Examples of hyperbolic spaces without the properties of quasi-ball or bounded eccentricity
Abstract.
In this note, we present examples of non-quasi-geodesic metric spaces which are hyperbolic (i.e., satisfying the Gromov’s -point condition) while the intersection of any two metric balls therein does not either “look like” a ball or has uniformly bounded eccentricity. This answers an open question posed in [2].
Keywords: Gromov’s hyperbolic spaces, Non-(quasi)-geodesic, Quasi-ball property, Bounded eccentricity property
1. Introduction
In the seminal work [4], Gromov introduced a notion of hyperbolicity for metric spaces which encodes the information of metric curvatures for the underlying spaces, with prototypes from classic hyperbolic geometry. Gromov’s hyperbolic spaces have attractd a lot of interest since they are discovered and have fruitful applications in various aspects of mathematics (see, e.g., [1, 3]).
Recall that a geodesic metric space is called hyperbolic (in the sense of Gromov [4]) if there exists such that for any geodesic triangle in , the union of the -neighbourhoods of any two sides of the triangle contains the third. Gromov also provided a characterisation for his hyperbolicity using the so-called Gromov product:
He proved in [4] that a geodesic metric space is hyperbolic if and only if the following condition holds:
Gromov’s -point condition: There exists such that
Note that the statement of the Gromov’s -point condition does not require that the underlying space is geodesic. Hence in the general context, we say that a (not necessarily geodesic) metric space is hyperbolic if the Gromov’s -point condition holds.
Later in [2], Chatterji and Niblo discovered new characterisations of Gromov’s hyperbolicity for geodesic metric spaces using the geometry of intersections of balls. More precisely, for a geodesic metric space, they showed that it is hyperbolic in the sense of Gromov if and only if the following holds:
Quasi-ball property: The intersection of any two metric balls is at uniformly bounded Hausdorff distance from a ball.
They also considered the eccentricity of the intersection of balls. Recall that for a metric space and , we say that the eccentricity of a subset of is less than if there exist and such that
(1.1) |
Here we use to denote the metric ball. The eccentricity of is the infimum of satisfying (1.1). By convention, the eccentricity of the empty set is . Chatterji and Niblo proved in [2] that a geodesic metric space is hyperbolic if and only if the following holds:
Bounded eccentricity property: The intersection of any two metric balls has uniformly bounded eccentricity.
In [2, Section 4], Chatterji and Niblo also discussed the situation of non-geodesic metric spaces. They recorded an example due to Viktor Schroeder (see [2, Example 18]) that there exists a non-geodesic metric space with the quasi-ball property but not hyperbolic (i.e., does not satisfy the Gromov’s -point condition). However, the other direction is unclear and hence, they asked the following:
Question 1.1.
Does there exist a non-geodesic hyperbolic metric space which does not satisfy the quasi-ball property or the bounded eccentricity property?
In this short note, we provide an affirmative answer to Question 1.1 by constructing concrete examples. The main result is the following:
Theorem 1.2.
There exists a non-quasi-geodesic hyperbolic (i.e., satisfying the Gromov’s -point condition) space which does not satisfy either the quasi-ball property or the bounded eccentricity property.
Our construction is motivated by Gromov’s observation in [4, Section 1.2] (also suggested in [2, Section 4]) that for a metric space , we can endow another metric on defined by
(1.2) |
such that satisfies the Gromov’s -point condition. We show that if is geodesic and unbounded, then cannot be quasi-geodesic (see Corollary 3.3). Then we study the relation of the quasi-ball property and the bounded eccentricity property between and (see Lemma 3.5, Lemma 3.7 and Lemma 3.9). Finally, we show in Example 3.10 that for the Euclidean space with the Euclidean metric , the construction in (1.2) provides an example to conclude Theorem 1.2.
2. Preliminaries
Here we collect some necessary notions and notation for this note.
Let be a metric space. For and , denote the (metric) ball by . We say that is bounded if there exist and such that , and unbounded if it is not bounded. For a subset and , denote the -neighbourhood of in . For subsets , the Hausdorff distance between and is
Recall that a path in a metric space is a continuous map . A path is called rectifiable if its length
is finite. Usually it is convenient to change the parameter to the standard arc parameter as follows. Define a map by , and set by . Then we have for any .
Now we recall the notion of (quasi-)geodesics.
Definition 2.1.
Let be a metric space.
-
(1)
Given , a geodesic between and is an isometric embedding with and . The space is called geodesic if for any in , there exists a geodesic between and .
-
(2)
Given and , an -quasi-geodesic between and is a map such that and
The space is called -quasi-geodesic if for any in , there exists an -quasi-geodesic between and . We also say that is quasi-geodesic if it is -quasi-geodesic for some and .
We also need the notion of ultrametric space. Recall that a metric space is called ultrametric if there exists such that for any points , we have
The following is due to Gromov:
Lemma 2.2 ([4, Section 1.2]).
An ultrametric space satisfies the Gromov’s -point condition.
3. Proof of Theorem 1.2
This whole section is devoted to the proof of Theorem 1.2, which is divided into several parts.
Firstly, we would like to study the property of (quasi-)geodesic for the new metric defined in (1.2). To simplify the notation, for a path in , we denote and its length with respect to the metric and , respectively.
We need the following lemma:
Lemma 3.1.
Let be a metric space and be the metric on defined in (1.2). A path in is rectifiable with respect to if and only if it is rectifiable with respect to . In this case, we have .
Proof.
Firstly, we assume that is rectifiable with respect to , i.e., . Note that holds for all . Hence for any partition , we have
which implies that . In particular, is rectifiable with respect to .
Conversely, we assume that is rectifiable with respect to , i.e., . Without loss of generality, we can assume that is parametrised by the standard arc parameter with and . Note that for any , there exists such that holds for all . Given a partition , we choose a refinement such that holds for all . Hence we have
which implies that due to (1.2). Therefore, we obtain
for all . Letting and taking the supremum of the left hand side, we obtain that , which concludes the proof. ∎
As a direct corollary, we obtain the following:
Corollary 3.2.
Let be a geodesic metric space which contains at least two elements, and be the metric defined in (1.2). Then the metric space is not geodesic.
Proof.
By assumption, we take two distinct points . If is geodesic, we choose a geodesic between and . In particular, is rectifiable with respect to . Hence by Lemma 3.1, we know that is also rectifiable with respect to and we have
where the last inequality follows from the assumption that . This is a contradiction to the assumption that is a geodesic between and with respect to the metric . Hence we conclude the proof. ∎
Moreover, with an extra hypothesis, the new metric cannot be even quasi-geodesic.
Corollary 3.3.
Let be an unbounded geodesic metric space, and be the metric defined in (1.2). Then for any and , the metric space cannot be -quasi-geodesic.
To prove Corollary 3.3, we need the following lemma to tame quasi-geodesics. The idea is similar to [1, Lemma III.H.1.11], but the setting is slightly different.
Lemma 3.4.
Let be a geodesic metric space and be the metric defined in (1.2). Given an -quasi-geodesic with respect to , there exists a continuous and rectifiable -quasi-geodesic with respect to satisfying the following:
-
(1)
and ;
-
(2)
;
-
(3)
for all , where and ;
-
(4)
.
Careful readers might already notice that in the situation of [1, Lemma III.H.1.11], we need to assume that the new metric on is geodesic instead of the current setting that the original metric is geodesic. Although the proof is similar, here we also provide one for convenience to readers.
Proof of Lemma 3.4.
Define to agree with on , then choose geodesic segments with respect to joining the images of successive points in and define by concatenating linear reparameterisations of these geodesic segments.
Let denote the point of closest to . Note that the -distance of the images of successive points in is at most , and hence we have
which implies that . Since is an -quasi-geodesic with respect to , and for all , we have
and similarly, we have
(3.1) |
for all . Hence is an -quasi-geodesic with respect to .
Proof of Corollary 3.3.
Assume that is -quasi-geodesic for some and . For any , choose an -quasi geodesic (with respect to ) connecting them. Lemma 3.4 implies that there is a rectifiable path which is an -quasi-geodesic (with respect to ) connecting and . Moreover, we have for and . Hence Lemma 3.1 implies that
Note that is unbounded, which implies that is also unbounded. Hence taking , we conclude a contradiction and finish the proof. ∎
Next, we move to study the relation of the quasi-ball property and the bounded eccentricity property between the metric spaces and . Again to save the notation, for and , we denote and the closed balls with respect to the metrics and , respectively. For and , we denote and the -neighbourhood of with respect to the metrics and , respectively.
Lemma 3.5.
Let be a metric space and be the metric on defined in (1.2). Then has the quasi-ball property if and only if has the quasi-ball property.
Proof.
Firstly, we assume that has the quasi-ball property, i.e., there exists such that the intersection of any two balls in is -close to another ball (i.e., their Hausdorff distance is bounded by ). Note that there exists such that for all . This implies that for with , we have .
Given two balls and in , it is clear that and . Hence by the assumption, there exists another ball in such that
It follows from the previous paragraph that in this case, we have
Hence has the quasi-ball property.
The converse holds similarly, using the fact that holds for all . ∎
Combining Lemma 2.3, Corollary 3.3 and Lemma 3.5, we obtain the following, which concludes part of Theorem 1.2.
Corollary 3.6.
Let be a geodesic metric space which is not hyperbolic (e.g., the Euclidean space with the Euclidean metric) and be the metric on defined in (1.2). Then is a non-quasi-geodesic metric space which satisfies the Gromov’s -point condition but not the quasi-ball property.
Concerning the bounded eccentricity property, we have the following:
Lemma 3.7.
Let be a metric space and be the metric on defined in (1.2). If satisfies the bounded eccentricity property, so does .
Proof.
Given two balls and in , we assume that their intersection is non-empty. Note that
is again an intersection of balls in . Hence by the assumption, there exist and such that
Therefore in , we have
Then the eccentricity of in is bounded above by
which concludes the proof. ∎
Remark 3.8.
Readers might wonder whether the converse to Lemma 3.7 holds. Unfortunately, in general this is false. Note that if we have
in , then it implies that
in . Hence the eccentricity of in is bounded by . However, if (i.e., the radius of the ball contained in ) does not have a uniform upper bound, then neither does the eccentricity of .
Lemma 3.9.
Let be a metric space and be the metric on defined in (1.2). Assume that there exists a sequence of subsets of satisfying the following:
-
(1)
each is the intersection of two balls in ;
-
(2)
there exists such that for all , the radius (with respect to ) of any ball contained in is bounded above by ;
-
(3)
the eccentricity of in is not uniformly bounded.
Then does not satisfy the bounded eccentricity property.
Proof.
Assume the opposite, i.e., there exists such that the eccentricity of the intersection of any two balls in is uniformly bounded by . Hence by condition (1) we know that for each , there exist and such that
Hence in , we have
By condition (2), we know that for all . Therefore, we have
which is a contradiction to condition (3) in the assumption. ∎
Example 3.10.
Now we show that there exists a non-quasi-geodesic metric space which satisfies the Gromov’s -point condition but not the bounded eccentricity property. For example, take to be the Euclidean space equipped with the Euclidean metric, and let be the metric on defined in (1.2). Lemma 2.3 and Corollary 3.3 imply that is not quasi-geodesic but satisfies the Gromov’s -point condition.
For each , take and and set
It is easy to see that in , the biggest ball contained in is . Moreover, the diameter of is
which implies that the eccentricity of cannot be uniformly bounded. Therefore applying Lemma 3.9, we conclude the result.
Proof of Theorem 1.2.
Finally, recall that in [5] the following weaker form of the bounded eccentricity property was considered: For a metric space , there exist and such that for any two balls with non-empty intersection there exist and such that
Wenger showed in [5] that this condition also implies Gromov’s hyperbolicity for geodesic metric spaces.
We remark that this weaker form of the bounded eccentricity property does not hold either for the space constructed in Example 3.10.
References
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- [2] Indira Chatterji and Graham A. Niblo. A characterization of hyperbolic spaces. Groups Geom. Dyn., 1(3):281–299, 2007.
- [3] É. Ghys and P. de la Harpe, editors. Sur les groupes hyperboliques d’après Mikhael Gromov, volume 83 of Progress in Mathematics. Birkhäuser Boston, Inc., Boston, MA, 1990.
- [4] M. Gromov. Hyperbolic groups. In Essays in group theory, pages 75–263. Springer, 1987.
- [5] Stefan Wenger. Characterizations of metric trees and Gromov hyperbolic spaces. Math. Res. Lett., 15(5):1017–1026, 2008.