Global rigidity for some partially hyperbolic abelian actions with 1-dimensional center
Abstract.
We obtain a global rigidity result for abelian partially hyperbolic higher rank actions on certain step nilmanifolds . We show that, under certain natural assumptions, all such actions are conjugated to an affine model. As a consequence, we obtain a centralizer rigidity result, classifying all possible centralizers for any small perturbation of an irreducible, affine partially hyperbolic map on . Along the way, we prove two results of independent interest. We describe fibered partially hyperbolic diffeomorphisms on and we show that topological conjugacies between partially hyperbolic actions and higher rank affine actions are .
1. Introduction
Rigidity of actions on tori (and nilmanifolds) with some hyperbolicity have been studied extensively. The general philosophy is: large abelian actions with some hyperbolicity should be globally rigid, i.e. smoothly conjugated to algebraic models. A big breakthrough result in this direction was obtained by Katok and Spatzier [44] where they prove that all perturbations of certain algebraic Anosov actions are smoothly conjugated back to the corresponding algebraic models. There they also outline a rigidity program for abelian actions with hyperbolicity. Since the paper by Katok and Spatzier, a lot of results have been obtained for large abelian actions close to some algebraic model with some hyperbolicity [16, 18, 14, 62, 63, 67, 68, 66, 23, 12]. Even earlier than the result by Katok and Spatzier, Katok and Lewis [43] proved a global rigidity statement for Anosov action on tori. In [43], the authors show that a certain class of Anosov actions on the torus is, necessarily, smoothly conjugated to an algebraic model, even though the action might not be close to the algebraic model. A crucial assumption in [43] is that the action contains many Anosov elements. The property of having many Anosov elements was removed by F. Rodriguez Hertz in [53], where Rodriguez Hertz only assumes that the action contains one Anosov element. Nilmanifolds are natural generalizations of tori. There has been a lot of work studying the global rigidity of higher rank111See Definition 2.3. Anosov actions on nilmanifolds since the paper by Katok and Lewis [38, 39, 40, 25]. The culmination of these works is the result by F. Rodriguez Hertz, Z. Wang and D. Fisher, B. Kalinin, R. Spatzier [55, 26] proving that abelian higher rank Anosov actions on (infra-)nilmanifolds are smoothly conjugated to algebraic models, completely resolving the question of global rigidity of abelian higher rank Anosov actions on these manifolds. Relaxing the Anosov assumption leads to the question:
When are partially hyperbolic actions on nilmanifolds by affine maps?
These actions have been remarkably resistant to classification results. Even local rigidity for algebraic partially hyperbolic actions on (non-toral) nilmanifolds has been open for a long time until recent advances by Z. J. Wang [66]. In the global Anosov setting, any higher rank action is topologically conjugated to an affine action by the global topological rigidity for Anosov diffeomorphisms [27, 47]. Because of this, the key problem to solve is to upgrade the regularity of an already existing topological conjugacy. In contrast, for partially hyperbolic diffeomorphisms there is no global topological rigidity. In fact, there are nilmanifolds on which a generic partially hyperbolic diffeomorphism can not be conjugated to an affine model (for example, the manifolds considered in Theorem A). The reason for this is that affine partially hyperbolic diffeomorphisms always have isometric center whereas this is a very special property for general partially hyperbolic systems. As a consequence, when we study the global rigidity of partially hyperbolic actions, a significant problem to solve is the existence of a topological conjugacy. However, once the existence of a topological conjugacy is proved it turns out that upgrading to a smooth conjugacy follows similarly to the Anosov setting (see Theorem 1.2 and Section 8). In this paper, we produce an initial result towards answering the global rigidity question for partially hyperbolic actions.
In Theorem A we prove the first global rigidity result for higher rank abelian actions on nilmanifolds with one partially hyperbolic element. The nilmanifolds under consideration are products between tori and Heisenberg nilmanifolds. These manifolds are, in a sense, the simplest for studying partially hyperbolic diffeomorphisms (with dimensional center). The reason for this is that the affine models of partially hyperbolic systems on these manifolds simultaneously satisfy three important properties, (i) they have dimensional center direction, (ii) the center leaves are compact and (iii) these systems are accessible (see Section 2.1). This allows us to use significant portions of the partially hyperbolic theory when studying these systems. In contrast, when studying Anosov actions the simplest manifolds are tori. However, there are no accessible affine partially hyperbolic systems on tori, so studying global rigidity for partially hyperbolic actions on tori (that is not derived from Anosov) becomes very difficult because many of the tools from partially hyperbolic theory are not applicable.
The questions of local and global rigidity of higher rank actions can also be studied for different types of actions, either dropping the assumption that the action is abelian, or dropping the assumption that the action should have some hyperbolicity. Local rigidity has been obtained for large abelian parabolic actions, with no hyperbolicity [17, 15, 65, 13]. Removing the assumption that the action should be abelian, we can study the actions of higher rank lattices in semi-simple Lie groups, see for example [24] and the references therein. In fact, the rigidity result for Abelian actions in [43] was used to obtain local rigidity of action on tori. When considering rigidity of Anosov lattice actions on nilmanifolds, there are also global results, see for example [10]. A key point in [10] is that any conjugacy between the hyperbolic lattice action and the algebraic model also conjugates the action of a large abelian subgroup to some algebraic abelian action. So, the results of [55, 26] can be applied to improve the regularity of the conjugacy. Considering the main results of this paper, see Theorem A, a natural question is: are higher rank partially hyperbolic lattice actions on nilmanifolds always by affine maps? Conjecturally this question should have an affirmative answer (see [30, Conjecture 5]). In [46] H. Lee and the author show, by using results from this paper, that the question has an affirmative answer when the manifold is a Heisenberg nilmanifold.
1.1. Global rigidity of partially hyperbolic actions
Let be a simply connected step nilpotent Lie group. That is, the lower central series , , terminate at , . Given a lattice we define the associated compact nilmanifold as the quotient . Compact nilmanifolds have associated groups of automorphisms and affine maps
(1.1) | |||
(1.2) |
By automorphism rigidity of nilpotent lattices [51] we can, equivalently, define . An automorphism is said to have a rank factor if there is some quotient of such that descends to and the induced map factor through a map . A homomorphism is higher rank if it has no rank factor. More generally, given a smooth action we have an induced map . We say that is higher rank if the induced map is higher rank.
A diffeomorphism is partially hyperbolic if there is a invariant splitting such that is exponentially contracted, is exponentially expanded and the behaviour along is dominated by the behaviour of along and (for a precise definition, see Section 2.1). We will need a technical assumption on the stable and unstable foliations and , tangent to and . We say that and are quasi-isometric in the universal cover if the metric along the leaves of the foliations, after we lift them to the universal cover, is comparable to the ambient metric (see Definition 2.1). If the center bundle is the trivial bundle then is Anosov. The main result of this paper is an extension of the results of [55] to certain nilmanifolds by weakening the assumption that is Anosov. Instead, we assume that the action contains a partially hyperbolic element.
Theorem A.
Let be a step nilpotent Lie group with , a lattice and the associated nilmanifold. Let be a smooth higher rank action with such that is partially hyperbolic and satisfying
-
(i)
has dimensional center,
-
(ii)
the stable and unstable foliations , are quasi-isometric in the universal cover.
Then is conjugated to some affine action .
Remark 1.
Condition in the theorem is a technical assumption that guarantees that is fibered (see Theorem 1.1). Motivated by results in [34, 33, 35], it seems plausible that is always satisfied. Moreover, in [46, Lemma A2] it is shown that if is topologically conjugated (or more generally, leaf conjugated) to some affine then condition is satisfied. It follows that satisfies the assumptions of the theorem if satisfies the conclusion of the theorem, so the theorem is sharp in this sense. It also follows that if there are exotic partially hyperbolic systems that do not satisfy , then there exists no global rigidity result for these systems.
Remark 2.
With as in Theorem A the group can be written as , , where is a Heisenberg group. The nilmanifold is also a product of a Heisenberg nilmanifold and a torus. On these manifolds there exists no Anosov actions since the derived subgroup, , is isometric for any automorphism. So Theorem A is the only global rigidity result on these manifolds, since [55, 26] do not apply. In fact, to the author’s knowledge, Theorem A is the first global rigidity result for abelian actions assuming only one partially hyperbolic element.
Remark 3.
In principle the proof of Theorem A should work for step with as long as . In this case the quasi-isometric assumption, assumption , would have to be changed. This is a work in progress.
1.2. Applications to centralizer classification and centralizer rigidity
Given a diffeomorphism on a closed manifold we define its smooth centralizer as the group of diffeomorphisms that commute with . That is, we define
(1.3) |
We are interested in two questions about the group :
-
(i)
What are possible groups that arise as for some ?
- (ii)
In this level of generality, questions and are difficult (or possibly impossible) to answer. Instead, we fix for some , and consider questions and for those that are close to . We call the question of local centralizer classification and the question of local centralizer rigidity around . These questions were raised and addressed by Damjanović, Wilkinson and Xu in [20] where the authors study perturbations of time map of geodesic flows on negatively curved manifolds and trivial circle extensions of hyperbolic automorphisms. In [5] the authors study local centralizer rigidity of time maps of Anosov flows on manifolds, generalizing results from [20] in the context of manifolds. Another generalization of results from [20] was obtained by W. Wang in [69], where semi-simple Lie groups of higher rank were studied instead of rank simple groups. For ergodic toral automorphisms, Gan, Xu, Shi and Zhang studied partially hyperbolic diffeomorphisms on homotopic to an hyperbolic automorphism [28]. In [57] the author studies local centralizer classification and rigidity for some partially hyperbolic, irreducible222An automorphism is irreducible if the characteristic polynomial is irreducible in . toral automorphisms.
If is partially hyperbolic with (uniquely integrable) center foliation , then we obtain a normal subgroup , the center fixing centralizer:
(1.4) |
From [21, Theorem 5], if is sufficiently big and is fibered (see [21, Definition 1]) then is smoothly conjugated to an isometric extension of an Anosov map. Combining this with Theorem A we completely classify the centralizers of diffeomorphisms close to affine partially hyperbolic maps.
Let be the dimensional Heisenberg group and a compact Heisenberg nilmanifold. We have a natural fibration
(1.5) |
where we refer to as the base of . Any affine map on descends to an affine map on and from the group relations in any automorphism induces an element of on . Conversely, any defines an element of , see Section 2.2. Given we denote by the induced automorphism on . Before stating the theorem we define for any , with irreducible, hyperbolic induced map on the base , the natural number
(1.6) |
Lemma A.3 explicitly calculates the number , and if , then .
Theorem B.
Let be a compact Heisenberg nilmanifold and let be partially hyperbolic with dimensional center and irreducible. If is close to then one of the following holds
-
(i)
either is virtually trivial,
-
(ii)
or is virtually in which case is an isometric extension of some Anosov diffeomorphism on ,
-
(iii)
or is virtually and if then is conjugate to some (possibly different) affine map .
Remark 5.
All cases , and occur, so Theorem B completely classifies the centralizer of close to a partially hyperbolic . Case holds generically [6]. Case can be produced by fixing some irreducible, hyperbolic and defining on by where the second coordinate is identified with and is a cocycle over that is not cohomologous to a constant. The last case holds when is conjugate to some affine , so in particular when we take the trivial perturbation .
1.3. Partially hyperbolic maps on nilmanifolds
When proving Theorems A and B, we use a description of partially hyperbolic diffeomorphisms on the nilmanifolds considered in Theorem A. The main property that we show is that, under the assumptions of Theorem A, the system is fibered in the terminology of [4]:
Theorem 1.1.
Let (where we allow ), a lattice with associated nilmanifold . Let be partially hyperbolic and satisfy , from Theorem A. If is abelian we assume, in addition, that the induced map has at least one rational eigenvalue. The following holds
-
(i)
is dynamically coherent with global product structure,
-
(ii)
all foliations , , are uniquely integrable,
-
(iii)
the center foliation have compact oriented circle leaves,
-
(iv)
is fibered over some hyperbolic in the sense that there is some Hölder such that , and is homotopic to the projection ,
-
(v)
there is a finite index subgroup such that if we have where is defined by , is the induced map on homology if is non-abelian,
moreover, if is not abelian then
-
(vi)
is accessible.
Remark 7.
The assumption that has at least one rational eigenvalue is to remove derived-from-Anosov examples since these examples are not fibered.
Remark 8.
Properties and follow from [7].
Remark 9.
This Theorem is similar to the classification of partially hyperbolic diffeomorphisms on dimensional manifolds by Hammerlindl and Hammerlindl-Potrie [34, 33, 35]. In fact, in dimension , using [8], Theorem 1.1 essentially reduces to the main results of [34, 33] (in [33] we must make the extra assumption that the linearization has at least one rational eigenvalue).
1.4. Improved regularity of topological conjugacies between higher rank actions
The conjugacy in Theorems A and B, case , is produced in two steps. First, we construct a topological conjugacy and second we show that the topological conjugacy is . The second step is the content of the following theorem, that may be of independent interest.
Theorem 1.2.
Let be a nilmanifold and a homomorphism. Suppose that is higher rank. If is bi-Hölder conjugate to by and there is some such that is partially hyperbolic and accessible with center , then is a diffeomorphism.
Theorem 1.2 is a generalization of the global rigidity result by F. Rodriguez Hertz and Z. Wang [55] to some higher rank partially hyperbolic actions. In fact, large parts of the results in [55] generalize immediately to partially hyperbolic actions. One exception is that Rodriguez Hertz and Wang use a characterization of Anosov diffeomorphisms due to Mañé [48], to show that many elements of the action are Anosov. This characterization can not be applied in the partially hyperbolic setting. We also change some technical aspects of the proof, removing the use of Pesin theory.
1.5. Description of proofs
Let and be as in Theorem A and the partially hyperbolic element. By considering the Lie algebra of , , it is immediate that takes the form , , where is the dimensional Heisenberg group (for we will consider as the trivial group ). Moreover, under the assumptions of Theorem B has to be a Heisenberg group for some (this follows since any lattice in is, virtually, a product lattice so irreducibility of guarantee that either or ). The proof of Theorem A is divided into three steps, first we show that any as in Theorem A is fibered, then we show that any action as in A is topologically conjugated to some affine model and finally we show that the topological conjugacy can be improved to a smooth conjugacy.
1.5.1. Step 1
The first part of the proof of Theorem A is to show that any element as in the theorem has to fiber over a hyperbolic automorphism of the torus and that is accessible. Both of these properties are contents of Theorem 1.1. First, we obtain a map on , which is a contender for being the map in Theorem 1.1, this is done as in [27]. Second, we show that is injective on the lifted stable and unstable leaves , . By invariance of domain, this implies that the stable and unstable distributions of satisfy , where is the corresponding distribution for the linearization of . Since has center of dimension by assumption we conclude that for . This shows, see Lemma 3.1, that descends to a map . Showing that gives a fiber bundle structure as in Theorem 1.1 is then similar to [7].
Proving accessibility uses a topological argument. Since does not have a virtually abelian fundamental group, and since the kernel of the induced map
(1.7) |
is the center of , there can not exist a connected compact set such that is a finite covering map. This implies, in particular, that can not have a compact leaf. So, the proof of accessibility reduces to proving that if has a non-open accessibility class, then there is a compact leaf. Obtaining a compact leaf is done by studying the holonomies between center leaves in the universal cover induced by the fundamental group, as in [52, map defined on page 71]. If is the closed set such that does not have open accessibility class, then there is an action of on defined by mapping to the unique intersection between the accessibility class of and . We show that the induced action on the image of in has a fixed point if is non-empty. This fixed point corresponds to a compact leaf, which gives a contradiction so must be empty.
1.5.2. Step 2
The remainder of the proof of Theorem A follows an idea by Spatzier and Vinhage [61]: instead of producing the conjugacy directly, we produce a homogeneous structure on that is compatible with . The homogeneous structure on is obtained as the action of a certain quotient of the su-path group (see Section 4). We use the map to define the -path group, , and a natural action of on . The most technical part of the paper is the following theorem from Section 6.
Theorem 1.3.
The system has a unique measure of maximal entropy satisfying .
Using Theorem 1.3 we show that there is a normal subgroup, , of such that is a Nilpotent Lie group that act transitively and freely on . Moreover, the action of is constructed such that is compatible with the action in the sense that the joint action of is through a semi-direct product. We then use the action to produce coordinates on , in which is affine. These coordinates gives a bi-Hölder conjugacy from to some affine action .
1.5.3. Step 3
We finish the proof of Theorem A by proving Theorem 1.2, improving the regularity of from bi-Hölder to . The proof is similar to the proof in [55]. We begin the proof by using results from Wilkinson [70] to show that the conjugacy is smooth along the center . The proof of Theorem 1.2 then follows [55] to show that the component of the conjugacy along some coarse exponent defining a chamber wall for the chamber that contains (see Section 2.2) is smooth. That is, we show that the component of the bi-Hölder conjugacy restricted to and normalized by , denoted where is the coarse group with Lie algebra , is uniformly . Once we know that is smooth, we study the map
(1.8) |
where and the determinant is calculated with respect to some background Riemannian metric. The main observation is that can not vanish for all for any (see Lemma 8.7). This shows that is a submersion for every , so its fibers form a foliation within , denoted . Finally, we construct a invariant distribution transverse to the distribution by using a graph transform argument. Existence of the distributions and allows us to produce new partially hyperbolic elements of the action in a Weyl chamber adjacent to the Weyl chamber containing the first partially hyperbolic element . By induction we produce a partially hyperbolic element in every Weyl chamber. Using that contains many partially hyperbolic elements it follows that is uniformly for every coarse exponent , so is uniformly along and . Since is uniformly along , , and we can apply Journé’s lemma twice to show that is .
1.6. Outline of paper
In Section 2 we go through some of the background results, and basic definitions from partially hyperbolic dynamics and higher rank actions on nilmanifolds. In Section 3 we prove Theorem 1.1. In Section 4 we introduce the path group, one of the main objects in this paper, and show some of its basic properties. In Section 5 we recall the suspension construction of an abelian action and use it, combined with results from [3], to derive an invariance principle for higher rank actions on nilmanifolds. Section 6 is the most technical part of the paper, here we prove Theorem 1.3. In Section 7 we prove that the action in Theorem A is topologically conjugated to some affine action. In Section 8 we prove Theorem 1.2, showing that the topological conjugacy is . Finally, in Section 9 we complete the proofs of Theorems A and B. We also include an appendix, Appendix A, proving some basic properties of higher rank, abelian algebraic actions on nilmanifolds.
1.7. Acknowledgements
The author thanks Danijela Damjanović, Homin Lee, Kurt Vinhage, Amie Wilkinson and Disheng Xu for useful discussion.
2. Background and definitions
2.1. Partially hyperbolic diffeomorphisms
Let be a smooth closed manifold and a diffeomorphism. We fix a smooth metric on inducing a norm . We say that is (absolutely) partially hyperbolic if there is a continuous invariant splitting
(2.1) |
and constants , such that for
(2.2) | |||
(2.3) |
If we can choose the constants such that
(2.4) |
then we say that is bunching. The distributions , and are the stable, center and unstable distributions respectively.
Let be partially hyperbolic. The stable and unstable distributions are always uniquely integrable to foliations and with uniformly leaves, but the center distribution may fail to be integrable. A sufficient condition for being integrable is dynamical coherence. We say that is dynamically coherent if and are both integrable to foliations and . In this case we obtain a foliation tangent to by intersecting . We will denote the distance between two points , , in the leaf metric by . Denote the ball about of radius in by . If is bunching and dynamically coherent then , and have uniformly leaves [36] (or [20, Theorem 7]).
Let be the universal cover of , a foliation on , and the lifted foliation to .
Definition 2.1.
We say that a continuous foliation with leaves of have quasi-isometric leaves in the universal cover if there is a constant such that
(2.5) |
where is the metric along .
Remark 10.
The inequality is immediate since any path connecting and along also connect and in .
Remark 11.
We could have asked in the definition, but this is equivalent to Definition 2.1 since and are comparable on small balls in if have uniformly leaves.
In particular, if is partially hyperbolic (and dynamically coherent), we can apply Definition 2.1 to the lifted foliations , . We can also lift the distributions on to distributions on , also denoted .
Assume now that is dynamically coherent. Since is uniformly transverse to , and have a local product structure. Similarly, and subfoliate and is transverse to , so the foliations and have a local product structure in .
Definition 2.2.
We say that have global product structure [32] if
(2.6) | |||
(2.7) | |||
(2.8) | |||
(2.9) |
When has global product structure we define global holonomy maps in the universal cover . Given and we define
(2.10) |
Since and subfoliate the holonomy maps restricts to maps . The holonomy maps between center leaves descend to holonomy maps between center leaves on (Figure 1). Similarly we define stable holonomies when . When considering holonomies between center leaves then the holonomy maps are [9], and if is bunching then the holonomies , , are [50].
We say that a path is an path if has a subdivision such that is entirely contained in either an leaf or a leaf. If any two points are connected by an path, then we say that is accessible. A set is saturated, , if implies , and saturated if it is and saturated. Equivalently is accessible if the only saturated sets are and . For (or ) we define the accessibility class of
(2.11) |
Define a closed set by if is not open. That is
(2.12) |
If has dimensional center direction, then is laminated by accessibility classes [54, Proposition A.3]. In particular, if has dimensional center and then is jointly integrable to some continuous foliation with smooth leaves (in fact, the foliation will be a foliation if is bunching). In the other extreme, is accessible if and only if , in this case has a unique accessibility class.
2.2. Nilmanifolds and higher rank actions
Let be a (simply connected) Lie group with Lie algebra . We define the lower central series of inductively as
(2.13) |
If there is such that then we say that is nilpotent and the minimal satisfying is the step of . We say that is a step nilpotent Lie group if is step nilpotent. Given a discrete subgroup , we say that is a lattice if the quotient space carries a finite Haar measure . Equivalently, for nilpotent groups [11, Corollary 5.4.6], a discrete subgroup is a lattice if the quotient is compact.
If is simply connected, nilpotent, and is a lattice then we define the associated compact nilmanifold by
(2.14) |
Denote by the normalized Haar measure on and write
(2.15) |
for the natural projection map. If is step then there is a sequence of (normal) subgroups
(2.16) |
The intersection defines a lattice in [11, Theorem 5.2.3], define
(2.17) |
where is a compact nilmanifold and is a fiber bundle. In particular, if is step then we get one (non-trivial) projection map . Since , is abelian, so is a torus. In the case of step nilmanifolds, write
(2.18) |
for the projection, with the base of . The fibers of are which is also a torus. So is a fiber bundle with base and fibers both tori, but is not a torus.
We define the automorphism and affine group of by
(2.19) | |||
(2.20) |
There is a natural map defined by mapping to the automorphism , and each projection induce a map .
Fix a homomorphism
(2.21) |
We say that has a rank factor if there is a nilpotent group , of positive dimension, a surjective homomorphism such that is a lattice in and an automorphism such that for some finite index subgroup we have satisfying , . That is, has a rank factor if there is a factor of where the projected action of is a action (up to finite index). More generally, if is a homomorphism then has a rank factor if
(2.22) |
has a rank factor.
Definition 2.3.
A homomorphism is higher rank if it has no rank factor.
Let be a homomorphism. We say that is a Lyapunov exponent of if there is such that
(2.23) |
The Lyapunov exponents are linear and extends uniquely to , we will consider Lyapunov exponents as linear maps on . The Lyapunov space associated to , , is the subspace where Equation 2.23 hold. For the functional we write . Note that
(2.24) |
Denote the set of (non-zero) Lyapunov exponents for by
(2.25) |
For , define the associated coarse exponent and coarse space by
(2.26) |
If (or ) then (or ) for every so we define as the sign of (or as if ). We also define .
Definition 2.4.
Let be the coarse exponents of and
(2.27) |
Each connected component of is a Weyl chamber of . The kernels are Weyl chamber walls. A wall is a wall of if .
Two coarse exponents, and , are dependent if , otherwise the two exponents are independent. Given any two it is immediate
(2.28) |
so is a subalgebra of . Define the associated group
(2.29) |
In Section 8 we will use that every coarse group has a transverse normal subgroup in the stable group . More precisely, if has stable space , , and
(2.30) |
then is an ideal in [55, Lemma 3.1]. Equivalently, the subgroup is a normal subgroup.
The following two lemmas are well-known, we include proofs in Appendix A.
Lemma 2.1.
If is higher rank then there are at least two independent coarse exponents.
Lemma 2.2.
If is higher rank and is a coarse Lyapunov exponent then the space
defines a minimal translation action on (the translation action by is the translation action of the exponential of the Lie algebra generated by ).
Given a homomorphism , written , we obtain a linearization .
Definition 2.5.
A smooth action is higher rank if the linearization is higher rank.
Fix , and define . With and we define a multiplication
(2.31) |
This makes into a group, the dimensional Heisenberg group. Denote by the symplectic form on . The Lie bracket on is
(2.32) |
Let be a lattice and the associated nilmanifold. For we obtain a map by projecting onto the base, this element satisfies . In particular, if is a coarse exponent of then is also a coarse exponent, so the coarse exponents come in negatively proportional pairs.
In the remainder, we will be interested in groups of the form for some and . These groups constitute all abelian simply connected nilpotent groups and all step, simply connected nilpotent Lie groups with . Recall the Baker–Campbell–Hausdorff formula [11]
(2.33) |
Fix a left invariant metric, , on . Using the Baker–Campbell–Hausdorff formula, it is immediate that for , .
3. Some properties of partially hyperbolic diffeomorphisms with quasi isometric leaves in the universal cover
In this section, we prove Theorem 1.1. We begin by proving that from Theorem 1.1 exists in Section 3.1. In section 3.2 we show that is accessible.
Let be the product of some Heisenberg group and some abelian group, a lattice and the associated compact nilmanifold. If then we write and let be the base projection. If and we have an automorphism with dimensional center, then we let and be the projection from onto (note that if has dimensional center then the center direction is a rational line). Assume for the remainder of this section that satisfy all the assumptions of Theorem 1.1. Denote by the linearization of and the induced map on the base.
3.1. Existence of Franks-Manning coordinates
Write as
(3.1) |
with . Fix a lift , . For let
(3.2) |
Let , and be the stable, center and unstable direction of respectively. We decompose any with respect to the splitting as . Denote by the projection, where is the center of (we do not know, a priori, that has dimension ). Write for the map induced by , then is hyperbolic (if then ). Recall the following well-known lemma.
Lemma 3.1.
There exists a unique Hölder map
(3.3) |
such that . If then , descends to a map homotopic to and .
Proof.
The lemma follows from a calculation showing that satisfy , which has a unique solution since is hyperbolic. If then if is non-abelian (since lie in the center of any automorphism) so is the natural quotient by . The lemma follows since is invariant. If is abelian, then is some dimensional rational line (since we assume that have at least one rational eigenvalue) and the last conclusion follows. ∎
Lemma 3.2.
If , , then if and only if . That is is injective. Moreover, for , so descends and is hyperbolic.
Remark 12.
We prove the lemma when is non-abelian. The proof when is abelian simplifies since all terms from brackets vanish.
Proof.
Assume that , for the other case we reverse time. Let . Write where . With respect to the decomposition , decompose . If then for all , so independently of . On the other hand, . So to show that is injective on , it suffices to show that as if .
Suppose for contradiction that and uniformly in . From our definitions
or if we take logarithms
(3.4) | ||||
(3.5) |
Using 3.5 we estimate
(3.6) | ||||
(3.7) |
with constants that only depend on . Since is contracting on there is such that , or
(3.8) |
uniformly in . We have by assumption, so for some possibly larger we obtain
(3.9) |
After possibly enlarging again, we have
(3.10) |
On the other hand, the assumption that is quasi-isometric implies that there is some and such that
(3.11) |
If then 3.10 and 3.11 gives a contradiction for sufficiently large, so .
Since , , is injective it follows by invariance of domain that . On the other hand, we have
(3.12) |
or , so . This implies , which only hold if , , since . That is hyperbolic follows by Lemma 3.1. ∎
Remark 13.
We will make no notational distinction between the map and the induced map .
Lemma 3.3.
For every the map , defined by
(3.13) |
is a homeomorphism. For any , the map is uniformly bi-Hölder for fixed .
Proof.
By Lemma 3.2 is injective so is injective. Since and have the same dimension, it follows by invariance of domain that has an open image and is homeomorphic onto its image. In particular, the image of contain some ball around in (to make well-defined we take the maximal possible ). Given we have
(3.14) |
from which it follows that is invariant. Moreover, and vary continuously in , so is open. Combined with invariance and the fact that is compact, we find such that for all . Assume now , the other case follows by reversing time. We have
and letting , using that expand , we obtain .
So is a homeomorphism. Since is Hölder, is Hölder in and . The set is compact in , so we define as the minimal radius such that the closure of contain . Since vary continuously the map also vary continuosly in . If , then is such that if satisfy then . Let and such that . Let satisfy . There is such that , and only depends on . We have
Fix such that for all . For we obtain
(3.15) |
so is uniformly Hölder. Given and
(3.16) |
or if we choose , then
(3.17) |
which shows that is uniformly Hölder on any ball of radius . By covering any ball of radius with balls of radius , the lemma follows. ∎
Lemma 3.4.
If is a curve that is tangent to (or ) then (or ).
Proof.
Let be tangent to . Write . For
(3.18) |
so . In particular, if for then
(3.19) |
Let be defined by . Since
we have uniformly in . As in the proof of Lemma 3.2 it follows that we also have for some (possibly larger) constant . Let be a curve tangent to and denote the end-points of by and . We find and such that (this corresponds to choosing a two-legged path from to in ). By the reverse triangle inequality
(3.20) |
Since and lie in the same unstable leaf and have quasi-isometric leaves, for some and . But is a curve along from to , so
(3.21) |
where is the length of and . Finally, uniformly for since and lie in the same stable leaf. Equation 3.20 implies
(3.22) |
for some constant . If then we obtain a contradiction for large enough. We conclude that . That is, so , which implies
(3.23) |
proving the lemma for . The lemma follows for by reversing time. ∎
We can now prove the first five points of Theorem 1.1
Proof of Theorem 1.1.
Dynamical coherence of follows from [7]. Any curve tangent to satisfies by Lemma 3.4, so and is a union of leaves. We claim that is path-connected, which proves that . Given any there is a unique intersection (since maps homeomorphically onto under ). Since is tangent to and is tangent to the map
(3.24) |
is continuous. Since is surjective and is path-connected it follows that is path-connected. Properties and follows. Using
we obtain . Since descends to a map the fibers are compact. We define
(3.25) |
where is the linearization of . For we have
(3.26) |
where we have used and . So, if we fix a generator of then we can orient by letting . This is a well-defined orientation of since have no fixed points. That are circles follows since they are compact dimensional manifolds.
Let be small and fix . We denote by , and . With small enough we define
(3.27) |
by the unique holonomy first along then in . We obtain a map
(3.28) |
this map is smooth along since the holonomies are (where depends on the bunching). That semiconjugates (a finite index subgroup of) the centralizer onto its linearization is immediate since is (essentially) unique homotopic to (note that the uniqueness in Lemma 3.1 implies that is unique modulo the fact that we could change to where ). Indeed, for any we let be the induced map on by its linearization and let . Then is homotopic to and we still have
(3.29) |
so where is a fixed point for . Define
(3.30) |
Since and has finitely many fixed points has finite index in . For and we have so . It follows that
(3.31) |
or . ∎
3.2. Proof of accessibility
In this section, we show the last point of Theorem 1.1. For , define by
(3.32) |
which is well-defined by point of Theorem 1.1. A calculation shows
Recall that we denote by and the complement of open accessibility classes. The set is closed and saturated. Since is dimensional the set is laminated by accessibility classes, denoted , [54]. The union of open accessibility classes is invariant, so is invariant. Moreover, maps accessibility classes to accessibility classes so . Given and we have
so restricted to the map defines a group action of , see also [52, Lemma 6.1]. Before starting the proof we will need an elementary, but important, auxiliary lemma on actions on the circle.
Lemma 3.5.
Let be orientation preserving homeomorphisms on the circle and let be a compact subset that is invariant by and each . Moreover, assume that on and that there is some hyperbolic integer matrix such that
(3.33) |
Then the action generated by on , , has a periodic point. That is, there is a point and a finite index subgroup such that for .
Remark 14.
The condition in Equation 3.33 says that joint with form an Abelian-by-Cyclic (AbC) action on .
In the proof, we will use the following two lemmas whose proofs are standard, but we include them for completeness.
Lemma 3.6.
If is an orientation preserving homeomorphism on the circle with zero rotation number, , and is a compact invariant set, then have a fixed point in .
Proof.
If has zero rotation number then for any the sequence converges to a fixed point of as . For any the sequence lie in since is invariant. By compactness of any limit point of also lies in , so has a fixed point in . ∎
Lemma 3.7.
Let be orientation preserving homeomorphisms of the circle and assume that there is a and invariant probability measure . Then the rotation numbers satisfies .
Proof.
Write , where . Recall that if is a invariant measure then we obtain the rotation number of as
(3.34) |
Similarly we obtain the rotation number of . The measure is invariant and , so we can write the rotation number of as
where the second to last equality use that is invariant. ∎
Proof of Lemma 3.5.
Since the action is abelian on it has an invariant measure on . By Lemma 3.7 the rotation numbers satisfy
(3.35) |
for all integers . Since preserves orientation, conjugacy invariance of rotation number and Equation 3.33 implies
(3.36) |
Or if we denote the map by , then we can write . Using Equation 3.35 we obtain
(3.37) |
for all . Since is hyperbolic is invertible over the rationals. So there is a finite index subgroup such that for all . Let be generators. By Lemma 3.6 the map has a fixed point in . Since commute with within it follows that preserve the compact set . So, if we apply Lemma 3.6 once more we see that the set
(3.38) |
is non-empty. Proceeding by induction, we find a point that is fixed by , and therefore by . Since has a finite index in the lemma follows. ∎
Recall that is the linearization of and the fixed part of is (Equation 3.25).
Lemma 3.8.
Assume that . There is a finite index subgroup and such that for .
Proof.
Fix generators . Let be such that . Identify with . Since is central in we can identify with circle diffeomorphisms. We also identify with a circle diffeomorphism (by our choice of and the fact that is fixed we have ). Let , which is compact, invariant, invariant, and non-empty. Any act trivially on (and therefore ) under , so the action on factor through . Moreover, satisfy so the assumptions of Lemma 3.5 are satisfied with and . Therefore there is a finite index subgroup of that admits a fixed point on which implies the lemma. ∎
An immediate corollary of Lemma 3.8 is that there is a compact leaf.
Lemma 3.9.
If , or equivalently if is not accessible, then there is a compact leaf intersecting each center leaf times.
Proof.
For any the map
(3.39) |
is a homeomorphism by points and in Theorem 1.1. Choose as in Lemma 3.8 and let be of finite index such that for all . Note that has finite index in . Define
(3.40) |
Since for all there is for each some such that . In particular, . Since is a lattice in and we obtain a homeomorphism the set is compact. Since is homeomorphic to the lemma follows. ∎
We can now prove the last claim of Theorem 1.1
4. Action of the su-path group
In this section we introduce and prove basic properties of the path group . The path group naturally acts on (Definition 4.1). The group , its various subgroups, and its action on will be the key object in the following sections.
4.1. The su-path group
Let be a smooth action satisfying the assumptions of Theorem A. Moreover, let the action defined by from Theorem 1.1, the partially hyperbolic element, and let be the linearization of . Denote by and the stable and unstable distributions for .
Definition 4.1.
We define the path group as the free product
(4.1) |
If is a word in then we define to be the sum of all factors in . We define the normal subgroup .
Given any pair of negatively proportional course Lyapunov spaces, , , of , we define the path group
(4.2) |
with if is not a coarse exponent. We also define the complementary path group
(4.3) |
It is immediate that , . The following well-known lemma on free products will be useful.
Lemma 4.1.
Let be vector spaces, and the map defined by
(4.4) |
Then and any can be written with , and .
Proof.
For we have
Note that so consists of pairs. By induction we find such that
(4.5) |
This proves the last part of the lemma. Since for each , we have . In particular, if then and , so . ∎
Definition 4.2.
For we define (or ) by , where is defined in Lemma 3.3.
Remark 15.
By Lemma 3.3 the map is well-defined.
Lemma 4.2.
The map , , is a Hölder action that satisfies . The action naturally descends to and if , is the automorphism defined by , then . Finally, , so semi-conjugates to the standard translation action along on the base.
Proof.
That defines an action is immediate from the definition. Indeed, for
so if we subtract then . Applying on both sides of the equality yields . This also shows that . Given we have which implies , so descend to . For we have for some (that is fixed by ). It follows that
(4.6) |
or with
(4.7) |
Next, we show that is Hölder. Let , the other case is similar. Since is a bi-Hölder homeomorphism (Lemma 3.3) it is immediate that is Hölder in . The foliations and are uniformly transverse, so we find and such that for with we have ,
(4.8) |
If then Lemma 3.4 shows that , so
or . That is, preserve the foliation . Given
(4.9) |
with and as in Equation 4.8. So, it suffices to show that is Hölder along and . For
or . Since is Hölder and is uniformly Hölder
(4.10) |
so is Hölder along . Given we have since preserve . On the other hand, by the definition of . So . The unstable Holonomy is (uniformly) Hölder [50], so is Hölder along . ∎
Definition 4.3.
Remark 16.
We make no notational distinction between the action on and . It is clear that the action on covers the action on in the sense that the projection intertwines the two actions.
Lemma 4.3.
We have . That is semiconjugates the action onto the translation action on (and ).
Proof.
By induction, it suffices to consider . The Lemma follows from Lemma 4.2. ∎
Lemma 4.4.
For any the homeomorphism preserve the center foliation, . Moreover, if with , and
then and the map coincide with the composition
(4.12) |
That is, we have
(4.13) |
If is bunching then holonomies between center manifolds are smooth, so is along for all .
Proof.
Lemma 4.5.
We have if and only if for every .
Remark 17.
When then Lemma 4.5 shows that for every , so is the (homotopically trivial) center fixing part of .
Proof.
The lemma is immediate from (Lemma 4.3). ∎
Lemma 4.6.
If is accessible, then the action is transitive on (and ) for all (and ).
Proof.
Since is accessible for every , and if and only if (Lemma 4.3). Given write . Then . It follows that
and since is uncountable and is countable there is at least one such that . If we fix some then
For any we have so , or . Given any we define a path , , from to , so is path connected. The image is an interval in since it contains at least distinct points and is path connected. We claim that is an interior point in this interval. If is not an interior point, then or for some . We will assume that one of the first two cases holds the other two cases are similar. Let and let , then . Since and preserves orientation we have
(4.14) |
which would imply if is an end point of . After applying we obtain . This is a contradiction since we assumed . The point is interior in and was arbitrary, so the orbit of under is open. This holds for every and is connected, so . The second part of the lemma follows.
The first claim follows from the second part. Indeed the second part implies that for any the orbit of is open in . Connectedness of implies the first part of the lemma. ∎
Lemma 4.7.
We have and preserve , , , , and .
5. An invariance principle for higher rank Anosov actions
Let be any nilmanifold and a higher rank action. We will assume that is the restriction of some map . Let be a Hölder fiber bundle over with fibers uniformly for some (we allow ). We will assume throughout this section that is compact, and therefore have compact fibers.
Definition 5.1.
We say that is a cocycle over if is a action covering . Moreover, is a cocycle if is uniformly .
For a cocycle over we write for the map . For each coarse exponent of we have a translation action , for .
Definition 5.2.
A cocycle has translations if there is a Hölder action covering such that
(5.1) |
for any .
Our interest in cocycles over algebraic actions comes from the following lemma.
Lemma 5.1.
If is as in Theorem A, with , then is a cocycle over that admit translations for every coarse and .
The main result of this section is a sufficient condition for the translation action to preserve a invariant measure.
Theorem 5.1.
Let be a cocycle, , over . Let be a invariant probability measure projecting onto , , and the Lyapunov exponents of along the fibers of . If
(5.2) |
then is invariant.
Remark 18.
In Theorem 5.1 we assume that is the restriction of some homomorphism . This is without loss of generality after possibly dropping to a finite index subgroup.
To apply results from [3] it will be convenient to reformulate invariance of into essential holonomy invariance. Let , and . Since cover , we define
(5.3) |
We say that is the holonomy between and .
Definition 5.3.
Let be invariant such that and let be the disintegration of over . We say that , or , is essentially holonomy invariant if there is a full measure set such that for .
Lemma 5.2.
Let be invariant and projecting onto . If is essentially holonomy invariant then is invariant.
Proof.
Let be a full measure subset such that for . Let and so that for . If then
so is invariant. ∎
5.1. The suspension construction
Fix a higher rank action , a cocycle over , and a measure as in Theorem 5.1. We recall the definition of the suspension of an action .
Definition 5.4.
Let be defined by . We define the suspension of as
Given we denote by the equivalence class of in . We also define a natural action on by . Since
the action descends to an action on . Moreover the map descends to a map with fibers . The map semi-conjugates to the natural translation action on .
Given any invariant measure on we define a measure on as follows. For each we choose some such that . Let be defined by . Define a measure on by
(5.4) |
Given any we have . So invariance of implies
showing that is well-defined. Define a suspended measure by
(5.5) |
One checks that is invariant.
In the remainder of this section we denote by the suspension of with action and by the suspension of with action . We also denote by the suspension of and the suspension of . Note that is a volume on . Let be a homomorphism such that
(5.6) |
We suspend the actions and as
(5.7) |
For any we have
(5.8) |
so is a well-defined action on that acts in the fibers of . Similarly the action is well-defined on . Define by
(5.9) |
Since semi-conjugates onto , is well-defined. The following lemma is immediate from our definitions.
Lemma 5.3.
Let , , , and be as above. The following holds
-
(i)
the map is a Hölder fiber bundle with uniformly fibers. In fact, for any the restriction coincides with using natural identifications of and ,
-
(ii)
the map is a cocycle over ,
-
(iii)
the Lyapunov exponents for coincide with the Lyapunov exponents of ,
-
(iv)
the Lyapunov exponents along the fibers of for coincide with the fiberwise Lyapunov exponents of ,
-
(v)
the map semiconjugates to .
Proof.
Point follows from the analogous properties of since is defined in the fibers of . That conjugates to is immediate from its definition: . That is along the fibers of is immediate since is along the fibers of (note that the identifications , , defines a smooth structure on the fibers of in which is uniformly ). Points and holds for , and any functional is determined by its values on a lattice, proving and . Point is immediate from the definitions and the fact that conjugate to . ∎
Define holonomies along the orbits of as in Equation 5.3. That is, if , then
(5.10) |
We say that (or the disintegration ) is essentially holonomy invariant if there is a full measure set such that
(5.11) |
The key fact about the suspension, is that holonomy invariance of implies holonomy invariance of . So Theorem 5.1 follows by holonomy invariance of (by Lemma 5.2).
Lemma 5.4.
The measure is essentially holonomy invariant if and only if is essentially holonomy invariant.
Lemma 5.4 is immediate from the following lemma.
Lemma 5.5.
We have . The disintegration of over is given by
(5.12) |
where is the disintegration of over .
Proof.
By construction we have , so
If we define then
(5.13) |
where we have used for . So is well-defined. We calculate
which proves that is a disintegration of over . ∎
Proof of Lemma 5.4.
If is essentially holonomy invariant, then we find such that for . Letting be the image of in , one direction in Lemma 5.4 follows from the formula in Lemma 5.5. For the converse direction, let be such that for . Since we have
for almost every . For any , and we have
Similarly, . Since maps fibers of to fibers of , it follows that . With and Lemma 5.5
for . Choosing such that , we see that is essentially holonomy invariant. ∎
5.2. Proof of Theorem 5.1
By Lemmas 5.2 and 5.4 it suffices to show that the disintegration of the suspension of is essentially holonomy invariant. We will use the following general criteria for obtaining holonomy invariance, proved in [3, Proposition 4.2] (or [3, Corollary 4.3]).
Theorem 5.2.
Let be a volume preserving diffeomorphism on a closed, smooth manifold with an invariant contracting smooth foliation . Let be a Hölder fiber bundle with uniformly fibers and a map covering such that is uniformly along the fibers of . Assume that admits holonomies in , that is for every there is a map satisfying , and in [3, Section 2.4]. Let be an invariant measure on projecting onto volume. If the exponents of along the fibers of are then the disintegration of is essentially holonomy invariant. That is, there is a full volume set such that for .
Proof.
The theorem would follow immediately from [3, Proposition 4.2] if the foliation coincided with the stable foliation of (in the sense of [3, Section 4.1]). However, following the proof, it suffices that is contracting. In fact, since is a contracting foliation it is standard to produce a measurable partition subordinate to (see for example [45]) which simplifies the proof. ∎
6. Invariant structure in the center direction
Let be a smooth action satisfying the assumptions of Theorem A. In this section we prove Theorem 1.3: , and , have a unique measure of maximal entropy. Moreover, if is the measure of maximal entropy then and the disintegration of is invariant under stable and unstable holonomy. Equivalently [3, 56] we show that the center exponent vanish . The proof of Theorem 1.3 is by contradiction, so we assume that . The proof splits into two cases. First, we have a generic case when the kernel of does not coincide with the kernel of some exponent of . Second, we have an exceptional case when for some exponent of . The first case is dealt with by using Theorem 5.1 and Lemma 5.1. The second, more technical, case is dealt with by studying the circle dynamics induced by the holonomy maps on the center leaves. Suppose that has the same kernel as . We begin by showing that the action commute with the action. This implies that either or act transitively on center leaves (see Lemma 6.2). If act transitively on center leaves then Theorem 5.1 can be applied, as in the generic case. If acts transitively on center leaves, then we show that acts minimally on . We use the minimality of the action, and the fact that commute with to produce a continuous action preserving that commutes with . This shows that the exponent must vanish, a contradiction.
Denote by the invariant measures projecting to volume
(6.1) |
Equivalently the measures are precisely the measures of maximal entropy for [56]. From [56] the set is finite so we may assume, after possibly dropping to a finite index subgroup, that consist of invariant measures. Assume for contradiction that for some . This implies for all [56].
Lemma 6.1.
For any two we have where . Moreover, there is a full measure set such that for any we have with in the orientation of such that is the stable or unstable manifold for some in .
Proof.
We sketch the construction of measures in [56]. Let and be the disintegration of with respect to the center foliation. The measures are atomic almost everywhere since and has dimensional leaves. Denote by the invariant foliation (contracting or expanding) manifolds in defined almost everywhere. Let be such that exists and is atomic for each . For let
(6.2) |
Let be the positively oriented endpoint of . Define a new measure by and . Then and is ergodic, so . For any such that , is a stable manifold for . If , then any point in lie in the stable manifold for both and , which is a contradiction. It follows that implies , or for some (note that since there are no measure with zero center exponent [56]). The first part of the lemma follows for measures constructed as above. Since [56] the construction of new invariant measures outlined above can only produce new measures finitely many times. This proves the last part of the lemma, since if the invariant manifolds did not cover the center leaves, then we could proceed the construction. This also proves the first part of the lemma since the measures constructed above have invariant manifolds covering the entire center leaves for almost every . ∎
6.1. Generic case of Theorem 1.3
6.2. Exceptional case of Theorem 1.3
Now we deal with the exceptional case of Theorem 1.3. Fix and assume that for some Lyapunov exponent of . Denote by the corresponding coarse Lyapunov exponent. We will need two preliminary result on circle maps.
Lemma 6.2.
If are two path-connected groups such that for all then either or .
Proof.
We have , , or since is path-connected. Write . If then and are fixed by since is orientation preserving (and therefore fix the endpoints of the invariant interval ). So, and . If then , so . Since is path-connected is an interval that contain and , so or . Assume that . Since is fixed by we have so . ∎
Lemma 6.3.
Let be compact such that
-
(i)
there is a subgroup , that acts transitively, with subgroup ,
-
(ii)
if and satisfy then ,
-
(iii)
if satisfy for then ,
-
(iv)
there is a compact subset such that for every .
Then or is finite.
Proof.
The group act transitively and freely on by , and . Combining this with it follows that is a compact group, so preserves a measure on . From Lemma 3.7 it follows that the rotation number is a homomorphism. If for , then fix a point in by Lemma 3.6, so by we have . It follows that, if we view , is injective. The image is compact, so either or . In the second case, since is injective, we have . In the first case, is injective and surjective, so a homeomorphism. It follows that is homeomorphic to a circle, so is a local homeomorphism by invariance of domain. In particular, is both open and closed. Since is connected it follows that . ∎
Lemma 6.4.
The action of commute with the action of .
Proof.
By induction it suffices to consider and for independent of . Assume , the other case is identical. Let . Fix
which is a non-empty cone since and are independent. Let be the full measure set from Lemma 6.1. Given let . We have
The action is Hölder by Lemma 4.2, so from or choice of there is uniform such that for any
In particular, lie in the stable manifold of for any with . Assume for contradiction that . Since lie in the same stable manifold Lemma 6.1 implies
for some . So, for any . Since is independent of we find such that for any and for any . Since has the same kernel as we also have . This is a contradiction since
We conclude that for and since has full volume we conclude that holds on a dense set. The map is continuous so this implies . ∎
By Lemmas 6.2 and 6.4 either or acts transitively on for every . We will prove that neither or can act transitively on , which is a contradiction.
Lemma 6.5.
The group can not act transitively on any .
Proof.
Before proceeding we define the space
(6.3) |
and the associated translation action on by . The action is minimal (Lemma 2.2).
Lemma 6.6.
The group can not act transitively on any .
The proof of Lemma 6.6 is by contradiction. As in the proof of Lemma 6.5 we may assume that act transitively on every , we will do this in the remainder. We split the proof of Lemma 6.6 into parts, beginning by proving that acts minimally.
For define
(6.4) |
First, we show that is a minimal set for the action for every .
Lemma 6.7.
For any we have
(6.5) |
that is is a minimal set for the action. In particular, the set form a partition of .
Proof.
Define as those such that is minimal for the action. A standard application of Zorn’s lemma shows that is non-empty. Given any we have , so is invariant. By Lemma 6.4 the action of commute with the action of so, given , the map conjugates the action on to the action on . It follows that if and only if . Since is invariant and invariant Lemma 6.4 implies that is saturated. Accessibility and the fact that implies that . ∎
Lemma 6.8.
The action of is minimal.
Proof.
Since is invariant, Lemma 4.3 implies
(6.6) |
so is compact and invariant by from Equation 6.3. The action is minimal so . It follows that for every .
If and then the assumptions in Lemma 6.3 are satisfied (after identifying ). Indeed, act transitively by Lemma 4.6. Property and follows from Lemmas 6.4 and 6.7. To show property we follow [2, Section 8.3]. For , write
(6.7) |
That is consist of those words in with at most letters, and each letter has length of at most . The following is immediate from the definition
(6.8) |
Let and for fixed . Then is an ascending sequence of compact sets. If and then so . That is, property of Lemma 6.3 holds if for some . Since
(6.9) |
Baire’s category theorem implies that there is such that for (where is the interior in ). Define and (where the complement is in ). If then , so . From Equation 6.9 we obtain
(6.10) |
or
(6.11) |
Since is a descending sequence of compact sets there is such that . Equivalently proving that property of Lemma 6.3 holds. Lemma 6.3 implies that or for every .
We claim that is independent of . Indeed, as in the proof of Lemma 6.7, for we have . So given we find, by accessibility, some that satisfy and in extension (since , and is a partition, Lemma 6.7). We also have (since ) so . It follows that
(6.12) |
for all . If , then the fibers of intersect precisely times. Given we define
Let and small. For , we define as the element in that minimize (if this does not define a unique point, choose an arbitrary minimizer). If then any convergent subsequence of converges to an element of . From our choice of it is clear that any convergent subsequence converge to . So, and is continuous at . Choose small enough such that for all and . For and the reverse triangle inequality implies
where the last inequality use the definition of . In particular, for every , so . Moreover, we have
(6.13) |
Since , is the element that minimize . The same argument that showed continuity at , now show that is continuous at any . So the functions are continuous. Note that restricted to has inverse given by . So, is a finite covering map. In particular, is homeomorphic to . It follows that the map
(6.14) |
is injective with image of finite index. The map
(6.15) |
is injective since its injective after composition with . The group has finite index in and is abelian, but is not virtually abelian so this is a contradiction. We conclude that for every which implies for every . ∎
Lemma 6.9.
The map , is a well-defined surjective homomorphism. Moreover, if and only if .
Proof.
Fix , , and define by
(6.16) |
The function is continuous since rotation numbers vary continuously in the topology [41, Proposition 11.1.6]. Given we have (by Lemma 6.4) and (by Lemma 4.3). Let be the space defined in Equation 6.3. Given let be such that . We have
where the second to last equality uses that the rotation number is conjugacy invariant [41, Proposition 11.1.3]. Since is invariant under and is minimal is constant. That is, has a rotation number independent of . This shows that is well-defined. If then fix some , so Lemmas 6.4 and 6.8 implies that .
Since act transitively and freely on each , it follows that is homeomorphic to . So is a compact topological group. Since is compact the action preserve a measure. That is a homomorphism follows from Lemma 3.7. The image is a compact subgroup, so it is either finite or all of . But can not be finite since is injective and acts transitively. ∎
We can now prove Lemma 6.6.
Proof of Lemma 6.6.
Suppose that act transitively on some . By Lemma 6.9 we can define an action by with chosen such that . The action is free and transitive on each center leaf . Moreover, for and we have
(6.17) |
so by conjugacy invariance of the rotation number . It follows that
(6.18) |
which proves that commute with . This implies that have vanishing Lyapunov exponent along , which is a contradiction. We conclude that can not act transitively on . ∎
We finish the proof of Theorem 1.3 in the exceptional case.
7. Compatible algebraic structure
In this section we produce a topological conjugacy between and an affine action (Theorem 7.1). Let and satisfy the assumptions of Theorem A. By Theorem 1.3 there is a unique invariant measure , with center exponent , that projects to volume.
We begin by using the measure to construct a circle action that commutes with and , preserves center leaves and acts transitively and freely on each center leaf. Moreover, if then for some . This shows that the action of on factor through a nilpotent group with base and center isomorphic to . Lifting this action to we obtain a transitive free action of a step nilpotent group, , on .
Lemma 7.1.
Let and be independent. If and then
(7.1) |
Lemma 7.2.
For any the rotation number of
(7.2) |
is independent of . The map mapping to the rotation number of is a homomorphism with kernel .
Lemma 7.3.
The action of on factor through a nilpotent Lie group that acts transitively and freely on , the action of descends to an action on .
Proof.
Denote by the image of in and the image of in . We begin by showing that the action on factor through an abelian group. As in the proof of Lemma 6.6 we define by for any that satisfies . By Lemma 7.2 is well-defined, continuous, and acts transitively and freely on each center leaf .
As in the proof of Lemma 6.6, commutes with . Let be from Lemma 7.2. Given and we have since has the same rotation number as . It follows that
(7.3) |
which shows that commute with . Let be defined by where is the rotation number of with respect to the natural lift to from Definition 4.3. Lift to , then . It is immediate from the analogous properties of that commute with and .
Let be the image of . Since commute with and since for the subgroup is central in . Moreover, Lemma 4.1 implies that
(7.4) |
so . It follows that is step nilpotent. By Lemma 4.1 we can write any as with , , and . It follows that , so , is surjective. If then we apply and obtain , , Lemma 4.3. If , then we can simplify and obtain . Since is a free action this implies . So is bijective. It is also clear that is continuous. Let and be such that is close to . After applying , it is immediate that is close to and is close to . Writing we obtain
so is close to . Since act freely is close to , so has a continuous inverse and is therefore a homeomorphism. Since is a topological group homeomorphic to , has a unique structure as a Lie group [49, 29]. Finally, is step nilpotent as an abstract group so is a step nilpotent Lie group. ∎
Theorem 7.1.
The diffeomorphism is bi-Hölder conjugate to some affine map where with .
Proof.
Let be the group from Lemma 7.3 and a lift of . For we have by Lemma 4.7. It follows that for every . So, is a continuous autormophism such that for .
Define by if for the identity element . Any two are lifted from so there is such that . Similarly if then so . It follows that is a subgroup of . Moreover, is closed in so is closed.
The map is a homeomorphism by invariance of domain since is bijective. Let and , then
so descends to a map . If for and then we find such that (since the action of on is transitive). It follows that
or . The action of is free, so . That is, we have a diagram
where both horizontal maps are homeomorphisms. The group is a nilpotent Lie group by Lemma 7.3, so is a nilmanifold. It follows that is isomorphic to as a Lie group and is isomorphic to under this map [51].
We claim that the induced map , is affine. Equivalently, , is affine. From the relation , , we obtain
where is chosen such that . It follows that , and therefore also , is affine.
Denote by the conjugacy such that . After conjugating with a translation we may assume that . To finish the proof we show that is bi-Hölder. By uniqueness of we have . Since is Hölder and the inverse of restricted to stable and unstable leaves is Hölder (Lemma 3.3) is bi-Hölder along and . So it suffices to show that is Hölder along and is Hölder along . Write
(7.5) |
with and , . Since and is Hölder, both and are Hölder. The functional equation for implies
or
(7.6) |
We obtain an equation for
with Hölder. It follows that is Hölder [70], so is Hölder. Next we show that is Hölder along . Fix , such that with . Given the Baker–Campbell–Hausdorff formula implies , so
Letting be close to and using that is Hölder along and we obtain
Since for small we have
so for close. It follows that . ∎
8. Rigidity: Smoothness of the bi-Hölder conjugacy
In this section, we prove Theorem 1.2. Let , , , , and be as in Theorem 1.2. We prove Theorem 1.2 under the assumption that is accessible, this is done for two reasons. First, the proof simplifies because we can apply [70] to obtain regularity of the conjugacy along the center direction. In particular, there is no loss of generality in assuming that the center of coincides with the joint center of (see Remark 20). Second, if is accessible then naturally preserves a volume form and (see Lemma 8.2).
If is assumed to preserve a volume form such that then a result similar to Theorem 1.2 still holds, without accessibility. We give a brief sketch of the proof. Let be a lift of the conjugacy. By the argument below is uniformly along and is invertible at each for . Define
(8.1) |
then the fibers of coincides with . In particular, is uniformly along . Moreover, is uniformly along so is uniformly along . By Journé’s lemma [37] is smooth. The map is invertible, so is a submersion. It follows that the leaves of form a foliation, so is a foliation. Similarly, is a foliation. Once we know that is a foliation the arguments in [55, 26], to obtain regularity of along and , can also be used along (note that, a priori, the assumptions of [55, Theorem A.1] are not satisfied for ).
8.1. Dynamical coherence and regularity of center leaves
We begin by proving that is dynamically coherent with , and all uniquely integrable. We use this without mention in the remainder.
Lemma 8.1.
The map is dynamically coherent with , and all uniquely integrable with uniformly leaves.
Proof.
Since is conjugated to , and is uniformly subexponetial along its center , is also uniformly subexponential along its center . Indeed, for any invariant measure the stable Pesin manifold maps into the stable manifold, , of under . Since is invertible . It follows that no exponents are negative along . By exchanging for , no exponent is positive along . By [58] is uniformly subexponential along . Fix lifts , , and to such that . If is a curve tangent to then the length satisfies
(8.2) |
for any . The conjugacy can be written with being invariant. We estimate
for some uniform . With and we obtain
Now, , so
With sufficiently small it follows that . We conclude that is uniquely integrable with leaves given by
(8.3) |
Similarly, is uniquely integrable with . Since is uniformly subexponential along each foliation , and have uniformly leaves, see [20, Theorem 7] (or [36]). ∎
8.2. Volume preservation and smoothness along the center direction
To apply arguments using exponential mixing we need to show that preserves a smooth volume form. We assume that the action is accessible so we show that is along without using the exponential mixing argument from [26] and instead rely on results from [70].
Lemma 8.2.
Let be as in Theorem 1.2, then preserve a smooth volume form . Moreover, the conjugacy is volume preserving in the sense that where is the Haar measure on .
Remark 19.
By Moser’s trick, there is no loss of generality if we assume that .
Proof.
We show that is uniformly along following [70].
Lemma 8.3.
The restriction is uniformly .
Remark 20.
Using Lemma 8.3 we may assume, without loss of generality, that the center of coincides with the joint center of .
Proof.
Let and let be the graph of :
(8.4) |
Given any two we fix a path from to , such a path always exists by accessibility. Denote by the composition of holonomy maps along ( so ). Since is uniformly subexponential along , is bunching so is [50]. Since map , , onto we have where is the composition of holonomy maps along . Define
(8.5) |
Since we have . Moreover, , and were arbitrary, and is smooth so is homogeneous (see [70] for definitions). By [70, Corollary 1.3] is a submanifold. The graph of is and it follows that is also . Finally, is uniformly along since it intertwines the holonomies of with the holonomies of . ∎
8.3. Smoothness of coarse components along the stable foliation
Let be the splitting of with respect to . Denote by , , the subgroup associated to . We have a diffeomorphism defined by . Write with satisfying for all . We decompose with respect to the map
(8.6) |
It is immediate that each is Hölder. Given a coarse exponent we denote by the subgroup associated to .
Let be a coarse exponent along . We decompose further as
(8.7) |
where is the component of along and is the component of along the complementary group (see [55, Lemma 3.1]). The following is proved in [55, Section 3].
Lemma 8.4.
Proof.
8.4. New partially hyperbolic elements: passing the chamber wall
Let be in a Weyl chamber and let be a chamber wall for . Now we start the work of passing the Weyl chamber wall by constructing a partially hyperbolic element in the chamber adjacent to through . We initially follow [55], but change the argument from Section in [55], by not relying on smooth ergodic theory. If then the map is a homeomorphism. Define
(8.8) |
If with and then satisfy
For we write where is chosen continuously and such that . Then is . With this notation
or
If we multiply on the left by and on the right by , then the right-hand side of the equality lie in , but the left-hand side lies in . It follows that both sides of the equality are identity, so for we have
(8.9) | ||||
(8.10) |
Using the fact that the map , , and the map are both smooth the following is immediate, see also [55, Corollary 3.14].
Lemma 8.5.
The map is uniformly along .
Define with . From our definitions it is immediate
So if we prove that is a (local) submersion for every , then the fibers of defines a smooth foliation (within ). This shows that the, a priori only Hölder, foliation is a Hölder foliation with uniformly smooth leaves.
Lemma 8.6.
The map is uniformly .
Proof.
Lemma 8.7.
The map is surjective at every . In particular, the foliation has uniformly leaves.
Proof.
Denote by , then is compact and invariant. Our goal is to show that . Since is surjective it follows by Sard’s theorem that . We will prove that if is non-empty then contains a leaf, which is a contradiction since every leaf is dense (Lemma A.1).
In the remainder, fix some background metric and calculate determinants with respect to the top form induced by . Assume for contradiction that . Fix close to the kernel (we specify later how close) such that contract and . Fix and some subspace of dimension . We also define . The relation implies
(8.12) |
If is a representative of then for some uniform depending on the dimension of . If and is the grassmannian bundle of then is uniformly smooth along . For we have since is not surjective. It follows that there is some constant such that
(8.13) |
for . If , then
(8.14) |
where can be chosen independently of since we let be close to the kernel of . Equations 8.12 and 8.14 implies
Since contract the foliations and we have a uniform bound . We obtain an estimate
With be sufficiently close to we have , so if then
The point was arbitrary so for . The foliation is minimal (Lemma A.1) and is closed so . This contradicts Sard’s theorem. ∎
To show that exists as a continuous bundle we will apply a linear graph transform argument. Denote by the invariant, continuous subbundle tangent to . Let be any continuous bundle that is complementary to within . Fix such that and expands (that is, we chose such that have passed the chamber wall from the chamber that contains ). Write . With respect to the splitting we write
where is projected onto and is projected onto .
Lemma 8.8.
We have .
Proof.
Note that . There is , depending on our choice of , such that for any we have
(8.15) |
Since and (the fibers of are the foliation ) it follows that . That is, Equation 8.15 simplifies
(8.16) |
Since is an isomorphism (of vector bundles after identifying with the trivial bundle ) the lemma follows (after either changing the norm used or exchanging for with sufficiently large). ∎
Lemma 8.9.
The map defined by
has a unique fixed point.
Proof.
Since the lemma follows from Banach’s fixed point theorem. ∎
Lemma 8.10.
There exists an invariant continuous subbundle such that .
Proof.
Let be the unique fixed point from Lemma 8.9. Define . It is immediate that . Given
so . Or since is invertible. That is invariant for all follows by applying the graph transform of on the element . This defines a fixed point, since commute with , and the fixed point is unique (Lemma 8.9) so the graph transform of is . Equivalently, is invariant. ∎
Since conjugates to the following lemma follows by induction.
Lemma 8.11.
Every element defines a partially hyperbolic where the center of has the same dimension as the center of .
Remark 21.
Lemma 8.11 lets us pass the Weyl chamber containing and produce new partially hyperbolic elements in adjacent chambers.
8.5. Finishing the proof of Theorem 1.2
We finish the proof of Theorem 1.2 by showing that is a diffeomorphism. We begin by proving that , , are .
Lemma 8.12.
The maps , , are .
Proof.
It suffices to consider the case . By Lemma 8.5 and Journé’s lemma [37] it suffices to show that is uniformly smooth along . Number all coarse exponents along by . The function can be decomposed with respect to the map (see [55, Lemma 3.2]) as
(8.17) |
Using Lemmas 8.11 and 8.4 it is immediate that is . Moreover, we use Lemmas 8.11 and 8.4 to show that is smooth for all . If we define and assume that is smooth, then we can change the order of products in 8.17 modulo a polynomial in . Applying Lemmas 8.11 and 8.4 once more, is for each . For large enough, using that is nilpotent, it follows that is along . ∎
We are now ready to prove Theorem 1.2.
Proof of Theorem 1.2.
If we show that is then is automatically a diffeomorphism since the Jacobian can never vanish, this would contradict volume preservation of (Lemma 8.2).
By Lemma 8.3 the map is uniformly along . From equation 8.9 we have . Since and are both uniformly along byLemma 8.12, it follows that is uniformly along , so is uniformly along . Similarly is uniformly along . By using Journé’s lemma along and it follows that is uniformly along . Using Journé’s lemma once more along and it follows that is . ∎
9. Proof of main theorems
Proof of Theorem A.
By Theorem 7.1 the action is bi-Hölder conjugated to some affine action . We produce the conjugacy for the special element , but it conjugates the full action into an affine action. This is immediate from the construction of , but also follows from an argument as in [1]. Theorem A now follows from Theorem 1.2. ∎
Proof of Theorem B.
Let and be close to . Write for the induced hyperbolic automorphism. Note that satisfy assumptions and of Theorem A since it is close to (see also [46, Lemma A.2]). In particular, we obtain from Theorem 1.1. Denote by the centralizer of and let be the center fixing, normal subgroup of from Equation 1.4. Define the quotient
(9.1) |
If then so the induced map on satisfy . Since is an isomorphism it follows that . Conversely, if then (Theorem 1.1) so . It follows that each non-trivial represent an element of that project onto a non-trivial automorphism on . In particular, if then the image of in contains a subgroup isomorphic to . Irreducibility of implies that this subgroup in is higher rank, so the action of is conjugate to some affine action by Theorem A. If and then [21, Corollary 18] implies case of Theorem B. Finally, if and then is virtually so case of Theorem B holds. ∎
Appendix A Some algebraic lemmas
In this appendix, we show some basic properties of higher rank algebraic actions on nilmanifolds. The first two lemmas, 2.1 and 2.2, are stated in Section 2.2.
Proof of Lemma 2.1.
If the conclusion does not hold then there is a decomposition so that every is subexponential along and either contract or expand and . If the projected action on the base is rank, then the whole action is rank (and has a rank factor). For any there is such that if satisfies that the eigenvalues of with modulus larger than one have a product bounded by , then have no eigenvalues of modulus larger than .
Let be the kernel of the unique pair of negatively proportional exponents of . If is sufficiently close to then all eigenvalues of will be close to the unit circle, which implies that all eigenvalues of lie on the unit circle. It follows that any sufficiently close to lies in . In particular
(A.1) |
Elements in have all eigenvalues on the unit circle so after dropping to a finite index subgroup of , we may assume that all eigenvalues are . After taking a quotient to remove Jordan blocks the action of is trivial. Since the action factor through a action. ∎
Proof of Lemma 2.2.
The translation action of is minimal if and only if the induced translation action on the base is minimal, so we assume without loss of generality that is a torus. Let be the rational span of , then acts minimally if and only if . If then with and descend to . We have quotiened out all coarse exponents except for one negatively proportional pair, so the factor has only one pair of negatively proportional exponents. By Lemma 2.1 is a rank factor, which is a contradiction. We conclude that so act minimally. ∎
We will need a lemma like Lemma 2.2, but only considering coarse directions that lie in the same stable direction for some element of the action. The following lemma is a consequence of Lemma 2.1.
Lemma A.1.
Let be higher rank. We say that is regular if the center of coincide with the joint center of . Let be regular and be the stable space associated to . Let be a coarse exponent such that is a wall for the Weyl chamber that contains and . Either or the complementary subspace , , defines a minimal foliation in .
Proof.
After projecting to the base, we assume without loss of generality that is a torus . If for then there is nothing to prove, so assume that there is at least one coarse exponent satisfying and . Write for the complementary subspace defined by
(A.2) |
Let be the rational closure of , then is invariant and rational. Each preserves the lattice so . Given a coarse exponent , define for and by
(A.3) |
From this definition it is immediate that
(A.4) |
Our choice of implies that if and . Rewrite
Using
and combining estimates
(A.5) |
If is a sequence in the same Weyl chamber as such that , then
Each satisfies for some uniform . Letting , for , . It follows that for . If is non-trivial then the projected action on does not have two independent coarse Lyapunov exponents. By Lemma 2.1 is a rank factor of . This contradicts the assumption that is higher rank so which proves the lemma. ∎
Lemma A.2.
Let be a free abelian subgroup with Lyapunov exponents . Let be the maximal number of linearly independent Lyapunov exponents (so ). If the intersection of the kernels of all is trivial in then .
Proof.
Let be of degree , monic and with constant term . Let be the roots of (possibly with multiplicity). There is a constant such that either has only roots on the unit circle or
(A.6) |
see for example [22]. We number . Let be the dimension of the Lyapunov space associated to . Given let be the corresponding characteristic polynomial. We obtain
(A.7) |
Suppose that for contradiction. Let be chosen such that every lie in . If is such that then for all . The intersection
(A.8) |
is non-trivial since . The set is a lattice in so we find a sequence such that as but (where is the identity in ). It follows that
(A.9) |
tends to as . With big enough which implies that has all roots on the unit circle. It follows that lie in the kernel of all , so by assumption. This implies that which is a contradiction. ∎
Lemma A.3.
Let be hyperbolic with irreducible characteristic polynomial. If denotes the number of real eigenvalues of and the number of pairs of complex eigenvalues of then .
Proof.
Fix with irreducible characteristic polynomial. Let
(A.10) |
be the vector space of vectors. Let be the induced map on vectors. Note that is a invariant lattice in . Denote by the eigenspace of for . Write , since is a rational subspace of the subgroup is a lattice.
Given the wedge preserves and stabilize in . So, after identifying and we obtain a map defined by . It is immediate that is a homomorphism. Fix eigenvectors such that and . We identify (the complexification of) by so for we have
(A.11) |
where and . If then which implies that preserve the symplectic form that preserve (note that can be chosen such that the symplectic form can be written ). Conversely, if then . Equation A.11 also implies that the Lyapunov exponents of are given by
(A.12) |
It follows that has Lyapunov exponents. Indeed, if takes values in then defines one Lyapunov exponent. If takes values in then and for some , so
(A.13) |
By Lemma A.2 since implies that, at least, one Lyapunov exponent of can be written as a combination of the other exponents. By [42] the rank of is , so
or since , . The converse inequality is clear from Lemma A.2 since if is a Lyapunov exponent of then so is . ∎
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