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Dissipativity and positive off-diagonal property of operators on ordered Banach spaces

Feng Zhang College of Mathematics, Taiyuan University of Technology, Taiyuan 030024, Shanxi, China [email protected]  and  Onno van Gaans Mathematical Institute, Leiden University, 2333 CA Leiden, The Netherlands [email protected]
(Date: June 10, 2020)
Abstract.

In this paper, we provide a sublinear function pp on ordered Banach spaces, which depends on the order structure of the space. With respect to this pp, we study the relation between pp-contractivity of positive semigroups and the pp-dissipativity of its generators. The positive off-diagonal property of generators is also studied in ordered vector spaces.

Key words and phrases:
ordered Banach space, positive contractive semigroup, pp-dissipativity, positive off-diagonal property
2020 Mathematics Subject Classification:
Primary 46B40, 47B60, 47D03

1. Introduction

It is known that on a Banach space XX, the positivity and the contractivity of a semigroup (T(t))t0(T(t))_{t\geq 0} can be characterized by means of dissipativity of its generator AA with respect to some appropriate sublinear functions, see [2, Theorem 2.6]. This property is also proved in the case of XX being an ordered Banach space with normal positive cone and with respect to a canonical half-norm on XX, see [5, Proposition 7.13]. In Banach lattices, moreover, the positivity of (T(t))t0(T(t))_{t\geq 0} can be characterized by its generator AA which satisfies the “positive off-diagonal” property (it is called “positive minimum principle” in [3, Theorem 1.11]). This is also studied in an ordered Banach space with a positive cone with nonempty interior, [5, Theorem 7.27]. For more positive off-diagonal properties of operators on ordered normed spaces, we refer the reader to [4, 6, 7, 10].

The goal of this paper is to investigate the positivity and contractivity of semigroups through the dissipativity of generators with respect to corresponding sublinear functions on ordered vector spaces. So the choice of sublinear functions on ordered vector spaces is crucial. In Section 3, we give two different ways of defining the sublinear functions on ordered vector spaces. One is given by a regular norm and the other one is obtained through a dual function. The latter one turns out to be more effective in studying the positivity and contractivity of semigroups on ordered Banach spaces in Section 4, these are also our main results. Moreover, in Section 5 we will show a representation for positive functions on Archimedean pre-Riesz spaces, which will be used to study the positive off-diagonal property of operators on the pre-Riesz space C1[0,1]C^{1}[0,1].

2. Preliminaries

In this section, we will collect some basic terminology, which we mainly refer to [1, 2, 9]. Let XX be a real vector space, and KXK\subseteq X. KK is said to be a cone in XX if x,yKx,y\in K, λ,μ+\lambda,\mu\in\mathbb{R}^{+} implies λx+μyK\lambda x+\mu y\in K and K(K)={0}K\cap(-K)=\{0\}. A partial order in XX is induced by xyx\leq y whenever yxKy-x\in K, we then say (X,K)(X,K) is a (partially) ordered vector space. (X,K,)(X,K,\|\cdot\|) is called an ordered Banach space whenever it is norm complete. The space of all bounded linear operators on XX is denoted by L(X)L(X), the positive operators in L(X)L(X) are L(X)+:={TL(X):Tx0,0xX}L(X)^{+}:=\{T\in L(X):Tx\geq 0,\ \forall 0\leq x\in X\}. Then (L(X),L(X)+)(L(X),L(X)^{+}) is an ordered vector space. The domain of an operator TT on XX is denoted by 𝒟(T)\mathcal{D}(T). A one-parameter semigroup of operators is written usually as (T(t))t0(T(t))_{t\geq 0}, and it is called strongly continuous if the map tT(t)t\mapsto T(t) is continuous for the strong topology on L(X)L(X).

Let (X,K,)(X,K,\|\cdot\|) be an ordered normed vector space. A function pp on XX is called sublinear if p(x+y)p(x)+p(y)p(x+y)\leq p(x)+p(y) for all x,yXx,y\in X and p(λx)=λp(x)p(\lambda x)=\lambda p(x) for all xXx\in X, λ0\lambda\geq 0. It is clear that p(0)=0p(0)=0. If a sublinear function pp on XX satisfies p(x)+p(x)>0p(x)+p(-x)>0 whenever x0x\neq 0 in XX, then pp is called a half-norm. If there exists a constant M>0M>0 such that p(x)+p(x)Mxp(x)+p(-x)\geq M\|x\| for all xXx\in X, then pp is called a strict half-norm. Let xXx\in X, define

ψ(x)=dist(x,K)\displaystyle\psi(x)=\mbox{dist}(-x,K) =inf{x+y:yK}\displaystyle=\inf\{\|x+y\|\colon y\in K\}
(2.1) =inf{y:xy,yX},\displaystyle=\inf\{\|y\|\colon x\leq y,y\in X\},

then ψ\psi is a half-norm in XX. This half-norm ψ\psi is called the canonical half-norm. A seminorm pp on XX is called regular if for all xXx\in X one has

p(x):=inf{p(y):yX such that yxy}.p(x):=\inf\{p(y)\colon y\in X\mbox{ such that }-y\leq x\leq y\}.

A regular seminorm on an ordered vector space will be denoted by r\|\cdot\|_{r}. If (X,K)(X,K) is an ordered vector space equipped with a seminorm pp, then for xXx\in X, xr:=inf{p(y):yX,yxy}\|x\|_{r}:=\inf\{p(y)\colon y\in X,-y\leq x\leq y\} is called the regularization of the original seminorm pp. Moreover, r\|\cdot\|_{r} is a seminorm, and rp()\|\cdot\|_{r}\leq p(\cdot) on KK. A seminorm pp on XX is called monotone if for every x,yXx,y\in X such that 0xy0\leq x\leq y one has that p(x)p(y)p(x)\leq p(y).

If (M,)(M,\|\cdot\|) is any normed vector space, we denote by MM^{\prime} the continuous linear functionals on MM.

Let (X,K,)(X,K,\|\cdot\|) be an ordered normed vector space, pp be a sublinear function on XX. A bounded operator TT on XX is called pp-contractive if p(Tx)p(x)p(Tx)\leq p(x) for all xXx\in X. Similarly, a semigroup (T(t))t0(T(t))_{t\geq 0} is called pp-contractive if T(t)T(t) is pp-contractive for all t0t\geq 0. The subdifferential of pp at point xXx\in X, denoted by dp(x)dp(x), is defined as

(2.2) dp(x)={xK:y,xp(y) for all yX,x,x=p(x)}.dp(x)=\{x^{\prime}\in K^{\prime}\colon\langle y,x^{\prime}\rangle\leq p(y)\mbox{ for all }y\in X,\langle x,x^{\prime}\rangle=p(x)\}.
Definition 2.1.

An operator A:𝒟(A)XXA\colon\mathcal{D}(A)\subseteq X\to X is called pp-dissipative if for all x𝒟(A)x\in\mathcal{D}(A) there exists ydp(x)y^{\prime}\in dp(x) such that Ax,y0\langle Ax,y^{\prime}\rangle\leq 0; AA is called strictlystrictly pp-dissipative if for all x𝒟(A)x\in\mathcal{D}(A) the inequality Ax,y0\langle Ax,y^{\prime}\rangle\leq 0 holds for all ydp(x)y^{\prime}\in dp(x).

Let (X,)(X,\|\cdot\|) be a Banach lattice, pp be a canonical half-norm on XX. We have that p(x)=x+p(x)=\|x^{+}\| for all xXx\in X. In fact, let xXx\in X, p(x)x+p(x)\leq\|x^{+}\| is obvious. Since |x+y|(x+y)+x+|x+y|\geq(x+y)^{+}\geq x^{+} for any 0yX0\leq y\in X, we have that x+yx+\|x+y\|\geq\|x^{+}\|. So p(x)x+p(x)\geq\|x^{+}\|. To make a difference from the above, we will use distinctive notations. Let N+:XN^{+}\colon X\rightarrow\mathbb{R} be the function given by N+(x)=x+N^{+}(x)=\|x^{+}\|. Then the subdifferential of N+N^{+} at point xXx\in X is

dN+(x)={xK:x1,x,x=x+}.dN^{+}(x)=\{x^{\prime}\in K^{\prime}\colon\|x^{\prime}\|\leq 1,\langle x,x^{\prime}\rangle=\|x^{+}\|\}.

An operator TT on XX is called (strictly) dispersive if TT is (strictly) N+N^{+}-dissipative.

We continue by some notations of pre-Riesz theory. An ordered vector space (X,K)(X,K) is called directed if for every x,yXx,y\in X there exists zXz\in X such that zx,zyz\geq x,z\geq y, and is called Archimedean if for every x,yXx,y\in X with nxynx\leq y for all nn\in\mathbb{N} one has x0x\leq 0. We say that XX is a pre-Riesz space if for every x,y,zXx,y,z\in X the inclusion {x+y,x+z}u{y,z}u\{x+y,x+z\}^{\text{u}}\subseteq\{y,z\}^{\text{u}} implies xKx\in K, where {x,y}u={zX:zx,zy}\{x,y\}^{\text{u}}=\{z\in X\colon z\geq x,z\geq y\}. Every directed Archimedean ordered vector space is pre-Riesz [9]. A linear subspace DD of XX is called order dense in XX if

x=inf{dD:dx},xX.x=\inf\{d\in D\colon d\geq x\},\forall x\in X.

Every pre-Riesz space admits a Riesz completion, and it is an order dense subspace of the Riesz completion [9]. A linear map i:XYi\colon X\rightarrow Y between two ordered vector spaces is called bipositive if for every xXx\in X one has x0x\geq 0 if and only if i(x)0i(x)\geq 0.

3. Half-norms

In this section, we will introduce two different seminorms on ordered vector spaces. One is induced by the regular norms, and the other one involves the order structure which will be used in the following section.

Proposition 3.1.

Let (X,K,)(X,K,\|\cdot\|) be an ordered normed vector space, and r\|\cdot\|_{r} the regularization of \|\cdot\|, and let pp be defined as

(3.1) p(x)=inf{yr:yX,y0,yx},xX.\displaystyle p(x)=\inf\{\|y\|_{r}\colon\,y\in X,y\geq 0,y\geq x\},\forall x\in X.

Then pp is a strict half-norm on XX. Moreover, if ψ\psi on XX be defined by (2), then p(x)=ψ(x)p(x)=\psi(x) for all xK(K)x\in K\cup(-K), in particular, p(x)=ψ(x)=0p(x)=\psi(x)=0 for x(K)x\in(-K).

Proof.

Let x0x\neq 0 be in XX. Since r\|\cdot\|_{r} is the regularization of \|\cdot\|, we have that xr:=inf{y:yX,yxy}\|x\|_{r}:=\inf\{\|y\|\colon y\in X,-y\leq x\leq y\} with y0y\neq 0. As \|\cdot\| is a norm, y0\|y\|\neq 0. So we have that xr>0\|x\|_{r}>0. If y0y\geq 0, yxy\geq x and z0z\geq 0, zxz\geq-x, then (y+z)x(y+z)-(y+z)\leq x\leq(y+z). Since r\|\cdot\|_{r} is regular, we have xry+zr\|x\|_{r}\leq\|y+z\|_{r}. So yr+zry+zrxr>0\|y\|_{r}+\|z\|_{r}\geq\|y+z\|_{r}\geq\|x\|_{r}>0. Hence, by passing to the infimum in each term we get p(x)+p(x)xr>0p(x)+p(-x)\geq\|x\|_{r}>0. Thus pp is a strict half-norm.

Moreover, if 0xX0\leq x\in X, we can take y=x0y=x\geq 0 in (3.1), then p(x)=xr=ψ(x)p(x)=\|x\|_{r}=\psi(x). It is clear that p(x)=ψ(x)=0p(x)=\psi(x)=0 for x0x\leq 0 in XX. ∎

Proposition 3.2.

Let (X,K,)(X,K,\|\cdot\|) be an ordered normed vector space, and r\|\cdot\|_{r} the regularization of \|\cdot\|, and let pp be defined by (3.1). If TL(X)+T\in L(X)^{+} is a contractive operator with respect to the regular norm r\|\cdot\|_{r}, then TT is pp-contractive.

Proof.

Let TL(X)+T\in L(X)^{+}. By the assumption, we have that Tyryr\|Ty\|_{r}\leq\|y\|_{r} for all 0yX0\leq y\in X. Then for xXx\in X, p(x)=inf{yr:y0,yx}inf{Tyr:y0,yx}p(x)=\inf\{\|y\|_{r}\colon\,y\geq 0,y\geq x\}\geq\inf\{\|Ty\|_{r}\colon\,y\geq 0,y\geq x\}. Since TT is a positive operator, we have that y0,yxy\geq 0,y\geq x implies Ty0,TyTxTy\geq 0,Ty\geq Tx. Hence, inf{Tyr:y0,yx}inf{Tyr:Ty0,TyTx}=p(Tx)\inf\{\|Ty\|_{r}\colon\,y\geq 0,y\geq x\}\geq\inf\{\|Ty\|_{r}\colon\,Ty\geq 0,Ty\geq Tx\}=p(Tx). So TT is pp-contractive. ∎

We continue with a different approach of sublinear functions on ordered vector spaces, which turns out to be more useful in dealing with the contractivity and positivity of semigroups.

Let ϕX\phi\in X^{\prime}, define pϕp_{\phi} on XX by

(3.2) pϕ(x)=inf{y,ϕ:yX,y0,yx},xX.\displaystyle p_{\phi}(x)=\inf\{\langle y,\phi\rangle\colon\,y\in X,y\geq 0,y\geq x\},\,\forall\,x\in X.
Proposition 3.3.

Let XX be an ordered vector space, and let ϕX\phi\in X^{\prime}. If pϕp_{\phi} is defined by (3.2), then pϕp_{\phi} is sublinear. Moreover, pϕ(x)=x,ϕp_{\phi}(x)=\langle x,\phi\rangle if x0x\geq 0, and pϕ(x)=0p_{\phi}(x)=0 if x0x\leq 0.

Proof.

Let ϕX\phi\in X^{\prime}, and x,yXx,y\in X. By the definition, we have that pϕ(x+y)=inf{z,ϕ:zX,z0,zx+y}p_{\phi}(x+y)=\inf\{\langle z,\phi\rangle\colon\,z\in X,z\geq 0,z\geq x+y\}. Let z1+z2=zz_{1}+z_{2}=z, we have that inf{z,ϕ:zX,z0,zx+y}=inf{z1+z2,ϕ:z1+z2X,z1+z20,z1+z2x+y}\inf\{\langle z,\phi\rangle\colon\,z\in X,z\geq 0,z\geq x+y\}=\inf\{\langle z_{1}+z_{2},\phi\rangle\colon\,z_{1}+z_{2}\in X,z_{1}+z_{2}\geq 0,z_{1}+z_{2}\geq x+y\}. Since z1X,z2X,z10,z20,z1x,z2yz_{1}\in X,z_{2}\in X,z_{1}\geq 0,z_{2}\geq 0,z_{1}\geq x,z_{2}\geq y implies z1+z2X,z1+z20,z1+z2x+yz_{1}+z_{2}\in X,z_{1}+z_{2}\geq 0,z_{1}+z_{2}\geq x+y, we have that inf{z1+z2,ϕ:z1+z2X,z1+z20,z1+z2x+y}inf{z1+z2,ϕ:z1X,z2X,z10,z20,z1x,z2y}\inf\{\langle z_{1}+z_{2},\phi\rangle\colon\,z_{1}+z_{2}\in X,z_{1}+z_{2}\geq 0,z_{1}+z_{2}\geq x+y\}\leq\inf\{\langle z_{1}+z_{2},\phi\rangle\colon\,z_{1}\in X,z_{2}\in X,z_{1}\geq 0,z_{2}\geq 0,z_{1}\geq x,z_{2}\geq y\}. It is clear that inf{z1+z2,ϕ:z1X,z2X,z10,z20,z1x,z2y}=inf{z1,ϕ:z1X,z10,z1x}+inf{z2,ϕ:z2X,z20,z2y}=pϕ(x)+pϕ(y)\inf\{\langle z_{1}+z_{2},\phi\rangle\colon\,z_{1}\in X,z_{2}\in X,z_{1}\geq 0,z_{2}\geq 0,z_{1}\geq x,z_{2}\geq y\}=\inf\{\langle z_{1},\phi\rangle\colon\,z_{1}\in X,z_{1}\geq 0,z_{1}\geq x\}+\inf\{\langle z_{2},\phi\rangle\colon\,z_{2}\in X,z_{2}\geq 0,z_{2}\geq y\}=p_{\phi}(x)+p_{\phi}(y). So we have the subadditivity. The positive homogeneity of pϕp_{\phi} is obvious. So pϕp_{\phi} is sublinear.

It is clear that pϕ(x)=x,ϕp_{\phi}(x)=\langle x,\phi\rangle for x0x\geq 0, and pϕ(x)=0p_{\phi}(x)=0 for x0x\leq 0. ∎

Proposition 3.4.

If XX is a vector lattice, ϕX\phi\in X^{\prime} and pϕp_{\phi} is defined by (3.2). Then pϕ(x+)=pϕ(x)p_{\phi}(x^{+})=p_{\phi}(x) for xXx\in X.

Proof.

Let XX be a vector lattice, ϕX\phi\in X^{\prime} and xXx\in X. By (3.2), we have

pϕ(x+)\displaystyle p_{\phi}(x^{+}) =inf{y,ϕ:yx+,y0}\displaystyle=\inf\{\langle y,\phi\rangle\colon\,y\geq x^{+},y\geq 0\}
=inf{y,ϕ:yinf{z:zx,z0},y0}\displaystyle=\inf\{\langle y,\phi\rangle\colon\,y\geq\inf\{z\colon z\geq x,z\geq 0\},y\geq 0\}
inf{y,ϕ:yx,y0}=pϕ(x).\displaystyle\geq\inf\{\langle y,\phi\rangle\colon\,y\geq x,y\geq 0\}=p_{\phi}(x).

Because yxy\geq x and y0y\geq 0 implies yx+y\geq x^{+}, and ϕ\phi is monotone, we have that {y,ϕ:yx,y0}{y,ϕ:yx+,y0}\{\langle y,\phi\rangle\colon\,y\geq x,y\geq 0\}\subseteq\{\langle y,\phi\rangle\colon\,y\geq x^{+},y\geq 0\}, and hence inf{y,ϕ:yx,y0}inf{y,ϕ:yx+,y0}\inf\{\langle y,\phi\rangle\colon\,y\geq x,y\geq 0\}\geq\inf\{\langle y,\phi\rangle\colon\,y\geq x^{+},y\geq 0\}. So we have pϕ(x)pϕ(x+)p_{\phi}(x)\geq p_{\phi}(x^{+}). ∎

We note that the continuous differential function space X=C1[0,1]X=C^{1}[0,1] and the Sobolev space X=Wn,pX=W^{n,p} are (pointwise) ordered vector spaces but not lattices. They are norm complete with respect to \|\cdot\|_{\infty} and Wn,p\|\cdot\|_{W^{n,p}} respectively. However, these norms are not monotone, but one could still define a sublinear function pϕp_{\phi} by (3.2). Next, we will study the contractivity of (T(t))t0(T(t))_{t\geq 0} with respect to pϕp_{\phi} given by (3.2) on ordered Banach space in the following section.

4. Contractivity and positivity of semigroups on ordered Banach spaces

In this section, we will study the relation between the pϕp_{\phi}-contractivity of (T(t))t0(T(t))_{t\geq 0} and the strictly pϕp_{\phi}-dissipativity of its generator AA for XX being an ordered Banach space, the sublinear function pϕp_{\phi} on XX is defined by (3.2). Firstly, we will give a sufficient condition under which (T(t))t0(T(t))_{t\geq 0} is contractive with respect to pϕp_{\phi} on an ordered Banach space.

We will use XX to denote the ordered Banach space in the following of this section, and pϕp_{\phi} on XX is defined by (3.2) with respect to ϕX\phi\in X^{\prime}.

Theorem 4.1.

Let A:X𝒟(A)XA\colon X\supseteq\mathcal{D}(A)\to X be a pϕp_{\phi}-dissipative operator. If (IλA)(I-\lambda A) is invertible for some λ>0\lambda>0, then (IλA)1(I-\lambda A)^{-1} is pϕp_{\phi}-contractive.

Proof.

For a fixed x𝒟(A)x\in\mathcal{D}(A), let ψdpϕ(x)\psi\in dp_{\phi}(x) be such that Ax,ψ0\langle Ax,\psi\rangle\leq 0. Then y,ψpϕ(y)\langle y,\psi\rangle\leq p_{\phi}(y) for all yXy\in X, and x,ψ=pϕ(x)\langle x,\psi\rangle=p_{\phi}(x). Since ψ\psi is positive on XX, we have that |y,ψ|pϕ(y)|\langle y,\psi\rangle|\leq p_{\phi}(y). For some λ>0\lambda>0 one has that

pϕ((λIA)x)|(λIA)x,ψ|Re(λIA)x,ψ\displaystyle p_{\phi}((\lambda I-A)x)\geq|\langle(\lambda I-A)x,\psi\rangle|\geq\mbox{Re}\langle(\lambda I-A)x,\psi\rangle
=\displaystyle= Re(λx,ψAx,ψ)Reλx,ψ=Reλx,ψ=Reλpϕ(x)=λpϕ(x).\displaystyle\mbox{Re}(\langle\lambda x,\psi\rangle-\langle Ax,\psi\rangle)\geq\mbox{Re}\langle\lambda x,\psi\rangle=\mbox{Re}\lambda\langle x,\psi\rangle=\mbox{Re}\lambda p_{\phi}(x)=\lambda p_{\phi}(x).

So if λ>0\lambda>0 is such that (IλA)(I-\lambda A) is invertible, then (IλA)1(I-\lambda A)^{-1} is pϕp_{\phi}-contractive for some λ>0\lambda>0. ∎

Observe that (IλA)1=1λ(1λIA)1=1λR(1λ,A)(I-\lambda A)^{-1}=\frac{1}{\lambda}\left(\frac{1}{\lambda}I-A\right)^{-1}=\frac{1}{\lambda}R\left(\frac{1}{\lambda},A\right). If a strongly continuous semigroup (T(t))t0(T(t))_{t\geq 0} is generated by the operator AA, then for xx in XX, one has

T(t)x=limn[ntR(nt,A)]nx=limn(ItnA)nx.T(t)x=\lim_{n\rightarrow\infty}\left[\frac{n}{t}R\left(\frac{n}{t},A\right)\right]^{n}x=\lim_{n\rightarrow\infty}\left(I-\frac{t}{n}A\right)^{-n}x.

Hence, by Theorem 4.1, if AA is pϕp_{\phi}-dissipative, then T(t)T(t) is pϕp_{\phi}-contractive for every t0t\geq 0. As a consequence we have the following corollary.

Corollary 4.2.

If a strongly continuous semigroup (T(t))t0(T(t))_{t\geq 0} is generated by a pϕp_{\phi}-dissipative operator AA, and (IλA)(I-\lambda A) is invertible for some λ>0\lambda>0. Then T(t)T(t) is pϕp_{\phi}-contractive for every t0t\geq 0.

Next, we will study the positivity of strongly continuous semigroup (T(t))t0(T(t))_{t\geq 0} on an ordered Banach space. The generator AA of (T(t))t0(T(t))_{t\geq 0} is required to be pϕp_{\phi}-dissipative for all ϕ\phi in a total subset of an ordered Banach space.

Definition 4.3.

A nonempty subset ΦK\Phi\subseteq K^{\prime} is called total in XX if ϕ(x)0\phi(x)\geq 0 for each ϕΦ\phi\in\Phi implies x0x\geq 0.

The following example shows that the intersection of a subdifferential set and a total subset on an ordered Banach space X=C1[0,1]X=C^{1}[0,1] is nonempty.

Example 4.4.

Consider X=C1[0,1]X=C^{1}[0,1], and Φ={δt:t[0,1]}\Phi=\{\delta_{t}\colon\,t\in[0,1]\}, where δt(x)=x(t)\delta_{t}(x)=x(t) for an arbitrary xXx\in X. Since δt(x)=x(t)0\delta_{t}(x)=x(t)\geq 0 for all t[0,1]t\in[0,1] implies x0x\geq 0 in XX. So Φ\Phi is total. We claim that for a given t[0,1]t\in[0,1] and xXx\in X, dpt(x)Φdp_{t}(x)\cap\Phi\neq\emptyset for pt(x)=inf{δt(y):y0,yx}p_{t}(x)=\inf\{\delta_{t}(y)\colon\,y\geq 0,y\geq x\}. In fact, let t[0,1]t\in[0,1] and xXx\in X, then pt(x)=inf{δt(y):y0,yx}=inf{y(t):y0,yx}=x+(t)p_{t}(x)=\inf\{\delta_{t}(y)\colon\,y\geq 0,y\geq x\}=\inf\{y(t)\colon\,y\geq 0,y\geq x\}=x^{+}(t). (Here, as X=C1[0,1]X=C^{1}[0,1] is a partially ordered vector space, the positive part is defined in such a way, x+=inf{yX:yx,y0}x^{+}=\inf\{y\in X\colon y\geq x,y\geq 0\}, xX\forall x\in X). So if x(t)0x(t)\leq 0 then pt(x)=x+(t)=0p_{t}(x)=x^{+}(t)=0, and dpt(x)Φ=0dp_{t}(x)\cap\Phi=0. If x0x\geq 0, then δt(y)=y(t)y+(t)=pt(y)\delta_{t}(y)=y(t)\leq y^{+}(t)=p_{t}(y), and ψ(x)=δt(x)=x(t)=x+(t)=pt(x)\psi(x)=\delta_{t}(x)=x(t)=x^{+}(t)=p_{t}(x). So δtdp(x)\delta_{t}\in dp(x). Thus we have shown that Φdpt(x)\Phi\subset dp_{t}(x).

Theorem 4.5.

Let A:X𝒟(A)XA\colon X\supseteq\mathcal{D}(A)\to X be the generator of strongly continuous semigroup (T(t))t0(T(t))_{t\geq 0}. If AA is pϕp_{\phi}-dissipative for all ϕ\phi in a total set Φ\Phi and (IλA)(I-\lambda A) is invertible for some λ0\lambda\geq 0, then T(t)T(t) is positive for all t0t\geq 0.

Proof.

Let ϕΦ\phi\in\Phi, select x0x\leq 0 in XX. By Theorem 4.1, for the semigroup (T(t))t0(T(t))_{t\geq 0} is generated by the operator AA one has pϕ(T(t)x)pϕ(x)p_{\phi}(T(t)x)\leq p_{\phi}(x) for all t0t\geq 0, which means

inf{y,ϕ:yT(t)x,y0}inf{z,ϕ:zx,z0}.\inf\{\langle y,\phi\rangle\colon\,y\geq T(t)x,y\geq 0\}\leq\inf\{\langle z,\phi\rangle\colon\,z\geq x,z\geq 0\}.

Take z=0z=0, then the right side of the above inequality is 0. It follows that

inf{y,ϕ:yT(t)x,y0}0.\inf\{\langle y,\phi\rangle\colon\,y\geq T(t)x,y\geq 0\}\leq 0.

Because of yT(t)xy\geq T(t)x, then y,ϕT(t)x,ϕ\langle y,\phi\rangle\geq\langle T(t)x,\phi\rangle for ϕ\phi is positive. So

T(t)x,ϕinf{y,ϕ:yT(t)x,y0}0.\langle T(t)x,\phi\rangle\leq\inf\{\langle y,\phi\rangle\colon\,y\geq T(t)x,y\geq 0\}\leq 0.

Since Φ\Phi is total, one has that T(t)x,ϕ0\langle T(t)x,\phi\rangle\leq 0 for all ϕΦ\phi\in\Phi implies T(t)x0T(t)x\leq 0. Thus T(t)T(t) is positive. ∎

Remark 4.6.

Due to [3, Theorem 1.2], if AA is densely defined on a Banach lattice, then (T(t))t0(T(t))_{t\geq 0} is positive and contractive if and only if AA is dispersive and (λIA)(\lambda I-A) is surjective for some λ>0\lambda>0. By Theorem 4.1, we could generalize one direction of this conclusion to ordered Banach spaces. We will illustrate this through an example of a second derivative operator with Dirichlet boundary condition. This example originally comes from [3, Example 1.5].

Example 4.7.

Let X=(C1[0,1],)X=(C^{1}[0,1],\|\cdot\|_{\infty}) be an ordered Banach space, the densely defined operator AA be the second derivative operator with Dirichlet boundary condition. Then the domain satisfies 𝒟(A)={xC3[0,1]:x(0)=x(1)=x′′(0)=x′′(1)}\mathcal{D}(A)=\{x\in C^{3}[0,1]\colon\,x(0)=x(1)=x^{\prime\prime}(0)=x^{\prime\prime}(1)\}. For xXx\in X, we choose t[0,1]t\in[0,1] such that pδt(x)=x,δt=x(t)=sups[0,1]x(s)=xp_{\delta_{t}}(x)=\langle x,\delta_{t}\rangle=x(t)=\sup_{s\in[0,1]}x(s)=\|x\|_{\infty}. Then y,δt=y(t)y=pδt(y)\langle y,\delta_{t}\rangle=y(t)\leq\|y\|_{\infty}=p_{\delta_{t}}(y) for all yXy\in X. Hence δtdpδt(x)\delta_{t}\in dp_{\delta_{t}}(x). Moreover, since xx has a maximum in XX, we have that Ax,δt=x′′(t)0\langle Ax,\delta_{t}\rangle=x^{\prime\prime}(t)\leq 0. So AA is pδtp_{\delta_{t}}-dissipative. For yXy\in X define the function x0(t)=12[ett1esg(s)𝑑sett1esg(s)𝑑s]x_{0}(t)=\frac{1}{2}[e^{t}\int_{t}^{1}e^{-s}g(s)ds-e^{-t}\int_{t}^{1}e^{s}g(s)ds]. Then there exist m,nm,n\in\mathbb{R} such that x(t)=x0(t)+met+netx(t)=x_{0}(t)+me^{t}+ne^{-t} and x(0)=x(1)=0x(0)=x(1)=0, and then x𝒟(A)x\in\mathcal{D}(A). Since xx′′=x0x0′′=yx-x^{\prime\prime}=x_{0}-x_{0}^{\prime\prime}=y, we have (IA)(I-A) is surjective. For x𝒟(A)x\in\mathcal{D}(A), suppose that (IA)x=0(I-A)x=0, then x(t)=αet+βetx(t)=\alpha e^{t}+\beta e^{-t}. Notice that x(0)=x(1)=0x(0)=x(1)=0 such that α=β=0\alpha=\beta=0, so x(t)=0x(t)=0 for t[0,1]t\in[0,1]. So (IA)(I-A) is injective. It follows from Corollary 4.2 that AA is the generator of a contractive semigroup. By Theorem 4.5, AA generates a strongly continuous positive semigroup T(t)t0T(t)_{t\geq 0}.

Remark 4.8.

Note that in an ordered Banach space, specifically C1[0,1]C^{1}[0,1], it is hard to give the definition of the dispersivity of an operator AA with respect to the original norm, because C1[0,1]C^{1}[0,1] is not a lattice. However, by the above discussion, we still have flexibility to choose a function as in (3.2), which depends on a function ϕ\phi in XX^{\prime}. This is also different from the arguments in [3, Example 1.5].

5. Positive off-diagonal property of operators on ordered vector spaces

In this section, we will introduce the positive off-diagonal property especially on pre-Riesz spaces, in particular C1(Ω)C^{1}(\Omega) with Ωn\Omega\subseteq\mathbb{R}^{n} open. Explicitly, we investigate a representation theorem for positive linear functionals on Archimedean pre-Riesz spaces, which is also interesting independently.

Definition 5.1.

Let XX be an ordered vector space. A linear operator A:𝒟(A)XXA\colon\mathcal{D}(A)\subseteq X\rightarrow X is said to have the positive off-diagonal property if Ax,ϕ0\langle Ax,\phi\rangle\geq 0 whenever 0x𝒟(A)0\leq x\in\mathcal{D}(A) and 0ϕX0\leq\phi\in X^{\prime} with x,ϕ=0\langle x,\phi\rangle=0.

The motivation of the positive off-diagonal property comes from matrix theory, where the off-diagonal elements of the matrix A=(aij)A=(a_{ij}) are positive, i.e., aij0a_{ij}\geq 0 for all iji\neq j. It is shown in [5, Lemma 7.23] that on an ordered Banach space XX with an order unit uu such that u𝒟(A)u\in\mathcal{D}(A), the operator AA has the positive off-diagonal property and Au0Au\leq 0 if and only if AA is Ψu\Psi_{u}-dissipative, where Ψu\Psi_{u} is the order unit function, i.e. Ψu(x)=inf{λ0:xλu}\Psi_{u}(x)=\inf\{\lambda\geq 0\colon x\leq\lambda u\}, xXx\in X. However, in general, the properties that AA has the positive off-diagonal property and AA is pp-dissipative for a given pp on XX do not imply each other, as the following example shows.

Example 5.2.

Let X=2X=\mathbb{R}^{2} and p(x)=x12+x22p(x)=\sqrt{x_{1}^{2}+x_{2}^{2}} for x=(x1,x2)x=(x_{1},x_{2}). Let A=(1111)A=\begin{pmatrix}1&1\\ 1&1\end{pmatrix}, then AA has the positive off-diagonal property. Take x=(1,0)x=(1,0), then x=(1,0)dp(x)x^{\prime}=(1,0)\in dp(x) but Ax,x=1\langle Ax,x^{\prime}\rangle=1, so AA is not pp-dissipative. Let A=(1111)A=\begin{pmatrix}-1&-1\\ 1&1\end{pmatrix}, and 𝒟(A)={x=(x1,x2)X:x10,x2=0}\mathcal{D}(A)=\{x=(x_{1},x_{2})\in X\colon x_{1}\geq 0,x_{2}=0\}. Take x=(1,0)x^{\prime}=(1,0), then xdp(x)x^{\prime}\in dp(x) for every x𝒟(A)x\in\mathcal{D}(A). It is obvious that Ax,x0\langle Ax,x^{\prime}\rangle\leq 0. So AA is pp-dissipative, but does not have positive off-diagonal property.

Next, we consider a representation theorem in pre-Riesz spaces.

Theorem 5.3.

Let XX be an Archimedean pre-Riesz space with order unit. Then there exists a compact Hausdorff space Ω\Omega and a bipositive linear map i:XC(Ω)i\colon X\rightarrow C(\Omega) such that i(X)i(X) is order dense in C(Ω)C(\Omega). Moreover, for every positive linear functional ϕ\phi on XX, there exists a regular Borel measure μ\mu on Ω\Omega such that

ϕ(x)=Ωi(x)(ω)𝑑μ(ω),xX,ωΩ.\phi(x)=\int_{\Omega}i(x)(\omega)d\mu(\omega),\quad x\in X,\ \omega\in\Omega.
Proof.

The first part of this theorem follows from [8, Lemma 6].

For the second part, let C(Ω)C(\Omega) be the space of all continuous functions on Ω\Omega, where Ω\Omega is a compact Housdorff space. Let i:XC(Ω)i\colon X\rightarrow C(\Omega) be a bipositive linear map such that i(X)i(X) is an order dense subspace of C(Ω)C(\Omega). So for a positive linear function ϕ:X\phi\colon X\to\mathbb{R}, one has that ϕi1:i(X)+\phi\circ i^{-1}\colon i(X)\to\mathbb{R}^{+} is a positive linear function on i(X)i(X). Since \mathbb{R} is Dedekind complete, and i(X)i(X) is a majorizing subspace of C(Ω)C(\Omega), by Kantorovich’s extension theorem (see [1, Theorem 1.32]), there exists an extension of ϕi1\phi\circ i^{-1} to a positive function ψ:C(Ω)\psi\colon C(\Omega)\to\mathbb{R}. By the Riesz representation theorem, for ψ\psi on C(Ω)C(\Omega), there exists a unique regular Borel measure μ\mu on Ω\Omega such that

ψ(f)=Ωf(ω)𝑑μ(ω),fC(Ω),ωΩ.\psi(f)=\int_{\Omega}f(\omega)d\mu(\omega),\quad\forall f\in C(\Omega),\ \omega\in\Omega.

So for every xXx\in X, one has ϕi1(i(x))=ψ(i(x))\phi\circ i^{-1}(i(x))=\psi(i(x)). If we take f=i(x)f=i(x), then

ϕ(x)=ϕi1(i(x))=ψ(i(x))=Ωi(x)(ω)𝑑μ(ω).\phi(x)=\phi\circ i^{-1}(i(x))=\psi(i(x))=\int_{\Omega}i(x)(\omega)d\mu(\omega).

Thus we get the conclusion. ∎

We give an example to illustrate that the positive off-diagonal property of AA can be generalized to a special kind of ordered vector space, in particular to the pre-Riesz space C1[0,1]C^{1}[0,1].

Example 5.4.

Let C[0,1]C[0,1] be the real continuous functions. Let X=C1[0,1]X=C^{1}[0,1] which is an Archimedean pre-Riesz space, then XX is an order dense subspace of C[0,1]C[0,1]. Let AL(X)A\in L(X) be a densely defined operator, we claim that AA has positive off-diagonal property if and only if (Ax)(t)0(Ax)(t)\geq 0 whenever 0x𝒟(A)0\leq x\in\mathcal{D}(A) and t[0,1]t\in[0,1] with x(t)=0x(t)=0. In fact, first suppose that AA has the positive off-diagonal property and 0x𝒟(A)0\leq x\in\mathcal{D}(A), t[0,1]t\in[0,1] with x(t)=0x(t)=0. Take 0δtX0\leq\delta_{t}\in X^{\prime} to be the point evaluation at tt, then it follows from x(t)=x,δt=0x(t)=\langle x,\delta_{t}\rangle=0 that Ax,δt0\langle Ax,\delta_{t}\rangle\geq 0, i.e. (Ax)(t)0(Ax)(t)\geq 0. Conversely, assume 0x𝒟(A)0\leq x\in\mathcal{D}(A), and 0ϕX0\leq\phi\in X^{\prime} with x,ϕ=0\langle x,\phi\rangle=0. Then Theorem 5.3 can be applied since C[0,1]C[0,1] has an order unit, and then there exists a regular Borel measure μ\mu on [0,1][0,1] that represents ϕ\phi, i.e. x,ϕ=01i(x)(t)𝑑μ(t)\langle x,\phi\rangle=\int_{0}^{1}i(x)(t)d\mu(t). By assumption, we have i(x)(t)=0i(x)(t)=0 and x(t)=0x(t)=0 for all tt in the support of μ\mu, then (Ax)(t)0(Ax)(t)\geq 0 and i(Ax)(t)0i(Ax)(t)\geq 0. Hence Ax,ϕ=01i(Ax)(t)𝑑μ(t)0\langle Ax,\phi\rangle=\int_{0}^{1}i(Ax)(t)d\mu(t)\geq 0. This shows that AA has the positive off-diagonal property.

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