Non-Roelcke precompactness of groups of surface homeomorphisms
Abstract.
We prove that no subgroup of the group of boundary-fixing homeomorphisms of a compact surface whose action on the interior of the surface is sufficiently transitive can be Roelcke precompact with the topology inherited from the compact-open topology.
1. Introduction
Roelcke precompactness is the topological group counterpart of the model theoretic notion of -categoricity in classical and continuous logic. As such, it has received a lot of attention in the literature from a variety of angles.
Definition 1.1.
We say that a topological group is Roelcke precompact if for every neighbourhood of the identity there exists a finite subset such that .
It is a result of Culler and Rosendal [2] that the homeomorphism group of a manifold of dimension (and more generally, any group of homeomorphisms containing a specific class of elements) is not Roelcke precompact. In this note we elaborate on the general idea of their proof to show that the same property holds for a large class of groups of homeomorphisms of compact surfaces.
Given a surface with (possibly empty) boundary , from now on simply ´a surface’, and some tuple of points in the interior of , , we denote by the result of removing (the punctures) from . We write simply , when only interested in the homeomorphism type.
The pure mapping class group of a punctured surface , or is the quotient of the pointwise stabilizer of the set of punctures in (whose elements we can regard alternatively as homeomorphisms of fixing the boundary) by identifying any two elements which are homotopic via a homotopy fixing the punctures. Given we will denote the corresponding mapping class by .
Accordingly, there is a natural quotient map . The kernel is given by the image in of the point pushing map , which plays a certain role in this paper and about which we say a few more words at the beginning of section 1.
For simplicity we assume is compact, so that the compact-open topology on coincides with the uniform convergence topology. We will work with some fixed hyperbolic or flat Riemannian metric on compatible with its topology with respect to which the boundary is geodesic. A system of symmetric neighbourhoods of the identity is thus given by where and .
Definition 1.2.
Let the minimum positive integer such that the point pushing map is an embedding (a fortiori, of a torsion-free group), that is is equal to:
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if is a sphere
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if is a projective plane
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if is a torus or a disk
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otherwise
Theorem 1.3.
Let be a compact surface possibly with boundary and . If is -transitive, then with the topology inherited from the compact-open topology is not Roelcke precompact.
For the remainder of the paper we will use the notation . Given we write to denote the pointwise stabilizer of .
In view of one of the open questions at the end it might be worthwhile to be somewhat more precise.
Definition 1.4.
Let and a tuple of points in the interior of (possibly empty). Denote by be the collection of orbits of points of by .
We say that is sufficiently transitive if there exists a tuple of points in and a non null-homotopic simple closed curve in such that is contained in some .
Notice that if is -transitive then it is sufficiently transitive, so the following clearly implies 1.3.
Theorem 1.5.
Let be a compact surface. If is sufficiently transitive, then with the topology inherited from the compact-open topology is not Roelcke precompact.
Point pushing maps
Fix some tuple of points in . For any path parametrized by an interval and any open containing we choose a map supported in pushing to along . Very concretely: if and is simple this just means a map supported in some open disk which maps to and is supported in . If , where the are simple paths, then we can take as . When we use the expression to denote , where .
We recall the following fundamental fact:
Fact 1.6 (Alexander lemma).
The mapping class group of a once-punctured disk is trivial.
From it one can deduce the following (see Chapter of [1]):
Fact 1.7.
Let be paths in from a point to a point and open sets containing and respectively.
If and are homotopic in then and represent the identity in and respectively regardless of the choices made. If are paths in with and neighbourhoods of and respectively, then for some trivial in .
The induced map is a group homomorphism and an a non-trivial group embedding of a torsion free group under the conditions described in definition 1.2.
We will occasionally omit the superscript from in contexts where in light of the above the choice of neighbourhood and representative do not affect the resulting expression.
Given a curve , for any let be the restriction of to reparametrized to the domain is . If we let . We extend the parametrization of a curve to cyclically when needed.
We write to denote the collection of elements in sending to . Since for any the inner automorphism induces an isomorphism between and for which we will use the same expression .
Lemma 1.8.
Let be an -tuple of points in and an essential simple closed curve in with . Let . Assume that to any point we have assigned some subgroup such that the following holds:
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For any and any we have .
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For any there exists some such that for all and sufficiently small the set maps to a subset of the set
Then there exists some and some such that .
Proof.
By compactness there is a finite tuple such that . We may assume that this set is minimal for the property so that one can choose for so that . Let also and .
Pick , for each some and for some . Consider the group element . One can check that .
By assumption we can write and , where and and any fixed . Alternatively, by property (a) we can write , where .
Now we can write
where is a product of elements in and thus itself in . Notice that it is the same kind of manipulation that allows us to ignore the choice of particular point pushing maps in the expression above. In view of 1.7 we have . ∎
Lemma 1.9.
Let , , and be as in Lemma 1.8 and assume that . Then given any there is a sequence of triples of elements of such that:
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and
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is an infinite set
Proof.
Notice that any element supported in belongs to .
For any and any let
We distinguish two mutually exclusive cases:
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is infinite for all
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is finite for some
Continuity of inner automorphisms and transitivity of on implies that the same case holds for any . The first clearly implies the condition of the statement is satisfied, so from now on assume the second is always the case.
Define . This is the intersection of a descending chain of non-empty sets which are eventually finite. Hence, it is a finite non-empty subset of . Continuity of inner automorphisms implies that for any and any conjugation by induces an isomorphisms between and .
Lemma 1.10.
For any the set is closed under multiplication. It is therefore a finite subgroup of .
Proof.
Consider any and . Then pick some that can be written as , where and maps to . By continuity of the group operations there exists some such that . Choose of the form , where and maps to . Then and . Since is arbitrary, we are done. ∎
We are now in the position to apply Lemma 1.8 to the family . This yields some element (so that ) whose image in is of the form , where . Since is a group we get that , contradicting the finiteness of and the fact that by the choice of the map is an embedding of a torsion-free group. ∎
2. Discriminating between mapping classes
Given arcs between the same pair of boundary points of or simple closed curves in and given some subset we write to indicate that does not intersect and is homotopic to in (rel in the arc case).
Definition 2.1.
Let be small enough that for any at distance less than the point is in the domain of injectivity of the exponential map at , so that there is a unique geodesic segment from to of minimal length in , which we denote by .
As it is well known, given two maps from a space into such that for any a uniform parametrizataion of the geodesic yields a homotopy in between the two maps and .
An immediate consequence of this is the following observation:
Observation 2.2.
Let a tuple of points in and let . Then represents the identity in .
Another one is the Lemma below, which for future reference we state in a degree of generality not needed here. Its content is rather standard but we include a proof for the sake of completeness.
Definition 2.3.
We say that a path connected subset is -branching if there exist and paths between and for distinct such that the path does not contain points at distance from . Clearly, any path connected open set is -branching for some .
Lemma 2.4.
Let be -branching disjoint closed subdisks of . Then there is some constant depending only on the metric such that the following holds. If are two loops in with common endpoints and for all , then .
Proof.
For let the non-linearity of be witnessed by a triple of points in and paths in between the points in the triple.
Let be the homotopy between and where is a constant parametrization of the geodesic segment .
The following claim is easy to verify using rudiments of differential topology.
Claim 2.5.
After performing a small perturbation of , , and we may assume that and are differentiable, that is transverse to , and the points , while preserving the property that for any . After modifying the further and shrinking we may additionally assume that . In particular meet only at the endpoints and they do so smoothly.
Lemma 2.6.
For any connected component of the map is nullhomotopic.
Proof.
For convenience we will drop the superindex for the remainder of this proof. For let and . Let also . By transversality, we have the following:
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is finite for
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is a union of finitely many arcs between points in (potentially arcs between two points in or in )
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is the image of a simple closed curve
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is the endpoint of exactly one arc in for (say ).
This makes into a simplicial complex with and the components of as edges. Let be the projection of onto the second coordinate.
Notice that if and , then we cannot have for and , since this would imply the existence of such that .
We show that is null-homotopic by induction on the number of vertices in .
Number the vertices of cyclically as . Let and let be such that and such that .
Let be such that is minimal. Without loss of generality we may assume and . The case is excluded by our condition on .
Consider first the case in which , with . Without loss of generality we can assume that . We cannot have since then . But and , which forces , resulting in a collision. So . We may assume . Necessarily which in turn implies .
At this point we can remove vertices and connect and directly with an edge of type (so compatible with the other incident edges at the endpoints). The non-collision condition continues to be satisfied, since the image of the new edge is contained in the image of two edges of the same type in the old configuration: , as .
We have replaced a path of type (resp ) with one of type (resp. ), both of which represent homotopic paths between and itself (resp. and ) on the circle . Since the new configuration corresponds to a null-homotopic path by the induction hypothesis, so does the original.
The only case left is that in which . We may assume and thus , as well as and we can apply an argument identical to the one of the previous case.
∎
Given satisfying the conclusion of the sublemma, we can redefine on each component as above by extending to a map from to . Postcomposing with a homeomorphism that slightly enlarges each while fixing and yields a homotopy witnessing .
∎
In the proof of the theorem below we will use the following (see [1], Proposition 2.8)
Fact 2.7.
The action of the homeomorphism group descends to a well-defined action of the mapping class group on free homotopy classes of curves in the surface and homotopy classes relative to the boundary of arcs between points in the boundary. The kernel of the action of the mapping class group on the union of the two families is trivial.
See 1.5
Proof.
Roelcke precompactness of implies the existence of a finite collection such that .
Let , , for be as given by Lemma 1.9 applied to with constant . In view of the above, for any there exists and such that . Notice that for any we have (for the last inclusion, notice that ). If follows that
Up to passing to a subsequence again we may assume that equals some constant for all . For let .
For write . We know that and that () so that . We choose a series of paths between these points as follows. For , take any path in from to .
Lemma 2.8.
After passing to a subsequence we can choose for and paths from to and with the following properties.
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Neither of the points or belongs to for , .
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Let
and notice that it fixes the ball . Consider also the loops at :
Then for any the image of the set in is finite.
Proof.
After passing to a subsequence we may assume that the points converge to a point for all . If we let , then each of the sets are connected.
We start with the following observation:
Observation 2.9.
Let be the interior of an embedded disk, , two open sets in containing with and some countable closed sets of points. Then there exits some finite family of arcs between points such that for any two points there exists some and arcs and in such that
Proof.
This follows from a standard argument. By compactness, there are finitely many connected components of such that . Choose some point for . Now is connected and as it suffices to choose some finite collection of arcs in between and for every pair of distinct . ∎
For fixed let be the families that result from applying Observation 2.9 with , , and and .
For simplicity, write and so forth. Let . We can assume that and hence and intersects in a finite collection of arcs for , .
We first note that it follows from the finiteness of that the image of the collection in in the statement is finite.
Indeed, if then we can rewrite as
Since the simple closed paths and are contained in a disk in they must be homotopic to the identity there. Therefore so is .
In order to ensure the finiteness of the homotopy classes of the we will need the following two standard observations, whose proof we include for the sake of completeness:
Observation 2.10.
Let be a punctured surface, an open disk , and a curve based at some . Then given any and any supported in sending to , the homotopy class of in depends only on the connected component of to which the point belongs.
Proof.
Assume that and are two points in the same connected component of and supported in map and respectively to . If , then . Take some supported in mapping to , then . But by Fact 1.6 the map must be the identity in : a contradiction. ∎
The following follows from a standard application of transversality.
Observation 2.11.
For any any embedded disk contained in some open set and any finite collection of disjoint simple arcs between points outside of there exists another closed disk with such that each intersects in a finite collection of arcs.
Consider the loop . This is a loop in , since im for .
For , let be a closed embedded disk with and such that (and hence ) intersects in a finite collection of arcs.
By iteratively applying Observation 2.10, we conclude that the homotopy class of depends only on the connected component of in which lies for as well as the connected component of in which one lies for . Since in each case there are only finitely many possibilities the result follows.
The existence of such that does not intersect for , is clear. ∎
Choose such that is -branching and let .
By another application of Roelcke precompactness, after passing to a subsequence again we may assume that for all distinct there exists such that . Fix and for the time being also and let .
Let also be any essential simple closed curve or simple arc between boundary points that does not intersect any of the disks . It follows that does not intersect for any . Therefore does not intersect for any and the same holds for .
Now, and can be homotoped to each other through a homotopy with values in , it follows that
Consider the commuting products and . We may assume . Since is supported in , for any as above we have . It follows that
Since and we have
Since both and belong to and ranges over a set of curves/arcs containing representatives of all homotopy classes in we conclude that the images of these two elements in are equal. Expanding as with we obtain
Notice that . On the other hand, we have , since it is supported on . The latter also implies that the supports of for different values of are disjoint and hence . It follows that . By Observation 2.2 we then have and like-wise .
We now claim that , where is the finite set in Lemma 2.8. This concludes the proof, since letting range we obtain that the set has to be finite, contradicting the choice of .
The claim follows from a straightforward algebraic manipulation, which we sketch below, justifiably ignoring the choice of push representatives:
∎
3. Questions
The torus admits a -transitive Roelcke precompact subgroup of homeomorphisms, namely the one given by the diagonal action of on .
Question 3.1.
Is the bound on the degree of transitivity on of a Roelcke precompact subgroup of sharp in those cases in which and is not a torus?
Question 3.2.
Is the subgroup of given above the only -transitive Roelcke precompact subgroup on up to conjugacy?
Question 3.3.
Can a transitive (resp. -transitive) group of homeomorphisms of an -manifold, be Roelcke precompact?
References
- [1] Benson Farb and Dan Margalit. A primer on mapping class groups (pms-49). Princeton university press, 2011.
- [2] Christian Rosendal. Global and local boundedness of polish groups. Indiana University Mathematics Journal, pages 1621–1678, 2013.