Book free -Uniform Hypergraphs
Abstract
A -book in a hypergraph consists of Berge triangles sharing a common edge. In this paper we prove that the number of the hyperedges in a -book-free 3-uniform hypergraph on vertices is at most .
1 Introduction
Let be a graph. The vertex and the edge set of are denoted by and . If there are two triangles sitting on an edge in a graph, we call this a diamond. Whereas triangles sitting on an edge is called a -book, denoted by a . Similarly, let be a hypergraph and the vertex and the edge set of be denoted by and . A hypergraph is called -uniform if each member of has size . A hypergraph is called linear if every two hyperedges have at most one vertex in common. A Berge cycle of length , denoted by Berge-, is an alternating sequence of distinct vertices and distinct hyperedges of the form where for each and . The hypergraph equivalent of -books is defined similarly with Berge triangles sharing a common edge. We say that this common edge is the base of the -book.
The maximum number of edges in a triangle-free graph is one of the classical results in extremal graph theory and proved by Mantel in [13]. The extremal problem for diamond-free graphs follows from this. Given a graph on vertices and having edges. Mantel showed that contains a triangle. Rademacher (unpublished, and simplified later by Erdős in [6]) proved in the 1940s that the number of triangles in is at least . Erdős conjectured in 1962 [7] that the size of the largest book in is at least and this was proved soon after by Edwards (unpublished, see also Khadźiivanov and Nikiforov [11] for an independent proof).
Theorem 1 (Edwards [4], Khadźiivanov and Nikiforov [11]).
Every -vertex graph with more than edges contains an edge that is in at least triangles.
Both Rademacher’s and Edwards’ results are sharp. In the former, the addition of an edge to one part in the complete balanced bipartite graph (note that in there is an edge contained in triangles) achieves the maximum. In the latter, every known extremal construction of has triangles. For more details on book-free graphs we refer the reader to the following articles [2], [14] and [16]. We look into the equivalent problem in the case of hypergraphs.
Given a family of hypergraphs , we say that a hypergraph is -free if for every , the hypergraph does not contain a as a sub-hypergraph.
The systematic study of the Turán number of Berge cycles started with Lazebnik and Verstraëte [12], who studied the maximum number of hyperedges in an -uniform hypergraph containing no Berge cycle of length less than five. Another result was the study of Berge triangles by Győri [8]. He proved that:
Theorem 2 (Győri [8]).
The maximum number of hyperedges in a Berge triangle-free -uniform hypergraphs on vertices is at most .
It continued with the study of Berge five cycles by Bollobás and Győri [3]. In [9], Győri, Katona, and Lemons proved the following analog of the Erdős-Gallai Theorem [5] for Berge paths. For other results see [1, 10]. The particular case of determining the maximum number of the hyperedges of a triangle-free linear hypergraph on vertices is equivalent to the famous -problem, which is a special case of a general problem of Brown, Erdős, and Sós. The following theorem of Ruzsa and Szemerédi plays important role in our paper:
Theorem 3 (Ruzsa and Szemerédi [15]).
For any the exists such that if then a Berge-triangle-free 3-uniform linear hypergraph on vertices has at most hyperedges.
We continue the work on that and determine the maximum number of hyperedges for a -book-free -uniform hypergraph. The main result is as follows:
Theorem 4.
For a given and there exists such that if then a -uniform -free hypergraph on vertices can have at most edges.
The following example shows that this result is asymptotically sharp. Take a complete bipartite graph with color classes of size and respectively. Denote the vertices in each class with and respectively. Construct a graph by doubling each vertex and replacing each edge with two hyperedges as shown below (Figure 1). So essentially, we have replaced every graph edge with two hyperedges. The construction does not contain a , as it does not contain a Berge triangle. With this, the number of hyperedges is .
2 Proof of Theorem 4
Fix , and set
where is from Theorem 3. Suppose that . Let be a -free -uniform hypergraph on vertices. We are interested in the -shadow, i.e., let be a graph with vertex set and
If an edge in lies in more than one hyperedge in , we color it blue. Otherwise, we color it red. We define hypergraphs and in the following way. ,
and . Note that each hyperedge in contains two or three blue edges of .
Claim 5.
The number of hyperedges in is at most .
Proof.
Denote the subgraph of formed by the red colored edges by . Suppose that . By Theorem 1 we have a book of size in . Denote the vertices of the -book in with and , respectively where is the base of the book. Denote the third vertex of the hyperedge containing edge by , set and for each denote the hyperedge containing and by and respectively.
Set and . Go through the vertices of and perform the following procedure for each of them. At the beginning of the process no vertex is marked.
If the current vertex then mark it.
If is unmarked then
-
•
add to and hyperedges and to ,
-
•
if there exists such that then mark ,
-
•
if there exists such that then mark .
By definition of red edges and the procedure (i.e. it adds two new hyperedges to forming a Berge triangle with at each step handling an unmarked vertex but at most one: when ) the set of hyperedges with vertex set form a -book with base , where . Moreover at each step of the procedure whenever an unmarked vertex was added to then at most two more vertices became marked. Each unmarked vertex are in at the end of the procedure, therefore
at the end of the procedure and it is at least by the definition of , but this is a contradiction.
Hence and
by the definition of red colored edges. ∎
Now let us work on the sub-hypergraph .
Claim 6.
Each pair of vertices is contained in at most hyperedges of .
Proof.
Suppose that is a pair of vertices which is contained in hyperedges of . Note that edge is colored blue. Denote the third vertices of hyperedges containing and by and set . Observe that for each at least one of and is colored blue.
Set and . Go through the vertices of and perform the following procedure for each of them. At the beginning of the process no vertex is marked.
If the current vertex and there is no marked vertex in then do nothing.
Otherwise if is unmarked then
-
•
add to and add to ,
-
•
if is colored blue denote a hyperedge containing it by where and add to ,
-
•
otherwise is colored blue, so denote a hyperedge containing it by where and add to ,
-
•
if there exists such that then mark .
If at the end of the procedure there is no marked vertex in then set otherwise let be an arbitrary marked vertex.
By definition of blue edges and the procedure (i.e. it adds two new hyperedges to forming a Berge triangle with at each step handling an unmarked vertex but at most the last one) the set of hyperedges with vertex set form a -book with base where . Moreover if there is no marked vertex in at the end of the process then , otherwise at each step of the procedure whenever an unmarked vertex was added to than at most one more vertex became marked and each unmarked vertex are in at the end of the procedure. Therefore , but it is a contradiction. ∎
We now give an upper bound on the number of hyperedges in .
Claim 7.
The number of hyperedges in is at most .
Proof.
Take a hyperedge in the sub-hypergraph . By Claim 6 there are at most hyperedges of containing each of the pairs of vertices , , and . If we deleted all such hyperedges barring we would delete at most hyperedges. Therefore there is a linear 3-uniform subhypergraph of with and
(i.e. a greedy algorithm can find an appropriate ).
Consider a hyperedge in . Observe that is a -free hypergraph, since it is a subhypergraph of , therefore the number of Berge triangles sitting on the edge is at most . Apply the following greedy procedure until all the hyperedges are marked. In a step pick an unmarked hyperedge, mark it and delete an unmarked hyperedge of each Berge triangle containing the current hyperedge. Observe that this marked edge is not an edge of a triangle anymore. Define the following way. Let and contains the remaining hyperedges of . Observe that at most edges were deleted in each step and marked edges were never deleted. Therefore
Moreover is a Berge-triangle-free 3-uniform linear hypergraph therefore Theorem 3 can be applied with . We get that
∎
3 Conclusions
Recall that both Turán numbers of triangle-free graph and -book-free graphs on vertices are , moreover Győri [8] proved that the maximum number of hyperedges in a Berge triangle-free -uniform hypergraphs on vertices is at most . Given the similarities, we conjecture the following:
Conjecture 1.
For a given every -uniform -free hypergraph on vertices ( is large) has at most hyperedges.
4 Acknowledgements
Győri’s research was partially supported by the National Research, Development and Innovation Office NKFIH, grants K132696, K116769, and K126853. Judit Nagy-György acknowledges support by the project TKP2021-NVA-09. Project no. TKP2021-NVA-09 has been implemented with the support provided by the Ministry of Innovation and Technology of Hungary from the National Research, Development and Innovation Fund, financed under the TKP2021-NVA funding scheme. Nagy-György’s research was partially supported by the National Research, Development and Innovation Office NKFIH, grant KH129597.
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