Hausdorff Dimension of closure of cycles in -maps on the circle
Abstract.
We study the dynamics of the map on the unit circle. We characterize the invariant finite subsets of this map which are called cycles and are graded by their degrees. By looking at the combinatorial properties of the base-d expansion of the elements in the cycles, we prove a conjecture of Curt McMullen that the Hausdorff dimension of the closure of degree-m cycles is equal to .
1. Introduction
Degree- maps on the unit disk have many interesting geometric, topological and analytic properties, which are closely related to hyperbolic geometry. The dynamics of these maps has an important application in classifying dynamical systems generated by polynomials in single complex variable [goldberg1992fixed] and it provides useful information about Julia sets and Mandelbrot sets [keller2000invariant, douady1984etude]. To get an understanding of this family of maps, people studied the behaviour of these maps restricted to the boundary unit circle [goldberg1992fixed, goldberg1993fixed]. In the paper [mcmullen2010dynamics], McMullen gave a complete description of simple (i.e. degree 1) cycles of these boundary maps, showing that those simple cycles are an analogue of simple closed geodesics on hyperbolic surfaces in the sense that the closure of union of simple cycles has Hausdorff Dimension 0 and the closure of union of simple closed geodesics has Hausdorff Dimension 1.
Here we consider degree- holomorphic maps from the unit disk onto itself. We focus on one such map . The restriction of this map to the boundary circle is equivalent to the map on Combinatorial features of this map has been studied recently in [PZ, zakeri2021cyclic, tan2022counting]. In this paper, we study cycles of higher degrees in this map, and in particular, calculate the Hausdorff dimension of their closure, which confirms a conjecture of McMullen.
Definition 1 (-map).
Let . We define a -map to be the map on the unit circle given by
(1) |
In other words, if the base- expansion of a point is , then -map takes it to the point whose base- expansion is .
We say that a -map has degree .
Definition 2 (Cycle).
Let be a positive integer greater than 1. A finite set is called a cycle for the -map if and only if the -map restricted to is a transitive permutation. In terms of the base- expansion, is given by
(2) |
where is the size of the cycle and are fixed digits in .
Here are some examples of cycles. Consider the case . Here, is the only 1-element cycle and is the only 2-element cycle. For an integer , there are multiple -element cycles. For example, there are two 3-element cycles: and .
Now we define an important invariant of a cycle, called degree.
Definition 3 (Degree of a cycle).
Let be a positive integer greater than 1. Let be a cycle for -map. The degree of is the smallest non-negative integer for which there exists a degree- map such that and the -map agree on . It is denoted by .
Remark 1.
Note that by definition.
Remark 2.
The cycles which contain only one element are fixed points of -map and have degree 0. All other cycles have positive degree.
Now, we give two examples.
Example 1.
Consider and . Under the 2-map,
Here the cyclic order of the points in is preserved. As we jump on the points in the cycle from (jump over 0) and back to , we complete one full circle. As we jump on the images of these points, (jump over 0 to) and back to , again we complete one circle. This means that the degree of is 1. We can show this by explicitly constructing a suitable map as follows:
Observe that agrees with the 2-map, and it is of degree 1. As there are no maps with smaller degree, .
Example 2.
Consider and . Under the 3-map,
So, as we jump on the points in the cycle from (jump over 0) and back to , we complete one full circle. As we jump on the images of these points, (jump over 0 to) (jump over 0 to) and back to , we complete two circles. So, the degree of is 2. We can show this by explicitly constructing a suitable map as follows:
Observe that agrees with the 3-map, and it is of degree 2. As there are no maps with smaller degree, .
Definition 4 (Closure of cycles).
Let with and . We define as the closure of the union of degree- cycles for -map.
(3) |
Curtis McMullen discussed in [mcmullen2010dynamics] the simple (i.e. degree 1) cycles for the -map and and computed the Hausdorff Dimension of their closure . Recall that Hausdorff Dimension is defined as follows.
Definition 5 (Hausdorff Dimension).
The Hausdorff Dimension of a set is defined as
(4) |
Theorem 1 (McMullen).
Let be a positive integer greater than 1. Then
In this paper, we generalize the above results by showing the following.
Theorem 2.
Let with and . Then,
This paper is organized in the following way:
In Section 2, we get a lower bound on the Hausdorff Dimension of by calculating the Hausdorff Dimension of a subset of .
In Section 3, we prove the upper bound by imitating the proof of Theorem 1 in paper [mcmullen2010dynamics] using combinatorial arguments, and conclude by proving Theorem 2.
2. Lower Bound
In this section, we define and study two useful invariants of a cycle called crossing number and Digit Portrait, which are directly related to the degree of the cycle. Then we use these properties to construct a subset of which has Hausdorff Dimension .
Definition 6 (Crossing).
Let be a positive integer greater than 1. Let be a cycle for -map such that
Let . For any , the pair is called a crossing generated by (or simply a crossing) iff
(5) |
The total number of such crossings is called the crossing number of C.
(6) |
Remark 3.
If , then there are no crossings. The crossing number is 0 which is the degree of 1-element cycles.
Remark 4.
As we jump on in the counterclockwise direction and trace the points of the cycle from and (jump over 0) back to , we complete one full circle. When we trace the images of these points, and back to , we may jump over 0 multiple times. Each time we jump over 0, we have a crossing. The crossing number of the cycle is equal to its degree. We provide a rigorous proof of this intuitive result below.
Lemma 1.
Let be a positive integer greater than 1. Let be a cycle for -map with . Then, the crossing number of is equal to its degree or
Proof.
The case is obvious, so assume and let , for all
Let be such that for all , the pair is a crossing generated by .
First, we prove . Assume for the sake of argument that . We can divide or in intervals such that on each , there exists a continuous non-decreasing map to which agrees with the -map on .
Note that there are exactly sets of the type By our assumption that we can find a such that for some . In other words,
a contradiction of the non-decreasing nature of . Thus, .
Now we prove that by constructing an appropriate map of degree . To start, we divide into intervals of the type , each of which is mapped onto We take the endpoints of each such interval to 0, and points of to their images under the -map. In between, we make linear. We define
where intervals are taken in counter-clockwise direction.
So, is a continuous function for all , and the restriction of gives a bijection
Since has degree and agrees with the -map, by Definition 3, This, combined with above, completes the proof.
∎
Now that we have established the relation between the degree and the crossing number of a cycle, we need a tool to estimate the crossing number. We observe that the crossing number of a cycle is related to the order of points in the cycle, and hence the digits in the base- expansion of points of the cycle. We define an invariant of the cycle called Digit Portrait which characterizes these digits.
Definition 7 (Digit Portrait).
Let be a positive integer greater than 1. Let be a cycle for -map. The Digit Portrait of is the non-decreasing map which satisfies
or
Let be the number of distinct positive values taken by . Note that if a digit is absent in the base- expansion of a point in , then or . So, is also the number of distinct digits which appear in the base- expansion of any point in . To estimate the crossing number of , we need the second interpretation of .
Example 3.
Consider and the cycle . Note that
The Digit Portrait of is the map given by:
takes the values 2, 3 and 4. So, is 3. There are exactly 3 digits (0, 1 and 2) which appear in the base-4 expansion of the points in .
Now we establish the relation between and the crossing number of .
Lemma 2.
Let be a positive integer greater than 1, and be a cycle for the -map with and . Then, the crossing number of is at most the number of distinct digits which appear in the base- expansion of a point in . In other words,
Proof.
Let . Let and . In other words, the base- expansions of and begin with the digits and respectively. Note that because .
If , then
In this case, cannot be a crossing. So, is a crossing only if i.e., is the largest element of and is the smallest element of .
Thus, there are at most ’s for which and is a crossing. For some cycles, is an additional crossing. So, there are at most ’s for which and is a crossing. ∎
Together, Lemma 1 and Lemma 2 give a way of estimating the degree of a cycle by looking at the digits in the base- expansion of a point in the cycle. Now we use this to get a sufficient condition for a point to be in the closure of the cycles of fixed degree.
Lemma 3.
Let with and . Then, any point in whose base- expansion contains at most distinct digits lies in .
Proof.
Let Let such that Here, are fixed digits in base- such that
To prove that lies in , we will show that for all there exists a degree- cycle for the -map that intersects neighborhood of . Any periodic point whose base- expansion contains exactly distinct digits is in a cycle of degree at most . To get the maximum possible degree, we need maximum possible crossings. This can be achieved with the following construction:
Let such that for all is greater than the number of times appears in the first digits of . Let denote . Consider the following point:
(7) |
Clearly, is in neighborhood of . It is a point of cycle for the -map with .
Now we need to prove that . For each , let be such that the largest element of whose base- expansion starts with the digit is . Note that is at least . For , is at least . For each is the smallest element of whose base- expansion starts with the digit . Note that the base- expansion of starts with .
So, for all ,
i.e., is a crossing.
Note that and . So,
i.e., is a crossing.
Thus, the crossing number of is at least .
From Lemma 2, we know that the crossing number of is at most the number of distinct digits in the base- expansion of a point , which in this case, is .
Therefore, .
∎
The following result follows immediately.
Proposition 1.
. Thus,
Proof.
Note that since base- has only digits, the set of all points of whose base- expansion contains at most distinct digits is itself. So, we have or
∎
Now, we use Lemma 3 to construct a subset of . Let and be positive integers with and , and let be the set of points in whose base- expansion contains the digits from 0 to only. Clearly, .
The structure of is similar to the structure of Cantor’s set. Here, we start with . Write in closed intervals of length . Let be union of first of these intervals.
is the union of intervals of length . Divide each such interval in equal parts and take the first in is the union of intervals of length .
Repeat the process. If is the union of intervals of length , then divide each such interval in equal parts and take the first in .
Now we calculate the Hausdorff Dimension of .
Lemma 4.
.
Proof.
First, we prove that the Hausdorff dimension of is at most . Let . Note that for all . So, for each , we have intervals of length that form a covering of . Letting for some ,
This means that, for any , we can cover such that the summation of powers of the lengths of the intervals in the cover is as small as we like. So,
Now we need to show that the Hausdorff dimension of is at least . Note that we can consider as a subset of a compact set. So, for any countable cover of , we can find finitely many open sets such that
We next get a lower bound on . Let such that for all . Additionally, for all , let be the number of ’s which satisfy . Observe that if , then can intersect at most two intervals in . Hence, can contain at most intervals in , which has intervals. So,
or
For ,
In other words, the summation of powers of the lengths of the intervals which form a cover of has a positive lower bound. Thus,
∎
Since we immediately get a lower bound on the Hausdorff Dimension of
Theorem 3.
Let with and . Then,
∎
3. Upper Bound
In this section, we first find an upper bound on the number of degree- cycles for -map which have elements. We extend this result to precycles. Then, we find an appropriate covering of to prove that its Hausdorff Dimension is at most .
Definition 8 (Partition generated by a cycle).
Let be a degree- cycle for -map such that . Let be the map on which satisfies:
Note that is a permutation of because is a cycle.
Let be such that for all is a crossing generated by . From the ordering of the elements of and the definition of crossing, we conclude that:
and
Now we construct a partition of using the above property of .
is a partition of , called as the partition generated by and it is denoted by .
Remark 5.
Both and the map are useful counting -element degree- cycles, as we show below.
Example 4.
Let us consider the instance where and
Note that here, . Under the 3-map,
So, is the permutation of which takes 1, 2, 3, 4, 5 to 2, 4, 5, 3, 1 respectively. and are the crossings generated by the cycle. So, and , and the partition generated by is given by:
or
Now, we will show that if some properties of a cycle such as degree, the partition it generates and its digit portrait are given, then we can construct the cycle (find its points). Later, we will use this result to count the number of cycles of fixed degree and cardinality.
Lemma 5.
Given positive integers , which is a partition of , positive integer and a non-decreasing map with , there exists at most one cycle for -map such that:
-
(1)
with
-
(2)
-
(3)
or is the partition generated by
-
(4)
If, for all , , then is a crossing for all .
-
(5)
is the Digit Portrait of .
Proof.
Suppose is a cycle for -map which satisfies all the conditions above, and let be the map on given by:
where, for all , the elements of are in increasing order. Note that is uniquely determined by and . Comparing this with the definition of partition generated by a cycle, we conclude that
Let given by:
Note that is uniquely determined by and . Comparing this with the definition of Digit Portrait, we conclude that
or
Also,
Thus, we conclude that
In other words, the cycle is uniquely determined by and .
∎
Remark 6.
can be a crossing only if the first digits of the base- expansions of and differ. So, cycle satisfying all conditions in the above lemma can exist only if
We will use this in the proof of the following lemma.
Lemma 6.
Let with and . Then the number of cycles for -map satisfying and is at most
Proof.
are given. Now we need which is a partition of , positive integer and a non-decreasing map with to fix a degree-, -element cycle.
Let be the set of ordered -tuples such that
is a partition of ,
and .
We want an upper bound on the size of T, denoted here as .
After fixing an element of , we need to fix a non-decreasing map from to with and . Observe that there are or choices for , depending on if is in or not.
Using Lemma 5, we conclude that the number of degree- -element cycles for -map is at most .
∎
To conclude this section (and to show our desired result), we first introduce precycles.
Definition 9 (Precycle).
Let be a positive integer greater than 1. A finite set is called a precycle for -map, if and only if for some . In other words, a precycle is the forward orbit of a rational point in . It can be written in terms of base- expansion of its points as
where is a fixed non-negative integer, is a fixed positive integer and all are fixed digits in .
Remark 7.
Every precycle includes a cycle. If , then itself is a cycle.
Example 5.
Consider and . can be written as
or
Remark 8.
We can define degree, crossing, crossing number, digit portrait and partition for a precycle simply by replacing by in the respective definitions.
In the case where is a precycle but not a cycle, the map in the definition of partition (Definition 8) is not a permutation. Under , one element of has no preimages, one has two preimages and all other elements have exactly one preimage.
Lemma 7.
Let with . Then the number of precycles for the -map satisfying and is at most .
Proof.
Finally, we find a suitable covering of and get an upper bound on its Hausdorff Dimension, as desired.
Theorem 4.
Let with and . Then
Proof.
Fix a positive integer , and let
From Lemma 7, we have is at most (note the change in exponent due to the inequality).
Let be a degree- cycle for -map, and . There exists a degree- map which agrees with -map on . Letting denote composed times, we note that . See McMullen [mcmullen2010dynamics] for details. It follows there exists a point in neighborhood of for which two of coincide. Generalizing, each point of any degree- cycle for the -map lies in neighborhood of an element in . Thus, lies in a neighborhood of which has at most elements.
Let for some
For any , we can cover such that the summation of powers of the lengths of the intervals in the cover is as small as we like. So, .
∎
We are now ready to prove Theorem 2.
Theorem 2.
Let with and . Then,
Proof.
Follows from Theorems 3 and 4. ∎
Acknowledgment
The authors would like to thank Prof. Curtis McMullen for suggesting the problems and giving valuable comments. This project was undertaken by M.T. in SPUR (the Summer Program in Undergraduate Research) at MIT Mathematics Department in Summer 2014. M.T. would like to thank Prof. David Jerison and Prof. Pavel Etingof for their guidance and insightful discussions during the program. We also thank our mentor Xuwen Zhu for her help and support for completing this paper.