This paper was converted on www.awesomepapers.org from LaTeX by an anonymous user.
Want to know more? Visit the Converter page.

An alternate proof of Payan’s theorem on cubelike graphs

Jonathan Cervantes University of California, Riverside, Dept. of Mathematics, Skye Hall, 900 University Ave., Riverside, CA 92521, [email protected] Mike Krebs California State University, Los Angeles, Dept. of Mathematics, 5151 State University Drive, Los Angeles, CA 91711, [email protected]
Abstract

A cubelike graph is a Cayley graph on the product 2××2\mathbb{Z}_{2}\times\cdots\times\mathbb{Z}_{2} of the integers modulo 22 with itself finitely many times. In 1992, Payan proved that no cubelike graph can have chromatic number 33. The authors of the present paper previously developed a general matrix method for studying chromatic numbers of Cayley graphs on abelian groups. In this note, we apply this method of Heuberger matrices to give an alternate proof of Payan’s theorem.

Keywords— graph, chromatic number, abelian group, Cayley graph, cube-like graph, Payan’s theorem

1 Introduction

Given a finite set AA, we take 𝒫(A)\mathcal{P}(A) to be the power set of AA. We have that 𝒫(A)\mathcal{P}(A) is an abelian group under the operation of symmetric difference, that is, XY=(XY)(YX)X\triangle Y=(X\setminus Y)\cup(Y\setminus X). A cubelike graph is a Cayley graph whose underlying group is 𝒫(A)\mathcal{P}(A). Equivalently, writing A={x1,,xn}A=\{x_{1},\dots,x_{n}\} and identifying the set XAX\subset A with the nn-tuple whose iith component is 11 if xiXx_{i}\in X and is 0 otherwise, a cubelike graph can be regarded as a Cayley graph whose underlying group is an nn-fold product 2n=2××2\mathbb{Z}_{2}^{n}=\mathbb{Z}_{2}\times\cdots\times\mathbb{Z}_{2}, where 2\mathbb{Z}_{2} is the group of the integers modulo 22 under addition.

Chromatic numbers of cubelike graphs have been studied by many authors. One notable result is due to Payan [4], who proved that the chromatic number of a nonbipartite cubelike graph is always at least 44. That is, the chromatic number of a cubelike graph cannot equal 33. Publications with other results on chromatic numbers of cube-like graphs include [3] and [2, Section 9.7].

Payan’s proof is rather clever. It is, however, somewhat ad hoc. The purpose of the present note is to furnish an alternate proof of Payan’s theorem, one that may lend itself naturally to generalizations.

Indeed, in [1], the authors put forward a general method for approaching the problem of finding the chromatic number of a Cayley graph on an abelian group. We show that Payan’s theorem falls out quite naturally as a byproduct of this “method of Heuberger matrices.”

The other key ingredient in our proof is a special case of Payan’s theorem due to Sokolová [5], who computed that even-dimensional cubes-with-diagonals (defined below) have chromatic number 44. The key idea of our proof of Payan’s theorem is that if a cubelike graph is nonbipartite, then there is a graph homomorphism to it from an even-dimensional cube-with-diagonals. The Heuberger matrices make transparent the existence of this homomorphism.

This note depends heavily on [1], which we will refer to frequently. The reader should assume that all notation, terminology, and theorems used but not explained here are explained there.

2 Payan’s theorem

In this section we prove the following theorem.

Theorem 2.1 ([4]).

A cube-like graph cannot have chromatic number 3.

Throughout this section we take cube-like graph to be a Cayley graph on 2n\mathbb{Z}_{2}^{n}.

A special case of Theorem 2.1 had previously been proven by Sokolová in [5]. We will derive Payan’s theorem from Sokolová’s theorem, and for that reason we begin by discussing the latter.

For a positive integer nn, the nn-dimensional cube-with-diagonals graph QndQ^{d}_{n} is defined by

Qnd=Cay(2n,{e1,,en,wn}),Q_{n}^{d}=\text{Cay}(\mathbb{Z}_{2}^{n},\{e_{1},\dots,e_{n},w_{n}\}),

where eje_{j} is the nn-tuple in 2n\mathbb{Z}_{2}^{n} with 11 in the jjth entry and 0 everywhere else, and wnw_{n} is the nn-tuple in 2n\mathbb{Z}_{2}^{n} with 11 in every entry. We can visualize QndQ^{d}_{n} as a hypercube with edges (called “diagonals,” hence the name and the superscript ‘dd’) added to join each pair of antipodal vertices. Sokolová proved that for nn even, QndQ^{d}_{n} has chromatic number 44. We present here a condensed version of the proof in [5] of this result.

Theorem 2.2 ([5]).

If nn is even, then χ(Qnd)=4\chi(Q_{n}^{d})=4.

Proof.

First observe that (x1,,xn)(x1,x2++xn)(x_{1},\dots,x_{n})\mapsto(x_{1},x_{2}+\cdots+x_{n}) defines a group homomorphism from 2n\mathbb{Z}^{n}_{2} to 22\mathbb{Z}^{2}_{2} mapping {e1,,en,wn}\{e_{1},\dots,e_{n},w_{n}\} to {(1,0),(0,1),(1,1)}\{(1,0),(0,1),(1,1)\}. So this defines a graph homomorphism from QndQ^{d}_{n} to Q2dK4Q_{2}^{d}\cong K_{4}, the complete graph on 44 vertices. Hence χ(Qnd)4\chi(Q_{n}^{d})\leq 4.

Next we show that QndQ^{d}_{n} is not properly 33-colorable. We do so by induction. For the base case (n=2n=2), we saw previously that Q2dK4Q^{d}_{2}\cong K_{4}, which is not properly 33-colorable. Now assume that QndQ^{d}_{n} is not properly 33-colorable, and we will show that Qn+2dQ^{d}_{n+2} is not properly 33-colorable. Suppose to the contrary that c:2n+23c\colon\mathbb{Z}^{n+2}_{2}\to\mathbb{Z}_{3} is a proper 33-coloring. For two tuples v=(v1,,vj)v=(v_{1},\dots,v_{j}) and u=(u1,,uk)u=(u_{1},\dots,u_{k}), we define vu=(v1,,vj,u1,,uk)v*u=(v_{1},\dots,v_{j},u_{1},\dots,u_{k}). Define c:2n3c^{\prime}\colon\mathbb{Z}^{n}_{2}\to\mathbb{Z}_{3} by c(v)=kc^{\prime}(v)=k if {c(v(0,0)),c((v+wn)(1,0))}\{c(v*(0,0)),c((v+w_{n})*(1,0))\} equals either {k}\{k\} or {k,k+1}\{k,k+1\}. A straightforward case-by-case analysis shows that cc^{\prime} is a proper 33-coloring of QndQ^{d}_{n}, which is a contradiction.∎

Remark 2.3.

We briefly digress to remark that Sokolová’s theorem can be restated as follows. In any (not necessarily proper) 33-coloring of the vertices of an even-dimensional hypercube, there must exist two antipodal vertices, both of which are assigned the same color. Stated this way, it brings to mind various topological theorems such as the hairy ball theorem and the Borsuk–Ulam theorem. We wonder whether there might be some connection between Sokolová’s combinatorial result and one or more of these facts from topology, perhaps along the lines of the connection between Sperner’s lemma and the Brouwer fixed point theorem. \square

Using Heuberger matrices, we will now see how Sokolová’s theorem implies Payan’s theorem. The key idea is to show that every nonbipartite cube-like graph contains a homomorphic image of an even-dimensional cube-with-diagonals graph.

Proof of Theorem 2.1.

Let X=Cay(2n,S)X=\text{Cay}(\mathbb{Z}_{2}^{n},S) be a nonbipartite cube-like graph. Because 2x=02x=0 for all xSx\in S, there is a Heuberger matrix MXM_{X} associated to XX whose last mm columns are 2e1,,2em2e_{1},\dots,2e_{m}, where m=|S|m=|S|. That is, MXM_{X} has the form (A| 2Im)(A\;|\;2I_{m}) for some integer matrix AA. Here ImI_{m} is the m×mm\times m identity matrix. Using column operations as in [1, Lemma LABEL:general-lemma-isomorphisms], we have that

(A| 2Im)XSACG(A| 2Im)XSACG,(A\;|\;2I_{m})_{X}^{\text{SACG}}\cong(A^{\prime}\;|\;2I_{m})_{X}^{\text{SACG}},

for some matrix AA^{\prime} whose entries are all in {0,1}\{0,1\}. Because XX is nonbipartite, by [1, Lemma LABEL:general-lemma-bipartite], some column yy of AA^{\prime} contains an odd number zz of nonzero entries. Hence by [1, Lemma LABEL:general-lemma-homomorphisms, parts (LABEL:general-lemma-homomorphisms-append-columns) and (LABEL:general-lemma-homomorphisms-append-zero-row)], we have homomorphisms

(wzt| 2Iz)YSACG\ocircτ1(y 2ei1 2eiz)SACG\ocircτ2(A| 2Im)XSACG(w_{z}^{t}\;|\;2I_{z})_{Y}^{\text{SACG}}\xrightarrow[\tau_{1}]{\ocirc}(y\;2e_{i_{1}}\;\cdots\;2e_{i_{z}})^{\text{SACG}}\xrightarrow[\tau_{2}]{\ocirc}(A^{\prime}\;|\;2I_{m})_{X}^{\text{SACG}}

where i1,,izi_{1},\dots,i_{z} are the indices of the nonzero entries of yy, and wztw_{z}^{t} is a column vector of length zz with a 11 in every entry. For τ1\tau_{1}, we insert zero rows as appropriate; for τ2\tau_{2} we append the requisite columns. So χ(Y)χ(X)\chi(Y)\leq\chi(X) by [1, Lemma LABEL:general-lemma-pullback]. If z=1z=1, then XX has loops and is not properly colorable. So assume z3z\geq 3. Observe that YQz1dY\cong Q_{z-1}^{d}. An application of Theorem 2.2 then completes the proof.∎

References

  • [1] J. Cervantes and M. Krebs, Chromatic numbers of Cayley graphs of abelian groups: A matrix method, www.arxiv.org.
  • [2] Tommy R. Jensen and Bjarne Toft, Graph coloring problems, Wiley-Interscience Series in Discrete Mathematics and Optimization, John Wiley & Sons, Inc., New York, 1995, A Wiley-Interscience Publication.
  • [3] Janne I. Kokkala and Patric R. J. Östergård, The chromatic number of the square of the 8-cube, Math. Comp. 87 (2018), no. 313, 2551–2561.
  • [4] Charles Payan, On the chromatic number of cube-like graphs, Discrete Math. 103 (1992), no. 3, 271–277.
  • [5] Marie Sokolová, The chromatic number of extended odd graphs is four, Časopis Pěst. Mat. 112 (1987), no. 3, 308–311.