Generating functions for fixed points of the Mullineux map
Abstract.
Mullineux defined an involution on the set of -regular partitions of . When is prime, these partitions label irreducible symmetric group modules in characteristic . Mullineux’s conjecture, since proven, was that this “Mullineux map” described the effect on the labels of taking the tensor product with the one-dimensional signature representation. Counting irreducible modules fixed by this tensor product is related to counting irreducible modules for the alternating group in prime characteristic. In 1991, Andrews and Olsson worked out the generating function counting fixed points of Mullineux’s map when is an odd prime (providing evidence in support of Mullineux’s conjecture). In 1998, Bessenrodt and Olsson counted the fixed points in a -block of weight . We extend both results to arbitrary , and determine the corresponding generating functions. When is odd but not prime the extension is immediate, while even requires additional work and the results, which are different, have not appeared in the literature.
2020 Mathematics Subject Classification:
Primary 05E10, Secondary 20C301. Introduction
Let denote the symmetric group on letters. Recall that a partition is -regular if no part repeats or more times. Let be an algebraically closed field of characteristic . The irreducible modules are labelled by -regular partitions [Jam78, Chapter 11] and are denoted . Define an involution on the -regular partitions by In [Mul79], Mullineux defined a combinatorial map on the set of -regular partitions. He conjectured for a prime that . Almost twenty years later, Kleshchev [Kle96] described and Ford and Kleshchev [FK97] proved the conjecture by proving Kleshchev’s description matched Mullineux’s. The bijection is defined combinatorially on -regular partitions for arbitrary, and can be interpreted similarly using irreducible representations of a certain Hecke algebra [Mat99, Chapter 6.3]. For the sign representation is trivial and the Mullineux map is the identity. Combinatorial properties of this map have inspired much research, often independent of representation theoretic applications.
Let be the alternating group and let the characteristic of be an odd prime . One can count irreducible modules in two ways: group theoretically by counting -regular conjugacy classes of , or by restricting modules from using Clifford theory and counting in terms of fixed points of the map . In 1991 Andrews and Olsson, using Olsson’s work in [Ols92], counted the fixed points of :
Theorem 1.1.
[AO91, Propositions 2,3] Let be prime. The number of fixed points of is the number of partitions of with distinct odd parts, none of which are divisible by .
This answer agreed with the known representation theoretic count for fixed points of , providing evidence for the as-yet-unproven Mullineux conjecture by showing had the expected number of fixed points. Later Bessenrodt and Olsson refined this by computing fixed points in an arbitrary -block of weight w:
Theorem 1.2.
[BO98, Theorem 3.5] Let be an odd prime, and be a self-conjugate -core. For even the number of with and having -core is given by the number of -tuples of partitions with total weight . For odd there are no such partitions.
Our main results are to extend Theorems 1.1 and 1.2 to arbitrary . For odd but not prime it is a simple observation that the original proofs carry over, while for even additional work is needed. The author would like to acknowledge his colleague William Keith for useful discussions about generating functions.
2. The Mullineux Map, -cores and -weights
For a partition with Young diagram , define the rim of to be the boxes along the southeast edge of the diagram, i.e. boxes with . Now consider a subset of the rim defined as follows, and called the -rim. Starting at the top right of the rim, take the first elements on the rim. Then move to the rightmost element of the rim in the next row, and take the next elements. Continue until the final row is reached, observing that the final segment may contain fewer than boxes.
For example if and we have the e-rim:
centertableaux, boxsize=.5cm
\ytableaushort
*7,7,4,4,1,1
*[*(green)]6+1,6+1,4+3,3+1,4,1,1
Let be the number of boxes and be the number of rows in the -rim, so in our example , .
To define the Mullineux symbol , remove the -rim, and then calculate the -rim of what remains to determine . Continue this process until all boxes are removed. Assemble these numbers in an array, called the Mullineux symbol of :
(2.1) |
Notice that is also a partition of the same integer . For example from Figure 2.2 we see that:
centertableaux, boxsize=.5cm \ytableaushort *7,7,4,4,1,1 *[*(green)]6+1,6+1,4+3,3+1,4,1,1 *[*(red)]5+1,3+3,3+1,0+3 *[*(blue)]2+3,2+1,2+1,0+3 *[*(orange)]1+1,1+1,0+2 *[*(purple)]0+1,0+1
Now define if and otherwise, and set Then we have Mullineux’s conjecture (now theorem):
Proposition 2.1.
Let be -regular with Mullineux symbol
Then the Mullineux symbol for is:
It is easy to reconstruct from so Proposition 2.1 gives a combinatorial description of the Mullineux map. For example with as in Figure 2.2
and Thus a fixed point of will have a Mullineux symbol of the form:
(2.2) |
where is even if and only if if and only if .
In his original paper Mullineux described necessary and sufficient conditions for such an array to arise as the Mullineux symbox of an -regular partition:
Proposition 2.2.
Now we can apply Proposition 2.2 to arrays of the form (2.2), i.e. fixed points. The conditions on the in Proposition 2.2 can easily be translated to conditions on the . Thus we can enumerate fixed points simply by counting the suitable partitions .
Definition 2.3.
Define to be the set of partitions satisfying:
-
(i)
-
(ii)
-
(iii)
If then is even.
-
(iv)
If then is odd.
-
(v)
.
Then we have:
Proposition 2.4.
[AO91, Proposition 1] Let be an odd prime. The number of partitions fixed by the Mullineux map is equal to the cardinality of .
The proof of Proposition 2.4 goes through for arbitrary, so to enumerate Mullineux fixed points we need to understand the set . The criteria defining are not easily translated into a generating function. The main theorem (Theorem 2) of [AO91] gives a remarkable enumeration of partitions with difference conditions like this. Observe for odd that is a set of type from that paper, where and . The paper gives a bijection with a set , which in this case is just partitions with distinct odd parts not divisible by , giving Theorem 1.1.
2.1. -cores and -weights
A rim e-hook of is consecutive boxes in the rim which, when removed, leave a Young diagram of a partition. Given a partition , there is a unique partition , called the -core of , and obtained by removing rim -hooks from until none remain. The number of such hooks removed is called the -weight of , so . This is all described in [JK81]. In [GKS90, Bijection 2] there is a bijection between -core partitions and vectors where . Given the vector , the corresponding -core is a partition of
(2.3) |
The -weight can be obtained by subtracting (2.3) from and dividing by .
Bessonrodt and Olsson worked out how to determine directly from the Mullineux symbol of a Mullineux fixed point (they state it for an odd prime but the proof works for any ).
Proposition 2.5.
Remark 2.6.
It is clear from (2.4) that , and thus , depends only on the set of nonzero residues mod of the . The which are divisible by (and hence even with ), do not contribute to
3. Main Results
In Table 1 we list the number of fixed points under the Mullineux map when for and -weights . Weight zero partitions are -cores and acts as conjugation on -cores, so the first column of this table enumerates self-conjugate 4-core partitions, which is sequence A053692 in the Online Encyclopedia of Integer Sequence (OEIS) [OEI]. Each successive column is shifted down by and multiplied by the corresponding entry in the sequence , which is A002513 in the OEIS, counting partitions of with even parts of two colors, also known as “cubic partitions”. Our main results generalize Theorems 1.1 and 1.2 to arbitrary and explain the structure of this table.
1 | 1 | |||||
2 | 1 | |||||
3 | 0 | |||||
4 | 1 | |||||
5 | 1 | 1 | ||||
6 | 1 | 1 | ||||
7 | 1 | 0 | ||||
8 | 1 | 1 | ||||
9 | 0 | 1 | 3 | |||
10 | 0 | 1 | 3 | |||
11 | 2 | 1 | 0 | |||
12 | 0 | 1 | 3 | 4 | ||
13 | 1 | 0 | 3 | 4 | ||
14 | 1 | 0 | 3 | 4 | ||
15 | 1 | 2 | 3 | 0 | ||
16 | 2 | 0 | 3 | 4 | ||
17 | 0 | 1 | 0 | 4 | 9 | |
18 | 1 | 1 | 6 | 4 | 0 | |
19 | 1 | 2 | 0 | 4 | 9 | |
20 | 0 | 0 | 3 | 0 | 9 | 12 |
We fix some standard generating function notation. Define the -Pochhammer symbol:
and the Ramanujan function:
Observe that is the generating function counting partitions of into distinct odd parts.
Let be the number of -regular partitions of fixed by the Mullineux map and let
be the corresponding generating function. Our first result determines this generating function:
Theorem 3.1.
-
(a)
[Ols92, for e prime] Let be odd. Then is the number of partitions of into distinct odd parts not divisible by . Thus:
(3.1) -
(b)
Let be even. Then is the number of partitions of into parts which are either odd or are odd multiples of , and such that the odd parts are all distinct. Thus:
(3.2)
Notice that when that simplifies to , the generating function counting partitions with odd parts, which is known to be the same as that for distinct parts. Here, the Mullineux map is trivial and we obtain is the number of two-regular partitions, i.e. partitions with distinct parts, as expected.
If we look at the corresponding alternating series, there is a nice common description of the two generating functions:
Corollary 3.2.
For arbitrary:
(3.3) |
Proof.
For both the even and odd case, , which simplifies to the expression above. ∎
For the generating function corresponds to the sequences A098884, A261734, A133563 and A261736 respectively in the OEIS [OEI]. As of this writing there is no mention of the Mullineux map in any of these entries!
3.1. Mullineux fixed points of a given -weight
We also give a result for all generalizing Theorem 1.2, counting Mullineux fixed points by -weight.
Definition 3.3.
Let be the number of with -weight and .
It is well-known that the Mullineux map when restricted to -core partitions simply takes the transpose or conjugate partition, so determining means counting self-conjugate -cores. These were enumerated by Garvan, Kim and Stanton.
Definition 3.4.
Let () denote the number of self-conjugate -core partitions of n and let
Garvan, Kim and Stanton determined :
It turns out the for each -core partition of , we have the same number of Mullineux fixed point partitions of with that core, a number determined by . These numbers also have nice generating functions, again depending on the parity of . The next definition gives the sequences of “column multipliers” that we observed in Table 1:
Definition 3.6.
Let be even. Define by:
Let be odd. Define by:
Notice that both and enumerate certain tuples of partitions with total weights adding up to . With this notation, we can state our theorem enumerating Mullineux fixed points of a given weight. This result for an odd prime is Theorem 3.5 of [BO98].
Theorem 3.7.
-
(a)
Suppose is even. Then:
-
(b)
Suppose is odd. Then is zero unless is even in which case
Theorem 3.7 lets us determine a single two-variable generating function that keeps track of Mullineux fixed points by and the weight . We will need a small reindexing given by:
Lemma 3.8.
Suppose and Then:
Proof.
Simply reindex the sum with a substitution and (for the second term), . ∎
Now define a two-variable generating function:
Definition 3.9.
Let
Lemma 3.8 applied to the expressions in Theorem 3.7, and using the generating functions from Definition 3.6 and Theorem 3.5, proves the following:
Theorem 3.10.
The generating function is:
4. Proof of the main results
Theorems 1.1 and 1.2 are stated for an odd prime, because that is where the original representation theory motivation comes from. However there is nothing in either proof that makes use of primality, so the odd case of Theorems 3.1 and 3.7 should be attributed to those authors. Thus we will consider only the case where is even.
When is odd notice that Definition 2.3(i) gives that if then actually . This is not the case for -even, and this means that in this case is not dealt with by the bijections in [AO91]. However in [Bes95], Bessenrodt gave a vast generalization that includes this case. So in her notation let for even. Choose the sets and with One can check that the conditions for are precisely those defining Bessenrodt’s set Bessenrodt gives a bijection with a set , which are all partitions with parts congruent mod to elements of and repeating parts must be congruent to elements of . This is precisely the set of partitions with all parts odd or odd multiples of with the odd parts distinct. This proves Theorem 3.1(b).
Finally, to prove Theorem 3.7(b), we need to count Mullineux fixed points in a given block. We will follow the idea of [BO98, Theorem 3.5], although the proof is slightly more complicated since is even.
Definition 4.1.
Define to be the number of tuples where the and are partitions, has odd parts, and
Theorem 4.2.
Let be even, let be a self-conjugate core with . Then:
Consider the generating function in (3.6). The first term is counting tuples of partitions with even parts and the second term counts partitions with odd parts. We can equally well count tuples of arbitrary partitions but then double all the parts. So Theorem 4.2 immediately implies Theorem 3.7(b), and all that remains is to prove Theorem 4.2.
For the next result we will need the following observation, which is easy to see in [Bes95] (recalling that .)
Lemma 4.3.
Suppose is a Mullineux fixed point with as in (2.2) and corresponding partition Suppose the image partition under Bessenrodt’s bijection is . Then both partitions have the same set of nonzero residues mod (and thus also mod .)
Thus we can use the ’s to calculate and the corresponding -core and -weight as in Section 2.1. Recall that Bessenrodt’s in this case are partitions of with all parts either odd or odd multiples of , and the odd parts must be distinct. Henceforth we will consider these as pairs of partitions where has distinct odd parts and has odd parts. Notice that the set of nonzero residues mod in is the same as in , since the odd multiples of all have -residue zero To complete the proof we will need to use the theory of -bar cores and -bar quotients.
4.1. t-bar cores
For partitions with distinct parts (sometimes called “bar partitions”), Morris introduced [Mor65] the notion of a -bar core. These played a role in Humphrey’s determination [Hum86] of blocks of projective representations of symmetric groups in characteristic similar to the role played by -cores in the theory for . We will follow the combinatorics introduced in [MY86], where a version of James’ abacus notation is given for computing -bar cores. Note this is different from the more well-known James’ abacus display for arbitrary partitions using sets of -numbers.
Given a partition with distinct parts, we form an abacus with runners lying north to south labelled . The bead positions are labelled as below:
To display on the abacus place a bead on the abacus corresponding to each part. For example if and we obtain the display in Figure 4.1, where we have also included the labels on the runners.
From we can obtain its -bar core, denoted , by performing two types of operations on the abacus. The first slides a bead on a runner up one into a vacant spot (beads reaching the location zero disappear). This corresponds to replacing a part in the partition by if is not already a part, or removing a part . Alternately you can remove two beads at positions and in the first row. This corresponds to removing two parts of the partition equal to and . Either operation has the effect of removing a -bar (which we will not define) from the partition and reducing the number being partitioned by . Eventually there are no further operations possible, and you reach the -bar core . The total number of such operations is well-defined and called the -bar weight. So in our example we obtain with abacus display:
Much of the work done on -bar cores has assumed is odd, because the combinatorics is not as nice when is even. For example if is even a partition may be a -bar core without being a -bar core (e.g. for = and one can remove a -bar but not a -bar). Also the number of partitions with a given -bar core and bar weight may depend on the choice of -bar core and not just the weight. Neither of these pathologies happens for ordinary -cores and rim -hooks. However, as Olsson observes in [Ols87, p.,235], these difficulties do not arise if there are no beads on runner . This will be the case in our situation, where will equal for even, and the partitions will have only odd parts.
Remark 4.4.
Suppose for even and let have distinct odd parts. Then the abacus display for with runners has beads only on runners with odd labels and, in particular, no beads on runner 0 or . Moreover all partitions with distinct odd parts and the same set of residues mod will have the same -bar core as .
We now consider the -bar quotient, following [MY86]. Assume for even, and has distinct odd parts. Then we see that the -bar quotient is a sequence of partitions, one for each pair of runners . The actual construction is in [MY86, Theorem 2.2] but we will need only the count:
Lemma 4.5.
[MY86, Theorem 2.(2)] The number of partitions with distinct odd parts having the same -bar core as and -bar weight is the number of tuples of partitions of total weight .
Proof of Theorem 4.2: We are now ready to prove Theorem 4.2 by constructing a bijection between the Mullineux fixed points on the right and a set which has cardinality on the left.
Suppose has weight and self-conjugate core Apply Bessenrodt’s bijection to get a pair where has distinct odd parts and has all odd parts, and the nonzero residues mod for are the same as for . In particular all the have the same -bar core. As in [BO98], we can check that that -bar core is the same size as the -core of , i.e. that Equation 2.3 gives us in terms of the . Now the argument proceeds just as on the top of page 238 of [BO98].
Recall in the odd case that for of even weight and all the corresponding partitions had the same -bar weight . In this situation, with even, the -bar weight of can be less, with the “difference” made up for by
The next step in the bijection is to calculate the -bar quotient of Since has distinct odd parts, its -bar quotient is a tuple with -bar weight and
Now we can describe the bijection that proves Theorem 4.2. Given as above we send to the tuple . The calculations above shows that
So is in the set enumerated by
The final necessary observation is that any choice of -bar quotient concentrated on the odd runners together with satisfying the weight condition will correspond to an original in the correct block. This is again the observation from [BO98] that adding or removing a bar does not change the vector , nor does the choice of . So the map is surjective, completing the proof.
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