1 Introduction
The study of the differential structure of the space of all Riemannian metrics on a closed manifold is one of important studies in geometry.
In [10], Ebin particularly has proved a slice theorem for the pullback action of the diffeomorphism group on .
In [17], Koiso has also extended it to an Inverse Limit Hilbert (ILH for brevity)-version.
Moreover, he has also studied the conformal action on , and consequently has proved the following decomposition theorem:
Theorem 1.1 (Koiso’s decomposition theorem [18, Corollary 2.9] ).
Let be a closed -manifold , the space of all Riemannian metrics on and the diffeomorphism group of .
Set also
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where , and
denote respectively the volume of , the scalar curvature of and the set of all non-zero eigenvalues of the (non-negative) Laplacian of .
Note that these four spaces become naturally ILH-manifolds.
For any
and any smooth deformation of for sufficiently small ,
then there exist uniquely smooth deformations of , ) of the identity
and ) of with such that
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Here, denotes the divergence with respect to .
Note that the above decomposition can be replaced by
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This theorem has often played an important role in studying gemoetric structures related to several variational problems on a closed manifold.
Hence, extending this to on a manifold with boundary seems to be also important.
From now on, we throughout assume that is a compact connected oriented smooth -manifold with smooth boundary .
Let be the space of all Riemannian metrics on
In order to obtain a corresponding Koiso-type decomposition theorem on with
to Theorem 1.1 on a closed manifold, we need to fix a suitable boundary condition
for each metric on .
From the variational view point of the Einstein-Hilbert functional,
a candidate of such boundary conditions may be the following:
For a fixed metric on with zero mean curvature
along , we fix the boundary condition for each on as
and along
(see Fact 2.1 and [2],[3]).
Here, denotes the conformal class of .
However, one can notice that this boundary condition is not enough to get a
Koiso-type decomposition theorem, even more an Ebin-type slice theorem.
Here, we will fix a slightly stronger boundary condition below,
which still has a naturality(see Fact 2.1(1)).
Fix a Riemannian metric on with along
and set its conformal class on .
denotes the outer unit normal vector field along with respect to .
When two metrics and on have the same 1-jets
for all
we write it as
Set also
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where denote the set of all non-zero eigenvalues of with the Neumann boundary condition respectively.
Note that along for all .
Our main result is the following theorem:
Main Theorem.
For any ) and any smooth deformation
of for sufficiently small ,
there exist smooth deformations of
of
and of
with
such that
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The rest of this paper is organized as follows.
In Section 2, we state a Slice theorem for a manifold with boundary with a fixed conformal class on the boundary and prove it.
In Section 3, we prepare some necessary lemmas for the proof of Main Theorem.
Finally, combining them with Slice theorem, we prove Main Theorem.
In Section 4, we give two applications of Main Theorem.
Acknowledgement
I would like to thank my supervisor Kazuo Akutagawa for suggesting the initial direction for my study,
his good advice and support.
2 Preliminaries and a slice theorem
Let be a compact connected oriented smooth -dimensional manifold with non-empty smooth boundary .
Fix a Riemannian metric with . Here, denotes the mean curvature of with respect to . And set its conformal class on .
For a given positive definite symmetric (0,2)-type tensor field on , we will write when .
Note that this condition equivalent to for some , where is the natural inclusion.
Moreover, we denote when .
With this understood, we set
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Note also that and
Remark 2.1.
In the case that (that is, is a closed manifold),
it is well known that a Riemannian metric on is Einstein if and only if it is a critical point of the normalized
Einstein-Hilbert functional on the space
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where denote respectively the scalar curvature, the volume measure of and the volume of .
However, if we consider the analogue of the case of on compact -manifold with non-empty boundary,
then the set of critical points of on the space is empty (see Fact 2.1 below).
Hence, in this case, we need to fix a suitable boundary condition for all metrics, and then must be restricted to a subspace of .
When set the several subspaces of below:
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A metric is called a relative metric if
By Fact 2.1 below, it is reasonable to restrict the functional to the subspace
as well as and
Fact 2.1 ([2, Proposition 2.1], [3, Remark 1, Theorem 1.1]).
Let and be the same as the above.
Then the following holds:
(1) if and only if is an Einstein metric with
(namely, a relative Einstein metric) and
(2) if and only if is a relative Einstein metric and .
(3) if and only if is an Einstein metric with totally geodesic boundary.
(4)
Here, for instance, and denote respectively the set of all critical metrics of
and the set of those of its restriction to .
From now on, we will consentrate on the spaces and
For a smooth fibre bundle , we denote by the space of all -sections.
(Note that -norm does not depend on the choice of Riemannian metric, hence, we fix a reference metric to define these function spaces.)
The Sobolev embedding theorem states that is continuous if , see for instance [4].
By the Sobolev embedding, if , (the set of all -maps from to itself) is a Hilbert manifold.
Pick and let
and let .
From the Sobolev embedding, is open in and hence it is also a Hilbert manifold.
Let .
Then is a Hilbert submanifold of .
We denote by the identity map.
We set , where and the tensor field consisting of all symmetric (0,2)-tensors on
and the set of all metrics respectively.
Then is a Hilbert manifold modeled on (by the Sobolev embedding).
And we define a closed Hilbert submanifold of as .
Additionally, we set
and
.
Then and are Hilbert submanifolds of . See [10], [23] for more detail about these spaces.
Note that, for and
Moreover, for , we denote be the isotropy subgroup of in
, that is,
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In this section, we shall prove the following theorem:
Theorem 2.1 (Slice theorem for manifold with boundary).
Let and
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be an usual action by pullback.
Then for each there exsits a submanifold
containing ,which is diffeomorphic to a ball in a separable real Hilbert space, such that
(1)
(2) and
(3)There exists a local section:
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defined in a neighborhood of the identity coset such that if
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then is a homeomorphism onto a neighborhood of
Moreover, the same statement holds when we replace by .
First, we get the following lemma:
Lemma 2.1.
Under the identification
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where and are respectively the Levi-Civita connection with respect to and the -th component of in terms of some local coordinates.
For ,
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Here, and represent the tangent spaces respectively.
Moreover, for , we also have
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where denotes the derivative of the mean curvatrue function at
And, for
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Proof.
From the definition, (2), (3) and (4) are obvious.
For proving (1), we note that the derivative of a diffeomorphism-action via pull-back on metrics at coincides with the Lie derivative of
under the above identification (see for instance Lemma 6.2 in [10]).
Then the first condition comes from the conformal condition on and the second from the fact that any diffeomorphisms map to itself.
And (3) follows in the same way.
Here, we also note that may have some connected components. (Note that the number of components is finite since is compact.)
In fact, we assume that , where is a connected component of and
Then, under the above identification,
for sufficiently small
as explained below.
Here, is the corresponding curve to a tangent vector.
Since is compact manifold, we can take some open neighborhoods of each , such that
for all .
Consider ,
then this is an open subset of with respect to the compact-open topology.
Hence, this is an open neighborhood of in .
Since and is continuous, for all with .
In paticular, for all and with .
∎
From [23, Section 9], is linearly isomorphic to a closed subspace of finite direct sum of ,
where is a closed -dimensional disc. Therefore we obtain the following lemma in exactly the same way as in [10, Section 3].
Lemma 2.2 ([10, Section 3]).
is a topological group.
Furthermore, for all
,
the left(right) action
is smooth.
Remark 2.2.
It is well known that any -diffeomorphism, which is an isometry of a smooth metric, is smooth (see [10], [16], [20]).
Therefore, from the Sobolev embedding, and is the same for any such that .
The following lemma follows from Section 5 in [10] and the fact that is a submanifold of .
Lemma 2.3 ([10, Section 5]).
(1) The natural inclusion
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is smooth.
(2) is embedding, that is
for all , its derivative is injective and its image is closed in
(3) The composition map:
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is smooth.
(4) Let
, then is a involutive subbundle of
that is,
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where is the Lie algebra of .
Using lemma 2.3 and the Frobenius’s theorem(see [19, Chapter 6, Theorem 2]),
we obtain a Banach manifold structure on (see [10, Proposition 5.8, 5.9]).
And we can show the exsitence of a local section by using this Banach-coordinate-charts:
Lemma 2.4 ([10, Proposition 5.10]).
For any
there exists a local section
defined on a neighborhood .
Proof.
Using the above Banach-coordinate-charts, we can construct a local section exactly same as Proposition 5.10 in [10].
∎
For any , , we define
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and
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Then, by the definition of , it naturally induces
and .
Moreover, from the existence of a local section and the definition, are smooth injective maps.
Here, we will show that
and
are immersions (i.e., its derivation is injective and has closed image).
Remark 2.3.
We can similarly define , but it is not an immersion in general.
Next, we will show that the image of is closed in and
imege of is closed in .
As mentioned in the proof of lemma 2.1, under the identification as in lemma 2.1,
,
and .
For simplicity, we put the Lie derivative with respect to as , that is
For we set
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where
, and denote respectively the (1,2)-contraction with respect to
the divergence operator of :
and its formal adjoint : .
And “ ” in the definition of is an element of such that
Thus, is determined by them.
And these are Hilbert spaces.
Since the composition map is elliptic, we obtain
the following boundary estimate (see [12, Theorem 6.6]):
There exists a positive constant such that for any ,
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where is an extension to of
For and , from the Green’s formula,
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where
are -inner product with respect to .
And is the outer unit normal vector along with respect to
Since , from lemma 2.1, the second term vanishes. Thus we get
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Therefore
for all ,
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(1) |
From the closed range theorem([12, Lemma 5.10]), Proposition 6.8 and 6.9 in [10], we get the following:
Lemma 2.5.
is a closed subspace of and there is an orthogonal decomposition:
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From lemma 2.5, we get that
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On the other hand, from the equation (1),
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Hence we get an orthogonal decomposition
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In paticular, is closed subspace of .
Therefore, for each ,
is a closed subspace of .
Similarly, (however we consider up to upper order boundary datum,) we also get the decomposition
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and that is a closed subspace of for all .
Moreover, we can show that and are injective in the same way as Proposition 6.11 in [10].
Consequently, we obtain the following:
Lemma 2.6.
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are smooth injective immersions.
Moreover, we can prove the following in the same way as Proposition 6.13 in [10]:
Lemma 2.7.
Let , then
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is a homeomorphism mapping onto a closed subspace of .
Therefore, in paticular, is an embedding.
The same statement also holds when we replace respectively and by and .
Remark 2.4.
The connectedness of was used in the proof of lemma 2.7
(see the proof of Proposition 6.13 in [10]).
Proof of the Theorem 2.1.
The proof is same as in [10].
Because we can show in the same way for , we only descrie about .
For , we set the orbit of the action through
(where is in the lemma 2.7).
From Lemma 2.7, this is a closed submanifold of
Moreover, we define its normal vector bundle:
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where
Our first step is constructing the normal bundle of in
As stated in [10], this Riemannian metric is strong on but is not on
Thus we do not know automatically that is a subbundle of
To show this, we shall find a surjective vector-bundle-map:
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such that
(see [19, Chapter3, Section3]).
Since, from the proof of the lemma 2.6,
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Hence, from the definition of
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Thus
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Moreover, since the weak Riemannian metric is invariant under the action of ([10, Section 4]),
On the orbit of we define
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Thus, as in the same way in [10, Theorem 7.1], we can show that this satisfy the above properties.
Next, we shall construct the slice of
To do this, we consider the exponential map of
Thus we know the following fact:
Fact 2.2 ([10, Section 4]).
This is a smooth map and is a diffeomorphism mapping a neighborhood of the zero section of
to a neighborhood of in
Moreover, since is continuous and and the action of are commutative,
there are a neighborhood of in and a neighborhood of in such that
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Then is a diffeomorphism mapping onto a neighborhood of
Moreover, if necessary, we shall take and small enough so that
Consider the strong inner product on defined as at the end of Section 4 in [10].
Now let be the metric defined on by
Let be the open ball about of radius with respect to
Then, for some positive
Pick so that if
then
Then we set
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and this has the three properties of a slice
(These are checked in the same way in [10, Section 7 and the proof of Theorem 7.1]).
3 Main Results
Before starting the proof of Main theorem, we shall line up some basic definitions below:
Definition 3.1 ([21]).
(1) A topological space is called ILH-space
if is an inverse limit of Hilbert spaces such that
and each inclusions are bounded linear operators.
(2) A topological space is called -ILH-manifold modeled on
if has the following (a) and (b):
(a) is an inverse limit of -Hilbert manifolds modeled on
such that
(b) For each and there is an open neighborhood and homeomorphism
from onto an open subset in which gives a -coordinate around in and satisfies
for all
(3) Let be a -ILH-manifold( ) and the tangent budle of The inverse limit of is called
ILH-tangent bundle of .
(4) Let be -ILH-manifolds.
A mapping is called -ILH-differentiable ( )
if is an inverse limit of -differentiable maping
(that is, for each there exists
and -map such that
for all
(5) is a ILH-manifold
if is a -ILH-manifold for all
(6) Let be -manifolds.
A mapping is called ILH-differentiable
if
is -ILH-differentiable for all
(7) Let be the tangent space of at and the inverse limit of
Let
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be the -th (Fréchet) derivative of at
Then,
has the inverse limit
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It is called -th derivative of and we denote it by
Let and be the same as in Section 2 and use the same notations there.
As in the closed case,
,
naturally become ILH-manifolds and the pullback-action
is ILH-differentiable.
Moreover, for a fixed metric on ,
since each are a submanifold of ,
is an ILH-submanifold of
and the inclusion is -differentiable.
And, is an ILH-submanifold of and
the inclusion is -differentiable.
Similarly, is an ILH-submanifold of
and the inclusion is -differenciable.
Note that the pull-back action
is also -differentiable.
By the Sobolev embedding for fibre bundles over manifold with boundary, we obtain the following
(see [4]):
Lemma 3.1.
Let be vector bundles over and let be a -differentiable which preserves each fibers.
Let .Then the bundle map induced by
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is -differentiable.
Proof.
Same as Lemma 1.1 in [18]. See also [23, Theorem 11.3].
∎
Using this lemma and that is a submanifold of ,
the following hold in the same as in [18]:
Lemma 3.2 ([18, Proposition1.2 , Corollary1.3 , Corollary1.4]).
(1)
is -differentiable, where is the type tensor bundle and is the Levi-Civita connection with respect to .
(2)
is -differentiable.
(3) Mappings listed below are -differentiable:
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Remark 3.1.
Since is an ILH submanifold of , the same statements hold in the above lemma replaced
by .
Let .
We define
,
,
,
,
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For we define
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by
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where are defined by fixed
is the outer unit normal vector along with respect to
and
Here, also denotes the volume measure with respect to
From
Lemma 3.2 and the trace theorem([13, Appendix B]),
is a -differentiable map from
to
And we define
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Then, the following holds:
Lemma 3.3.
is an open subset of
Proof.
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is a diffeomorphism mapping to .
On the other hand,
the set of all isomorphisms is open in
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with respect to the operator-norm.
Hence
is an open subset of .
∎
Lemma 3.4.
and
Proof.
Since the proof for is exactly the same as for ,
we will only prove for
Fix .
Firstly, we consider the case that .
Given ,
we consider two boundary value problem:
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where
We firstly consider (3).
For a fixed positive constant we consider
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Thus we can show that there is a unique solution by using standard variational argument.
Let
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be the operatopr corresponding to the above equation, then this is an elliptic operator in the sence of Definition 20.1.1 in [13].
Therefore,
from Theorem 20.1.2 in [13], is a Fredholm operator.
Hence
and is closed.
Moreover, because of the existence and uniqueness of the above boundary value problem,
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We shall back to (3). We consider the corresponding operator:
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then, this operator is also an elliptic operator.
From Theorem 20.1.8 in [13], and since
Hence
Therefore is surjective.
Next, we consider (2).
The ellipticity only depends on its principal symbol, thus (2) is also elliptic
(Exactly speaking, the operator corresponding to (2) is elliptic).
Let
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be the corresponding operator, then from Theorem 20.1.8 in [13] and the above things,
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Since
Thus
On the other hand, from the Green’s formula,
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Hence
Thus
Therefore is surjective if
Next, we consider the case that
The above observation implies that (2) has a unique solution up to constants.
That is, if we take a solution of (2), then ( is arbitrary constant) is also solution of this equation.
Hence, for given , we take a constant so that
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Then, from the above observation, there exists a solution of (3).
Therefore is also surjective if .
Let , then
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(5) |
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(6) |
Multiply the contents in { } of (5) by the left hand side of (4) and integration it over
Thus, by integration by parts, (4) and (5),
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On the other hand,
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Hence, from (6) and , the first term of the right hand side is zero. Thus, since , the second term also vanish.
Therefore, we have
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Hence, if , then .
On the other hand, if , we multiply the both sides of (7) by , integral over
use the integration by parts and get But, since ,
Therefore is injective.
( ) This inclusion is obvious.
∎
Lemma 3.5.
Proof.
Since we can construct a negative constant scalar curvature metric (see [8]).
Thus, since the eigenvalues of are positive([4, Theorem 4.4]), from Lemma 3.4,
∎
Lemma 3.6.
is an ILH-submanifold of
Proof.
For each , we define a map
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by
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From Lemma 3.2, this is a -differentiable map.
We note that .
In fact, if , then along
since .
And it is clear that the first two terms are zero if ,
hence the inclusion of holds.
On the other hand, for , then, since the first and second components are both zero,
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But, since the second component is zero and from the Green’s formula, this constant must be zero.
Thus, by multiplying by and integrating it over from integration by parts and the fact that the second component is zero,
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Hence
Since the third component is zero, we obtain
The derivative of at is calculated as follows(see [5, Theorem 1.174]):
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where denotes the second fundamental form of
Take the variation
Then, since
we get is surjective.
Therefore, from the Inverse function theorem ([22]),
is a submanifold of
and the tangent space at
is .
On the other hand, since
is an ILH submanifold of ,
is an ILH submanifold of
∎
Lemma 3.7.
Let and
be a map
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Then is -differentiable.
Moreover, if
then is an isomorphism.
Proof.
It is clear that this is a -differentiable map. In fact,
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Let ,then since
On the other hand, since
Hence, since
We shall show it by contradiction.
If is not surjective, then
(since
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is a closed subspace in ).
We define an operator on (which is a closed subspace in )
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From the Green’s formula,
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where is the formal adjoint of
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Since is defined on and
on
Therefore on
Hence the first three terms in the right hand side of the above equation vanish on .
Also, since
where denotes the derivative of the mean curvature at
And
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(cf. [3, Claim 3.1], [8, Section 2])
where denotes the second fundamental form on .
Since and , we obtain
Take a point Since ,
at
where and denote respectively a local normal coordinates at
with respect to such that and
the -th components of with respect to
Let be a local normal coordinates at with respect to such that and the components of with respect to
Then,
Hence and
we get
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Thus, from the proof of Lemma 2.6 (and the fact that the principal symbol of is surjective),
we can get an orthogonal decomposition(cf. the proof of Lemma 2.4 in [18]):
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From the hypothesis
and from the above decomposition,
(since, if , then it must be ).
Let , then
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But, since ,
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Thus we can see that the image of is included in .
Then, from the above equation and , we obtain .
Hence .
This contradicts that .
Therefore is surjective.
We will show that the image of is included in in the following.
As in the proof of lemma 2.6, there is a decomposition of
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where is the Lie derivative of and is the divergence operator with respect to .
Therefore, we can write that .
We firstly consider .
Let .
Since is the first derivative of the functional ,
is diffeomorphism invariant and
the derivative of the pull-back action of diffeomorphism on is (as mentioning in the proof of lemma 2.1),
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Hence .
Finally, we consider .
Then .
Since ,
we can write
for some
.
Note that on
In fact, since
on .
Hence, on
where and denote respectively the components of and in terms of some local coordinates.
On the other hand, on
since on and .
Therefore, on ,
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where denote the natural inner product on the (0,2)-tensor bundle of induced by
Here, as mentioning above, .
And
since and .
Consequently, we obtain
∎
We get the following lemma in the same way as Lemma 2.8 in [17]:
Lemma 3.8.
Let and be bector bundles over associated with the frame bundle. Any
defines a natural linear map (by pullback)
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Let be an open subset and let
be a -differentiable map which commutes with the action of .
Put .
Then and is -differentiable.
Theorem 3.1.
is an ILH-submanifold of and the map
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is a local ILH-diffeomorphism into .
Proof.
It can be proved exactly the same as the proof of Theorem 2.5 in [18] using lemma 3.7 and 3.8.
And note that .
∎
Since and are submanifold of and respectively,
from Lemma 3.8 and Theorem 2.1, we can obtain the following -version of the Slice theorem
exactly same as in [17]:
Theorem 3.2 (-version of Theorem 2.1).
For all there exists an ILH-submanifold containing
so that the following holds:
(1)
(2) and
(3) There exists a local section defined on an open neighborhood of
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such that
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is an ILH-diffeomorphism mapping onto an open nighborhood of
Consequently, from this Slice theorem and Theorem 3.1,
we can prove Main Theorem in Section 1.
Proof of Main Theorem.
From Theorem 3.1, we can decompose as
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where is a deformation of in and
is a deformation of in .
Moreover, from Theorem 3.2, can be decomposed as
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Since the scalar curvature is invariant under the action of diffeomorphisms,
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∎
Theorem 3.3.
For any and any smooth deformation
of for sufficiently small
there exists uniquely a smooth deformation of
a smooth one of
and a smooth one of
with
such that
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Proof.
Reverse the order of applying Theorem 3.1 and Theorem 3.2 in the proof of Main Theorem.
∎