This paper was converted on www.awesomepapers.org from LaTeX by an anonymous user.
Want to know more? Visit the Converter page.

Free Banach lattices over pre-ordered Banach spaces

Marcel de Jeu Mathematical Institute, Leiden University, P.O. Box 9512, 2300 RA Leiden, The Netherlands
and
Department of Mathematics and Applied Mathematics, University of Pretoria, Corner of Lynnwood Road and Roper Street, Hatfield 0083, Pretoria, South Africa
[email protected]
 and  Xingni Jiang College of Mathematics, Sichuan University, No. 24, South Section, First Ring Road, Chengdu, P.R. China [email protected]
Abstract.

We define the free Banach lattice over a pre-ordered Banach space in a category of Banach lattices of a given convexity type, and show its existence. The subsumption of a pre-ordering necessitates an approach that differs fundamentally from the known one for the free Banach lattice over a Banach space under a given convexity condition, which is a special case. The relation between the free vector lattice over a pre-ordered Banach space and the free Banach lattice of a given convexity type over it is made explicit. It is determined when precisely the free Banach lattice has a canonical realisation as a lattice of homogeneous continuous functions on the positive part of the unit ball of the dual space. For free pp-convex Banach lattices with convexity constant 1 over pre-ordered Banach spaces, realisations as function lattices are obtained that generalise those for free Banach lattices of that type over Banach spaces.

A characterisation of pp-convex Banach lattices in terms of vector lattice homomorphisms into Lp\mathrm{L}_{p}-spaces or into the real numbers is included.

Key words and phrases:
Pre-ordered vector space, pre-ordered Banach space, free vector lattice, free Banach lattice
2010 Mathematics Subject Classification:
Primary 46B42, 46A40; Secondary 06F20, 47B60

1. Introduction and overview

The notion of the free Banach lattice over a set was introduced by de Pagter and Wickstead in 2015 [de_pagter_wickstead:2015]; it was followed by the definition of the free Banach lattice FBL[X]{\mathrm{FBL}}[X] over a Banach space XX by Avilés, Rodríguez, and Tradacete in [aviles_rodriguez_tradacete:2018]. The latter paper was the starting point of an active line of research.

In the present paper, we bring (pre-)ordering into the picture. For a pre-ordered Banach space XX with positive wedge X+X^{+} and a given convexity type 𝒞{\mathcalalt C} (a notion introduced in the paper), we define the free Banach lattice FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] over (X,X+)(X,X^{+}). When taking 𝒞={\mathcalalt C}=\emptyset, our FBL[X,{0}]{\mathrm{FBL}}^{\emptyset}[X,\{0\}] is FBL[X]{\mathrm{FBL}}[X] from [aviles_rodriguez_tradacete:2018]; the free Banach lattices FBL𝒟[X]{\mathrm{FBL}}^{\mathcalalt D}[X] under convexity conditions from [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] all occur as an FBL𝒞[(X,{0}]{\mathrm{FBL}}^{\mathcalalt C}[(X,\{0\}] in the present paper. When XX is an ordered Banach space with a (not necessarily generating) closed positive cone X+X^{+}, there is a linear injection from XX into FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] that is bipositive. Thus XX sits inside FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})], and its ordering extends to a lattice ordering on the enveloping space. It is a non-trivial question, left for further research, to find conditions under which the image is closed; this is always the case if X+={0}X^{+}=\{0\} when the injection is even isometric. When the image is closed, XX is embedded (though perhaps not necessarily isometrically) into the Banach lattice FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as an ordered Banach space. The embedding of a Banach space XX into FBL[X]{\mathrm{FBL}}[X] makes a better understanding possible of the relation between Banach spaces and Banach lattices. The same can now be expected for that between ordered Banach spaces and Banach lattices.

Compared to earlier papers on free Banach lattices, our approach to the existence of the free Banach lattice is of a fundamentally different nature. We do not start from a function lattice, but instead from an algebraic free object which we know to exist, and proceed from there. This has not only the advantage that it works in all generality, whereas—as we shall argue—this cannot be expected for the function lattice method, but we also believe that it makes the picture more transparent. As will become clear, one can say quite a bit about the free Banach lattice without having a concrete function lattice realisation of it (which may not exist), or without even knowing that it actually exists.

This paper is organised as follows.

Section 2 contains the necessary preliminaries.

Section 3 contains preparatory material on convexity in Banach lattices. In its first part, using an idea from [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], a characterisation of pp-convex Banach lattices is obtained in terms of vector lattice homomorphisms into Lp\mathrm{L}_{p}-spaces or the real numbers. This characterisation, which appears to be new, is instrumental to Section 7. It also allows one to give an alternate proof of the well-known fact that pp-convex Banach lattices can always be renormed so that the pp-convexity constant becomes 1. In its second part, the notion of a convexity type is introduced, generalising that of a convexity condition in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022]. If, for a Banach lattice, there is a norming family of contractive vector lattice homomorphisms into Banach lattices that are all of the same convexity type, then so is the domain lattice.

Section 4 introduces the free vector lattice FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})] over a pre-ordered vector space VV with positive wedge V+V^{+}. It is shown that it exists. One can argue that, once this existence been established (a consequence of a basic principle in universal algebra), it is routine to verify that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] always exists.

In Section 5, the free Banach lattice FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] of a given convexity type over a pre-ordered Banach space (X,X+)(X,X^{+}) is defined. The definition is purely categorical, in terms of positive contractions that factor over contractive vector lattice homomorphisms, without any conditions on maps being injective or isometric, or on norms of operators being equal. The remainder of the section is a study of its properties, should it exist. It is not disappointing what can already be said a priori. Our definition of FVL[(X,{0})]{\mathrm{FVL}}^{\emptyset}[(X,\{0\})], for example, can be shown to be equivalent to the seemingly stronger one for FBL[X]{\mathrm{FBL}}[X] in [aviles_rodriguez_tradacete:2018]. A formula for the norm can be derived, and it can be determined when FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] contains FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})]. This is always the case when X+={0}X^{+}=\{0\}. Consequently, the free Banach lattices in [aviles_rodriguez_tradacete:2018, jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] always contain a copy of the free vector lattice over the Banach space XX. In the notation of these papers, the vector lattices of functions on the dual space that is generated by the δx\delta_{x} is the free vector lattice over XX. This seems to have gone unnoticed in the papers on free Banach lattices thus far, and one can regard it is an explanation why the approach in [aviles_rodriguez_tradacete:2018, jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], where one starts with a function lattice on the dual unit ball, actually works. We also give arguments why this will in all likelihood not work when X+{0}X^{+}\neq\{0\}. It can also be determined a priori when precisely there is a canonical realisation of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as a function lattice on the positive part of the dual unit ball.

In Section 6, the existence of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is established in a manner as was already done in [de_jeu:2021] for FBL[X]{\mathrm{FBL}}[X], and as is systematically exploited in [van_amstel_THESIS:2023]. The idea, which can already be found in the books by Dixmier and presumably also elsewhere, is to start with a free object in an algebraic context and proceed routinely along a standard path. There is no role for function lattices on the dual space, or even for the dual space itself.

In Section 7, it is shown that the free pp-convex Banach lattices with pp-convexity constant 1 over (X,X+)(X,X^{+}) can be realised as lattices of homogeneous continuous functions on the positive part of the dual unit ball. When X+={0}X^{+}=\{0\}, one retrieves the realisations in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022]. This section is clearly indebted to the ingenious techniques in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], but in spite of the similarity the road to these realisations is very different. Whereas in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] the proof of the existence of the free Banach lattice is essentially redone by showing that the proposed Banach function lattice has the correct universal property, we start from the free object itself, which we know to exist, and analyse it to the extent that it becomes a triviality that it has a realisation as a function lattice on the positive part of the dual unit ball. One could say that in the present paper these realisations are derived, and that in [aviles_rodriguez_tradacete:2018, jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] they are found.

A words on notation. Firstly, compared to many papers on free Banach lattices, our canonical choice of letters is reversed: XX is a Banach space and EE and FF are Banach lattices or vector lattices. We believe that this reflects the notation in most of the existing textbooks on Banach lattices and vector lattices, and apologise for any inconvenience this may cause. Secondly, we have consistently used Greek letters for positive contractions and contractive vector lattice homomorphisms, rather than the usual operator letters such as TT. This fits better into our categorical approach, where these are the morphisms we work with.

2. preliminaries

In this section, we collect the necessary notation, definitions, and conventions.

All vector spaces are over the real numbers. A vector lattice need not be Archimedean.

If VV is a vector space, then a wedge in VV is a non-empty subset V+V^{+} such that α1x1+α2x2V+\alpha_{1}x_{1}+\alpha_{2}x_{2}\in V^{+} for all α1,α20\alpha_{1},\alpha_{2}\geq 0 and x1,x2V+x_{1},x_{2}\in V^{+}. A wedge V+V^{+} is a cone when V+(V+)={0}V^{+}\cap(-V^{+})=\{0\}. There is a well-known correspondence between pre-orderings on VV and wedges in VV, where the partial orderings correspond to the cones. A pre-ordered vector space is a pair (V,V+)(V,V^{+}), where V+V^{+} is a wedge in the vector space VV. If (V,V+)(V,V^{+}) and (W,W+)(W,W^{+}) are pre-ordered vector spaces, then a linear map φ:VW\varphi\colon V\to W is positive when φ(V+)W+\varphi(V^{+})\subseteq W^{+}. When V+={0}V^{+}=\{0\}, these are just the linear maps.

A pre-ordered Banach space is a pair (X,X+)(X,X^{+}), where X+X^{+} is a wedge in the Banach space XX. It need not be closed.

If XX is a Banach space, then XX^{*} denotes its dual. When (X,X+)(X,X^{+}) is a pre-ordered Banach space, we write BX{\mathrm{B}}_{X} for its unit ball, BX{\mathrm{B}}_{X^{\ast}} for the unit ball of its dual, and BX+{\mathrm{B}}_{X^{\ast}_{+}} for the positive elements of BX{\mathrm{B}}_{X^{\ast}}. If X+={0}X^{+}=\{0\}, then BX+=BX{\mathrm{B}}_{X^{\ast}_{+}}={\mathrm{B}}_{X^{\ast}}.

We supply BX+{\mathrm{B}}_{X^{\ast}_{+}} with the relative weak*-topology, making it into a compact Hausdorff space, and let Ch(BX+)\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}) denote the continuous, homogeneous, real-valued functions on it. For xXx\in X, we define δxCh(BX+)\delta_{x}\in\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}) by setting

(2.1) δx(x)x(x)\delta_{x}(x^{*})\coloneqq x^{*}(x)

for xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}. If X+={0}X^{+}=\{0\}, then δx\delta_{x} is defined on BX{\mathrm{B}}_{X^{\ast}}.

Contractions between Banach spaces are linear.

To conclude, we recall the following definition of free objects from [adamek_herrlich_strecker_ABSTRACT_AND_CONCRETE_CATEGORIES_THE_JOY_OF_CATS:2006, Definition 8.22].

Definition 2.1.

Suppose that Cat1\textup{{\footnotesize Cat}}_{1} and Cat2\textup{{\footnotesize Cat}}_{2} are categories, and that U:Cat2Cat1U\colon\textup{{\footnotesize Cat}}_{2}\mapsto\textup{{\footnotesize Cat}}_{1} is a faithful functor.111Recall that UU is faithful when the associated map U:HomCat2(O2,O2)HomCat1(U(O2),U(O2))U\colon\mathrm{Hom}_{{\textup{{\tiny{Cat}}}}_{2}}(O_{2},O_{2}^{\prime})\to\mathrm{Hom}_{{\textup{{\tiny{Cat}}}}_{1}}(U(O_{2}),U(O_{2}^{\prime})) is injective for all objects O2,O2O_{2},O_{2}^{\prime} of Cat2\textup{{\footnotesize Cat}}_{2}. This will always be the case in the present paper.. Take an object O1O_{1} of Cat1\textup{{\footnotesize Cat}}_{1}. A free object over O1O_{1} of Cat2\textup{{\footnotesize Cat}}_{2} with respect to UU is a pair (j,FCat1Cat2[O1])(j,\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]), where FCat1Cat2[O1]\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right] is an object of Cat2\textup{{\footnotesize Cat}}_{2} and j:O1U(FCat1Cat2[O1])j:O_{1}\to U\left(\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]\right) is a morphism of Cat1\textup{{\footnotesize Cat}}_{1}, with the property that, for every object O2O_{2} of Cat2\textup{{\footnotesize Cat}}_{2} and every morphism φ:O1U(O2)\varphi:O_{1}\to U(O_{2}) of Cat1\textup{{\footnotesize Cat}}_{1}, there exists a unique morphism φ¯:FCat1Cat2[O1]O2\overline{\varphi}:\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]\to O_{2} of Cat2\textup{{\footnotesize Cat}}_{2} such that the diagram

O1{O_{1}}U(FCat1Cat2[O1]){U\left(\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]\right)}U(O2){U(O_{2})}j\scriptstyle{j}φ\scriptstyle{\varphi}U(φ¯)\scriptstyle{U(\overline{\varphi})}

in Cat1\textup{{\footnotesize Cat}}_{1} is commutative.

A free object (j,FCat1Cat2[O1])(j,\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]) as in Definition 2.1 need not exist. However, if it exists, and if (j,FCat1Cat2[O1])(j^{\prime},\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]^{\prime}) is another such pair, then a standard argument shows that the unique morphism j¯:FCat1Cat2[O1]FCat1Cat2[O1]\overline{j^{\prime}}:\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]\to\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]^{\prime} of Cat2\textup{{\footnotesize Cat}}_{2} such that U(j¯)j=jU(\overline{j^{\prime}})\circ j=j^{\prime} is, in fact, an isomorphism with as its inverse the unique morphism j¯:FCat1Cat2[O1]FCat1Cat2[O1]\overline{j}:\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right]^{\prime}\to\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right] of Cat2\textup{{\footnotesize Cat}}_{2} such that U(j¯)j=jU(\overline{j})\circ j^{\prime}=j . In particular, a free object over O1O_{1} of Cat2\textup{{\footnotesize Cat}}_{2} with respect to UU, if it exists, is determined up to an isomorphism of Cat2\textup{{\footnotesize Cat}}_{2}. In the case of existence we shall, therefore, sometimes simply speak of ‘the’ free object FCat1Cat2[O1]\textup{F}_{{\textup{{\tiny{Cat}}}}_{1}}^{{\textup{{\tiny{Cat}}}}_{2}}\!\left[O_{1}\right] over O1O_{1} of Cat2\textup{{\footnotesize Cat}}_{2}, the accompanying morphism jj often being tacitly understood from the context.

In the current paper, we are concerned with two contexts for Definition 2.1, an algebraic and an analytic one. The results in the algebraic context are the stepping stone for those in the analytic context.

3. Convexity

In this section, we collect the material on convexity that will be needed in the sequel. For the positively homogeneous functional calculus for Banach lattices that is used in it, we refer to [lindenstrauss_tzafriri_CLASSICAL_BANAH_SPACES_VOLUME_II_FUNCTION_SPACES:1979, Section 1.d]. It will be important that it is compatible with vector lattice homomorphisms; this follows from the uniqueness statement in [lindenstrauss_tzafriri_CLASSICAL_BANAH_SPACES_VOLUME_II_FUNCTION_SPACES:1979, Theorem 1.d.1].

3.1. p-convexity

Section 7 is concerned with free pp-convex Banach lattices. As a preparation for this, we recall the definitions and give characterisations of pp-convex Banach lattices in terms of contractive vector lattice homomorphisms into Lp\mathrm{L}_{p}-spaces or {\mathbbm{R}}.

Let M1M\geq 1. For 1p<1\leq p<\infty, a Banach lattice EE is said to be pp-convex with pp-convexity constant at most MM when

(i=1n|xi|p)1/pM(i=1nxip)1/p{\left\lVert\left(\sum_{i=1}^{n}{\lvert x_{i}\rvert}^{p}\right)^{1/p}\right\rVert}\leq M\left(\sum_{i=1}^{n}{\lVert x_{i}\rVert}^{p}\right)^{1/p}

for x1,,xnEx_{1},\dotsc,x_{n}\in E. The smallest such MM is called the pp-convexity constant M(p)(E)M^{(p)}(E) of EE. All Lp\mathrm{L}_{p}-spaces are pp-convex with pp-convexity constant 1. All Banach lattices are 1-convex with 1-convexity constant 1.

It is said to be \infty-convex with \infty-convexity constant at most MM when

i=1n|xi|Mi=1nxi{\left\lVert\bigvee_{i=1}^{n}{\lvert x_{i}\rvert}\right\rVert}\leq M\bigvee_{i=1}^{n}{\lVert x_{i}\rVert}

for x1,,xnEx_{1},\dotsc,x_{n}\in E. The smallest such MM is the \infty-convexity constant M()(E)M^{(\infty)}(E) of EE.

Parts of the proofs of the following results are inspired by ideas in the proof of [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, Theorem 6.1].

Proposition 3.1.

Let EE be a Banach lattice. Then, for xEx\in E,

x=maxφφ(x),{\lVert x\rVert}=\max_{\varphi}{\lVert\varphi(x)\rVert},

where φ\varphi runs over all contractive vector lattice homomorphisms φ:EL1(μ)\varphi\colon E\to\mathit{L}_{1}(\mu) for probability measures μ\mu.

Proof.

Take xEx^{*}\in E^{*} with x1{\lVert x^{*}\rVert}\leq 1 such that x(|x|)=xx^{*}({\lvert x\rvert})={\lVert x\rVert}. We let Nx{xF:x(|x|)}N_{x^{*}}\coloneqq\{x\in F:x^{*}({\lvert x\rvert})\} be its null-ideal, and define FF to be the completion of E/N(x)E/N(x^{*}) in the norm x+Nxx(|x|){\lVert x+N_{x^{*}}\rVert}\coloneqq x^{*}({\lvert x\rvert}). As disjoint elements in a quotient have disjoint lifts, FF is an AL-space, so that it can be identified with a concrete L1\mathrm{L}_{1}-space L1(ν)L_{1}(\nu) on a set Ω\Omega. If we let ψ:EL1(ν)\psi\colon E\to\mathrm{L}_{1}(\nu) be the resulting contractive vector lattice homomorphism, then x=ψ(x)L1(ν){\lVert x\rVert}={\lVert\psi(x)\rVert}_{\mathrm{L}_{1}(\nu)}. To obtain a probability measure μ\mu, we restrict ν\nu to S{ωΩ:[ψ(x)](ω)0}S\coloneqq\{\omega\in\Omega:[\psi(x)](\omega)\neq 0\} and let μ\mu be this restriction, divided by |ψ(x|{\lvert\psi(x\rvert}. Then χ:L1(ν)L1(μ)\chi\colon\mathrm{L}_{1}(\nu)\to\mathrm{L}_{1}(\mu), defined by setting χ(f)|ψ(x)|fS\chi(f)\coloneqq{\lvert\psi(x)\rvert}\,\,f\!\!\restriction_{S} for fL1(ν)f\in\mathrm{L}_{1}(\nu), is a contractive vector lattice homomorphism such that (χψ)(x)L1(μ)=ψ(x)L1(ν)=x{\lVert(\chi\circ\psi)(x)\rVert}_{\mathrm{L}_{1}(\mu)}={\lVert\psi(x)\rVert}_{\mathrm{L}_{1}(\nu)}={\lVert x\rVert}. This result follows. ∎

Theorem 3.2.

Let 1<p<1<p<\infty and let M1M\geq 1. The following are equivalent for a Banach lattice EE:

  1. 1.

    EE is pp-convex with pp-convexity constant at most MM;

  2. 2.

    for xEx\in E,

    xMsupφφ(x),{\lVert x\rVert}\leq M\sup_{\varphi}{\lVert\varphi(x)\rVert},

    where φ\varphi runs over all contractive vector lattice homomorphisms φ:ELp(μ)\varphi\colon E\to\mathit{L}_{p}(\mu) for probability measures μ\mu.

Proof.

We start with the easy proof that part (2) implies part (1).​ Take x1,,xnEx_{1},\dotsc,x_{n}\in E. Using that the codomains are Lp\mathrm{L}_{p}-spaces in the third step, we then have

(i=1n|xi|p)1/p\displaystyle{\left\lVert\left(\sum_{i=1}^{n}{\lvert x_{i}\rvert}^{p}\right)^{1/p}\right\rVert} Msupφφ((i=1n|xi|p)1/p)\displaystyle\leq M\sup_{\varphi}{\left\lVert\varphi\left(\left(\sum_{i=1}^{n}{\lvert x_{i}\rvert}^{p}\right)^{1/p}\right)\right\rVert}
=Msupφ(i=1n|φ(xi)|p)1/p\displaystyle=M\sup_{\varphi}{\left\lVert\left(\sum_{i=1}^{n}{\lvert\varphi(x_{i})\rvert}^{p}\right)^{1/p}\right\rVert}
=Msupφ(i=1nφ(xi)p)1/p\displaystyle=M\sup_{\varphi}\left(\sum_{i=1}^{n}{\lVert\varphi(x_{i})\rVert}^{p}\right)^{1/p}
=M(i=1nxip)1/p.\displaystyle=\leq M\left(\sum_{i=1}^{n}{\lVert x_{i}\rVert}^{p}\right)^{1/p}.

We now prove that part (1) implies part (2). Take xEx\in E. Proposition 3.1 furnishes a probability measure μ\mu and a contractive vector lattice homomorphism φ:EL1(μ)\varphi\colon E\to\mathrm{L}_{1}(\mu) such that xE=φ(x)L1(μ){\lVert x\rVert}_{E}={\lVert\varphi(x)\rVert}_{\mathrm{L}_{1}(\mu)}. Take x1,,xnEx_{1},\dotsc,x_{n}\in E. Then

(i=1n|φ(xi)|p)1/pL1(μ)\displaystyle{\left\lVert\left(\sum_{i=1}^{n}{\lvert\varphi(x_{i})\rvert}^{p}\right)^{1/p}\right\rVert}_{\mathrm{L}_{1}(\mu)} =φ((i=1n|xi|p)1/p)L1(μ)\displaystyle={\left\lVert\varphi\left(\left(\sum_{i=1}^{n}{\lvert x_{i}\rvert}^{p}\right)^{1/p}\right)\right\rVert}_{\mathrm{L}_{1}(\mu)}
(i=1n|xi|p)1/pE\displaystyle\leq{\left\lVert\left(\sum_{i=1}^{n}{\lvert x_{i}\rvert}^{p}\right)^{1/p}\right\rVert}_{E}
M(i=1nxiEp)1/p\displaystyle\leq M\left(\sum_{i=1}^{n}{\lVert x_{i}\rVert}_{E}^{p}\right)^{1/p}

The Maurey-Nikishin factorisation theorem (see [albiac_kalton_TOPICS_IN_BANACH_SPACE_THEORY:2006, Theorem 7.1.2]) now yields a probability measure ν\nu, a vector lattice homomorphism S:ELp(ν)S\colon E\to\mathrm{L}_{p}(\nu) with SM{\lVert S\rVert}\leq M, and an isometric embedding j:L1(ν)L1(μ)j\colon\mathrm{L}_{1}(\nu)\to\mathrm{L}_{1}(\mu) such that the diagram

(3.1) E{E}L1(μ){\mathrm{L}_{1}(\mu)}Lp(ν){\mathrm{L}_{p}(\nu)}L1(ν){\mathrm{L}_{1}(\nu)}φ\scriptstyle{\varphi}S\scriptstyle{S}i\scriptstyle{i}j\scriptstyle{j}

is commutative. Here ii is the inclusion map which—this is the point—is contractive as ν\nu is a probability measure. We then have

xE\displaystyle{\lVert x\rVert}_{E} =φ(x)L1(μ)=(jiS)(x)L1(μ)=(iS)(x)L1(ν)S(x)Lp(ν).\displaystyle={\lVert\varphi(x)\rVert}_{\mathrm{L}_{1}(\mu)}={\lVert(j\circ i\circ S)(x)\rVert}_{\mathrm{L}_{1}(\mu)}={\lVert(i\circ S)(x)\rVert}_{\mathrm{L}_{1}(\nu)}\leq{\lVert S(x)\rVert}_{\mathrm{L}_{p}(\nu)}.

On writing S=M(S/M)S=M\cdot(S/M) we see that the inequality in part (2) holds for xx. ∎

Corollary 3.3.

Let 1p<1\leq p<\infty. The following are equivalent for a Banach lattice EE:

  1. 1.

    EE is pp-convex with pp-convexity constant 1;

  2. 2.

    for xEx\in E,

    x=supφφ(x),{\lVert x\rVert}=\sup_{\varphi}{\lVert\varphi(x)\rVert},

    where φ\varphi runs over all contractive vector lattice homomorphisms φ:ELp(μ)\varphi\colon E\to\mathit{L}_{p}(\mu) for probability measures μ\mu.

We complement this with the following.

Proposition 3.4.

The following are equivalent for a Banach lattice EE:

  1. 1.

    EE is \infty-convex with \infty-convexity constant 1;

  2. 2.

    for xEx\in E,

    x=maxφφ(x),{\lVert x\rVert}=\max_{\varphi}{\lVert\varphi(x)\rVert},

    where φ\varphi runs over all contractive vector lattice homomorphisms φ:E\varphi\colon E\to{\mathbbm{R}}.

Proof.

It follows from the Kakutani representation theorem (see [lindenstrauss_tzafriri_CLASSICAL_BANAH_SPACES_VOLUME_II_FUNCTION_SPACES:1979, Theorem 1.b.6], for example) that the \infty-convex Banach lattices with \infty-convexity constant 1 are, up to an isometric vector lattice homomorphism, precisely the Banach sublattices of C(K)\mathrm{C}(K) for some compact Hausdorff space KK. On considering the point evaluations in such a functional representation, we see that part (1) implies part (2). For the converse, one realises EE canonically as a Banach lattice of continuous functions on the space of the real-valued contractive vector lattice homomorphisms, supplied with the relative weak*-topology, to see that it is a Banach sublattice of a C(K)\mathrm{C}(K)-space. ∎

Remark 3.5.

For 1p<1\leq p<\infty, we shall see in Remark 3.8 how Corollary 3.3 provides an alternate proof of the fact that a pp-convex Banach lattice has an equivalent norm in which it is pp-convex with pp-convexity constant 1.

3.2. Convexity types

In this section, we introduce the notion of a convexity type for Banach lattices. This generalises the notion of a 𝒟\mathcalalt D-convexity condition in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022]. As we shall see, if there exists a norming family of contractive vector lattice homomorphisms from a Banach lattice into codomains which are all of the same convexity type, then the domain is also of this type.

The definition of a convexity type uses the positively homogeneous functional calculus. For nn\in{\mathbbm{N}}, we let n{\mathcalalt H}_{n} denote the set of all continuous positively homogeneous real-valued functions on n{\mathbbm{R}}^{n}. We set

ni{hn:h(t1,,tn)h(s1,,sn) when 0tisi for i=1,,n}{\mathcalalt H}_{n}^{\mathrm{i}}\coloneqq\{h\in{\mathcalalt H}_{n}:h(t_{1},\dotsc,t_{n})\leq h(s_{1},\dotsc,s_{n})\text{ when }0\leq t_{i}\leq s_{i}\text{ for }i=1,\dots,n\}

for its elements that are increasing on the positive cone +n{\mathbbm{R}}^{n}_{+} of n{\mathbbm{R}}^{n}.

A convexity implication {\mathcalalt I} is a triple (a,c;n)({\mathcalalt I}_{\mathrm{a}},{\mathcalalt I}_{\mathrm{c}};n), where nn\in{\mathbbm{N}}, an{\mathcalalt I}_{\mathrm{a}}\subseteq{\mathcalalt H}_{n}, and cn×ni{\mathcalalt I}_{\mathrm{c}}\subseteq{\mathcalalt H}_{n}\times{\mathcalalt H}_{n}^{\mathrm{i}}. We allow that a={\mathcalalt I}_{\mathrm{a}}=\emptyset, but require that c{\mathcalalt I}_{\mathrm{c}}\neq\emptyset. A Banach lattice EE is said to satisfy {\mathcalalt I} if

(3.2) c1(x1,,xnc2(x1,,xn){\lVert c_{1}(x_{1},\dotsc,x_{n}\rVert}\leq c_{2}({\lVert x_{1}\rVert},\dots,{\lVert x_{n}\rVert})

for every (c1,c2)c(c_{1},c_{2})\in{\mathcalalt I}_{\mathrm{c}} whenever x1,,xnEx_{1},\cdots,x_{n}\in E are such that a(x1,,xn)0a(x_{1},\ldots,x_{n})\leq 0 for all aaa\in{\mathcalalt I}_{\mathrm{a}}. When a={\mathcalalt I}_{a}=\emptyset, we require that (3.2) hold for all x1,,xnEx_{1},\cdots,x_{n}\in E. 222Thus EE satisfies {\mathcalalt I} if an implication is valid for it, the (possibly vacuously fulfilled) antecedent of which is expressed in terms of a{\mathcalalt I}_{a} and its elements aa, and the consequent of which is expressed in terms of c{\mathcalalt I}_{\mathrm{c}} and its elements (c1,c2)(c_{1},c_{2}). This motivates the notation. A convexity type 𝒞{\mathcalalt C} is a (possibly) empty set of convexity implications. A Banach lattice is said to be 𝒞{\mathcalalt C}-convex if it satisfies all convexity implications in 𝒞{\mathcalalt C}. Every Banach lattice is \emptyset-convex.

For ana\in{\mathcalalt H}_{n}, the condition that a(x1,,xn)=0a(x_{1},\dots,x_{n})=0 is equivalent to requiring that a(x1,,xn)0a(x_{1},\dots,x_{n})\leq 0 and (a)(x1,,xn)0(-a)(x_{1},\dots,x_{n})\leq 0. Thus also antecedents in terms of equalities are covered by the formalism. Likewise, if c1c_{1} is also increasing on +n{\mathbbm{R}}^{n}_{+}, then including both (c1,c2)(c_{1},c_{2}) and (c2,c1)(c_{2},c_{1}) in c{\mathcalalt I}_{\mathrm{c}} makes it possible to include certain equalities in the consequent.

Take nn\in{\mathbbm{N}} and define ania\in{\mathcalalt H}_{n}^{\mathrm{i}} by setting a(t1,,tn)i=1n|ti|ti||a(t_{1},\dotsc,t_{n})\coloneqq\sum_{i=1}^{n}{{\lvert t_{i}-{\lvert t_{i}\rvert}\rvert}}. Then a(x1,,xn)0a(x_{1},\dotsc,x_{n})\leq 0 if and only if x1,,xnE+x_{1},\dotsc,x_{n}\in E^{+}. As a variation, set a(t1,,tn)i,j=1n|t1||t2|a^{\prime}(t_{1},\dotsc,t_{n})\coloneqq\sum_{i,j=1}^{n}{\lvert t_{1}\rvert}\wedge{\lvert t_{2}\rvert}. Then a(x1,,xn)0a^{\prime}(x_{1},\dotsc,x_{n})\leq 0 if and only if the xix_{i} are pairwise disjoint.

After these two observations, it is clear how every convexity condition 𝒟\mathcalalt D as defined in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, Section 3] leads to a corresponding convexity type 𝒞{\mathcalalt C} as above, such that the 𝒟\mathcalalt D-convex Banach lattices as defined in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] are precisely the 𝒞{\mathcalalt C}-convex Banach lattices as defined above. The present set-up is, however, more general and it is for this reason that we have chosen a different terminology (‘type’ versus ‘condition’) and a different letter. This avoids a possible misunderstanding when using results from [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022].

Example 3.6.

Let M1M\geq 1. Take 1p<1\leq p<\infty. For n1n\geq 1, we set cpn(t1,,tn)(i=1n|ti|p)1/pc^{n}_{p}(t_{1},\ldots,t_{n})\coloneqq\left(\sum_{i=1}^{n}{\lvert t_{i}\rvert}^{p}\right)^{1/p}. Let 𝒞pM{,{(cpn,Mcpn;n):n=1,2,}}{\mathcalalt C}_{p}^{M}\coloneqq\big{\{}\emptyset,\{(c^{n}_{p},Mc^{n}_{p};n):n=1,2,\ldots\}\big{\}}. Then the 𝒞pM{\mathcalalt C}_{p}^{M}-convex Banach lattices are the pp-convex Banach lattices with pp-convexity constant at most MM.

For the choice cn(t1,,tn)i=1n|ti|c^{n}_{\infty}(t_{1},\ldots,t_{n})\coloneqq\sum_{i=1}^{n}{\lvert t_{i}\rvert} and 𝒞M{,{(cn,Mcn;n):n=1,2,}}{\mathcalalt C}_{\infty}^{M}\coloneqq\big{\{}\emptyset,\{(c^{n}_{\infty},Mc^{n}_{\infty};n):n=1,2,\ldots\}\big{\}} one obtains the \infty-convex Banach lattices with \infty-convexity constant at most MM.

In [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], the existence of free 𝒟\mathcalalt D-convex Banach lattices was established. For this, a study of the positively homogeneous functional calculus and its continuity properties was needed for suitable, not necessarily uniformly complete, vector lattices, to show that the 𝒟\mathcalalt D-convexity passes from a certain normed vector lattice to its completion in the final step of the existence proof. In our approach, this is not necessary. The 𝒞{\mathcalalt C}-convexity of the free 𝒞{\mathcalalt C}-convex Banach lattice will be immediate from the following result, the proof of which uses only the compatibility of the homogeneous functional calculus with vector lattice homomorphisms. It will now become clear why the condition above that c2c_{2} be increasing on +n{\mathbbm{R}}^{n}_{+} is necessary.

Lemma 3.7.

Let EE be a Banach lattice and let 𝒞{\mathcalalt C} be a convexity type. Suppose that, for all xEx\in E,

x=supφφ(x){\lVert x\rVert}=\sup_{\varphi}{\lVert\varphi(x)\rVert}

where φ\varphi runs over a class of contractive vector lattice homomorphisms φ:EEφ\varphi\colon E\to E_{\varphi} into Banach lattices EφE_{\varphi}. If all EφE_{\varphi} are 𝒞{\mathcalalt C}-convex, then EE is 𝒞{\mathcalalt C}-convex.

Proof.

If 𝒞={\mathcalalt C}=\emptyset, there is nothing to prove, so we suppose that 𝒞{\mathcalalt C} is non-empty. Take a convexity implication =(a,c;n){\mathcalalt I}=({\mathcalalt I}_{\mathrm{a}},{\mathcalalt I}_{\mathrm{c}};n) in 𝒞{\mathcalalt C}. Suppose that x1,,xnEx_{1},\cdots,x_{n}\in E are such that a(x1,,xn)0a(x_{1},\ldots,x_{n})\leq 0 for all aaa\in{\mathcalalt I}_{\mathrm{a}}; this is vacuously fulfilled if a={\mathcalalt I}_{\mathrm{a}}=\emptyset. Take a φ:EEφ\varphi\colon E\to E_{\varphi} as in the statement. Then a(φ(x1),,φ(xn))=φ(a(x1,,xn))0a(\varphi(x_{1}),\ldots,\varphi(x_{n}))=\varphi(a(x_{1},\ldots,x_{n}))\leq 0 for all aaa\in{\mathcalalt I}_{\mathrm{a}}. Since EφE_{\varphi} satisfies {\mathcalalt I}, we have

c1(φ(x1),,φ(xn)c2(φ(x1),,φ(xn)){\lVert c_{1}(\varphi(x_{1}),\dotsc,\varphi(x_{n})\rVert}\leq c_{2}({\lVert\varphi(x_{1})\rVert},\dots,{\lVert\varphi(x_{n})\rVert})

for all (c1,c2)c(c_{1},c_{2})\in{\mathcalalt I}_{\mathrm{c}}. Using the fact that c2c_{2} is increasing on +n{\mathbbm{R}}^{n}_{+} in the final step, we then see that, for all (c1,c2)c(c_{1},c_{2})\in{\mathcalalt I}_{c},

c1(x1,,xn\displaystyle{\lVert c_{1}(x_{1},\dotsc,x_{n}\rVert} =supφφ(c1(x1,,xn))\displaystyle=\sup_{\varphi}{\lVert\varphi\left(c_{1}(x_{1},\dotsc,x_{n})\right)\rVert}
=supφc1(φ(x1),,φ(xn))\displaystyle=\sup_{\varphi}{\lVert c_{1}(\varphi(x_{1}),\dotsc,\varphi(x_{n}))\rVert}
supφc2(φ(x1),,φ(xn))\displaystyle\leq\sup_{\varphi}c_{2}({\lVert\varphi(x_{1})\rVert},\dots,{\lVert\varphi(x_{n})\rVert})
c2(x1,,x2).\displaystyle\leq c_{2}({\lVert x_{1}\rVert},\dotsc,{\lVert x_{2}\rVert}).

Hence EE satisfies {\mathcalalt I}, as required. ∎

Remark 3.8.

Let 1p<1\leq p<\infty, and let EE be a pp-convex Banach lattice. The definition of pp-convexity and Theorem 3.2 imply that there exists an M1M\geq 1 such that xMsupφφ(x){\lVert x\rVert}\leq M\sup_{\varphi}{\lVert\varphi(x)\rVert}, where φ\varphi runs over all contractive vector lattice homomorphisms φ:ELp(μ)\varphi\colon E\to\mathrm{L}_{p}(\mu) for probability measures μ\mu. For xEx\in E, set xsupφφ(x){\lVert x\rVert}^{\prime}\coloneqq\sup_{\varphi}{\lVert\varphi(x)\rVert}. Since xxMx{\lVert x\rVert}^{\prime}\leq{\lVert x\rVert}\leq M{\lVert x\rVert}^{\prime}, {\lVert\,\cdot\,\rVert} is a complete lattice norm on XX that is equivalent to {\lVert\,\cdot\,\rVert}. As all codomains of the φ\varphi are pp-convex with pp-convexity constant 1, Lemma 3.7 shows that the same is true for EE in the norm {\lVert\,\cdot\,\rVert}^{\prime}. We have thus retrieved a part of [lindenstrauss_tzafriri_CLASSICAL_BANAH_SPACES_VOLUME_II_FUNCTION_SPACES:1979, Proposition 1..8].

The zero lattice is always 𝒞{\mathcalalt C}-convex. It can happen that this is the only 𝒞{\mathcalalt C}-convex Banach lattice. As an example where this is the case, take n=1n=1, define c1(t1)=2t1c_{1}(t_{1})=2t_{1} and c2(t1)=t1c_{2}(t_{1})=t_{1}, and set 𝒞={(,{(c1,c2)};1)}{\mathcalalt C}=\big{\{}(\emptyset,\{(c_{1},c_{2})\};1)\big{\}}. There is a convenient criterion to avoid such a collapse of Sections 5 and 6 to the study of the zero lattice. For this, we note that a Banach sublattice of a 𝒞{\mathcalalt C}-convex Banach lattice is also 𝒞{\mathcalalt C}-convex. On considering one-dimensional Banach sublattices, it now follows that the existence of non-zero 𝒞{\mathcalalt C}-convex Banach lattices is equivalent to {\mathbbm{R}} being 𝒞{\mathcalalt C}-convex.

We assume in the sequel that \bm{{\mathbbm{R}}} is 𝒞\bm{{\mathcalalt C}}-convex.

For each convexity condition 𝒟\mathcalalt D in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], {\mathbbm{R}} is 𝒟\mathcalalt D-convex, hence also 𝒞{\mathcalalt C}-convex in the corresponding reformulation of 𝒟\mathcalalt D as a convexity type 𝒞{\mathcalalt C}.333For this we need to check, in the notation of [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, p. 15], that, under certain conditions on x1,,xn+nx_{1},\dots,x_{n}\in{\mathbbm{R}}^{n}_{+}, |g(x1,,xn)|M(g)g(|x1|,,|xn|){\lvert g(x_{1},\dots,x_{n})\rvert}\leq M(g)g({\lvert x_{1}\rvert},\dotsc,{\lvert x_{n}\rvert}). Since M(g)1M(g)\geq 1 and gg is positive on +n{\mathbbm{R}}^{n}_{+}, this is even true without any conditions.

4. Free vector lattices over pre-ordered vector spaces

The existence of free Banach lattices over pre-ordered spaces in Section 6 is a routinely verified consequence of the existence of free vector lattices over pre-ordered vector spaces. The latter will be taken care of in this section.

We apply Definition 2.1 in the following context. For Cat1\textup{{\footnotesize Cat}}_{1}, we take the pre-ordered vector spaces as objects and the positive linear maps as morphisms. For Cat2\textup{{\footnotesize Cat}}_{2}, we take the vector lattices as objects and the vector lattice homomorphisms as morphisms. We define the functor UU from Cat1\textup{{\footnotesize Cat}}_{1} to Cat2\textup{{\footnotesize Cat}}_{2} by sending a vector lattice EE to the pre-ordered vector space (E,E+)(E,E^{+}) and viewing a vector lattice homomorphism as a positive linear map. Simplifying the notation and terminology a little, this leads to the following definition.

Definition 4.1.

A free vector lattice over the pre-ordered vector space (V,V+)(V,V^{+}) is a pair (j,FVL[(V,V+)])(j,{\mathrm{FVL}}[(V,V^{+})]), where FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})] is a vector lattice and j:VFVL[(V,V+)]j\colon V\to{\mathrm{FVL}}[(V,V^{+})] is a positive linear map with the property that, for every positive linear map φ:VF\varphi\colon V\to F into a vector lattice FF, there exists a unique vector lattice homomorphism φ¯:FVL[(V,V+)]F\overline{\varphi}\colon{\mathrm{FVL}}[(V,V^{+})]\to F such that the diagram

(4.1) V{V}FVL[(V,V+)]{{\mathrm{FVL}}[(V,V^{+})]}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}φ¯\scriptstyle{\overline{\varphi}}

commutes.

Remark 4.2.
  1. 1.

    When V+={0}V^{+}=\{0\}, every linear map φ:VF\varphi\colon V\to F is positive, so that (j,FVL[(V,{0})])(j,{\mathrm{FVL}}[(V,\{0\})]) is what is generally called the free vector lattice over the vector space VV.

  2. 2.

    If FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})] exists, then it is clear that its vector sublattice that is generated by j(V)j(V) is also a free vector lattice over (V,V+)(V,V^{+}). Hence the inclusion map from this vector sublattice into FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})] is a (surjective) vector lattice isomorphism. Thus j(V)j(V) generates FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})].

  3. 3.

    If FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})] exists, then it is clear that the map jj in (4.1) is injective if and only if the positive linear maps φ:VF\varphi\colon V\to F into vector lattices FF separate the points of VV. When V+={0}V^{+}=\{0\}, the linear maps into {\mathbbm{R}} already do this, so that the free vector lattice over a vector space VV will contain VV as a subspace. This is not always the case. When V+=VV^{+}=V, the only positive linear map φ\varphi in (4.1) is the zero map. Hence FVL[(V,V)]={0}{\mathrm{FVL}}[(V,V)]=\{0\} and jj is the zero map.

Theorem 4.3.

Let (V,V+)(V,V^{+}) be a pre-ordered vector space. There exists a free vector lattice (j,FVL[(V,V+)])(j,{\mathrm{FVL}}[(V,V^{+})]) over (V,V+)(V,V^{+}). It is generated by j(V)j(V) as a vector lattice.

Proof.

There exists a free vector lattice (j,FVL[(V,{0})]))(j,{\mathrm{FVL}}[(V,\{0\})])) over (V,{0})(V,\{0\}). This is a part of [de_jeu:2021, Theorem 6.2]. Alternatively, one can infer this existence from the well-known fact that the free vector lattice over a set exists (see [baker:1968, birkhoff:1942, bleier:1973, weinberg:1963]). Indeed, the free vector lattice over a basis of VV is then as needed. 444In both approaches, the existence ultimately relies on the existence theorem for free objects in equational classes over sets; see [jacobson_BASIC_ALGEBRA_II_SECOND_EDITION:1989, Corollary to Theorem 2.10], for example. We refer to [de_jeu:2021] for a detailed and self-contained exposition in the context of vector lattices and vector lattice algebras..

Take the order ideal II of FVL[(V,{0})]{\mathrm{FVL}}[(V,\{0\})] that is generated by {j(v)+j(v):vV+}\{j(v)^{+}-j(v):v\in V^{+}\}. Let q:FVL[(V,{0})]FVL[(V,{0})]/Iq\colon{\mathrm{FVL}}[(V,\{0\})]\to{\mathrm{FVL}}[(V,\{0\})]/I denote the quotient map. We claim that (qj,FVL[(V,{0})]/I)(q\circ j^{\prime},{\mathrm{FVL}}[(V,\{0\})]/I) is a free vector lattice over the pre-ordered vector space (V,V+)(V,V^{+}).

Take vV+v\in V^{+}. Then [(qj)(v)]+=[q(j(v))]+=q(j(v)+)=q(j(v))=(qj)(v)[(q\circ j)(v)]^{+}=[q(j(v))]^{+}=q(j(v)^{+})=q(j(v))=(q\circ j)(v). Hence qjq\circ j is positive, as required.

Let EFE\to F be a positive linear map into a vector lattice FF. There exists a unique vector lattice homomorphism φ:FVL[(V,{0})]F\varphi\colon{\mathrm{FVL}}[(V,\{0\})]\to F such that φ¯j=φ\overline{\varphi}\circ j=\varphi. Take vV+v\in V^{+}. Then, using the positivity of φ\varphi in the final step, we have

φ¯(j(v)+j(v))\displaystyle\overline{\varphi}\big{(}j(v)^{+}-j(v)\big{)} =φ¯(j(v)+)φ¯(j(v))\displaystyle=\overline{\varphi}\big{(}j(v)^{+}\big{)}-\overline{\varphi}(j(v))
=[φ¯(j(v))]+φ(v)\displaystyle=\left[\overline{\varphi}(j(v))\right]^{+}-\varphi(v)
=φ(v)+φ(v)\displaystyle=\varphi(v)^{+}-\varphi(v)
=0.\displaystyle=0.

Hence IkerφI\subseteq\operatorname{ker}\varphi, so that there exists a unique vector lattice homomorphism φ¯¯:FVL[(V,{0})]/IF\overline{\overline{\varphi}}\colon{\mathrm{FVL}}[(V,\{0\})]/I\to F such that φ¯¯q=φ¯\overline{\overline{\varphi}}\circ q=\overline{\varphi}. Since the diagram

V{V}FVL[(V,{0})]{{\mathrm{FVL}}[(V,\{0\})]}FVL[(V,{0})]/I{{\mathrm{FVL}}[(V,\{0\})]/I}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}q\scriptstyle{q}φ¯\scriptstyle{\overline{\varphi}}φ¯¯\scriptstyle{\overline{\overline{\varphi}}}

is commutative, we have φ¯¯(qj)=φ\overline{\overline{\varphi}}\circ(q\circ j)=\varphi. To show uniqueness, suppose that ψ:FVL[(V,{0})]/IF\psi\colon{\mathrm{FVL}}[(V,\{0\})]/I\to F is a vector lattice homomorphism such that ψ(qj)=φ\psi\circ(q\circ j)=\varphi. Then (ψq)j=φ(\psi\circ q)\circ j=\varphi, so ψq=φ¯\psi\circ q=\overline{\varphi} and then ψ=φ¯¯\psi=\overline{\overline{\varphi}}. ∎

The following separation result is elementary, and in analogous forms obviously valid in many other contexts. We still include its proof to put later results in a similar vein into perspective.

Proposition 4.4.

Let (V,V+)(V,V^{+}) be a pre-ordered vector spaces. Take 𝔣FVL[(V,V+)]\mathfrak{f}\in{\mathrm{FVL}}[(V,V^{+})]. If φ¯(𝔣)=0\overline{\varphi}(\mathfrak{f})=0 for all positive linear maps φ:VF\varphi\colon V\to F into a vector lattice FF, then 𝔣=0\mathfrak{f}=0.

Proof.

Set Iφkerφ¯I\coloneqq\bigcap_{\varphi}\operatorname{ker}{\overline{\varphi}}, where φ\varphi runs over all positive linear maps φ:VF\varphi\colon V\to F into a vector lattice FF. For each such φ\varphi, we have IkerφI\subseteq\operatorname{ker}\varphi, so there is a unique vector lattice homomorphism φ¯¯:FVL[(V,V+)]/IF\overline{\overline{\varphi}}\colon{\mathrm{FVL}}[(V,V^{+})]/I\to F making the diagram

(4.2) V{V}FVL[(V,V+)]{{\mathrm{FVL}}[(V,V^{+})]}FVL[(V,V+)]/I{{\mathrm{FVL}}[(V,V^{+})]/I}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}q\scriptstyle{q}φ¯\scriptstyle{\overline{\varphi}}φ¯¯\scriptstyle{\overline{\overline{\varphi}}}

commutative. Hence (qj,FVL[(V,V+)]/I)(q\circ j,{\mathrm{FVL}}[(V,V^{+})]/I) is also a free vector lattice over (V,V+)(V,V^{+}). Then the unique vector lattice homomorphism ψ:FVL[(V,V+)]FVL[(V,V+)]/I\psi\colon{\mathrm{FVL}}[(V,V^{+})]\to{\mathrm{FVL}}[(V,V^{+})]/I such that ψj=qj\psi\circ j=q\circ j is an isomorphism. We conclude that qq is injective. ∎

5. Free 𝒞{\mathcalalt C}-convex Banach lattices over pre-ordered Banach spaces: definition and a priori properties

In this section, we define the free 𝒞{\mathcalalt C}-convex Banach lattice FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] over a pre-ordered Banach space (X,X+)(X,X^{+}). We shall see in Section 6 that it always exists. A number of its properties can, however, be determined a priori. We include these here, rather than after the existence has been established, thus emphasizing that they are an immediate consequence of the categorical definition and basic facts about the duals of Banach spaces and Banach lattices. It will become clear that an existing, seemingly stronger, definition in the literature for FBL𝒞[X,{0}]{\mathrm{FBL}}^{\mathcalalt C}[X,\{0\}] is equivalent to ours, but that its natural analogue for the general case where X+X^{+} need not be trivial appears not to be suitable to work with; see Remark 5.12.

Fix a convexity type 𝒞{\mathcalalt C}. In the general context of Definition 2.1, we take for Cat1\textup{{\footnotesize Cat}}_{1} the pre-ordered Banach spaces as objects and the positive contractions as morphisms. Note that, under our standing assumption that {\mathbbm{R}} be 𝒞{\mathcalalt C}-convex, BX+{\mathrm{B}}_{X^{\ast}_{+}} consists of morphisms in Cat1\textup{{\footnotesize Cat}}_{1} for every pre-ordered Banach space (X,X+)(X,{X^{+}}). For Cat2\textup{{\footnotesize Cat}}_{2}, we take the 𝒞{\mathcalalt C}-convex Banach lattices as objects and the contractive vector lattice homomorphisms as morphisms. The functor UU is defined by sending a Banach lattice EE to the pre-ordered Banach space (E,E+)(E,E^{+}) and viewing a contractive vector lattice homomorphism as a positive contraction. This leads to the following definition.

Definition 5.1.

Let 𝒞{\mathcalalt C} be a convexity type. A free 𝒞{\mathcalalt C}-convex Banach lattice over the pre-ordered Banach (X,X+)(X,X^{+}) is a pair (j,FBL𝒞[(X,X+)])(j,{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]), where FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is a 𝒞{\mathcalalt C}-convex Banach lattice and j:XFBL𝒞[(X,X+)]j\colon X\to{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is a positive contraction with the property that, for every positive contraction φ:XF\varphi\colon X\to F into a 𝒞{\mathcalalt C}-convex Banach lattice FF, there exists a unique contractive vector lattice homomorphism φ¯:FBL𝒞[(X,X+)]F\overline{\varphi}\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F such that the diagram

(5.1) X{X}FBL𝒞[(X,X+)]{{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}φ¯\scriptstyle{\overline{\varphi}}

commutes.

Remark 5.2.

When T:XFT\colon X\to F is an arbitrary bounded linear operator, scaling yields that there is a unique vector lattice homomorphism T¯\overline{T} making the diagram commutative. Then T¯=T{\lVert\overline{T}\rVert}={\lVert T\rVert} by Lemma 5.8, below.

If FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists, then it is uniquely determined up to an isometric vector lattice isomorphism. Indeed, for any two free objects, there are mutually inverse contractive vector lattice isomorphisms between them. These contractions must then, in fact, be isometries.

If FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists, then, as for the free vector lattice over a pre-ordered vector space, general principles imply that j(X)j(X) generates FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as a Banach lattice. An argument as that in the proof of Proposition 4.4 shows that the family of all φ¯\overline{\varphi} obtained from (5.1) separate the points of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})].

The following simple observation is pivotal to the results in Section 7.

Lemma 5.3.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. Let FF and FF^{\prime} be 𝒞{\mathcalalt C}-convex Banach lattices, let φ:XF\varphi\colon X\to F be a positive contraction, and let ψ:FF\psi\colon F\to F^{\prime} be a contractive vector lattice homomorphism. Then ψφ¯=ψφ¯\overline{\psi\circ\varphi}=\psi\circ\overline{\varphi}.

Proof.

We have (ψφ¯)j=ψφ(\psi\circ\overline{\varphi})\circ j=\psi\circ\varphi. As ψφ¯\psi\circ\overline{\varphi} is a contractive vector lattice homomorphism, it must be ψφ¯\overline{\psi\circ\varphi}. ∎

Under our standing assumption that {\mathbbm{R}} be 𝒞{\mathcalalt C}-convex it is still possible that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is trivial. This is obviously the case when X+=XX^{+}=X. The general criterion is as follows. In it, and in other results, we prefer to say that BX+{\mathrm{B}}_{X^{\ast}_{+}} is non-trivial or that it separates the points of XX, rather than saying that X+X^{\ast}_{+} has this property. The reason is that the first set consists of morphisms and the second does not when X{0}X\neq\{0\}.

Lemma 5.4.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. Then FBL𝒞[(X,X+)]{0}{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\neq\{0\} if and only if BX+{0}{\mathrm{B}}_{X^{\ast}_{+}}\neq\{0\}.

Proof.

Clearly, if BX+{0}{\mathrm{B}}_{X^{\ast}_{+}}\neq\{0\}, then FBL𝒞[(X,X+)]{0}{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\neq\{0\}, since otherwise the factoring of an arbitrary xx^{*} in BX+{\mathrm{B}}_{X^{\ast}_{+}} would imply that it is 0. Conversely, if FBL𝒞[(X,X+)]{0}{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\neq\{0\}, then its generating linear subspace j(X)j(X) is not trivial. Pick xXx\in X such that j(x)0j(x)\neq 0 and then a positive contractive xx^{*} in the dual of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\neq such that x(j(x))0x^{*}(j(x))\neq 0. Then xjx^{*}\circ j is a non-zero element of BX+{\mathrm{B}}_{X^{\ast}_{+}}. ∎

A similar argument, again using that the positive contractive functionals on FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] separate its points, yields the following.

Lemma 5.5.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. Take xXx\in X. Then j(x)=0j(x)=0 if and only if x(x)=0x^{*}(x)=0 for all xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}. Consequently, jj is injective if and only if BX+{\mathrm{B}}_{X^{\ast}_{+}} separates the points of XX.

Lemma 5.6.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. Then j(x)=maxxBX+x(x){\lVert j(x)\rVert}=\max_{x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}}x^{*}(x) for xX+x\in X^{+}.

Proof.

Take xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}. Then x(x)=|x(x)|=|(x¯j)(x)|j(x)x^{*}(x)={\lvert x^{*}(x)\rvert}={\lvert(\overline{x^{*}}\circ j)(x)\rvert}\leq{\lVert j(x)\rVert}. Hence j(x)supxBX+x(x){\lVert j(x)\rVert}\geq\sup_{x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}}x^{*}(x). For the reverse inequality, take a positive contractive xx^{*} in the dual of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] such that (xj)(x)=x(j(x))=j(x)(x^{*}\circ j)(x)=x^{*}(j(x))={\lVert j(x)\rVert}, which is possible as j(x)j(x) is positive. This implies the reverse inequality, and also that the supremum is a maximum. ∎

As a consequence of Lemmas 5.5 and 5.6 we have the following.

Corollary 5.7.

Let XX be a Banach lattice, and let 𝒞{\mathcalalt C}-type be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. Then jj is injective on XX and isometric on X+X^{+}.

Lemma 5.8.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. If φ:XF\varphi\colon X\to F is a positive contraction into a 𝒞{\mathcalalt C}-convex Banach lattice, then φ=φ¯{\lVert\varphi\rVert}={\lVert\overline{\varphi}\rVert}.

Proof.

We may suppose that φ0\varphi\neq 0. As φ=φ¯j\varphi=\overline{\varphi}\circ j, we have φφ¯{\lVert\varphi\rVert}\leq{\lVert\overline{\varphi}\rVert}. The reverse inequality follows from the observation that φ¯\overline{\varphi} is even the unique vector lattice homomorphism that makes (5.1) commutative. To see this, we note that any such vector lattice homomorphism φ¯\overline{\varphi} is uniquely determined on j(X)j(X) and then also on the vector sublattice generated by j(X)j(X). As this is dense and φ¯\overline{\varphi} is automatically continuous, φ¯\overline{\varphi} is unique.555This argument is also used in[jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, Corollary 3.5]. Now φ/φ\varphi/{\lVert\varphi\rVert} is also a positive contraction, so it has an accompanying contraction (φ/φ)¯\overline{(\varphi/{\lVert\varphi\rVert})} such that φ/φ=(φ/φ)¯j\varphi/{\lVert\varphi\rVert}=\overline{(\varphi/{\lVert\varphi\rVert})}\circ j, which is also the unique vector lattice homomorphism ψ:FBL𝒞[(X,X+)]F\psi\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F such that ψj=φ/φ\psi\circ j=\varphi/{\lVert\varphi\rVert}. As φ¯/φ\overline{\varphi}/{\lVert\varphi\rVert} obviously has this property, it must be the contraction (φ/φ)¯\overline{(\varphi/{\lVert\varphi\rVert})}. Thus φ¯/φ1{\lVert\overline{\varphi}/{\lVert\varphi\rVert}\rVert}\leq 1 and it follows that φ¯φ{\lVert\overline{\varphi}\rVert}\leq{\lVert\varphi\rVert}, as desired. ∎

Lemma 5.9.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. Then FBL𝒞[(X,X+)]{0}{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\neq\{0\} if and only if j=1{\lVert j\rVert}=1.

Proof.

Suppose that FBL𝒞[(X,X+)]{0}{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\neq\{0\}. By Lemma 5.4, there exists a non-zero xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}. Since x=x¯jx¯j=xj{\lVert x^{*}\rVert}={\lVert\overline{x^{*}}\circ j\rVert}\leq{\lVert\overline{x^{*}}\rVert}{\lVert j\rVert}={\lVert x^{*}\rVert}{\lVert j\rVert} we have j1{\lVert j\rVert}\geq 1. Hence j=1{\lVert j\rVert}=1. The converse statement is trivial. ∎

Lemma 5.10.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. If BX+{\mathrm{B}}_{X^{\ast}_{+}} is norming for XX, then jj is isometric. This is the case when X+={0}X^{+}=\{0\}.

Proof.

Let xXx\in X. As BX+{\mathrm{B}}_{X^{\ast}_{+}} is norming, there exists an xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}} such that x=|x(x)|{\lVert x\rVert}={\lvert x^{*}(x)\rvert}. Then x=|x(x)|=|x¯(j(x))|x¯j(x)j(x){\lVert x\rVert}={\lvert x^{*}(x)\rvert}={\lvert\overline{x^{*}}(j(x))\rvert}\leq{\lVert\overline{x^{*}}\rVert}{\lVert j(x)\rVert}\leq{\lVert j(x)\rVert}. As jj is contractive by definition, it is isometric. Clearly, when X+={0}X^{+}=\{0\}, BX+=BX{\mathrm{B}}_{X^{\ast}_{+}}={\mathrm{B}}_{X^{\ast}} is norming for XX.

We refrain from claiming any originality for the following.

Lemma 5.11.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, where X+X^{+} is a closed cone.

  1. 1.

    For xXx\in X, xX+x\in X^{+} if and only if x(x)0x^{*}(x)\geq 0 for all xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}

  2. 2.

    X+X^{\ast}_{+} separates the points of XX.

  3. 3.

    jj is bipositive.

Proof.

The separation theorem [conway_A_COURSE_IN_FUNCTIONAL_ANALYSIS_SECOND_EDITION:1990, Theorem 3.9] shows that, for xX+x\notin X^{+}, there exists an xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}} such that x(x)<0x^{*}(x)<0. This implies the first part, which is still true for closed wedges. For cones, the second part then follows easily. For the third, suppose that j(x)0j(x)\geq 0. Then x(x)=x¯(j(x))0x^{*}(x)=\overline{x^{*}}(j(x))\geq 0 all xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}. Hence x0x\geq 0. ∎

Remark 5.12.

Let XX be a Banach space. As all Banach lattices are \emptyset-convex, a free \emptyset-convex Banach lattice over (X,{0})(X,\{0\}) is a pair (j,FBL[X])(j,{\mathrm{FBL}}[X]), where FBL[X]){\mathrm{FBL}}[X]) is a Banach lattice and j:XFBL[X]j\colon X\to{\mathrm{FBL}}[X] is a contraction with the property that, for every contraction φ:XF\varphi\colon X\to F into a Banach lattice FF, there exists a unique contractive vector lattice homomorphism φ¯:FBL[X]F\overline{\varphi}\colon{\mathrm{FBL}}[X]\to F such that the diagram

(5.2) X{X}FBL[X]{{\mathrm{FBL}}[X]}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}φ¯\scriptstyle{\overline{\varphi}}

commutes. This is almost the definition/description of the free Banach lattice over the Banach space XX in the sense of [aviles_rodriguez_tradacete:2018], but there it is also required that φ¯=φ{\lVert\overline{\varphi}\rVert}={\lVert\varphi\rVert} and that jj be isometric. Lemmas 5.8 and 5.10, however, show that both are automatic for our free objects. Thus the specialisation of our general categorical definition to the case where 𝒞={\mathcalalt C}=\emptyset and X+={0}X^{+}=\{0\} and the definition in [aviles_rodriguez_tradacete:2018] are in agreement after all.

The fact that jj is automatically an isometry when X+={0}X^{+}=\{0\} is a consequence of the fact that BX+{\mathrm{B}}_{X^{\ast}_{+}} is then norming for XX. Since, in the general situation of Definition 5.1, where it is possible that X+{0}X^{+}\neq\{0\}, BX+{\mathrm{B}}_{X^{\ast}_{+}} cannot be expected to be norming for XX, a definition analogous to that in [aviles_rodriguez_tradacete:2018], including the requirement that jj be an isometry, would not, or at least not obviously, lead to a theory in which (j,FBL𝒞[(X,X+)])(j,{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]) exists.

The norm on FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is determined by its universal property in an explicit way.

Lemma 5.13.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] exists. Then, for 𝔣FBL𝒞[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})],

𝔣=maxφφ¯(𝔣),{\lVert\mathfrak{f}\rVert}=\max_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert},

where φ\varphi runs over the positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into 𝒞{\mathcalalt C}-convex Banach lattices FφF_{\varphi}. In particular, for xXx\in X, we have

j(x)=maxφφ(x),{\lVert j(x)\rVert}=\max_{\varphi}{\lVert\varphi(x)\rVert},

where φ\varphi runs over the positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into 𝒞{\mathcalalt C}-convex Banach lattices FφF_{\varphi}.

Proof.

Take 𝔣FBL𝒞[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] and a positive contraction φ:FBL𝒞[(X,X+)]Fφ\varphi\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F_{\varphi} into a 𝒞{\mathcalalt C}-convex Banach lattice FφF_{\varphi}. Then φ¯(𝔣)φ¯𝔣𝔣{\lVert\overline{\varphi}(\mathfrak{f})\rVert}\leq{\lVert\overline{\varphi}\rVert}{\lVert\mathfrak{f}\rVert}\leq{\lVert\mathfrak{f}\rVert}. Hence 𝔣supφφ¯(𝔣){\lVert\mathfrak{f}\rVert}\geq\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert}. For φ=j\varphi=j, φ¯\overline{\varphi} is the identity map. This gives the reverse inequality, and also that the supremum is a maximum. The expression for j(x{\lVert j(x\rVert} is then clear. ∎

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type. What is the relation between the free vector lattice FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] and the free Banach lattice FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]? To make this question precise, we take—if it exists—a free 𝒞{\mathcalalt C}-convex Banach lattice (j,FBL𝒞[(X,X+)])(j,{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]) over (X,X+)(X,X^{+}) and a free vector lattice (jpo,FVL[(X,X+)])(j_{\mathrm{po}},{\mathrm{FVL}}[(X,X^{+})]) over the pre-ordered vector space (X,X+)(X,X^{+}). Here the subscript in the latter indicates that are working with positive linear maps between pre-ordered vector spaces. There is a unique vector lattice homomorphism j¯:FVL[(X,X+)]FBL𝒞[(X,X+)]\overline{j}\colon{\mathrm{FVL}}[(X,X^{+})]\to{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] such that the diagram

(5.3) X{X}FVL[(X,X+)]{{\mathrm{FVL}}[(X,X^{+})]}FBL𝒞[(X,X+)]{{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]}jpo\scriptstyle{j_{\mathrm{po}}}j\scriptstyle{j}j¯\scriptstyle{\overline{j}}

is commutative. Hence j¯(FVL[(X,X+)])\overline{j}\big{(}{\mathrm{FVL}}[(X,X^{+})]\big{)} coincides with the dense vector sublattice of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] that is generated by j(X)j(X). Thus, when j¯\overline{j} is injective, FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] is embedded in FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as a dense vector sublattice. We shall now determine when this is the case. Take a positive contraction φ:XFφ\varphi\colon X\to F_{\varphi} into a 𝒞{\mathcalalt C}-convex Banach lattice FF. There exist a unique vector contractive lattice homomorphism φ¯:FBL𝒞[(X,X+)]F\overline{\varphi}\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F such that φ¯j=φ\overline{\varphi}\circ j=\varphi, and a unique vector lattice homomorphism φpo¯:FVL[(X,X+)]F\overline{\varphi_{\mathrm{po}}}\colon{\mathrm{FVL}}[(X,X^{+})]\to F such that φpo¯jpo=φpo\overline{\varphi_{\mathrm{po}}}\circ j_{\mathrm{po}}=\varphi_{\mathrm{po}}, where φpo\varphi_{\mathrm{po}} indicates that we view φ\varphi as a positive linear map between pre-ordered vector spaces. For xXx\in X, we have

(5.4) (φ¯j¯)(jpo(x))=φ¯(j(x))=φ(x)=φpo¯(jpo(x)).\left(\overline{\varphi}\circ\overline{j}\right)(j_{\mathrm{po}}(x))=\overline{\varphi}(j(x))=\varphi(x)=\overline{\varphi_{\mathrm{po}}}(j_{\mathrm{po}}(x)).

Since they agree on a generating subset of FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})], we have φ¯j¯=φpo¯\overline{\varphi}\circ\overline{j}=\overline{\varphi_{\mathrm{po}}}. As the φ¯\overline{\varphi} as thus obtained separate the points of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})], we now see that, for 𝔣FVL[(X,X+)]\mathfrak{f}\in{\mathrm{FVL}}[(X,X^{+})], j¯(𝔣)=0\overline{j}(\mathfrak{f})=0 if and only if φpo¯(𝔣)=0\overline{\varphi_{\mathrm{po}}}(\mathfrak{f})=0 for all positive contractions φ\varphi from XX into a 𝒞{\mathcalalt C}-convex Banach lattice, seen as positive linear maps with the vector space XX as domain. Therefore, j¯\overline{j} in (5.3) embeds FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] into FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as a (dense) vector sublattice if and only if the φpo¯\overline{\varphi_{\mathrm{po}}} thus obtained separate the points of FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})]. In that case, if we let EE denote the vector sublattice of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] that is generated by j(V)j(V), and view jj as a map with codomain EE, then (j,E)(j,E) is a free vector lattice over the pre-ordered vector space (X,X+)(X,X^{+}). Conversely, if this is the case, then the unique positive linear map j¯\overline{j} that makes (5.3) commutative is an isomorphism, so j¯\overline{j} is injective.

We know from Proposition 4.4 that allowing φ\varphi to be a positive linear map from XX into an arbitrary vector lattice gives a separating family of morphisms φ¯\overline{\varphi} on FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})], but there is no reason why this should be the case for the smaller family that is obtained by allowing only positive contractions into Banach lattices. Hence the dense vector sublattice of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] that is generated by j(X)j(X) will, in general, be a proper quotient of FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})] via the map j¯\overline{j} in (5.3).

When X+={0}X^{+}=\{0\}, however, j¯\overline{j} is always injective. Then the positive contractive φ:X\varphi\colon X\to{\mathbbm{R}} already yield a separating family of vector lattice homomorphisms φ¯po\overline{\varphi}_{\mathrm{po}} for FVL[X,{0}]{\mathrm{FVL}}[X,\{0\}], as a consequence of the following result from [de_jeu_UNPUBLISHED:2020b].

Theorem 5.14.

Let VV be a vector space. Take a separating vector space LL^{*} of linear functionals on VV. Then the l¯\overline{l^{*}} for lLl^{*}\in L^{*} separate the points of FVL[V,{0}]{\mathrm{FVL}}[V,\{0\}].

For a Banach space XX, XX^{\ast} is such a separating vector space, so the xpo¯\overline{x^{*}_{\mathrm{po}}} for xBXx^{*}\in{\mathrm{B}}_{X^{\ast}} are a separating family for FVL[(X,{0})]{\mathrm{FVL}}[(X,\{0\})].

We summarise the above as follows. As said, the existence condition is always fulfilled.

Theorem 5.15.

Let XX be a Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that the free 𝒞{\mathcalalt C}-convex Banach lattice (j,FBL𝒞[(X,X+)])(j,{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]) over XX exists. Let EE be the dense vector sublattice of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] that is generated by j(X)j(X), and view jj as a positive linear map from XX into EE. Then the following are equivalent:

  1. 1.

    (j,E)(j,E) is a free vector lattice over (X,X+)(X,X^{+});

  2. 2.

    The family of vector lattice homomorphism φ¯po:FVL[(X,X+)]Fφ\overline{\varphi}_{\mathrm{po}}\colon{\mathrm{FVL}}[(X,X^{+})]\to F_{\varphi}, obtained as the unique vector lattice homomorphism such that φ¯poj=φ\overline{\varphi}_{\mathrm{po}}\circ j=\varphi as φ\varphi runs over the positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into a 𝒞{\mathcalalt C}-convex Banach lattice FφF_{\varphi}, separate the points of FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})].

When X+={0}X^{+}=\{0\}, this is the case.

Remark 5.16.

Suppose that VV is a vector space and that LL^{*} is a separating vector space of linear functionals on VV. For xVx\in V, define δx:L\delta^{\prime}_{x}\colon L^{*}\to{\mathbbm{R}} by setting δx(l)l(x)\delta_{x}^{\prime}(l^{*})\coloneqq l^{*}(x) for lLl^{*}\in L^{*}, and let EE^{\prime} be the function lattice on LL^{*} that is generated by the δx\delta^{\prime}_{x} for xVx\in V. With δ:VE\delta^{\prime}\colon V\to E^{\prime} denoting the linear map thus obtained, Theorem 5.14 shows that (δ,E)(\delta^{\prime},E^{\prime}) is a free vector lattice over (V,{0})(V,\{0\}).

This applies, in particular, to a Banach space XX and its dual XX^{\ast}. Since restriction of homogeneous functions on XX^{\ast} to BX{\mathrm{B}}_{X^{\ast}} yields an isomorphic function lattice, we can define δx\delta_{x} for xXx\in X as in (2.1) (for X+={0}X^{+}=\{0\}), let EE be the function lattice on BX{\mathrm{B}}_{X^{\ast}} that is generated by the δx\delta_{x}, and let δ:XE\delta\colon X\to E denote the linear map thus obtained. Then (δ,E)(\delta,E) is a free vector lattice over (X,0)(X,0).

This fact seems to have escaped notice in the papers on free Banach lattices so far. In [oikhberg_taylor_tradacete_troitsky_UNPUBLISHED:2022], for example, the lattice linear calculus is used to proved that (δ,E)(\delta,E) has the pertinent universal property with respect to Archimedean vector lattices as codomains (see [oikhberg_taylor_tradacete_troitsky_UNPUBLISHED:2022, p. 24]). As is now clear, the Archimedean property can be omitted, and the lattice linear calculus is not needed.

The proof of Theorem 5.14 in [de_jeu_UNPUBLISHED:2020b] is surprisingly easy, using elegant arguments due to Bleier in [bleier:1973]. It has the existence of FVL[V,{0}]{\mathrm{FVL}}[V,\{0\}], known from universal algebra, as a starting point. In the general case, we do know from Theorem 4.3 that FVL[(V,V+)]{\mathrm{FVL}}[(V,V^{+})] exists, but the method of proof in [de_jeu_UNPUBLISHED:2020b] does not appear to generalise to give any conjectured generalisation of Theorem 5.14 at all. Consequently, to the minds of the authors, a conjecture that the δx\delta_{x} from (2.1) always generate FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] is suspect. This also makes it doubtful whether the methods in [aviles_rodriguez_tradacete:2018] and [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] to construct free Banach lattices can be successful when X+{0}X^{+}\neq\{0\}. These start from—what we now know to be—a canonical realisation of FVL[(X,)]{\mathrm{FVL}}[(X,\emptyset)] on XX^{\ast}, establish ‘by hand’ its universal property in the pertinent context (which we now know to be a consequence of it being a free vector lattice over XX), use this to supply it with a suitable norm, and then complete the space to obtain the sought free object. When the δx\delta_{x} on BX+{\mathrm{B}}_{X^{\ast}_{+}} do not generated FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})], this method is bound to run aground in the very beginning. As we shall see in the next section, however, everything works smoothly as long one does not attempt to start from a function lattice on BX+{\mathrm{B}}_{X^{\ast}_{+}}.

Another matter is the question whether FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] can be realised as a function lattice on some set. As {\mathbbm{R}} is 𝒞{\mathcalalt C}-convex, there is a canonical candidate for such a set, namely X+X^{\ast}_{+}. For 𝔣FBL𝒞[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})], define 𝔣^:\widehat{\mathfrak{f}}\colon\to{\mathbbm{R}} by setting

(5.5) 𝔣^x¯(𝔣)\widehat{\mathfrak{f}}\coloneqq\overline{x^{*}}(\mathfrak{f})

for xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}. The map 𝔣𝔣^\mathfrak{f}\mapsto\widehat{\mathfrak{f}} is then a vector lattice homomorphism from FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] into the vector lattice of all homogeneous functions on BX+{\mathrm{B}}_{X^{\ast}_{+}}. Lemma 5.13 makes clear that convergence in FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] implies uniform convergence in Ch(BX+)\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}). As the dense vector sublattice of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] that is generated by j(X)j(X) clearly maps into Ch(BX+)\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}), this is true for FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] itself.

Proposition 5.17.

Let XX be a Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that the free 𝒞{\mathcalalt C}-convex Banach lattice (j,FBL𝒞[(X,X+)])(j,{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]) over XX exists. The following are equivalent:

  1. 1.

    The map 𝔣𝔣^\mathfrak{f}\mapsto\widehat{\mathfrak{f}} in (5.5) gives a realisation of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as a vector sublattice of Ch(BX+)\mathit{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}).

  2. 2.

    The contractive vector lattice homomorphisms φ¯:FBL𝒞[(X,X+)]F\overline{\varphi}\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F separate the points of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as φ\varphi runs over all positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into finite dimensional Banach lattices FφF_{\varphi}.

Proof.

If 𝔣𝔣^\mathfrak{f}\mapsto\widehat{\mathfrak{f}} is injective, then the φ¯\overline{\varphi} for one-dimensional Banach lattice already suffice to separate the points of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]. Conversely, suppose that the φ¯:XFφ\overline{\varphi}\colon X\to F_{\varphi} for positive contractions φ\varphi into finite dimensional Banach lattices FφF_{\varphi} separate the points of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})], and that 𝔣FBL𝒞[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is such that 𝔣^=0\widehat{\mathfrak{f}}=0. Take such a φ\varphi. As FφF_{\varphi} is isomorphic as a vector lattice to n{\mathbbm{R}}^{n} for some nn, there are—after this identification—x1,,xnBX+x_{1}^{*},\ldots,x_{n}^{*}\in{\mathrm{B}}_{X^{\ast}_{+}} and λ1,,λn0\lambda_{1},\dotsc,\lambda_{n}\geq 0 such that λ1x1,,λnxn\lambda_{1}x_{1}^{*},\cdots,\lambda_{n}x_{n}^{*} are the coordinate components of φ\varphi. By the uniqueness of the factoring morphism, the coordinate components of φ¯\overline{\varphi} are λ1x1¯,,λnxn¯\lambda_{1}\overline{x_{1}^{*}},\cdots,\lambda_{n}\overline{x_{n}^{*}}. Hence φ¯(𝔣)=0\overline{\varphi}(\mathfrak{f})=0. As φ\varphi was arbitrary, we have 𝔣=0\mathfrak{f}=0. ∎

For the free Banach lattices FBL()[(X,X+)]{\mathrm{FBL}}^{(\infty)}[(X,X^{+})] and FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})] in Section 7, the condition in part (2) of Proposition 5.17 is satisfied; see (7.2) and Theorem 7.7. It is thus clear that they can be realised as a vector sublattice of Ch(BX+)\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}). The formulas for the norms in the images are just the transported formulas for the norms in the free Banach lattice.

6. Free 𝒞{\mathcalalt C}-convex Banach lattices over pre-ordered Banach spaces: existence

We shall now show that the free 𝒞{\mathcalalt C}-convex Banach lattice over a pre-ordered Banach space always exists. This generalises [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, Theorem 3.3] in two ways. At the technical level, our convexity types are more general than the convexity conditions in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022]. Subsuming a pre-ordering, however, is a fundamental change.

With the existence of the free vector lattice over a pre-ordered vector space as a starting point, we follow the method that already appears in [de_jeu:2021, pp.103-106] and which is systematically exploited in [van_amstel_THESIS:2023]. The first step is the introduction of a (semi)norm on FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] in terms of its universal property. When X+={0}X^{+}=\{0\}, so that the δx\delta_{x} generated FVL[X,{0}]{\mathrm{FVL}}[X,\{0\}], this is, in fact, also what is done in [aviles_rodriguez_tradacete:2018] and [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], but apparently without the authors being aware of the fact that they were working with FVL[X,{0}]{\mathrm{FVL}}[X,\{0\}]. As argued in Remark 5.16, it seems doubtful that a similar approach, where one starts from a vector lattice on BX+{\mathrm{B}}_{X^{\ast}_{+}}, will work when X+{0}X^{+}\neq\{0\}.

We believe that even when X+={0}X^{+}=\{0\} the construction below is easier. The latter is perhaps best illustrated at the very end, when it needs to be verified that the Banach lattice as constructed is 𝒞{\mathcalalt C}-convex. A non-trivial preparatory technical effort is needed for this in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], but in the proof below it is an immediate consequence of Lemma 3.7.

As in [de_jeu:2021] and [van_amstel_THESIS:2023], the idea is to first take a free object in an algebraic category, and then exploit its universal property to arrive at the desired object in an analytic category. This concept occurs already as early as 1964 in the construction of the enveloping C\text{C}^{\ast}​-algebra of an involutive Banach algebra AA with an isometric involution and an approximate identity; see [dixmier_C-STAR-ALGEBRAS_FRENCH_FIRST_EDITION:1964, Proposition 2.7.1] (or [dixmier_C-STAR-ALGEBRAS_ENGLISH_NORTH_HOLLAND_EDITION:1977, Proposition 2.7.1]). Knowing that C\text{C}^{\ast}​-algebras are subalgebras of some B(H)B(H), what is done is the following: take the free involutive algebra over AA (which is just AA itself), introduce a semi-norm on it in terms of its universal property with respect to C\text{C}^{\ast}​-algebras seen as involutive algebras, quotient out the kernel, and complete the quotient to obtain the so-called enveloping C\text{C}^{\ast}​-algebra of AA. This enveloping C\text{C}^{\ast}​-algebra is, in fact, the free C\text{C}^{\ast}​-algebra over AA in the sense of Definition 2.1. We shall follow the exact same path.

We shall have use for the following preparatory lemma about norming classes of operators. It can very likely already be found elsewhere, but we are not aware of a concrete reference. In view of its pivotal role in the present paper, we include the easy proof.

Lemma 6.1.

Let XX be a normed space. Suppose that, for all xx in a dense subset of XX,

(6.1) x=supφφ(x){\lVert x\rVert}=\sup_{\varphi}{\lVert\varphi(x)\rVert}

where φ\varphi runs over a class of contractions φ:XXφ\varphi\colon X\to X_{\varphi} into normed spaces XφX_{\varphi}. Then (6.1) holds for all xXx\in X.

Proof.

Take xXx\in X. It is clear that xsupφφ(x){\lVert x\rVert}\geq\sup_{\varphi}{\lVert\varphi(x)\rVert}. For the reverse inequality, take ε>0\varepsilon>0 and then an x0x_{0} with xx0<ε/3{\lVert x-x_{0}\rVert}<\varepsilon/3 such that x0=supφφ(x0){\lVert x_{0}\rVert}=\sup_{\varphi}{\lVert\varphi(x_{0})\rVert}. There exists a φ0\varphi_{0} in the class such that x0φ0(x0)+ε/3{\lVert x_{0}\rVert}\leq{\lVert\varphi_{0}(x_{0})\rVert}+\varepsilon/3. Then

x\displaystyle{\lVert x\rVert} xx0+x0\displaystyle\leq{\lVert x-x_{0}\rVert}+{\lVert x_{0}\rVert}
ε/3+φ0(x0)+ε/3\displaystyle\leq\varepsilon/3+{\lVert\varphi_{0}(x_{0})\rVert}+\varepsilon/3
φ0(x0x)+φ0(x)+2ε/3\displaystyle\leq{\lVert\varphi_{0}(x_{0}-x)\rVert}+{\lVert\varphi_{0}(x)\rVert}+2\varepsilon/3
φ0(x)+ε\displaystyle\leq{\lVert\varphi_{0}(x)\rVert}+\varepsilon
supφφ(x)+ε.\displaystyle\leq\sup_{\varphi}{\lVert\varphi(x)\rVert}+\varepsilon.

As ε\varepsilon was arbitrary, we are done. ∎

Starting with the existence proof, let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type. We start by viewing (X,X+)(X,X^{+}) as a pre-ordered vector space and take the free vector lattice (j,FVL[(X,X+)])(j,{\mathrm{FVL}}[(X,X^{+})]) over it, which we know to exist from Theorem 4.3. If φ:XF\varphi\colon X\to F is a positive contraction into a 𝒞{\mathcalalt C}-convex Banach lattice FF, then there exists a unique vector lattice homomorphism φ¯:FVL[(X,X+)]F\overline{\varphi}\colon{\mathrm{FVL}}[(X,X^{+})]\to F such that the diagram

(6.2) X{X}FVL[(X,X+)]{{\mathrm{FVL}}[(X,X^{+})]}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}φ¯\scriptstyle{\overline{\varphi}}

commutes.666In Section 5, this was denoted by φ¯po\overline{\varphi}_{\mathrm{po}}, but here there is no possibility of confusion. Take ξFVL[(X,X+)]\xi\in{\mathrm{FVL}}[(X,X^{+})]. Motivated by Lemma 5.13, we set

(6.3) ρ(ξ):-supφφ¯(ξ)\rho(\xi)\coloneq\sup_{\varphi}{\lVert\overline{\varphi}(\xi)\rVert}

where φ\varphi runs over the positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into 𝒞{\mathcalalt C}-convex Banach lattices FφF_{\varphi}. Evidently, ρ(j(x))=supφφ(x)x\rho(j(x))=\sup_{\varphi}{\lVert\varphi(x)\rVert}\leq{\lVert x\rVert} for xXx\in X. Since the subset of FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] where ρ\rho is finite is easily seen to be a vector sublattice, and since it contains the generating subset j(X)j(X), ρ\rho is finite everywhere. It is a lattice semi-norm. The kernel kerρ(f)\operatorname{ker}\rho(f) is an order ideal of FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})]. Let q:FVL[(X,X+)]FVL[(X,X+)]/kerρq\colon{\mathrm{FVL}}[(X,X^{+})]\to{\mathrm{FVL}}[(X,X^{+})]/\operatorname{ker}\rho denote the quotient map and introduce a lattice norm {\lVert\,\cdot\,\rVert} on FVL[(X,X+)]/kerρ{\mathrm{FVL}}[(X,X^{+})]/\operatorname{ker}\rho by setting q(ξ)ρ(ξ){\lVert q(\xi)\rVert}\coloneqq\rho(\xi) for ξFVL[(X,X+)]\xi\in{\mathrm{FVL}}[(X,X^{+})]. Let FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] be the completion of (FVL[(X,X+)]/kerρ,)({\mathrm{FVL}}[(X,X^{+})]/\operatorname{ker}\rho,{\lVert\,\cdot\,\rVert}) and view qq as a map from FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] into FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]. We claim that, as the notation suggests, (qj,FBL𝒞[(X,X+)])(q\circ j,{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]) is a free 𝒞{\mathcalalt C}-convex Banach lattice over (X,X+)(X,X^{+}). There are a number of things to be checked. First of all, qjq\circ j is positive since qq and jj are; it is contractive as (qj)(x)=ρ(j(x))=supφφ(x)x{\lVert(q\circ j)(x)\rVert}=\rho(j(x))=\sup_{\varphi}{\lVert\varphi(x)\rVert}\leq{\lVert x\rVert} for xXx\in X. Next, take a positive contraction φ:XF\varphi\colon X\to F into a 𝒞{\mathcalalt C}-convex Banach lattice FF. It follows from (6.3) that kerρkerφ¯\operatorname{ker}\rho\subseteq\operatorname{ker}\overline{\varphi}, so there exists a unique vector lattice homomorphism φ¯¯:FVL[(X,X+)]/kerρF\overline{\overline{\varphi}}\colon{\mathrm{FVL}}[(X,X^{+})]/\operatorname{ker}\rho\to F such that φ¯¯q=φ¯\overline{\overline{\varphi}}\circ q=\overline{\varphi}. For ξFVL[(X,X+)]\xi\in{\mathrm{FVL}}[(X,X^{+})], we have φ¯¯(q(ξ))=φ¯(ξ)ρ(ξ)=q(ξ){\lVert\overline{\overline{\varphi}}(q(\xi))\rVert}={\lVert\overline{\varphi}(\xi)\rVert}\leq\rho(\xi)={\lVert q(\xi)\rVert}. Hence φ¯¯\overline{\overline{\varphi}} is a contractive vector lattice homomorphism. It extends to a contractive vector lattice homomorphism φ¯¯¯:FBL𝒞[(X,X+)]F\overline{\overline{\overline{\varphi}}}\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F. It is a consequence of the construction that φ¯¯¯(qj)=φ\overline{\overline{\overline{\varphi}}}\circ(q\circ j)=\varphi. Furthermore, since j(X)j(X) generates FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})] as a vector lattice, (qj)(X)(q\circ j)(X) generates FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] as a Banach lattice. Hence φ¯¯¯\overline{\overline{\overline{\varphi}}} is the only contractive vector lattice homomorphism (by automatic continuity: even the only vector lattice homomorphism) such that φ¯¯¯(qj)=φ\overline{\overline{\overline{\varphi}}}\circ(q\circ j)=\varphi.

The construction is summarised in the following commutative diagram:

(6.4) X{X}FVL[(X,X+)]{{\mathrm{FVL}}[(X,X^{+})]}FVL[(X,X+)]/kerρa{{\mathrm{FVL}}[(X,X^{+})]/\operatorname{ker}\rho_{a}}FBL𝒞[(X,X+)]{{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}q\scriptstyle{q}φ¯\scriptstyle{\overline{\varphi}}φ¯¯\scriptstyle{\overline{\overline{\varphi}}}φ¯¯¯\scriptstyle{\overline{\overline{\overline{\varphi}}}}

It remains to verify that FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is 𝒞{\mathcalalt C}-convex. For this, take ξFVL[(X,X+)]\xi\in{\mathrm{FVL}}[(X,X^{+})]. Then

q(ξ)=ρ(ξ)=supφφ¯(ξ)=supφφ¯¯(q(ξ))=supφφ¯¯¯(q(ξ)).{\lVert q(\xi)\rVert}=\rho(\xi)=\sup_{\varphi}{\lVert\overline{\varphi}(\xi)\rVert}=\sup_{\varphi}{\Big{\lVert}\overline{\overline{\varphi}}(q(\xi))\Big{\rVert}}=\sup_{\varphi}{\Big{\lVert}\overline{\overline{\overline{\varphi}}}(q(\xi))\Big{\rVert}}.

Since q(FVL[(X,X+)])q({\mathrm{FVL}}[(X,X^{+})]) is dense in FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})], Lemma 6.1 yields that

𝔣=supφφ¯¯¯(𝔣){\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\Big{\lVert}\overline{\overline{\overline{\varphi}}}(\mathfrak{f})\Big{\rVert}}

for 𝔣FBL𝒞[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]. By Lemma 3.7, FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] is 𝒞{\mathcalalt C}-convex since all codomains are.

Remark 6.2.

The above construction also works when the zero lattice is the only 𝒞{\mathcalalt C}-convex Banach lattice, in which case the zero outcome is already clear from the start. Under our standing assumption that {\mathbbm{R}} is 𝒞{\mathcalalt C}-convex, it is clear from the a priori results in Section 5 that there is a role to be played by BX+{\mathrm{B}}_{X^{\ast}_{+}} for the properties of FBL𝒞[(X,X+)]{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})], but for its existence as established above there is none.

After brushing up our notation to match that in Definition 5.1, and collecting additional a priori information from Section 5, we have thus established the following.

Theorem 6.3.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space, and let 𝒞{\mathcalalt C} be a convexity type such that {\mathbbm{R}} is 𝒞{\mathcalalt C}-convex. Then there exist a 𝒞{\mathcalalt C}-convex Banach lattice and a positive contraction j:XFBL𝒞[(X,X+)]j\colon X\to{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})] with the property that, for every positive contraction φ:XF\varphi\colon X\to F into a 𝒞{\mathcalalt C}-convex Banach lattice FF, there exists a unique contractive vector lattice homomorphism φ¯:FBL𝒞[(X,X+)]F\overline{\varphi}\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F such that the diagram

(6.5) X{X}FBL𝒞[(X,X+)]{{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]}F{F}j\scriptstyle{j}φ\scriptstyle{\varphi}φ¯\scriptstyle{\overline{\varphi}}

commutes. It is generated by j(X)j(X). Furthermore:

  1. 1.

    For 𝔣FBL𝒞[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})], we have

    (6.6) 𝔣=supφφ¯(𝔣),{\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert},

    where φ\varphi runs over the positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into 𝒞{\mathcalalt C}-convex Banach lattices FφF_{\varphi}. In particular, for xXx\in X, we have

    (6.7) j(x)=supφφ(x),{\lVert j(x)\rVert}=\sup_{\varphi}{\lVert\varphi(x)\rVert},

    where φ\varphi runs over the positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into 𝒞{\mathcalalt C}-convex Banach lattices FφF_{\varphi}.
    For xX+x\in X^{+}, we have

    j(x)=maxxBX+x(x).{\lVert j(x)\rVert}=\max_{x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}}x^{*}(x).
  2. 2.

    φ=φ¯{\lVert\varphi\rVert}={\lVert\overline{\varphi}\rVert}.

  3. 3.

    When X+X^{+} is a closed cone, jj is a bipositive injection.

  4. 4.

    If BX+{\mathrm{B}}_{X^{\ast}_{+}} is norming for XX, then jj is isometric. This is the case when X+=0X^{+}=0.

  5. 5.

    If XX is a Banach lattice, then jj is injective on XX and isometric on X+X^{+}.

  6. 6.

    For xXx\in X, j(x)=0j(x)=0 if and only if x(x)=0x^{*}(x)=0 for all xBX+x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}.

  7. 7.

    The map jj is injective if and only if BX+{\mathrm{B}}_{X^{\ast}_{+}} separates the points of XX.

  8. 8.

    The following are equivalent:

    1. (a)

      FBL𝒞[(X,X+)]{0}{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\neq\{0\};

    2. (b)

      BX+{0}{\mathrm{B}}_{X^{\ast}_{+}}\neq\{0\};

    3. (c)

      j=1{\lVert j\rVert}=1.

    When X+X^{+} is a closed cone, these are also equivalent to:

    1. (d)

      X{0}X\neq\{0\}.

We refer to Theorem 5.15 for the precise criterion when j(X)j(X) generates FVL[(X,X+)]{\mathrm{FVL}}[(X,X^{+})], and recall that this is always the case when X+={0}X^{+}=\{0\}.

7. Realisation of the free pp-convex Banach lattice with pp-convexity constant 1 over a pre-ordered Banach space as a function lattice

We recall from Example 3.6 that (quite obviously) there is a convexity types 𝒞p{\mathcalalt C}_{p} for 1p1\leq p\leq\infty such that the 𝒞p{\mathcalalt C}_{p}-convex Banach lattices are the pp-convex Banach lattices with pp-convexity constant 1. Hence we know from Theorem 6.3 that, for every 1p1\leq p\leq\infty, the free pp-convex Banach lattice with pp-convexity constant 1 over a pre-ordered Banach (X,X+)(X,X^{+}) space exists. We shall denote it by FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})]. The free Banach lattices FBL(p)[X]{\mathrm{FBL}}^{(p)}[X] as in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] are then our FBL(p)[X,{0}]{\mathrm{FBL}}^{(p)}[X,\{0\}]. In this section, we shall give a concrete realisation of FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})] as a Banach lattice of functions. For FBL(p)[X,{0}]{\mathrm{FBL}}^{(p)}[X,\{0\}] such a realisation is known: for p=1p=1 this can be found in [aviles_rodriguez_tradacete:2018] and for 1<p1<p\leq\infty in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022]. When looking at the pertinent realisations as lattices of functions on BX{\mathrm{B}}_{X^{\ast}}, there is a natural Ansatz for the general case: write down the obvious analogues of lattices of functions, but then on BX+{\mathrm{B}}_{X^{\ast}_{+}}, rather than on BX{\mathrm{B}}_{X^{\ast}}. At least when X+={0}X^{+}=\{0\} we know that this gives the right answer. As we shall see, this is indeed correct.

As with existence, our proofs different from those in [aviles_rodriguez_tradacete:2018] and [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], where the existence of FBL(p)[X,{0}]{\mathrm{FBL}}^{(p)}[X,\{0\}] is re-proven by showing that the pertinent function lattice has the correct universal property. Instead, we shall analyse the structure of FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})], which we know to exist, to the point where it is immediate, almost as an afterthought, that it can be realised as a function lattice. To illustrate the difference further, and at the risk of then also annoying the reader further, we remark that, as in Section 5, this section can be read under the hypothesis that FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})] exist. Theorems 7.2 and 7.8 then show what it must look like, should it exist.

Our proof for 1p<1\leq p<\infty profits from the ingenuity of some of the arguments in the proof of [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, Theorem  6.1].

Remark 7.1.

As in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, Example 3.6], if T:XFT\colon X\to F is a bounded linear operator into a pp-convex Banach lattice with pp-convexity constant M(p)(F)M^{(p)}(F), then there exists a unique vector lattice homomorphism T¯:FBL𝒞[(X,X+)]F\overline{T}\colon{\mathrm{FBL}}^{\mathcalalt C}[(X,X^{+})]\to F such that Tj=φT\circ j=\varphi. Moreover T¯M(p)(F)T{\lVert\overline{T}\rVert}\leq M^{(p)}(F){\lVert T\rVert}. This follows from the values of the constants in the renorming in Remark 3.8.

7.1. The case p=p=\infty

This is the easy case. Take 𝔣FBL()[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{(\infty)}[(X,X^{+})]. Then

(7.1) 𝔣=supφφ¯(𝔣),{\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert},

where φ\varphi runs over all positive contractions φ:XFφ\varphi\colon X\to F_{\varphi} into \infty-convex Banach lattice with \infty-convexity constant 1. Take such a φ\varphi. By Proposition 3.4, there exists a contractive vector lattice homomorphism ψ:Fφ\psi\colon F_{\varphi}\to{\mathbbm{R}} such that φ¯(𝔣)=|ψ(φ¯(𝔣))|{\lVert\overline{\varphi}(\mathfrak{f})\rVert}={\lvert\psi(\overline{\varphi}(\mathfrak{f}))\rvert}. By Lemma 5.3, ψφ¯=ψφ¯\overline{\psi\circ\varphi}=\psi\circ\overline{\varphi}. Hence φ¯(𝔣)=|ψφ¯(𝔣)|{\lVert\overline{\varphi}(\mathfrak{f})\rVert}={\lvert\overline{\psi\circ\varphi}(\mathfrak{f})\rvert}. It is now clear that

(7.2) 𝔣=supxBX+|x¯(𝔣)|.{\lVert\mathfrak{f}\rVert}=\sup_{x^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}}{\lvert\overline{x^{*}}(\mathfrak{f})\rvert}.

In view of Proposition 5.17, (7.2) implies that we have a canonical realisation of FBL()[(X,X+)]{\mathrm{FBL}}^{(\infty)}[(X,X^{+})] as a vector sublattice of Ch(BX+)\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}).

For 𝔣FBL()[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{(\infty)}[(X,X^{+})], define 𝔣^:BX+\widehat{\mathfrak{f}}\colon{\mathrm{B}}_{X^{\ast}_{+}}\to{\mathbbm{R}} by setting

𝔣^(x)=x¯(𝔣).\widehat{\mathfrak{f}}(x^{*})=\overline{x^{*}}(\mathfrak{f}).

Using Proposition 5.17, we thus have the following.

Theorem 7.2.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space. Supply Ch(BX+)\mathit{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}) with the maximum norm, and let EE be the closed vector sublattice of the normed vector lattice Ch(BX+)\mathit{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}) that is generated by the δx\delta_{x} for xXx\in X. Define j:XEj\colon X\to E by setting j(x)δxj(x)\coloneqq\delta_{x}. Then (j,E)(j,E) is a free \infty-convex Banach lattice with \infty-convexity constant 1 (i.e., a free AM-space) over (X,X+)(X,X^{+}).

We recall from Theorem 5.15 that, when X+={0}X^{+}=\{0\}, the δx\delta_{x} generate a free vector lattice over (X,{0})(X,\{0\}).

Remark 7.3.

Of course, Ch(BX+)\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}) is a Banach lattice in the maximum norm. We have, nevertheless, formulated the result without this to illustrate the fundamental difference between the present approach and that in [aviles_rodriguez_tradacete:2018] and [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022]. Being an isometric image of FBL()[(X,X+)]{\mathrm{FBL}}^{(\infty)}[(X,X^{+})], we know EE to be complete. In the approach as in [aviles_rodriguez_tradacete:2018] and [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] for X+={0}X^{+}=\{0\}, however, it is essential that everything takes place in what is known to be a complete function lattice. Without this, there is no guarantee that the completion that is taken in the construction yields a function lattice again. In the present approach, this is immaterial.

7.2. The case 1p<1\leq p<\infty

We now turn to the remaining case 1p<1\leq p<\infty, which is more demanding.777 We also include the case p=1p=1. This is excluded in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022, Section 6], perhaps because [aviles_rodriguez_tradacete:2018] then already provides the answer with an easier proof, but the same method works. Our aim is to show that, for 𝔣FBL(p)[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{(p)}[(X,X^{+})],

(7.3) 𝔣=supφφ¯(𝔣),{\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert},

where φ\varphi runs over the positive contractions from XX into pn\ell_{p}^{n} for n=1,2,n=1,2,\ldots. Then Proposition 5.17 will take care of the rest.

The first step towards (7.3) is to note that, for 𝔣FBL(p)[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{(p)}[(X,X^{+})],

(7.4) 𝔣=supφφ¯(𝔣){\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert}

where φ\varphi runs over the positive contractions from XX into Lp(μ)\mathrm{L}_{p}(\mu)-spaces for probability measures μ\mu. This is an immediate consequence of Corollary 3.3 and Lemma 5.3.

We now start the next step, which is the passage from (7.4) to (7.3).

For 1p1\leq p\leq\infty, we let qq denote its conjugate exponent. For gLq(μ)g\in L_{q}(\mu), we write gg^{*} for the corresponding element of Lp(μ)L_{p}(\mu)^{*}. The following preparatory observation from [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022] is at the same time trivial and crucial.

Lemma 7.4.

Let 1p1\leq p\leq\infty, and let f1,,fkLp(μ)f_{1},\dotsc,f_{k}\in\mathit{L}_{p}(\mu) for some (not necessarily probability) measure μ\mu on a set Ω\Omega. Suppose that SS is a measurable subset of Ω\Omega with the property that there exists 1ik1\leq i^{\prime}\leq k such that i=ikfi(ω)=fi(ω)\bigvee_{i=i}^{k}f_{i}(\omega)=f_{i^{\prime}}(\omega) for all ωS\omega\in S. If gLq(μ)g\in\mathit{L}_{q}(\mu) is positive on SS and zero outside SS, then

g(i=ikfi)=i=1kg(fi).g^{*}\left(\bigvee_{i=i}^{k}f_{i}\right)=\bigvee_{i=1}^{k}g^{*}(f_{i}).

Similarly for the infimum.

We shall also use the following, which was essentially proved in [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022].

Lemma 7.5.

Let 1p1\leq p\leq\infty. Suppose that Γ={g1,,gk}Lq(μ)\Gamma=\{g_{1},\dotsc,g_{k}\}\subset\mathit{L}_{q}(\mu) for some (not necessarily probability) measure μ\mu is such that gigj=0g_{i}g_{j}=0 for 1i<jk1\leq i<j\leq k and that giq1{\lVert g_{i}\rVert}_{q}\leq 1 for i=1,,ki=1,\dotsc,k. For fLp(μ)f\in\mathit{L}_{p}(\mu), set

ψΓ(f)(g1(f),,gk(f))pk.\psi_{\Gamma}(f)\coloneqq(g_{1}^{*}(f),\dotsc,g_{k}^{*}(f))\in\ell_{p}^{k}.

Then ψΓ:Lp(μ)pk\psi_{\Gamma}\colon\mathit{L}_{p}(\mu)\to\ell_{p}^{k} is a contraction. If all gig_{i} are positive, then ψΓ\psi_{\Gamma} is positive.

Proof.

Using that the unit ball of qk\ell_{q}^{k} is norming for pk\ell_{p}^{k} in the second equality, we have

ψΓ(f)\displaystyle{\lVert\psi_{\Gamma}(f)\rVert} =(i=1k|gi(f)|p)1/p\displaystyle=\left(\sum_{i=1}^{k}{\lvert g_{i}^{*}(f)\rvert}^{p}\right)^{1/p}
=max(a1,,ak)Bqki=1kaigi(f)\displaystyle=\max_{(a_{1},\dotsc,a_{k})\in{\mathrm{B}}_{\ell_{q}^{k}}}\sum_{i=1}^{k}a_{i}g_{i}^{*}(f)
=max(a1,,ak)Bqk(i=1kaigi)(f).\displaystyle=\max_{(a_{1},\dotsc,a_{k})\in{\mathrm{B}}_{\ell_{q}^{k}}}\left(\sum_{i=1}^{k}a_{i}g_{i}\right)^{*}(f).

The disjointness of the gig_{i} is easily seen to imply that i=1kaigiq1{\lVert\sum_{i=1}^{k}a_{i}g_{i}\rVert}_{q}\leq 1 whenever (a1,,ak)Bqk(a_{1},\dotsc,a_{k})\in{\mathrm{B}}_{\ell_{q}^{k}}. An application of the Hölder inequality concludes the proof. ∎

We now come to the proof proper for 1p<1\leq p<\infty. We use χA\chi_{A} for the characteristic function of a set AA.

Let 𝔣\mathfrak{f} be an element of the vector sublattice of FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})] that is generated by j(X)j(X). Varying on [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], we use (see [aliprantis_burkinshaw_POSITIVE_OPERATORS_SPRINGER_REPRINT:2006, Exercise 4.1.8]) that there exist m,nm,n and xklXx_{kl}\in X for 1km1\leq k\leq m and 1ln1\leq l\leq n such that

𝔣=k=1ml=1nj(xkl).\mathfrak{f}=\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}j(x_{kl}).

Let φ:XLp(μ)\varphi\colon X\to\mathrm{L}_{p}(\mu) be a positive contraction for a probability measure μ\mu on a set Ω\Omega. Then

φ¯(𝔣)=k=1ml=1nφ(xkl).\overline{\varphi}(\mathfrak{f})=\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}\varphi(x_{kl}).

For k=1,,mk^{\prime}=1,\dotsc,m, set

A~k{ωΩ:k=1ml=1n[φ(xkl)](ω)=l=1n[φ(xkl)](ω)}.\widetilde{A}_{k^{\prime}}\coloneqq\left\{\omega\in\Omega:\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}[\varphi(x_{kl})](\omega)=\bigwedge_{l=1}^{n}[\varphi(x_{k^{\prime}l})](\omega)\right\}.

Then Ω=k=1mA~k\Omega=\bigcup_{k^{\prime}=1}^{m}\widetilde{A}_{k^{\prime}}. For k=1,,mk^{\prime}=1,\dotsc,m, set Ak=A~kk<kA~kA_{k^{\prime}}=\widetilde{A}_{k^{\prime}}\setminus\bigcup_{k<k^{\prime}}\widetilde{A}_{k}, so that Ω=k=1mAk\Omega=\bigcup_{k^{\prime}=1}^{m}A_{k}^{\prime} as a disjoint union and

Ak{ωΩ:k=1ml=1n[φ(xkl)](ω)=l=1n[φ(xkl)](ω)}.A_{k^{\prime}}\subseteq\left\{\omega\in\Omega:\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}[\varphi(x_{kl})](\omega)=\bigwedge_{l=1}^{n}[\varphi(x_{k^{\prime}l})](\omega)\right\}.

Proceeding similarly for l=1nφ(xkl)\bigwedge_{l=1}^{n}\varphi(x_{k^{\prime}l}) on AkA_{k^{\prime}}, we obtain a disjoint union Ak=l=1nBklA_{k^{\prime}}=\bigcup_{l^{\prime}=1}^{n}B_{k^{\prime}l^{\prime}} such that

Bkl{ωΩ:l=1n[φ(xkl)](ω)=[φ(xkl)](ω)}.B_{k^{\prime}l^{\prime}}\subseteq\left\{\omega\in\Omega:\bigwedge_{l=1}^{n}[\varphi(x_{k^{\prime}l})](\omega)=[\varphi(x_{k^{\prime}l^{\prime}})](\omega)\right\}.

Finally, set

Bkl+={ωBkl:k=1ml=1n[φ(xkl)](ω)0}B_{k^{\prime}l^{\prime}}^{+}=\left\{\omega\in B_{k^{\prime}l^{\prime}}:\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}[\varphi(x_{kl})](\omega)\geq 0\right\}

and

Bkl={ωBkl:k=1ml=1n[φ(xkl)](ω)<0},B_{k^{\prime}l^{\prime}}^{-}=\left\{\omega\in B_{k^{\prime}l^{\prime}}:\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}[\varphi(x_{kl})](\omega)<0\right\},

so that Ω\Omega is the disjoint union of the Bkl+B_{k^{\prime}l^{\prime}}^{+} and BklB_{k^{\prime}l^{\prime}}^{-}. For all kk^{\prime} and ll^{\prime}, choose a positive gkl+Lq(μ)g_{k^{\prime}l^{\prime}}^{+}\in\mathrm{L}_{q}(\mu) with gkl+1{\lVert g_{k^{\prime}l^{\prime}}^{+}\rVert}\leq 1 which is zero outside Bkl+B_{k^{\prime}l^{\prime}}^{+} and such that

(gkl+)(φ¯(𝔣))=χBkl+φ¯(𝔣)Lp(μ),\left(g_{k^{\prime}l^{\prime}}^{+}\right)^{*}(\overline{\varphi}(\mathfrak{f}))={\left\lVert\chi_{B_{k^{\prime}l^{\prime}}^{+}}\overline{\varphi}(\mathfrak{f})\right\rVert}_{\mathrm{L}_{p}(\mu)},

and a positive gklLq(μ)g_{k^{\prime}l^{\prime}}^{-}\in\mathrm{L}_{q}(\mu) with gkl1{\lVert g_{k^{\prime}l^{\prime}}^{-}\rVert}\leq 1 which is zero outside BklB_{k^{\prime}l^{\prime}}^{-} and such that

|(gkl)(φ¯(𝔣))|=χBklφ¯(𝔣)Lp(μ).{\left\lvert\left(g_{k^{\prime}l^{\prime}}^{-}\right)^{*}(\overline{\varphi}(\mathfrak{f}))\right\rvert}={\left\lVert\chi_{B_{k^{\prime}l^{\prime}}^{-}}\overline{\varphi}(\mathfrak{f})\right\rVert}_{\mathrm{L}_{p}(\mu)}.

From the disjointness of the union, we have

φ¯(𝔣)Lp(μ)p\displaystyle{\lVert\overline{\varphi}(\mathfrak{f})\rVert}_{\mathrm{L}_{p}(\mu)}^{p} =k=1ml=1n(χBkl+φ¯(𝔣)Lp(μ)p+χBklφ¯(𝔣)Lp(μ)p)\displaystyle=\sum_{k^{\prime}=1}^{m}\sum_{l^{\prime}=1}^{n}\left({\left\lVert\chi_{B_{k^{\prime}l^{\prime}}^{+}}\overline{\varphi}(\mathfrak{f})\right\rVert}_{\mathrm{L}_{p}(\mu)}^{p}+{\left\lVert\chi_{B_{k^{\prime}l^{\prime}}^{-}}\overline{\varphi}(\mathfrak{f})\right\rVert}_{\mathrm{L}_{p}(\mu)}^{p}\right)
(7.5) =k=1ml=1n(|(gkl+)(φ¯(𝔣))|p+|(gkl)(φ¯(𝔣))|p).\displaystyle=\sum_{k^{\prime}=1}^{m}\sum_{l^{\prime}=1}^{n}\left({\left\lvert\left(g_{k^{\prime}l^{\prime}}^{+}\right)^{*}(\overline{\varphi}(\mathfrak{f}))\right\rvert}^{p}+{\left\lvert\left(g_{k^{\prime}l^{\prime}}^{-}\right)^{*}(\overline{\varphi}(\mathfrak{f}))\right\rvert}^{p}\right).

The salient point of all this is that, by a double application of Lemma 7.4 in the first equality,

(gkl±)(φ¯(𝔣))\displaystyle\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}(\overline{\varphi}(\mathfrak{f})) =k=1ml=1n(gkl±)[φ(xkl)]\displaystyle=\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}[\varphi(x_{kl})]
=k=1ml=1n((gkl±)φ)(xkl)\displaystyle=\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}\left(\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}\circ\varphi\right)(x_{kl})
=k=1ml=1n((gkl±)φ)¯(j(xkl))\displaystyle=\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}\overline{\left(\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}\circ\varphi\right)}(j(x_{kl}))
=((gkl±)φ)¯(k=1ml=1nj(xkl))\displaystyle=\overline{\left(\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}\circ\varphi\right)}\left(\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}j(x_{kl})\right)
=((gkl±)φ)¯(𝔣).\displaystyle=\overline{\left(\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}\circ\varphi\right)}(\mathfrak{f}).

Thus (7.2) gives that

(7.6) φ¯(𝔣)Lp(μ)p=k=1ml=1n(|((gkl+)φ)¯(𝔣)|p+|((gkl)φ)¯(𝔣)|p).{\lVert\overline{\varphi}(\mathfrak{f})\rVert}_{\mathrm{L}_{p}(\mu)}^{p}=\sum_{k^{\prime}=1}^{m}\sum_{l^{\prime}=1}^{n}\left({\left\lvert\overline{\left(\left(g_{k^{\prime}l^{\prime}}^{+}\right)^{*}\circ\varphi\right)}(\mathfrak{f})\right\rvert}^{p}+{\left\lvert\overline{\left(\left(g_{k^{\prime}l^{\prime}}^{-}\right)^{*}\circ\varphi\right)}(\mathfrak{f})\right\rvert}^{p}\right).

We shall now interpret this. In view of Lemma 7.5, the set

Γ{(gkl±):1km,1ln}\Gamma\coloneqq\left\{\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}:1\leq k^{\prime}\leq m,1\leq l^{\prime}\leq n\right\}

yields a positive contraction ψΓ\psi_{\Gamma} from Lp(μ)\mathrm{L}_{p}(\mu) into p2mn\ell_{p}^{2mn}. Then ψΓφ:Xp2mn\psi_{\Gamma}\circ\varphi\colon X\to\ell_{p}^{2mn} is a positive contraction, the coordinate components of which are the (gkl±)φ\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}\circ\varphi. By the uniqueness of the factor morphism, the coordinate components of ψΓφ¯\overline{\psi_{\Gamma}\circ\varphi} are the (gkl±)φ¯\overline{\left(g_{k^{\prime}l^{\prime}}^{\pm}\right)^{*}\circ\varphi}. Thus (7.6) states that φ¯(𝔣)Lp(μ)p=(ψΓφ)¯(𝔣)p2mnp{\lVert\overline{\varphi}(\mathfrak{f})\rVert}_{\mathrm{L}_{p}(\mu)}^{p}={\lVert\overline{\left(\psi_{\Gamma}\circ\varphi\right)}(\mathfrak{f})\rVert}_{\ell_{p}^{2mn}}^{p}.

Combining this with (7.4), we have established the following.888Naturally, when working with elements of the form k=1mj(xj)l=1nj(yl)\bigvee_{k=1}^{m}j(x_{j})-\bigvee_{l=1}^{n}j(y_{l}), analogously to [jardon-sanchez_laustsen_taylor_tradacete_troitsky:2022], the norm is obtained for positive contractions into p2mn\ell_{p}^{2mn}.

Proposition 7.6.

For 𝔣=k=1ml=1nj(xkl)\mathfrak{f}=\bigvee_{k=1}^{m}\bigwedge_{l=1}^{n}j(x_{kl}) in FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})], its norm is given by

𝔣=supφφ¯(𝔣),{\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert},

where φ\varphi runs over the positive contractions from XX into p2mn\ell_{p}^{2mn}.

Now the work has been done. Evidently, if 𝔣\mathfrak{f} is any element of the vector sublattice of FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})] that is generated by j(X)j(X), then

𝔣=supφφ¯(𝔣){\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert}

as φ\varphi runs over the positive contractions from XX into pn\ell_{p}^{n} for n1n\geq 1. On invoking Lemma 6.1, we have the following.

Theorem 7.7.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space. For 𝔣FBL(p)[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{(p)}[(X,X^{+})], its norm is given by

𝔣=supφφ¯(𝔣),{\lVert\mathfrak{f}\rVert}=\sup_{\varphi}{\lVert\overline{\varphi}(\mathfrak{f})\rVert},

where φ\varphi runs over the positive contractions from XX into pn\ell_{p}^{n} for n1n\geq 1.

As for p=p=\infty, we shall now finally transport FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})] to BX+{\mathrm{B}}_{X^{\ast}_{+}}.

A positive contraction φ:Xpn\varphi\colon X\to\ell_{p}^{n} corresponds to a subset {x1,,xn}BX+\{x_{1}^{*},\dotsc,\dotsc x_{n}^{*}\}\subset{\mathrm{B}}_{X^{\ast}_{+}} such that

supxBXi=1n|xi(x)|p1,\sup_{x\in{\mathrm{B}}_{X}}\sum_{i=1}^{n}{\lvert x_{i}^{*}(x)\rvert}^{p}\leq 1,

in which case φ¯\overline{\varphi} is easily seen to be given by {x1¯,,xn¯}\{\overline{x_{1}^{*}},\dotsc,x\overline{{}_{n}^{*}}\}, as a consequence of the uniqueness of a factor morphism.

Hence

(7.7) 𝔣=sup{(i=1n|xi¯(𝔣)|p)1/p:n1,x1,,xnBX+ s.t. supxBXi=1n|xi(x)|p1}.{\lVert\mathfrak{f}\rVert}=\sup\left\{\left(\sum_{i=1}^{n}{\left\lvert\overline{x_{i}^{*}}(\mathfrak{f})\right\rvert}^{p}\right)^{1/p}\!\!\!\!\!:n\geq 1,x_{1}^{*},\dotsc,x_{n}^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}\text{ s.t.\ }\!\!\sup_{x\in{\mathrm{B}}_{X}}\sum_{i=1}^{n}{\lvert x_{i}^{*}(x)\rvert}^{p}\leq 1\right\}.

For fCh(BX+)f\in\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}), define fp[0,]{\lVert f\rVert}_{p}\in[0,\infty] by setting

fp=sup{(i=1n|f(xi)|p)1/p:n1,x1,,xnBX+ s.t. supxBXi=1n|xi(x)|p1}.{\lVert f\rVert}_{p}\!=\sup\left\{\!\left(\sum_{i=1}^{n}{\left\lvert f(x_{i}^{*})\right\rvert}^{p}\right)^{1/p}\!\!\!\!\!\!\!\!\!\!:n\geq 1,x_{1}^{*},\dotsc,x_{n}^{*}\in{\mathrm{B}}_{X^{\ast}_{+}}\text{ s.t.\ }\!\!\sup_{x\in{\mathrm{B}}_{X}}\sum_{i=1}^{n}{\lvert x_{i}^{*}(x)\rvert}^{p}\leq 1\right\}.

Set

Cph(BX+){fCh(BX+):fp<}.\mathrm{C}^{\mathrm{h}}_{p}({\mathrm{B}}_{X^{\ast}_{+}})\coloneqq\left\{f\in\mathrm{C}^{\mathrm{h}}({\mathrm{B}}_{X^{\ast}_{+}}):{\lVert f\rVert}_{p}<\infty\right\}.

This is a vector lattice, and we supply it with the lattice norm p{\lVert\,\cdot\,\rVert}_{p}.

For 𝔣FBL(p)[(X,X+)]\mathfrak{f}\in{\mathrm{FBL}}^{(p)}[(X,X^{+})], define 𝔣^:BX+\widehat{\mathfrak{f}}\colon{\mathrm{B}}_{X^{\ast}_{+}}\to{\mathbbm{R}} by setting 𝔣^(x)x¯(𝔣)\widehat{\mathfrak{f}}(x^{*})\coloneqq\overline{x^{*}}(\mathfrak{f}).

Then Proposition 5.17 yields the following.

Theorem 7.8.

Let (X,X+)(X,X^{+}) be a pre-ordered Banach space. Let EE be the closed sublattice of the normed vector lattice Cph(BX+)\mathit{C}^{\mathrm{h}}_{p}({\mathrm{B}}_{X^{\ast}_{+}}) that is generated by the δx\delta_{x} for xXx\in X. Define j:XEj\colon X\to E by setting j(x)δxj(x)\coloneqq\delta_{x}. Then (j,E)(j,E) is a free pp-convex Banach lattice with pp-convexity constant 1 over (X,X+)(X,X^{+}).

We recall from Theorem 5.15 that, when X+={0}X^{+}=\{0\}, the δx\delta_{x} generate a free vector lattice over (X,{0})(X,\{0\}).

Remark 7.9.

It is routine to verify that Cph(BX+)\mathrm{C}^{\mathrm{h}}_{p}({\mathrm{B}}_{X^{\ast}_{+}}) is a pp-convex Banach lattice with pp-convexity constant 1. As for the case p=p=\infty, it is not necessary to know that this space is complete to realise FBL(p)[(X,X+)]{\mathrm{FBL}}^{(p)}[(X,X^{+})] as a Banach lattice of homogeneous continuous functions on BX+{\mathrm{B}}_{X^{\ast}_{+}}.

References