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Harmonic Interpolation and a Brunn-Minkowski Theorem for Random Determinants

Julius Ross  and  David Witt Nyström Mathematics Statistics and Computer Science, University of Illinois at Chicago, Chicago IL, USA [email protected] Department of Mathematical Sciences, Chalmers University of Technology and the University of Gothenburg, Sweden [email protected], [email protected]
Abstract.

We describe the harmonic interpolation of convex bodies, and prove a strong form of the Brunn-Minkowski inequality and characterize its equality case. As an application we improve a theorem of Berndtsson on the volume of slices of a pseudoconvex domain. We furthermore apply this to prove subharmonicity of the expected absolute value of the determinant of a matrix of random vectors through the connection with zonoids.

2020 Mathematics Subject Classification:
32J27, 52A40, 52A21 (Primary) 32U05, 14C17, 52A40 (Secondary)

1. Introduction

Let AA and BB be convex subsets of n\mathbb{R}^{n}. The Minkowski sum of AA and BB is defined as

A+B:={a+b:aA,bB},A+B:=\{a+b:a\in A,b\in B\},

and the famous Brunn-Minkowski inequality says that

|A+B|1/n|A|1/n+|B|1/n,|A+B|^{1/n}\geq|A|^{1/n}+|B|^{1/n},

where |||\cdot| denotes the Euclidean volume.

We wish to consider the interpolation of convex sets. Given convex AA and BB there is a natural interpolating family At:=(1t)A+tBA_{t}:=(1-t)A+tB, t[0,1]t\in[0,1], and it follows from the Brunn-Minkowski inequality that the map

t|At|1/nt\mapsto|A_{t}|^{1/n}

is concave in t[0,1]t\in[0,1].

For an infinite family of convex sets, there are many possible interpolations. To consider this in more detail, suppose Ω\Omega is a smoothly bounded domain in m\mathbb{R}^{m} and that we have a continuous family of convex bodies (i.e. compact convex sets) AτnA_{\tau}\subset\mathbb{R}^{n} parametrized by τΩ\tau\in\partial\Omega. If Ω\Omega is itself convex, a natural interpolation can be obtained by considering

A=Convexhull(τΩAτ×{τ})n+mA=\operatorname{Convexhull}\left(\bigcup_{\tau\in\partial\Omega}A_{\tau}\times\{\tau\}\right)\subseteq\mathbb{R}^{n+m}

and letting AxA_{x} be the fiber of AA over xΩx\in\Omega. We call this the convex interpolation of {Aτ}\{A_{\tau}\}. Then directly from the Brunn-Minkowski inequality it follows that the map x|Ax|1/nx\mapsto|A_{x}|^{1/n} is concave in xΩx\in\Omega.

If Ω\Omega is not convex, the convex interpolation is not suitable since it will not necessarily agree with the given boundary data {Aτ}\{A_{\tau}\} on Ω\partial\Omega. For general Ω\Omega a natural interpolation was proposed in our recent paper [3] that we now describe.

First note that if AyA_{y} is a continuous family of convex bodies in n\mathbb{R}^{n} over some parameter set DmD\subseteq\mathbb{R}^{m} and μ\mu is a Radon measure on DD, then there is a set-integral

DAy𝑑μ(y)\int_{D}A_{y}d\mu(y)

which is itself a subset of n\mathbb{R}^{n}. To define this precisely recall that the support function of a convex set AA is given by

hA(ξ):=supζA(ζξ)h_{A}(\xi):=\sup_{\zeta\in A}(\zeta\cdot\xi)

with and has the property that

hA is convex and hA(tξ)=|t|hA(ξ) for t.h_{A}\text{ is convex and }h_{A}(t\xi)=|t|h_{A}(\xi)\text{ for }t\in\mathbb{R}. (1)

On the other hand, if hh is a function with those two properties then hh is the support function of a unique closed convex set, which we denote by A(h)A(h).

It is an elementary exercise to see that hA+B=hA+hBh_{A+B}=h_{A}+h_{B} and more generally

ht1A1++tkAk=t1hA1++tkhAk.h_{t_{1}A_{1}+...+t_{k}A_{k}}=t_{1}h_{A_{1}}+...+t_{k}h_{A_{k}}.

Furthermore if AtA_{t} are convex sets such that AtAA_{t}\to A in the Hausdorff topology, then for each ξ\xi, hAt(ξ)hA(ξ)h_{A_{t}}(\xi)\to h_{A}(\xi).

Definition 1.1.

Let dμd\mu be a measure on a measurable set DD in m\mathbb{R}^{m}, and AyA_{y} be a convex set for each yDy\in D. We define the Minkowski integral DAy𝑑μ(y)\int_{D}A_{y}d\mu(y) as

DAy𝑑μ(y):=A(DhAy𝑑μ(y)).\int_{D}A_{y}d\mu(y):=A\left(\int_{D}h_{A_{y}}d\mu(y)\right).

Such set-valued integrals have been considered in various places, for example [1, 5]. As one would expect, some conditions are needed to ensure that the Minkowski integral is well-defined. For our purpose the following is sufficient: assume DD is compact, dμd\mu is a Radon measure and yAyy\mapsto A_{y} is a continuous family of convex bodies. Then for each ζ\zeta the map yhAy(ζ)y\mapsto h_{A_{y}}(\zeta) is continuous, so DhAy𝑑μ(y)\int_{D}h_{A_{y}}d\mu(y) exists and has properties (1), and thus DAy𝑑μ(y)\int_{D}A_{y}d\mu(y) exists.

Definition 1.2.

Let Ωm\Omega\subset\mathbb{R}^{m} be a smoothly bounded domain. The harmonic interpolation of a continuous family {Aτ}τΩ\{A_{\tau}\}_{\tau\in\partial\Omega} of convex bodies is defined as

Ax:=ΩAτ𝑑μx(τ),A_{x}:=\int_{\partial\Omega}A_{\tau}d\mu_{x}(\tau),

where dμxd\mu_{x} is the harmonic measure on Ω\partial\Omega with respect to xΩx\in\Omega.

The harmonic interpolation and convex interpolation may differ, even when Ω\Omega is convex. We argue that the former is better suited in some contexts, one of which is the theory of zonoids.

A zonotope is a convex set that can be written as the Minkowski sum of line segments. Clearly any zonotope is a convex polytope, but it is easy to see that not all convex polytopes are zonotopes. A zonoid is a convex set which can be approximated arbitrarily well (in the Hausdorff topology) by zonotopes, or equivalently a convex set that can be written as the Minkowski integral of line segments (see for example [4] for a introduction to zonoids). The harmonic interpolation has the property that it preserves zonoids; i.e. if each boundary set AτA_{\tau} is a zonoid then each member of the interpolating family AxA_{x} will also be a zonoid (and this is not true for the convex interpolation, even when Ω\Omega is convex).

Acknowledgements

This material is based upon work supported by the National Science Foundation under Grant No. DMS-1749447. The second named author is supported by the Swedish Research Council and the Göran Gustafsson Foundation for Research in Natural Sciences and Medicine. The authors thank Bo Berndtsson and Dario Cordero-Erausquin for conversations on this topic.

2. A Brunn-Minkowski Inequality for Harmonic Interpolation

We continue to assume Ωm\Omega\subset\mathbb{R}^{m} is a smoothly bounded domain (which by convention is also bounded), and AτA_{\tau} for τΩ\tau\in\partial\Omega is a continuous family of convex bodies in n\mathbb{R}^{n}. In [3] we proved the following weak version of a Brunn-Minkowski inequality for the harmonic interpolation.

Theorem 2.1.

If AxA_{x} is the harmonic interpolation of {Aτ}\{A_{\tau}\} then xlog|Ax|x\mapsto\log|A_{x}| is superharmonic in xx.

Our main result in this short note is a direct proof of the following stronger version:

Theorem 2.2.

If AxA_{x} is the harmonic interpolation of {Aτ}\{A_{\tau}\} then x|Ax|1/nx\mapsto|A_{x}|^{1/n} is superharmonic in xx.

Proof.

Let Bϵ(x)B_{\epsilon}(x) denote the Euclidean ball of radius ϵ\epsilon centered at xx. We need to show that if Bϵ(x)ΩB_{\epsilon}(x)\subseteq\Omega then

|Ax|1/nBϵ(x)|Ay|1/n𝑑S(y),|A_{x}|^{1/n}\geq\int_{\partial B_{\epsilon}(x)}|A_{y}|^{1/n}dS(y),

where dSdS denotes the normalized Euclidean surface measure on Bϵ(x)\partial B_{\epsilon}(x).

A standard property of harmonic measures is that

μx=Bϵ(x)μy𝑑S(y),\mu_{x}=\int_{\partial B_{\epsilon}(x)}\mu_{y}dS(y),

and this clearly implies that

Ax=Bϵ(x)Ay𝑑S(y).A_{x}=\int_{\partial B_{\epsilon}(x)}A_{y}dS(y).

Now we approximate the surface measure dSdS with a sequence of atomic measure νk=i=1Nkλi,kδyi,k\nu_{k}=\sum_{i=1}^{N_{k}}\lambda_{i,k}\delta_{y_{i,k}} chosen so νkdS\nu_{k}\to dS weakly as kk\to\infty. Then for kk sufficiently large i=1Nkλi,kAyi\sum_{i=1}^{N_{k}}\lambda_{i,k}A_{y_{i}} is arbitrarily close (in the Hausdorff distance) to AxA_{x}. Thus for any ϵ>0\epsilon>0 and kk sufficiently large we have

|Ax|1/n+ϵ|i=1Nkλi,kAyi,k|1/ni=1Nkλi,k|Ayi,k|1/nBϵ(x)|Ay|1/n𝑑S(y)ϵ,\displaystyle|A_{x}|^{1/n}+\epsilon\geq|\sum_{i=1}^{N_{k}}\lambda_{i,k}A_{y_{i,k}}|^{1/n}\geq\sum_{i=1}^{N_{k}}\lambda_{i,k}|A_{y_{i,k}}|^{1/n}\geq\int_{\partial B_{\epsilon}(x)}|A_{y}|^{1/n}dS(y)-\epsilon,

where the second follows from the classical Brunn-Minkowski inequality. Letting ϵ0\epsilon\to 0 we have

|Ax|1/nBϵ(x)|Ay|1/n𝑑S(y),|A_{x}|^{1/n}\geq\int_{\partial B_{\epsilon}(x)}|A_{y}|^{1/n}dS(y),

which completes the proof. ∎

Definition 2.3.

We say that a continuous family of convex sets AxnA_{x}\subseteq\mathbb{R}^{n} over some domain Ωm\Omega\subseteq\mathbb{R}^{m} is subharmonic over Ω\Omega if whenever Bϵ(x)ΩB_{\epsilon}(x)\subseteq\Omega we have that

AxBϵ(x)Ay𝑑S(y).A_{x}\supseteq\int_{\partial B_{\epsilon}(x)}A_{y}dS(y).

The then get the following Corollary of Theorem 2.2.

Corollary 2.4.

If AxA_{x} is subharmonic over Ω\Omega then x|Ax|1/nx\mapsto|A_{x}|^{1/n} is superharmonic.

As an application we can give a strengthening of the following theorem of Berndtsson [2]

Theorem 2.5.

Let Un+mU\subseteq\mathbb{C}^{n+m} be a pseudoconvex domain with the property that if (x1+iy1,,xn+iyn,w)U(x_{1}+iy_{1},...,x_{n}+iy_{n},w)\in U then (x1+iy1,,xn+iyn,w)U(x_{1}+iy^{\prime}_{1},...,x_{n}+iy^{\prime}_{n},w)\in U for all y1,,yny_{1}^{\prime},\ldots,y_{n}^{\prime}, and let Uw:={xn:(x,w)U}U_{w}:=\{x\in\mathbb{R}^{n}:(x,w)\in U\}.

Then the map wlog|Uw|w\mapsto-\log|U_{w}| is plurisubharmonic in ww.

Theorem 2.6.

In the same setting as Theorem 2.5, the map w|Uw|1/nw\mapsto-|U_{w}|^{1/n} is plurisubharmonic.

Proof.

Without loss of generality we can assume that m=1m=1. Note that the pseudoconvexity and symmetry of UU implies that UwU_{w} is convex for all ww. By approximation we can also without loss of generality assume that the family UwU_{w} is bounded and continuous. We claim that the family UwU_{w} is subharmonic. Note that for two closed convex sets AA and BB we have that ABA\supseteq B if and only if hAhBh_{A}\geq h_{B}, so UwU_{w} is subharmonic if and only if for any ξn\xi\in\mathbb{R}^{n}, hUw(ξ)=supxUw(xξ)h_{U_{w}}(\xi)=\sup_{x\in U_{w}}(x\cdot\xi) is superharmonic in ww.

Let ϕ\phi be a plurisubharmonic exhaustion function for UU which we can assume to be independent of Im(n)\operatorname{Im}(\mathbb{C}^{n}), just as UU itself. Note that ϕR:=max(ϕR,0)\phi_{R}:=\max(\phi-R,0) is also plurisubharmonic and independent of Im(n)\operatorname{Im}(\mathbb{C}^{n}), and that the same is true for ψR(x+iy,w):=ϕR(x+iy,w)xξ\psi_{R}(x+iy,w):=\phi_{R}(x+iy,w)-x\cdot\xi. Thus by Kiselman’s minimum principle infxUwψR(x,w)\inf_{x\in U_{w}}\psi_{R}(x,w) is subharmonic in ww. We now note that

supxUw(xξ)=limRinfxUwψR(x,w),\sup_{x\in U_{w}}(x\cdot\xi)=-\lim_{R\to\infty}\inf_{x\in U_{w}}\psi_{R}(x,w),

and hence it follows that hUw(ξ)h_{U_{w}}(\xi) is superharmonic and thus UwU_{w} is subharmonic. That |Uw|1/n-|U_{w}|^{1/n} is subharmonic now follows from Corollary 2.4. ∎

3. Characterization of the extremal case

By Corollary 2.4 we know that if {Ax}xΩ\{A_{x}\}_{x\in\Omega} is a subharmonic family of convex bodies in n\mathbb{R}^{n} over a domain Ω\Omega then x|Ax|1/nx\mapsto|A_{x}|^{1/n} is superharmonic. Our next result characterizes when this map is in fact harmonic.

Theorem 3.1.

The map x|Ax|1/nx\mapsto|A_{x}|^{1/n} is harmonic if and only if we can write Ax=cxB+dxA_{x}=c_{x}B+d_{x} where BnB\subset\mathbb{R}^{n} is a fixed convex body, and cxc_{x} and dxd_{x} are harmonic functions on Ω\Omega taking values in +\mathbb{R}_{+} and n\mathbb{R}^{n} respectively.

Proof.

Let Ω\Omega^{\prime} be a relatively compact subdomain of Ω\Omega with smooth boundary. Since AxA_{x} is subharmonic it must dominate the harmonic interpolation of AyA_{y} restricted to Ω\partial\Omega^{\prime}, but since |Ax|1/n|A_{x}|^{1/n} is assumed to be harmonic we must have that AxA_{x} is equal to the harmonic interpolation.

Write Ω\partial\Omega^{\prime} as the disjoint union of a finite number of measurable subsets DiD_{i} and let

Bi:=DiAy𝑑μx(y),B_{i}:=\int_{D_{i}}A_{y}d\mu_{x}(y),

where μx\mu_{x} is the harmonic measure on Ω\partial\Omega^{\prime} with respect to xx. Then Ax=iBiA_{x}=\sum_{i}B_{i}, and by the Brunn-Minkowski inequality we have

|Ax|1/ni|Bi|1/n.|A_{x}|^{1/n}\geq\sum_{i}|B_{i}|^{1/n}.

On the other hand, as in the proof of Theorem 2.2 one sees that

|Bi|1/nDi|Ay|1/n𝑑μx(y).|B_{i}|^{1/n}\geq\int_{D_{i}}|A_{y}|^{1/n}d\mu_{x}(y).

But |Ax|1/n|A_{x}|^{1/n} being harmonic then implies the equality

|Ax|1/n=i|Bi|1/n.|A_{x}|^{1/n}=\sum_{i}|B_{i}|^{1/n}.

The well-known characterization of the equality case of the Brunn-Minkowski inequality then says that we can write Bi=ciB+diB_{i}=c_{i}B+d_{i}, where BB is some fixed convex set, and some ci+c_{i}\in\mathbb{R}_{+} and dind_{i}\in\mathbb{R}^{n}. We may normalize BB to have volume one and center of gravity at the origin. We thus also see that Ax=cxB+dxA_{x}=c_{x}B+d_{x} where cx=icic_{x}=\sum_{i}c_{i} and dx=idid_{x}=\sum_{i}d_{i}.

Now if we decompose a fixed DiD_{i} further into disjoint pieces EjE_{j} the same argument yields that for each jj there are cj+c^{\prime}_{j}\in\mathbb{R}_{+} and djnd^{\prime}_{j}\in\mathbb{R}^{n} such that EjAy𝑑S(y)=cjB+dj\int_{E_{j}}A_{y}dS(y)=c^{\prime}_{j}B+d^{\prime}_{j}. As we can make the decomposition arbitrarily fine the continuity of AyA_{y} implies that there are continuous functions cyc_{y} and dyd_{y} on Ω\partial\Omega^{\prime} such that Ay=cyB+dyA_{y}=c_{y}B+d_{y}. It follows that Ax=cxB+dxA_{x}=c_{x}B+d_{x} where cxc_{x} is the harmonic extension of cyc_{y} and dxd_{x} is the harmonic extension of dyd_{y} to Ω\Omega^{\prime}.

As this can be done for any for relatively compact subdomain of Ω\Omega with smooth boundary, the result follows. ∎

4. A Brunn-Minkowski theorem for expected absolute random determinants

Consider now a random (n,n)(n,n) matrix MYM_{Y} whose columns are iid copies of a random vector YY, corresponding to a Borel probability measure νv\nu_{v} on n\mathbb{R}^{n}. We are then interested in the expected absolute value of the determinant (ead) E|detMY|E|\det M_{Y}| of MYM_{Y}.

Suppose YτY_{\tau} is a family of random vectors parametrized by the boundary of a smoothly bounded domain Ωm\Omega\subseteq\mathbb{R}^{m}. We assume that each YτY_{\tau} has finite expectation. Then a natural interpolating family YxY_{x} over Ω\Omega is given by letting

νYx:=ΩνYτ𝑑μx(τ),\nu_{Y_{x}}:=\int_{\partial\Omega}\nu_{Y_{\tau}}d\mu_{x}(\tau),

where as before dμxd\mu_{x} denotes the harmonic measure with respect to xx.

Theorem 4.1.

The map x(E|detMYx|)1/nx\mapsto(E|\det M_{Y_{x}}|)^{1/n} is superharmonic in xx.

Our proof relies on the connection between eads and a special class of convex sets called zonoids which was established in [5, Thm 3.1]: to any random vector YY with finite expectation we may associate a zonoid

Z(Y):=n[0,y]𝑑νv(y).Z(Y):=\int_{\mathbb{R}^{n}}[0,y]d\nu_{v}(y).

Then the main result [5, Thm. 3.2] says that

E|detMY|=n!|Z(Y)|.E|\det M_{Y}|=n!|Z(Y)|. (2)
Proof of Theorem 4.1.

Note that

Z(Yx)=n[0,y]𝑑νYx(y)=nΩ[0,y]𝑑μx(τ)𝑑νYτ(y)=\displaystyle Z(Y_{x})=\int_{\mathbb{R}^{n}}[0,y]d\nu_{Y_{x}}(y)=\int_{\mathbb{R}^{n}}\int_{\partial{\Omega}}[0,y]d\mu_{x}(\tau)d\nu_{Y_{\tau}}(y)=
=Ωn[0,y]𝑑νYτ(y)𝑑μx(τ)=ΩZ(Yτ)𝑑μx(τ),\displaystyle=\int_{\partial{\Omega}}\int_{\mathbb{R}^{n}}[0,y]d\nu_{Y_{\tau}}(y)d\mu_{x}(\tau)=\int_{\partial{\Omega}}Z(Y_{\tau})d\mu_{x}(\tau),

i.e. Z(Yx)Z(Y_{x}) is the harmonic interpolation of Z(Yτ)Z(Y_{\tau}). Thanks to the volume equality (2) the result follows immediately from Theorem 2.2. ∎

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