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A Sufficient Condition for Blowup of the Nonlinear Klein-Gordon Equation with Positive Initial Energy in FLRW Spacetimes

Abstract.

In this paper we demonstrate a sufficient condition for blowup of the nonlinear Klein-Gordon equation with arbitrarily positive initial energy in Friedmann-Lemaître-Robertson-Walker spacetimes. This is accomplished using an established concavity method that has been employed for similar PDEs in Minkowski space. This proof relies on the energy inequality associated with this equation, E(t0)E(t)E(t_{0})\geq E(t), also proved herein using a geometric method.


Jonathon McCollum 111email address: [email protected],⋆, Gregory Mwamba 222email address: [email protected],#, and Jesús Oliver 333email address: [email protected],†


Oregon State University,
Department of Mathematics,
Kidder Hall 368,
Corvallis, Oregon, USA, 97331-4605


#University of California, Merced,
Department of Applied Mathematics,
5200 North Lake Road,
Merced, California, USA, 95343


California State University East Bay,
Department of Mathematics,
25800 Carlos Bee Boulevard,
Hayward, California, USA, 94542

1. Introduction

The nonlinear Klein-Gordon equations are a class of important evolution equations that describe the movement of spinless relativistic particles, which can lend understanding in many physical applications (see [8] and references therein). In this paper we consider the question of finite time blow up for a nonlinear class of Klein-Gordon equations propagating on a fixed cosmological spacetime. We have adapted the methods of Yang & Xu in [8] and Wang in [7], both of which prove blowup results for solutions to the Klein-Gordon equation in a non-expanding spacetime. The result from [7] was the first to show a condition for blowup using this general method, and this work was expanded upon in [8] to broaden the conditions that reliably lead to blowup. Both of these were done under the assumption of a Minkowski background metric – for which energy conservation for Klein-Gordon is readily available. On the other hand, our work focuses on adapting this method of proof to backgrounds that include expanding spacetimes – for which only an energy inequality is available. Due to the accelerating nature of the expansion of the observable universe, such cosmological spacetimes are of general interest. The results in this paper also supplement those in [2]. In that work, the authors establish small data global existence for a class of semilinear Klein-Gordon equations propagating in a family of expanding cosmological backgrounds which include the de Sitter spacetime. On the other hand, in this paper we are considering large initial data satisfying a specific set of conditions that ensure L2L^{2} blow up in finite time.

The general concavity method employed to prove the blowup result in this paper, along with in [7] and [8], is based on the work of Levine in [3] and [4], which has been a common wellspring for such results. This method relies on identifying time invariant spaces, then proving that solutions in this invariant space must blowup based on consistent negative concavity and slope of a functional based on this solution. As mentioned, we employ this method to classes of solutions of the Klein-Gordon equation, though in more generality than [8] and [7] by considering all metrics that have a certain restriction on the expanding factor. The fact that there must be restrictions on the expanding factor should satisfy intuition that aggressively expanding spacetimes would create problems with local existence for fluids and would smooth out initial data too quickly to allow for blowup. Furthermore, this method requires some assumptions on the initial data relative to the initial energy which is necessary for the concavity argument and can be broken down into cases (listed in Table 1 below). This table is adapted from Yang & Xu in [8] to illustrate our results as well as the remaining unsolved problems in the context of cosmological spacetimes. Note that our assumption (2.13) follows directly from Cases II & III.


Table 1: Obtained results and unsolved problems.

Case I Initial data leading to high energy blowup of problem (2.4)
I(u0)<0I\left(u_{0}\right)<0 u023(ϵ+2)m~2ϵE(t0)\left\|u_{0}\right\|^{2}\geq\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0}) 3(ϵ+2)m~2ϵE(t0)>(u0,u1)>0\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>\left(u_{0},u_{1})\right.>0 Still open
Case II I(u0)<0I\left(u_{0}\right)<0 u023(ϵ+2)m~2ϵE(t0)\left\|u_{0}\right\|^{2}\geq\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0}) (u0,u1)3(ϵ+2)m~2ϵE(t0)>0\left(u_{0},u_{1}\right)\geq\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>0 Solved in this paper
Case III I(u0)<0I\left(u_{0}\right)<0 3(ϵ+2)m~2ϵE(t0)>u02\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>\left\|u_{0}\right\|^{2} (u0,u1)3(ϵ+2)m~2ϵE(t0)>0\left(u_{0},u_{1}\right)\geq\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>0 Solved in this paper
Case IV I(u0)<0I\left(u_{0}\right)<0 3(ϵ+2)m~2ϵE(t0)>u02\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>\left\|u_{0}\right\|^{2} 3(ϵ+2)m~2ϵE(t0)>(u0,u1)>0\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>\left(u_{0},u_{1}\right.)>0 Still open

As our work follows directly from the method in [8], we do not have any specific conditions on the u02||u_{0}||^{2} term. Their process removed specific consideration of this term that had been present in [7], and so covered the Case II and Case III with this value having no specific relationship to the bounding constant. So while a lower bound on this quantity was required for [7], our method has no such requirement and therefore covers the two cases.

2. Setup and main theorem

Let nn\in\mathbb{N} and (,𝐠)(\mathcal{M},{\mathbf{g}}) be a Friedmann-Lemaître-Robertson-Walker (FLRW) spacetime with topology +×n\mathbb{R}^{+}\times\mathbb{R}^{n} and metric

(2.1) 𝐠:=dt2+a(t)2(dx12+dx22++dxn2).{\mathbf{g}}:=-dt^{2}+a(t)^{2}\big{(}dx_{1}^{2}+dx_{2}^{2}+...+dx_{n}^{2}\big{)}.

Let m0m\neq 0 and g\Box_{g} be the covariant wave operator associated to 𝐠\mathbf{g} defined by

(2.2) 𝐠u:=1|𝐠|α(𝐠αβ|𝐠|βu),\square_{{\mathbf{g}}}u:=\frac{1}{\sqrt{|{\mathbf{g}}|}}\partial_{\alpha}\left({\mathbf{g}}^{\alpha\beta}\sqrt{|{\mathbf{g}}|}\partial_{\beta}u\right),

where |𝐠|=det(𝐠αβ)|{\mathbf{g}}|=-\det({\mathbf{g}}_{\alpha\beta}), 𝐠αβ{\mathbf{g}}^{\alpha\beta} are the components of the inverse of 𝐠αβ{\mathbf{g}}_{\alpha\beta}, and greek indices run from 0 to nn. For the FLRW metric (2.1),we have

(2.3) 𝐠u=uttna˙aut+1a2Δu,\square_{{\mathbf{g}}}u=-u_{tt}-n\frac{{\dot{a}}}{a}u_{t}+\frac{1}{a^{2}}\Delta u,

with Δ\Delta denoting the Laplacian operator on the nn-dimensional flat metric

Δ:=i=1n2xi2.\Delta:=\sum_{i=1}^{n}\frac{\partial^{2}}{\partial x^{2}_{i}}.

Let 0<t0<T0<t_{0}<T, t[t0,T)t\in[t_{0},T), and xnx\in\mathbb{R}^{n}. In this work we study solutions to the Cauchy problem for the nonlinear Klein-Gordon equation

(2.4) {𝐠u+m2u=f(u)u(t0,x)=u0(x),ut(t0,x)=u1(x).\begin{cases}&-\square_{{\mathbf{g}}}u+m^{2}u=f(u)\\ &u(t_{0},x)=u_{0}(x),\ u_{t}(t_{0},x)=u_{1}(x).\end{cases}

where u0H01(n)u_{0}\in H_{0}^{1}(\mathbb{R}^{n}) and u1L2(n)u_{1}\in L^{2}(\mathbb{R}^{n}). This Cauchy problem describes a local self-interaction for a massive scalar field. In quantum field theory the matter fields are described by a function u:[t0,T)×nu:[t_{0},T)\times\mathbb{R}^{n}\rightarrow\mathbb{R} that must satisfy equations of motion. In the case of a massive scalar field, the equation of motion is the semilinear Klein-Gordon equation in (2.4).

We now specify the assumptions in our work.

2.1. Admissible nonlinearities

For the function f:f:\mathbb{R}\rightarrow\mathbb{R}, we will assume that there exists ϵ>0\epsilon>0 such that

(2.5) f(s)s(2+ϵ)F(s) and F(s):=0sf(ξ)𝑑ξ.f(s)s\geq(2+\epsilon)F(s)\qquad\mbox{ and }\qquad F(s):=\int_{0}^{s}f(\xi)\ d\xi.

Let us consider an example of a type of nonlinearity that satisfies condition (2.5): Take f(u)=upf(u)=u^{p} with p>1p>1; it follows that

sps(2+ϵ)sp+1p+1p+1(2+ϵ).s^{p}s\geq(2+\epsilon)\frac{s^{p+1}}{p+1}\qquad\Rightarrow\qquad p+1\geq(2+\epsilon).

Hence power nonlinearities with p1+ϵp\geq 1+\epsilon will satisfy Eq.(2.5). Another example of an admissible nonlinearity is the case of a focusing power nonlinearity f(u)=|u|p1uf(u)=|u|^{p-1}u. The defocusing power nonlinearity f(u)=|u|p1uf(u)=-|u|^{p-1}u is a non-example of an admissible nonlinearity.

Next we describe assumptions on the admissible nonlinearities that are needed to ensure local wellposedness for problem (2.4).

Definition: A function h:=h(x,s)h:=h(x,s), h:n×h:\mathbb{R}^{n}\times\mathbb{R}\rightarrow\mathbb{R} is said to be Lipshitz continuous in ss with exponent α\alpha, if there exist α0\alpha\geq 0 and C>0C>0 such that

|h(x,s)h(x,v)|C|sv|(|s|α+|v|α)for all s,v,xn.|h(x,s)-h(x,v)|\leq C|s-v|(|s|^{\alpha}+|v|^{\alpha})\qquad{\text{for all }}s,v\in\mathbb{R},x\in\mathbb{R}^{n}.

In our work we will assume that f(s)f(s) satisfies the following two assumptions:

  1. 1)

    f(0)=0f(0)=0,

  2. 2)

    ff is Lipshitz continuous with exponent 0α2n20\leq\alpha\leq\frac{2}{n-2}.

The restriction on the exponent α\alpha is needed for local wellposedness for problem (2.4) to hold. We discuss this in more detail in Section 3.

2.2. Assumptions on the expanding factor a(t)a(t)

We consider cosmologies undergoing an accelerated expansion in the direction of positive time tt. This expansion corresponds to

(2.6) a(t)>0anda˙(t):=dadt>0,a(t)>0\qquad{\text{and}}\qquad\dot{a}(t):=\frac{da}{dt}>0\ ,

for all t>0t>0. Let a0:=a(t0)a_{0}:=a(t_{0}), a˙0:=a˙(t0)\dot{a}_{0}:=\dot{a}(t_{0}); we assume that there exists a t0>0t_{0}>0 such that

(2.7) a˙(t)a(t)a˙0a0ϵ6n,\frac{\dot{a}(t)}{a(t)}\leq\frac{\dot{a}_{0}}{a_{0}}\leq\frac{\epsilon}{6n}\ ,

holds for all tt0t\geq t_{0}. This assumption is essential in order to treat the effect of the accelerated expansion perturbatively.

Next we codify an assumption on the mass mm and the expanding factor a(t)a(t) that is needed for local wellposedness for problem (2.4) to hold. Define the curved mass M(t)M(t) (see [2]) to be

(2.8) M2(t):=m2+(n2n24)(a˙(t)a(t))2n2a¨(t)a(t).M^{2}(t):=m^{2}+\Big{(}\frac{n}{2}-\frac{n^{2}}{4}\Big{)}\Big{(}\frac{\dot{a}(t)}{a(t)}\Big{)}^{2}-\frac{n}{2}\frac{\ddot{a}(t)}{a(t)}.

We make the following assumption on M(t)M(t): there exists a c0>0c_{0}>0 such that

(2.9) M(t)>c0>0,M˙(t)0,for all t[t0,).M(t)>c_{0}>0,\qquad\dot{M}(t)\leq 0,\qquad{\text{for all }}t\in[t_{0},\infty).

This assumption will be satisfied by the FLRW and de Sitter metrics under suitable conditions on the parameters. See Section 2.4 for more details.

2.3. Norms, energy, and modified Nehari functional.

We denote the L2L^{2} norm and inner product by

u:=uL2(n):=(nu2𝑑x)1/2,(u,v):=n(uv)𝑑x.\displaystyle\|u\|:=\|u\|_{L^{2}(\mathbb{R}^{n})}:=\Big{(}\int_{\mathbb{R}^{n}}u^{2}dx\Big{)}^{1/2}\ ,\qquad(u,v):=\int_{\mathbb{R}^{n}}(uv)\ dx\ .

We define the functional spaces

H1\displaystyle H^{1} :=H1(n):={uL2|uH1=(1Δ)1/2u<+},\displaystyle:=H^{1}(\mathbb{R}^{n}):=\Big{\{}u\in L^{2}\ \big{|}\ \|u\|_{H^{1}}=\|(1-\Delta)^{1/2}u\|<+\infty\Big{\}},
H01\displaystyle H_{0}^{1} :=H01(n):={uH1| supp(u) is compact in n}.\displaystyle:=H_{0}^{1}(\mathbb{R}^{n}):=\Big{\{}u\in H^{1}\ \big{|}\ {\text{ supp$(u)$ is compact in $\mathbb{R}^{n}$}}\Big{\}}.

The energy for this problem is defined to be

(2.10) E(t):=12(ut2+m2u2+1a2u22nF(u)𝑑x),E(t):=\frac{1}{2}\left(\|u_{t}\|^{2}+m^{2}\|u\|^{2}+\frac{1}{a^{2}}\|\nabla u\|^{2}-2\int_{\mathbb{R}^{n}}F(u)\ dx\right),

where u\nabla u denotes the spatial gradient of uu. We also define the modified Nehari functional

(2.11) I(u):=n(m2u2+1a2(u)2+na˙am~2uutuf(u))𝑑x.I(u):=\int_{\mathbb{R}^{n}}\left(m^{2}u^{2}+\frac{1}{a^{2}}(\nabla u)^{2}+n\frac{\dot{a}}{a}\tilde{m}^{2}uu_{t}-uf(u)\right)dx.

Note that because of utu_{t}, the modified Nehari functional I(u)I(u) is defined on functions that depend on time. Since I(u)I(u) is a function of time tt, we will use the notation I(u(t))I(u(t)) when we wish to emphasize this fact. Now we define the unstable set for the Nehari functional

(2.12) :={uC([t0,T);H01(n))C1([t0,T);L2(n))|I(u)<0}.\mathcal{B}:=\{u\in C([t_{0},T);H_{0}^{1}(\mathbb{R}^{n}))\cap C^{1}([t_{0},T);L^{2}(\mathbb{R}^{n}))\ |\ I(u)<0\}.

The functional space in this definition comes directly from the regularity given by local wellposedness theorem in section 3. The key here is that our assumptions guarantee that the sign condition I(u(t))<0I(u(t))<0 will be preserved by the flow. This fact is proved in section 6.1.

In the following, we will work as if uu is smooth and supported away from spatial infinity. This assumption can be removed by a standard approximation argument.

2.4. Statement of main theorem

We are now ready to state our main result.

Theorem 1.

Suppose that there exists ϵ>0\epsilon>0 such that Eq. (2.5) is satisfied. Assume that f(0)=0f(0)=0 and that f(s)f(s) is Lipshitz continuous with exponent 0α2n20\leq\alpha\leq\frac{2}{n-2}. Suppose that the expanding factor a(t)a(t) satisfies Eq. (2.6) and that the initial time t0t_{0} satisfies Eq. (2.7). Assume that m>0m>0, and let m~=min{1,m}\tilde{m}=min\{1,m\}. Further, assume that there is a positive number c0c_{0} such that the curved mass M(t)M(t) satisfies (2.9). Let u0(x)H01u_{0}(x)\in H_{0}^{1} and u1(x)L2u_{1}(x)\in L^{2}. Suppose that u0,u1u_{0},u_{1} are such that I(u(t0))<0I(u(t_{0}))<0 and that

(2.13) (u0,u1)2(ϵ+2)m~2(ϵ2n(a˙0a0))E(t0)=3(ϵ+2)m~2ϵE(t0)>0,(u_{0},u_{1})\geq\frac{2(\epsilon+2)}{\tilde{m}^{2}\big{(}\epsilon-2n\big{(}\frac{\dot{a}_{0}}{a_{0}}\big{)}\big{)}}E(t_{0})=\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>0\ ,

holds for the initial data. Then the corresponding local solution to (2.4) blows up in finite time. Furthermore, the maximal time of existence TmaxT_{max} has the explicit upper bound

Tmax<t0+B(t0)ϵB(t0),T_{max}<t_{0}+\frac{B(t_{0})}{\epsilon B^{\prime}(t_{0})}\ ,

with

B(t):=mu2,B(t):=2(m2u,ut).B(t):=\|mu\|^{2}\ ,\qquad B^{\prime}(t):=2(m^{2}u,u_{t})\ .

One of the advantages of this result is the simple, explicit form for the upper bound TmaxT_{max}; from this form one can readily infer how each parameter affects the time of existence. For instance, larger ϵ\epsilon results in shorter time of existence. Similarly, larger inner product B(t0):=2(m2u(t0),ut(t0))B^{\prime}(t_{0}):=2(m^{2}u(t_{0}),u_{t}(t_{0})) also results in shorter time of existence. From our main theorem we can also read off how some commonly referenced cosmological backgrounds affect TmaxT_{max}: For example, for FLRW with power expansion a(t)=tka(t)=t^{k}, we have

a˙(t)a(t)=kt\frac{\dot{a}(t)}{a(t)}=\frac{k}{t}

and therefore t0=6nk/ϵt_{0}=6nk/\epsilon. Patching this together with the local existence result means that as kk increases, we have a larger and larger region of safety. So in this case, the faster the expansion, the longer it takes for the nonlinear effects to kick in. By contrast, in the cases of Minkowski spacetime a(t)=1a(t)=1 or de Sitter a(t)=eHta(t)=e^{Ht}, the choice of initial time t0>0t_{0}>0 has no effect on the upper bound TmaxT_{max}.

As mentioned in the introduction, this result is complementary to the result in [2]. In that work, the authors prove small data global existence for a class of semilinear Klein-Gordon equations propagating in a family of expanding cosmological backgrounds which include de Sitter. The main point of departure from that work is the fact that here we are considering large initial data in H01×L2H_{0}^{1}\times L^{2}. This comes from the fact that our initial condition (2.13) excludes the possibility of small initial data in these functional spaces. In particular, our initial conditions imply that the norm of initial data cannot be too small due to the existence of a positive lower bound for the H1H^{1} norm at the initial time t0t_{0}. For the interested reader, we prove this fact in an Appendix at the end of this manuscript.

2.5. Applicable cosmology examples

Two of the most commonly referenced cosmological backgrounds have expanding factors that allow the use of our method. For certain combinations of parameters, FLRW space with expanding factor a(t)=tka(t)=t^{k}, k>0k>0 works as long as our initial time is spaced far enough forward from the singularity at t=0t=0. De Sitter space works as long as the Hubble constant H>0H>0 is suitably low. We present the relevant computations here.

2.5.1. De Sitter

For the de Sitter metric, we have a(t)=eHta(t)=e^{Ht}, with H>0H>0. In this case we get

a˙(t)a(t)=H.\frac{\dot{a}(t)}{a(t)}=H.

Thus we require that H<ϵ6nH<\frac{\epsilon}{6n} for our method to be applicable. Next we compute the curved mass

M2(t)=m2+(n2n24)H2n2H2=(mn2H)(m+n2H),\displaystyle M^{2}(t)=m^{2}+\Big{(}\frac{n}{2}-\frac{n^{2}}{4}\Big{)}H^{2}-\frac{n}{2}H^{2}=\Big{(}m-\frac{n}{2}H\Big{)}\Big{(}m+\frac{n}{2}H\Big{)},
M˙(t)=0,\displaystyle\dot{M}(t)=0,

so that condition (2.9) is satisfied if

mn2H>0.m-\frac{n}{2}H>0.

In particular, our method is applicable if HH is sufficiently small and mm is sufficiently large.

2.5.2. FLRW

For the Friedmann–Lemaître-Robertson–Walker metric with power expansion we have a(t)=tka(t)=t^{k}, k>0k>0. Thus

a˙(t)a(t)=kt.\frac{\dot{a}(t)}{a(t)}=\frac{k}{t}.

So to satisfy condition (2.7) we choose

(2.14) t0=6knϵ.t_{0}=\frac{6kn}{\epsilon}.

Next we compute the curved mass

M2(t)=m2+(n2n24)(kt)2n2k(k1)t2=m2+nk2t2(1nk2)\displaystyle M^{2}(t)=m^{2}+\Big{(}\frac{n}{2}-\frac{n^{2}}{4}\Big{)}\Big{(}\frac{k}{t}\Big{)}^{2}-\frac{n}{2}\frac{k(k-1)}{t^{2}}=m^{2}+\frac{nk}{2t^{2}}\Big{(}1-\frac{nk}{2}\Big{)}

from which we can see that condition (2.9) is satisfied if 0<k2n0<k\leq\frac{2}{n}, for example.

3. Local Wellposedness

In this section we make use of the local wellposedness result in [2, Section 1]. We state the theorem, hypotheses, and (readjusted) notation for the reader’s convenience here.

Theorem 2 (Galstian and Yagdjian, 2014).

Suppose that the expanding factor a(t)a(t) satisfies assumptions (2.6) and (2.7). Suppose that m>0m>0 and that there is a positive number c0c_{0} such that the curved mass M(t)M(t) satisfies (2.9). Consider the Cauchy problem for the equation

(3.1) {utt+na˙auta2Δu+m2uVu(x,t,u)=0u(t0,x)=u0(x),ut(t0,x)=u1(x).\begin{cases}&u_{tt}+n\frac{\dot{a}}{a}u_{t}-a^{-2}\Delta u+m^{2}u-V_{u}^{{}^{\prime}}(x,t,u)=0\\ &u(t_{0},x)=u_{0}(x),\ u_{t}(t_{0},x)=u_{1}(x).\end{cases}

where Vu(x,t,u)=Γ(t)f(u)V_{u}^{{}^{\prime}}(x,t,u)=-\Gamma(t)f(u) with ΓC([t0,))\Gamma\in C([t_{0},\infty)), ff Lipshitz continuous with exponent 0α2n20\leq\alpha\leq\frac{2}{n-2} and f(0)=0f(0)=0. Then for every u0(x)H1(n)u_{0}(x)\in H^{1}(\mathbb{R}^{n}) and u1(x)L2(n)u_{1}(x)\in L^{2}(\mathbb{R}^{n}) there exists T1>t0T_{1}>t_{0} such that the problem (3.1) has a unique solution uC([t0,T1);H01(n))C1([t0,T1);L2(n))u\in C([t_{0},T_{1});H_{0}^{1}(\mathbb{R}^{n}))\cap C^{1}([t_{0},T_{1});L^{2}(\mathbb{R}^{n}))

The statement of this theorem, combined with our assumptions in Section 2 and with the fact that H01(n)H1(n)H_{0}^{1}(\mathbb{R}^{n})\subset H^{1}(\mathbb{R}^{n}) immediately implies that the Cauchy problem (2.4) satisfies the conditions of this theorem with Γ(t)=1\Gamma(t)=1.

4. Energy Formalism

In this section we develop the framework needed to prove our energy estimate. We largely follow the setup of [5] and [6]. Define the energy-momentum tensor to be

(4.1) Tαβ:=αuβu12gαβ(μuμu+m2u22F(u)).T_{\alpha\beta}:=\partial_{\alpha}u\partial_{\beta}u-\frac{1}{2}g_{\alpha\beta}\Big{(}\partial^{\mu}u\partial_{\mu}u+m^{2}u^{2}-2F(u)\Big{)}\;.

Let DD be the covariant derivative corresponding to the metric gg. The energy momentum tensor is divergence free

DαTαβ=0.D^{\alpha}T_{\alpha\beta}=0.

Given a (smooth) vector field XX we define the 1-form

Pα(X):=TαβXβ.{}^{(X)}P_{\alpha}:=T_{\alpha\beta}X^{\beta}.

Taking the divergence yields

(4.2) Dα(Pα(X))=12(X)παβTαβD^{\alpha}\big{(}{}^{(X)}P_{\alpha}\big{)}=\frac{1}{2}\;^{(X)}\pi^{\alpha\beta}T_{\alpha\beta}

where the symmetric 2-tensor π(X){}^{(X)}\pi is the deformation tensor of gg with respect to XX. Integrating this divergence over the spacetime region

{(t,x)|t0tt1}\{(t,x)\;|\;t_{0}\leq t\leq t_{1}\}

and using Stokes’ theorem we get the following multiplier identity

(4.3) t=t0(X)PαNα|𝐠|12𝑑xt=t1(X)PαNα|𝐠|12𝑑x=t0t1n(12(X)παβTαβ)𝑑Vg\begin{split}\int_{t=t_{0}}\;^{(X)}P_{\alpha}N^{\alpha}|{\mathbf{g}}|^{\frac{1}{2}}\ dx-\int_{t=t_{1}}\;^{(X)}P_{\alpha}N^{\alpha}|{\mathbf{g}}|^{\frac{1}{2}}\ dx=\int_{t_{0}}^{t_{1}}\int_{\mathbb{R}^{n}}(\frac{1}{2}\;^{(X)}\pi^{\alpha\beta}T_{\alpha\beta})\ dV_{g}\end{split}

where

dVg:=|𝐠|12dtdxdV_{g}:=|{\mathbf{g}}|^{\frac{1}{2}}dtdx

and NN is the vector field defined below:

(4.4) Nα:=gαββt(gαβαtβt)12=gα0.N^{\alpha}:=\frac{-g^{\alpha\beta}\partial_{\beta}t}{(-g^{\alpha\beta}\partial_{\alpha}t\partial_{\beta}t)^{\frac{1}{2}}}=-g^{\alpha 0}.

The integrand on the left hand side of Eq. (4.3) is the energy density associated to XX through the foliation by the spacelike hypersurfaces t=constt=const.

Given a vector field XX we define the normalized deformation tensor of XX to be

(4.5) π^(X)=(X)π12|𝐠|trace((X)π){}^{(X)}\hat{\pi}=\;^{(X)}\pi-\frac{1}{2}|{\mathbf{g}}|\cdot trace(^{(X)}\pi)

which can be computed using the following identity (see [5]):

(4.6) (X)π^αβ=|𝐠|12X(|𝐠|12gαβ)gαβγXγ+gαγγXβ+gβγγXα.^{(X)}\hat{\pi}^{\alpha\beta}=-|{\mathbf{g}}|^{-\frac{1}{2}}X(|{\mathbf{g}}|^{\frac{1}{2}}g^{\alpha\beta})-g^{\alpha\beta}\partial_{\gamma}X^{\gamma}+g^{\alpha\gamma}\partial_{\gamma}X^{\beta}+g^{\beta\gamma}\partial_{\gamma}X^{\alpha}.

In combination with Eq. (4.2), we get

(4.7) Dα(Pα(X))=12(X)π^αβαuβu.D^{\alpha}\big{(}{}^{(X)}P_{\alpha}\big{)}=\frac{1}{2}\;^{(X)}\hat{\pi}^{\alpha\beta}\partial_{\alpha}u\partial_{\beta}u.

Combining (4.7) and (4.3) yields

(4.8) t=t0(X)PαNα|𝐠|12dxt=t1(X)PαNα|𝐠|12dx=t0t1n12((X)π^αβαuβu)|𝐠|12dtdx\int_{t=t_{0}}\;^{(X)}P_{\alpha}N^{\alpha}|{\mathbf{g}}|^{\frac{1}{2}}dx-\int_{t=t_{1}}\;^{(X)}P_{\alpha}N^{\alpha}|{\mathbf{g}}|^{\frac{1}{2}}dx=\int_{t_{0}}^{t_{1}}\int_{\mathbb{R}^{n}}\frac{1}{2}\Big{(}\;^{(X)}\hat{\pi}^{\alpha\beta}\partial_{\alpha}u\partial_{\beta}u\Big{)}|{\mathbf{g}}|^{\frac{1}{2}}dtdx\\

5. Proof of Energy Inequality

In this section we will prove the energy nonincreasing property as stated below:

Lemma 3.

Let u(t,x)u(t,x) be a solution to problem (2.4). Then

E(t0)E(t)tt0E(t_{0})\geq E(t)\qquad\;\forall t\geq t_{0}

Proof: Let X=antX=a^{-n}\partial_{t}. We can compute the normalized deformation tensor of XX using Eq. (4.6). This yields

π^00(X){}^{(X)}{\hat{\pi}^{00}} =2nan1a˙0,(X)π^0j=0,\displaystyle=2na^{-n-1}\dot{a}\geq 0,\hskip 79.49744pt^{(X)}{\hat{\pi}^{0j}}=0,
π^ij(X){}^{(X)}{\hat{\pi}^{ij}} =(2n)(an3a˙)δij+nan3a˙δij=2an3a˙δij0.\displaystyle=(2-n)(a^{-n-3}\dot{a})\delta^{ij}+na^{-n-3}\dot{a}\;\delta^{ij}=2a^{-n-3}\dot{a}\;\delta^{ij}\geq 0.

Hence,

(5.1) 12((X)π^αβαuβu)|𝐠|12=na˙a|ut|2+na˙a3|u|20.\frac{1}{2}\big{(}\;^{(X)}\hat{\pi}^{\alpha\beta}\partial_{\alpha}u\partial_{\beta}u\big{)}\ |{\mathbf{g}}|^{\frac{1}{2}}=n\frac{\dot{a}}{a}|u_{t}|^{2}+n\frac{\dot{a}}{a^{3}}|\nabla u|^{2}\geq 0.

From Eq. (4.8) it follows that:

(5.2) t=t0(X)PαNα|𝐠|12𝑑xt=t1(X)PαNα|𝐠|12𝑑x0.\begin{split}\int_{t=t_{0}}\;^{(X)}P_{\alpha}N^{\alpha}|{\mathbf{g}}|^{\frac{1}{2}}dx&-\int_{t=t_{1}}\;^{(X)}P_{\alpha}N^{\alpha}|{\mathbf{g}}|^{\frac{1}{2}}dx\geq 0.\end{split}

Expanding the integrand yields

Pα(X)Nα|𝐠|12=gα0Tα0anan=T00=12(|ut|2+a2|u|2+m2u22F(u)){}^{(X)}P_{\alpha}N^{\alpha}|{\mathbf{g}}|^{\frac{1}{2}}=-g^{\alpha 0}T_{\alpha 0}a^{-n}a^{n}=T_{00}=\frac{1}{2}\Big{(}|u_{t}|^{2}+a^{-2}|\nabla u|^{2}+m^{2}u^{2}-2F(u)\Big{)}

Combining this with Eq. (5.2) gives us

(5.3) E(t0)E(t)tt0.E(t_{0})\geq E(t)\;\;\;\;\forall t\geq t_{0}.\;\;\;\;\;\;\;\square

6. Proof of Blow up in Finite Time

In this section we will prove that the set \mathcal{B} defined in Eq. (2.12) is invariant for the Cauchy problem when the assumptions in the main theorem are satisfied.

6.1. Proof that \mathcal{B} is an invariant set

Lemma 4.

Let u0(x)H01u_{0}(x)\in H_{0}^{1} and u1(x)L2u_{1}(x)\in L^{2} and a0=a(t0)a_{0}=a(t_{0}) and m~=min{1,m}\tilde{m}=min\{1,m\}. Then u,utu,u_{t} of the corresponding local solution to (2.4) satisfy I(u(t))<0I(u(t))<0 for all tTmaxt\leq T_{max} provided that I(u(t0))<0I(u(t_{0}))<0 initially and

(6.1) (u0,u1)2(ϵ+2)m~2(ϵ2na˙0a0)E(t0)=2(ϵ+2)23m~2ϵE(t0)=3(ϵ+2)m~2ϵE(t0)>0.(u_{0},u_{1})\geq\frac{2(\epsilon+2)}{\tilde{m}^{2}\big{(}\epsilon-2n\frac{\dot{a}_{0}}{a_{0}}\big{)}}E(t_{0})=\frac{2(\epsilon+2)}{\frac{2}{3}\tilde{m}^{2}\epsilon}E(t_{0})=\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>0.

Proof: For the purpose of a contradiction, we assume t(t0,Tmax)\exists t^{*}\in(t_{0},T_{max}) where tt^{*} is the least positive value such that:

(6.2) I(u(t))=0I(u(t^{*}))=0

And we therefore have:

(6.3) I(u(t))<0t[t0,t)I(u(t))<0\;\;\forall t\in[t_{0},t^{*})

We define the auxiliary function:

(6.4) B(t):=mu2B(t):=\|mu\|^{2}

and therefore

(6.5) B(t)=2(m2u,ut)B^{\prime}(t)=2(m^{2}u,u_{t})

and we therefore arrive at the fact:

(6.6) B(t0)=2m2(u0,u1)6(ϵ+2)ϵE(t0)>0B^{\prime}(t_{0})=2m^{2}(u_{0},u_{1})\geq\frac{6(\epsilon+2)}{\epsilon}E(t_{0})>0

and from (2.4)

(6.7) B′′(t)=2m2(u,utt)+2m2ut2=2m2ut2+2m2nu(a2Δuna˙aut+f(u)m2u)𝑑x=2m2ut2+2m2n(a2(u)2na˙auut+uf(u)m2u2)𝑑x2m2ut22m2I(u)\begin{split}B^{\prime\prime}(t)&=2m^{2}(u,u_{tt})+2m^{2}\|u_{t}\|^{2}\\ &=2m^{2}\|u_{t}\|^{2}+2m^{2}\int_{\mathbb{R}^{n}}u(a^{-2}\Delta u-n\frac{\dot{a}}{a}u_{t}+f(u)-m^{2}u)dx\\ &=2m^{2}\|u_{t}\|^{2}+2m^{2}\int_{\mathbb{R}^{n}}(-a^{-2}(\nabla u)^{2}-n\frac{\dot{a}}{a}uu_{t}+uf(u)-m^{2}u^{2})dx\\ &\geq 2m^{2}\|u_{t}\|^{2}-2m^{2}I(u)\end{split}

So from (6.3) and (6.7) we can establish:

(6.8) B′′(t)>0t[t0,t)B^{\prime\prime}(t)>0\;\;\forall t\in[t_{0},t^{*})

So from (6.6) and (6.8) we can conclude:

(6.9) B(t)>B(t0)=2m2(u0,u1)6(ϵ+2)ϵE(t0)>0B^{\prime}(t)>B^{\prime}(t_{0})=2m^{2}(u_{0},u_{1})\geq\frac{6(\epsilon+2)}{\epsilon}E(t_{0})>0

With this we have established that B(t)B(t) and (u,ut)(u,u_{t}) are positive and monotonic increasing on [t0,t)[t_{0},t^{*}), i.e.

(6.10) (u(t),ut(t))(u0,u1)3(ϵ+2)m~2ϵE(t0)>0,t(t0,t)(u(t),u_{t}(t))\geq(u_{0},u_{1})\geq\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>0,\;\;\forall t\in(t_{0},t^{*})

From this result we have (u(t),ut(t))3(ϵ+2)m~2ϵE(t)(u(t^{*}),u_{t}(t^{*}))\geq\frac{3(\epsilon+2)}{{\tilde{m}^{2}}\epsilon}E(t^{*}), but now we proceed using (2.10) along the same lines as [8], but with our modified energy inequality (5.3):

(6.11) E(t0)E(t)=12ut2+12m2u2+12a2u2nF(u)𝑑x12ut2+12m2u2+12a2u21ϵ+2nuf(u)𝑑x=12ut2+(121ϵ+2)(m2u2+a2u2)+1ϵ+2I(u)na˙a(ϵ+2)(m~2u0,u1)\begin{split}E(t_{0})&\geq E(t)\\ &=\frac{1}{2}\|u_{t}\|^{2}+\frac{1}{2}m^{2}\|u\|^{2}+\frac{1}{2}a^{-2}\|\nabla u\|^{2}-\int_{\mathbb{R}^{n}}F(u)dx\\ &\geq\frac{1}{2}\|u_{t}\|^{2}+\frac{1}{2}m^{2}\|u\|^{2}+\frac{1}{2}a^{-2}\|\nabla u\|^{2}-\frac{1}{\epsilon+2}\int_{\mathbb{R}^{n}}uf(u)dx\\ &=\frac{1}{2}\|u_{t}\|^{2}+(\frac{1}{2}-\frac{1}{\epsilon+2})(m^{2}\|u\|^{2}+a^{-2}\|\nabla u\|^{2})+\frac{1}{\epsilon+2}I(u)\\ &\;\;\;\;-\frac{n\dot{a}}{a(\epsilon+2)}(\tilde{m}^{2}u_{0},u_{1})\end{split}

Let a=a(t)a_{*}=a(t^{*}). Therefore, as we know I(u(t))=0I(u(t^{*}))=0 from our assumption, we arrive at:

(6.12) E(t0)12ut(t)2+(121ϵ+2)(m2u(t)2+a2u(t)2)na˙a(ϵ+2)(m~2u(t),ut(t))=12ut(t)2+(ϵ2(ϵ+2))(m2u(t)2+a2u(t)2)na˙a(ϵ+2)(m~2u(t),ut(t))ϵ2(ϵ+2)(ut(t)2+mu(t)2+a2u(t)2)na˙a(ϵ+2)(m~2u(t),ut(t))ϵ2(ϵ+2)(2(m2u(t),ut(t))+a2u(t)2)na˙a(ϵ+2)(m~2u(t),ut(t))ϵ2(ϵ+2)(2(m~2u(t),ut(t))na˙a(ϵ+2)(m~2u(t),ut(t))=aϵna˙a(ϵ+2)(m~2u(t),ut(t))=ϵna˙aϵ+2(m~2u(t),ut(t))\begin{split}E(t_{0})&\geq\frac{1}{2}\|u_{t}(t^{*})\|^{2}+(\frac{1}{2}-\frac{1}{\epsilon+2})(m^{2}\|u(t^{*})\|^{2}+a^{-2}\|\nabla u(t*)\|^{2})\\ &\;\;\;\;-\frac{n\dot{a_{*}}}{a_{*}(\epsilon+2)}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ &=\frac{1}{2}\|u_{t}(t^{*})\|^{2}+(\frac{\epsilon}{2(\epsilon+2)})(m^{2}\|u(t^{*})\|^{2}+a^{-2}\|\nabla u(t^{*})\|^{2})\\ &\;\;\;\;-\frac{n\dot{a_{*}}}{a_{*}(\epsilon+2)}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ &\geq\frac{\epsilon}{2(\epsilon+2)}(\|u_{t}(t^{*})\|^{2}+\|mu(t^{*})\|^{2}+a^{-2}\|\nabla u(t^{*})\|^{2})\\ &\;\;\;\;-\frac{n\dot{a_{*}}}{a_{*}(\epsilon+2)}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ &\geq\frac{\epsilon}{2(\epsilon+2)}(2(m^{2}u(t^{*}),u_{t}(t^{*}))+a^{-2}\|\nabla u(t^{*})\|^{2})\\ &\;\;\;\;-\frac{n\dot{a_{*}}}{a_{*}(\epsilon+2)}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ &\geq\frac{\epsilon}{2(\epsilon+2)}(2(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))-\frac{n\dot{a_{*}}}{a_{*}(\epsilon+2)}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ &=\frac{a_{*}\epsilon-n\dot{a_{*}}}{a_{*}(\epsilon+2)}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ &=\frac{\epsilon-n\frac{\dot{a_{*}}}{a_{*}}}{\epsilon+2}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ \end{split}

Therefore we have:

(6.13) E(t0)>ϵna˙aϵ+2(m~2u(t),ut(t))(m~2u(t),ut(t))<ϵ+2ϵna˙aE(t0)(m~2u(t),ut(t))<ϵ+2ϵna0˙a0E(t0)(m~2u(t),ut(t))<ϵ+2ϵ16ϵE(t0)(u(t),ut(t))<6(ϵ+2)5m~2ϵE(t0)\begin{split}E(t_{0})&>\frac{\epsilon-n\frac{\dot{a_{*}}}{a_{*}}}{\epsilon+2}(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))\\ \therefore\;\;\;(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))&<\frac{\epsilon+2}{\epsilon-n\frac{\dot{a_{*}}}{a_{*}}}E(t_{0})\\ \therefore\;\;\;(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))&<\frac{\epsilon+2}{\epsilon-n\frac{\dot{a_{0}}}{a_{0}}}E(t_{0})\\ \therefore\;\;\;(\tilde{m}^{2}u(t^{*}),u_{t}(t^{*}))&<\frac{\epsilon+2}{\epsilon-\frac{1}{6}\epsilon}E(t_{0})\\ \therefore\;\;\;(u(t^{*}),u_{t}(t^{*}))&<\frac{6(\epsilon+2)}{5\tilde{m}^{2}\epsilon}E(t_{0})\end{split}

Which gives us that (u(t),ut(t))<6(ϵ+2)5m~2ϵE(t0)(u(t^{*}),u_{t}(t^{*}))<\frac{6(\epsilon+2)}{5\tilde{m}^{2}\epsilon}E(t_{0}),which obviously contradicts 6.10.

Therefore it must follow that no such tt^{*} exists, and therefore I(u(t))<0I(u(t))<0, t>t0\;\forall t>t_{0} and therefore the set \mathcal{B} is invariant. \square

6.2. Proof of the Main Theorem

In this section we prove Theorem 1.

Proof: From Lemma 4 we know that u(x,t)u(x,t)\in\mathcal{B} implies

(6.14) B(t)>0t[t0,Tmax)B(t)>0\;\;\forall t\in[t_{0},T_{max})

And from (6.6) and the Cauchy-Schwarz Inequality we arrive at

(6.15) B(t)2=4m4(u,ut)24m4u2ut2=4m2B(t)ut2B^{\prime}(t)^{2}=4m^{4}(u,u_{t})^{2}\leq 4m^{4}\|u\|^{2}\|u_{t}\|^{2}=4m^{2}B(t)\|u_{t}\|^{2}

Combining with (6.7) we get the inequality

(6.16) B′′(t)B(t)λ+34B(t)2B(t)(B′′(t)(λ+3)m2ut2)B(t)((λ+1)m2ut22m2I(u))\begin{split}&B^{\prime\prime}(t)B(t)-\frac{\lambda+3}{4}B^{\prime}(t)^{2}\\ \geq&B(t)(B^{\prime\prime}(t)-(\lambda+3)m^{2}\|u_{t}\|^{2})\\ \geq&B(t)(-(\lambda+1)m^{2}\|u_{t}\|^{2}-2m^{2}I(u))\end{split}

From our energy inequality (6.11) we have:

E(t0)12ut2+(121ϵ+2)(m2u2+a2|u2)+1ϵ+2I(u)na˙a(ϵ+2)m~2(u,ut)\displaystyle E(t_{0})\geq\frac{1}{2}\|u_{t}\|^{2}+(\frac{1}{2}-\frac{1}{\epsilon+2})(m^{2}\|u\|^{2}+a^{-2}\ |\nabla u\|^{2})+\frac{1}{\epsilon+2}I(u)-\frac{n\dot{a}}{a(\epsilon+2)}\tilde{m}^{2}(u,u_{t})

Therefore,

E(t0)12ut2ϵ2(ϵ+2)(m2u2+a2u2)+na˙a(ϵ+2)m~2(u,ut)1ϵ+2I(u)\displaystyle E(t_{0})-\frac{1}{2}\|u_{t}\|^{2}-\frac{\epsilon}{2(\epsilon+2)}(m^{2}\|u\|^{2}+a^{-2}\|\nabla u\|^{2})+\frac{n\dot{a}}{a(\epsilon+2)}\tilde{m}^{2}(u,u_{t})\geq\frac{1}{\epsilon+2}I(u)

Which gives us:

(6.17) 2I(u)2(ϵ+2)E(t0)(ϵ+2)ut2ϵ(m2u2+a2u2)+2nm~2a˙a(u,ut)2I(u)\leq 2(\epsilon+2)E(t_{0})-(\epsilon+2)\|u_{t}\|^{2}-\epsilon(m^{2}\|u\|^{2}+a^{-2}\|\nabla u\|^{2})+2n\tilde{m}^{2}\frac{\dot{a}}{a}(u,u_{t})

We now define ξ:nonneg\xi:\mathbb{R}_{nonneg}\to\mathbb{R}

ξ(t):=m2(λ+1)ut22m2I(u)\displaystyle\xi(t):=-m^{2}(\lambda+1)\|u_{t}\|^{2}-2m^{2}I(u)

And combining this with inequality (6.17) above we get:

ξ(t)m2\displaystyle\frac{\xi(t)}{m^{2}} (λ+1)ut22(ϵ+2)E(t0)+(ϵ+2)ut2+ϵ(m2u2+a2u2)\displaystyle\geq-(\lambda+1)\|u_{t}\|^{2}-2(\epsilon+2)E(t_{0})+(\epsilon+2)\|u_{t}\|^{2}+\epsilon(m^{2}\|u\|^{2}+a^{-2}\|\nabla u\|^{2})
2nm~2a˙a(u,ut)\displaystyle\;\;\;\;-2n\tilde{m}^{2}\frac{\dot{a}}{a}(u,u_{t})
=(ϵ+1λ)ut2+ϵ(m2u2+a2u2)2(ϵ+2)E(t0)\displaystyle=(\epsilon+1-\lambda)\|u_{t}\|^{2}+\epsilon(m^{2}\|u\|^{2}+a^{-2}\|\nabla u\|^{2})-2(\epsilon+2)E(t_{0})
2nm~2a˙a(u,ut)\displaystyle\;\;\;\;-2n\tilde{m}^{2}\frac{\dot{a}}{a}(u,u_{t})

We now substitute λ=ϵ2+1\lambda=\frac{\epsilon}{2}+1 to arrive at:

(6.18) ξ(t)m2ϵ2ut2+ϵ(m2u2+a2u2)2(ϵ+2)E(t0)2nm~2a˙a((u,ut)>ϵ2(ut2+m2u2)2(ϵ+2)E(t0)2nm~2a˙a(u,ut)m~2(ϵ2na˙a)(u,ut)2(ϵ+2)E(t0)23ϵm~2(u,ut)2(ϵ+2)E(t0)\begin{split}\frac{\xi(t)}{m^{2}}&\geq\frac{\epsilon}{2}\|u_{t}\|^{2}+\epsilon(m^{2}\|u\|^{2}+a^{-2}\|\nabla u\|^{2})-2(\epsilon+2)E(t_{0})-2n\tilde{m}^{2}\frac{\dot{a}}{a}((u,u_{t})\\ &>\frac{\epsilon}{2}(\|u_{t}\|^{2}+m^{2}\|u\|^{2})-2(\epsilon+2)E(t_{0})-2n\tilde{m}^{2}\frac{\dot{a}}{a}(u,u_{t})\\ &\geq\tilde{m}^{2}(\epsilon-2n\frac{\dot{a}}{a})(u,u_{t})-2(\epsilon+2)E(t_{0})\\ &\geq\frac{2}{3}\epsilon\tilde{m}^{2}(u,u_{t})-2(\epsilon+2)E(t_{0})\end{split}

And since we have

(6.19) (u(t),ut(t))>(u0,u1)3(ϵ+2)m~2ϵE(t0)>0,t(t0,Tmax)(u(t),u_{t}(t))>(u_{0},u_{1})\geq\frac{3(\epsilon+2)}{\tilde{m}^{2}\epsilon}E(t_{0})>0,\;\;\forall t\in(t_{0},T_{max})

We arrive at the conclusion:

(6.20) ξ(t)>0,t(t0,Tmax)\xi(t)>0,\;\;\forall t\in(t_{0},T_{max})

Now, we will, using (6.20) to continue our inequality from (6.16) consider:

(6.21) B′′(t)B(t)λ+34B(t)2B(t)(B′′(t)(λ+3)m2ut2)B(t)((λ+1)m2ut22m2I(u))=B(t)ξ(t)>0B(t)>0andξ(t)>0,t(t0,Tmax]B′′(t)B(t)λ+34B(t)2>0,t(t0,Tmax)\begin{split}&B^{\prime\prime}(t)B(t)-\frac{\lambda+3}{4}B^{\prime}(t)^{2}\\ \geq&B(t)(B^{\prime\prime}(t)-(\lambda+3)m^{2}\|u_{t}\|^{2})\\ \geq&B(t)(-(\lambda+1)m^{2}\|u_{t}\|^{2}-2m^{2}I(u))\\ =&B(t)\xi(t)>0\\ \because\;&B(t)>0\;and\;\xi(t)>0,\;\;\forall t\in(t_{0},T_{max}]\\ \therefore\;&B^{\prime\prime}(t)B(t)-\frac{\lambda+3}{4}B^{\prime}(t)^{2}>0,\;\;\forall t\in(t_{0},T_{max})\end{split}

We can now rejoin [7] in the concavity argument. As 4+ϵ4>1\frac{4+\epsilon}{4}>1, and letting α=ϵ4\alpha=\frac{\epsilon}{4}, we get:

(6.22) (Bα)=αBα1B(t)<0,(Bα)′′=αBα2[B′′(t)B(t)4+ϵ4B(t)2]<0t(t0,Tmax).\begin{split}(B^{-\alpha})^{\prime}&=-\alpha B^{-\alpha-1}B^{\prime}(t)<0,\\ (B^{-\alpha})^{\prime\prime}&=-\alpha B^{-\alpha-2}[B^{\prime\prime}(t)B(t)-\frac{4+\epsilon}{4}B^{\prime}(t)^{2}]<0\\ &\forall t\in(t_{0},T_{max}).\end{split}

And if we consider the line tangent to BαB^{-\alpha} at t=t0t=t_{0}:

(6.23) GBα(t0)(t):=αBα1(t0)B(t0)(tt0)+Bα(t0)G_{B^{-\alpha}(t_{0})}(t):=-\alpha B^{-\alpha-1}(t_{0})B^{\prime}(t_{0})(t-t_{0})+B^{-\alpha}(t_{0})

And solve for GBα(t0)(t)=0G_{B^{-\alpha}(t_{0})}(t)=0, we get:

(6.24) 0=αBα1(t0)B(t0)(tt0)+Bα(t0)Bα(t0)=αBα1(t0)B(t0)(tt0)t=Bα(t0)αBα1(t0)B(t0)+t0=t0+4B(t0)ϵB(t0)\begin{split}0&=-\alpha B^{-\alpha-1}(t_{0})B^{\prime}(t_{0})(t-t_{0})+B^{-\alpha}(t_{0})\\ \therefore\;B^{-\alpha}(t_{0})&=\alpha B^{-\alpha-1}(t_{0})B^{\prime}(t_{0})(t-t_{0})\\ \therefore\;t&=\frac{B^{-\alpha}(t_{0})}{\alpha B^{-\alpha-1}(t_{0})B^{\prime}(t_{0})}+t_{0}=t_{0}+\frac{4B(t_{0})}{\epsilon B^{\prime}(t_{0})}\end{split}

Therefore it follows that BαB^{-\alpha} is concave down and decreasing and subsequently bounded above by GBα(0)(t)G_{B^{-\alpha}(0)}(t). And since we know B(t0)>0B(t_{0})>0 it must follow that Tmax<4B(t0)ϵB(t0)\exists T_{max}<\frac{4B(t_{0})}{\epsilon B^{\prime}(t_{0})} such that:

(6.25) limtTmaxBα=0limtTmaxB(t)=limtTmaxu(t,.)2.\begin{split}\lim_{t\to T_{max}^{-}}B^{-\alpha}&=0\\ \therefore\;\lim_{t\to T_{max}^{-}}B(t)&=\lim_{t\to T_{max}^{-}}\|u(t,.)\|^{2}\to\infty\;\;\;\;\;\square.\end{split}
Refer to caption
Figure 1. Demonstration of the qualitative behavior that leads to the existence of TmaxT_{max}

7. Applicable Cosmology Examples Revisited

Here we will explore two specific cases for the expansion factor a(t)a(t). The first is the de Sitter case, where a(t)=eHta(t)=e^{Ht} for some H>0H>0. This case serves as a manner of “upper limit” on the rate of growth of a(t)a(t), as we can see if we consider H=ϵ6nH=\frac{\epsilon}{6n}. We then see a˙a=ϵ6n\frac{\dot{a}}{a}=\frac{\epsilon}{6n}, the upper limit of this ratio from our general case. Clearly for any function consistently above exponential order this ratio would result in an increasing function, which could not be bounded forward in time as we require.

The other case is the FLRW expansion factor a(t)=tka(t)=t^{k} such that k>1k>1. Here we see the benefit of being well under exponential order, but we find our a˙a\frac{\dot{a}}{a} ratio is undefined at t=0t=0. This, as we will explain, is the inspiration for our t0t_{0} requirement in the general case of our argument above. While many expansion factors will allow for t0=0t_{0}=0 (Minkowski spacetime and de Sitter come to mind), extreme behavior at t=0t=0 can require t0t_{0} to be placed adequately far in the future.

7.1. The de Sitter Case

Of course, in the de Sitter case, where we have a(t)=eHta(t)=e^{Ht}, we satisfy our conditions on a(t)a(t) as well as the energy inequality with t0=0t_{0}=0 with the restriction that Hϵ6nH\leq\frac{\epsilon}{6n}. This gives us a˙a=Hϵ6n\frac{\dot{a}}{a}=H\leq\frac{\epsilon}{6n} and E(t0)E(t)t[0,)E(t_{0})\geq E(t)\forall t\in[0,\infty), clearly.

The argument for Lemma 4 therefore proceeds as follows in this case:

(7.1) E(t0)E(t)=12ut2+12m2u2+12e2Hu2nF(u)𝑑x12ut2+12m2u2+12e2Hu21ϵ+2nuf(u)𝑑x=12ut2+(121ϵ+2)(m2u2+e2Hu2)+1ϵ+2I(u)nHϵ+2(m~2u0,u1)\begin{split}E(t_{0})&\geq E(t)\\ &=\frac{1}{2}\|u_{t}\|^{2}+\frac{1}{2}m^{2}\|u\|^{2}+\frac{1}{2}e^{-2H}\|\nabla u\|^{2}-\int_{\mathbb{R}^{n}}F(u)dx\\ &\geq\frac{1}{2}\|u_{t}\|^{2}+\frac{1}{2}m^{2}\|u\|^{2}+\frac{1}{2}e^{-2H}\|\nabla u\|^{2}-\frac{1}{\epsilon+2}\int_{\mathbb{R}^{n}}uf(u)dx\\ &=\frac{1}{2}\|u_{t}\|^{2}+(\frac{1}{2}-\frac{1}{\epsilon+2})(m^{2}\|u\|^{2}+e^{-2H}\|\nabla u\|^{2})+\frac{1}{\epsilon+2}I(u)\\ &\;\;\;\;-\frac{nH}{\epsilon+2}(\tilde{m}^{2}u_{0},u_{1})\end{split}

And following along the same lines as the general argument, with our restriction on HH, we arrive at the same contradiction arrived at with 6.13.

This particular example is enlightening not only because of the pertinence to the current assumed nature of our universe, but also for making clear that t0t_{0} is only a positive quantity in cases where our a(t)a(t) conditions cannot be satisfied over all nonnegative tt, whether due to discontinuity or some other early behavior associated with the expansion factor.

This example also matches the intuition that one would have for how blow-up would be influenced by our choice of aa. The limit on HH serves as a limit on on the rate of expansion, which if too great might “smooth out” too quickly to allow for blowup. Furthermore, the local existence result in Theorem 1.2 of [2] also requires that HH be small relative to mm.

7.2. The FLRW Case

Here we have a(t)=tka(t)=t^{k} and the metric is therefore expressed as follows:

(7.2) 𝐠:=dt2+t2k(dx12+dx22++dxn2).{\mathbf{g}}:=-dt^{2}+t^{2k}(dx_{1}^{2}+dx_{2}^{2}+...+dx_{n}^{2}).

When we consider the a˙a\frac{\dot{a}}{a} ratio we arrive at:

(7.3) a˙(t)a(t)=knt1\frac{\dot{a}(t)}{a(t)}=knt^{-1}

Thus the discontinuity at t=0t=0 requires that we consider our initial time t0t_{0} as follows:

(7.4) 6knϵ=t0.\frac{6kn}{\epsilon}=t_{0}.
(7.5) E(t0)E(t)=12ut2+12m2u2+12t2ku2nF(u)𝑑x12ut2+12m2u2+12t2ku21ϵ+2nuf(u)𝑑x=12ut2+(121ϵ+2)(m2u2+t2ku2)+1ϵ+2I(u)knt1ϵ+2(m~2u0,u1)\begin{split}E(t_{0})&\geq E(t)\\ &=\frac{1}{2}\|u_{t}\|^{2}+\frac{1}{2}m^{2}\|u\|^{2}+\frac{1}{2}t^{-2k}\|\nabla u\|^{2}-\int_{\mathbb{R}^{n}}F(u)dx\\ &\geq\frac{1}{2}\|u_{t}\|^{2}+\frac{1}{2}m^{2}\|u\|^{2}+\frac{1}{2}t^{-2k}\|\nabla u\|^{2}-\frac{1}{\epsilon+2}\int_{\mathbb{R}^{n}}uf(u)dx\\ &=\frac{1}{2}\|u_{t}\|^{2}+(\frac{1}{2}-\frac{1}{\epsilon+2})(m^{2}\|u\|^{2}+t^{-2k}\|\nabla u\|^{2})+\frac{1}{\epsilon+2}I(u)\\ &\;\;\;\;-\frac{knt^{-1}}{\epsilon+2}(\tilde{m}^{2}u_{0},u_{1})\end{split}

Again, following the lines of the general argument, we quickly arrive at the same contradiction of 6.10 that allows the proof to proceed. With the curtailed expansion of this polynomial case, we see that there are no restrictions reminiscent of those that had to be placed on H in the de Sitter case. Rather, here we have to contend with the discontinuity at t=0t=0, which is avoided by placing our start time suitably far from that initial singularity.

It is worth noting that the general argument is widely applicable, and these simple, well-studied metrics fall within the restrictions on the expanding factor required for the argument. One can also think of the exponential de Sitter case as an upper bound for this factor, as it is the most rapidly expanding expansion factor that can remain within these restrictions.

8. Acknoledgements

Jesús Oliver was supported by an AMS-Simons Research Enhancement Grant for Primarily Undergraduate Institution Faculty.

9. Appendix: Lower Bound for the Initial Data

In this section we prove that the assumptions of our main theorem imply that the norm of the initial data u0(x)H01u_{0}(x)\in H_{0}^{1}, u1(x)L2u_{1}(x)\in L^{2} has a positive uniform lower bound.

Theorem 5.

Suppose that all the hypotheses of Theorem 1 are satisfied. Then there exists a uniform constant Cmin>0C_{min}>0 such that

Cmin<u0H01C_{min}<\|u_{0}\|_{H_{0}^{1}}
Proof.

By the density of CcC^{\infty}_{c} in H01H^{1}_{0}, it suffices to consider smooth, compactly supported functions. The condition u0u_{0}\in\mathcal{B} (equivalently I(u(t0))<0I(u(t_{0}))<0) implies

(9.1) {t=t0}×n(m2u2+1a2(u)2+na˙am~2uut)𝑑x<{t=t0}×nuf(u)𝑑x.\int_{\{t=t_{0}\}\times\mathbb{R}^{n}}\left(m^{2}u^{2}+\frac{1}{a^{2}}(\nabla u)^{2}+n\frac{\dot{a}}{a}\tilde{m}^{2}uu_{t}\right)dx<\int_{\{t=t_{0}\}\times\mathbb{R}^{n}}uf(u)\ dx.

By assumption m>0m>0; by Eq. (2.6) a(t0)a(t_{0}) and a˙(t0)\dot{a}(t_{0}) are also positive. By Eq. (2.13) we also have a lower bound for the last term on the LHS of (9.1). Consequently

(9.2) 0<{t=t0}×n(u2+(u)2)𝑑x+E(t0)<C{t=t0}×nuf(u)𝑑x.0<\int_{\{t=t_{0}\}\times\mathbb{R}^{n}}\left(u^{2}+(\nabla u)^{2}\right)dx+E(t_{0})<C\int_{\{t=t_{0}\}\times\mathbb{R}^{n}}uf(u)\ dx.

Since ff is Lipshitz continuous with exponent 0α2n20\leq\alpha\leq\frac{2}{n-2}, we have

|f(u)f(0)|=|f(u)0|C|u|α+1.|f(u)-f(0)|=|f(u)-0|\leq C|u|^{\alpha+1}.

Using this together with the triangle inequality, and E(t0)>0E(t_{0})>0 we can conclude

(9.3) u0H012<C{t=t0}×nuf(u)𝑑x<Cu0Lα+2α+2\|u_{0}\|_{H_{0}^{1}}^{2}<C\int_{\{t=t_{0}\}\times\mathbb{R}^{n}}uf(u)\ dx<C\|u_{0}\|_{L^{\alpha+2}}^{\alpha+2}

Next, using the Sobolev Embedding Theorem (see for example Thm. 27.18 in [1]) we have the bound

u0LqCu0H1\|u_{0}\|_{L^{q^{*}}}\leq C\|u_{0}\|_{H^{1}}

with q=4n2q^{*}=\frac{4}{n-2}. Since 0α2n20\leq\alpha\leq\frac{2}{n-2}, we also have

α2n2<4n2=2n2n+4n2α+2<2nn2,\alpha\leq\frac{2}{n-2}<\frac{4}{n-2}=\frac{2n-2n+4}{n-2}\qquad\Rightarrow\qquad\alpha+2<\frac{2n}{n-2},

Therefore (9.3) and the compact support of uu yields

u0H012<Cu0Lα+2α+2Cu0Lqq(α+2)<Cminu0H01α+2\|u_{0}\|_{H_{0}^{1}}^{2}<C\|u_{0}\|_{L^{\alpha+2}}^{\alpha+2}\leq C\|u_{0}\|_{L^{q^{*}}}^{q^{*}(\alpha+2)}<C_{min}\|u_{0}\|^{\alpha+2}_{H_{0}^{1}}

where CminC_{min} is a uniform constant depending only on the Sobolev embedding inequality and on the inequalities assumed in Theorem 1. As a result, we have the lower bound

Cmin1α<u0H01C_{min}^{-\frac{1}{\alpha}}<\|u_{0}\|_{H_{0}^{1}}

from which the theorem follows. ∎

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