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Entanglement witness for combined atom interferometer-mechanical oscillator setup

Gayathrini Premawardhana [email protected] Joint Center for Quantum Information and Computer Science, University of Maryland-NIST, College Park, Maryland 20742, USA    Deven P. Bowman [email protected] Department of Physics, University of Maryland, College Park, Maryland 20742, USA Department of Physics, Stanford University, Stanford, California 94305, USA    Jacob M. Taylor [email protected] Joint Center for Quantum Information and Computer Science, University of Maryland-NIST, College Park, Maryland 20742, USA Joint Quantum Institute, University of Maryland-NIST, College Park, Maryland 20742, USA
Abstract

We investigate how to entangle an atom interferometer and a macroscopic mechanical oscillator in order to create non-classical states of the oscillator. We propose an entanglement witness, from whose violation, the generation of entanglement can be determined. We do this for both the noiseless case and when including thermal noise. Thermal noise can arise from two sources: the first being when the oscillator starts in a thermal state, and the second when a continuous thermal bath is in contact with the oscillator. We find that for the appropriate oscillator quality factor QQ, violation always exists for any value of magnetic coupling λ\lambda and thermal occupancy n¯\bar{n}. Cooling the oscillator to its ground state provides an O(n¯)O(\bar{n}) improvement in the EW violation than starting in a thermal state. However, this still requires at least 105 measurements to be determined. We then consider how to use magnetic interactions to realize this idea.

preprint: APS/123-QED

Entanglement is a core feature of quantum mechanics that precludes any hidden variable classical theory. Many groups have considered entanglement in macroscopic systems, particularly in the case of spin-spin systems [1, 2, 3, 4, 5], oscillator-oscillator systems [6, 7, 8, 9, 10, 11, 12], and spin-oscillator systems [13, 14, 15]. For instance, Kong et al. experimentally generate entanglement between the spins of atoms in a vapor [1], Ockeloen-Korppi et al. use a cavity to entangle two mirrors located 600 µm apart [6], and Riedinger et al. entangle two chips separated by 20 cm [7]. Thomas et al. entangle a spin ensemble with a square membrane of sides 1 mm in length [13].

Of particular interest are approaches to entangle masses and/or spins to investigate theories that incorporate quantum mechanics with gravity. For example, Kafri et al. [16], Bose et al. [2] and Marletto et al. [17] propose using two masses which interact with each other though a gravitational force; if the two masses become entangled, then we can conclude that the gravitational field is capable of generating entanglement. A different approach by Carney et al. [18] suggests gravitationally coupling an atom interferometer with a mechanical oscillator. If the interaction is capable of entanglement, the oscillator and the atoms will get entangled, which can be detected using the interferometer’s signal.

Such experiments have to use certain techniques to determine the existence of entanglement. The experiments in Ref. [1, 6, 7, 13, 2] use (or propose using) an entanglement witness (EW) that work for very low noise situations, where one prepares pure states of the two systems, and noise and decoherence are neglected. An EW is a quantity composed of observables; it has a bound satisfied by separable states, which, if violated, determines that entanglement exists between the systems. The literature on creating an entanglement witness is varied. The most well-known example of EWs might be Bell inequalities [19, 20] used to distinguish between the possibility of local hidden variable theories and entanglement. Another common EW is one which is often applied to oscillator-oscillator entanglement, whose general version was proposed by Duan et al. [21].

In this paper, we work within the context of the proposal by Carney et al. [18], introduced previously. In the progress towards such a gravity experiment, it is more reasonable to first attempt the generation of magnetic entanglement between the atom interferometer and the oscillator, since a sufficiently strong magnetic coupling is easier to obtain. Before proceeding with physically building the experiment, it is important to ensure that entanglement will exist, at least theoretically, and understand the physical parameters at which it will occur. In order to do this, we construct an entanglement witness (EW) for our setup that provides a path for violation at finite motional temperatures and with noise and dephasing. We investigate the effects of thermal noise on its violation and establish the conditions on parameters such that violation exists. We find that for appropriate values of oscillator quality factor QQ, violation always exists for any value of magnetic coupling λ\lambda and thermal occupancy n¯\bar{n}.

Refer to caption
Figure 1: (a) Simplified version of oscillator-interferometer setup. The atoms (pink) of the interferometer are in traps [22], and are located at equal distances above and below the center of the cylinder. An external magnetic field 𝐁ext\mathbf{B_{\rm{ext}}} induces a magnetic field in the cylinders which have magnetic susceptibility χm\chi_{m}. The oscillator rotates in the horizontal plane with frequency ω\omega. (b) Depiction of how the oscillator and spin operators become correlated with each other, with η=2/(mω)(g/ω)\eta=\sqrt{2/(m\omega)}~{}(g/\omega). The explicit expressions are given in the Supplemental Material.

General entanglement witness - A simplified setup that we can consider is shown in Figure 1. The Hamiltonian of the system is (note that =1\hbar=1 herein) [18]

H=ωc^c^+g(c^+c^)J^z.H=\omega\hat{c}^{\dagger}\hat{c}+g(\hat{c}+\hat{c}^{\dagger})\hat{J}_{z}. (1)

c^\hat{c}^{\dagger} and c^\hat{c} are the oscillator creation and annihilation operators. J^z\hat{J}_{z} is a pseudo-spin operator describing the location of NN atoms; that is, J^z=j=1NS^z,j\hat{J}_{z}=\sum_{j=1}^{N}\hat{S}_{z,j}, where S^z,j\hat{S}_{z,j} characterizes which of the two interferometer traps the jthj^{th} atom is in. As stated earlier, the creation of entanglement between the interferometer and the oscillator can be determined by measuring an entanglement witness (EW). We find that the following quantity is an applicable EW for our setup:

W=Var(J^x)+Var(J^y+ayq^+byp^)+Var(J^z+azq^+bzp^)W=\textrm{Var}(\hat{J}_{x})+\textrm{Var}(\hat{J}_{y}+a_{y}\hat{q}+b_{y}\hat{p})+\textrm{Var}(\hat{J}_{z}+a_{z}\hat{q}+b_{z}\hat{p}) (2)

Here, J^μ=j=1NS^μ,j\hat{J}_{\mu}=\sum_{j=1}^{N}\hat{S}_{\mu,j} and q^(t)=1/(2mω)(c^+c^)\hat{q}(t)=\sqrt{1/(2m\omega)}(\hat{c}+\hat{c}^{\dagger}). The coefficients aμa_{\mu} and bμb_{\mu} can be chosen as appropriate. Such spin-oscillator variances allow for the characterization of spin-oscillator correlations. Eq. 2 is bounded by WbW_{b} for all separable states. If this bound is violated by the experimental state of concern, we can conclude that it is an entangled state.

WbW_{b} can be derived using the theorem in the paper by Hofmann et al. [23]. They showed that for operators A^μ\hat{A}_{\mu} of system AA and B^μ\hat{B}_{\mu} of system BB, if μVar(A^μ)UA\sum_{\mu}\textrm{Var}(\hat{A}_{\mu})\geq U_{A} and μVar(B^μ)UB\sum_{\mu}\textrm{Var}(\hat{B}_{\mu})\geq U_{B}, then μVar(A^μ+B^μ)UA+UB\sum_{\mu}\rm{Var}(\hat{A}_{\mu}+\hat{B}_{\mu})\geq U_{A}+U_{B} for any separable state. Starting with W~=μVar(J^μ+aμq^+bμp^)\tilde{W}=\sum_{\mu}\textrm{Var}(\hat{J}_{\mu}+a_{\mu}\hat{q}+b_{\mu}\hat{p}), where the summation μ\sum_{\mu} is over the x,y,x,y, and zz components, we follow Ref. [23] to arrive at the general bound W~[μVar(J^μ)]min+[μVar(aμq^+bμp^)]min\tilde{W}\geq\left[\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\right]_{\rm{min}}+\left[\sum_{\mu}\textrm{Var}(a_{\mu}\hat{q}+b_{\mu}\hat{p})\right]_{\rm{min}}. To obtain the witness in Eq. 2, we set ax=0a_{x}=0 and bx=0b_{x}=0 on the left and right hand sides of this inequality.

The oscillator-operator bound can be derived using the Heisenberg uncertainty principle and carrying out a minimization process; we get μxVar(aμq^+bμp^)|aybzazby|\sum_{\mu\neq x}\textrm{Var}(a_{\mu}\hat{q}+b_{\mu}\hat{p})\geq|a_{y}b_{z}-a_{z}b_{y}|. In analogy to a derivation in Ref. [23], the general bound for the spin operators is μVar(J^μ)j\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\geq j, which for a fully symmetric state will be μVar(J^μ)N/2\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\geq N/2. The most general case will be μVar(J^μ)[j]min,exp\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\geq[j]_{\textrm{min,exp}} where [j]min,exp[j]_{\textrm{min,exp}} is the minimum value that jj can take at the time of measurement.

For the EW in Eq. 2, we can finally write the general bound to be

Wb=[j]min,exp+|aybzazby|.W_{b}=[j]_{\textrm{min,exp}}+|a_{y}b_{z}-a_{z}b_{y}|. (3)

That is, for a separable state, the condition that WWbW\geq W_{b} will be satisfied. If we evaluate WW with respect to a possibly entangled state in order to obtain the value WenW_{\rm{en}} and find that Wen<WbW_{\rm{en}}<W_{b}, then the bound is violated and we can conclude that the state is indeed entangled.

We explore this EW in the context of two scenarios; when the systems are noiseless and when there is thermal noise (the case of atomic dephasing can be found in the Supplementary Material). For each scenario, we determine whether the EW is violated. In an experimental setting, WbW_{b} is a theoretical value that we have at hand, while WenW_{\rm{en}} is the quantity that we estimate through measurement. We consider the quantity Wratio=[(WbWen)/Wb]maxW_{\rm{ratio}}=\left[(W_{b}-W_{\rm{en}})/{W_{b}}\right]_{\rm{max}}; the EW is violated if Wratio>0W_{\rm{ratio}}>0. Since the imprecision is set by WbWenW_{b}-W_{\rm{en}}, WratioW_{\rm{ratio}} informs us of the number of measurements nmeasn_{\rm{meas}} required to determine the existence of entanglement, since nmeasWratio2n_{\rm{meas}}\sim W_{\rm{ratio}}^{-2}.

A key step in this process is determining the coefficients aμa_{\mu} and bμb_{\mu}, where we attempt to minimize the variance of the EW. When |WbWen||Wb||W_{b}-W_{\rm{en}}|\ll|W_{b}|, finding aμa_{\mu} and bμb_{\mu} that maximizes |WbWen||W_{b}-W_{\rm{en}}| suffices. Practically, however, finding |WbWen|max|W_{b}-W_{\rm{en}}|_{\rm{max}} is complicated due to the absolute value term given by |aybzazby||a_{y}b_{z}-a_{z}b_{y}|. Therefore, in this paper we minimize the value WenW_{\rm{en}}.

Noiseless entanglement witness - First, we investigate the violation for the noiseless scenario. Here the atomic states starts in the J^x\hat{J}_{x} eigenstate |+++\ket{++...+} and the oscillator in the ground state |0\ket{0} [18]; after evolving under Eq. 1, the final entangled state is given by |ψen\ket{\psi_{\rm{en}}} (explicit form is given in the Supplemental Material).

We can understand the evolution of the system described by Eq. 1 within the Heisenberg picture. The first component to consider is the Heisenberg operator c^(t)=eiωtc^(0)i0t𝑑tgJ^zeiω(tt)\hat{c}(t)=e^{-i\omega t}\hat{c}(0)-i\int_{0}^{t}dt^{\prime}~{}g\hat{J}_{z}e^{-i\omega(t-t^{\prime})}. The second component is the rotation of the spin operators J^x\hat{J}_{x} and J^y\hat{J}_{y} about the z-axis by angle ϵ(t)=g0t𝑑t[c^(t)+c^(t)]\epsilon(t)=g\int_{0}^{t}dt^{\prime}~{}[\hat{c}(t^{\prime})+\hat{c}(t^{\prime})^{\dagger}], due to the term gq^J^zg~{}\hat{q}\hat{J}_{z} in the Hamiltonian; this is visually shown in Figure 1. These two components show us that the different operators become correlated with each other, for instance, q^(t)\hat{q}(t) with J^z\hat{J}_{z}. Optimizing the values of aμa_{\mu} and bμb_{\mu} translates to controlling the contributions of these correlations such that the variances of Eq. 2 are minimized for the entangled state. For instance, if we consider the operator combination J^y(t)+ayq^(t)+byp^(t)\hat{J}_{y}(t)+a_{y}\hat{q}(t)+b_{y}\hat{p}(t), to first order in λ\lambda (where λ=g/ω\lambda=g/\omega) for simplicity, we have

J^y(t)+ayq^(t)+byp^(t)J^y+λJ^x[2mω[p^p^cos(ωt)]+2mωq^sin(ωt))]+ay[q^cos(ωt)+p^sin(ωt)mω]+by[p^cos(ωt)mωq^sin(ωt)]+O(λJ^z)\begin{split}&\hat{J}_{y}(t)+a_{y}\hat{q}(t)+b_{y}\hat{p}(t)\\ &\approx\hat{J}_{y}+\lambda\hat{J}_{x}\left[\sqrt{\frac{2}{m\omega}}~{}[\hat{p}-\hat{p}\cos(\omega t)]+\sqrt{2m\omega}~{}\hat{q}\sin(\omega t))\right]\\ &+a_{y}\left[\hat{q}\cos(\omega t)+\frac{\hat{p}\sin(\omega t)}{m\omega}\right]+b_{y}[\hat{p}\cos(\omega t)-m\omega\hat{q}\sin(\omega t)]\\ &+O(\lambda\hat{J}_{z})\end{split} (4)

The first line of Eq. 4 is the Heisenberg-evolved operator J^y(t)\hat{J}_{y}(t) expanded to O(λ)O(\lambda) (with the squeezing term dropped). The term ayq^(t)+byp^(t)a_{y}\hat{q}(t)+b_{y}\hat{p}(t) added to Jy(t)J_{y}(t) contributes the coefficients aya_{y} and byb_{y}; given the explicit form of ayq^(t)+byp^(t)a_{y}\hat{q}(t)+b_{y}\hat{p}(t) as shown in the second line of Eq. 4, it seems plausible that values for aya_{y} and byb_{y} can be chosen such that the contribution to J^y(t)\hat{J}_{y}(t) from J^x\hat{J}_{x} can be canceled. Note that, since we are starting in the state |++\ket{++...}, the J^x\hat{J}_{x} operators here evaluate to N/2N/2 and the O(λJ^z)O(\lambda\hat{J}_{z}) terms evaluate to 0.

If we proceed with solving for aμa_{\mu} and bμb_{\mu}, we see that this does indeed occur. We first expand various products of the operators (J^x(t)q^(t)\hat{J}_{x}(t)\hat{q}(t), etc.) to O(λ2)O(\lambda^{2}); O(λ2)O(\lambda^{2}) should be appropriate, since the only other parameter that can greatly “cancel out” the effects of λ\lambda is the number of atoms NN and the highest order of NN is N2N^{2} (which arises from the squaring of the spin operators). Once we have these Heisenberg-evolved operators and their products, we can evaluate their expectation values with respect to |++|0\ket{++...}\ket{0} (which is the remainder of |ψen\ket{\psi_{\rm{en}}}) to obtain WenW_{\rm{en}}.

Now we can minimize WenW_{\rm{en}} with respect to aμa_{\mu} and bμb_{\mu}. We find that

ay,0,λ\displaystyle a_{\rm{y,0,\lambda}} =λNmω2sin(ωt)\displaystyle=-\lambda N\sqrt{\frac{m\omega}{2}}\sin(\omega t) (5)
by,0,λ\displaystyle b_{\rm{y,0,\lambda}} =λN12mω[1cos(ωt)]\displaystyle=\lambda N\sqrt{\frac{1}{2m\omega}}[1-\cos(\omega t)] (6)
az,0,λ\displaystyle a_{\rm{z,0,\lambda}} =λNmω2[1cos(ωt)]\displaystyle=\lambda N\sqrt{\frac{m\omega}{2}}[1-\cos(\omega t)] (7)
bz,0,λ\displaystyle b_{\rm{z,0,\lambda}} =λN12mωsin(ωt)\displaystyle=\lambda N\sqrt{\frac{1}{2m\omega}}\sin(\omega t) (8)

As can be seen, these coefficients and, thereby, the EW of Eq. 2, depend on the following experimental parameters: the coupling λ\lambda, the number of atoms NN, the mass of the oscillator mm, oscillator frequency ω\omega, and the interaction time tt. Furthermore, these coefficients satisfy 𝐚𝐛=0\mathbf{a}\cdot\mathbf{b}=0.

We can substitute these coefficients into Eq. 4 to see how they can be used to cancel out correlations between operators. If we were to set ++|J^x|++=N/2\bra{++...}\hat{J}_{x}\ket{++...}=N/2, we find that ψen|J^y+ayq^+byp^|ψen=0|++|J^y|++|0\bra{\psi_{\rm{en}}}\hat{J}_{y}+a_{y}\hat{q}+b_{y}\hat{p}\ket{\psi_{\rm{en}}}=\bra{0}\bra{++...}\hat{J}_{y}\ket{++...}\ket{0}.

We can now finally obtain the bound

Wb,0=N2+λ2N2|[1cos(ωt)]|W_{\rm{b,0}}=\frac{N}{2}+\lambda^{2}N^{2}|[1-\cos(\omega t)]| (9)

and the entangled-state value

Wen,0=N2λ2N22[1cos(ωt)].W_{\rm{en,0}}=\frac{N}{2}-\frac{\lambda^{2}N^{2}}{2}[1-\cos(\omega t)]. (10)

We see that |ψen\ket{\psi}_{\rm{en}} violates the EW bound by a value of (3/2)λ2N2[1cos(ωt)](3/2)\lambda^{2}N^{2}[1-\cos(\omega t)]. It must be emphasized again that these calculations hold for λ1\lambda\ll 1. The exact limit on λ\lambda is such that Eq. 10 is always positive; that is, the result is valid for λ<1/2N\lambda<1/\sqrt{2N}, which for N=106N=10^{6} would be λ<7×104\lambda<7\times 10^{-4}. Fig. 2 shows a plot of the violation (black line); it is highest at t=π/ωt=\pi/\omega, which is consistent with the results in Carney et al. [18] where the oscillator is completely entangled with the atoms at t=π/ωt=\pi/\omega.

Figure 2: The black line depicts the noiseless case. We have set λ=104.5\lambda=10^{-4.5}, N=106N=10^{6}, and ω=2π/20\omega=2\pi/20 rad/s. White noise depends only on n¯/Q\bar{n}/Q. Thus, the scenario where the oscillator starts in a ground state and then remains in contact with a bath can be characterized solely using n¯/Q\bar{n}/Q. However, a value for n¯\bar{n} must be set when starting in a thermal state. Since the condition n¯λ21\bar{n}\lambda^{2}\ll 1 must be satisfied, we consider n¯=325\bar{n}=325 to be the highest appropriate value. Purple lines correspond to n¯/Q=1/10\bar{n}/Q=1/10 and blue lines correspond to n¯/Q=1/4\bar{n}/Q=1/4. As can be seen in the plots, the lower the value of n¯/Q\bar{n}/Q, the better the violation. Note that introducing a bath results in the violation not being seen for the entire oscillator period; where the plots get truncated is when WbWen<0W_{b}-W_{\rm{en}}<0.
Refer to caption

Entanglement witness with a thermal state and white noise bath - We can now consider the case of thermal noise. There are three scenarios that can be considered; the first when the oscillator starts in a thermal state, the second when the oscillator starts in a thermal state and remains in contact with a white noise bath, and the third when the oscillator starts in the ground state and remains in contact with a bath.

For a thermal state ρ^=n=0enβω1eβω|nn|\ \hat{\rho}=\sum_{n=0}^{\infty}\frac{e^{-n\beta\omega}}{1-e^{-\beta\omega}}\ket{n}\bra{n} [24], we find that, to O(λ)O(\lambda), the new coefficients are

ay,n¯\displaystyle a_{\rm{y,\bar{n}}} =λNmω2sin(ωt)\displaystyle=-\lambda N\sqrt{\frac{m\omega}{2}}\sin(\omega t) (11)
by,n¯\displaystyle b_{\rm{y,\bar{n}}} =λN12mω[1cos(ωt)]\displaystyle=\lambda N\sqrt{\frac{1}{2m\omega}}[1-\cos(\omega t)] (12)
az,n¯\displaystyle a_{\rm{z,\bar{n}}} =λN2n¯+1mω2[1cos(ωt)]\displaystyle=\frac{\lambda N}{2\bar{n}+1}\sqrt{\frac{m\omega}{2}}[1-\cos(\omega t)] (13)
bz,n¯\displaystyle b_{\rm{z,\bar{n}}} =λN2n¯+112mωsin(ωt)\displaystyle=\frac{\lambda N}{2\bar{n}+1}\sqrt{\frac{1}{2m\omega}}\sin(\omega t) (14)

The next order of these coefficients is O(λ3)O(\lambda^{3}). Comparing with Equations 5-8, it can be seen that az,n¯a_{\rm{z,\bar{n}}} and bz,n¯b_{\rm{z,\bar{n}}} have been modified by a factor of 1/(2n¯+1)1/(2\bar{n}+1). However, they no longer satisfy 𝐚𝐛=0\mathbf{a}\cdot\mathbf{b}=0. As explained previously, and as can be seen by their similar forms, these coefficients work together with the covariances and correlations to minimize the value of WenW_{\rm{en}} when starting in a thermal state.

The bound to O(λ2)O(\lambda^{2}) is

Wb,n¯=N2+12n¯+1λ2N2|[1cos(ωt)]|W_{\rm{b,\bar{n}}}=\frac{N}{2}+\frac{1}{2\bar{n}+1}\lambda^{2}N^{2}|[1-\cos(\omega t)]| (15)

and the entangled state value of the EW to O(λ2)O(\lambda^{2}) is

Wen,n¯=N212n¯+1λ2N22[1cos(ωt)].W_{\rm{en,\bar{n}}}=\frac{N}{2}-\frac{1}{2\bar{n}+1}\frac{\lambda^{2}N^{2}}{2}[1-\cos(\omega t)]. (16)

The expansion to O(λ2)O(\lambda^{2}) is only valid if n¯λ21\bar{n}\lambda^{2}\ll 1; larger n¯λ2\bar{n}\lambda^{2} leads to key corrections associated with atomic phase evolution of order unity. Plots for different values of n¯\bar{n} are shown in Fig. 2; the higher the value of n¯\bar{n}, the weaker the violation.

Next, we consider a scenario where the oscillator is in continuous contact with white noise, which approximates a thermal bath at high temperature. The Hamiltonian is now given by

H=ωc^c^+[gJz+Fin(t)](c^+c^),H=\omega\hat{c}^{\dagger}\hat{c}+[gJ_{z}+F_{\rm{in}}(t)](\hat{c}+\hat{c}^{\dagger}), (17)

where Fin(t)F_{\rm{in}}(t) is a classical white noise force; this Hamiltonian is simply that of Eq. 1 to which the effect from Fin(t)F_{\rm{in}}(t) has been added. The auto-correlation function is a delta function with an amplitude set by the fluctuation-dissipation theorem Fin(t)Fin(t)=n¯γδ(tt)\langle\langle F_{\rm{in}}(t)F_{\rm{in}}(t^{\prime})\rangle\rangle=\bar{n}\gamma\delta(t-t^{\prime}). Proceeding to understand within the Heisenberg picture as previously, we can solve for c^(t)\hat{c}(t) to obtain c^(t)=eiωtc^(0)i0t𝑑t(gJ^z+Fin(t))eiω(tt)\hat{c}(t)=e^{-i\omega t}\hat{c}(0)-i\int_{0}^{t}dt^{\prime}~{}(g\hat{J}_{z}+F_{in}(t^{\prime}))e^{-i\omega(t-t^{\prime})}. With q^(t)=qzpf[c^(t)+c^(t)]\hat{q}(t)=q_{\rm{zpf}}[\hat{c}(t)+\hat{c}^{\dagger}(t)] and p^(t)=ipzpf[c^(t)+c^(t)]\hat{p}(t)=ip_{\rm{zpf}}[-\hat{c}(t)+\hat{c}^{\dagger}(t)], the noise contributions to q^(t)\hat{q}(t) and p^(t)\hat{p}(t) can be expressed as 𝒬(t)=2qzpf0t𝑑tFin(t)sin[ω(tt)]\mathcal{Q}(t)=-2q_{\rm{zpf}}\int_{0}^{t}dt^{\prime}~{}F_{\rm{in}}(t^{\prime})\sin[\omega(t-t^{\prime})] and 𝒫(t)=2pzpf0t𝑑tFin(t)cos[ω(tt)]\mathcal{P}(t)=-2p_{\rm{zpf}}\int_{0}^{t}dt^{\prime}~{}F_{\rm{in}}(t^{\prime})\cos[\omega(t-t^{\prime})]. Further, J^x\hat{J}_{x} and J^y\hat{J}_{y} will rotate about the z-axis by an angle ξ(t)=g0t𝑑t[c^(t)+c^(t)]\xi(t)=g\int_{0}^{t}dt^{\prime}~{}[\hat{c}(t^{\prime})+\hat{c}(t^{\prime})^{\dagger}] as follows: J^y(t)=J^ycos[ξ(t)]+J^xsin[ξ(t)]\hat{J}_{y}(t)=\hat{J}_{y}\cos[\xi(t)]+\hat{J}_{x}\sin[\xi(t)] and J^x(t)=J^xcos[ξ(t)]J^ysin[ξ(t)]\hat{J}_{x}(t)=\hat{J}_{x}\cos[\xi(t)]-\hat{J}_{y}\sin[\xi(t)]. The white noise contribution to this angle is given by Ξ(t)=g0t𝑑t𝒬(t)/qzpf=2g0t0t𝑑t′′𝑑tFin(t′′)sin[ω(tt′′)]\Xi(t)=-g\int_{0}^{t}dt^{\prime}~{}\mathcal{Q}(t^{\prime})/q_{\rm{zpf}}=2g\int_{0}^{t}\int_{0}^{t^{\prime}}dt^{\prime\prime}dt^{\prime}~{}F_{\rm{in}}(t^{\prime\prime})\sin[\omega(t^{\prime}-t^{\prime\prime})]. Note that here, qzpf=1/(2mω)q_{\rm{zpf}}=\sqrt{1/(2m\omega)} and pzpf=mω/2p_{\rm{zpf}}=\sqrt{m\omega/2}.

Note that 𝒬(t)\mathcal{Q}(t), 𝒫(t)\mathcal{P}(t), and Ξ(t)\Xi(t) are not operators since they arise from the classical noise Fin(t)F_{\rm{in}}(t); therefore, their covariances consist of averages over classical noise and are hence represented with the notation \langle\langle...\rangle\rangle. For instance, Ξ(t)Ξ(t)\langle\langle\Xi(t)\Xi(t)\rangle\rangle contributes to the noise in the EW term ΔJ^x2\Delta\langle\langle\hat{J}_{\rm{x}}\rangle\rangle^{2} and 𝒬(t)𝒬(t)\langle\langle\mathcal{Q}(t)\mathcal{Q}(t)\rangle\rangle contributes to the noise in q^2\langle\langle\hat{q}^{2}\rangle\rangle. Therefore, the expectation values that compose the EW must be modified by adding the noise contributions ΔJ^x2\Delta\langle\langle\hat{J}_{\rm{x}}\rangle\rangle^{2}, Δq2\Delta\langle\langle q^{2}\rangle\rangle, Δp2\Delta\langle\langle p^{2}\rangle\rangle, Δp^J^y+J^yp^\Delta\langle\langle\hat{p}\hat{J}_{y}+\hat{J}_{y}\hat{p}\rangle\rangle, Δq^J^y+J^yq^\Delta\langle\langle\hat{q}\hat{J}_{y}+\hat{J}_{y}\hat{q}\rangle\rangle and Δq^p^+q^p^\Delta\langle\langle\hat{q}\hat{p}+\hat{q}\hat{p}\rangle\rangle; an appropriate linear combination of these gives ΔWn¯,noise\Delta W_{\rm{\bar{n},noise}}. Thus, we now have, Wen,n¯,noise=Wen,n¯+ΔWn¯,noiseW_{\rm{en,\bar{n}},noise}=W_{\rm{en,\bar{n}}}+\Delta W_{\rm{\bar{n},noise}}, where

ΔWn¯,noise=N24λ2n¯Q[6ωt8sin(ωt)+sin(2ωt)]+ay12mωN216λn¯Qsin4(ωt2)bymω2N28λn¯Q[ωt2sin(ωt)+sin(2ωt)4]+(ay2+az2)12mωn¯Q[2ωtsin(2ωt)]+(by2+bz2)mω2n¯Q[2ωt+sin(2ωt)]+(ayby+azbz)2n¯Qsin2(ωt)\begin{split}\Delta W_{\bar{n},\rm{noise}}&=\frac{N^{2}}{4}\frac{\lambda^{2}\bar{n}}{Q}[6\omega t-8\sin(\omega t)+\sin(2\omega t)]\\ &+a_{y}\sqrt{\frac{1}{2m\omega}}\frac{N}{2}\frac{16\lambda\bar{n}}{Q}\sin^{4}\left(\frac{\omega t}{2}\right)\\ &-b_{y}\sqrt{\frac{m\omega}{2}}\frac{N}{2}\frac{8\lambda\bar{n}}{Q}\left[\frac{\omega t}{2}-\sin(\omega t)+\frac{\sin(2\omega t)}{4}\right]\\ &+(a_{y}^{2}+a_{z}^{2})\frac{1}{2m\omega}\frac{\bar{n}}{Q}[2\omega t-\sin(2\omega t)]\\ &+(b_{y}^{2}+b_{z}^{2})\frac{m\omega}{2}\frac{\bar{n}}{Q}[2\omega t+\sin(2\omega t)]\\ &+(a_{y}b_{y}+a_{z}b_{z})\frac{2\bar{n}}{Q}\sin^{2}(\omega t)\end{split} (18)

with the coefficients being those in Equations 11-14. Note that the terms where λ\lambda appears have been truncated to O(λ2)O(\lambda^{2}). The term J^x2+Jy2\langle\langle\hat{J}_{x}^{2}+J_{y}^{2}\rangle\rangle is unaffected by noise as it commutes through the Hamiltonian. Therefore, for the spin variances, only the term ΔJ^x2\Delta\langle\langle\hat{J}_{\rm{x}}\rangle\rangle^{2} comes into play; starting in J^x\hat{J}_{x} eigenstate means that, to O(λ2)O(\lambda^{2}), there is no noise contribution from J^y\langle\langle\hat{J}_{\rm{y}}\rangle\rangle either.

Using the previous bound in Eq. 15, we plot the EW violation in Figure 2 (dotted lines). For violation to take place, the condition that

Qn¯>π[7+12n¯(1+n¯)]6(1+2n¯)πn¯\ \frac{Q}{\bar{n}}>\frac{\pi[7+12\bar{n}(1+\bar{n})]}{6(1+2\bar{n})}\sim\pi\bar{n} (19)

is required when t=π/ωt=\pi/\omega. The bound is approximately πn¯\pi\bar{n} for n¯1\bar{n}\gg 1.

We can further consider the scenario where the oscillator is cooled to its ground state at the start, but remains in contact with a bath for the rest of time; this is given by Wen,0,noise=Wen,0+ΔWn¯,noiseW_{\rm{en,0},noise}=W_{\rm{en,0}}+\Delta W_{\rm{\bar{n},noise}}, with the coefficients of Eqs. 5-8 being used in Eq. 18 (see Supplemental Material for “re-optimized” coefficients). The dot-dashed lines in Fig. 2 shows the violation for different values of n¯/Q\bar{n}/Q. The condition for violation to take place is now

Qn¯>csc(ωt2)212[10ωt4ωtcos(ωt)4sin(ωt)sin(2ωt)]\ \frac{Q}{\bar{n}}>\frac{\csc(\frac{\omega t}{2})^{2}}{12}[10\omega t-4\omega t\cos(\omega t)-4\sin(\omega t)-\sin(2\omega t)] (20)

which for t=π/ωt=\pi/\omega is Qn¯>(7π/6)\frac{Q}{\bar{n}}>(7\pi/6). This is O(n¯)O(\bar{n}) better than for an initial thermal state.

We now investigate the value of the magnetic coupling in Figure 1. A large diamagnetic coupling can be attained by using superconducting masses and placing the atoms in different magnetically sensitive states. For instance, we can place one atom in the mF=1m_{F}=1 state and the other in mF=1m_{F}=-1. In such a scenario, the coupling would primarily be due to the first order Zeeman shift, which is linear in BB [25]. For a cylinder with 2R=L=52R=L=5 mm, χ=1\chi=-1, density=11.34=11.34 g/cm3 [26], Δz=5μ\Delta z=5~{}\mum, s=8s=8 mm, R0=4.5R_{0}=4.5 cm, Bext=B_{\rm{ext}}= 50 mT, ω=2π/20\omega=2\pi/20, and N=106N=10^{6}, we get λ=6.3×104\lambda=6.3\times 10^{-4}. A coupling approximately ×102\times 10^{2} weaker is available for atomic clock (mF=0m_{F}=0) states. For details on this calculation, see the Supplemental Material; this includes the cylindrical field expressions [27], and calculations for regular metals like tungsten [28, 29].

Conclusion - Within the context of a combined atom interferometer and oscillator system, we can use an entanglement witness to show that entanglement exists even in the case where the oscillator starts in a thermal state and remains in contact with a bath. In fact, we find that for the appropriate oscillator quality factor QQ and thermal occupancy n¯\bar{n}, violation always exists for any value of magnetic coupling λ\lambda. Additionally, an O(n¯)O(\bar{n}) improvement in the EW violation if the oscillator is cooled to its ground state before running the experiment. However, to observe this violation, the number of measurements required would be at least on the order of 105. Hence, experimentally using the proposed EW to measure entanglement may not be ideal; rather our results tell us that with the right physical parameters we can indeed experimentally generate entanglement between an atom interferometer and a mechanical oscillator, even with thermal noise. For practical detection of entanglement, other methods will have to be employed.

Acknowledgments - We would like to acknowledge Yuxin Wang and Jon Kunjummen for conceptual and mathematical discussions. We would also like to thank our collaborators for helping with experimental details and overall discussions, in particular, Jon Pratt, Garrett Louie, Cristian Panda, Prabudhya Bhattacharyya, Matt Tao, Lorenz Keck, James Egelhoff, John Manley, Stephan Schlamminger, Holger Müller, and Daniel Carney. We thank Daniel Barker and John Manley for comments on our paper. The work of G. P. and D. B. was made possible by the Heising-Simons Foundation grant 2023-4467 “Testing the Quantum Coherence of Gravity” and through the support of Grant 63121 from the John Templeton Foundation. The opinions expressed in this publication are those of the authors and do not necessarily reflect the views of the John Templeton Foundation. J. T. is solely funded by the National Institute of Standards and Technology.

I Supplemental Material: Entanglement witness for combined atom interferometer-mechanical oscillator setup

I.1 Entanglement witness

This section provides more details and discussion on the derivation of the entanglement witness and its violation in the noiseless and thermal noise scenarios. Additionally, we add a section on the effects of atomic dephasing.

I.1.1 General entanglement witness form and bound

We investigate the entanglement witness,

W=Var(J^x)+Var(J^y+ayq^+byp^)+Var(J^z+azq^+bzp^).W=\textrm{Var}(\hat{J}_{x})+\textrm{Var}(\hat{J}_{y}+a_{y}\hat{q}+b_{y}\hat{p})+\textrm{Var}(\hat{J}_{z}+a_{z}\hat{q}+b_{z}\hat{p}). (21)

As we stated in the main paper, the bound for WW can be derived using the theorem in the paper by Hofmann et al. [23]: for operators A^μ\hat{A}_{\mu} of system AA and B^μ\hat{B}_{\mu} of system BB, if μVar(A^μ)UA\sum_{\mu}\textrm{Var}(\hat{A}_{\mu})\geq U_{A} and μVar(B^μ)UB\sum_{\mu}\textrm{Var}(\hat{B}_{\mu})\geq U_{B}, then μVar(A^μ+B^μ)UA+UB\sum_{\mu}\rm{Var}(\hat{A}_{\mu}+\hat{B}_{\mu})\geq U_{A}+U_{B} for any separable state. There is, however, a prerequisite that for each operator A^μ\hat{A}_{\mu} there must be a B^μ\hat{B}_{\mu}. In the case of Eq. 21, A^μ=J^μ\hat{A}_{\mu}=\hat{J}_{\mu} and B^μ=aμq^+bμp^\hat{B}_{\mu}=a_{\mu}\hat{q}+b_{\mu}\hat{p}. It can be seen in Eq. 21 that there is a term with no oscillator operators, and composed of only the spin operator J^x\hat{J}_{x}; we do not measure correlations between J^x\hat{J}_{x} and the oscillator operators because the mean of these correlations are zero, at least for the noiseless entangled state in Equation 34. In order to satisfy the requirement of every A^μ\hat{A}_{\mu} operator having its counterpart B^μ\hat{B}_{\mu}, we started with the term Var(J^x+axq^+bxp^)\textrm{Var}(\hat{J}_{x}+a_{x}\hat{q}+b_{x}\hat{p}) and set the coefficients axa_{x} and bxb_{x} to zero after the derivation of the bound. We lay out this derivation here.

Starting with W~=μVar(J^μ+aμq^+bμp^)\tilde{W}=\sum_{\mu}\textrm{Var}(\hat{J}_{\mu}+a_{\mu}\hat{q}+b_{\mu}\hat{p}), where the summation μ\sum_{\mu} is over the x,y,x,y, and zz components, we follow Ref. [23] to arrive at the general bound

W~[μVar(J^μ)]min+[μVar(aμq^+bμp^)]min.\tilde{W}\geq\left[\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\right]_{\rm{min}}+\left[\sum_{\mu}\textrm{Var}(a_{\mu}\hat{q}+b_{\mu}\hat{p})\right]_{\rm{min}}. (22)

To obtain the witness in Eq. 21, we set ax=0a_{x}=0 and bx=0b_{x}=0 on the left and right hand sides of the inequality. The oscillator-operator bound can be derived as follows: we have

Var(A)+Var(B)=Var(A)+Var(A)Var(B)Var(A)\textrm{Var}(A)+\textrm{Var}(B)=\textrm{Var}(A)+\frac{\textrm{Var}(A)\textrm{Var}(B)}{\textrm{Var}(A)} (23)

for which we can apply the Heisenberg uncertain principle

Var(A)Var(B)14|[A,B]|2\textrm{Var}(A)\textrm{Var}(B)\geq\frac{1}{4}|\langle[A,B]\rangle|^{2} (24)

and minimize the R.H.S to give

Var(A)+Var(B)|[A,B]|.\textrm{Var}(A)+\textrm{Var}(B)\geq|\langle[A,B]\rangle|. (25)

Setting A^=ayq^+byp^\hat{A}=a_{y}\hat{q}+b_{y}\hat{p} and B^=azq^+bzp^\hat{B}=a_{z}\hat{q}+b_{z}\hat{p}, we then find that the sum of the oscillator-operator variances is bounded by

μxVar(aμq^+bμp^)|aybzazby|.\sum_{\mu\neq x}\textrm{Var}(a_{\mu}\hat{q}+b_{\mu}\hat{p})\geq|a_{y}b_{z}-a_{z}b_{y}|. (26)

In analogy to a derivation in Ref. [23], the general bound for the spin operators can be obtained as follows:

μVar(J^μ)=μ(J^μ2J^μ2)\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})=\sum_{\mu}(\langle\hat{J}_{\mu}^{2}\rangle-\langle\hat{J}_{\mu}\rangle^{2}) (27)

With μJ^μ2=j(j+1)\sum_{\mu}\langle\hat{J}_{\mu}^{2}\rangle=j(j+1) and μJ^μ2j2\sum_{\mu}\langle\hat{J}_{\mu}\rangle^{2}\leq j^{2} we have

μVar(J^μ)j.\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\geq j. (28)

The question now arises as to the exact value of jj. For a fully symmetric state, we have

μVar(J^μ)N2.\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\geq\frac{N}{2}. (29)

Here jj takes the maximum possible value. Eq. 29 can also be derived from the fact that μ[Var(σ^μ)]2\sum_{\mu}[\textrm{Var}(\hat{\sigma}_{\mu})]\geq 2 (shown in Ref. [23]),

[μVar(J^μ)]min=N[μVar(S^μ)]min=N2\left[\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\right]_{\textrm{min}}=N\left[\sum_{\mu}\textrm{Var}(\hat{S}_{\mu})\right]_{\textrm{min}}=\frac{N}{2} (30)

Using [j]min,exp[j]_{\textrm{min,exp}}, the minimum value that jj will take at the time of measurement, we write the most general bound to be

Wb=[j]min,exp+|aybzazby|.W_{b}=[j]_{\textrm{min,exp}}+|a_{y}b_{z}-a_{z}b_{y}|. (31)

as in the main paper.

As mentioned, we consider the quantity

Wratio=[WbWenWb]max;W_{\rm{ratio}}=\left[\frac{W_{b}-W_{\rm{en}}}{W_{\rm{b}}}\right]_{\rm{max}}; (32)

when |WbWen||Wb||W_{b}-W_{\rm{en}}|\ll|W_{\rm{b}}|, finding |WbWen|max|W_{b}-W_{\rm{en}}|_{\rm{max}} suffices. Practically, however, finding |WbWen|max|W_{b}-W_{\rm{en}}|_{\rm{max}} is complicated due to the absolute value term given by |aybzazby||a_{y}b_{z}-a_{z}b_{y}|. Therefore, in this paper we minimize the value WenW_{\rm{en}}; that is, we solve for aμa_{\mu} and bμb_{\mu} such that aμ(Wen)=0\partial_{a_{\mu}}(W_{\rm{en}})=0 and bμ(Wen)=0\partial_{b_{\mu}}(W_{\rm{en}})=0. WenW_{\rm{en}}, being quadratic in aμa_{\mu} and bμb_{\mu}, is solvable. Note that this gives a higher violation than if were to maximize WbWenW_{b}-W_{\rm{en}} by expressing the absolute value as s(aybzazby)s(a_{y}b_{z}-a_{z}b_{y}), where ss sets the sign (+1, or -1), for reasons we cannot explain currently; the underlying reason must be that optimizing s(aybzazby)s(a_{y}b_{z}-a_{z}b_{y}) (and choosing the pairing of ss and the coefficients which makes this value positive) is not equivalent to optimizing (aybzazby)2\sqrt{(a_{y}b_{z}-a_{z}b_{y})^{2}}.

aμa_{\mu} and bμb_{\mu} contribute to obtaining Wen,minW_{\rm{en,min}} by reducing the value of the variance terms in Equation 21. In the most general case, an expansion of Eq. 21 gives

W=μ=x,y,zVar(J^μ)+μ=y,z(aμ2q^2+bμp^2+aμJ^μq^+q^J^μ+bμJ^μp^+p^J^μ+aμbμ{q^,p^}2aμq^+bμp^J^μaμq^+bμp^2)\ W=\sum_{\mu=x,y,z}\text{Var}(\hat{J}_{\mu})+\sum_{\mu=y,z}(a_{\mu}^{2}\langle\hat{q}^{2}\rangle+b_{\mu}\langle\hat{p}^{2}\rangle+a_{\mu}\langle\hat{J}_{\mu}\hat{q}+\hat{q}\hat{J}_{\mu}\rangle\\ ~{}~{}~{}~{}+b_{\mu}\langle\hat{J}_{\mu}\hat{p}+\hat{p}\hat{J}_{\mu}\rangle+a_{\mu}b_{\mu}\{\hat{q},\hat{p}\}-2\langle a_{\mu}\hat{q}+b_{\mu}\hat{p}\rangle\langle\hat{J}_{\mu}\rangle-\langle a_{\mu}\hat{q}+b_{\mu}\hat{p}\rangle^{2}) (33)

To obtain WenW_{\rm{en}}, the expectation value indicated by \langle\rangle is taken by evaluating the operators between the appropriate entangled state denoted by |ψen\ket{\psi_{\rm{en}}}. Observing the terms of WW, we can see that aμa_{\mu} and bμb_{\mu} characterize the contribution of covariances to the value of the witness; for instance, there are terms such as aμJ^μq^+q^J^μa_{\mu}\langle\hat{J}_{\mu}\hat{q}+\hat{q}\hat{J}_{\mu}\rangle and bμJ^μp^+p^J^μb_{\mu}\langle\hat{J}_{\mu}\hat{p}+\hat{p}\hat{J}_{\mu}\rangle. Additionally, as described in the upcoming sections, the spin and oscillator operators get correlated with each other, which can be seen when investigating their evolution in the Heisenberg picture. Therefore, in optimizing for the values of aμa_{\mu} and bμb_{\mu}, we are primarily controlling the contribution of these covariances and correlations, such that we obtain Wen,minW_{\rm{en,min}}.

I.1.2 Noiseless entanglement witness

The noiseless entangled state of our system is given by [18]

|ψen=D(λJ^z)eiωc^c^tD(λJ^z)|+++|0.\ket{\psi_{\rm{en}}}=D^{\dagger}(\lambda\hat{J}_{z})e^{-i\omega\hat{c}^{\dagger}\hat{c}t}D(\lambda\hat{J}_{z})\ket{+++~{}...}\ket{0}. (34)

Compared with Ref. [18], we have dropped the exp[i(g2t/ω)J^z2]\exp[-i(g^{2}t/\omega)\hat{J}_{z}^{2}] squeezing term, because it’s likely to be of O(1)O(1) given the size of the coupling gg.

As explained in the main paper, the Heisenberg operator c^(t)\hat{c}(t) is given by,

c^(t)=eiωtc^(0)i0t𝑑tgJ^zeiω(tt).\ \hat{c}(t)=e^{-i\omega t}\hat{c}(0)-i\int_{0}^{t}dt^{\prime}~{}g\hat{J}_{z}e^{-i\omega(t-t^{\prime})}. (35)

The spin operators J^x\hat{J}_{x} and J^y\hat{J}_{y} rotate about the z-axis by angle g0t𝑑t[c^(t)+c^(t)]g\int_{0}^{t}dt^{\prime}~{}[\hat{c}(t^{\prime})+\hat{c}(t^{\prime})^{\dagger}], due to the term gJ^z(c^+c^)g\hat{J}_{z}(\hat{c}+\hat{c}^{\dagger}) in the Hamiltonian. We find the operator evolution of J^x,J^y,q^\hat{J}_{x},\hat{J}_{y},\hat{q} and p^\hat{p} to be:

J^x(t)\displaystyle\hat{J}_{x}(t) J^xcos(θp^+θq^)J^ysin(θp^+θq^)\displaystyle\approx\hat{J}_{x}\cos(\theta_{\hat{p}}+\theta_{\hat{q}})-\hat{J}_{y}\sin(\theta_{\hat{p}}+\theta_{\hat{q}}) (36)
J^y(t)\displaystyle\hat{J}_{y}(t) J^ycos(θp^+θq^)+J^xsin(θp^+θq^)\displaystyle\approx\hat{J}_{y}\cos(\theta_{\hat{p}}+\theta_{\hat{q}})+\hat{J}_{x}\sin(\theta_{\hat{p}}+\theta_{\hat{q}}) (37)
q^(t)\displaystyle\hat{q}(t) =q^cos(ωt)+p^mωsin(ωt)2mωλJ^z[1cos(ωt)]\displaystyle=\hat{q}\cos(\omega t)+\frac{\hat{p}}{m\omega}\sin(\omega t)-\sqrt{\frac{2}{m\omega}}\lambda\hat{J}_{z}[1-\cos(\omega t)] (38)
p^(t)\displaystyle\hat{p}(t) =p^cos(ωt)mωq^sin(ωt)2mωλJ^zsin(ωt)\displaystyle=\hat{p}\cos(\omega t)-m\omega\hat{q}\sin(\omega t)-\sqrt{2m\omega}\lambda\hat{J}_{z}\sin(\omega t) (39)

where

θp^\displaystyle\theta_{\hat{p}} =2mωλp^[1cos(ωt)]\displaystyle=\sqrt{\frac{2}{m\omega}}\lambda\hat{p}[1-\cos(\omega t)] (40)
θq^\displaystyle\theta_{\hat{q}} =2mωλq^sin(ωt)\displaystyle=\sqrt{2m\omega}\lambda\hat{q}\sin(\omega t) (41)

Note that we have dropped the squeezing term, which goes as λ2J^z\lambda^{2}\hat{J}_{z} inside the cosine and sine functions of Equations 36 and 37. As observed in these equations, the operators become correlated with each other (for instance, q^(t)\hat{q}(t) and J^z\hat{J}_{z}). Optimizing the values of aμa_{\mu} and bμb_{\mu} translates to controlling the contributions of these correlations such that the variances of Eq. 21 are minimized for the entangled state. As described in the main paper, if we consider the operator combination J^y(t)+ayq^(t)+byp^(t)\hat{J}_{y}(t)+a_{y}\hat{q}(t)+b_{y}\hat{p}(t), aya_{y} and byb_{y} can be chosen such that the contribution to J^y(t)\hat{J}_{y}(t) from J^x\hat{J}_{x} can be canceled.

The non-simplified versions of these coefficients are

ay,0\displaystyle a_{\rm{y,0}} =2mωλNsin(ωt){2+3λ2N+λ2N[cos(2ωt)4cos(ωt)]}\displaystyle=-\frac{\sqrt{2m\omega}\lambda N\sin(\omega t)}{\{2+3\lambda^{2}N+\lambda^{2}N[\cos(2\omega t)-4\cos(\omega t)]\}} (42)
by,0\displaystyle b_{\rm{y,0}} =2mωλN[1cos(ωt)][2+λ2Nλ2Ncos(2ωt)]\displaystyle=\sqrt{\frac{2}{m\omega}}\frac{\lambda N[1-\cos(\omega t)]}{[2+\lambda^{2}N-\lambda^{2}N\cos(2\omega t)]} (43)
az,0\displaystyle a_{\rm{z,0}} =2mωλN[1cos(ωt)]{2+3λ2N+λ2N[cos(2ωt)4cos(ωt)]}\displaystyle=\frac{\sqrt{2m\omega}\lambda N[1-\cos(\omega t)]}{\{2+3\lambda^{2}N+\lambda^{2}N[\cos(2\omega t)-4\cos(\omega t)]\}} (44)
bz,0\displaystyle b_{\rm{z,0}} =2mωλNsin(ωt)[2+λ2Nλ2Ncos(2ωt)]\displaystyle=\sqrt{\frac{2}{m\omega}}\frac{\lambda N\sin(\omega t)}{[2+\lambda^{2}N-\lambda^{2}N\cos(2\omega t)]} (45)

which, when written to O(λ)O(\lambda), give Eqs. 5-8 in the main paper.

The lowest order of the expectation values J^x\langle\hat{J}_{x}\rangle, J^x2\langle\hat{J}_{x}^{2}\rangle, J^y\langle\hat{J}_{y}\rangle, J^y2\langle\hat{J}_{y}^{2}\rangle, q^2\langle\hat{q}^{2}\rangle, and p^2\langle\hat{p}^{2}\rangle is λ2\lambda^{2}. q^J^x+J^xq^=p^J^x+J^xp^=0\langle\hat{q}\hat{J}_{x}+\hat{J}_{x}\hat{q}\rangle=\langle\hat{p}\hat{J}_{x}+\hat{J}_{x}\hat{p}\rangle=0. Very interestingly, to lowest order in λ\lambda, q^J^y+J^yq^=ay,0,λ\langle\hat{q}\hat{J}_{y}+\hat{J}_{y}\hat{q}\rangle=-a_{\rm{y,0,\lambda}}, p^J^y+J^yp^=az,0,λ\langle\hat{p}\hat{J}_{y}+\hat{J}_{y}\hat{p}\rangle=-a_{\rm{z,0,\lambda}}, q^J^z+J^zq^=by,0,λ\langle\hat{q}\hat{J}_{z}+\hat{J}_{z}\hat{q}\rangle=-b_{\rm{y,0,\lambda}}, and p^J^z+J^zp^=bz,0,λ\langle\hat{p}\hat{J}_{z}+\hat{J}_{z}\hat{p}\rangle=-b_{\rm{z,0,\lambda}}, where ay,0,λa_{\rm{y,0,\lambda}} etc. are the expressions Eqs. 5-8 of the main paper. It must be noted that these coefficients reduced to being O(λ)O(\lambda) to lowest order in the end, despite the fact that the calculations were conducted to O(λ2)O(\lambda^{2}).

We can also understand the coefficients by investigating how the sum of the spin variances change as the system evolves. To O(λ2)O(\lambda^{2}), we find that

μVar(J^μ)=N2+λ2N22[1cos(ωt)].\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})=\frac{N}{2}+\frac{\lambda^{2}N^{2}}{2}[1-\cos(\omega t)]. (46)

for |ψen\ket{\psi_{\rm{en}}}. This shows that there is overall increase in [μVar(J^μ)]\left[\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})\right] as the system evolves. However, if we consider the contribution from the rest of the operators in WW (see Eq. 33), we find that the coefficients work with the q^\hat{q} and p^\hat{p} operators to bring the overall value of WenW_{\rm{en}} to be less than N/2N/2; this contribution is given by

Wen,0μVar(J^μ)=λ2N2[1cos(ωt)],\ W_{\rm{en,0}}-\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})=-\lambda^{2}N^{2}[1-\cos(\omega t)], (47)

such that the total value of WenW_{\rm{en}} is

Wen,0=N2λ2N22[1cos(ωt)].W_{\rm{en,0}}=\frac{N}{2}-\frac{\lambda^{2}N^{2}}{2}[1-\cos(\omega t)]. (48)

In essence, the coefficients work in various ways with the terms in Eq. 33 to minimize WenW_{\rm{en}}.

Note that Wen,0W_{\rm{en,0}} and Wb,0W_{\rm{b,0}} are obtained by minimizing the value of the EW for state |ψen\ket{\psi}_{\rm{en}}. While this means that Eq. 48 is the lowest value for the EW that can be obtained with |ψen\ket{\psi}_{\rm{en}}, it may not necessarily provide us with the greatest difference between the separable-state bound and the entangled-state value, which would be obtained by maximizing the quantity WbWenW_{\rm{b}}-W_{\rm{en}} with respect to aμa_{\mu} and bμb_{\mu}. The reason that we have not presented results from the optimization of WbWenW_{\rm{b}}-W_{\rm{en}} is due to certain mathematical complexities.

Note also that, though we present the coefficients to O(λ)O(\lambda) in the main paper, when calculating Wb,0W_{b,0} and Wen,0W_{\rm{en},0}, we used the non-simplified expressions given in this section.

If experimentally measuring the entanglement witness, measurements of all the operators of a single variance term must be made in a single experimental run; that is, in a single run we must measure all the operators in the set {J^y,J^y2,q^2,q^J^y+J^yq^,p^J^y+J^yp^}\{\hat{J}_{y},\hat{J}_{y}^{2},\hat{q}^{2},\hat{q}\hat{J}_{y}+\hat{J}_{y}\hat{q},\hat{p}\hat{J}_{y}+\hat{J}_{y}\hat{p}\}, with analogous sets for the μ=x\mu=x and μ=z\mu=z variance terms. After the completion of all runs, appropriate averaging over these runs is conducted to obtain J^x\langle\hat{J}_{x}\rangle, J^x2\langle\hat{J}_{x}^{2}\rangle, etc.. Due to the existence of noise, these averages are not purely the expectation values of operators taken over a quantum state. We will also be averaging over noise, so it is in fact more accurate to state that the final experimental values we obtain are those for J^x\langle\langle~{}\langle\hat{J}_{x}\rangle~{}\rangle\rangle, J^x2\langle\langle~{}\langle\hat{J}_{x}^{2}\rangle~{}\rangle\rangle etc., where double-angle brackets denote averaging over classical noise. We look at the cases of atomic dephasing and thermal noise in the upcoming sections.

I.1.3 Entanglement witness with atomic dephasing

Refer to caption
Figure 3: Here, ω=2π/20\omega=2\pi/20 rad s-1, σ2=t/600\sigma^{2}=t/600, N=106N=10^{6}, and we have set [j]min,exp,start=N/2[j]_{\rm{min,exp,start}}=N/2. Note that the coupling satisfies λ<7×104\lambda<7\times 10^{-4}. As expected, dephasing reduces the violation.

In reality, our experiment is subject to noise which can affect the entangled-state value of the EW. This can result in decreasing the value of WbWenW_{\rm{b}}-W_{\rm{en}}, potentially making it more difficult to observe violation of the entanglement witness.

Atomic dephasing can be introduced to the entangled state by introducing a spin-rotation aja_{j} about the z-axis for each atom jj:

|ψen,αj=D(λJz)eiωcctD(λJz)×exp[ijS^z,jαj]|+++|0\ket{\psi}_{\rm{en,\alpha_{j}}}=D^{\dagger}(\lambda J_{z})e^{-i\omega c^{\dagger}ct}D(\lambda J_{z})\\ \times\exp\left[i\sum_{j}\hat{S}_{z,j}\alpha_{j}\right]\ket{+++~{}...}\ket{0} (49)

We evaluate each of the expectation value terms in Eq. 33 for |ψen,αj\ket{\psi}_{\rm{en,\alpha_{j}}}; as previously, we evolve the operators in the Heisenberg picture first, with appropriate modifications made to Eqs. 36-39 as dictated by the spin-rotation αj\alpha_{j}, after which we evaluate with respect to |++|0\ket{++...}\ket{0}. Taking each αj\alpha_{j} to be independent of each other and having a Gaussian distribution of

p(αj)=12πσ2exp[αj22σ2],p(\alpha_{j})=\frac{1}{\sqrt{2\pi\sigma^{2}}}\exp\left[\frac{-\alpha_{j}^{2}}{2\sigma^{2}}\right], (50)

we obtain the classical mean of each of these terms (that is, expressions for J^x\langle\langle~{}\langle\hat{J}_{x}\rangle~{}\rangle\rangle, J^x2\langle\langle~{}\langle\hat{J}_{x}^{2}\rangle~{}\rangle\rangle etc.) with respect to the angles αj\alpha_{j}. The notation \langle\langle~{}\langle...\rangle~{}\rangle\rangle refers to the process of first evaluating the expectation value of the operators, \langle~{}\rangle, and afterwards the classical mean, \langle\langle~{}\rangle\rangle.

Compared to the noiseless case, we have the following change Δ\Delta to the variances of the spin operators for |ψen\ket{\psi_{\rm{en}}}, to O(σ2)O(\sigma^{2}):

ΔVar(J^x)\displaystyle\Delta\textrm{Var}(\hat{J}_{x}) ={N4λ2N2[1cos(ωt)]}σ2\displaystyle=\left\{\frac{N}{4}-\frac{\lambda^{2}N}{2}[1-\cos(\omega t)]\right\}\sigma^{2} (51)
ΔVar(J^y)\displaystyle\Delta\textrm{Var}(\hat{J}_{y}) ={λ2N2[1cos(ωt)]λ2N22[1cos(ωt)]}σ2\displaystyle=\left\{\frac{\lambda^{2}N}{2}[1-\cos(\omega t)]-\frac{\lambda^{2}N^{2}}{2}[1-\cos(\omega t)]\right\}\sigma^{2} (52)

Since J^z\hat{J}_{z} commutes with the dephasing operators S^z,j\hat{S}_{z,j}, its variance remains intact.

With these, the value of the EW with the inclusion of atomic dephasing is

Wen,σ,nonopt=N2(1+σ22)λ2N22[1cos(ωt)].\langle\langle W_{\rm{en,\sigma,non-opt}}\rangle\rangle=\frac{N}{2}\left(1+\frac{\sigma^{2}}{2}\right)-\frac{\lambda^{2}N^{2}}{2}[1-\cos(\omega t)]. (53)

Note that the expressions are to O(σ2)O(\sigma^{2}); σ=t/τc\sigma=\sqrt{t/\tau_{c}}, where τc\tau_{c} is the coherence time of interferometer which we require to be large for interferometry; therefore, we expect σ1\sigma\ll 1. Here, we have used the same values of aμa_{\mu} and bμb_{\mu} as for the noiseless case. The (N/4)σ2(N/4)\sigma^{2} difference between Equations 53 and 48 arises from dephasing-induced changes to the sum of the spin variances μVar(J^μ)\sum_{\mu}\textrm{Var}(\hat{J}_{\mu}). If we break down the contributions from the different operators, we have

μVar(J^μ)=N2(1+σ22)+λ2N22[1cos(ωt)](1σ2)\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})=\frac{N}{2}\left(1+\frac{\sigma^{2}}{2}\right)+\frac{\lambda^{2}N^{2}}{2}[1-\cos(\omega t)](1-\sigma^{2}) (54)

while the rest of the operators give

Wen,σ,nonoptμVar(J^μ)=λ2N2[1cos(ωt)](1σ22)\ \langle\langle W_{\rm{en,\sigma,non-opt}}\rangle\rangle-\sum_{\mu}\textrm{Var}(\hat{J}_{\mu})=-\lambda^{2}N^{2}[1-\cos(\omega t)]\left(1-\frac{\sigma^{2}}{2}\right) (55)

It can be seen that Wen,σ,nonopt>Wen,0\langle\langle W_{\rm{en,\sigma,non-opt}}\rangle\rangle>W_{\rm{en,0}} (given in Eq. 48), showing that atomic dephasing can make it harder to violate the separable-state bound. Since we used the same coefficients as for the noiseless case, the EW bound is partially given by Wb,0W_{b,0} of the noiseless case,

Wb,σ,nonopt=[j]min,exp,start(1σ22)+λ2N2|[1cos(ωt)]|\langle\langle W_{\rm{b,\sigma,non-opt}}\rangle\rangle=[j]_{\textrm{min,exp,start}}\left(1-\frac{\sigma^{2}}{2}\right)+\lambda^{2}N^{2}|[1-\cos(\omega t)]| (56)

[j]min,exp,start[j]_{\rm{min,exp,start}} is the minimum value of the total spin variances for a separable state as can be experimentally achieved at the start of the experiment; its occurrence in this equation, which reduces the violation by σ2/2\sigma^{2}/2, indicates the value we expect it to reduce to just before the measurement as atomic dephasing reduces the total jj quantum number.

We can further re-optimize the coefficients aμa_{\mu} and bμb_{\mu} for the case of dephasing by applying the constrain that ay,σ=(az,σbz,σ)/by,σa_{y,\sigma}=-(a_{z,\sigma}b_{z,\sigma})/b_{y,\sigma}. To O(σ2)O(\sigma^{2}) and O(λ)O(\lambda) we have

ay,σ=λNmω2sin(ωt){4σ2[1+cos(ωt)]}4\displaystyle a_{y,\sigma}=-\lambda N\sqrt{\frac{m\omega}{2}}\sin(\omega t)\frac{\{4-\sigma^{2}[1+\cos(\omega t)]\}}{4} (57)
az,σ=λNmω2[1cos(ωt)]{4σ2[1+cos(ωt)]}4\displaystyle a_{z,\sigma}=\lambda N\sqrt{\frac{{m\omega}}{2}}[1-\cos(\omega t)]\frac{\{4-\sigma^{2}[1+\cos(\omega t)]\}}{4} (58)
by,σ=λN12mω[1cos(ωt)]{4σ2[1cos(ωt)]}4\displaystyle b_{y,\sigma}=\lambda N\sqrt{\frac{1}{2m\omega}}[1-\cos(\omega t)]\frac{\{4-\sigma^{2}[1-\cos(\omega t)]\}}{4} (59)
bz,σ=λN12mωsin(ωt){4σ2[1cos(ωt)]}4\displaystyle b_{z,\sigma}=\lambda N\sqrt{\frac{1}{2m\omega}}\sin(\omega t)\frac{\{4-\sigma^{2}[1-\cos(\omega t)]\}}{4} (60)

Note that in the succeeding calculations, we used less simplified expressions; we do not present them here due to their complexity. As can be verified, these coefficients satisfy 𝐚.𝐛=0\mathbf{a}.\mathbf{b}=0. The bound is now

Wb,σ=[j]min,exp,start(1σ22)+λ2N2[1cos(ωt)](1σ22).\begin{split}\langle\langle W_{\rm{b,\sigma}}\rangle\rangle&=[j]_{\textrm{min,exp,start}}\left(1-\frac{\sigma^{2}}{2}\right)\\ &+\lambda^{2}N^{2}[1-\cos(\omega t)]\left(1-\frac{\sigma^{2}}{2}\right).\end{split} (61)

The entangled-state value for the optimized coefficients remains the same as that of Eq. 53 to O(λ2)O(\lambda^{2}) and O(σ2)O(\sigma^{2}); that is, the “optimized” coefficients give the same entangled state value as when using noiseless coefficients (given in Eq. 53) to O(σ2)O(\sigma^{2}). Thus, we may as well use the noiseless coefficients for the case of atomic dephasing, because the “optimized” coefficients only serve to decrease Wb,σ\langle\langle W_{\rm{b,\sigma}}\rangle\rangle while keeping Wen,σ,nonopt\langle\langle W_{\rm{en,\sigma,non-opt}}\rangle\rangle unchanged.

Due to our initial expansions to O(λ2)O(\lambda^{2}), there is a maximum value that λ\lambda can take such that Eq. 53 is always positive; this condition is given by

λ<(1+σ22)2N\lambda<\sqrt{\frac{\left(1+\frac{\sigma^{2}}{2}\right)}{2N}} (62)

For σ=t/600\sigma=\sqrt{t/600}, t = 20 s, and N=106N=10^{6}, it is required that λ<7×104\lambda<7\times 10^{-4}. We have plotted the violation in Fig. 3. As expected, dephasing reduces the violation.

I.1.4 Entanglement witness with a thermal state and white noise bath

Refer to caption
Figure 4: EW violation when the oscillator starts in a ground state and remains in contact with a thermal bath. λ=104.5\lambda=10^{-4.5}, N=106N=10^{6}, and ω=2π/20\omega=2\pi/20. We can see that re-optimized coefficients perform better for certain values of tt and n¯/Q\bar{n}/Q, while the noiseless coefficients perform better for others.

We now elaborate on the case of thermal noise. There are three scenarios that can be considered; the first when the oscillator starts in a thermal state, the second when the oscillator starts in a thermal state and remains in contact with a white noise bath, and the third when the oscillator starts in the ground state and remains in contact with a bath.

For a thermal state [24]

ρ^=n=0enβω1eβω|nn|,\ \hat{\rho}=\sum_{n=0}^{\infty}\frac{e^{-n\beta\omega}}{1-e^{-\beta\omega}}\ket{n}\bra{n}, (63)

introducing the initial-thermal-state-only effect into the previous noiseless calculation is rather straightforward. For average thermal occupancy n¯\bar{n}, we need only replace the expectation values of any any q^2\hat{q}^{2} and p^2\hat{p}^{2} terms that appear in the evaluation of the Heisenberg picture operators as follows

q2:12mω12mω(2n¯+1)\displaystyle\langle\langle q^{2}\rangle\rangle:\frac{1}{2m\omega}\rightarrow\frac{1}{2m\omega}(2\bar{n}+1) (64)
p2:mω2mω2(2n¯+1).\displaystyle\langle\langle p^{2}\rangle\rangle:\frac{m\omega}{2}\rightarrow\frac{m\omega}{2}(2\bar{n}+1). (65)

We can then find the coefficients as listed in the main paper, along with the bound Wb,n¯W_{\rm{b,\bar{n}}} and entangled-state value Wen,n¯W_{\rm{en,\bar{n}}}.

Next, we consider the scenario where the oscillator is in continuous contact with a white noise bath. As explained in the main paper, we can solve for c^(t)\hat{c}(t) to obtain

c^(t)=eiωtc^(0)i0t𝑑t(gJ^z+Fin(t))eiω(tt).\ \hat{c}(t)=e^{-i\omega t}\hat{c}(0)-i\int_{0}^{t}dt^{\prime}~{}(g\hat{J}_{z}+F_{in}(t^{\prime}))e^{-i\omega(t-t^{\prime})}. (66)

With q^(t)=qzpf[c^(t)+c^(t)]\hat{q}(t)=q_{\rm{zpf}}[\hat{c}(t)+\hat{c}^{\dagger}(t)] and p^(t)=ipzpf[c^(t)+c^(t)]\hat{p}(t)=ip_{\rm{zpf}}[-\hat{c}(t)+\hat{c}^{\dagger}(t)], the noise contributions to q^(t)\hat{q}(t) and p^(t)\hat{p}(t) can be expressed as

𝒬(t)=21/(2mω)0t𝑑tFin(t)sin[ω(tt)]\displaystyle\ \mathcal{Q}(t)=-2\sqrt{1/(2m\omega)}\int_{0}^{t}dt^{\prime}~{}F_{\rm{in}}(t^{\prime})\sin[\omega(t-t^{\prime})] (67)
𝒫(t)=2mω/20t𝑑tFin(t)cos[ω(tt)]\displaystyle\ \mathcal{P}(t)=-2\sqrt{m\omega/2}\int_{0}^{t}dt^{\prime}~{}F_{\rm{in}}(t^{\prime})\cos[\omega(t-t^{\prime})] (68)

Further, J^x\hat{J}_{x} and J^y\hat{J}_{y} will rotate about the z-axis by an angle ξ(t)=g0t𝑑t[c^(t)+c^(t)]\xi(t)=g\int_{0}^{t}dt^{\prime}~{}[\hat{c}(t^{\prime})+\hat{c}(t^{\prime})^{\dagger}] as follows:

J^x(t)=J^xcos[ξ(t)]J^ysin[ξ(t)]\displaystyle\hat{J}_{x}(t)=\hat{J}_{x}\cos[\xi(t)]-\hat{J}_{y}\sin[\xi(t)] (69)
J^y(t)=J^ycos[ξ(t)]+J^xsin[ξ(t)]\displaystyle\ \hat{J}_{y}(t)=\hat{J}_{y}\cos[\xi(t)]+\hat{J}_{x}\sin[\xi(t)] (70)

We can define the thermal noise contribution to this angle as

Ξ(t)=2mωg0t𝑑t𝒬(t)=2g0t0t𝑑t′′𝑑tFin(t′′)sin[ω(tt′′)]\ \Xi(t)=-\sqrt{2m\omega}~{}g\int_{0}^{t}dt^{\prime}~{}\mathcal{Q}(t^{\prime})\\ =2g\int_{0}^{t}\int_{0}^{t^{\prime}}dt^{\prime\prime}dt^{\prime}~{}F_{\rm{in}}(t^{\prime\prime})\sin[\omega(t^{\prime}-t^{\prime\prime})] (71)

The covariances that contribute to the bath noise are as follows:

Ξ(t)Ξ(t)=λ2n¯Q[6ωt8sin(ωt)+sin(2ωt)]Ξ(t)𝒬(t)=12mω8λn¯Qsin4(ωt2)Ξ(t)𝒫(t)=mω24λn¯Q[ωt2sin(ωt)+sin(2ωt)4]𝒬(t)𝒬(t)=12mωn¯Q[2ωtsin(2ωt)]𝒫(t)𝒫(t)=mω2n¯Q[2ωt+sin(2ωt)]𝒬(t)𝒫(t)=n¯Qsin2(ωt).\ \langle\langle\Xi(t)\Xi(t)\rangle\rangle=\frac{\lambda^{2}\bar{n}}{Q}[6\omega t-8\sin(\omega t)+\sin(2\omega t)]\\ \langle\langle\Xi(t)\mathcal{Q}(t)\rangle\rangle=-\sqrt{\frac{1}{2m\omega}}\frac{8\lambda\bar{n}}{Q}\sin^{4}\left(\frac{\omega t}{2}\right)\\ \langle\langle\Xi(t)\mathcal{P}(t)\rangle\rangle=\sqrt{\frac{m\omega}{2}}\frac{4\lambda\bar{n}}{Q}\left[\frac{\omega t}{2}-\sin(\omega t)+\frac{\sin(2\omega t)}{4}\right]\\ \langle\langle\mathcal{Q}(t)\mathcal{Q}(t)\rangle\rangle=\frac{1}{2m\omega}\frac{\bar{n}}{Q}[2\omega t-\sin(2\omega t)]\\ \langle\langle\mathcal{P}(t)\mathcal{P}(t)\rangle\rangle=\frac{m\omega}{2}\frac{\bar{n}}{Q}[2\omega t+\sin(2\omega t)]\\ \langle\langle\mathcal{Q}(t)\mathcal{P}(t)\rangle\rangle=\frac{\bar{n}}{Q}\sin^{2}(\omega t). (72)

As examples, Ξ(t)Ξ(t)\langle\langle\Xi(t)\Xi(t)\rangle\rangle contributes to the noise in the EW term Var(J^x)\textrm{Var}(\hat{J}_{x}) and 𝒬(t)𝒬(t)\langle\langle\mathcal{Q}(t)\mathcal{Q}(t)\rangle\rangle contributes to the noise in q^2\langle\langle\hat{q}^{2}\rangle\rangle. Therefore, the expectation values that compose the EW must be modified as shown in the main paper.

Next, we move to the scenario where the oscillator starts in a ground state and remains in contact with a white noise bath. Some additional plots to those in the main paper are shown in Fig. 4; in particular, plots for “re-optimized” coefficients. It can be seen that for certain values of n¯/Q\bar{n}/Q, the re-optimized coefficients show higher violation for certain times than the noiseless coefficients, while for other values of n¯/Q\bar{n}/Q, the noiseless coefficients are better.

Refer to caption
Figure 5: More advanced version of oscillator-atom setup. The parameter definitions are given in Table 1. An external magnetic field 𝐁ext\mathbf{B_{\rm{ext}}} induces a magnetic field in the cylinders which have magnetic susceptibility χm\chi_{m}. Note that, while only the field lines for one of the cylinders are shown for presentation purposes, both cylinders next to the atoms will be magnetized in reality. The direction of the induced magnetic field depends on the sign of χm\chi_{m}. The oscillator rotates in the x-y plane with frequency ω\omega. The cylinders are separated by angle 2θ02\theta_{0}. The reason for this configuration is to translate a force along the z-direction (as applied to the atoms) to a torque in the x-y plane. The two cylinders on the right are to balance the oscillator.
Refer to caption
(a)
Refer to caption
(b)
Figure 6: The physical parameters used are given in Table 1. In (a), the interferometer phase accumulation rate is plotted for different locations of the atoms in the y-z plane shown in Figure 5. In (b), the phase accumulation rate is plotted for different z locations of the atoms and rotation angles of the oscillator. The black line is the path the atom oscillator system follows to produce the interferometer phase plotted in Figure 7.

I.2 Magnetic interactions

We now explain in detail the interaction between an atom interferometer and a mechanical oscillator, and how to the obtain the magnetic coupling between them.

Atom interferometers measure the phase difference accumulated by the components of an atom’s wave function that travel along different trajectories between two points in spacetime. In general, the phase accumulated by each component is the integral of the Lagrangian along the classical trajectory it traverses. In an optical lattice atom interferometer, the trajectories include a hold period where the atom is in a superposition of being trapped at different sites in an optical lattice. When this hold period is much longer than the time for the trajectories to separate and recombine, the dominant contribution to the relative phase is the integral of the force, Fa(t)F_{a}(t), across the atoms at rar_{a} through the hold time, TT, multiplied by the atom separation Δra\Delta r_{a}. In units with =1\hbar=1, the interferometer phase has the following form [22]:

Δϕ=Δra0T𝑑tFa(t)\Delta\phi=\Delta r_{a}\int_{0}^{T}dtF_{a}(t) (73)

I.2.1 Interactions through the quadratic Zeeman effect

If the atoms are exposed to a spatially varying magnetic field, then a force across the atoms is generated due to the gradient in the Zeeman splitting of the atom’s energy levels. For Cesium-133 atoms in the mF=0m_{F}=0 ground state, the leading order Zeeman effect is quadratic in the magnetic field [25], yielding a force

FaB2(ra)ra.F_{a}\propto\frac{\partial B^{2}(r_{a})}{\partial r_{a}}. (74)

Thus, atom interferometers can act as magnetometers, measuring the gradient in the magnitude of the magnetic field. If the source of the magnetic field is an oscillator composed of magnetic material, then the force across the atoms will encode the displacement of the oscillator, ror_{o}.

Fa(ro)B2(ro,ra)raF_{a}(r_{o})\propto\frac{\partial B^{2}(r_{o},r_{a})}{\partial r_{a}} (75)

The atoms will feel a force that is modulated by the oscillator’s motion. This results in an interferometer phase that is sensitive to the oscillators position. There will also be a back action force on the oscillator, FoF_{o}, from the dependence of the magnetic field on the oscillator’s position. This force will be sensitive to the atom’s position.

Fo(ra)B2(ro,ra)roF_{o}(r_{a})\propto\frac{\partial B^{2}(r_{o},r_{a})}{\partial r_{o}} (76)

This physics is captured by the interaction potential for small displacements in the atom and oscillator coordinates.

U(ro,ra)=ϕ02B2(0,0)rorararoU(r_{o},r_{a})=\phi_{0}\frac{\partial^{2}B^{2}(0,0)}{\partial r_{o}\partial r_{a}}r_{a}r_{o} (77)

The oscillator motion is now subject to a linear potential which modifies its motion and the potential interacts with the atoms, spatially separated by Δra\Delta r_{a}, to accumulate interferometer phase at a rate ϕ˙\dot{\phi},

ϕ˙=ϕ02B2(0,0)roraroΔra\dot{\phi}=\phi_{0}\dfrac{\partial^{2}B^{2}(0,0)}{\partial r_{o}\partial r_{a}}r_{o}\Delta r_{a} (78)

Here, ϕ0\phi_{0} is an atom’s energy difference between the mF=0m_{F}=0 states of the ground state. To understand the magnitude of this interaction achievable with current technologies and how it can be increased, we model a particular experimental setup in the next section.

I.2.2 Proposed setup

Refer to caption
Figure 7: The physical parameters used are given in Table 1. The interferometer phase from magnetic interaction with the oscillator in classical motion is plotted with a solid line. The rotation angle of the oscillator is plotted in a dashed line. The oscillator motion is clearly encoded in the interferometer phase.
Table 1: The model of the atom-oscillator system has the following parameters, unless otherwise stated.
Parameter Symbol Value
mF=0m_{F}=0 Cs ground state shift [25] ϕ0\phi_{0} 268.575 (radns T2)(\frac{\text{rad}}{\text{ns}\text{ T}^{2}})
External magnetic field strength BextB_{\rm{ext}} 55 mT
magnetic susceptibility [29] χm\chi_{m} 6.8×1056.8\times 10^{-5}
pendulum radius R0R_{0} 10 cm
pendulum frequency ω\omega 2π/202\pi/20 rad/s
pendulum density [28] ρcyl\rho_{\rm{cyl}} 19.3 g/cm3
cylinder height ll 10 mm
cylinder radius RR 55 mm
half of cylinder separation angle θ0\theta_{0} 22^{\circ}
atom to pendulum distance ss 8 mm
atom wave packet separation Δz\Delta z 5 μ\mum

The main paper proposed a simplified version of the torsional pendulum. Since we plan to gradually proceed to a gravity experiment, we investigated a more advanced version of a pendulum as depicted in Figure 5. The pendulum that will oscillate at frequency ω\omega about the vertical axis with two diamagnetic cylinders with magnetic susceptibility χm\chi_{m} on its base. The atom interferometer sequence will trap atoms in a superposition of two lattice sites that are horizontally separated from the pendulum base by a distance, ss, and vertically separated above and below the base by Δz/2\Delta z/2; that is, Δra=Δz\Delta r_{a}=\Delta z, since our atoms only have a vertical separation. In a uniform external magnetic field, 𝐁ext\mathbf{B_{\rm{ext}}}, these cylinders will produce an induced magnetic field. The gradients in the induced field will couple to the atom interferometer through the quadratic Zeeman effect to produce an interaction potential that is sensitive to the pendulum’s rotation angle and the atom’s location.

The magnetic field from a finite length cylinder with uniform magnetization has been calculated in Ref. [27]. The total magnetic field is a superposition of the induced field from each cylinder and the external magnetic field. The resulting phase accumulation rate for a range of atom locations and oscillator rotation angles is displayed in Figures 6a and 6b. With the atoms centered at y=z=0y=z=0, the interferometer phase is calculated for the oscillator in classical motion: θ(t)=θmaxsin(ωt)\theta(t)=\theta_{\text{max}}\sin{(\omega t)}. The result is plotted in Fig. 7 along with the rotation angle of the oscillator. The interferometer phase, and therefore the probability to find the atom in each lattice site, is clearly correlated with the oscillators position. If the oscillator is quantum mechanical and its position and momentum become sufficiently correlated with the atoms, then there is the possibility of observing the system in a non-classical state.

I.2.3 Interaction with a quantum harmonic oscillator

The combined oscillator-atom Hamiltonian has the following form [18]:

H=ωc^c^+g(c^+c^)S^zH=\omega\hat{c}^{\dagger}\hat{c}+g(\hat{c}+\hat{c}^{\dagger})\hat{S}_{z} (79)

Here, c^\hat{c}^{\dagger} and c^\hat{c} are the oscillator creation and annihilation operators, while S^z\hat{S}_{z} is a pseudo-spin operator describing the atom’s location. The second term is the interaction potential in Eq. 77 with quantized oscillator and atom coordinates. gg is defined as follows.

g=12ncylπR2LρcylωΔzϕ01R0Rd2B2(0,0)dzdθg=\sqrt{\frac{1}{2~{}n_{\rm{cyl}}~{}\pi R^{2}L\rho_{\rm{cyl}}~{}\omega}}\Delta z\phi_{0}\frac{1}{R_{0}-R}\dfrac{d^{2}B^{2}(0,0)}{dz~{}d\theta} (80)

Here, ncyln_{\rm{cyl}} is the number of cylinders. The factor of 1/(R0R)1/(R_{0}-R) simply arises from taking the derivative in the direction of θ\theta. For oscillator mass and frequency mm and ω\omega, the harmonic oscillator position operator is r^o=(R0R)θ^=12mω(c^+c^)\hat{r}_{o}=(R_{0}-R)\hat{\theta}=\sqrt{\frac{1}{2m\omega}}(\hat{c}+\hat{c}^{\dagger}). Since the atom is confined to two sites in an optical lattice separated by Δz\Delta z, the atom’s position operator can be expressed as a spin operator in a pseudo-spin-1/2 Hilbert space.

r^a=Δz/2|00|Δz/2|11|=ΔzS^z\hat{r}_{a}=\Delta z/2\ket{0}\bra{0}-\Delta z/2\ket{1}\bra{1}=\Delta z\hat{S}_{z} (81)

For the more realistic case of an atom interferometer with NN atoms, the interaction potential can be linearized in each of their coordinates to produce an interaction linear in the collective N/2N/2 pseudo-spin operator J^z\hat{J}_{z} [18].

Umulti-atom=g(c^+c^)J^zU_{\text{multi-atom}}=g(\hat{c}+\hat{c}^{\dagger})\hat{J}_{z} (82)

The system Hamiltonian, Eq. 79, is capable of generating entanglement between the atoms and oscillator. For the oscillator initialized in its ground state and the atom in a symmetric spatial superposition, the system evolves to an entangled state where the displacement of the oscillator is correlated with the atom’s location [18],

|0a|δo+|1a|δo2\dfrac{\ket{0}_{a}\ket{\delta}_{o}+\ket{1}_{a}\ket{-\delta}_{o}}{\sqrt{2}} (83)

|δ||\delta| is the coherent state amplitude proportional to λ=g/ω\lambda=g/\omega. For an experiment to resolve the correlations between the oscillator and the atom, λ\lambda must be sufficiently large.

We can readily calculate λ\lambda with Eq. 80 for our proposed setup. With the parameter values in Table 1, we find the following value for λ\lambda (for ncyln_{\rm{cyl}} = 4) to first order in χm\chi_{m}:

λ=4.0×1016×(Bext5mT)2(|χm|6.8×105)×(19.3g/cm3ρcyl)12(1α)72\begin{split}\ \lambda=-4.0\times 10^{-16}\times\left(\frac{B_{\text{ext}}}{5~{}\text{mT}}\right)^{2}\left(\frac{|{\chi_{m}}|}{6.8\times 10^{-5}}\right)\\ \times\left(\frac{19.3~{}\rm{g/cm^{3}}}{\rho_{\rm{cyl}}}\right)^{\frac{1}{2}}\left(\frac{1}{\alpha}\right)^{\frac{7}{2}}\end{split} (84)

The susceptibility of 6.8×1056.8\times 10^{-5} and density of 19.3g/cm319.3~{}\rm{g/cm^{3}} correspond to those of tungsten [28, 29]. α\alpha parametrizes the length scale of the system as LαLL\rightarrow\alpha L; that is, α\alpha is the scaling factor for all the length parameters in Table 1, with the exception of Δz\Delta z (i.e the parameters R0,l,R,R_{0},l,R, and ss). This scaling implies that gg is increased by decreasing the system size. In the parameter space we are at, recalling that 𝐁=𝐁ext+𝐁cyl\mathbf{B}=\mathbf{B_{\rm{ext}}}+\mathbf{B_{\rm{cyl}}} (with 𝐁cyl\mathbf{B_{\rm{cyl}}} being the induced magnetic field of the cylinders), the term dB2/dzdB^{2}/dz of Eq. 80 can be approximated to be 2𝐁ext.(𝐁cyl/z)2~{}\mathbf{B}_{\rm{ext}}.(\partial\mathbf{B}_{\rm{cyl}}/\partial z). This is because |𝐁ext|2|\mathbf{B}_{\rm{ext}}|^{2} has no gradient and |𝐁cyl|2/z\partial|\mathbf{B}_{\rm{cyl}}|^{2}/\partial z is negligible compared to the cross-term. This allows the scalings of |χm||\chi_{m}| and α\alpha to be expressed as “single” factors. As a side note, the value of 4.0×1016-4.0\times 10^{-16} was obtained using the expressions in Ref. [27].

The value of the coupling in Eq. 80 is extremely small. As will be seen in the succeeding sections, entanglement witness violation requires couplings of around λ104.5\lambda\sim 10^{-4.5}, which is orders of magnitude larger than that which can be obtained from the parameters in Table 1. There are several ways through which we can increase λ\lambda. One of the primary changes is to switch to a superconducting mass. Though one might think that this will re-introduce the contribution from |𝐁cyl|2/z\partial|\mathbf{B}_{\rm{cyl}}|^{2}/\partial z, it is still ×102\times 10^{2} smaller than the cross-term (at least for the physical parameters we use). Therefore, we can still use Eq. 80 to inform us of how the values change with rescaling the parameters; having said that, the upcoming calculation was done exactly using the expressions in Ref. [27]. We now have χ=1\chi=-1, which will increase the coupling by a factor of 10510^{5}; increasing the field to 50 mT will contribute a factor of 10210^{2} (note that at this field, we are still well before the Paschen-Back regime for cesium, as seen in Ref. [25]); the system size can be reduced by a factor of 2 (taking α=0.5\alpha=0.5); a cloud of NN atoms leads to a N\sqrt{N} increase - we set N=106N=10^{6}. If we take the material to be lead, then the density will be ρcyl=11.34\rho_{\rm{cyl}}=11.34 g/cm3 [26]. Together, these factors increase the coupling to λN=8.8×106\lambda_{N}=8.8\times 10^{-6}. The main concern would be the experimental challenges for some of these changes; in particular, scaling the atom to pendulum distance from 8 mm to 4 mm would be pushing the limits of existing systems, since there is a requirement that the atom trap laser not interact with the pendulum.

We can also gain improvements in coupling by having the cesium atoms be magnetically sensitive states; for instance, we can place one atom in the mF=1m_{F}=1 state and the other in the mF=1m_{F}=-1. In such a scenario, the coupling would primarily be due to the first order Zeeman shift, which is linear in BB [25]. The energy difference in the atoms now arises due to the difference in their internal states, in addition to the magnetic field differences between their two locations (that is, a coupling will exist even if Δz=0\Delta z=0). In particular, the term of the Zeeman energy shift which contributes to the coupling is [25]

ω1st,zeeman=(gJgI)μB(2I+1)mFB\ \omega_{\rm{1st,~{}zeeman}}=\frac{(g_{J}-g_{I})~{}\mu_{B}}{(2I+1)\hbar}m_{F}B (85)

where II is the nuclear spin, which is 7/2 for Cs; we take the difference of this quantity between the two atoms, and then the gradient in the direction of oscillator motion to obtain the coupling. However, having atoms be located symmetrically in the top and bottom halves of the cylinder is detrimental to the coupling, because now it arises solely from dB/dθdB/d\theta. Thus, we shift the positions of both atoms such that they are both in z>0z>0 plane. If we place the top atom to be at around L/2L/2, we obtain the coupling to be

λ=4.4×1012×(Bext5mT)(|χm|6.8×105)(19.3g/cm3ρcyl)12(1α)52;\begin{split}\lambda=-4.4\times 10^{-12}\times\left(\frac{B_{\text{ext}}}{5~{}\text{mT}}\right)\left(\frac{|{\chi_{m}}|}{6.8\times 10^{-5}}\right)\\ \left(\frac{19.3~{}\rm{g/cm^{3}}}{\rho_{\rm{cyl}}}\right)^{\frac{1}{2}}\left(\frac{1}{\alpha}\right)^{\frac{5}{2}};\end{split} (86)

we can see that it is now four orders of magnitude higher. Note that the α\alpha scaling here also incorporates changing the position of the top atom location by a factor of α\alpha; the separation between the two atom locations is still kept constant, so the position of the second location changes too. For 50 mT, χ=1\chi=-1, ρcyl=11.34\rho_{\rm{cyl}}=11.34 g/cm3 [26], N=106N=10^{6}, and α=0.5\alpha=0.5, we will get λN=4.8×103\lambda_{N}=4.8\times 10^{-3}, which is a significant improvement from having purely mF=0m_{F}=0 states. Note that scaling α\alpha also decreases the atom-oscillator separation from 8 mm to 4 mm.

If we re-calculate the superconducting case for the simplified setup in the main paper, with changes such that ncyl=2n_{\rm{cyl}}=2, the atom-oscillator separation is 8 mm (which is the more feasible situation), and the atoms are symmetrically located at ±Δz/2\pm\Delta z/2, we get λN=6.3×104\lambda_{N}=6.3\times 10^{-4} (as quoted in the main paper). Potential issues of having the atoms be in magnetically sensitive states is that it can introduce sensitivities to stray magnetic fields.

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