Generic nondegeneracy for solutions of the Allen-Cahn equation under a volume constraint in closed manifolds
Abstract.
Let be a connected closed smooth manifold with . We adapt the techniques in [MP09] and [GM11] to prove the generic nondegeneracy for solutions of the Van der Waals-Allen-Cahn-Hilliard equation under a volume constraint in .
Keywords. nondegenerate critical points, Allen-Cahn equation, generic result.
2010 Mathematics Subject Classification. 58E05, 35J20.
1. Introduction and main result
Let be a connected closed smooth Riemannian manifold, where . Let be a function of class . Fix . A pair is a solution for the Van der Waals-Allen-Cahn Hilliard equation under volume constraint when
() |
where is a measure induced by defined on the Borel subsets of and is a convenient Sobolev space of functions defined in section 2.
In [BNAP20], the authors establish lower bounds on the number of solutions for in function of topological invariants of for sufficiently small and under specific hypotheses on the potential function . In particular: if only admits nondegenerate solutions, then Morse theory may be applied to prove that it admits at least solutions, where is the Poincaré polynomial of .
Our main result is that under suitable growth conditions for and , this is indeed the case generically with respect to , where and is the space of Riemannian metrics of class on :
This result is obtained by the application of an abstract transversality theorem through an appropriate adaptation of the techniques in [MP09] and [GM11] to the context of this article.
More precisely, we say that a solution for is nondegenerate when the only pair which solves the linearized problem
() |
is the trivial one .
In fact, this notion coincides with the Morse theoretic notion of a nondegenerate critical point for the functional given by
Indeed, is a functional of class for which is a solution for if, and only if, and . Therefore, is a nondegenerate solution for precisely when is a nondegenerate critical point of such that .
For Differential Geometry, interest for the Van der Waals-Allen-Cahn-Hilliard equation under a volume constraint is justified by the results of [PR03], where Pacard and Ritoré showed that one can approach constant mean curvature hypersurfaces by the nodal sets of critical points for as . If we consider critical points without the volume constraint, these sets approach a minimal hypersurface.
Acknowledgement
The author thanks Paolo Piccione for suggesting the topic and discussing drafts of this article.
2. Preliminaries
Basic constructions
Fix . Denote by the Banach space of symmetric 2-covectors on of class . The space of Riemannian metrics on of class is an open convex cone in .
Consider any . induces the following inner products on :
, are, respectively, the Hilbert spaces endowed with , obtained as completions of . Similarly: given , is the Banach space obtained as completion of with respect to the norm
One may check that the norms induced by , on are equivalent. In particular, this implies as sets and that the canonical inclusion is an isomorphism of Banach spaces. The same holds for the canonical inclusion for any . For details, we refer the reader to [Heb00, Proposition 2.2].
Considered setting
Suppose that
(1) |
(2) |
for a certain , where for , for .
Fix . Consider any . Due to the Kondrakov theorem, the canonical inclusion is a compact operator. Set . We define as the adjoint of while considering the canonical Banach space isomorphisms and :
Definition 2.1.
Remark 2.2.
is a compact self-adjoint operator and for any .
Lemma 2.3.
is a map of class , where . In particular,
where is a symmetric 2-covector on of class given locally by
Lemma 2.4.
is a map of class , where . In particular,
is a function of class with suitable growth conditions, so is a Nemytskii operator of class . For details on this argument, we recommend the reference [Kav93]. This implies:
Lemma 2.5.
The Nemytskii operator given by is a map of class . In particular,
In the next definition, we identify the space of constant real-valued functions on with :
Definition 2.6.
Let be given by
Using remark 2.2, we can prove that the set of solutions for is a level-set of :
Remark 2.7.
is a solution for if, and only if, .
Lemma 2.8.
is a map of class . In particular,
3. Proof of main result
Consider the following abstract transversality theorem:
Theorem 3.1.
[HHL05, Theorem 5.4] Let be real Banach spaces and be respective open subsets of . Let be a map of class , where . Let . Suppose that
-
(1)
Given , is a Fredholm map of index , i.e., is a Fredholm operator of index for any ;
-
(2)
is a regular value of , i.e., is surjective for any ;
-
(3)
Let be the canonical embedding and be the projection of the first coordinate. Then is -proper, i.e., , where given , is a closed subset of and is proper.
Then the set is an open dense subset of .
The first step to prove our main result is the lemma that follows, in which we restrict ourselves to nonconstant solutions:
Its proof consists of a direct application of the abstract transversality theorem. Specifically, we consider , , , and . We verify that its hypotheses hold in section 4.
After analysing the constant solutions for , we refine lemma 3.2 to prove our main result:
Proof of Theorem 1.1.
Let and be a neighborhood of in .
is not empty. Indeed, let . If does not admit constant solutions, then . Otherwise, the volume constraint shows that the unique constant solution is . This is a degenerate solution if, and only if, admits a nontrivial solution. This only happens when there exists such that
(3) |
where is the set of nonzero eigenvalues of . is a discrete subset of , so there exists such that and (3) does not hold for any positive integer . This implies .
is an open subset of . Indeed, let . If does not admit constant solutions, the result is a corollary of lemma 3.2. Otherwise, note that and are continuous maps for any positive integer , so admits a neighborhood in in which the constant solutions are nondegenerate. To conclude, is a neighborhood of in for which the respective Allen-Cahn equation does not admit degenerate solutions. ∎
4. Technical steps
For a pair , let be given by We adopt similar notation when fixing other variables.
In lemma 4.2, we shall verify that the first hypothesis of theorem 3.1 holds. With that objective in mind, consider the following preliminary result:
Lemma 4.1.
Let , be given by and be given by . Then is a Fredholm operator of index .
Proof.
is a linear functional, so in . This implies
in .
so
so , so is a Fredholm operator of index . ∎
Lemma 4.2.
Given , is a Fredholm map of index .
Proof.
Fix and let be given by
, where was defined in lemma 4.1. Therefore, it suffices to prove that is a compact operator to conclude that is a Fredholm operator with index . This is indeed the case, because is a compact operator. ∎
Let us examine the second hypothesis of the abstract transversality theorem. Let . To conclude that is surjective, it suffices to show that
(4) |
which we shall prove in lemma 4.4.
The following defines an inner product on :
This allows us to establish the characterization:
Remark 4.3.
Let and . Then
We use this characterization to prove inclusion (4):
Lemma 4.4.
Let . Let be a solution for . If
for all , then .
Proof.
Due to lemmas 2.3, 2.4 and 2.8, the equation on the statement is rewritten
(5) |
where we recall that is a symmetric 2-covector on of class given locally by
An argument with normal coordinates centered at arbitrary which considers specific perturbations of proves that
(6) |
for any . For details, see [GM11, Lemma 12].
On one hand: integrating the equation above (7) yields
(8) |
On the other hand: taking into account (6) and the fact that is a weak solution for ,
If , then is a weak solution for – which only happens with a constant . We do not consider constant solutions, so does not vanish identically. Due to proposition 4.5, are functions of class . Therefore, is a continuous function which does not vanish identically.
In particular, vanishes in a nonempty open subset of . In this context, we can use strong unique continuation ([PRS08, Theorem A.5]) in problem to conclude that . ∎
Proposition 4.5.
Fix and . If is a solution for , then . If it also holds that is a solution for , then .
Proof.
Regularity is a local problem, so we fix a coordinate system where the s are bounded and is the coordinate open subset of . Let be the local expression of . Note that is a weak solution for
where for any .
The third hypothesis is proved analogously as[GM11, Lemma 11]:
Lemma 4.6.
is -proper, where and are defined in theorem 3.1.
Proof.
Given ; let
where are respective open balls in centered at with radius and
Fix a positive integer . Let us prove that is a proper map. Let be a sequence such that , and given , is a solution for .
We claim that has a convergent subsequence. Due to the Kondrakov theorem, the canonical inclusion is a compact operator for any , so converges in up to subsequence to a certain . is bounded, so it converges up to a subsequence to a certain . Arguing as in lemma 4.2, we see that . We can use the Mean Value Inequality and lemma 2.4 to prove that, in fact, . ∎
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