Locally closed sets and submaximal spaces
Abstract.
A topological space is called submaximal if every dense subset of is open. In this paper, we show that if , the Stone-Čech compactification of , is a submaximal space, then is a compact space and hence . We also prove that if , the Hewitt realcompactification of , is submaximal and first countable and is without isolated point, then is realcompact and hence . We observe that every submaximal Hausdorff space is pseudo-finite. It turns out that if is a submaximal space, then is a pseudo-finite -compact space. An example is given which shows that may be submaximal but may not be submaximal. Given a topological space , the collection of all locally closed subsets of forms a base for a topology on which is denotes by . We study some topological properties between and , such as we show that a) is discrete if and only if is a -space; b) is a locally indiscrete space if and only if ; c) is indiscrete space if and only if is connected. We see that, in locally indiscrete spaces, the concepts of , , , , submaximal and discrete coincide. Finally, we prove that every clopen subspace of an lc-compact space is lc-compact.
Key words and phrases:
locally closed set, locally indiscrete space, -space, submaximal space, Stone-Čech compactification, Hewitt realcompactification.2010 Mathematics Subject Classification:
54G99, 54G05, 54G10, 54C301. Introduction
Throughout this paper we consider topological spaces on which no separation axioms are assumed unless explicity stated. The topology of a space is denoted by and will be replaced by if there is no chance for confusion. For a subset of , the closure, the interior, the boundary and the set of accumulation points of are denoted by or , or , or and , respectively. In places where there is no chance for confusion and stands for and , respectively. If be open, closed or locally closed respect to the topology on , then we write sometimes to avoid confusion, -open, -closed or -locally closed, respectively. A subset of a topological space is called locally closed if for every there is an open set such that and is closed in . Since the intersection of two locally closed sets is locally closed, the family of -locally closed sets forms a base for a finer topology on . For a Tychonoff (completely regular Hausdorff) space , is the Stone-Čech compactification and is the Hewitt realcompactification of . It is well known that is compact, pseudocompact or realcompact if and only if , or , respectively. For a Tychonoff space the symbol (resp. ) denotes the ring of all continuous real valued (resp. all bounded continuous real valued) functions defined on . We say that a subspace of is -embedded in if every function in can be extended to a function in . For , the zero-set of is the set . The set-theoretic complement of is denoted by . The support of a function is the . For any , the maximal ideal (resp. the ideal ) is the set of all for which (resp. ). More generally, for , (resp. ) is the intersection of all (resp. ) with . It is clear that .
A space is said to be a, a) door space if every set is either open or closed; b) -space if every singleton is either open or closed; c) submaximal space if every dense subset is open; d) principal space, if every intersection of open sets is open, e) -principal space, if every countable intersection of open sets (i.e., -set) is open, f) resolvable space if it has two disjoint dense subsets.
Tychonoff -principal spaces are the same -spaces, see Exercise 4J of [12]. A door space is submaximal and a submaximal space is . The one-point compactification of any discrete space is submaximal. A nonempty resolvable space never submaximal. For example, and are resolvable spaces. For more information about the locally closed sets, see [2, 8, 11], about the submaximal spaces, see [2, 8, 7, 1], about the door spaces, see [7, 9] and about the -spaces, see [3]. For details about and , see [12, 18] and about other concepts of general topology, see [10, 19].
Section 2, of this paper is devoted to investigate some separation properties between and . Such as we show that is discrete if and only if is a -space. We show that, in this section, if is submaximal, then is compact and therefor, in this case, we conclude that . We also prove that if is submaximal and first countable and is without isolated point, then is realcompact. We observe that every submaximal Hausdorff space is pseudo-finite. It turns out that if is a submaximal space, then is a pseudo-finite -compact space. In Section 3, we study and investigate the behavior locally indiscrete spaces. We observe that is a locally indiscrete space if and only if if and only if every dense open subset of is regular open. In Section 4, we introduce some lc-properties such as lc-regular and lc-completely regular and compare them with the concepts regular and completely regular. We prove that every clopen subset of a lc-compact space is lc-compact.
2. Locally closed sets and -topology
A space is called a -space if every singleton is locally closed. It is well known that the space is submaximal if and only if every subset of is locally closed, see Theorem 4.2 of [8] and also every subspace of a submaximal space is submaximal, see Theorem 1.1 of [8].
The proof of the following proposition is straightforward.
Proposition 2.1.
The following statements are equivalent, for a subset of the space .
a) is a locally closed set.
b) , which is open and is closed.
c) , which is open.
d) , which and are closed.
e) is a closed set.
f) .
g) is an open set.
Remark 2.2.
a) Every closed (resp. open) set is locally closed.
b) Every dense locally closed set is open.
c) The intersection of finite number locally closed sets is locally closed.
d) Every intersection of locally closed sets may not be locally closed.
e) The complement of a locally closed set need not be locally closed. For example, is a locally closed set in while is not locally closed.
f) The union of two locally closed sets need not be locally closed. For example, suppose that and in . Then is not locally closed.
g) The union of two completely separated locally closed sets is locally closed.
h) If is preopen, (that is, ) then it is open if and only if it is locally closed.
i) If is open, where is locally closed, then is open.
j) If is locally closed and is clopen, then is locally closed.
k) If and are locally closed, then the equal may not be true. For example, let and . Now suppose that and .
l) Let be a topological space and a subspace of . The set is locally closed in if and only if , where is locally closed in .
m) In a locally compact Hausdorff space, any subset is locally closed if and only if it is a locally compact set, see Theorem 18.4 of [19] or Corollary 3.3.10 of [10].
n) Let are topological spaces, the continuous mapping is one-to-one and let the one element family separates points and closed sets. If is a -space and is open subset of , then is a -space, see Lemma 2.3.19 of [10].
o) A locally closed set of is dense in if and only if there is an open set of such that is dense in .
p) Every discrete subset of a -space is locally closed.
q) is locally closed in if and only if it is locally closed in .
Given a topological space , the collection of all locally closed subsets of forms a base for a topology on which is denotes by . It is clear that and in locally indiscrete spaces we have , see Proposition 3.4. In the sequel, we study some topological properties between and .
Proposition 2.3.
is indiscrete if and only if is a connected space.
Proof.
Let and let . Clearly and and therefore is disconnected.
Suppose that , which and are two nonempty disjoint -open sets and let . Hence there is a -locally closed set such that . Therefor , where . If , then we are done. Assume that . This implies that , that is, is a -open. Since , we infer that . Now if , then which is not true. Consequently, is a -open set. This complete the proof.
∎
Proposition 2.4.
is a -space if and only if is a -space.
Proof.
It is trivial.
Let and . Hence there is such that and . Let be -locally closed set such that . Therefor , where . If , then we are done. If , then . Otherwise and so which is not true. Thus there is such that and . This consequence that and this complete the proof.
∎
If is a -space then is discrete. The converse is not true. For example, let and . For the converse see the next proposition.
Proposition 2.5.
is a -space if and only if is discrete.
Proof.
It is trivial.
Let . Hence , and therefore there is a -locally closed set such that . It implies that , i.e., is a -space.
∎
Remark 2.6.
Every -space is . The converse is false. For example, we consider the topology on .
If be the principal topology on , then every element has a minimal open neighborhood . For details about principal topology, see [17].
Lemma 2.7.
Every principal -space is .
Proof.
Suppose that . If , then we are done. Hence, assume that . Since there is no an open set such that and we infer that there is an open set such that and . Now let be the minimal open neighborhood of . We claim that . Assume that . We show that . If not, then two cases occur. In the first case, there is an open set such that and , which is not true, for . In the second case, there is an open set such that and . Now since , we conclude that which is not true. Consequently, and this implies that is locally closed set. ∎
Remark 2.8.
a) If is a principal space, then every intersection of locally closed sets is locally closed.
b) If is a principal space, then is principal. The converse is false. For example, is principal but , where denotes usual topology on , is not principal.
Example 2.9.
A continuous image of a -space need not be -space. Let with usual topology and with , where on . We define by . Then is a one-to-one and onto which is continuous. To prove continuity, suppose that be open and , where . There is such that and . We put , where . It is clear that . Note that is a -space while is not a -space.
If is a -space, then is a -space for each . The converse is true if is finite. In the next example we see that an arbitrary product of -spaces need not be .
Example 2.10.
Let and , for any and let . Suppose that , where for every . It is clear that belongs to every nonempty open set in . We claim that is not a locally closed set. Otherwise, there is an open set and a closed set such that . If , then which is not true. If , then . But , where , for every , which is finite and this is impossible. It is consequence that is not locally closed.
Lemma 2.11.
is a -principal space if and only if all but finitely many of the are trivial spaces.
Proof.
It is straightforward. ∎
In the sequel, by we mean the cardinality of for every set .
Remark 2.12.
Let be a -principal space and . Then is a -space if and only if each factor space is a -space, see part (b) of Exercise 2.3.B of [10].
Every -space is . The converse is not true. For example, let and , where , for any . Since , we infer that is a -space. It is clear that the set neither open nor closed, so is not a -space.
Recall that union of two locally closed sets may not be locally closed. In the next example, we see that even if we add a cluster point to a locally closed set, the resulting set may not be locally closed. In other words, if is locally closed and , then need not be locally closed.
Example 2.13.
Suppose that , and for any , let . We consider and we put . Then is closed and hence is locally closed in . Now assume that . Clearly, . Note that is not closed set in and hence is not locally closed.
Example 2.14.
An arbitrary product of Tychonoff, compact and submaximal spaces need not be submaximal. For example, assume that be a one-point compactification of a discrete space , for every . Suppose that and suppose that , then is dense in which is not open.
Proposition 2.15.
Let be a submaximal space and with . Then is discrete.
Proof.
Suppose that . Hence is locally closed in . Therefor there is an open set in such that . Let be open in such that . Note that . This implies that . Similarly, there is an open set in such that . Now . This consequence that is an isolated point of . ∎
If is a submaximal space and , then is a discrete subset of . Also if is a submaximal space and is a discrete subset of , then is discrete and if in addition is a -space, then is discrete.
Theorem 2.16.
If is a submaximal space, then is compact. In this case .
Proof.
Since is countably compact, by Theorem 4.20 of [1], is a finite disjoint union of one-point compactification of some discrete spaces. Suppose that , where is the one-point compactification of discrete space , for every . Assume that , and . Clearly, is discrete and hence . It is sufficient to show that . On the contrary suppose that is a nonempty set. Then is discrete and . One can easily see that is -embedded in and consequently is -embedded in . Hence, and therefor . This implies that which is contradiction, for by Theorem 9.2 of [12] we have . ∎
The converse of the above theorem is not true, in general. For example, is compact, while is not a submaximal space. Also, if is a submaximal space, then may not be submaximal. For example, is submaximal but is not submaximal.
Corollary 2.17.
Let be a submaximal space. The following statements are equivalent.
a) is compact.
b) is -compact.
c) is countably compact.
d) is pseudocompact.
Proof.
and are trivial.
Since is union a finite number of compact spaces, then it is countably compact.
If is a pseudocompact space, then and by hypothesis is submaximal. Now by Theorem 2.16 we conclude that is compact. ∎
Lemma 2.18.
If is a dense countably compact set in and is a Hausdorff submaximal space, then .
Proof.
Since is a submaximal space, then by Theorem 4.21 of [1], is compact and since is Hausdorff, we infer that is closed in . Therefor, by density of we have . ∎
By the above lemma the proof of the next corollary is obvious.
Corollary 2.19.
If is submaximal and is countably compact, then is realcompact.
Remark 2.20.
We denote the set of all isolated points of space with . If is open in , then and if is dense in , then . Hence, if is an open dense set in , then .
Theorem 2.21.
Suppose that is a first countable, Hausdorff and submaximal space and is a dense set in and . Then .
Proof.
Let . Hence, there is an infinite sequence contained in which converges to . Put . Let be a copy of contained in . Since is compact, then has an accumulation point in , namely . We claim that . To see this, let and , which is an open set in . We must show that . If not, then and hence there is an open set in such that . It is clear that , that is which is contradiction. Now one can easily see that while , that is is not open, so it contradicts the submaximality of . ∎
Corollary 2.22.
Let be a compact submaximal space. Then is finite if and only if is finite.
Proof.
Suppose that is finite. If is infinite, then similar to the proof of the Theorem 2.21, we can show that is not submaximal, which is a contradiction. Hence is finite and so is finite. ∎
Corollary 2.23.
If is submaximal and first countable and , then i.e., is realcompact.
Proof.
By Theorem 2.21 is clear. ∎
A space is called a pseudo-finite (resp. pseudo-discrete) space if every compact subspace of is finite (resp. has finite interior). We say that is real pseudo-finite, if is pseudo-finite. Every pseudo-finite space is pseudo-discrete, but not conversely. For example, we consider the space of rational numbers.
Example 2.24.
The space is pseudo-finite. To see this, let be a compact subspace. If , then is discrete and hence it is finite. If and is infinite, then assume that be an infinite subset of and put . Now be an open cover for which has not a finite subcover. This is a contradiction.
Proposition 2.25.
Every submaximal Hausdorff space is pseudo-finite.
Proof.
Let be a submaximal Hausdorff space and let be a compact subspace of . If be infinite, then contains a copy of , namely . Suppose that , where . Now similar to the proof of the Theorem 2.21, it is observe that is dense in but it is not an open set in , so it contradicts the submaximality of . ∎
A pseudo-finite Tychonoff space may be not submaximal. For example, is pseudo-finite but not submaximal. See also the following example.
Example 2.26.
We consider the space in Example 2 of [16]. This example shows that the Tychonoff space is an infinite countably compact subset of which is also pseudo-finite. We claim that is not submaximal. Otherwise, by Theorem 4.20 of [1], must be a compact space. In this case, since is pseudo-finite, it must be finite, which is not true.
(resp. ) is the family of all with compact (resp. pseudocompact) support. Also is a subcollection of consisting of all functions vanishing at infinity, that is all for which is compact for every . For the convenience of readers, some special ideals are listed below.
a) is the intersection of all essential ideals in . Recall that is the socle of and it is well known that , see Proposition 3.3 of [14].
b) is the intersection of all free ideals in , see 7E of [12].
c) is the intersection of all free maximal ideals in .
d) is the intersection of all hyper-real maximal ideals in .
e) is the intersection of all free maximal ideals in .
One can easily see that . In Theorem 8.19 of [12], it is shown that if is realcompact, then . In part (a) of Theorem 4.5 of [4], it is proved that is a pseudo-discrete if and only if .
In [13] a space is called:
a) a -compact if .
b) an -compact if .
c) a -compact if .
d) an -compact if .
In [15] a space is called an -compact if .
Proposition 2.27.
If is a submaximal space, then is a pseudo-finite -compact space.
Proof.
The converse of the above proposition is not true, in general. For example, is a pseudo-finite -compact space but is not submaximal.
By part (b) of Theorem 4.5 of [4], the proof of the result is obvious.
Corollary 2.28.
Let be a submaximal Hausdorff space and . Then .
Proposition 2.29.
Let be a submaximal space and . Then the following statement are hold.
a) is a -compact.
b) is a -compact.
c) is compact if and only if it is a realcompact space.
Proof.
The proof of parts (a) and (b) and implication () of (c) is clear. For the other side of (c), since is -compact, then . Since is realcompact, we infer that , that is, is -compact and -compact. Hence and by Corollary 2.5 of [5] we conclude that is compact. ∎
Similar to Theorem 2.16, the question arises that if is a submaximal space, is realcompact?. So far, we have not been able to answer this question, in general. Therefor we express it as a question.
Question: If is a submaximal space, is realcompact?
The space is a realcompact space which is not submaximal. See the following example for an example of a space that is submaximal but not realcompact. This example, also shows that may be submaximal but may not be submaximal.
Example 2.30.
We consider the space in 5I of [12]. By 5I. 5, the space is pseudocompact which it is not a realcompact space. We now show that it is submaximal. Suppose that . Since , we infer that , where . Assume that , which . Put , where containing all but a finite number of points of . Then is an open set contains and . This implies that , that is open and consequence that is submaximal. Furthermore, since is not compact, by Theorem 2.16, is not submaximal. Now shows that is not a submaximal space.
It is possible that is a locally compact and pseudocompact space but is not submaximal. See the next example.
Example 2.31.
We consider the space of all countable ordinals and , where denoting the first uncountable ordinal. It is well known that is a pseudocompact locally compact space which neither compact nor realcompact. Clearly, . Since is not compact, then by Theorem 2.16, is not submaximal. For a direct proof let , where is the first infinite ordinal and let . One can easily check that is dense in . But is not open in , for while .
3. locally indiscrete spaces
A space is called locally indiscrete if every open set is closed or equivalently if every closed set is open. Every discrete space is locally indiscrete. For another nontrivial example, let be a principal ideal ring. Then the space with Zariski topology is a locally indiscrete space.
Proposition 3.1.
For a topological space the following conditions are equivalent.
a) is locally indiscrete.
b) Every subset of is preopen.
c) Every singleton in is preopen.
d) Every closed subset of is preopen.
e) Every locally closed subset of is open.
f) Every locally closed subset of is closed.
g) The closure of every locally closed set is open.
h) Every dense open subset of is regular open.
Proof.
All implications are straightforward. We only show . Suppose that is an open set in and consider . Then is open in . Furthermore, . Hence, by hypothesis is regular open and therefore we have . It implies that and thus . This consequence that , that is, is closed and we are done. ∎
Proposition 3.2.
For a topological -space the following conditions are equivalent.
a) is discrete.
b) is locally indiscrete.
c) Every open set is regular open.
Proof.
It is straightforward. ∎
To see the definition of the concepts given in the next remark, see [12, 10]. Foe details about -spaces, see [6].
Remark 3.3.
a) A locally indiscrete space need not be discrete.
b) If is a -space, then it is locally indiscrete if and only if it is discrete.
c) Every locally indiscrete space is a strongly zero-dimensional space. The converse is not true. For example, is a strongly zero-dimensional subspace of while it is not locally indiscrete.
d) Every locally indiscrete space is a -space. The converse is not true. For example, the space of 4M in [12] is a -space which is not locally indiscrete.
e) A locally indiscrete space need not be submaximal. For instance, let and .
f) A submaximal space need not be a locally indiscrete space. For example we consider the space of 4M in [12].
g) Every locally indiscrete space is a -space. The converse is false. For example, the space in 4.N of [12] is a -space which is not locally indiscrete.
h) Every locally indiscrete space is a extremally disconnected and hence is basically disconnected. The converse is false. For example, the space in 4.N of [12] is a basically disconnected which is not locally indiscrete and the space is extremally disconnected which is not locally indiscrete.
Proposition 3.4.
The space is a locally indiscrete space if and only if .
Proof.
Let . Then , where is -locally closed, for any . By hypothesis, is -open, hence and we are done.
Let is a -locally closed subset of . Hence and therefore . This shows that is a locally indiscrete space.
∎
Proposition 3.5.
Let be a locally indiscrete space. The following conditions are equivalent.
a) is a -space.
b) is a -space.
c) is a -space.
d) is a -space.
e) is a submaximal space.
f) is a discrete space.
Proof.
All implications are obvious. We only show . Let and on the contrary suppose that and . If there is an open set such that and , then which is not true. If there is an open set such that and , then and since is open we infer that and this is not true. Therefor is a -space and we are through. ∎
4. lc-properties
In this section, by using the locally closed sets, we introduce some separation axioms. For more details about lc-continuous functions, see [11]. We begin with the following definition.
Definition 4.1.
A space is called:
a) lc-regular if for each locally closed set and for each point , there are disjoint open sets and with and .
b) lc-completely regular if for each locally closed set and for each point , there exists a continuous function such that and .
c) lc-normal if for every two disjoint locally closed sets and , there are disjoint open sets and with and .
Every lc-regular (resp. lc-completely regular, lc-normal) space is a regular (resp. completely regular, normal) space. The converse is hold in locally indiscrete spaces, but is not true, in general. See the following example.
Example 4.2.
We consider with usual topology.
a) is not a lc-regular space. To see this let . Then is locally closed and . But cannot be separated from by disjoint open sets.
b) is not a lc-completely regular space. To see this let . Then is locally closed and . But cannot be separated from by a continuous function.
c) is not a lc-normal space. To see this let and . Then and are locally closed sets. But and cannot be separated by disjoint open sets.
Remark 4.3.
a) Every lc-completely regular -space is completely regular.
b) Every lc-normal -space is Hausdorff.
Definition 4.4.
A space is called lc-compact if each locally closed cover of has a finite subcover.
Every lc-compact space is compact. Every infinite compact -space is not lc-compact. One can easily see that is lc-compact if and only if is compact.
Proposition 4.5.
Every clopen subset of a lc-compact space is lc-compact.
Proof.
Suppose that , where is locally closed set in , for each . Hence, , which is locally closed set in , for each . Therefor there is an open set and a closed set in which . Now it is clear that . Since is a lc-compact space we infer that , for a natural number and for . It implies that , that is, is a lc-compact space. ∎
Definition 4.6.
A function is called lc-continuous if the converse image of any open set in is locally closed in .
Every continuous function is lc-continuous. The converse is not true. For example, let and and are two topology on . We define by . Then is lc-continuous but it is not a continuous function.
Remark 4.7.
Let be a onto and be a lc-compact space. Then
a) if is continuous then is lc-compact.
b) if is lc-continuous then is compact.
Remark 4.8.
If is lc-continuous, then is continuous. The converse is false. To see this we consider and define by and , which is equipped with discrete topology. Since is discrete, then is continuous. But is not locally closed set in while is an open set in . This shows that is not a lc-continuous function.
Remark 4.9.
Let be continuous.Then
a) if is locally closed then is locally closed.
b) if is locally closed then need not be locally closed. Let , be discrete topology and be trivial topology on . We define by . Then is locally closed set in but is not locally closed set in .
Definition 4.10.
A function is called locally closed if the image of each locally closed set of , is locally closed in .
If is one-to-one, open and closed function, then it is locally closed. A locally closed function need not be open or closed. See the next example.
Example 4.11.
a) Let , be discrete topology and be another topology on . We define by . Then is locally closed but it is not an open function.
b) Let , be discrete topology and be another topology on . We define by . Then is locally closed but it is not a closed function.
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