Modularity of -representations over totally real fields
Abstract
We study an analogue of Serre’s modularity conjecture for projective representations , where is a totally real number field. We prove new cases of this conjecture when by using the automorphy lifting theorems over CM fields established in [AKT].4442010 Mathematics Subject Classification: 11F41, 11F80.
1 Introduction
Let be a number field, and consider a continuous representation
where is a finite field. (Here denotes the absolute Galois group of ; for this and other notation, see §1.1 below.) We say that is of Serre-type, or -type, if it is absolutely irreducible and totally odd, in the sense that for each real place of and each associated complex conjugation , .
Serre’s conjecture and its generalisations assert that any of -type should be automorphic (see for example [Ser75, Ser87] in the case , [BDJ10] when is totally real, and [ŞS18] for a general number field ). The meaning of the word ‘automorphic’ depends on the context but when is totally real, for example, we can ask for to be associated to a cuspidal automorphic representation of which is regular algebraic of weight 0 (see §2.1 below). Serre’s conjecture is now a theorem when [KW09a, KW09b]. For a totally real field , some results are available when is ‘small’. These are summarised in the following theorem, which relies upon the papers [Ser87, Tun81, SBT97, Man04, Ell05]:
Theorem 1.1.
Let be a totally real number field, and let be a representation of -type. Then is automorphic provided .
One can equally consider continuous representations
where again is a finite field. We say that is of -type if it is absolutely irreducible and totally odd, in the sense that if has odd characteristic then for each real place of , is non-trivial. One could formulate a projective analogue of Serre’s conjecture, asking that any representation of -type be automorphic. A theorem of Tate implies that lifts to a linear representation valued in for some finite extension , and by being automorphic we mean that a lift of it to a linear representation is automorphic (see §2.1 below). Thus if is allowed to vary, this conjecture is equivalent to Serre’s conjecture, since any representation has an associated projective representation , and any projective representation lifts to a representation valued in for some finite extension ; moreover, is of -type if and only if is, and is automorphic if and only if is.
However, for fixed the two conjectures are not equivalent: certainly if is valued in then takes values in , but it is not true that any representation admits a lift valued in , and in fact in general the determination of the minimal extension such that there is a lift to is somewhat subtle. It is therefore of interest to ask whether the consideration of projective representations allows one to expand the list of ‘known’ cases of Serre’s conjecture.
Our main theorem affirms that this is indeed the case. Before giving the statement we need to introduce one more piece of notation. We write for the homomorphism induced by the determinant. We say that a homomorphism is totally even (resp. totally odd) if each complex conjugation in is trivial (resp. non-trivial) image.
Theorem 1.2.
Let be a totally real number field, and let be a representation of -type. Then is automorphic provided that one of the following conditions is satisfied:
-
1.
.
-
2.
, , and is totally even.
-
3.
, , and is totally odd.
-
4.
and is totally odd.
-
5.
and is totally even.
We note the exceptional isomophisms , , , which link our results to showing that splitting fields of polynomials of small degree over arise automorphically.
The proof of Theorem 1.2 falls into three cases. The first is when is even or . When is even, the homomorphism splits, so we reduce easily to Theorem 1.1. When , the homomorphism splits and we can use the Langlands–Tunnell theorem [Tun81] to establish the automorphy of .
The second case is when is odd and is a square in (resp. a non-square in ) and is totally even (resp. totally odd). In this case we are able to construct the following data:
-
•
A solvable totally real extension and a representation such that (by showing that can be chosen to kill the Galois cohomological obstruction to lifting).
-
•
A representation such that and are conjugate in (by choosing an arbitrary lift of to and applying the Khare–Wintenberger method).
We can then use Theorem 1.1 to verify the automorphy of , hence the residual automorphy of . An automorphy lifting theorem then implies the automorphy of , hence itself by solvable descent, hence finally of .
The final case is when and is totally odd. In this case there does not exist any totally real extension such that lifts to a representation valued in (there is a local obstruction at the real places). However, it is possible to find a CM extension such that lifts to a representation valued in with determinant the cyclotomic character. When such a representation necessarily appears in the group of 5-torsion points of an elliptic curve over (cf. [SBT97]) and so we can use the automorphy results over CM fields established in [AKT] together with a solvable descent argument to obtain the automorphy of . The main novelty in this paper is contained in our treatment of this case.
Remark 1.3.
In the final case above of a representation with non-solvable image, the residual automorphy of the lift ultimately depends on [AKT, Theorem 7.1], which proves the automorphy of certain residually dihedral 2-adic Galois representations. The residual automorphy of these 2-adic representations is verified using automorphic induction. In particular, our proof in this case does not depend on the use of the Langlands–Tunnell theorem. This is in contrast to the argument used in e.g. [SBT97, Theorem 4.1] to establish the automorphy of representations with cyclotomic determinant.
This ‘2-3 switch’ strategy can also be used to prove the automorphy of representations with totally odd using the 2-adic automorphy theorems proved in [All14], see Theorem 3.1 of the text. This class of representations includes the projective representations associated to the Galois action on the 3-torsion points of an elliptic curve over . This gives a way to verify the modulo 3 residual automorphy of elliptic curves over which does not rely on the Langlands–Tunnell theorem (and in particular the works [Lan80, JPSS81]) but only on the Saito–Shintani lifting for holomorphic Hilbert modular forms [Sai75]. (We note that we do need to use the Langlands-Tunnell theorem to prove the automorphy of representations with totally even, cf. Theorem 2.12.)
We now describe the structure of this note. We begin in §2 by studying the lifts of projective representations and collecting various results about the existence of characteristic 0 lifts of residual representations and their automorphy. We are then able to give the proofs of Theorem 1.1 and the first two cases in the proof of Theorem 1.2 described above. In §3, we expand on Remark 1.3 by showing how the main theorems of [All14] can be used to give another proof of the automorphy of -type representations (still under the hypothesis that is totally real and is totally odd). Finally, in §4 we use similar arguments, now based on the main theorems of [AKT], to complete the proof of Theorem 1.2.
Acknowledgments
We would like to thank the anonymous referee for their comments and corrections. P.A. was supported by Simons Foundation Collaboration Grant 527275 and NSF grant DMS-1902155. He would like to thank the third author and Cambridge University for hospitality during a visit where some of this work was completed. Parts of this work were completed while P.A. was a visitor at the Institute for Advanced Study, where he was partially supported by the NSF. He would like to thank the IAS for providing excellent working conditions during his stay. J.T.’s work received funding from the European Research Council (ERC) under the European Union’s Horizon 2020 research and innovation programme (grant agreement No 714405). This research was begun during the period that J.T. served as a Clay Research Fellow.
1.1 Notation
If is a perfect field then we write for the Galois group of with respect to a fixed choice of algebraic closure. If is a number field and is a place of then we write for the completion of at , and fix an embedding extending the natural embedding ; this determines an injective homomorphism . If is a finite place of then we write for a lift of the geometric Frobenius, for the residue field of , and for the cardinality of ; if is a real place, then we write for complex conjugation. Any homomorphism from a Galois group to another topological group will be assumed to be continuous.
If is a prime and is a field of characteristic 0, then we write for the -adic cyclotomic character, for its reduction modulo , and for the character . More generally, if is a representation, then we write for the associated semisimple residual representation (uniquely determined up to conjugation).
If is a field then we write for the natural projection and for the character induced by the determinant. We will only use these maps in the case .
If is a field of characteristic 0, is an elliptic curve curve over , and is a prime, then we write for the representation associated to after a choice of basis. Thus .
2 Lifting representations
In this section we study different kinds of liftings of representations: liftings to characteristic 0 (and the automorphy of such liftings) and liftings of projective representations to true (linear) representations. We begin by discussing what it means for a (projective or linear) representation to be automorphic.
2.1 Automorphy of linear and projective representations
Let be a CM or totally real number field. If is a cuspidal, regular algebraic automorphic representation of then (see e.g. [Tay89, HLTT16]) for any isomorphism , there exists a semisimple representation satisfying the following condition, which determines uniquely up to conjugation: for all but finitely many finite places of such that is unramified, is unramified and is related to the representation under the Tate-normalised unramified local Langlands correspondence. (See [Tho16, §2] for an explanation of how the characterstic polynomial of may be expressed in terms of the eigenvalues explicit unramified Hecke operators.) In this paper we only need to consider automorphic representations which are of regular algebraic automorphic representations which are of weight 0, in the sense that for each place of , has the same infinitesimal character as the trivial representation.
Let be a finite field of characteristic , viewed inside its algebraic closure . In this paper, we say that a representation is automorphic if it is -conjugate to a representation of the form , where is a cuspidal, regular algebraic automorphic representation of of weight 0. We say that a representation is automorphic if it is -conjugate to a representation of the form , where is a cuspidal, regular algebraic automorphic representation of of weight 0.
We say that a representation is automorphic if it is conjugate to a representation of the form , where is a cuspidal, regular algebraic automorphic representation of of weight 0. We say that an elliptic curve over is modular if the representation of afforded by is automorphic in this sense.
Lemma 2.1.
Let be a CM or totally real number field, let be a representation, and let . Then:
-
1.
Let be a character. Then is automorphic if and only if is automorphic.
-
2.
is automorphic if and only if is automorphic.
Proof.
If is a character then its Teichmüller lift is associated, by class field theory, to a finite order Hecke character . If is a cuspidal automorphic representation which is regular algebraic of weight 0 and is conjugate to , then is also cuspidal and regular algebraic of weight 0 and is conjugate to .
It is clear from the definition that if is automorphic then so is . Conversely, if is automorphic then there is a cuspidal, regular algebraic automorphic representation of and isomorphism such that . It follows that there exists a character such that is conjugate to . The automorphy of follows from the first part of the lemma. ∎
2.2 Lifting to characteristic 0
We recall a result on the existence of liftings with prescribed properties. We first need to say what it means for a representation to be exceptional. If is a number field and is a projective representation, we say that is exceptional if it is -conjugate to a representation such that contains and the character is trivial. (Here we write for the composition of with the unique isomorphism .) We say that a representation is exceptional if is exceptional. If is totally real then this is equivalent to the definition given in [KT17, §3]. The exceptional case is often excluded in the statements of automorphy lifting theorems (the root cause being the non-triviality of the group ).
Theorem 2.2.
Let be a totally real field, let be a representation of -type, and let be a continuous character lifting such that is of finite order. Suppose that the following conditions are satisfied:
-
1.
and is absolutely irreducible.
-
2.
If then is non-exceptional.
Then lifts to a continuous representation satisfying the following conditions:
-
1.
For all but finitely many places of , is unramified.
-
2.
.
-
3.
For each place of , is potentially crystalline and for each embedding , . Moreover, for any such that is reducible, we can assume that is ordinary, in the sense of [Tho16, §5.1].
Proof.
This follows from [Sno09, Theorem 7.6.1], on noting that the condition (A2) there can be replaced by the more general condition that is non-exceptional (indeed, the condition (A2) is used to invoke [Kis09, Proposition 3.2.5], which is proved under this more general condition). To verify the existence of a potentially crystalline lift of for each (or in the terminology of loc. cit., the compatibility of with type or ) we apply [Sno09, Proposition 7.8.1] (when is irreducible) or [BLGG12, Lemma 6.1.6] (when is reducible). ∎
We next recall an automorphy lifting theorem.
Theorem 2.3.
Let be a totally real number field, and let be a continuous representation satisfying the following conditions:
-
1.
and is absolutely irreducible.
-
2.
For all but finitely many finite places of , is unramified.
-
3.
For each place of , is de Rham and for each embedding , .
-
4.
The representation is automorphic.
Then is automorphic.
Proof.
This follows from [KT17, Theorem 9.3]. ∎
We now combine the previous two theorems to obtain a “solvable descent of automorphy” theorem for residual representations, along similar lines to [Kha00, Tay03].
Proposition 2.4.
Let be a totally real number field and let be a representation of -type. Suppose that there exists a solvable totally real extension such that the following conditions are satisfied:
-
1.
and is absolutely irreducible. If , then is non-exceptional.
-
2.
is automorphic.
Then is automorphic.
Proof.
We can now give the proof of Theorem 1.1, which we restate here for the convenience of the reader:
Theorem 2.5.
Let be a totally real field and let be a representation of -type. Suppose that . Then is automorphic.
Proof.
Many of the results we quote here are stated in the case of but hold more generally for totally real fields with minor modification. We will apply them in the more general setting without further comment.
If is dihedral then this is a consequence of results of Hecke (see [Ser87, §5.1]). If , it is a consequence of the Langlands–Tunnell theorem [Tun81] (see the discussion following Theorem 5.1 in [Wil95, Chapter 5]). We may thus assume for the remainder of the proof that . We may also assume that for any abelian extension , the restriction is absolutely irreducible (as otherwise would be dihedral).
Next suppose that . We note that is not exceptional, by [KT17, Lemma 3.1]. Let be the totally real cyclic extension cut out by . By [SBT97, Theorem 1.2], there is an elliptic curve over such that and contains . By the case of the theorem and by Theorem 2.3, we see that is automorphic, hence so is . The automorphy of then follows from Proposition 2.4. The case is similar, using [Man04, Proposition 3.1] instead of [SBT97, Theorem 1.2].
Next suppose that . We can twist to assume that it is valued in . Then [SBT97, Theorem 3.4] shows that there is an abelian surface over with real multiplication by such that the -representation on is isomorphic to and such that the -representation on has image containing . By the case of the theorem, Theorem 2.2, and Theorem 2.3, we see that is automorphic, hence so is .
Finally suppose that . Let be the totally real cyclic extension cut out by . Then the argument of [Ell05, §2.5] shows that there is a solvable totally real extension containing and an abelian surface over with real multiplication by such that the -representation on is isomorphic to and such that the -representation on has image containing . By the case of the theorem, Theorem 2.2, and Theorem 2.3, we see that is automorphic, hence so is . The automorphy of follows from Proposition 2.4. ∎
Remark 2.6.
The ‘2-3 switch’ strategy employed in Theorem 3.1 below, can be used to prove automorphy of totally odd representations without using the Langlands-Tunnell theorem.
2.3 Lifting projective representations
We now consider the problem of lifting projective representations.
Lemma 2.7.
Let be a number field, and let be a continuous homomorphism. Then there exists a finite extension such that lifts to a homomorphism .
Proof.
The obstruction to lifting a continuous homomorphism to a continuous homomorphism lies in . Tate proved that (see [Ser77, §6.5]) so a lift always exists. ∎
Lemma 2.8.
Suppose that , let be a number field, and let be a homomorphism. Let be a finite set of places of such that for each , there exists a lift of to a homomorphism . Then we can find the following data:
-
1.
A solvable -split extension .
-
2.
A homomorphism such that and for each and each place of , .
Moreover, if is a CM field we can choose also to be a CM field.
Proof.
Let denote the -Sylow subgroup of , of order , and let denote its prime-to-2 complement. If , we write , which is an extension
We show by induction on that we can find a solvable, -split extension and a homomorphism lifting and such that for each and each place of , . The case is the existence of . The case implies the statement of the lemma, since . (Note [AT09, Ch. X, Theorem 5] implies that any collection of characters can be globalised to a character .)
For the induction step, suppose the induction hypothesis holds for a fixed value of . We consider the obstruction to lifting to a homomorphism . This defines an element of which is locally trivial at the places of lying above . We can therefore find an extension of the form , where is a solvable -split extension, such that the image of this obstruction class in vanishes and so there is a homomorphism lifting .
If and is a place of then there is a character such that . We can certainly find a character such that for each such place . The induction step is complete on taking .
It remains to explain why we can choose to be CM if is. Since the extensions in the proof are required only to satisfy some local conditions, which are vacuous if is CM, we can choose the fields to be of the form where is a totally real extension, in which case the field constructed in the proof is seen to be CM. ∎
Remark 2.9.
We remark that if is a real place of and , then there exists a lift of to if and only if either is a square in and , or is not a square in and . We also note the utility of the ‘-split’ condition: we can add any set of places at which is unramified to , and in this way ensure that the -split extension is linearly disjoint from any other fixed finite extension of .
Here is a variant.
Lemma 2.10.
Suppose that . Let be a number field, let be a homomorphism, and let be a character. Suppose that the following conditions are satisfied:
-
1.
.
-
2.
For each finite place of , and are unramified.
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3.
For each real place of , and .
Then there exists a homomorphism such that and .
Proof.
We consider the short exact sequence of groups
where the last group is the subgroup of such that . By hypothesis the pair defines a homomorphism such that for every place of , lifts to (see Remark 2.9). The subgroup of locally trivial elements of is trivial, by class field theory, so lifts to a homomorphism , as required. ∎
We now prove an analogue of Proposition 2.4 for projective representations.
Proposition 2.11.
Let be a totally real number field and let be a representation of -type. Suppose that there exists a solvable totally real extension satisfying the following conditions:
-
1.
and is absolutely irreducible. If , then is non-exceptional.
-
2.
is automorphic.
Then is automorphic.
Proof.
We are now in a position to establish a large part of Theorem 1.2.
Theorem 2.12.
Let be a totally real number field and let be a representation of -type. If one of the following conditions holds, then is automorphic:
-
1.
.
-
2.
or and is totally even. If , then is non-exceptional.
-
3.
and is totally odd.
Proof.
When or , the map is an isomorphism, so trivially lifts to a representation and we can apply Theorem 2.5. The case when follows from [Tun81]. In the other cases, we can assume that is absolutely irreducible (as otherwise lifts to a dihedral representation). Let be the set of infinite places of and choose a finite set of finite places of at which is unramified such that is generated by . We can apply Lemma 2.8, see also Remark 2.9, with to find a solvable, totally real extension such that lifts to a representation such that is absolutely irreducible and is not exceptional if . Then Theorem 2.5 implies the automorphy of and Proposition 2.11 implies the automorphy of , as desired. ∎
3 Modularity of mod representations
In this section, which is a warm-up for the next one, we give a proof of the following theorem that does not depend on the Langlands–Tunnell theorem:
Theorem 3.1.
Let be a totally real number field, and let be a representation of -type such that is totally odd. Then is automorphic.
Proof.
We can assume that is not dihedral; by the classification of finite subgroups of , we can therefore assume that contains . By Proposition 2.11, we can moreover assume, after replacing by a solvable totally real extension, that is everywhere unramified and that for each place of , and is trivial.
Lemma 3.2.
There exists a solvable totally real extension and a modular elliptic curve over satisfying the following conditions:
-
1.
contains . In particular, is of -type.
-
2.
The homomorphism is -conjugate to .
Proof.
The character is totally even, so cuts out a totally real (trivial or quadratic) extension , and contains and satisfies . Using Lemma 2.10, we can find a lift of satisfying the following conditions:
-
•
.
-
•
For each place of , is trivial.
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•
contains . In particular, is absolutely irreducible.
We can then apply [AKT, Lemma 9.7] to conclude that there exists an elliptic curve satisfying the following conditions:
-
•
There is an isomorphism .
-
•
For each place of , has multiplicative reduction at and the valuation at of the minimal discriminant of is 3.
-
•
.
Then [All14, p. 1237, Corollary] implies that is modular, proving the lemma. ∎
We see that is automorphic. We can then apply Proposition 2.11 to conclude that itself is automorphic, as required. ∎
4 Modularity of mod representations
Theorem 4.1.
Let be a totally real field, and let be a representation of -type which is non-exceptional, and such that is totally odd. Then is automorphic.
Proof.
By the classification of subgroups of , automorphic induction, and the Langlands–Tunnell theorem, we can assume that contains . By Theorem 2.2, Lemma 2.7, and Proposition 2.11 we can assume, after possibly replacing be a solvable totally real extension, that the following conditions are satisfied:
-
•
There exists a representation such that is -conjugate to . Moreover, is everywhere unramified.
-
•
There exists a representation lifting , which is unramified almost everywhere.
-
•
For each place of , , is trivial, and is ordinary, in the sense of [Tho16, §5.1].
-
•
Let . Then has finite order prime to and for each finite place of , is unramified. In particular, is everywhere unramified.
Let denote the quadratic CM extension cut out by the character .
Lemma 4.2.
The representation is decomposed generic in the sense of [ACC+, Definition 4.3.1].
Proof.
It is enough to find a prime number such that splits in and for each place of , and the eigenvalues of are distinct. The argument of [ACC+, Lemma 7.1.5, (3)] will imply the existence of such a prime if we can show that if and is the Galois closure of , then contains . To see this, first let be the Galois closure of . Then is totally real, and so because is totally odd. The extension is abelian, so is abelian and must contain . ∎
By construction, , so by Lemma 2.10, lifts to a continuous homomorphism such that . In particular, there is a character such that . Let denote the Teichmüller lift of ; then the determinant of equals .
Lemma 4.3.
The representation satisfies the following conditions:
-
1.
is absolutely irreducible and is non-exceptional.
-
2.
is decomposed generic.
Proof.
The representation is absolutely irreducible because its projective image contains . If then and so ; this possibility is ruled out because is non-exceptional. It follows that is non-exceptional. The representation is decomposed generic because is (and this condition only depends on the associated projective representation). ∎
Thanks to the lemma, we can apply [AKT, Lemma 9.7] and [AKT, Corollary 9.13] to conclude the existence of a modular elliptic curve over such that and for each place of , has multiplicative reduction at the place . We can then apply the automorphy lifting theorem [AKT, Theorem 8.1] to conclude that is automorphic, hence that is automorphic. It follows by cyclic descent [Lan80] that and hence are also automorphic, and this completes the proof. ∎
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