,Zx,yB_{x},B_{y},Z_{x,y}\in\mathbb{R} are defined as follows:

Bx\displaystyle B_{x} :=bxax22,By:=byay22\displaystyle:=b_{x}-\frac{a_{x}^{2}}{2},\ B_{y}:=b_{y}-\frac{a_{y}^{2}}{2}
Zx,y\displaystyle Z_{x,y} :=2(ByayaxBx).\displaystyle:=2\Big{(}B_{y}-\frac{a_{y}}{a_{x}}B_{x}\Big{)}.

Suppose first that Zx,y=0Z_{x,y}=0, and choose infinite sequences (km)m,(rm)m(k_{m})_{m\in\mathbb{N}},(r_{m})_{m\in\mathbb{N}} of integers such that

|a(km,rm)|=|kmax+rmay|1\big{|}a(k_{m},r_{m})\big{|}=\big{|}k_{m}a_{x}+r_{m}a_{y}\big{|}\leqslant 1

for every mm. By our assumption that Zx,y=0Z_{x,y}=0, we have that (b(km,rm))m(b(k_{m},r_{m}))_{m\in\mathbb{Z}} is also bounded, and hence so is (ρ(xkmyrm))m(\rho(x^{k_{m}}y^{r_{m}}))_{m\in\mathbb{N}}, violating our assumption that ρ\rho is discrete and faithful.

Now suppose that Zx,y0Z_{x,y}\neq 0. Let mm\in\mathbb{Z} with mZx,y<0mZ_{x,y}<0, and define

nm:=mayax+1ax|mZx,y|n_{m}:=\left\lfloor-m\frac{a_{y}}{a_{x}}+\frac{1}{a_{x}}\sqrt{|mZ_{x,y}|}\right\rfloor

so that

|a(m,nm)|mZx,y||=|ax||nm+ayaxm1ax|mZx,y|||ax|.\Big{|}a(m,n_{m})-\sqrt{|mZ_{x,y}|}\Big{|}=|a_{x}|\Big{|}n_{m}+\frac{a_{y}}{a_{x}}m-\frac{1}{a_{x}}\sqrt{|mZ_{x,y}|}\Big{|}\leqslant|a_{x}|. (2)

Note that |a(m,nm)||m||a(m,n_{m})|\asymp\sqrt{|m|}, and hence

|b(m,nm)|\displaystyle\big{|}b(m,n_{m})\big{|} Bx2ax2+12|a(m,nm)+Bxax|mZx,y|||a(m,nm)+Bxax+|mZx,y||\displaystyle\leqslant\frac{B_{x}^{2}}{a_{x}^{2}}+\frac{1}{2}\left|a(m,n_{m})+\frac{B_{x}}{a_{x}}-\sqrt{|mZ_{x,y}|}\right|\cdot\left|a(m,n_{m})+\frac{B_{x}}{a_{x}}+\sqrt{|mZ_{x,y}|}\right|
Bx2ax2+(|ax|+|Bx||ax|)(|a(m,nm)|+|Bx||ax|+|mZx,y|)\displaystyle\leqslant\frac{B_{x}^{2}}{a_{x}^{2}}+\left(|a_{x}|+\frac{|B_{x}|}{\big{|}a_{x}\big{|}}\right)\left(\big{|}a(m,n_{m})\big{|}+\frac{\big{|}B_{x}\big{|}}{\big{|}a_{x}\big{|}}+\sqrt{|mZ_{x,y}|}\right)
=O(|m|),mZx,y,\displaystyle=O(\sqrt{|m|}),\ \ mZ_{x,y}\rightarrow-\infty,

where the second inequality follows from (2).

Finally, we claim that the sequence ρ(wm)m\rho(w_{m})_{m\in\mathbb{Z}}, where wm:=xnmymw_{m}:=x^{n_{m}}y^{m}, has an infinite subsequence that is not regular. Indeed, for mm\in\mathbb{Z} with mZx,y<0mZ_{x,y}<0, we have by Lemma 2.3 that

σ1(ρ(wm))σ2(ρ(wm))2a(m,nm)2+b(m,nm)22|a(m,nm)|+|a(m,nm)2b(m,nm)|\frac{\sigma_{1}(\rho(w_{m}))}{\sigma_{2}(\rho(w_{m}))}\asymp\frac{2a(m,n_{m})^{2}+b(m,n_{m})^{2}}{2\big{|}a(m,n_{m})\big{|}+\big{|}a(m,n_{m})^{2}-b(m,n_{m})\big{|}}

and the latter fraction remains bounded since |a(m,nm)||m|\big{|}a(m,n_{m})\big{|}\asymp\sqrt{|m|} and |b(m,nm)|=O(|m|)\big{|}b(m,n_{m})\big{|}=O(\sqrt{|m|}) as mZx,ymZ_{x,y}\rightarrow-\infty.

We thus arrive at a contradiction, and so we conclude that axcy=aycx=0a_{x}c_{y}=a_{y}c_{x}=0. ∎

Completing the proof of Theorem 1.3. We have reduced to the case that ρ\rho is as in (1) with axcy=aycx=0a_{x}c_{y}=a_{y}c_{x}=0.

Suppose first that ax=cx=0a_{x}=c_{x}=0 and aycy0a_{y}c_{y}\neq 0. In this case, we may define a new representation ρ:2𝖲𝖫3()\rho^{\prime}:\mathbb{Z}^{2}\rightarrow\mathsf{SL}_{3}(\mathbb{R}) given by

ρ(x)=ρ(xy),ρ(y)=ρ(y).\rho^{\prime}(x)=\rho(xy),\ \rho^{\prime}(y)=\rho(y).

Since ρ\rho is assumed to be regular, the same holds for ρ\rho^{\prime}. Now note that the (1,2)(1,2) and (2,3)(2,3) entries of ρ(x)\rho^{\prime}(x) and ρ(y)\rho^{\prime}(y) are non-zero, so that the representation ρ\rho^{\prime} cannot be regular by Claim 1, a contradiction. By applying the same argument with xx and yy interchanged, we conclude that in fact ax=ay=0a_{x}=a_{y}=0 or cx=cy=0c_{x}=c_{y}=0 as desired.

Finally, we verify that if ρ(2)\rho(\mathbb{Z}^{2}) is a lattice in a minimal horospherical subgroup of 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}), then ρ\rho is indeed regular. This follows immediately from Lemma 2.3, but we present the following geometric argument that applies in any dimension. We first consider the case that ρ(2)\rho(\mathbb{Z}^{2}) is a lattice in the unipotent radical of the stabilizer in 𝖲𝖫3()\mathsf{SL}_{3}(\mathbb{R}) of a hyperplane in 3\mathbb{R}^{3}.

Claim 3. Let UU be the unipotent radical of the stabilizer in 𝖲𝖫d()\mathsf{SL}_{d}(\mathbb{R}) of a hyperplane VdV\subset\mathbb{R}^{d}. Then any lattice FF in UU is PP-regular, where PP is the stabilizer of a line in d\mathbb{R}^{d}.

Proof of Claim 3.

We identify the UU-invariant affine chart (d)(V)\mathbb{P}(\mathbb{R}^{d})\smallsetminus\mathbb{P}(V) with d1\mathbb{R}^{d-1}, so that UU acts on d1\mathbb{R}^{d-1} via translations. For a point zd1z\in\mathbb{R}^{d-1} and R>0R>0, denote by B(z,R)B(z,R) the Euclidean ball in d1\mathbb{R}^{d-1} of radius RR centered at zz. Fix a point z0d1z_{0}\in\mathbb{R}^{d-1}.

Now let (γn)n(\gamma_{n})_{n\in\mathbb{N}} be a sequence in FF with γn\gamma_{n}\rightarrow\infty. Then, since (d)\mathbb{P}(\mathbb{R}^{d}) is compact, up to extraction, we have that γnz0z+\gamma_{n}z_{0}\rightarrow z^{+} for some z+(d)z^{+}\in\mathbb{P}(\mathbb{R}^{d}). Moreover, since FF acts properly on d1\mathbb{R}^{d-1}, we in fact have z+(V)z^{+}\in\mathbb{P}(V).

We claim that (γn)n(\gamma_{n})_{n\in\mathbb{N}} converges uniformly on compact subsets of d\mathbb{R}^{d} to the constant function z+z^{+}. Indeed, let WnW_{n} be a metric 1n\frac{1}{n}-neighborhood of z+z^{+} in (d)\mathbb{P}(\mathbb{R}^{d}) with respect to the Fubini–Study metric on the latter; viewed in our chosen affine chart, the boundary of WnW_{n} is a two-sheeted hyperboloid for nn sufficiently large. It suffices to show that for any nn\in\mathbb{N}, there is some NN\in\mathbb{N} such that WnγNB(z0,n)=B(γNz0,n)W_{n}\supset\gamma_{N}B(z_{0},n)=B(\gamma_{N}z_{0},n). But this is true since, given any nn\in\mathbb{N}, there is some mm\in\mathbb{N} such that B(z,n)WnB(z,n)\subset W_{n} for each zWmz\in W_{m}.∎

In the remaining case, where ρ(2)\rho(\mathbb{Z}^{2}) lies in the unipotent radical of the stabilizer of a line in 3\mathbb{R}^{3}, one argues as above with the dual representation ρ\rho^{\ast} instead of ρ\rho, as σi(ρ(γ))=σ4i(ρ(γ))1\sigma_{i}(\rho^{\ast}(\gamma))=\sigma_{4-i}(\rho(\gamma))^{-1} for γ2\gamma\in\mathbb{Z}^{2} and 1i31\leqslant i\leqslant 3. ∎

Remark 3.1.

Following the above approach, it is not difficult to see that if a,b<𝖲𝖫3()\langle a,b\rangle<\mathsf{SL}_{3}(\mathbb{R}) is a discrete 2\mathbb{Z}^{2} which is not contained in a minimal horospherical subgroup, then the limit set of a,b\langle a,b\rangle in (3)\mathbb{P}(\mathbb{R}^{3}) consists of at most three points.

4. Proof of Proposition 1.6

To prove Proposition 1.6, we use the following variant of the ping-pong lemma. Similar arguments appear in work of Dey and Kapovich [4], but we include them here for the convenience of the reader.

Lemma 4.1.

Let GG be a Lie group acting continuously on a manifold \mathcal{F}. Suppose Γ1,Γ2<G\Gamma_{1},\Gamma_{2}<G are infinite333In fact, our argument requires only that |Γi|>2|\Gamma_{i}|>2 for i=1,2i=1,2. The statement remains true if at least one of the Γi\Gamma_{i} has size at least 33. and that there are closed nonempty disjoint subsets C1,C2C_{1},C_{2}\subset\mathcal{F} such that γiCjCi\gamma_{i}C_{j}\subset C_{i} for γiΓi{1}\gamma_{i}\in\Gamma_{i}\smallsetminus\{1\} and iji\neq j. Then Γ1,Γ2<G\langle\Gamma_{1},\Gamma_{2}\rangle<G is discrete and decomposes as Γ1Γ2\Gamma_{1}*\Gamma_{2}.

Proof.

Let ρ:Γ1Γ2G\rho:\Gamma_{1}*\Gamma_{2}\rightarrow G be the map induced by the inclusions ΓiG\Gamma_{i}\subset G for i=1,2i=1,2. Take a sequence wnΓ1Γ2w_{n}\in\Gamma_{1}*\Gamma_{2} and suppose for a contradiction that wn1w_{n}\neq 1 for any nn\in\mathbb{N} but limnρ(wn)=1G\lim_{n}\rho(w_{n})=1\in G. Up to relabeling Γ1\Gamma_{1} and Γ2\Gamma_{2} and extracting a subsequence of (wn)n(w_{n})_{n}, we may assume that for some fixed i{1,2}i\in\{1,2\} and each nn\in\mathbb{N}, the first letter (read from the left) in the canonical form of wnw_{n} belongs to Γ1{1}\Gamma_{1}\smallsetminus\{1\} and the last belongs to Γi{1}\Gamma_{i}\smallsetminus\{1\}.

Suppose first that i=1i=1. Then ρ(wn)C2C1\rho(w_{n})C_{2}\subset C_{1} for each nn\in\mathbb{N}. Selecting some zC2z\in C_{2}, we then have z=limnρ(wn)zC1z=\lim_{n}\rho(w_{n})z\in C_{1} since C1C_{1} is closed, so that zC1C2z\in C_{1}\cap C_{2}, a contradiction.

Now suppose that i=2i=2. Pick an element γ1Γ1{1}\gamma_{1}\in\Gamma_{1}\smallsetminus\{1\}, and let wn=γ1wnγ11w_{n}^{\prime}=\gamma_{1}w_{n}\gamma_{1}^{-1} for nn\in\mathbb{N}. Note that we still have limnρ(wn)=1\lim_{n}\rho(w_{n}^{\prime})=1. If for some subsequence (wnk)k(w^{\prime}_{n_{k}})_{k} of (wn)n(w_{n}^{\prime})_{n} the canonical form of wnkw^{\prime}_{n_{k}} has odd length for each kk\in\mathbb{N}, then one obtains a contradiction as in the previous paragraph. Otherwise, there is some NN\in\mathbb{N} such that the first letter (read from the left) in the canonical form of wnw_{n} is γ11\gamma_{1}^{-1} for nNn\geqslant N. Now select γ1Γ1{1,γ1}\gamma^{\prime}_{1}\in\Gamma_{1}\smallsetminus\{1,\gamma_{1}\}, and let wn′′=γ1wn(γ1)1w^{\prime\prime}_{n}=\gamma_{1}^{\prime}w_{n}(\gamma_{1}^{\prime})^{-1} for nn\in\mathbb{N}. Then again we have limnρ(wn′′)=1\lim_{n}\rho(w_{n}^{\prime\prime})=1, but now the canonical form of wn′′w^{\prime\prime}_{n} has odd length for nNn\geqslant N, so that we arrive at a contradiction as in the previous paragraph. ∎

Proof of Proposition 1.6.

Since we have assumed that there is a point in G/PG/P opposite to each point in ΛΔP\Lambda_{\Delta}^{P}, we can find a compact neighborhood W0W_{0} of ΛΔP\Lambda_{\Delta}^{P} and a compact subset UG/PU\subset G/P with nonempty interior such that UU and W0W_{0} are antipodal; see [5, Lem. 4.24]. As in [4, Rmk. 6.4], we have by PP-regularity of Δ\Delta that δUW0\delta U\subset W_{0} for each nontrivial element δΔ\delta\in\Delta apart from a finite list δ1,,δkΔ{1}\delta_{1},\ldots,\delta_{k}\in\Delta\smallsetminus\{1\}.

For i=1,,ki=1,\ldots,k, let ZiZ_{i} be the set of all zG/Pz\in G/P such that zz is not opposite to δiz\delta_{i}z. Since each of the ZiZ_{i} is a proper algebraic subset of G/PG/P, we have that Ui=1kZiU\smallsetminus\bigcup_{i=1}^{k}Z_{i} has nonempty interior. We can thus find a compact subset VUi=1kZiV\subset U\smallsetminus\bigcup_{i=1}^{k}Z_{i} with nonempty interior such that VV and δiV\delta_{i}V are antipodal for i=1,,ki=1,\ldots,k. Setting W=W0i=1kδiVW=W_{0}\cup\bigcup_{i=1}^{k}\delta_{i}V, we then have that VV and WW remain antipodal in G/PG/P.

Now since Γ\Gamma is a lattice in GG, there is an element gΓg\in\Gamma generating a PP-regular cyclic subgroup with ΛgPV̊\Lambda_{\langle g\rangle}^{P}\subset\mathring{V} (one can always choose PP-proximal such gΓg\in\Gamma, the existence of which already follows, for instance, from [15, Lemma 1]). There is then some NN\in\mathbb{N} such that gnWVg^{n}W\subset V for all nn\in\mathbb{Z} with |n|N|n|\geqslant N. Moreover, by design, we have δVW\delta V\subset W for each δΔ{1}\delta\in\Delta\smallsetminus\{1\}. Setting γ=gN\gamma=g^{N}, we conclude from Lemma 4.1 that Δ,γ<Γ\langle\Delta,\gamma\rangle<\Gamma decomposes as Δγ\Delta*\langle\gamma\rangle. ∎

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Institut des Hautes Études Scientifiques, Université Paris-Saclay, 35 route de Chartres, 91440 Bures-sur-Yvette, France

E-mail address: [email protected]

CNRS, Laboratoire Alexander Grothendieck, Institut des Hautes Études Scientifiques, Université Paris-Saclay, 35 route de Chartres, 91440 Bures-sur-Yvette, France

E-mail address: [email protected]