Maps preserving the local spectral subspace of skew-product of operators
Abstract Let be the algebra of all bounded linear operators on an infinite-dimensional complex Hilbert space . For and , let denotes the local spectral subspace of associated with . We prove that if be an additive map such that its range contains all operators of rank at most two and satisfies
for all and , then there exist a unitary operator in and a nonzero scalar such that for all . We also show if and be additive maps from into such that their ranges contain all operators of rank at most two and satisfies
for all and . Then is invertible, and and for all .
Mathematics Subject Classification: Primary 47B11: Secondary 47A15, 47B48.
Keywords: Local spectrum, Local spectral subspace, Nonlinear preservers, Rank-one operators.
1 Introduction
Throughout this paper, and are infinite-dimensional complex Hilbert
spaces. As usual denotes the space of all bounded linear operators from
into . When we simply write instead of , and its unit will be denoted by . The inner
product of or will be denoted by if there is no confusion. For an operator , let denote as usual its adjoint. A preserver problem generally deals with characterizing those maps on some specific algebraic structures which preserve a particular subset, property or relation. This subject has a long history and its origins goes back well over a century to the
so-called first linear preserver problem, due to Frobenius [11], that determines linear
maps preserving the determinant of matrices. As we mentioned earlier, the main of this subject goal is to describe the general form of linear maps between two Banach algebras which preserve a certain property, or a certain class of elements,
or a certain relation. One of the most famous related problems is Kaplansky’s problem
[17] asking whether every surjective unital invertibility preserving linear map between two semisimple
Banach algebras is a Jordan homomorphism.
His question was motivated by two classical results, the result of Marcus and Moyls [18] on linear maps preserving eigenvalues of matrices and the Gleason-Kahane-Zelazko theorem [15, 16] stating that every unital invertibility preserving linear functional on a unital complex Banach algebra is necessarily multiplicative. The later this result was obtained independently by Gleason in [15] and Kahane-Zelazko in [16], and was refined by Zelazko in [23]. In the non-commutative case,
the best known result so far are due to Sourour [22]. He answered to the
Kaplansky’s question in the affirmative for bijective unital
linear invertibility preserving maps acting on the algebra of all bounded operators on a Banach
space. Note that when the maps are unital, then preserving invertibility is equivalent to preserving spectrum. These results opened the gate for many authors who investigate linear (or additive) maps preserving spectrum; see for instance [1, 12, 13] and the references therein. Along this line, Molnar [19] investigated maps preserving the spectrum of operator
products without assuming linearity or additivity.
The local resolvent set, , of an operator at a point is the union of all open subsets of the complex plane for which there is an analytic function such that for all . The complement of local resolvent set is called the local spectrum of at , denoted by , and is obviously a closed subset (possibly empty) of , the spectrum of . We recall that an operator is said to have the single-valued extension property (henceforth abbreviated to SVEP) if, for every open subset of , there exists no nonzero analytic solution, , of the equation
Every operator for which the interior of its point spectrum,
, is empty enjoys this property.
For every subset the local spectral subspace is defined by
Clearly, if then . For more information about these notions one may see the books [2, 20].
The study of linear and nonlinear local spectra preserver problems attracted the attention of a number of authors. Bourhim and Ransford were the first ones to consider this type of preserver problem, characterizing in [8] additive maps on , the algebra of all linear bounded operators on infinite-dimensional complex Banach space , that preserves the local spectrum of operators at each vector of . Their results motivated several authors to describe maps on matrices or operators that preserve local spectrum, local spectral radius, and local inner spectral radius; see, for instance, the last section of the survey article [5] and the references therein. Based on the results from the theory of linear preservers proved by Jafarian and Sourour [14], Dolinar et al. [9], characterised the form of maps preserving the lattice of sum of operators. They showed that the map (not necessarily linear) satisfies LatLat for all , if and only if there are a non zero scalar and a map such that for all (See [9, Theorem 1]), where is the complex field or the real field and Lat is denoted the lattice of , that is, the set of all invariant subspaces of . They proved also, in the same paper, that a not necessarily linear maps satisfies Lat Lat (resp. Lat Lat, resp. Lat Lat) for all , if and only if there is a map such that if and for all (See [9, Theorem 2]).
For a Banach space , it is well-known that , the local spectral subspace of associated with a subset of , is an element of , so one can replace the lattice preserving property by the local spectral subspace preserving property. In [10], the authors described additive maps on that preserve the local spectral subspace of operators associated with any singleton. More precisely, they proved that the only additive map on for which for all and , is the identity. In [4], Benbouziane et al. characterized the forms of surjective weakly continuous maps from into which satisfy
Afterwards, in [3], the authors studied surjective maps that preserve the local spectral subspace of the sum of two operators associated with non-fixed singletons. In other words, they characterized surjective maps on which satisfy
They also gave a characterization of maps on that preserve the local spectral subspace of the difference of operators associated with non-fixed singletons. Furthermore, they investigated the product case as well as the triple product case. Namely, they described surjective maps on satisfying
and also surjective maps on satisfying
Bourhim and Lee [6] investigated the form of all maps and on such that, for every and in , the local spectra of and are the same at a nonzero fixed vector . In this paper, We show that if is an additive map such that its range contains all operators of rank at most two and satisfies
then there exist a unitary operator in and a nonzero scalar such that for all . We also investigate the form of all maps and on such that, for every and in , the local spectral subspaces of and , associated with the singleton , coincide.
2 Preliminaries
The first lemma summarizes some known basic and properties of the local spectrum.
Lemma 2.1.
In the next theorem we collect some of the basic properties of the subspaces .
Lemma 2.2.
For a nonzero and , we use a useful notation defined by Bourhim and Mashreghi in [7]:
For two nonzero vectors and in , let stands for the operator of rank at most one defined by
Note that every rank one operator in can be written in this form,
and that every finite rank operator can be written as a finite
sum of rank one operators; i.e., for some and . By and , we mean the set of all finite rank operators in . and the set of all operators of rank at most , is a positive integer, respectively.
The following lemma is an elementary observation which discribes the nonzero local spectrum of any rank one operator.
Lemma 2.3.
(See [7, Lemma 2.2].) Let be a nonzero vector in . For every vectors , we have
The following theorem, which may be of independent interest, gives a spectral characterization of rank one operators in term of local spectrum.
Theorem 2.4.
(See [7, Theorem 4.1].)
For a nonzero vector and
a nonzero operator the following statements are equivalent.
(a) has rank one.
(b) contains at most one element for all .
(c) contains at most one element for all .
The following Lemma is a key tool for the proofs in the sequel.
Lemma 2.5.
(See [3, Lemma 1.6].) Let be a nonzero vector in and . If for all . Then, if and only if for all .
Moreover, this theorem will be useful in the proofs of our main result.
Theorem 2.6.
(See [3, Theorem 2.1].)
Let . The following statements are equivalent.
.
for all
and .
The next theorem describes additive maps on that preserve the local spectral subspace of operators associated with any singleton.
Theorem 2.7.
(See [10, Theorem 2.1].) Let be an additive map such that for all and . Then for all .
The following theorem will be useful in the sequel. We recall that if is a ring homomorphism, then an additive map satisfying is called an -quasilinear operator.
Theorem 2.8.
(See [21, Theorem 3.3].) Let be a bijective additive map preserving rank one operators in both directions. Then there exist a ring automorphism , and either there are -quasilinear bijective maps and such that
or there are -quasilinear bijective maps and such that
Note that, if in Theorem 2.8 the map is linear, then is the identity map on and so the maps and are linear.
3 Main Results
The following theorem is the first main result of this paper, which characterizes those maps preserving the local spectral subspace of skew-product operators.
Theorem 3.1.
Let be an additive map such that its range contains . If
(1) |
then there exist a unitary operator in and a nonzero scalar such that for all .
Proof.
The proof breaks down into several claims.
Claim 1. is injective.
If for some , we get that
for all and . By Theorem 2.6, we see that and hence is injective.
Claim 2. preserves rank one operators in both directions.
Let be a rank one operator where . Note that, , since and is injective. Let be an arbitrary operator. Since and has the SVEP, then . We have
As the range of contains , using Lemma 2.5, contains at most one element for all operators . By Theorem 2.4, we see that has rank one. The converse holds in a similar way and thus preserves the rank
one operators in both directions.
Claim 3. is linear.
We show that is homogeneous. Let be an arbitrary rank-one operator. By the previous claim, there exists a rank one operator in such that . For every with and , we have
By Theorem 2.6, we see that .
Since is assumed to be additive, the map is, in fact, linear.
Claim 4. There are bijective linear mappings and
such that for all .
By the previous claim is a bijective linear map from onto and preserves rank one operators in both directions, thus by Theorem 2.8, either there are bijective linear mappings and such that
(2) |
or there are bijective linear mappings and such that
(3) |
Assume that takes the form . Let be a nonzero vector in . Choose a nonzero vector such that . Set , since and are nonzero vectors in , there exists a such that and , since is idempotent, we have
On the other hand, since , we have and consequently . This implies that
Using Lemma 2.5, . But lemma 2.3 implies that
This contradiction shows that only takes the form .
Claim 5. and are bounded unitary operators multiplied by positive scalars and such that .
Let be nonzero vectors in , since , by the previous claim, we have
By the Lemma 2.5, we see that
(4) |
Now, let be a fixed unit vector in and let . By , we have
for all . Hence, is an isometry and thus it is a unitary operator in , because is bijective. Similarly, fix a unit vector and take , and note that is a unitary operator in . Finally, by , we see that .
Claim 6. and are linearly dependent.
Assume, by the way of contradiction, that there exists a nonzero vector such that and are linearly independent. Let be a vector such that and . Since , then
using Lemma 2.5, we have
This contradiction shows that there is a nonzero scalar such that
.
Claim 7. for all , where is unitary operators and is a nonzero scalar.
By claim 5 we shall assume that and for some unitary operators . Using the previous claim and , for every rank one operator and every operator we have
Since preserves rank one operators in both directions, Theorem 2.6 shows that for all . Claim 6 tells us that for ever we have for some . ∎
From this result, it is easy to deduce a generalization for the case of two different Hilbert spaces .
Corollary 3.2.
Suppose be a unitary operator. Let be an additive map from into such that its range contains . If
Then there exist a unitary operator and a nonzero scalar such that for all .
Proof.
We consider the map defined by for all . We have,
for every and . So by Theorem 3.1, there exist a unitary operator and such that for all . Therefore for all , where . ∎
In the next theorem, we investigate the form of all maps and on such that, for every and in , the local spectral subspaces of and , associated with the singleton , coincide.
Theorem 3.3.
Let and be additive maps from into which satisfy
(5) |
If the range of and contain , then is invertible, and and for all .
Proof.
The proof is rather long and we break it into several claims.
Claim 1. is a one to one linear map preserving rank one
operators in both directions.
Similar to the proof of Theorem 3.1, we can shows that is a one to one linear map preserving rank one
operators in both directions.
Claim 2. There are bijective linear mappings and
such that for all .
By the claim 1 is a bijective linear map which preserves
rank one operators in both directions. Thus by Theorem 2.8, has one of the following forms.
There exist bijective linear
maps and such that
(6) |
There exist bijective linear maps and such that
(7) |
Assume that takes the form . Let be a nonzero vector in , choose a nonzero vector such that . Set , since and are nonzero vectors in , there exists a vector such that and . Since , we have
Using Lemma 2.5, . But lemma 2.3 implies that
This contradiction shows that only takes the form .
Claim 3. For every , .
Assume that and are arbitrary vectors in . We have, , so the previous claim and imply that
Assume first that , using lemma 2.5,
which means that . Then Lemma 2.3 implies that
Now, if , we choose a vector such that . By application of what has been shown previously to both and , we have and . So
This shows that in this case too.
Claim 4. is invertible.
It is clear that is injective, if not, there is a nonzero vector such that . Take , and let be a vector such that . By the previous claim, we have . This contradiction tells us that is injective. Now, we show that is continuous and . Assume that is a sequence in such that and . Then, for every , we have
Since is bijective and is an arbitrary vector, the closed graph theorem shows
that is continuous. Moreover, we have
for all , and thus .
It follows that is invertible.
Claim 5. and are linearly dependent.
Assume, by the way of contradiction, that there exists a nonzero vector such that and are linearly independent. Let be a vector in such that and . We have and , then and . Since , using Lemma 2.5 and claim 2, we have
This contradiction shows that there is a nonzero scalar such that
.
Claim 6. and have the desired forms.
We define the map by for all . We have,
for all and . So by Theorem 2.7, for all , therefore for all . Once again, we consider the map defined by for all . We see that for all and ,
by Theorem 2.7, for all . Hence for all . ∎
Theorem 3.3 leads directly to the following corollary.
Corollary 3.4.
Suppose be a unitary operator. Let and be two additive map from into which satisfy
If the range of and contain , then there exists a bijective linear map such that and for all .
Proof.
We consider the maps defined by and defined by for all . We have,
for every and . So by Theorem 3.3, and for all , where . Therefore and for all , where . ∎
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