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Device-independent self-testing of unsharp measurements

Prabuddha Roy [email protected] National Institute of Technology Patna, Ashok Rajpath, Patna, Bihar 800005, India    A. K. Pan [email protected] National Institute of Technology Patna, Ashok Rajpath, Patna, Bihar 800005, India Department of Physics, Indian Institute of Technology Hyderabad, Telengana-502284, India
Abstract

Semi-device-independent certification of an unsharp instrument has recently been demonstrated [New J. Phys. 21, 083034 (2019)] based on the sequential sharing of quantum advantages in a prepare-measure communication game by assuming the system to be qubit. In this work, we provide device-independent (DI) self-testing of the unsharp instrument through the quantum violation of two Bell inequalities where the devices are uncharacterized and the dimension of the system remains unspecified. We introduce an elegant sum-of-squares approach to derive the dimension-independent optimal quantum violation of Bell inequalities which plays a crucial role. Note that the standard Bell test cannot self-test the post-measurement states and consequently cannot self-test unsharp instrument. The sequential Bell test possess the potential to self-test an unsharp instrument. We demonstrate that there exists a trade-off between the maximum sequential quantum violations of the Clauser-Horne-Shimony-Holt inequality, and they form an optimal pair that enables the DI self-testing of the entangled state, the observables, and the unsharpness parameter. Further, we extend our study to the case of elegant Bell inequality and we argue that it has two classical bounds - the local bound and the non-trivial preparation non-contextual bound, lower than the local bound. Based on the sharing of preparation contextuality by three independent sequential observers, we demonstrate the DI self-testing of two unsharpness parameters. Since an actual experimental scenario involves losses and imperfection, we demonstrate robustness of our certification to noise.

I Introduction

Measurement plays a pivotal role in quantum theory which is in stark contrast to classical theory. The textbook version of a quantum measurement is modeled by a set of orthogonal projectors belonging to the Hilbert space. However, there exist more general measurements defined in terms of positive-operator-valued measures (POVMs) satisfying the completeness relation. Note that the POVMs can be defined in many different ways. However, in this paper, we are concerned about those POVMs which are noisy or unsharp variants of the projective measurements.

In a sharp projective measurement [1], the system collapses to one of the eigenstates of the measured observable, and the system is completely disturbed by the process of sharp measurement, so that, no residual coherence remains in the system. On the other hand, in the case of unsharp measurements that are characterized by the POVMs, the system is less disturbed compared to the sharp projective measurement. Since a projective measurement maximally disturbs the quantum system and hence extracts more information from the system compared to POVMs, one may think that a sharp measurement is more advantageous in information processing tasks. However, there exist certain information processing tasks where POVMs are proven to be more useful compared to sharp measurement.

Advantage of POVMs over sharp measurement has been explored in the context of quantum state discrimination [2, 3], randomness certification [4, 7, 6, 5], quantum tomography[8], state estimation [9], quantum cryptography [10], information acquisition from a quantum source [11], quantum violation of certain Bell inequalities [12], and many more. There is one more advantage that is particularly relevant in the present work is the sequential sharing of various forms of quantum correlations [13, 14, 15, 16, 17, 18]. For example, a sequential Bell test by multiple independent observers inevitably requires the prior observers to perform the unsharp quantum measurements.

In this work, we aim to provide device-independent (DI) self-testing of the unsharp measurements, which are noisy variants of the sharp projective measurements. Self-testing [19, 20, 21, 22, 23] is the strongest form of certification protocol where the devices are treated as black boxes. Also, the dimension of the quantum system is assumed to be finite but unbounded. In that, observed experimental statistics uniquely certify the state and measurement observables of an unknown dimension. DI self-testing is advantageous over the standard certification methods such as those based on quantum tomography. Essentially, a self-testing protocol requires optimal quantum violation of a suitable Bell’s inequality [24]. For example, optimal violation of Clauser-Horne-Shimony-Holt (CHSH) inequality self-tests the maximally entangled state and mutually anticommuting local observables in any arbitrary dimension. Note that the DI certification encounters practical challenges arising from the requirement of a loophole-free Bell test. Such tests have recently been realized [25, 28, 26, 27, 29] enabling experimental demonstrations of DI certification of randomness [30, 31]. Of late, the DI certification is used as a resource for secure quantum key distribution [32, 33, 34, 35], randomness certification [36, 38, 37], witnessing Hilbert space dimension [39, 40, 41, 42, 43, 44, 45] and for achieving advantages in communication complexity tasks [46].

We provide DI self-testing schemes to certify the unsharpness parameters through the quantum violation of two well-known Bell inequalities viz., the CHSH inequality [24] and the elegant Bell inequality [47]. Note that optimal quantum violations of such Bell inequalities can be obtained only for sharp measurement. Any value less than the optimal quantum value may originate due to various reasons. It may come from the unsharp measurements of local observables but may also come from the nonideal preparation of the state or the inappropriate choices of the local observables than the ones required for the optimal quantum violation. However, a more serious issue regarding DI self-testing of unsharp measurement through a Bell test arises due to Naimark’s theorem. It states that every non-projective measurement can be modeled as a projective measurement in a larger Hilbert space by introducing suitable ancilla in a higher dimension. Since in the DI Bell test, there is no bound on the dimension, a stubborn physicist may argue that the sub-optimal quantum violation is arising due to the inappropriate choice of observables in a higher dimension and not due to the unsharpness of the measurement. Hence, to self-test unsharp measurements, one needs to introduce a protocol that certifies the state, the observables, and the unsharpness parameters without referring to the dimension of the system.

Against this backdrop, we demonstrate that the sequential Bell test has such potential where the sub-optimal sequential quantum violations of a Bell inequality by multiple independent observers on one side can enable such a self-testing. Such a scheme successfully bypasses the constraints that would arise from Naimark’s theorem as the optimization of sequential Bell expression is performed without imposing any constraint on the dimension of Hilbert space. As far as our knowledge goes, the DI self-testing of non-projective measurements through the Bell test has not hitherto been demonstrated. However, semi-DI certification of non-projective measurements has been demonstrated by using the qubit system. In [48, 49, 50], the extremal qubit POVMs were experimentally certified based on the theoretical proposal [4]. Those experiments [48, 49, 50, 51] do certify the non-projective character of measurement, but not how it relates to a specific target POVM. The semi-DI certification of qubit unsharp measurements (noisy variants of projective measurement) in the prepare-measure scenario has recently been proposed [52, 53, 54, 55]. The proposal of [52] has been experimentally verified [51, 56, 57].

Specifically, in our self-testing protocol, two sequential sub-optimal quantum violations of a Bell inequality form an optimal pair powering the DI certifications of the state, the local observables, and the unsharpness parameter of one of the two parties. We also note here that all the previous works that demonstrated the sharing of various quantum correlations [17, 60, 16, 59, 61, 58, 62, 55, 63, 64, 65], the dimension of the system was assumed. In contrast, throughout this work, we impose no bound on the dimension of the Hilbert space, and we consider that the measurement devices are black boxes. We first demonstrate that, at most, two independent sequential observers on one side can violate the CHSH inequality. We simultaneously maximize the quantum violations of CHSH inequality for two sequential observers on one side and demonstrate that there is a trade-off between the two sub-optimal quantum violations. This, in turn, certifies the state, and the observables for both the sequential observers and the unsharpness parameter of the first observer. Since in a practical implementation there remains imperfection, we show how a range of an unsharpness parameter can be self-tested in that scenario.

The protocol developed for the CHSH inequality is further extended to the case of elegant Bell inequality, where we demonstrate that, at most, two observers can share the quantum advantage when considering the inequality’s local bound. However, we argue that the elegant Bell inequality has two classical bounds, the local and the preparation non-contextual bound, and the latter is smaller than the former. We show that if we consider the preparation non-contextual bound of the elegant Bell inequality, then at most three observers can share the quantum advantage. Further, we demonstrate that if the quantum advantage is extended to a third sequential observer, then the range of the values of the unsharpness parameter for the first observer can be more restricted, thereby self-testing a narrow range of the values of the unsharpness parameter in the sub-optimal scenario.

This paper is organized as follows. In Sec. II, we demonstrate the optimal quantum violation of CHSH inequality using an elegant sum-of-squares approach. In section III, we explicitly show the sequential violation of CHSH inequality and self-testing of the unsharpness parameter. In Sec. IV, we briefly introduce the notion of the preparation non-contextuality in an ontological model and provide the preparation non-contextual bound of elegant Bell inequality. In Sec. V, we extend the sharing of preparation contextuality by three sequential observers based on the quantum violation of elegant Bell inequality and demonstrate the self-testing of two unsharpness parameters along with the states and the observables. Finally, we discuss our results in Sec. VI.

II Optimal quantum violation of CHSH inequality

The CHSH scenario consists of two space-like separated parties (say, Alice and Bob) who share a common physical system. Alice (Bob) performs local measurements on her (his) subsystem upon receiving inputs x{1,2}(y{1,2})x\in\{1,2\}(y\in\{1,2\}), and returns outputs a{0,1}(b{0,1})a\in\{0,1\}(b\in\{0,1\}). Representing MxM_{x} and NyN_{y} as respective dichotomic observables of Alice and Bob, the CHSH form of Bell’s inequality can be written as

=(M1+M2)N1+(M1M2)N22.\mathcal{B}=\left(M_{1}+M_{2}\right)N_{1}+\left(M_{1}-M_{2}\right)N_{2}\leq 2. (1)

The optimal quantum value of the CHSH expression is ()Qopt=22\left(\mathcal{B}\right)^{opt}_{Q}=2\sqrt{2}, commonly known as Tirelson bound [66]. The optimal value can be obtained when the shared state is maximally entangled in a two-qubit system and the local qubit observables are mutually anticommuting. However, one does not need to impose the bound on the dimension to obtain the optimal value. Also, the measurement of Alice and Bob remains uncharacterized. In other words, the optimal value ()Qopt\left(\mathcal{B}\right)^{opt}_{Q} can be achieved if Alice and Bob perform dichotomic measurements on a maximally entangled state |ψAB𝒞d𝒞d\ket{\psi}_{AB}\in\mathcal{C}^{d}\otimes\ \mathcal{C}^{d} where d2d\geq 2 is arbitrary.

For our purpose, we provide a derivation of the ()Qopt\left(\mathcal{B}\right)^{opt}_{Q} without imposing a bound on the Hilbert space dimension by introducing an elegant sum-of-squares (SOS) approach. Let us assume that ()QΩ2(\mathcal{B})_{Q}\leq\Omega_{2}, where Ω2\Omega_{2} is a positive quantity and the upper bound of ()Q(\mathcal{B})_{Q}. Equivalently, one can argue that there is a positive semi-definite operator η0\eta\geq 0, that can be expressed as

ηQ=Ω2()Q\displaystyle\langle\eta\rangle_{Q}=\Omega_{2}-(\mathcal{B})_{Q} (2)

for a quantum state |ψAB|\psi\rangle_{AB}. This can be proven by considering two suitable positive operators, L1L_{1} and L2L_{2}, which are polynomial functions of MxM_{x} and NyN_{y}, so that

η=12(ω1L1L1+ω2L2L2).\displaystyle\eta=\frac{1}{2}\left(\omega_{1}L_{1}^{\dagger}L_{1}+\omega_{2}L_{2}^{\dagger}L_{2}\right). (3)

For our purpose, we suitably choose L1L_{1} and L2L_{2} as

L1|ψAB=M1+M2ω1|ψABN1|ψAB\displaystyle L_{1}|\psi\rangle_{AB}=\frac{M_{1}+M_{2}}{\omega_{1}}|\psi\rangle_{AB}-N_{1}|\psi\rangle_{AB} (4)
L2|ψAB=M1M2ω1|ψABN2|ψAB\displaystyle L_{2}|\psi\rangle_{AB}=\frac{M_{1}-M_{2}}{\omega_{1}}|\psi\rangle_{AB}-N_{2}|\psi\rangle_{AB}

where ω1=(M1+M2)|ψAB2\omega_{1}=||\left(M_{1}+M_{2}\right)|\psi\rangle_{AB}||_{2} an ω2=(M1M2)|ψAB2\omega_{2}=||\left(M_{1}-M_{2}\right)|\psi\rangle_{AB}||_{2}. Here ||.||2||.||_{2} is the Frobenius norm of a vector, 𝒪2=Tr[𝒪𝒪ρ]||\ \mathcal{O}\ ||_{2}=\sqrt{Tr[\mathcal{O}^{\dagger}\mathcal{O}\rho]}. Plugging Eq. (4) into Eq. (3) and by noting that MxMx=NyNy=𝕀M_{x}^{\dagger}M_{x}=N_{y}^{\dagger}N_{y}=\mathbb{I}, we get

()Q=(ω1+ω2)ηQ.\displaystyle(\mathcal{B})_{Q}=\left(\omega_{1}+\omega_{2}\right)-\langle\eta\rangle_{Q}. (5)

Optimal value of ()Q(\mathcal{B})_{Q} can be obtained when ηQ=0\langle\eta\rangle_{Q}=0, i.e.,

()Qopt\displaystyle(\mathcal{B})_{Q}^{opt} =\displaystyle= max(ω1+ω2)\displaystyle\underset{{}}{max}\left(\omega_{1}+\omega_{2}\right)
=\displaystyle= max(2+{M1,M2}+2{M1,M2}).\displaystyle\underset{{}}{max}\left(\sqrt{2+\langle\{M_{1},M_{2}\}\rangle}+\sqrt{2-\langle\{M_{1},M_{2}\}\rangle}\right).

Thus, the maximization requires {M1,M2}=0\{M_{1},M_{2}\}=0 implying Alice’s observables have to be anticommuting. In turn, we find the values ω1=ω2=2\omega_{1}=\omega_{2}=\sqrt{2}, and consequently the optimal value ()Qopt=22(\mathcal{B})_{Q}^{opt}=2\sqrt{2}. The explicit conditions for the optimization are L1|ψAB=0L_{1}|\psi\rangle_{AB}=0 and L2|ψAB=0L_{2}|\psi\rangle_{AB}=0, i.e., N1=(M1+M2)/2N_{1}=(M_{1}+M_{2})/\sqrt{2} and N2=(M1M2)/2N_{2}=(M_{1}-M_{2})/\sqrt{2}. It can be easily checked that {N1,N2}=0\{N_{1},N_{2}\}=0, i.e., Bob’s observables are also anticommuting.

Note also that for the state ρAB=|ψABψAB|𝒞d𝒞d\rho_{AB}=\ket{\psi_{AB}}\bra{\psi_{AB}}\in\mathcal{C}^{d}\otimes\mathcal{C}^{d}, optimal violation requires Tr[N1N1ρAB]=Tr[N2N2ρAB]=1Tr[N_{1}\otimes N_{1}\rho_{AB}]=Tr[N_{2}\otimes N_{2}\rho_{AB}]=1, which again confirms that ρAB\rho_{AB} has to be a pure state. Let us choose the state in Hilbert-Schmidt form as

ρAB=1d2[𝕀𝕀+i=1d21NiNi]\displaystyle\rho_{AB}=\frac{1}{d^{2}}\Big{[}\mathbb{I}\otimes\mathbb{I}+\sum_{i=1}^{d^{2}-1}N_{i}\otimes N_{i}\Big{]} (7)

where {Ni,Nj}=0\{N_{i},N_{j}\}=0 and consequently [NiNi,NjNj]=0[N_{i}\otimes N_{i},N_{j}\otimes N_{j}]=0 for any arbitrary dimension dd. For a density matrix ρAB\rho_{AB}, Tr[ρAB]=1Tr[\rho_{AB}]=1 has to be satisfied. This in turn provides Tr[N1]=Tr[N2]=0Tr[N_{1}]=Tr[N_{2}]=0. Also, Tr[ρAB2]=1Tr[\rho_{AB}^{2}]=1 ensures that the observables in the summation in Eq. (II) contains full set of mutually anticommuting observables {NiNi}\{N_{i}\otimes N_{i}\}. Consequently, TrA[ρAB]=TrB[ρAB]=𝕀dTr_{A}[\rho_{AB}]=Tr_{B}[\rho_{AB}]=\frac{\mathbb{I}}{d}, i.e., partial trace of ρAB\rho_{AB} is maximally mixed state for both Alice and Bob. Thus, the optimal violation of the CHSH inequality is achieved for the maximally entangled state |ψAB\ket{\psi_{AB}}. We thus derive the optimal quantum value ()Qopt(\mathcal{B})_{Q}^{opt} which uniquely certifies the state and observables. The entire derivation is done without assuming the dimension of the system.

III Sequential sharing of nonlocality and self-testing of unsharpness parameter

The sequential Bell-CHSH test in the DI scenario is depicted in Figure 1. There is only one Alice, who always performs sharp measurement and arbitrary kk number of sequential Bobs (say, Bobk). Alice and Bob1 share an entangled state ρAB1\rho_{AB_{1}}. Our aim is to demonstrate the sharing of nonlocality by multiple sequential observers. Since a projective measurement inevitably disturbs the system maximally; hence, in the sequential Bell test, if the first Bob (Bob1) performs a sharp measurement, the entanglement is lost after the measurement. In such a case, no residual entanglement remains for the second sequential observer (Bob2); consequently, the Bell inequality cannot be violated. If both the sequential observers obtain the sub-optimal quantum violations, then the first observer must have to perform an unsharp measurement.

In this work, the unsharp measurement corresponds to the noisy variant of projective measurements, i.e., the number of measurement operators is restricted to two. After performing the unsharp measurement, Bob1 relays the post-measurement state to Bob2, who performs an unsharp measurement intending to violate the Bell inequality. The chain runs up to arbitrary kthk^{th} Bob (Bobk) until the quantum violation of Bell’s inequality is obtained. The kthk^{\text{th}} Bob may perform the sharp measurement. It is quite known that in the standard scenario at most, two Bobs can sequentially demonstrate nonlocality through the violation of CHSH inequality [13]. We stress again that, before our work all the studies that demonstrated the sharing of nonlocality, the dimension of the system was assumed.

We consider that Alice, upon receiving input x={1,2}x=\{1,2\}, always performs the projective measurements of observables A1A_{1} and A2A_{2}. The CHSH form of Bell’s inequality can be written as

=(A1+A2)B1+(A1A2)B22.\mathcal{B}=\left(A_{1}+A_{2}\right)B_{1}+\left(A_{1}-A_{2}\right)B_{2}\leq 2. (8)

There are arbitrary kk number of sequential Bobs (say, Bobk), who upon receiving input yk{1,2}y_{k}\in\{1,2\} perform measurements of B1B_{1} and B2B_{2} producing outputs bk{0,1}b_{k}\in\{0,1\}. We demonstrate how sequential quantum violations of CHSH inequality by multiple independent Bobs enable the DI certification of the unsharpness parameter.

Refer to caption
Figure 1: Black box diagram for sequential Bell test consisting of one Alice and multiple sequential Bobs (Bobk). Alice shares an entangled state with Bob1. After Bob1’s unsharp measurement, the average state is relayed to Bob2 and so on.

Now, if Bobk’s instrument is represented by measurement operators {Kbk|yk}\{K_{b_{k}|y_{k}}\} then after (k1)th(k-1)^{th} Bob’s measurement, the average state shared between Alice and Bobk is

ρABk=12bk±yk=12Kbk|ykρAB(k1)Kbk|yk\displaystyle\rho_{AB_{k}}=\frac{1}{2}\sum_{b_{k}\in\pm}\sum_{y_{k}=1}^{2}K_{b_{k}|y_{k}}^{\dagger}\ \rho_{AB_{(k-1)}}\ K_{b_{k}|y_{k}} (9)

where k\forall k, bk=±1Kbk|ykKbk|yk=𝕀\sum_{b_{k}=\pm 1}K_{b_{k}|y_{k}}^{\dagger}K_{b_{k}|y_{k}}=\mathbb{I}. Also, Kbk|yk=Ebk|ykK_{b_{k}|y_{k}}=\sqrt{E_{b_{k}|y_{k}}} where Ebk|ykE_{b_{k}|y_{k}} is the POVM. We consider that k\forall k and yk\forall y_{k} the POVM [67, 68] is of the form

E±|yk=1±λk2Πyk++1λk2Πyk\displaystyle E_{\pm|y_{k}}=\frac{1\pm\lambda_{k}}{2}\Pi_{y_{k}}^{+}+\frac{1\mp\lambda_{k}}{2}\Pi_{y_{k}}^{-} (10)

where {Πyk±}\{\Pi_{y_{k}}^{\pm}\} are the projectors corresponding to the observable BykB_{y_{k}} satisfying Πyk++Πyk=𝕀\Pi_{y_{k}}^{+}+\Pi_{y_{k}}^{-}=\mathbb{I}, and λk\lambda_{k} is the unsharpness parameter for kthk^{\text{th}} Bob. The measurement operators can then be written as, K±|yk=αk𝕀±βkBykK{\pm|y_{k}}=\alpha_{k}\mathbb{I}\pm\beta_{k}B_{y_{k}} where

αk=12((1+λk)2+(1λk)2)\displaystyle\alpha_{k}=\frac{1}{2}\Big{(}\sqrt{\frac{(1+\lambda_{k})}{2}}+\sqrt{\frac{(1-\lambda_{k})}{2}}\Big{)} (11)
βk=12((1+λk)2(1λk)2),\displaystyle\beta_{k}=\frac{1}{2}\Big{(}\sqrt{\frac{(1+\lambda_{k})}{2}}-\sqrt{\frac{(1-\lambda_{k})}{2}}\Big{)},

satisfying αk2+βk2=1/2\alpha_{k}^{2}+\beta_{k}^{2}=1/2 with αkβk\alpha_{k}\geq\beta_{k}.

We derive the maximum quantum value of CHSH expression for Alice and Bob1 as

(1)Q=λ1()Qopt\displaystyle(\mathcal{B}^{1})_{Q}=\lambda_{1}(\mathcal{B})_{Q}^{opt} (12)

which is independent of assuming the dimension. Here, λ1\lambda_{1} is the unsharpness parameter of Bob1.

After his unsharp measurement, Bob1 relays the average state to Bob2. From Eq. (9), the reduced state for Alice and Bob2 can be written as

ρAB2\displaystyle\rho_{AB_{2}} =\displaystyle= 12b1{+,}y1=12(𝕀Kb1|y1)ρAB1(𝕀Kb1|y1)\displaystyle\dfrac{1}{2}\sum_{b_{1}\in\{+,-\}}\sum_{y_{1}=1}^{2}\left(\mathbb{I}\otimes K_{b_{1}|y_{1}}\right)\rho_{AB_{1}}\left(\mathbb{I}\otimes K_{b_{1}|y_{1}}\right) (13)
=\displaystyle= 2α12ρAB1+β12y1=12(𝕀By1)ρAB1(𝕀By1).\displaystyle 2\alpha^{2}_{1}\rho_{AB_{1}}+\beta^{2}_{1}\sum_{y_{1}=1}^{2}(\mathbb{I}\otimes B_{y_{1}})\rho_{AB_{1}}(\mathbb{I}\otimes B_{y_{1}}).

For the time being, let us consider that each sequential Bob measures same set of observables B1B_{1} and B2B_{2}, i.e., k,Byk=1B1\forall k,\ B_{y_{k=1}}\equiv B_{1} and Byk=2B2B_{y_{k=2}}\equiv B_{2}. By using Eq. (13), the maximum quantum value of CHSH expression for Alice and Bob2 can be written as

(2)Q\displaystyle(\mathcal{B}^{2})_{Q} =\displaystyle= max(Tr[ρAB2])\displaystyle max\Big{(}Tr[\rho_{AB_{2}}\mathcal{B}]\Big{)} (14)
=\displaystyle= max(Tr[ρAB1((A1+A2)B~1+(A1A2)B~2)])\displaystyle max\Bigg{(}Tr\Big{[}\rho_{AB_{1}}\Big{(}(A_{1}+A_{2})\tilde{B}_{1}+(A_{1}-A_{2})\tilde{B}_{2}\Big{)}\Big{]}\Bigg{)}

where we assume Bob2 performs sharp measurement. We derive the explicit forms of B~1\tilde{B}_{1} and B~2\tilde{B}_{2} as

B~1\displaystyle\tilde{B}_{1} =\displaystyle= (2α12+β12)B1+β12B2B1B2\displaystyle(2\alpha_{1}^{2}+\beta_{1}^{2})B_{1}+\beta_{1}^{2}B_{2}B_{1}B_{2}
B~2\displaystyle\tilde{B}_{2} =\displaystyle= (2α12+β12)B2+β12B1B2B1.\displaystyle(2\alpha_{1}^{2}+\beta_{1}^{2})B_{2}+\beta_{1}^{2}B_{1}B_{2}B_{1}. (15)

Note that, Eq. (14) has a similar form of CHSH expression as in Eq. (8), if B~1\tilde{B}_{1} and B~2\tilde{B}_{2} are considered to be effective observables of Bob2. We can use the earlier SOS approach to obtain the maximum quantum value. However, (B~1)2𝕀(\tilde{B}_{1})^{2}\neq\mathbb{I} and (B~2)2𝕀(\tilde{B}_{2})^{2}\neq\mathbb{I}, and hence they need to be properly normalized. By considering ω~1=B~1\tilde{\omega}_{1}=||\tilde{B}_{1}|| and ω~2=B~2\tilde{\omega}_{2}=||\tilde{B}_{2}||, and by using the SOS approach we have

(2)Q=max(ω1ω~1+ω2ω~2).\displaystyle(\mathcal{B}^{2})_{Q}=max\left(\omega_{1}\tilde{\omega}_{1}+\omega_{2}\tilde{\omega}_{2}\right). (16)

As we already proved earlier, to obtain the optimal quantum value Alice’s and Bob’s observables have to be mutually anticommuting. Hence, for Bob’s (unnormalized) observables B~1\tilde{B}_{1} and B~2\tilde{B}_{2} we require,

{B~1,B~2}=4α12(α12+2β12){B1,B2}+β14{B1,B2}3=0.\displaystyle\{\tilde{B}_{1},\tilde{B}_{2}\}=4\alpha_{1}^{2}(\alpha_{1}^{2}+2\beta_{1}^{2})\{B_{1},B_{2}\}+\beta_{1}^{4}\{B_{1},B_{2}\}^{3}=0. (17)

Since α1>0\alpha_{1}>0 and β10\beta_{1}\geq 0, Eq. (17) gives {B1,B2}=0\{B_{1},B_{2}\}=0. In other words, the observables of Bob2 have to be anticommuting to obtain the maximum quantum value of the Bell expression (2)Q(\mathcal{B}^{2})_{Q}. This, in turn, provides

ω~1=(2α12)2+(2α12+β12)β12{B1,B2}2=2α12,\displaystyle\tilde{\omega}_{1}=\sqrt{(2\alpha_{1}^{2})^{2}+(2\alpha_{1}^{2}+\beta_{1}^{2})\beta_{1}^{2}\{B_{1},B_{2}\}^{2}}=2\alpha_{1}^{2}, (18)

and ω~2=ω~1=2α12\tilde{\omega}_{2}=\tilde{\omega}_{1}=2\alpha_{1}^{2}. Note that the above result is obtained by considering that Bob1 and Bob2 perform the measurements on the same set of observables B1B_{1} and B2B_{2}. In Appendix A, we prove that to obtain the maximum quantum value (2)Q(\mathcal{B}^{2})_{Q} the choices of observables of Bob2 have to be the same as Bob1.

Using Eqs. (II) and (18), from Eq. (16) we can then write

(2)Q=2α12max(ω1+ω2)=2α12()Qopt.\displaystyle(\mathcal{B}^{2})_{Q}=2\alpha_{1}^{2}\ max\Big{(}\omega_{1}+\omega_{2}\Big{)}=2\alpha_{1}^{2}(\mathcal{B})_{Q}^{opt}.

Putting the value of α1\alpha_{1}, we write (2)Q(\mathcal{B}^{2})_{Q} in terms of unsharpness parameter λ1\lambda_{1} of Bob1 as

(2)Q=12(1+1λ12)()Qopt.(\mathcal{B}^{2})_{Q}=\dfrac{1}{2}\Big{(}1+\sqrt{1-\lambda_{1}^{2}}\Big{)}(\mathcal{B})_{Q}^{opt}. (19)

Hence, we have derived the maximum quantum values of Bell expressions for two sequential Bobs where ()Qopt(\mathcal{B})_{Q}^{opt} is common, but they differ by the coefficients, which are solely dependent only on λ1\lambda_{1}. Using Eq. (12), the quantum value of the CHSH expression (2)Q(\mathcal{B}^{2})_{Q} in Eq. (19) can be written in terms of (1)Q(\mathcal{B}^{1})_{Q} as

(2)Q=2(1+1((1)Q()Qopt)2).(\mathcal{B}^{2})_{Q}=\sqrt{2}\Big{(}1+\sqrt{1-\Bigg{(}\frac{(\mathcal{B}^{1})_{Q}}{(\mathcal{B})_{Q}^{opt}}\Bigg{)}^{2}}\Big{)}. (20)

This implies that if (1)Q(\mathcal{B}^{1})_{Q} increases, then (2)Q(\mathcal{B}^{2})_{Q} decreases, i.e., the more the Bob1 disturbs the system, the more he gains the information, and consequently the quantum value (2)Q(\mathcal{B}^{2})_{Q} of Bob2 decreases. Hence, there is a trade-off between (2)Q(\mathcal{B}^{2})_{Q} and (1)Q(\mathcal{B}^{1})_{Q}, which eventually form an optimal pair demonstrating the certification of unsharpness parameter.

Refer to caption
Figure 2: Optimal trade-off between quantum bound of CHSH inequality of Bob1 and Bob2 is shown by the solid blue curve while the shaded portion gives the suboptimal range. The solid green line is for classical bound of CHSH inequality for the same two observers.

In Figure 2, we plot the optimal trade-off characteristics between (1)Q(\mathcal{B}^{1})_{Q} and (2)Q(\mathcal{B}^{2})_{Q}. The green line corresponds to the maximum classical value of the CHSH expression where Bob2 can get a maximum value independent of Bob1, i.e., there is no trade-off in classical theory. The blue curve exhibits the trade-off between quantum values of (2)Q(\mathcal{B}^{2})_{Q} and (1)Q(\mathcal{B}^{1})_{Q} where each point on it certifies a unique value of unsharpness parameter λ1\lambda_{1}. For example, when (2)Q=(1)Q(\mathcal{B}^{2})_{Q}=(\mathcal{B}^{1})_{Q}, the value of λ1=4/5=0.80\lambda_{1}=4/5=0.80 is certified, as shown in the figure by brown dot.

Note that in our protocol we consider Alice always performs sharp measurements. Before making the self-testing statements of our protocol, let us examine whether our protocol certifies sharp measurements of Alice. As mentioned earlier that the blue curve in Figure 2 represents the optimal trade-off between (2)Q(\mathcal{B}^{2})_{Q} and (1)Q(\mathcal{B}^{1})_{Q}. If Alice performs unsharp measurement then the trade-off curve will always be below the blue curve. For instance, (2)Q=(1)Q=82/5(\mathcal{B}^{2})_{Q}=(\mathcal{B}^{1})_{Q}=8\sqrt{2}/5 (represented by the brown dot over the blue line) can never be reached unless Alice performs the sharp measurement of her anti-commuting observables. The same argument holds for any point over the blue curve in Figure 2. We are now in the position to make the DI self-testing statements of our protocol.

III.1 DI self-testing statements

The sub-optimal quantum values (1)Q(\mathcal{B}^{1})_{Q} and (2)Q(\mathcal{B}^{2})_{Q} form an optimal pair {(1)Q,(2)Q}\{(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q}\} that uniquely certifies the shared state between Alice and Bob1, the set of observables, and the unsharpness parameter λ1\lambda_{1}. The self-testing statements are the following,

(i) Alice performs sharp measurements of two mutually anticommuting observables on her local subsystem in any arbitrary local dimension.

(ii) Bob1 performs unsharp measurement corresponding to two observables which are also mutually anticommuting in any arbitrary local dimension. The set of observables for Bob1 and Bob2 are the same.

(iii) Alice and Bob1 share a maximally entangled state in any arbitrary dimension.

(iv) The optimal pair {(1)Q,(2)Q}\{(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q}\} self-tests the unsharpness parameter λ1\lambda_{1} which in turn certifies the shared entangled state between Alice, Bob1 and Bob2. In Figure 2, each point on the surface of blue curve certifies a unique value of unsharpness parameter λ1\lambda_{1}.

III.2 Robust certification of unsharpness parameter

Note, however, that the experimental implementation of any protocol inevitably introduces noise and imperfections. We provide an argument to demonstrate how our certification protocol is robust to the noise. In the real experimental scenario, the maximum values of CHSH expressions (2)Q(\mathcal{B}^{2})_{Q} and (1)Q(\mathcal{B}^{1})_{Q} may not be achieved, and hence unique certification of λ1\lambda_{1} may not be accurate. In such a case, we can certify the range within which λ1\lambda_{1} can belong.

The quantum advantage for Bob1 requires (1)Q>2(\mathcal{B}^{1})_{Q}>2, which fixes the (λ1)min=1/20.707(\lambda_{1})_{min}=1/\sqrt{2}\approx 0.707 as ()Qopt=22(\mathcal{B})_{Q}^{opt}=2\sqrt{2}. Thus, any value of λ1[1/2,1]\lambda_{1}\in[1/\sqrt{2},1] provides quantum advantage for Bob1. However, this range has to be further restricted if the nonlocality is extended to Bob2. To obtain advantage for Bob2, two sequential Bob requires (1)Q,(2)Q>2(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q}>2 and in turn necessitates λ2=1\lambda_{2}=1. From Eq. (19), we get

λ1<1(2(2)Q()Qopt1)2\displaystyle\lambda_{1}<\sqrt{1-\Bigg{(}\frac{2(\mathcal{B}^{2})_{Q}}{(\mathcal{B})_{Q}^{opt}}-1\Bigg{)}^{2}} (21)

which in turn fixes the upper bound of (λ1)max=2(21)0.912(\lambda_{1})_{max}=\sqrt{2(\sqrt{2}-1)}\approx 0.912. Hence, when both Bob1 and Bob2 get quantum advantage, the interval 0.707<λ1<0.9120.707<\lambda_{1}<0.912 is certified.

Now, as an example, let us consider an experiment in which we attempt to certify the desired value of λ1=0.74\lambda_{1}=0.74 corresponding to the optimal pair {(1)Q,(2)Q}\{(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q}\}. In such a scenario, we need the value of {(1)Q,(2)Q}{2.093,2.365}\{(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q}\}\approx\{2.093,2.365\}. However, due to imperfections, accurate quantum values may not be obtained. Instead, experimentalist gets {(1)Q,(2)Q}{2.05,2.34}\{(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q}\}\approx\{2.05,2.34\}. In such a case, we cannot obtain the desired value of λ1\lambda_{1} but will deduce a range of λ1\lambda_{1} within which it has to be confined. From Eqs. (12) and (21), we can calculate the range of λ1\lambda_{1} as 0.724<λ1<0.7550.724<\lambda_{1}<0.755. Thus, depending upon the observed quantum values, the range of λ1\lambda_{1} can be confined, i.e., the more perfect the experimental determination of {(1)Q,(2)Q}\{(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q}\}, the certified range of λ1\lambda_{1} becomes narrower.

III.3 Sharing of nonlocality by the third Bob

We examine whether the sharing of nonlocality can be extended to the third Bob (Bob3). If so, we can certify two unsharpness parameters. Also, the range of λ1\lambda_{1} can be made more restrictive if the third Bob can share the nonlocality. By using Eq. (9), the maximum quantum value of CHSH expression (3)Q=max(Tr[ρAB3()])(\mathcal{B}^{3})_{Q}=max(Tr[\rho_{AB_{3}}(\mathcal{B})]) between Alice and Bob3 can be calculated where ρAB3\rho_{AB_{3}} is the average state shared between Alice and Bob3. Then,

(3)Q\displaystyle(\mathcal{B}^{3})_{Q} =\displaystyle= max(Tr[(2α22ρAB2+β22y2=12(𝕀By2)ρAB2(𝕀By2))])\displaystyle max\left(Tr\left[\Big{(}2\alpha^{2}_{2}\rho_{AB_{2}}+\beta^{2}_{2}\sum_{y_{2}=1}^{2}(\mathbb{I}\otimes B_{y_{2}})\rho_{AB_{2}}(\mathbb{I}\otimes B_{y_{2}})\Big{)}\mathcal{B}\right]\right)

which can be re-written in a similar form as in Eq. (14), is given by

(3)Q=max(Tr[ρAB1((A1+A2)B~~1+(A1A)B~~2)]).\displaystyle(\mathcal{B}^{3})_{Q}=max\Bigg{(}Tr\Big{[}\rho_{AB_{1}}\Big{(}(A_{1}+A_{2})\tilde{\tilde{B}}_{1}+(A_{1}-A)\tilde{\tilde{B}}_{2}\Big{)}\Big{]}\Bigg{)}. (23)

Here, B~~1\tilde{\tilde{B}}_{1} and B~~2\tilde{\tilde{B}}_{2} represent effective observables of Bob3 are derived as

B~~i\displaystyle\tilde{\tilde{B}}_{i} =\displaystyle= (4α12α22+2β12β22)Bi+(2α22β12+2α12β22)(Bi+BjBiBj)\displaystyle(4\alpha^{2}_{1}\alpha_{2}^{2}+2\beta_{1}^{2}\beta_{2}^{2})B_{i}+(2\alpha_{2}^{2}\beta_{1}^{2}+2\alpha_{1}^{2}\beta_{2}^{2})(B_{i}+B_{j}B_{i}B_{j}) (24)
+\displaystyle+ β12β22(BjBiBj+BiBjBiBjBi)\displaystyle\beta_{1}^{2}\beta_{2}^{2}(B_{j}B_{i}B_{j}+B_{i}B_{j}B_{i}B_{j}B_{i})

with i(j)ij{1,2}i(j)_{i\neq j}\in\{1,2\}. Again (B~~i)2𝕀(\tilde{\tilde{B}}_{i})^{2}\neq\mathbb{I} and hence B~~i\tilde{\tilde{B}}_{i}’s need to be properly normalized. Following the earlier argument, we can use the aforesaid SOS approach to obtain the optimal value of (3)Q(\mathcal{B}^{3})_{Q}. By considering ω~~1=B~~1\tilde{\tilde{\omega}}_{1}=||\tilde{\tilde{B}}_{1}|| and ω~~2=B~~2\tilde{\tilde{\omega}}_{2}=||\tilde{\tilde{B}}_{2}||, and by using the SOS approach we obtain

(3)Q=max(ω1ω~~1+ω2ω~~2).\displaystyle(\mathcal{B}^{3})_{Q}=max\left(\omega_{1}\tilde{\tilde{\omega}}_{1}+\omega_{2}\tilde{\tilde{\omega}}_{2}\right). (25)

Note that, to obtain the maximum quantum value, B~~1\tilde{\tilde{B}}_{1} and B~~2\tilde{\tilde{B}}_{2} have to be mutually anticommuting, i.e.,

{B~~1,B~~2}=(8(4α12α24β12+2α14(α24+2α22β12)3β14β14)){B1,B2}\displaystyle\{\tilde{\tilde{B}}_{1},\tilde{\tilde{B}}_{2}\}=\Big{(}8(4\alpha^{2}_{1}\alpha^{4}_{2}\beta^{2}_{1}+2\alpha^{4}_{1}(\alpha^{4}_{2}+2\alpha^{2}_{2}\beta^{2}_{1})-3\beta^{4}_{1}\beta^{4}_{1})\Big{)}\{B_{1},B_{2}\}
+\displaystyle+ (4(α24β14+2α22β12(2α12+β12)β22+α12(α12+2β12)β24)){B1,B2}3\displaystyle\Big{(}4(\alpha_{2}^{4}\beta_{1}^{4}+2\alpha_{2}^{2}\beta_{1}^{2}(2\alpha_{1}^{2}+\beta_{1}^{2})\beta_{2}^{2}+\alpha_{1}^{2}(\alpha_{1}^{2}+2\beta_{1}^{2})\beta_{2}^{4})\Big{)}\{B_{1},B_{2}\}^{3}
+\displaystyle+ (β12β22)2{B1,B2}5=0\displaystyle(\beta_{1}^{2}\beta_{2}^{2})^{2}\{B_{1},B_{2}\}^{5}=0

which provides {B1,B2}=0\{B_{1},B_{2}\}=0. Then, Bob3 also requires the anticommuting observables to obtain the maximum quantum value. We then calculate

ω~~1\displaystyle\tilde{\tilde{\omega}}_{1} =\displaystyle= (16α14α24+(4α24β14+2α12α22β12(α22+2β22)+α14(2α22β22+β24))\displaystyle\Bigg{(}16\alpha^{4}_{1}\alpha_{2}^{4}+\Big{(}4\alpha_{2}^{4}\beta_{1}^{4}+2\alpha_{1}^{2}\alpha_{2}^{2}\beta_{1}^{2}(\alpha_{2}^{2}+2\beta_{2}^{2})+\alpha^{4}_{1}(2\alpha_{2}^{2}\beta_{2}^{2}+\beta_{2}^{4})\Big{)} (26)
{B1,B2}2+(2α22β14β22+β12(2α12+β12)β24){B1,B2}4)1/2.\displaystyle\{B_{1},B_{2}\}^{2}+\Big{(}2\alpha_{2}^{2}\beta_{1}^{4}\beta_{2}^{2}+\beta_{1}^{2}(2\alpha_{1}^{2}+\beta_{1}^{2})\beta_{2}^{4}\Big{)}\{B_{1},B_{2}\}^{4}\Bigg{)}^{1/2}.

Since, {B1,B2}=0\{B_{1},B_{2}\}=0, we obtain ω~~1=4α12α22\tilde{\tilde{\omega}}_{1}=4\alpha^{2}_{1}\alpha_{2}^{2}, and similarly we find ω~~2=ω~~1=4α12α22\tilde{\tilde{\omega}}_{2}=\tilde{\tilde{\omega}}_{1}=4\alpha^{2}_{1}\alpha_{2}^{2}.

Then, the maximum quantum value (3)Q(\mathcal{B}^{3})_{Q} in Eq. (25) becomes

(3)Q=4α12α22max(ω1+ω2)=4α12α22()Qopt.\displaystyle(\mathcal{B}^{3})_{Q}=4\alpha^{2}_{1}\alpha_{2}^{2}\ max\Big{(}\omega_{1}+\omega_{2}\Big{)}=4\alpha^{2}_{1}\alpha_{2}^{2}(\mathcal{B})_{Q}^{opt}.

Putting the values of α1\alpha_{1} and α2\alpha_{2}, we write (3)Q(\mathcal{B}^{3})_{Q} in terms of unsharpness parameters of Bob1 and Bob2 as

(3)Q=14(1+1λ12)(1+1λ22)()Qopt.(\mathcal{B}^{3})_{Q}=\dfrac{1}{4}\Big{(}1+\sqrt{1-\lambda_{1}^{2}}\Big{)}\Big{(}1+\sqrt{1-\lambda_{2}^{2}}\Big{)}(\mathcal{B})_{Q}^{opt}. (27)

Now, to exhibit the quantum violation for three sequential Bobs, we have to show that (1)Q,(2)Q,(3)Q>2(\mathcal{B}^{1})_{Q},(\mathcal{B}^{2})_{Q},(\mathcal{B}^{3})_{Q}>2. For (1)Q>2(\mathcal{B}^{1})_{Q}>2, the lower bound on λ1\lambda_{1} is λ1>1/2\lambda_{1}>1/\sqrt{2}. From Eq. (19), we can calculate the lower bound of λ2\lambda_{2} for (2)Q>2(\mathcal{B}^{2})_{Q}>2 is

λ2>4()Qopt(1+1(2()Qopt)2=22+10.828.\displaystyle\lambda_{2}>\frac{4}{(\mathcal{B})_{Q}^{opt}\Big{(}1+\sqrt{1-\Big{(}\frac{2}{(\mathcal{B})_{Q}^{opt}}}\Big{)}^{2}}=\dfrac{2}{\sqrt{2}+1}\approx 0.828. (28)

By considering that Bob1 and Bob2 implement their unsharp measurements with minimum required values of unsharpness parameters at their respective sites, and by substituting the values of (λ1)min0.707(\lambda_{1})_{min}\approx 0.707 and (λ2)min0.828(\lambda_{2})_{min}\approx 0.828 in Eq. (27), we get (3)Q=1.89(\mathcal{B}^{3})_{Q}=1.89. This means Alice and Bob3 cannot violate CHSH inequality when both Bob1 and Bob2 violate it.

IV Elegant Bell inequality and its local and preparation non-contextual bounds

We extend the sequential sharing of nonlocality by using another well-known Bell inequality known as Gisin’s elegant Bell inequality [47]. The elegant Bell expression can be written as,

𝔼\displaystyle\mathbb{E} =\displaystyle= (A1+A2+A3A4)B1+(A1+A2A3\displaystyle(A_{1}+A_{2}+A_{3}-A_{4})\otimes B_{1}+(A_{1}+A_{2}-A_{3} (29)
+\displaystyle+ A4)B2+(A1A2+A3+A4)B3.\displaystyle A_{4})\otimes B_{2}+(A_{1}-A_{2}+A_{3}+A_{4})\otimes B_{3}.

whose local bound is (𝔼)l6(\mathbb{E})_{l}\leq 6. We show that the elegant Bell expression has two bounds, the local bound (which can be considered as trivial preparation non-contextual bound) and a nontrivial preparation non-contextual bound when there exists a relational constraint between the observables of Alice and Bob. We show that the non-trivial preparation non-contextual bound (𝔼)pnc4(\mathbb{E})_{pnc}\leq 4.

Before proceeding further, we briefly introduce the notion of preparation non-contextuality in an ontological model of quantum theory. Consider that a preparation procedure PP prepares a density matrix ρ\rho, and a measurement procedure MM realizes the measurement of a POVM EkE_{k}. Quantum theory predicts the probability of obtaining a particular outcome kk is p(k|P,M)=Tr[ρEk]p(k|P,M)=Tr[\rho E_{k}] - the Born rule. In an ontological model of quantum theory, preparation procedures assign a probability distribution μP(λ|ρ)\mu_{P}(\lambda|\rho) on ontic states λΛ\lambda\in\Lambda where Λ\Lambda is the ontic state space. Given the measurement procedure, the ontic state λ\lambda assigns a response function ξM(k|λ,Ek)\xi_{M}(k|\lambda,E_{k}). A viable ontological model must reproduce the Born rule, i.e., k,ρ,Ek:p(k|P,M)=ΛμP(λ|ρ)ξM(k|λ,Ek)dλ\forall k,\rho,E_{k}:\ \ p(k|P,M)=\int_{\Lambda}\mu_{P}(\lambda|\rho)\xi_{M}(k|\lambda,E_{k})d\lambda.

The dependencies of PP and MM do not appear if the ontological model is preparation and measurement non-contextual, respectively. Two preparation procedures PP and PP^{\prime} are said to be operationally equivalent if they can not be distinguished by any measurement, implying, k,M:p(k|P,M)=p(k|P,M)\forall k,M:\hskip 2.84544ptp(k|P,M)=p(k|P^{\prime},M). In quantum theory, such preparation procedures are realized by the density matrix ρ\rho. Such equivalence in operational theory can be reflected in the ontic state level, assuming preparation non-contextuality [69]. An ontological model of an operational quantum theory is considered to be preparation non-contextual if two preparation procedures PP and PP^{\prime} prepare the same density matrix ρ\rho, and no measurement can operationally distinguish the context by which ρ\rho is prepared, i.e., k,M:p(k|P,M)=p(k|P,M)λ:μ(λ|ρ,P)=μ(λ|ρ,P)\forall k,M:\hskip 2.84544ptp(k|P,M)=p(k|P^{\prime},M)\Rightarrow\forall\lambda:\mu(\lambda|\rho,P)=\mu(\lambda|\rho,P^{\prime}), implying two ontic state distributions are equivalent irrespective of the contexts PP and PP^{\prime} [69, 70, 71, 72, 73].

Let us intuitively understand the notion of preparation non-contextuality in the CHSH scenario. Consider that Alice and Bob share an entangled state ρAB\rho_{AB} and Alice measures A1A_{1} and A2A_{2}. Alice’s measurements on her local system produces density matrices ρA1\rho_{A_{1}} and ρA2\rho_{A_{2}} on Bob’s side corresponding to measurement contexts A1A_{1} and A2A_{2}, respectively. The non-signaling condition demands that ρA1\rho_{A_{1}} and ρA2\rho_{A_{2}} cannot be distinguishable by any measurement of Bob, i.e., ρA1=ρA2σ\rho_{A_{1}}=\rho_{A_{2}}\equiv\sigma. Equivalently, in an ontological model we assume that μ(λ|σ,A1)=μ(λ|σ,A2)\mu(\lambda|\sigma,A_{1})=\mu(\lambda|\sigma,A_{2}), i.e., the distribution of ontic states are preparation non-contextual. Intuitively, preparation non-contextuality implies the locality assumption in the Bell scenario. In other words, every probability distribution that violates a Bell inequality can also be regarded as proof of preparation contextuality as proved in [74]. Here, we provide a modified version of the proof.

For this, by using Bayes’ theorem we write the joint probability distribution in the ontological model as

p(a,b|Ai,Bj)=λp(a|Ai,Bj)p(λ|a,Ai)p(b|Bj,λ).p(a,b|A_{i},B_{j})=\sum_{\lambda}p(a|A_{i},B_{j})p(\lambda|a,A_{i})p(b|B_{j},\lambda). (30)

Now, the no-signaling condition implies the marginal probability of Alice’s side is independent of Bob’s input and hence we can write

p(a,b|Ai,Bj)=λp(a|Ai)p(λ|a,Ai)p(b|Bj,λ).p(a,b|A_{i},B_{j})=\sum_{\lambda}p(a|A_{i})p(\lambda|a,A_{i})p(b|B_{j},\lambda). (31)

Using Bayes’ theorem we can write p(a|Ai)p(λ|a,Ai)=μ(λ|Ai)p(a|λ,Ai)p(a|A_{i})p(\lambda|a,A_{i})=\mu(\lambda|A_{i})p(a|\lambda,A_{i}) where we specifically denoted the probability distribution p(λ|Ai)p(\lambda|A_{i}) as μ(λ|Ai)\mu(\lambda|A_{i}).

From Eq. (31), we then obtain

p(a,b|Ai,Bj)=λμ(λ|Ai)p(a|λ,Ai)p(b|Bj,λ).p(a,b|A_{i},B_{j})=\sum_{\lambda}\mu(\lambda|A_{i})p(a|\lambda,A_{i})p(b|B_{j},\lambda). (32)

Due to the assignment of the same ontic-state distribution for the different preparation procedures on Bob’s side, the assumption of preparation non-contextuality is enforced. Then the preparation non-contextual assumption for Bob’s preparation reads as μ(λ|ρ,A1)=μ(λ|ρ,A2)μ(λ)\mu(\lambda|\rho,{A_{1}})=\mu(\lambda|\rho,{A_{2}})\equiv\mu(\lambda), which in turn provides

p(a,b|Ai,Bj)=λμ(λ)p(a|λ,Ai)p(b|λ,Bj).p(a,b|A_{i},B_{j})=\sum_{\lambda}\mu(\lambda)p(a|\lambda,A_{i})p(b|\lambda,B_{j}). (33)

which is the desired factorizability condition commonly derived for a local hidden variable model. Therefore, we can argue that whenever in an ontological model p(a,b|Ai,Bj)p(a,b|A_{i},B_{j}) satisfies preparation non-contextuality, this, in turn, satisfies locality in a hidden variable model.

Here we go one step further. The above case involving the CHSH scenario is a trivial one. We introduce a nontrivial form of preparation non-contextuality in the Bell experiment involving more than two inputs. Consider a Bell experiment where Alice receives four inputs and performs the measurements of four observables A1A_{1}, A2A_{2}, A3A_{3} and A4A_{4}. Bob receives three inputs and performs the measurement of three observables B1B_{1} , B2B_{2} and B3B_{3}. In quantum theory, when Alice and Bob share an entangled state ρAB\rho_{AB}

ρa|Ai+ρa1|Ai=ρa|Ai+ρa1|Aiσ\displaystyle\rho_{a|A_{i}}+\rho_{a\oplus 1|A_{i}}=\rho_{a|A_{i^{\prime}}}+\rho_{a\oplus 1|A_{i^{\prime}}}\equiv\sigma (34)

where i,i=1,2,3,4i,i^{\prime}=1,2,3,4 with iii\neq i^{\prime}, and ρa|Ai=TrA[ρABΠAi𝕀]\rho_{a|A_{i}}=Tr_{A}\left[\rho_{AB}\Pi_{A_{i}}\otimes\mathbb{I}\right]. This is within the premise of preparation non-contextuality in an ontological model as the distribution of ontic states is assumed to be equivalent for those two preparation procedures ii and ii^{\prime}. As argued above, such a trivial preparation non-contextuality can be attributed to the locality in a Bell experiment. In that case, the local bound of the elegant Bell expression (𝔼)l6(\mathbb{E})_{l}\leq 6.

We introduce a nontrivial form of preparation non-contextuality in an ontological model of quantum theory by imposing an additional relational constraint on Alice’s measurement observables. For this, we consider that the joint probability satisfies

b,j,\displaystyle\forall b,j,\ P(a,b|A1,Bj)+i=24P(a1,b|Ai,Bj)\displaystyle P(a,b|A_{1},B_{j})+\sum\limits_{i=2}^{4}P(a\oplus 1,b|A_{i},B_{j})
=\displaystyle= P(a1,b|A1,Bj)+i=24P(a,b|Ai,Bj)\displaystyle P(a\oplus 1,b|A_{1},B_{j})+\sum\limits_{i=2}^{4}P(a,b|A_{i},B_{j})

which in quantum theory implies that

ρa1|A1+ρa|A2+ρa|A3+ρa|A4\displaystyle\rho_{a\oplus 1|A_{1}}+\rho_{a|A_{2}}+\rho_{a|A_{3}}+\rho_{a|A_{4}} (36)
=\displaystyle= ρa|A1+ρa1|A2+ρa1|A3+ρa1|A4\displaystyle\rho_{a|A_{1}}+\rho_{a\oplus 1|A_{2}}+\rho_{a\oplus 1|A_{3}}+\rho_{a\oplus 1|A_{4}}

Since ρa|Ai=TrA[ρABΠAi𝕀]\rho_{a|A_{i}}=Tr_{A}\left[\rho_{AB}\Pi_{A_{i}}\otimes\mathbb{I}\right] with ΠAi=(𝕀+Ai)/2\Pi_{A_{i}}=\left(\mathbb{I}+A_{i}\right)/2, the above Eq. (36) implies that A1A2A3A4=0A_{1}-A_{2}-A_{3}-A_{4}=0. Along with the equivalence in Eq. (34) a non-trivial constraint Eq. (36) is also imposed on Alice’s preparation procedures. In such a case, the local bound reduces to the preparation non-contextual bound (𝔼)l4(\mathbb{E})_{l}\leq 4 as A1=A2+A3+A4A_{1}=A_{2}+A_{3}+A_{4}. Thus, the quantum violation of it provides a weaker notion of nonlocality, which we call nontrivial preparation contextuality. It is well-known that steering is a weaker form of nonlocality, but the relation between steering and nontrivial preparation contextuality needs to be properly explored. While we plan to do it in another occasion, interested reader may see a relevant work [74]. However, for our present purpose it is not directly relevant and hence we skip such discussion.

Note that the quantum value of (𝔼)Q(\mathbb{E})_{Q} has also to be calculated by considering this constraint. Below we show that the optimal quantum value (𝔼)Qopt=43(\mathbb{E})_{Q}^{opt}=4\sqrt{3} satisfies the constraint A1=A2+A3+A4A_{1}=A_{2}+A_{3}+A_{4}.

V Sharing preparation contextuality and certification of multiple unsharpness parameters

We derive the optimal quantum value (𝔼)Qopt(\mathbb{E})_{Q}^{opt} without using the dimension of the system. For this, we again use the SOS approach developed in Sec. II. We define a positive semidefinite operator χQ0\langle\chi\rangle_{Q}\geq 0 so that χQ+𝔼=Ω3\langle\chi\rangle_{Q}+\mathbb{E}=\Omega_{3} where Ω3\Omega_{3} is a positive quantity. By considering suitable positive operators L1L_{1}, L2L_{2} and L3L_{3} we can write

χ=12(ω1L1L1+ω2L2L2+ω3L3L3)\displaystyle\chi=\frac{1}{2}\left(\omega_{1}L_{1}^{\dagger}L_{1}+\omega_{2}L_{2}^{\dagger}L_{2}+\omega_{3}L_{3}^{\dagger}L_{3}\right) (37)

where ω1\omega_{1}, ω2\omega_{2} and ω3\omega_{3} are positive numbers that will be determined soon. For our purpose, we choose

L1|ψAB=A1+A2+A3A4ω1|ψABB1|ψAB\displaystyle L_{1}|\psi\rangle_{AB}=\frac{A_{1}+A_{2}+A_{3}-A_{4}}{\omega_{1}}|\psi\rangle_{AB}-B_{1}|\psi\rangle_{AB}
L2|ψAB=A1+A2A3+A4ω2|ψABB2|ψAB\displaystyle L_{2}|\psi\rangle_{AB}=\frac{A_{1}+A_{2}-A_{3}+A_{4}}{\omega_{2}}|\psi\rangle_{AB}-B_{2}|\psi\rangle_{AB} (38)
L3|ψAB=A1A2+A3+A4ω3|ψABB3|ψAB\displaystyle L_{3}|\psi\rangle_{AB}=\frac{A_{1}-A_{2}+A_{3}+A_{4}}{\omega_{3}}|\psi\rangle_{AB}-B_{3}|\psi\rangle_{AB}

where ω1=(A1+A2+A3A4)|ψAB2,ω2=(A1+A2A3+A4)|ψAB2\omega_{1}=||(A_{1}+A_{2}+A_{3}-A_{4})|\psi\rangle_{AB}||_{2},\omega_{2}=||(A_{1}+A_{2}-A_{3}+A_{4})|\psi\rangle_{AB}||_{2} and ω3=(A1A2+A3+A4)|ψAB2\omega_{3}=||(A_{1}-A_{2}+A_{3}+A_{4})|\psi\rangle_{AB}||_{2}. Substituting Eq. (V) in Eq. (37), we get

χQ=(𝔼)Q+i=13ωi.\langle\chi\rangle_{Q}=-(\mathbb{E})_{Q}+\sum_{i=1}^{3}\omega_{i}. (39)

Hence, the optimal value (𝔼)Qopt(\mathbb{E})_{Q}^{opt} is obtained if χQ=0\langle\chi\rangle_{Q}=0, i.e.,

(𝔼)Qopt=max(ω1+ω2+ω3)(\mathbb{E})_{Q}^{opt}=max(\omega_{1}+\omega_{2}+\omega_{3}) (40)

where

ω1=4+{A1,(A2+A3A4)}+{A2,(A3A4)}{A3,A4}\displaystyle\omega_{1}=\sqrt{4+\langle\{A_{1},(A_{2}+A_{3}-A_{4})\}+\{A_{2},(A_{3}-A_{4})\}-\{A_{3},A_{4}\}\rangle}

and similarly for ω2\omega_{2} and ω3\omega_{3}.

We use the concavity inequality i=1nωini=1n(ωi)2\sum_{i=1}^{n}\omega_{i}\leq\sqrt{n\sum_{i=1}^{n}(\omega_{i})^{2}} where the equality holds when ωi\omega_{i}’s are equal to each other. We can then write

(𝔼)Qmax(3(ω12+ω22+ω32)).(\mathbb{E})_{Q}\leq max\Big{(}\sqrt{3(\omega_{1}^{2}+\omega_{2}^{2}+\omega_{3}^{2})}\Big{)}. (42)

Now, by using the expressions of ω1\omega_{1}, ω2\omega_{2} and ω3\omega_{3} we can write

ω12+ω22+ω32=ψ|AB(12+δ)|ψAB\displaystyle\omega_{1}^{2}+\omega_{2}^{2}+\omega_{3}^{2}={{}_{AB}\bra{\psi}}(12+\delta)\ket{\psi}_{AB} (43)

where

δ=({A1,(A2+A3+A4)}{A2,(A3+A4)}{A3,A4}).\displaystyle\delta=(\{A_{1},(A_{2}+A_{3}+A_{4})\}-\{A_{2},(A_{3}+A_{4})\}-\{A_{3},A_{4}\}).

To maximize δ\delta, we consider that there exist a state |ψ\ket{\psi^{\prime}} which can be written as |ψ=(A1A2A3A4)|ψAB\ket{\psi^{\prime}}=(A_{1}-A_{2}-A_{3}-A_{4})\ket{\psi}_{AB} such that |ψAB0\ket{\psi}_{AB}\neq 0. We can show that ψ|ψ=4δ\langle{\psi^{\prime}}|{\psi^{\prime}}\rangle=4-\langle\delta\rangle. By rearranging we can write δ=4ψ|ψ\langle\delta\rangle=4-\langle{\psi^{\prime}}|{\psi^{\prime}}\rangle. Clearly, the maximum value δmax=4\langle\delta\rangle_{max}=4 is obtained when ψ|ψ=0\langle{\psi^{\prime}}|{\psi^{\prime}}\rangle=0. Since, |ψAB0\ket{\psi}_{AB}\neq 0, we find the condition of maximization

A1A2A3A4=0.\displaystyle A_{1}-A_{2}-A_{3}-A_{4}=0. (45)

Since, δmax=4\langle\delta\rangle_{max}=4, we find max(ω12+ω22+ω32)=16max(\omega_{1}^{2}+\omega_{2}^{2}+\omega_{3}^{2})=16. From Eq. (42) we can then write (𝔼)Q43(\mathbb{E})_{Q}\leq 4\sqrt{3}.

Using Eq. (45), a few steps of calculations gives the following relations that need to be satisfied by Alice’s observables given by

{A1,A2}={A1,A3}={A1,A4}=23,\displaystyle\{A_{1},A_{2}\}=\{A_{1},A_{3}\}=\{A_{1},A_{4}\}=\frac{2}{3}, (46)
{A2,A3}={A2,A4}={A3,A4}=23.\displaystyle\{A_{2},A_{3}\}=\{A_{2},A_{4}\}=\{A_{3},A_{4}\}=-\frac{2}{3}. (47)

Putting Eqs. (46) and (47) in Eq. (V), we get ω1=4/3\omega_{1}=4/\sqrt{3}. A similar calculation gives us ω2=ω3=4/3\omega_{2}=\omega_{3}=4/\sqrt{3}. Since, ω1=ω2=ω3\omega_{1}=\omega_{2}=\omega_{3}, the optimal quantum value of elegant Bell expression is (𝔼)Qopt=43(\mathbb{E})_{Q}^{opt}=4\sqrt{3}. Note here again that we have not imposed any bound on the dimension of the system throughout the derivation.

As mentioned, the optimal quantum value of 𝔼\mathbb{E} for any given dimension is obtained when χQ=0\langle\chi\rangle_{Q}=0, implying that

i[3],Li|ψAB=0.\displaystyle\forall i\in[3],\ L_{i}\ket{\psi}_{AB}=0. (48)

Further, using the conditions in Eq. (V), Bobs observables B1B_{1}, B2B_{2}, and B3B_{3} can be written as

B1\displaystyle B_{1} =\displaystyle= 3(A1+A2+A3A4)4,\displaystyle\frac{\sqrt{3}(A_{1}+A_{2}+A_{3}-A_{4})}{4},
B2\displaystyle B_{2} =\displaystyle= 3(A1+A2A3+A4)4,\displaystyle\frac{\sqrt{3}(A_{1}+A_{2}-A_{3}+A_{4})}{4},
B3\displaystyle B_{3} =\displaystyle= 3(A1A2+A3+A4)4.\displaystyle\frac{\sqrt{3}(A_{1}-A_{2}+A_{3}+A_{4})}{4}. (49)

It is straightforward to show that Bob’s observables satisfy,

{B1,B2}\displaystyle\{B_{1},B_{2}\} =\displaystyle= 34{(A1+A2+A3A4),(A1+A2A3+A4)}\displaystyle\frac{\sqrt{3}}{4}\{(A_{1}+A_{2}+A_{3}-A_{4}),(A_{1}+A_{2}-A_{3}+A_{4})\} (50)
=\displaystyle= 34({A1,A2}+{A3,A4}).\displaystyle\frac{\sqrt{3}}{4}\Big{(}\{A_{1},A_{2}\}+\{A_{3},A_{4}\}\Big{)}.

Putting the values of Alice’s anticommuting relations from Eqs. (46) and (47), we get {B1,B2}=0\{B_{1},B_{2}\}=0. Similarly, it can also be shown that {B1,B3}=0\{B_{1},B_{3}\}=0 or {B2,B3}=0\{B_{2},B_{3}\}=0. Thus, Bobs observables B1,B2B_{1},B_{2} and B3B_{3} have to be mutually anticommuting to obtain the optimal quantum value (𝔼)Qopt=43(\mathbb{E})_{Q}^{opt}=4\sqrt{3}. Following the argument developed for CHSH, it can be proved that the shared state between Alice and Bob has to be a maximally entangled state as in Eq. (7).

V.1 Certification of multiple unsharpness parameters

Similar to the sequential CHSH scenario, for elegant Bell inequality, the average state shared between Alice and Bobk if Alice and Bob(k-1) shares a maximally entangled state and each Bob performs a dichotomic POVM measurement in the sequential scheme is

ρABk=13bk±yk=13Kbk|ykρAB(k1)Kbk|yk\displaystyle\rho_{AB_{k}}=\frac{1}{3}\sum_{b_{k}\in\pm}\sum_{y_{k}=1}^{3}K_{b_{k}|y_{k}}\rho_{AB_{(k-1)}}K_{b_{k}|y_{k}} (51)

where {Kbk|yk}\{K_{b_{k}|y_{k}}\} are the Kraus operators satisfying bkKbk|yKbk|yk=𝕀\sum_{b_{k}}K_{b_{k}|y}^{\dagger}K_{b_{k}|y_{k}}=\mathbb{I} and Kbk|yk=Ebk|ykK_{b_{k}|y_{k}}=\sqrt{E_{b_{k}|y_{k}}}.

The quantum value of elegant Bell expression due to the unsharp measurement of Bob1 irrespective of the dimension is calculated as

(𝔼1)Q=λ1(𝔼)Qopt.\displaystyle(\mathbb{E}^{1})_{Q}=\lambda_{1}(\mathbb{E})_{Q}^{opt}. (52)

Let us assume that every sequential Bob measures same set of observables B1B_{1}, B2B_{2} and B3B_{3} i.e., k,Byk=1B1\forall k,\ B_{y_{k}=1}\equiv B_{1} and so on. The average post-measurement state after Bob1’s unsharp measurement can be written as

ρAB2\displaystyle\rho_{AB_{2}} =\displaystyle= 13b1{+,}y1=13(𝕀Kb1|y1)ρAB1(𝕀Kb1|y1)\displaystyle\dfrac{1}{3}\sum_{b_{1}\in\{+,-\}}\sum_{y_{1}=1}^{3}\left(\mathbb{I}\otimes K_{b_{1}|y_{1}}\right)\rho_{AB_{1}}\left(\mathbb{I}\otimes K_{b_{1}|y_{1}}\right) (53)
=\displaystyle= 13[6α12ρAB1+2β12y1=13(𝕀By1)ρAB1(𝕀By1)].\displaystyle\dfrac{1}{3}\Big{[}6\alpha^{2}_{1}\rho_{AB_{1}}+2\beta^{2}_{1}\sum_{y_{1}=1}^{3}(\mathbb{I}\otimes B_{y_{1}})\rho_{AB_{1}}(\mathbb{I}\otimes B_{y_{1}})\Big{]}.

Using ρAB2\rho_{AB_{2}} in Eq. (53), the maximum quantum value of elegant Bell expression between Alice and Bob2 is given by

(𝔼2)Q\displaystyle(\mathbb{E}^{2})_{Q} =\displaystyle= max(Tr[ρAB2𝔼])\displaystyle max\Big{(}Tr[\rho_{AB_{2}}\mathbb{E}]\Big{)} (54)
=\displaystyle= max(Tr[ρAB1((A1+A2+A3A4)B1+(A1+A2\displaystyle max\Big{(}Tr\Big{[}\rho_{AB_{1}}\Big{(}(A_{1}+A_{2}+A_{3}-A_{4})B_{1}^{\prime}+(A_{1}+A_{2}
\displaystyle- A3+A4)B2+(A1A2+A3+A4)B3)]).\displaystyle A_{3}+A_{4})B_{2}^{\prime}+(A_{1}-A_{2}+A_{3}+A_{4})B_{3}^{\prime}\Big{)}\Big{]}\Big{)}.

We derive B1B_{1}^{\prime}, B2B_{2}^{\prime} and B3B_{3}^{\prime} as

B1\displaystyle B_{1}^{\prime} =\displaystyle= 2(α12+β123)B1+23β12(B2B1B2+B3B1B3),\displaystyle 2(\alpha_{1}^{2}+\frac{\beta_{1}^{2}}{3})B_{1}+\frac{2}{3}\beta_{1}^{2}(B_{2}B_{1}B_{2}+B_{3}B_{1}B_{3}),
B2\displaystyle B_{2}^{\prime} =\displaystyle= 2(α12+β123)B2+23β12(B1B2B1+B3B2B3),\displaystyle 2(\alpha_{1}^{2}+\frac{\beta_{1}^{2}}{3})B_{2}+\frac{2}{3}\beta_{1}^{2}(B_{1}B_{2}B_{1}+B_{3}B_{2}B_{3}), (55)
B3\displaystyle B_{3}^{\prime} =\displaystyle= 2(α12+β123)B3+23β12(B1B3B1+B2B3B2).\displaystyle 2(\alpha_{1}^{2}+\frac{\beta_{1}^{2}}{3})B_{3}+\frac{2}{3}\beta_{1}^{2}(B_{1}B_{3}B_{1}+B_{2}B_{3}B_{2}).

Eq. (LABEL:ebi2) has a complete resemblance with elegant Bell inequality in Eq. (29) with the effective observables of Bob are B1B_{1}^{\prime}, B2B_{2}^{\prime} and B3B_{3}^{\prime}. However, (Bi)2𝕀(B_{i}^{\prime})^{2}\neq\mathbb{I} with i[3]i\in[3] and hence they need to be normalized. By assuming, ωi=Bi\omega_{i}^{\prime}=||B_{i}^{\prime}|| and using the SOS approach we get

(𝔼2)Q=max(ω1ω1+ω2ω2+ω3ω3).\displaystyle(\mathbb{E}^{2})_{Q}=max\left(\omega_{1}\omega_{1}^{\prime}+\omega_{2}\omega_{2}^{\prime}+\omega_{3}\omega_{3}^{\prime}\right). (56)

Optimization of quantum value of (𝔼2)Q(\mathbb{E}^{2})_{Q} demands Bob’s observables B1B_{1}^{\prime}, B2B_{2}^{\prime} and B3B_{3}^{\prime} have to be mutually anticommuting. It is explicitly shown in Appendix B that the anticommutation {Bi,Bj}\{B_{i}^{\prime},B_{j}^{\prime}\} can be written in terms of {Bi,Bj}\{B_{i},B_{j}\} where i(j)1,2,3i(j)\in 1,2,3 with iji\neq j. It is proved that {Bi,Bj}=0\{B_{i}^{\prime},B_{j}^{\prime}\}=0 implying {Bi,Bj}=0\{B_{i},B_{j}\}=0 as the parameters α1\alpha_{1} and β1\beta_{1} are positive.

In other words, Bob2 also requires the anticommuting observables to obtain the maximum quantum value of (𝔼2)Q(\mathbb{E}^{2})_{Q}. We then calculate

ω1\displaystyle\omega_{1}^{\prime} =\displaystyle= ((2α12+23β12)2+(23β12)2(4+B2{B1,B2}B3{B1,B3}\displaystyle\Bigg{(}(2\alpha_{1}^{2}+\frac{2}{3}\beta_{1}^{2})^{2}+(\frac{2}{3}\beta_{1}^{2})^{2}\Big{(}4+B_{2}\{B_{1},B_{2}\}B_{3}\{B_{1},B_{3}\} (57)
\displaystyle- B2{B1,B2}B1B1B3{B1,B3}+B3{B1,B3}B2{B1,B2}\displaystyle B_{2}\{B_{1},B_{2}\}B_{1}-B_{1}B_{3}\{B_{1},B_{3}\}+B_{3}\{B_{1},B_{3}\}B_{2}\{B_{1},B_{2}\}
\displaystyle- B3{B1B3}B1B1B2{B1,B2})+(2α12+23β12)23β12\displaystyle B_{3}\{B_{1}B_{3}\}B_{1}-B_{1}B_{2}\{B_{1},B_{2}\}\Big{)}+(2\alpha_{1}^{2}+\frac{2}{3}\beta_{1}^{2})\frac{2}{3}\beta_{1}^{2}
({B1,B2}2+{B1,B3}24))1/2.\displaystyle\Big{(}\{B_{1},B_{2}\}^{2}+\{B_{1},B_{3}\}^{2}-4\Big{)}\Bigg{)}^{1/2}.

Using {Bi,Bj}=0\{B_{i},B_{j}\}=0, we get ω1=2(α12β123)\omega_{1}^{\prime}=2(\alpha_{1}^{2}-\frac{\beta_{1}^{2}}{3}). Similarly, we find ω2=ω3=ω1\omega_{2}^{\prime}=\omega_{3}^{\prime}=\omega_{1}^{\prime}.

Putting the values of ω1\omega_{1}^{\prime}, ω2\omega_{2}^{\prime} and ω3\omega_{3}^{\prime}, the maximum quantum value of the elegant Bell expression (𝔼2)Q(\mathbb{E}^{2})_{Q} can be obtained from Eq. (56) as

(𝔼2)Q\displaystyle(\mathbb{E}^{2})_{Q} =\displaystyle= 2(α12β123)(𝔼)Qopt.\displaystyle 2(\alpha_{1}^{2}-\frac{\beta_{1}^{2}}{3})(\mathbb{E})_{Q}^{opt}.

By inserting the values of α1\alpha_{1} and β1\beta_{1}, we have (𝔼2)Q(\mathbb{E}^{2})_{Q} in terms of unsharpness parameter as

(𝔼2)Q=13(1+21λ12)(𝔼)Qopt.(\mathbb{E}^{2})_{Q}=\dfrac{1}{3}\Big{(}1+2\sqrt{1-\lambda_{1}^{2}}\Big{)}(\mathbb{E})_{Q}^{opt}. (58)
Refer to caption
Figure 3: Optimal trade-off between quantum bound of elegant Bell inequality of Bob1 and Bob2 is shown by the solid green curve while the shaded portion gives the suboptimal range. The solid orange line is for classical bound for the same two observers.

Note that, the maximum values of (𝔼1)Q(\mathbb{E}^{1})_{Q} and (𝔼2)Q(\mathbb{E}^{2})_{Q} in Eq. (52) and Eq. (58) are dependent only on the unsharpness parameter λ1\lambda_{1} as (𝔼)Qopt(\mathbb{E})^{opt}_{Q} is common. Writing (𝔼2)Q(\mathbb{E}^{2})_{Q} in terms of (𝔼1)Q(\mathbb{E}^{1})_{Q} we get

(𝔼2)Q=43(1+21((𝔼1)Q(𝔼)Qopt)2).(\mathbb{E}^{2})_{Q}=\frac{4}{\sqrt{3}}\Big{(}1+2\sqrt{1-\Bigg{(}\frac{(\mathbb{E}^{1})_{Q}}{(\mathbb{E})^{opt}_{Q}}}\Bigg{)}^{2}\Big{)}. (59)

It can be seen for Eq. (59) that if Bob1 extracts more information then the quantum value of (𝔼1)Q(\mathbb{E}^{1})_{Q} increases and consequently decreases the value of (𝔼2)Q(\mathbb{E}^{2})_{Q} and hence there is a trade-off between the values of (𝔼2)Q(\mathbb{E}^{2})_{Q} and (𝔼1)Q(\mathbb{E}^{1})_{Q}. Figure 3 represents the optimal trade-off relation written in Eq. (59) where the green curve shows the quantum values where each point on its surface certifies a unique value of unsharpness parameter λ1\lambda_{1}. For (𝔼1)Q=(𝔼2)Q=12(4+3)/135.291(\mathbb{E}^{1})_{Q}=(\mathbb{E}^{2})_{Q}=12(4+\sqrt{3})/13\approx 5.291, both the Bob1 and Bob2 gets equal advantage as shown by the blue point on the surface of the curve which uniquely certifies the value of sharpness parameter λ1=(57+243)/130.763\lambda_{1}=(\sqrt{57+24\sqrt{3}})/13\approx 0.763.

Similarly, the quantum value of elegant Bell expression between Alice and Bob3 can be calculated as (𝔼3)Q=Tr[ρAB3(𝔼)](\mathbb{E}^{3})_{Q}=Tr[\rho_{AB_{3}}(\mathbb{E})] where ρAB3\rho_{AB_{3}} is the average state shared between Alice and Bob3. Then, the elegant Bell expression between Alice and Bob3 can be re-written as

(𝔼3)Q\displaystyle(\mathbb{E}^{3})_{Q} =\displaystyle= Tr[ρAB1((A1+A2+A3A4)B1′′+(A1+A2\displaystyle Tr\Big{[}\rho_{AB_{1}}\Big{(}(A_{1}+A_{2}+A_{3}-A_{4})B_{1}^{\prime\prime}+(A_{1}+A_{2} (60)
\displaystyle- A3+A4)B2′′+(A1A2+A3+A4)B3′′)]\displaystyle A_{3}+A_{4})B_{2}^{\prime\prime}+(A_{1}-A_{2}+A_{3}+A_{4})B_{3}^{\prime\prime}\Big{)}\Big{]}

where B1′′B^{\prime\prime}_{1}, B2′′B^{\prime\prime}_{2} and B3′′B^{\prime\prime}_{3} are explicitly defined in Appendix C.

Now, we can use the SOS approach as mentioned earlier to obtain the optimal value of (𝔼3)Q(\mathbb{E}^{3})_{Q}. But, (Bi′′)2𝕀(B^{\prime\prime}_{i})^{2}\neq\mathbb{I} and hence needs to be normalised. By considering ω1′′=B1′′\omega^{\prime\prime}_{1}=||B^{\prime\prime}_{1}||, ω2′′=B2′′\omega^{\prime\prime}_{2}=||B^{\prime\prime}_{2}|| and ω3′′=B3′′\omega^{\prime\prime}_{3}=||B^{\prime\prime}_{3}|| and by using the SOS approach we obtain

(𝔼3)Q=max(ω1ω1′′+ω2ω2′′++ω3ω3′′).\displaystyle(\mathbb{E}^{3})_{Q}=max\left(\omega_{1}\omega^{\prime\prime}_{1}+\omega_{2}\omega^{\prime\prime}_{2}++\omega_{3}\omega^{\prime\prime}_{3}\right). (61)

Note that, Bi′′B^{\prime\prime}_{i} and Bj′′B^{\prime\prime}_{j} with i(j)ij{1,2,3}i(j)_{i\neq j}\in\{1,2,3\} can again be proved to be mutually anticommuting. That is, Bob3 requires the anticommuting observables to obtain the optimal quantum value. Using the anticommutation relation we then calculate ω1′′=4(α12β123)(α22β223)\omega^{\prime\prime}_{1}=4(\alpha_{1}^{2}-\frac{\beta_{1}^{2}}{3})(\alpha_{2}^{2}-\frac{\beta_{2}^{2}}{3}). Similarly, we find ω2′′=ω3′′=ω1′′\omega^{\prime\prime}_{2}=\omega^{\prime\prime}_{3}=\omega^{\prime\prime}_{1}.

The quantum value for Alice and Bob3 can be written as

(𝔼3)Q\displaystyle(\mathbb{E}^{3})_{Q} =\displaystyle= 4(α12β123)(α22β223)max(ω1+ω2+ω3)\displaystyle 4(\alpha_{1}^{2}-\frac{\beta_{1}^{2}}{3})(\alpha_{2}^{2}-\frac{\beta_{2}^{2}}{3})\ max\Big{(}\omega_{1}+\omega_{2}+\omega_{3}\Big{)} (62)
=\displaystyle= 4(α12β123)(α22β223)(𝔼)Qopt.\displaystyle 4(\alpha_{1}^{2}-\frac{\beta_{1}^{2}}{3})(\alpha_{2}^{2}-\frac{\beta_{2}^{2}}{3})(\mathbb{E})_{Q}^{opt}. (63)

Writing (𝔼3)Q(\mathbb{E}^{3})_{Q} in terms of the unsharpness parameters λ1\lambda_{1} and λ2\lambda_{2} we get

(𝔼3)Q=19(1+21λ12)(1+21λ22)(𝔼)Qopt(\mathbb{E}^{3})_{Q}=\dfrac{1}{9}\Big{(}1+2\sqrt{1-\lambda_{1}^{2}}\Big{)}\Big{(}1+2\sqrt{1-\lambda_{2}^{2}}\Big{)}(\mathbb{E})_{Q}^{opt} (64)

which can be generalised for Alice and any arbitrary kthk^{\text{th}} Bob (Bobk) as

(𝔼k)Q=13ki=1k13(1+21λi2)(𝔼)Qopt.(\mathbb{E}^{k})_{Q}=\dfrac{1}{3^{k}}\prod_{i=1}^{k-1}\sqrt{3}\Big{(}1+2\sqrt{1-\lambda_{i}^{2}}\Big{)}(\mathbb{E})_{Q}^{opt}. (65)

Further, (𝔼3)Q(\mathbb{E}^{3})_{Q} can be simplified in term of (𝔼1)Q(\mathbb{E}^{1})_{Q}, (𝔼2)Q(\mathbb{E}^{2})_{Q} as

(𝔼3)Q=19(1+Δ1)(1+4+4Δ1Δ21+Δ1)(\mathbb{E}^{3})_{Q}=\dfrac{1}{9}(1+\Delta_{1})\Bigg{(}1+\sqrt{\frac{4+4\Delta_{1}-\Delta_{2}}{1+\Delta_{1}}}\Bigg{)} (66)

where Δ1=21((𝔼1)Q(𝔼)Qopt)2\Delta_{1}=2\sqrt{1-\Big{(}\frac{(\mathbb{E}^{1})_{Q}}{(\mathbb{E})^{opt}_{Q}}\Big{)}^{2}} and Δ2=3(𝔼1)Q4\Delta_{2}=\dfrac{\sqrt{3}(\mathbb{E}^{1})_{Q}}{4}.

Refer to caption
Figure 4: Optimal trade-off between quantum bound of elegant Bell inequality of Bob1, Bob2 and Bob3. The black point on the three-dimensional graph indicates the point which certifies the unsharpness parameters λ1\lambda_{1} and λ2\lambda_{2} when quantum values of all three sequential Bobs are considered to be equal.

Optimal trade-off between quantum bound of elegant Bell inequality of Bob1, Bob2 and Bob3 are given by Eq. (66) and plotted in Figure 4. The brown cube represents the preparation non-contextual bound showing no trade-off. The three-dimensional semi-paraboloid over the cube represents the trade-off between quantum bound. For sharp measurement of Bob3 with λ3=1\lambda_{3}=1, each point on the surface of the semi paraboloid in Figure 4 uniquely certifies λ1\lambda_{1} and λ2\lambda_{2}. The black point on the surface of the semi paraboloid uniquely certifies λ1=0.644\lambda_{1}=0.644 and λ2=0.763\lambda_{2}=0.763 for (𝔼1)Q=(𝔼2)Q=(𝔼3)Q=4.462(\mathbb{E}^{1})_{Q}=(\mathbb{E}^{2})_{Q}=(\mathbb{E}^{3})_{Q}=4.462.

V.2 DI self-testing statement in sequential scenario

Thus, the optimal triple {(𝔼1)Q,(𝔼2)Q\{(\mathbb{E}^{1})_{Q},(\mathbb{E}^{2})_{Q}, (𝔼3)Q}(\mathbb{E}^{3})_{Q}\} uniquely certifies the states shared between Alice and of Bob1, Bob2 and Bob3, their observables, and the unsharpness parameters of Bob1 and Bob2. The self-testing statements are the following,

(i) Alice performs the sharp measurement of her observables in any arbitrary local dimension, satisfying the functional relations in Eq. (45).

(ii) Bob1 performs unsharp measurement corresponding to three observables that are mutually anticommuting in any arbitrary local dimension. The set of observables of Bob2 and Bob3 are the same.

(iii) Alice and Bob1 share a maximally entangled state in any arbitrary dimension.

(iv) The optimal triple pair {(𝔼1)Q,(𝔼2)Q,(𝔼3)Q}\{(\mathbb{E}^{1})_{Q},(\mathbb{E}^{2})_{Q},(\mathbb{E}^{3})_{Q}\} certifies the unsharpness parameters λ1\lambda_{1} and λ2\lambda_{2} which, in turn, self-tests the shared state between Alice, Bob1, Bob2 and Bob3 respectively. As shown in Figure 4, each point on the surface of semi-paraboloid self-tests unique values of unsharpness parameters λ1\lambda_{1} and λ2\lambda_{2}.

V.3 Robust certification of unsharpness parameters

Similar to the sequential CHSH scenario, for sub-optimal violation of elegant Bell expression, the certifiable range of λ1\lambda_{1} from Eqs. (52) and (58) can be calculated as

(𝔼1)Q(𝔼)Qopt<λ1<114(3(𝔼2)Qλ2(𝔼)Qopt1)2.\displaystyle\frac{(\mathbb{E}^{1})_{Q}}{(\mathbb{E})^{opt}_{Q}}<\lambda_{1}<\sqrt{1-\frac{1}{4}\Bigg{(}\frac{3(\mathbb{E}^{2})_{Q}}{\lambda_{2}(\mathbb{E})^{opt}_{Q}}-1\Bigg{)}^{2}}. (67)

Eq. (67) shows that for the optimal quantum value of (𝔼)Qopt(\mathbb{E})_{Q}^{opt}, the lower bound of λ1\lambda_{1} depends only on the maximum quantum value of (𝔼1)Q(\mathbb{E}^{1})_{Q}. Since, (𝔼)Qopt(\mathbb{E})_{Q}^{opt} is 434\sqrt{3}, for violating the elegant Bell inequality Bob1 requires (𝔼1)Q>4(\mathbb{E}^{1})_{Q}>4, which fixes lower bound of unsharpness parameter as (λ1)min1/30.57(\lambda_{1})_{min}\approx 1/\sqrt{3}\approx 0.57. Any value of λ1[1/3,1]\lambda_{1}\in[1/\sqrt{3},1] therefore provides the quantum advantage for Bob1.

The upper bound of unsharpness parameter λ1\lambda_{1} is a function of λ2\lambda_{2} and the maximum quantum value of (𝔼2)Q(\mathbb{E}^{2})_{Q}. To get advantage for Bob2, two sequential Bob requires (𝔼1)Q,(𝔼2)Q>4(\mathbb{E}^{1})_{Q},(\mathbb{E}^{2})_{Q}>4. Considering Bob2 performs sharp measurement (λ2=1\lambda_{2}=1), the upper bound on the unsharpness parameter i.e., (λ1)max(\lambda_{1})_{max} from Eq. (67) is calculated as (λ1)max=3/20.93(\lambda_{1})_{max}=\sqrt{\sqrt{3}/2}\approx 0.93. Thus, when both Bob1 and Bob2 get quantum advantage, the interval 0.57<λ1<0.930.57<\lambda_{1}<0.93 can be certified.

Now, the range of λ1\lambda_{1} becomes more restricted if the quantum advantage is further extended to Bob3 which demands (𝔼1)Q,(𝔼2)Q,and(𝔼3)Q>4(\mathbb{E}^{1})_{Q},(\mathbb{E}^{2})_{Q},\text{and}\ (\mathbb{E}^{3})_{Q}>4. In such a case, from Eqs. (52) and (64), the interval of λ1\lambda_{1} is narrower down to 0.57<λ1<0.770.57<\lambda_{1}<0.77 which requires a more efficient experimental realization.

Again, if sequential Bobs up to Bob3 get the quantum advantage, the range of λ2\lambda_{2} can be calculated from Eqs. (58) and (64) as

3(𝔼2)Qξ1(𝔼)Qopt<λ2<114(9(𝔼3)Qξ11)2\displaystyle\dfrac{3(\mathbb{E}^{2})_{Q}}{\xi_{1}(\mathbb{E})_{Q}^{opt}}<\lambda_{2}<\sqrt{1-\dfrac{1}{4}\Bigg{(}\dfrac{9(\mathbb{E}^{3})_{Q}}{\xi_{1}}-1\Bigg{)}^{2}} (68)

where ξ1=(1+21λ12)\xi_{1}=\Big{(}1+2\sqrt{1-\lambda_{1}^{2}}\Big{)}. Eq. (68) shows that both the upper and lower bound of λ2\lambda_{2} are dependent on λ1\lambda_{1}. Thus, the range 0.65<λ2<0.870.65<\lambda_{2}<0.87 can be certified. Further, from Eq. (64) the lower bound of (λ3)min(\lambda_{3})_{min} is calculated as,

(λ3)min=9(𝔼3)Qξ1(1+21λ22)(𝔼)Qopt0.78.(\lambda_{3})_{min}=\dfrac{9(\mathbb{E}^{3})_{Q}}{\xi_{1}\Big{(}1+2\sqrt{1-\lambda_{2}^{2}}\Big{)}(\mathbb{E})_{Q}^{opt}}\approx 0.78. (69)

Now, considering Bob1, Bob2 and Bob3 implement their unsharp measurements with lower critical values of unsharpness parameters at their respective sites, from Eq. (65) we get (𝔼4)Q=3.84(\mathbb{E}^{4})_{Q}=3.84, i.e., Alice and Bob4 cannot violate elegant Bell inequality, thereby will not provide any quantum advantage over preparation non-contextual bound.

VI Summary and discussion

The precise control of quantum devices plays a crucial role in the development of quantum technologies. Therefore, developing elegant protocols for certifying quantum devices is indispensable in quantum information theory. In this work, we provided DI self-testing of unsharp instruments based on two Bell inequalities, viz., the CHSH inequality and the elegant Bell inequality. Note that the optimal quantum violation of a Bell inequality uniquely self-tests the state and the observables. We discussed that such a violation does not certify the post-measurement states, and hence self-testing the unsharp instrument is not possible in that way. We demonstrated that the sequential Bell test by multiple independent observers on one side of the Bell experiment enables the self-testing of post-measurement states, which, in turn, uniquely self-tests the unsharp instruments. The optimal quantum violation of CHSH inequality can be achieved only for sharp measurement, and for unsharp measurement, one obtains the sub-optimal value. Notably, the sub-optimal quantum value may also arise due to the nonideal preparation of the state or the inappropriate choices of the local observables. However, as explicitly discussed in [51], the primary criticism regarding DI self-testing of unsharp measurement through a Bell test arises from Naimark’s theorem, which states that any non-projective measurement can be viewed as a projective measurement in a higher-dimensional Hilbert space. Since there is no bound on dimension in DI self-testing, one can always argue that the sub-optimal quantum violation arises from the inappropriate choice of observables in higher-dimension and not from the unsharp measurement.

By providing the dimension-independent optimization of the sequential Bell test, we provided a scheme for self-testing of unsharp instruments. As mentioned, the sequential sharing of nonlocality by multiple independent observers plays a crucial role in our work. Crucially, such a sharing of quantum correlation without assuming the dimension of the system has not hitherto been discussed. Here, we impose no bound on the dimension of the system, and the quantum devices are taken as black boxes. We introduced an elegant SOS approach enabling us to derive the maximum quantum values in the sequential Bell test. We note here that the semi-DI certification of the unsharp instruments in a sequential prepare-measure scenario was demonstrated in [52] by using a qubit system. In [52], the authors leave DI self-testing of an unsharp instrument as an open question which is now provided in our work.

We first considered the sequential sharing of CHSH nonlocality where Alice always performs sharp measurement and an arbitrary kk number of sequential Bobs (Bobk) who perform unsharp measurements on their local sub-system. If the first observer (Bob1) performs a sharp projective measurement, the entanglement between Alice and Bob1 will be lost, and there is no chance that Alice and Bob2 will violate the CHSH inequality. On the other hand, if Bob1 performs an unsharp measurement, a sufficient residual entanglement may remain to exhibit the violation of CHSH inequality between Alice and Bob2. In such a case, we jointly maximized the sub-optimal quantum advantages for both sequential observers and demonstrated that there exists a trade-off relation between the two sequential quantum violations. The sub-optimal quantum violations form an optimal pair which eventually self-tests the unsharp instrument of Bob1 along with the entangled state and the observables of Alice, Bob1 and Bob2. In the CHSH scenario, at most, two sequential Bobs can share the nonlocality, and hence only one unsharpness parameter can be self-tested.

We extend our treatment to the sharing of preparation contextuality based on the elegant Bell inequality. We demonstrated that the preparation contextuality can be shared up to a maximum of three sequential Bobs. We jointly maximized the sub-optimal sequential quantum values by using the SOS approach without assuming the dimension of the system. There is a trade-off between the three sub-optimal quantum values for Bob1, Bob2, and Bob3 violating the elegant Bell inequality. Three sub-optimal quantum values form an optimal triple which in turn self-tests the unsharp instruments of Bob1 and Bob2. In the process of maximization of the sub-optimal values, the entangled state and the observables of Alice and of Bob1, Bob2, and Bob3 are self-tested.

We note that due to unavoidable losses and imperfection in the actual experimental scenarios, the unique certification of the unsharpness parameter is not possible. In such a case, we provided an analysis of robust certification so that a range of the unsharpness parameter can be certified. The more perfect the actual experiment, one can achieve more accurate the certification of the unsharpness parameters.

We conclude by proposing the following future direction and potential applications. Our work can be further generalized to self-test an arbitrary number of unsharp instruments based on the quantum violation of a family of preparation non-contextual inequalities proposed in [72]. It can be interesting to study the sequential sharing of preparation contextuality by multiple numbers of observers on one side of the Bell experiment. Using the SOS approach one can simultaneously maximize the sub-optimal quantum values corresponding to the independent sequential observers. This can be an interesting line of future study. Our work has immediate application in generating a higher amount of DI-certified randomness. In a recent work, based on the sequential sharing of nonlocality by using the two-qubit entangled state, the generation of a higher amount of randomness was proposed [5], which is experimentally tested in [75]. The self-testing protocol provided here can be used to generate a higher amount of DI-certified randomness. This calls for further study.

Acknowledgment

PR acknowledges the support from the research grant DST/ICPS/QuEST/2019/4. AKP acknowledges the support from the research grant MTR/2021/000908.

Appendix A Calculation to show that every sequential Bob requires same set of observables

Here we show that the set of observables require for achieving the maximum quantum violation for Bob1 and Bob2 are the same. Let Bob1 performs measurement of B1B_{1} and B2B_{2} on his local subsystems upon receiving input y1{1,2}y_{1}\in\{1,2\} on the entangled state ρAB1\rho_{AB_{1}}, and Bob2 upon receiving input y2{1,2}y_{2}\in\{1,2\} performs measurements of the observables B3B_{3} and B4B_{4} on a state ρAB2\rho_{AB_{2}} producing outputs b2{0,1}b_{2}\in\{0,1\}. Putting ρAB2\rho_{AB_{2}} from Eq. (13), we can explicitly write the CHSH expression between Alice and Bob2 as

(2)Q\displaystyle(\mathcal{B}^{2})_{Q} =\displaystyle= Tr[ρAB1((A1+A2)B¯+((A1A2)B¯¯)]\displaystyle Tr\Big{[}\rho_{AB_{1}}\left(\Big{(}A_{1}+A_{2}\Big{)}\bar{B}+\Big{(}(A_{1}-A_{2})\bar{\bar{B}}\right)\Big{]} (70)

where B¯=2α12B3+β12(B1B3B1+B2B3B2)\bar{B}=2\alpha^{2}_{1}B_{3}+\beta^{2}_{1}\Big{(}B_{1}B_{3}B_{1}+B_{2}B_{3}B_{2}\Big{)} and B¯¯=2α12B4+β12(B1B4B1+B2B4B2)\bar{\bar{B}}=2\alpha^{2}_{1}B_{4}+\beta^{2}_{1}\Big{(}B_{1}B_{4}B_{1}+B_{2}B_{4}B_{2}\Big{)}.

By writing Eq. (70) in terms of the unsharpness parameter and rearranging, the CHSH expression can be written as

(2)Q\displaystyle(\mathcal{B}^{2})_{Q} =\displaystyle= Tr[ρAB1(γ1((A1+A2)B3+(A1A2)B4)+γ12((A1+A2)(B1B3B1+B2B3B2)+(A1A2)(B1B4B1+B2B4B2))]\displaystyle Tr\Bigg{[}\rho_{AB_{1}}\Bigg{(}\gamma_{1}\Big{(}(A_{1}+A_{2})B_{3}+(A_{1}-A_{2})B_{4}\Big{)}+\dfrac{\gamma_{1}^{\prime}}{2}\Big{(}(A_{1}+A_{2})(B_{1}B_{3}B_{1}+B_{2}B_{3}B_{2})+(A_{1}-A_{2})(B_{1}B_{4}B_{1}+B_{2}B_{4}B_{2}\Big{)}\Bigg{)}\Bigg{]} (71)

where γ1=12(1+1λ12)\gamma_{1}=\dfrac{1}{2}({1+\sqrt{1-\lambda_{1}^{2}}}) and γ1=12(11λ12)\gamma_{1}^{\prime}=\dfrac{1}{2}({1-\sqrt{1-\lambda_{1}^{2}}}).

The first term in Eq. (71) has the form of CHSH inequality where B3B_{3} and B4B_{4} can be proved as mutually anticommuting by the SOS approach. Since γ1>γ1\gamma_{1}>\gamma_{1}^{\prime}, we can then write

(2)Qγ1max((A1+A2)+(A1A2))+γ12((A1+A2)(B1B3B1+B2B3B2)+(A1A2)(B1B4B1+B2B4B2)).(\mathcal{B}^{2})_{Q}\leq\gamma_{1}\ max\Big{(}||(A_{1}+A_{2})||+||(A_{1}-A_{2})||\Big{)}+\dfrac{\gamma_{1}^{\prime}}{2}\Big{(}(A_{1}+A_{2})(B_{1}B_{3}B_{1}+B_{2}B_{3}B_{2})+(A_{1}-A_{2})(B_{1}B_{4}B_{1}+B_{2}B_{4}B_{2})\Big{)}. (72)

It is simple to show that {(B1B3B1+B2B3B2),(B1B4B1+B2B4B2)}=0\{(B_{1}B_{3}B_{1}+B_{2}B_{3}B_{2}),(B_{1}B_{4}B_{1}+B_{2}B_{4}B_{2})\}=0 which requires B1=B3B_{1}=B_{3} and B2=B4B_{2}=B_{4}, and in turn {B1,B2}=0\{B_{1},B_{2}\}=0.

Appendix B Detailed calculation for sequential quantum value of elegant Bell expression for Alice and Bob2

To derive optimal quantum value of the elegant Bell expression written in Eq. (LABEL:ebi2) we require the (unnormalized) observables to be B1B_{1}^{\prime}, B2B_{2}^{\prime} and B3B_{3}^{\prime} mutually anticommuting. We show that {Bi,Bj}=0\{B_{i}^{\prime},B_{j}^{\prime}\}=0 implies {Bi,Bj}=0\{B_{i},B_{j}\}=0 where i,j=1,2,3i,j=1,2,3 with iji\neq j.

{B1,B2}\displaystyle\{B_{1}^{\prime},B_{2}^{\prime}\} (73)
=\displaystyle= 4(α12+β123)2{B1,B2}+43β12(α12+β123)(B1B3{B2,B3}+B2B3{B1,B3}+B3{B1,B3}B2+B3{B2,B3}B1)\displaystyle 4\Bigg{(}\alpha_{1}^{2}+\frac{\beta_{1}^{2}}{3}\Bigg{)}^{2}\{B_{1},B_{2}\}+\frac{4}{3}\beta_{1}^{2}\Bigg{(}\alpha_{1}^{2}+\frac{\beta_{1}^{2}}{3}\Bigg{)}\Bigg{(}B_{1}B_{3}\{B_{2},B_{3}\}+B_{2}B_{3}\{B_{1},B_{3}\}+B_{3}\{B_{1},B_{3}\}B_{2}+B_{3}\{B_{2},B_{3}\}B_{1}\Bigg{)}
+\displaystyle+ (23β12)2({B1,B2}33{B1,B2}B1B3{B2,B3}B2{B1,B2}B2B1{B1,B2}B1B3{B2,B3}B1B3{B1,B3}B2\displaystyle\Bigg{(}\frac{2}{3}\beta_{1}^{2}\Bigg{)}^{2}\Bigg{(}\{B_{1},B_{2}\}^{3}-3\{B_{1},B_{2}\}-B_{1}B_{3}\{B_{2},B_{3}\}-B_{2}\{B_{1},B_{2}\}B_{2}-B_{1}\{B_{1},B_{2}\}B_{1}-B_{3}\{B_{2},B_{3}\}B_{1}-B_{3}\{B_{1},B_{3}\}B_{2}
\displaystyle- B2B3{B1,B3}+B2{B1,B2}B3{B2,B3}+B3{B2,B3}B2{B1,B2}+B3{B1,B3}B1{B1,B2}+B1{B1,B2}B3{B1,B3}+B3{B1,B2}B3)\displaystyle B_{2}B_{3}\{B_{1},B_{3}\}+B_{2}\{B_{1},B_{2}\}B_{3}\{B_{2},B_{3}\}+B_{3}\{B_{2},B_{3}\}B_{2}\{B_{1},B_{2}\}+B_{3}\{B_{1},B_{3}\}B_{1}\{B_{1},B_{2}\}+B_{1}\{B_{1},B_{2}\}B_{3}\{B_{1},B_{3}\}+B_{3}\{B_{1},B_{2}\}B_{3}\Bigg{)}

The co-efficients α1>0\alpha_{1}>0, β10\beta_{1}\geq 0. So, the above expression can only be zero when {Bi,Bj}=0\{B_{i},B_{j}\}=0 where i(j)1,2,3i(j)\in 1,2,3.

To derive the optimal quantum value of (𝔼2)Q(\mathbb{E}^{2})_{Q} in the Eq. (LABEL:ebi2) we use SOS approach where ωi=Bi\omega_{i}^{\prime}=||B_{i}^{\prime}|| with i{1,2,3}i\in\{1,2,3\} where ||.||2||.||_{2} is the Euclidean norm of a vector. The optimal quantum value of (𝔼2)Q(\mathbb{E}^{2})_{Q} can be obtained as

(𝔼2)Qopt=max(ω1ω+ω2ω2+ω3ω3)=2(α12β123)(𝔼)Qopt\displaystyle(\mathbb{E}^{2})_{Q}^{opt}={max}\left(\omega_{1}\omega^{\prime}+\omega_{2}\omega_{2}^{\prime}+\omega_{3}\omega_{3}^{\prime}\right)=2(\alpha_{1}^{2}-\frac{\beta_{1}^{2}}{3})(\mathbb{E})_{Q}^{opt} (75)

Appendix C Detailed calculation for the sequential quantum value of elegant Bell expression for Alice and Bob3

The average reduced state for Alice and Bob3 is calculated by using Eq. (51) as

ρAB3\displaystyle\rho_{AB_{3}} =\displaystyle= 13b2{+,}y2=13(𝕀Kb2|y2)ρAB2(𝕀Kb2|y2)\displaystyle\dfrac{1}{3}\sum_{b_{2}\in\{+,-\}}\sum_{y_{2}=1}^{3}\left(\mathbb{I}\otimes K_{b_{2}|y_{2}}\right)\rho_{AB_{2}}\left(\mathbb{I}\otimes K_{b_{2}|y_{2}}\right)
=\displaystyle= 4(α12α22+β12β223)ρAB1+43(α12β22+β12α22)y2=13(𝕀By2)ρAB1(𝕀By2)\displaystyle 4\Big{(}\alpha_{1}^{2}\alpha_{2}^{2}+\frac{\beta_{1}^{2}\beta_{2}^{2}}{3}\Big{)}\rho_{AB_{1}}+\frac{4}{3}\Big{(}\alpha_{1}^{2}\beta_{2}^{2}+\beta_{1}^{2}\alpha_{2}^{2}\Big{)}\sum_{{y_{2}}=1}^{3}(\mathbb{I}\otimes B_{y_{2}})\rho_{AB_{1}}(\mathbb{I}\otimes B_{y_{2}})
+\displaystyle+ 4β12β229(B1B2ρAB1B2B1+B2B1ρAB1B1B2+B1B3ρAB1B3B1+B3B1ρAB1B1B3+B2B3ρAB1B3B2+B3B2ρAB1B2B3)\displaystyle\frac{4\beta_{1}^{2}\beta_{2}^{2}}{9}\Big{(}B_{1}B_{2}\rho_{AB_{1}}B_{2}B_{1}+B_{2}B_{1}\rho_{AB_{1}}B_{1}B_{2}+B_{1}B_{3}\rho_{AB_{1}}B_{3}B_{1}+B_{3}B_{1}\rho_{AB_{1}}B_{1}B_{3}+B_{2}B_{3}\rho_{AB_{1}}B_{3}B_{2}+B_{3}B_{2}\rho_{AB_{1}}B_{2}B_{3}\Big{)}

The quantum value of elegant Bell expression between Alice and Bob3 from Eq. (C) is given by

(𝔼3)Q\displaystyle(\mathbb{E}^{3})_{Q} =\displaystyle= max(Tr[ρAB1((A1+A2+A3A4)B1′′+(A1+A2A3+A4)B2′′+(A1A2+A3+A4)B3′′)])\displaystyle max\Bigg{(}Tr\Big{[}\rho_{AB_{1}}\Big{(}(A_{1}+A_{2}+A_{3}-A_{4})B_{1}^{\prime\prime}+(A_{1}+A_{2}-A_{3}+A_{4})B_{2}^{\prime\prime}+(A_{1}-A_{2}+A_{3}+A_{4})B_{3}^{\prime\prime}\Big{)}\Big{]}\Bigg{)}

where

B1′′\displaystyle B_{1}^{\prime\prime} =\displaystyle= (4α12α22+4β12β223+4α12β223+4β12α223)B1+(4α12β223+4β12α223+4β12β229)(B2B1B2+B3B1B3)\displaystyle\Big{(}4\alpha_{1}^{2}\alpha_{2}^{2}+\frac{4\beta_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\alpha_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\alpha_{2}^{2}}{3}\Big{)}B_{1}+\Big{(}\frac{4\alpha_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\alpha_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\beta_{2}^{2}}{9}\Big{)}(B_{2}B_{1}B_{2}+B_{3}B_{1}B_{3}) (77)
+\displaystyle+ 4β12β229(B1B2B1B2B1+B1B3B1B3B1+B3B2B1B2B3+B2B3B1B3B2),\displaystyle\frac{4\beta_{1}^{2}\beta_{2}^{2}}{9}(B_{1}B_{2}B_{1}B_{2}B_{1}+B_{1}B_{3}B_{1}B_{3}B_{1}+B_{3}B_{2}B_{1}B_{2}B_{3}+B_{2}B_{3}B_{1}B_{3}B_{2}),
B2′′\displaystyle B_{2}^{\prime\prime} =\displaystyle= (4α12α22+4β12β223+4α12β223+4β12α223)B2+(4α12β223+4β12α223+4β12β229)(B1B2B1+B3B2B3)\displaystyle\Big{(}4\alpha_{1}^{2}\alpha_{2}^{2}+\frac{4\beta_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\alpha_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\alpha_{2}^{2}}{3}\Big{)}B_{2}+\Big{(}\frac{4\alpha_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\alpha_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\beta_{2}^{2}}{9}\Big{)}(B_{1}B_{2}B_{1}+B_{3}B_{2}B_{3}) (78)
+\displaystyle+ 4β12β229(B2B1B2B1B2+B2B3B2B3B2+B3B1B2B1B3+B1B3B2B3B1),\displaystyle\frac{4\beta_{1}^{2}\beta_{2}^{2}}{9}(B_{2}B_{1}B_{2}B_{1}B_{2}+B_{2}B_{3}B_{2}B_{3}B_{2}+B_{3}B_{1}B_{2}B_{1}B_{3}+B_{1}B_{3}B_{2}B_{3}B_{1}),
B3′′\displaystyle B_{3}^{\prime\prime} =\displaystyle= (4α12α22+4β12β223+4α12β223+4β12α223)B3+(4α12β223+4β12α223+4β12β229)(B1B3B1+B2B3B2)\displaystyle\Big{(}4\alpha_{1}^{2}\alpha_{2}^{2}+\frac{4\beta_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\alpha_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\alpha_{2}^{2}}{3}\Big{)}B_{3}+\Big{(}\frac{4\alpha_{1}^{2}\beta_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\alpha_{2}^{2}}{3}+\frac{4\beta_{1}^{2}\beta_{2}^{2}}{9}\Big{)}(B_{1}B_{3}B_{1}+B_{2}B_{3}B_{2}) (79)
+\displaystyle+ 4β12β229(B3B1B3B1B3+B3B2B3B2B3+B2B1B3B1B2+B1B2B3B2B1).\displaystyle\frac{4\beta_{1}^{2}\beta_{2}^{2}}{9}(B_{3}B_{1}B_{3}B_{1}B_{3}+B_{3}B_{2}B_{3}B_{2}B_{3}+B_{2}B_{1}B_{3}B_{1}B_{2}+B_{1}B_{2}B_{3}B_{2}B_{1}).

It can also be proved that {Bi′′,Bj′′}=0\{B_{i}^{\prime\prime},B_{j}^{\prime\prime}\}=0 with i,j=1,2,3i,j=1,2,3 provided {Bi,Bj}=0\{B_{i},B_{j}\}=0.

References